Shane found a website that gives the daily weather report from mars. for 4 days, shane recorded the daily high and low temperatures on mars.use the dropdowns to complete each statement. table of daily high and low temperatures in degrees celsius. on day 1, the low was negative eighty-two; the high was negative twenty-four. on day 2, the low was negative eighty-three; the high was negative twenty-six. on day 3, the low was negative eighty-four; the high was negative twenty-seven. on day 4, the low was negative eighty-four; the high was negative twenty-eight.a. the average temperature on day 2 was blank.b. the difference of the average high temperature and the average low temperature for all four days is blank.c. the day with the greatest average temperature was blank.

Answer:

Answer: 3 + 97

Step-by-step explanation:

Just off the top of my head, I'm pretty sure that the answer you want is 3 and 97.

The single digit primes are 2 3 5 7

2 + 98 is what you are forced to use. 98 is not prime

3 + 97 is the answer I gave.

5 and 95 Ninety five is not prime (5 divides into it).

7 and 93 but 93 is not prime. 3 will divide into it.

The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

The magnetic field inside the central area of the solenoid is given by B = μ₀ni where

Since B = μ₀ni

Substituting the values of the variables into the equation, we have

B = μ₀ni

B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A

B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m

B = 84956π × 10⁻⁷ T

B = 266897.15 × 10⁻⁷ T

B = 0.026689715 T

B ≅ 0.0267 T

So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T

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The magnitude of the magnetic field in the central area inside the considered solenoid (assuming in vaccum), is approx 2.67 × 10^{-2} T

Magnetic field = permeability constant x relative permeability x turn density x current

B = [tex]k\mu_0nI = \mu nI[/tex]

where turn density is calculated as:

n = N/L

Where N represents the number of turns of the wire and

L represents the length of the solenoid.

Assuming that the solenoid is placed in vaccum, we have:

[tex]\mu = k\mu_0 = \mu_0 = 4\pi \times 10^{-7} \: \rm T m/A[/tex]

And it is given that:

Thus, we get:

[tex]B = \mu n I = 4\pi \times 10^{-7} \times 3170 \times 6.7 \approx 2.67 \times 10^5 \times 10^{-7} \\\\B = 2.67 \times 10^{5 + (-7)}B = 2.67 \times 10^{-2} \: \tm T[/tex]

Thus, the magnitude of the magnetic field in the central area inside the considered solenoid (assuming in vaccum), is approx 2.67 × 10^{-2} T

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Answer:

Surface Area = 6×62 = 216 inches2

Step-by-step explanation:

Formula for surface area of cube is 6 into side²

EXPLANATION

Cube has all sides of equal dimensions and like that it has 6 faces.

So total surface area of cube is equal to the combined area of all the six faces.

Now each face has equal dimensions so same area

Therefore,

area of a single face =side²

Therefore, area of entire cube = 6 times the area of a single face

= 6 * side²

Answer:

a= 50

b=50

c=110

d=20

Answer:

Step-by-step explanation:

This is a kite. So the two triangles formed by the longest diagonal being drawn in form 2 congruent triangles.

Therefore c = 110 degrees.

d = 20 degrees.

a and b are found by noting that every triangle has 180 degrees.

110 + 20 + a = 180           Combine the left.

130 + a = 180                   Subtract 130 from both sides

a = 180 - 130

a = 50 degrees

b also equals 50 degrees.  Congruent triangles

Answer

Answer:

72x430/43

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

4 inches by 2.5 inches

Step-by-step explanation:

The scale factor is 7 feet/1 inch.

This can be written as  7'/1" or as 1"/7'

28 feet converts to (28')*(1"/7') = 4"

17.5 feet converts to (17.5)*(1"/7') = 2.5"

The drawing dimensions are 4 inches by 2.5 inches.

Answer:

Step-by-step explanation:

Answer:

4.6320447e+16

I used a calculator for this LOL.

Based on the formula given of 27π = πn, we can find the value of n after substitution in an equation to be 27.

The value of n can be found by making n the subject of the formula as shown below;

27π = πn

n = 27π / π

Solving of n therefore gives:

n = 27π/π

n = 27

In conclusion, n is 27.

