![RecoverySolve For X Usingcross Multiplication.2x + 132x11 -=x + 22x = [?]Enter](https://brainimage.s3.us-east-005.backblazeb2.com/contents/attachments/CuIFXmbzDRS2hmQOnQNBVeCnrwP3z6iy.jpeg)
Answers
Answer:
x = 4
Step-by-step explanation:
Cross-multiplying means multiplying the numerator of one side by the denominator of the other side.
So, let's multiply the sides:
[tex]\begin{gathered} \frac{2x+1}{3}=\frac{x+2}{2} \\ 2\cdot(2x+1)=3\cdot(x+2) \end{gathered}[/tex]Now, we can solve each side:
[tex]\begin{gathered} 4x+2=3x+6 \\ 4x-3x=6-2 \\ 1x=4 \\ x=4 \end{gathered}[/tex]So, x = 4.
Related Questions
Puppets made by each puppeteer43ASCNumber of puppetsAsMYCol?0AlexKalinBruceMarcoMYPuppeteerProIf the mean of the data set is 3 puppets, find the number of puppets Marco made.ProTeapuppets
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Remember that we can get the mean of a dataset by adding up each datum and dividing such sum by the number of data.
Now, let's call the number of puppets Marco made M
This way, we would have that:
[tex]\frac{1+4+3+M}{4}=3[/tex]Solving for M :
[tex]\begin{gathered} \frac{1+4+3+M}{4}=3 \\ \\ \rightarrow\frac{8+M}{4}=3 \\ \\ \rightarrow8+M=12\rightarrow M=12-8 \\ \Rightarrow M=4 \end{gathered}[/tex]Therefore, we can conclude that Marco made 4 puppets.
How can I know how many students scored 5 in their test?
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Based on the given table, consider that the value in the column frequency specifies the number of times that a certain score (first column) is repeated in a given data.
In this case, the value of the frequency for a specific score determines the number of students with such a score in their tests.
As you can notice, for the value of the frequency equal to 3, the corresponding value of the score is 5. It means that 3 student get 5 scores in their tests.
Given that the shape below is a rectangle, we know that the diagonals, lines AD and CB, are ____.
Answers
The given information is the shape is a rectangle.
About the diagonals of rectangles, there are two known properties:
- The diagonals of a rectangle bisect each other
- Both diagonals have the same length
Then, the answer is option C. They have the same length
Adina sets up a taste test of 3 different waters: tap, bottled in glass, and bottled in plastic. She puts these waters in identical cups and has a friend taste them one by one. The friend then tries to identify which water was in each cup. Assume that Adina's friend can't taste any difference and is randomly guessing. What is the probability that Adina's friend correctly identifies each of the 3 cups of water
Answers
Given
3 different waters: tap, bottled in glass, and bottled in plastic.
Find
probability that Adina's friend correctly identifies each of the 3 cups of water
Explanation
As we have given three different waters : tap , bottled in glass and bottled in plastic.
number of ways in which the person can make guesses about the 3 cups of water =
[tex]\begin{gathered} ^3P_3 \\ \frac{3!}{0!} \\ 6 \end{gathered}[/tex]number of ways in which person identifies correctly the 3 cups of water = 1
so , probability that Adina's friend correctly identifies each of the 3 cups of water =
[tex]P\text{ = }\frac{number\text{ of ways in which person identifies correctly the 3 cups of water}}{number\text{ of ways in which the person can make guesses about the 3 cups of water }}[/tex]so , P = 1/6
Final Answer
Therefore , the probability that adina's friend correctly identifies each of the cup of water = 1/6
Really need help with this math assignment please help no
Answers
In a linear relationship, each step of x modifies the y value in the same way.
In the first table, when x = 1, y = 3 and when x = 2, y = 6. This is an increment of 3. If this is a linear relationship, we expect the next value of y to be the previous value plus 3, thus y = 9. But in the table shows x =3 and y = 12. We can rule out the first table.
With similar reasoning, in the second table, we see (1, 2) and (2, 5). This is an increase of the y value of 3. We expect the next value to be y = 8, but we see (3, 9). The second table is not a linear relationship.
In the third table, we see (1, -3) and (2, -5). This is a decrease of -2. We expect the next value of y to be y = -7, and we do see (3, -7). The next value should be y = -9, and the table shows (4, -9). Table 3 shows a linear relationship.
To be sure, let's see the 4th table. We see (1, -2) and (2, -4). This is a decrease of -2. The expected next value is y = -6, but the next point is (3, -2). Fourth table is not a linear relationship.
Thus, the correct answer is the top-right table.
hello this the the problem Im stuck on. I need to know where to plot the point on the graph aswell. ty
Answers
Given:
The rent for trucks is $3750.
The additional charge per ton of sugar is $150.
To write: The equation relating the total cost C and amount of sugar S.
Explanation:
The equation represents the total cost C and the amount of sugar S is given by,
[tex]C=3750+150S[/tex]Let us find the three coordinates to plot the graph.
When
[tex]S=0[/tex]Then,
[tex]\begin{gathered} C=3750+150(0) \\ =3750 \end{gathered}[/tex]When
[tex]S=1[/tex]Then,
[tex]\begin{gathered} C=3750+150 \\ =3900 \end{gathered}[/tex]When
[tex]S=2[/tex]Then,
[tex]\begin{gathered} C=3750+150(2) \\ =3750+300 \\ =4050 \end{gathered}[/tex]So, the coordinates are,
[tex](0,3750),(1,3900),(2,4050)[/tex]The equation represents the total cost C and the amount of sugar S is given by,
[tex]C=3750+150S[/tex]The graph is,
Find the quotient32 divided by 517 what is quotient and what is remainder
Answers
Calculate the division as shown below
Therefore, the quotient is 16 and the remainder is 5
The answer is 16R5involving two rolls of a dieESEAn ordinary (falr) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a dle is rolled twice in successionand that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.Compute the probability of each of the following events.Event A: The sum is greater than 8.Event B: The sum is an odd number.Write your answers as fractions.Ola(a) P(A) = 1х5?(b) P(B) = 0
Answers
Answer:
[tex]\begin{gathered} a)\text{ }\frac{5}{18} \\ \\ b)\text{ }\frac{1}{2} \end{gathered}[/tex]Explanation:
Here, we want to compute some probabilities
The first thing to do is to get the count of results in our sample space
In the sample space, the total possible results is 36
Now, let us get the probabilities
a) The event that the sum is greater than 8
We have to count possible results greater than 8 here
3, 6 (3 on the first die, 6 on the second)
6,3 (6 on the first die, 3 on the second)
6,4 (6 on the first die, 4 on the second)
4,6
4,5
5,4
5,5
5,6
6,5
6,6
The number of possible results greater than 8 is 10
Thus, we have the probability as the count of this divided by the total number of possible results
Mathematically, we have that as:
[tex]\frac{10}{36}\text{ = }\frac{5}{18}[/tex]b) The sum is an odd number
For the sum to be an odd number, we know that if we add a table of 6 rows for all the sums, the even sum on each line is 3
The total even sum is 6 * 3 = 18
The probability is thus:
[tex]\frac{18}{36}\text{ = }\frac{1}{2}[/tex]2×+22=2(x+11)whats the property
Answers
Distributive property
In this property, multiplying the sum of two or more terms in that add up in a bracket by a number outside the bracket will be equal to multiplying each term in the bracket individually and then followed by sum of the product. In this question:
2x + 22 = 2(x + 11 ) in that when you perform product on the right side of the equation, the result is the same i.e 2x + 2*11 = 2x + 22
One package of markers has dimensions 6"×8"×1"what are the dimensions of the box that will hold 30 packages of markers and use the LEAST amount of cardboard? A. 6"×8"×30" B. 6"×16"×15" C. 10"×10"×10"D. 12"×8"×15" E. 18"×8"×10
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The required Dimensions are 6'' x 8'' x 30'' , That is option A
all you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd
Answers
We have the following:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}[/tex]replacing:
[tex]\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}[/tex]Quadrilateral ABCD is a rhombus.DA АC СBMatch the reasons that justifies the given statements.
Answers
A rhombus is a quadrilateral with 4 congruent sides.