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Step-by-step explanation:Updated answer is the second one

Answer:

89

Step-by-step explanation:

Answer:

0.950 L

Step-by-step explanation:

ml/1000 = L

Answer:

144

Step-by-step explanation:

The equation to find c is:

[tex](\frac{b}{2} )^{2}[/tex]

So put -24 into b:

[tex](\frac{-24}{2} )^{2}[/tex]

Which simplifies to:

144

So if you want to test this:

x^2 - 24x + 144

is

(x-12)^2

Answer:

"LOCATION: Most temperate, deciduous (leaf-shedding) forests are located in the eastern United States, Canada, Europe, China, Japan, and parts of Russia. Deciduous forests are broken up into five zones."

Step-by-step explanation:

✖ Brazil

✓ China

✓ United States

✓ Russia

✖ Chile

Hopefully this helps you!

-Keira

Answer:

60 cm

Step-by-step explanation:

The perimeter of a polygon means adding up all the side lengths.

In this case, we need to add up 13, 12, 8, 8, and 19

Adding all of these gets us 60

Answer:

16 to 20

Step-by-step explanation:

Let's do our math.

4 to 5

8 to 10

12 to 15

16 to 20

In order to get to 20, you'd have to multiply 5 by 4. So in order to get an equal ratio, you multiply 4 by 4 and get 16.

I hope this helps!

-No one

Explanation:

The distributive property allows us to go from the original expression to choice A. We multiply the outer term 8 by each term inside the parenthesis.

In general, the distributive property is a(b+c) = ab+ac. Example: 2(3+4) = 2(3)+2(4) = 6+8 = 14.

After simplifying the expression in choice A, it leads directly to choice E. This is because 8(6x) = 48x and 8(9) = 72.

Side note: A common mistake students do is to multiply the outer term by only one of the terms inside the parenthesis, while forgetting about the other term inside. Choice B shows this mistake. It's possible your teacher put choice B in there as a trap/trick answer.

Answer: C

Step-by-step explanation:

The maximum number of whole gallons of fuel the tank can contain due to safety measures is 174.584 gallons

r = radius

h = height

Therefore,

r = 10 ft

h = 25 ft

The tank can only be 80% filled due to safety measures. Therefore,

v = 3.14 × 10² × 25

v = 3.14 × 100 × 25

v = 3.14 × 2500

v = 7850 ft³

80% capacity of 7850 ft³  is as follows:

80 / 100 × 7850 = 628000 / 100 = 6280 ft³

100 ft³ = 2.78 gallons

6280 ft³ = ?

cross multiply

maximum number of whole gallons  = 6280 × 2.78 / 100 = 17458.4 / 100 = 174.584 gallons

Therefore, the maximum number of whole gallons of fuel the tank can contain due to safety measures is 174.584 gallons

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Answer:

[tex]4x + 6y^{3} x^{2}[/tex]

Step-by-step explanation:

Simplify

Answer:

120 m²

Step-by-step explanation:

A = (1/2) · (p + q) · h
A = (1/2)(14 + 10)(10)
A = (1/2)(24)(10)
A = 120
Hope this helps :)

Answer:

Pretty sure it's 2:30 P.M.

Step-by-step explanation:

If her track practice started at 12:00 P.M., and and ran relays for one hour, it would already be 1:00 P.M.

Then she practiced the long jump for an hour and thirty minutes. Add another hour to that and it would be 2:00 P.M. Add thirty minutes, and it would be 2:30 P.M.

Hopefully that makes sense to you

Derivation of f(x):

   [tex]f'(x) = \frac{g(x)*8x-4x^2*g'(x)}{(g(x))^2} -\frac{1}{x+2}[/tex]

    Since g(3) = 6 and g'(3) = 3

   [tex]f'(3) = \frac{g(3)*8*3-4(3)^2*g'(3)}{(g(3))^2} -\frac{1}{3+2} \\f'(3) = \frac{6*8*3-4*9*3}{36} -\frac{1}{5} \\f'(3) = \frac{36}{36} -\frac{1}{5} =1-\frac{1}{5} =\frac{4}{5}\\ f'(3) = 0.8[/tex]

Thus f'(3) = 0.8

Hope that helps!

A couple of identities I used in derivation:

[tex]\frac{d}{dx} (ln x) = \frac{1}{x}[/tex]

answer

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x

in the expression you substitute

−

3

and for each

y

you substitute

5

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=

+

)

(

(

2

⋅

−

3

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5

−

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−

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6

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47

Answer linkStep-by-step explanation:

Let's see

Put x and y

Done!