For the Rhombus ABCD given
[tex]\begin{gathered} AB\mleft\Vert DC\text{ }\mright? \\ \\ \text{Opposite sides of a rho}mbus\text{ are parallel} \end{gathered}[/tex]Also,
[tex]\begin{gathered} DA\cong CB \\ \text{Opposite sides of a rhombus are congruent} \end{gathered}[/tex]Also,
[tex]\begin{gathered} <\text{ADC}\cong<\text{ABC} \\ \text{Opposite angles of a rhombus are congruent} \end{gathered}[/tex]In which quadrant does 0 lie if the following statements are true:sin 0 > 0 and sec 0 < 0Quadrant IQuadrant IIQuadrant IIIQuadrant IV
Answers
Given the conditions in the question:
1. sin θ > 0, therefore, it must be positive. From that, we can conclude that y must be on the positive side, therefore, located at the top of the coordinate plane.
2. sec θ < 0, therefore, it must be negative. From that, we can conclude that x must be on the negative side, therefore, located at the left side of the coordinate plane.
Therefore, the quadrant that the θ belongs to is in the top and left of the coordinate plane and that is Quadrant II.
The Lyon Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United States. For 186 restaurants located in Boston, the average price of a dinner, including one drink and tip, was 48.60 Dollars. You are leaving on a business trip to Boston and will eat dinner 23 of these restaurants, randomly selected. Your company will reimburse you for a maximum of 50 dollars per dinner. Business associates familiar with these restaurants have told you that the meal cost at one-third of these restaurants will exceed 50 dollars.
a. What is the probability that none of the meals will exceed the cost covered by your company?
b. What is the probability that at most 12 of the meals will exceed the cost covered by your company? What is the probability that between 4 and 8 of the meals will exceed the cost covered by your company?
c. Calculate the expected number of restaurants that will exceed the cost covered by your company.
d. Calculate the probability of the first question by using the binomial distribution approximation. Therefore, in this case we will consider the possibility of repetition in the randomly selected restaurants. Define p=r/N as the success probability.N is the size of the population. r is the number of elements considered as successes in the population.
e. Calculate the probability of the second question by using the binomial disribution approximation.
f. Calculate the probability of the third question by using the binomial disribution approximation.
g. Calculate the expected number of the fourth question by using the binomial disribution aproximation
Answers
Using the binomial distribution, the probabilities are given as follows:
a. None: 0%.
b.
At most 12: 0.9814 = 98.14%.Between 4 and 8: 0.6249 = 62.49%.c. The expected number of restaurants that will exceed the cost covered by your company is of 7.67.
Using the normal approximation, the probabilities are:
a. None: 0.0008 = 0.08%.
b.
At most 12: 98.38 = 98.38%.Between 4 and 8: 0.6121 = 61.21%.The difference in these probabilities is due to the small sample size.
Binomial distributionThe formula for the probability of x successes is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In which the parameters are given by:
n is the number of trials of the experiment.p is the probability of a success on a single trial of the experiment.Considering that you will eat dinner at 23 restaurants, and at around one-third of them the meal cost will exceed 50 dollars, the values of these parameters are given as follows:
n = 23, p = 1/3 = 0.3333.
The probability that none will exceed is P(X = 0), hence:
P(X = 0) = (1 - 0.3333)^23 = 0% (rounded).
The probability of at most 12 is:
P(X <= 12) = P(X = 0) + P(X = 1) + ... + P(X = 12).
Using a binomial distribution calculator with the given parameters, the probability is:
P(X <= 12) = 0.9814 = 98.14%.
The probability that between 4 and 8 dinners are paid is:
P(4 <= X <= 8) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)
Using a calculator, or the mass function P(X = x) and adding each probability, the desired probability is:
P(4 <= X <= 8) = 0.0493 + 0.0937 + 0.1405 + 0.1707 + 0.1707 = 0.6249 = 62.49%.
Normal approximationThe first step for the normal approximation is finding the mean and the standard deviation, as follows:
Mean = expected number: [tex]\mu = np = 23 \times 0.3333 = 7.67[/tex]Standard deviation: [tex]\sigma = \sqrt{np(1-p) = \sqrt{23 \times 0.3333 \times 0.6667} = 2.26[/tex]The probability of none, using continuity correction, is P(X < 0.5), which is the p-value of Z when X = 0.5, hence:
(the p-value of Z is found using the z-score table).
[tex]Z = \frac{X - \mu}{\sigma}[/tex] (z-score formula)
Z = (0.5 - 7.67)/2.26
Z = -3.17
Z = -3.17 has a p-value of 0.0008.
Hence the probability is 0.0008 = 0.08%.
The probability of at most 12 is P(X <= 12.5), using continuity correction, which is the p-value of Z when X = 12.5, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (12.5 - 7.67)/2.26
Z = 2.14
Z = 2.14 has a p-value of 0.9838.