The original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

Suppose a figure (pre image) is dilated (dilated image) by scale factor of k.

So, if a side of the figure is of length L units, and that of its similar figure is of M units, then:

L = k × M

where 'k' will be called as scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple of linear things twice grow by square of scale factor. Thus, we need to multiply or divide by k² to get each other corresponding quantity from their similar figures' quantities.

So area of first figure = k² × area of second figure

Similarly,

Volume of first figure = k³ × volume of second figure.

It is because we will need to multiply 3 linear quantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

For this case, we're given that;

Let the scale fator of dilation be k.

Then:

So area of pre-image = k² × area of dilated image

Thus, we get:

[tex]35 = k^2 \times 315\\\\k = \sqrt{\dfrac{35}{315}} = 1/3[/tex]

(took positive root as scaling is done by non-negative factors as only magnitude matters mostly)

Thus, we get:

Height of pre-image = (1/3) × Height of dilated image (say h)

[tex]5.8 = (1/3) \times h\\h = 3 \times 5.8 = 17.4 \rm \: m[/tex]

Thus, the original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

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Answer:

q=50

d=22

Step-by-step explanation:

Answer:

Mode = 1

Step-by-step explanation:

Relation between the Central Measures of Tendency

Solving

Therefore,

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

We know the relation between mean, Median and mode. that is :

[tex]\qquad \sf  \dashrightarrow \:mode = 3 \: median - 2 \: mean[/tex]

now, plug in the values ~

[tex]\qquad \sf  \dashrightarrow \:mode = 3(5) - 2(7)[/tex]

[tex]\qquad \sf  \dashrightarrow \:mode = 15 - 14[/tex]

[tex]\qquad \sf  \dashrightarrow \:mode = 1[/tex]

Hence, value of mode is 1

Answer:

14 (exactly 500) or 15 (over 500)

Step-by-step explanation:

We know that Alexis has already bought 50 stamps.

50 + 30 = 80

We need to subtract to see how many stamps she needs.

500 - 80 = 420

We divide by 30 to see about how many weeks it would take.

420 / 30 = 14

We can add 1 more week because she wants to have more than 500 stamps.

hope this helps :)

The average squared distance between the points is their variance

The average squared distance is 8/3

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

[tex]D\² = \int \int (x-2)\² + (y-2)\² dx dy[/tex]

Expand

[tex]D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy[/tex]

Evaluate the inner integral with respect to x from 0 to 2

[tex]D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy[/tex]

Expand

[tex]D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy[/tex]

Simplify

[tex]D\² = \int \frac 83 + (2)(y-2)\² dy[/tex]

Expand

[tex]D\² = \int \frac 83 + 2y^2-8y + 8 \ dy[/tex]

Evaluate the integral with respect to y from 0 to 2

[tex]D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0[/tex]

Expand

[tex]D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2[/tex]

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 [tex]\div[/tex] 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

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The average squared distance between the points of R = {(x,y): 0<=x<= h, 0<=y<=k } is 8/3.

How do determine the average squared distance?

From the given parameters R = {(x,y): 0<=x<= h, 0<=y<=k }

The squared distance from point (h, k) is calculated as

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) will be

A = xy

Substitute the maximum values of x and y

A = 2 × 2 = 4

The minimum values of x and y are 0.

So, The integral becomes

[tex]D^{2} = \int \int(x-2)^2 +(y-2)^2 dx dy\\\\D^{2} = \int \int\limits^2_0 (x)^2 -4x + 4+(y-2)^2 dx dy\\\\D^{2} = \int1/3(x)^3-2x^{2} +4x + 4+x(y-2)^2 dy\\\\D^{2} = \int8/3+2y^{2} -8y +8 dy[/tex]

[tex]D^2 = {8/3y +2/3y^2 -4y^2+8y[/tex]

By expanding we get,

D^2 = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

AD² = 32/3  4

AD² = 32/12

AD² = 8/3

Hence, the average squared distance is 8/3

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Answer:

20 shirts = $445.00

40 shirts = $541.00

60 shirts = $637.00

Step-by-step explanation:

multiply 20, 40 and 60 by 4.8 then add 349.

20*4.8 = 96

96+349 = 445

40*4.8 = 192

192+349 = 551

60*4.8 = 288

288+349 = 637