Hence the probability is of 98.38 = 98.38%.
The probability of between 4 and 8 dinners being paid is P(3.5 <= X <= 8.5), which is the p-value of Z when X = 8.5 subtracted by the p-value of Z when X = 3.5, hence:
X = 8.5:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (8.5 - 7.67)/2.26
Z = 0.37
Z = 0.37 has a p-value of 0.6443.
X = 3.5:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (3.5 - 7.67)/2.26
Z = -1.85
Z = -1.85 has a p-value of 0.0322.
Hence the probability is:
0.6443 - 0.0322 = 0.6121 = 61.21%.
More can be learned about the binomial distribution at https://brainly.com/question/24756209
#SPJ1
Can you please answer this question for me. I don’t want full explanation I just want the answers
Answers
we have the fractions
1/4 and 3/4
Remember that
If the denominators are the same, then the fraction with the greater numerator is the greater fraction
3/4 > 1/4
use the number line
Divide number 1 into 4 parts
Find the volume of the figure. 6 cm. 6 cm. 1 8 cm. 10 cm. Volume of the prism cm3
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The volume of the pyramid is 144 cm³
Explanations:The volume of a prism is given by the formula:
V = BH
where B is the base area
and H is the height
The base of the the pyramid is the lateral triangle, and the area is given by the formula:
B = 0.5 x b x h
b = 8 cm
h = 6 cm
B = 0.5 x 8 x 6
B = 24 cm²
The volume is then:
V = BH, where H = 6 cm
V = 24 x 6
V = 144 cm³
I need help with this practice from my ACT prep guide Having trouble
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Given:
[tex]f(x)=-4\cos (\frac{2}{3}x+\frac{\pi}{3})-3[/tex]Determine the input value for which the statementf(x) = g(x) is true.From the graph, the input value is approximatelyf(x) = 3 and g(x) = 3x-23 = {x-25= xThe x-value at which the two functions' values areequal is
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You can see from the graph, f (x) is a constant value and g (x) = -5, when x = -2, g (x) = - 2, when x = 0 and g (x) = 1, when x = 2.
Step by step solution thank you much appreciated
Answers
Answer:
11.796
Step-by-step explanation:
2nd term
[tex] {1.3}^{2} = 1.3 + \frac{1.3}{ \frac{10}{3} } [/tex]
[tex] {1.3}^{2} = 1.69[/tex]
add first term
[tex]27.8 + 1.69 = 29.49[/tex]
times by 0.4 or ×2/5
[tex]29.49 \times \frac{2}{5} = \frac{58.98}{5} [/tex]
[tex] = 11.796[/tex]
I need help with finding the output y when x is -4 it's on a graph
Answers
As observed from the graph, the curve is a straight line from point (-2,-1) to (-5,2).
Consider that the equation of a straight line passing through two points is given by,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}\times(x-x_1)[/tex]So the equation of the line passing through (-2,-1) and (-5,2) is given by,
[tex]\begin{gathered} y-(-1)=\frac{2-(-1)}{-5-(-2)}\times(x-(-2)) \\ y+1=\frac{3}{-3}\times(x+2) \\ y+1=-x-2 \\ y=-x-3 \end{gathered}[/tex]Note that this function is only for the interval [-2, -5].
Now, the value of 'y' corresponding to the input x=-4 is calculated as,
[tex]\begin{gathered} y=-(-4)-3 \\ y=4-3 \\ y=1 \end{gathered}[/tex]Thus, the required output is y = 1 .
point).
Questions
1. (1) How many observations are collected? (2) How many variables are collected? (3) write
I
down quantitative variables (4) write down qualitative variables
2. Describe the data visually
2.1.(1) Make a frequency tables and histogram for the “Hour” variable (bin limit = 1), and (2)
describe the shapes of the histogram
2.2.(1) Make a frequency tables and histogram for the “Type” variable, and (2) prepare a 2-D
pie chart and write down the title of chart
2.3.(1) Make a frequency tables and histogram for the “Weekday” variable, and (2) prepare a 2-
D pie chart and write down the title of chart
2.4.(1) Make a frequency tables and histogram for the “Location” variable, and (2) prepare a 2-D
pie chart and write down the title of chart
2.5.(1) Make a scatter plot of the data for the “Time” and “Hour variables, placing “Hour" on the
X-axis and "Time" on the Y-axis. Add titles and modify the default colors, fonts, etc., to make
the scatter plot easy to understand. (2) Describe the relationship (if any) between X and Y.
Weak? Strong? Negative? Positive? Linear? Nonlinear?
2.6.(1) Make a dot plot of the “Hour" variable for the “Deposit Type" variable. (2) Make a dot
plot of the "Hour" variable for the "Withdraw Type” variable. (3) Compare the shapes of both
charts
Answers
1). 68 observations
1.2) 8 variables
1.3) Quantitative Variables: Type, Time, Date, DayCode, Hour, and Amount
1.4) Qualitative Variables: Location, Weekday
Question 1) Let's examine that table to find out the number of collected observations. Counting each row, we have 68 observations. Each one informing the type, time, date, day code, weekday, Location, Hour, and Amount
1.2) We have then 8 variables namely (type, time, date, day code, weekday, Location, Hour, and Amount)
1.3) The Quantitative Variables are the ones whose entries are numerical, so examining then we can state that:
Type, Time, Date, DayCode, Hour, and Amount each and every one of them receives a numerical entry.
1.4) Qualitative or Categoricals variables are the ones whose entry is not a numerical one. So we can enlist the following ones as Qualitative:
Location
Weekday
Hence the answers are:
1). 68 observations
1.2) 8 variables
1.3) Quantitative Variables: Type, Time, Date, DayCode, Hour, and Amount
1.4) Qualitative Variables: Location, Weekday
Hi, can you help me answer this question please, thank you!
Answers
Let x be a random variable representing the blood pressures of adults in the USA. Since it is normally distributed, we would apply the formula for determining z score which is expressed as
z = (mean - population mean)/standard deviation
From the information given,
population mean = 121
Standard deviation = 16
For stage 2 high blood pressure, the probability is
P(x greater than or equal to 160). It is also equal to 1 - P(x < 160)
Thus, for x = 160, we have
z = (160 - 121)/16 = 2.4375
From the standard normal distribution table, the probability value corresponding to a z score of 2.4375 is 0.9927
P(x < 160) = 0.9927
P(x greater than or equal to 160) = 1 - 0.9927 = 0.0073
Converting to percentage, it is 0.0073 * 100 = 0.73%
b) If 2000 peaople were sampled, the number of people with stage 2 high blood pressure would be
0.73/100 * 2000 14.6
To the nearest person, it is 15 people
c) For stage 1, the probability is
P(140 < x < 160)
For x = 140,
z = (140 - 121)/16 = 1.1875
From the standard normal distribution table, the probability value corresponding to a z score of 1.1875 is 0.883
Recall, for x = 160, the probaility is 0.9927
Thus,
P(140 < x < 160) = 0.9927 - 0.883 = 0.1097
Converting to percentage, it is
0.1097 * 100 = 10.97%
d) The 30th percentile refers to all values of blood pressure below k, where k is the 30th percentile. This means that we would find
P(x < k) = 0.3
The z score corresponding to a probability value of 0.3 is - 0.52
Thus,
(k - 121)/16 = - 0.52
k - 121 = - 0.52 * 16 = - 8.32
k = - 8.32 + 121
k = 112.68
The pressure for the 30th percentile is 112.68
i need help with this question
Answers
The side AB = BD
7x + 10 = 9x - 2
SImplify for x :
Subtract 7x from both side :
7x + 10 - 7x = 9x - 7x - 2
10 = 2x - 2
Add 2 on both side :
10 + 2 = 2x - 2 + 2
12 = 2x
divide both side by 2 :
2x/2 = 12/2
x = 6
Write these numbers from least to greatest: 0, -6.1, 4, 10/2
Answers
Answer:
10/2, 4, 0, -6.1
Step-by-step explanation:
It is the only answer that makes sense.
pls mark brainliest
Answer: -6.1, 0, 4 , 10/2
Step-by-step explanation:
-6.1 is the only negative number, so it is the least. Zero comes next. 10/2 is 5, so 4 comes before it. Therefore 4 is the 3rd installment in these ordered numbers.
geometry special parallelogramsSide GH =Side JG =Side FH =
Answers
we have that
In a rhombus the length sides are congruent
the diagonals bisect each other and are perpendicular
so
If mmIn the right triangle IFJ
mtan(30)=FJ/IJ
Remember that
[tex]\tan (30^o)=\frac{\sqrt[]{3}}{3}[/tex]FJ=4
substitute the given values
[tex]\begin{gathered} \frac{\sqrt[]{3}}{3}=\frac{4}{IJ} \\ \\ IJ=\frac{12}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}}=4\sqrt[]{3} \end{gathered}[/tex]Find the length side IF
Applying Pythagorean Theorem
IF^2=4^2+IJ^2
IJ^2=48
IF^2=16+48
IF^2=64
IF=8 units
that means
side GH=8 units
side JG=side IJ=4√3 units
side FH=2*side FJ=2*4=8 units
a road is 4/7 of a mile long. a crew needs to replace 4/5 of the road. how long is the section that needs to be repaired
Answers
To solve this problem we need to find the fraction of a fraction, for that we just have to multiply them. This is done below:
[tex]\frac{4}{7}\cdot\frac{4}{5}=\frac{16}{35}\text{ of a mile}[/tex]The section is 16/35 of a mile long.
The Hornet's soccer team scored 5 goals in their last match.The other team, the Panthers, won by 3 goals. Which integerrepresents the number of goals that the Panthers won by?
Answers
The match was Hornet's vs Panthers
Hornets's scored 5 goals
Panthers won by 3 goals, this means that the panters scored 3 more goals than the Hornets.
That would be +3 goals.
help me please. using the axis of symmetry find the vertex for the follow quadratic function. f (x)=3x^2-6x+8
Answers
Answer:
[tex]P(1,5)[/tex]
Explanation: Axis of symmetry is a vertical line that makes function symmetrical along either side:
In case of parabla function or:
[tex]y(x)=3x^2-6x+8[/tex]We get axial symmetry where the first derivate is zero, and in fact, that is the x value for vertex:
Therefore:
[tex]\begin{gathered} f^{\prime}(x)=(3x^2-6x+8)^{\prime}=6x-6=0 \\ \therefore\rightarrow \\ x=\frac{6}{6}=1 \end{gathered}[/tex]And the corresponding y-value is:
[tex]f(1)=3(1)^2-6(1)+8=5[/tex]Therefore vertex is at the point:
[tex]P(1,5)[/tex]Last year, Bob had $10,000 to invest. He invested some of it in an account that paid 10% simple interest per year, and he invested the rest in an account that paid 8% simple interest per year. After one year, he received a total of $820 in interest. How much did he invest in each account?
Answers
Given:
The total amount is P = $10,000.
The rate of interest is r(1) = 10% 0.10.
The other rate of interest is r(2) = 8%=0.08.
The number of years for both accounts is n = 1 year.
The total interest earned is A = $820.
The objective is to find the amount invested in each account.
Explanation:
Consider the amount invested for r(1) as P(1), and the interest earned as A(1).
The equation for the amount obtained for r(1) can be calculated as,
[tex]\begin{gathered} A_1=P_1\times n\times r_1 \\ A_1=P_1\times1\times0.1 \\ A_1=0.1P_1\text{ . . . . .(1)} \end{gathered}[/tex]Consider the amount invested for r(2) as P(2), and the interest earned as A(2).
The equation for the amount obtained for r(2) can be calculated as,
[tex]\begin{gathered} A_2=P_2\times n\times r_2 \\ A_2=P_2\times1\times0.08 \\ A_2=0.08P_2\text{ . . . . . (2)} \end{gathered}[/tex]Since, it is given that the total interest earned is A=$820. Then, it can be represented as,
[tex]A=A_1+A_2\text{ . . . . . (3)}[/tex]On plugging the obtained values in equation (3),
[tex]820=0.1P_1+0.08P_2\text{ . . . . .(4)}[/tex]Also, it is given that the total amount is P = $10,000. Then, it can be represented as,
[tex]\begin{gathered} P=P_1+P_2 \\ 10000=P_1+P_2 \\ P_1=10000-P_2\text{ . }\ldots\ldots.\text{. .(3)} \end{gathered}[/tex]Substitute the equation (3) in equation (4).
[tex]undefined[/tex]is it true that all whole numbers are rational numbers ? why or why not
Answers
all whole numbers are rational numbers
because we can write 21 as 21/1 in rational form.
.
We can write any whole number (a) into the form of
[tex]\frac{a}{b}[/tex]where b = 1,
so all whole numbers can be written in form of rational numbers.