Answer:
S = θ R where S is the arc length and θ the arc length in radians
S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft (1 radian = 2.5 ft)
Assuming 4π3 means 4π^3
The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
What is a circle?It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).
We have Reagan rides on a playground roundabout with a radius of 2.5 feet.
We know the relation between arc length and radius of the circle:
S = R∅
Here R = 2.5 feet, and central angle ∅ = 4π/3
[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]
S = 10.47 feet ≈ 10 feet
Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
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An object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m
The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
Work done by the force experienced by the objectThe magnitude of the work done by force experience by the object is calculated as follows;
W = f.d
where;
F is the applied force (2xyi + 3yj), where x and y are in metersd is the displacement of the object = (a, b)The work done by the force is determined from the dot product of the force and the displacement of the object.
F = (2xyi + 3yj).(a + b)
W = (2abi + 3bj).(ai + bj)
W = (2a²b + 3b²)J
Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
The complete question is below:
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
How much work does the force do?
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The total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
What is work done?Work done is the force applied on a body to move it over a distance. Work done for inclined plane can be given as,
[tex]W=F\times d[/tex]
Here (F) is the magnitude of force and (d) is the distance traveled.
An object moving in the xy-plane is subjected to the force
[tex]\vec f =(2xy\hat i +3y\hat j)[/tex]
Here, x and y are in meter.
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
(a) How much work does the force do?For the first part, the particle moves along x-axis. It moves zero along x-axis. Thus, the force, as y=0.
[tex]W_1=\int\limits^a_0 {2xy\hat i} \, dx =0\\[/tex]
Now, when the object moves along y-axis,
[tex]W_2=\int\limits^a_0 {3y\hat j} \, dx \\W_2=3\int\limits^b_0 {y\hat j} \, dx\\W_2=3y(a-0)\\W_2=3ba\\W_2=3ab[/tex]
Total work done,
[tex]W=0+3ab\\W=3ab\rm\; N[/tex]
Thus, the total work done for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.
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Brody drives 180 km in two hours. How fast is he travelling?
should be in km/hour)
Answer:
90 km/h
Explanation:
we just divide the distance by the time to get the speed.
Which of the following statements about waves are true? Select all that apply.
O
Sound waves cannot travel through empty space.
Sound waves can travel through liquids.
Light waves are not true waves.
Light waves need matter in order to travel.
Waves can only move matter up and down or from side to side.
Answer:
Sound waves cannot travel through empty space
sound can travel through liqui
Sound waves cannot travel through empty space but can travel through liquids. Waves make the particles of matter up and down but do not along with them. The light waves are not true mechanical waves. Therefore, options (A), (B), (C), and (E) are correct.
What are sound waves?Sound can transmit through liquids, gases, and plasma as longitudinal waves, also known as compression waves. It needs a medium to propagate so it can be propagated through solids as both longitudinal waves and transverse waves.
Longitudinal sound waves contain alternating pressure deviations causing compression and rarefaction, while transverse waves have waves of alternating shear stress perpendicular to the direction of propagation.
Waves can make matter move up and down or from side to side but do not carry along with them. Light waves are not considered true waves because they carry without the involvement of the motion of matter.
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Gwen runs back and forth along a straight track. During the time interval 0≤t≤45 seconds, gwen’s velocity, in feet per second, is modeled by the function v given by v(t)=250sin(t2120)t 6
Gwen's position is a function of his velocity and time
Gwen's position at 45 seconds is 63.9 feet
How to determine Gwen's position at 45 seconds?The function is given as:
v(t) = 250sin(t^2/120)/(t + 6)
When t = 45, we have:
v(45) = 250sin(45^2/120)/(45 + 6)
Evaluate the sum, the exponent and the quotient
v(45) = 250sin(16.875)/(51)
Evaluate the sine ratio
v(45) = 250 * 0.2903/51
Evaluate the product and quotient
v(45) = 1.42
The position is then calculated as:
S(45) = v(45) * 45
This gives
S(45) = 1.42 * 45
Evaluate the product
S(45) = 63.9
Hence, Gwen's position at 45 seconds is 63.9 feet
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The displacement is the shortest between any two given points. The displacement of Gwen at the time period of 45 seconds is 63.9 feet.
What is displacement?The displacement is the shortest between any two given points. It is the product of velocity and time.
Given that the function of the velocity is [tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]. Therefore, substitute the value of t as 45, to know the velocity of Gwen at 45 seconds,
[tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]
[tex]v(45)=\dfrac{250\sin\left(\frac{45^{2}}{120}\right)}{\left(45+6\right)}\\\\v(45) = 1.42[/tex]
Since displacement is the product of velocity and time, therefore, the displacement is equal to,
[tex]s = v \times t\\\\s = 1.42 \times 45\\\\s = 63.9\rm \ feet[/tex]
Hence, the displacement of Gwen at the time period of 45 seconds is 63.9 feet.
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You are part of a police unit that has found a powder in a suspect's home. You think it might be a new drug called XYZ. XYZ is an ionic compound that dissolves in water. However, what you think might be a drug may just be salt. Unfortunately there seems to be iron fillings and sand mixed in with the white powder. Your job is to isolate the white powder before sending it to the police lab to be tested to determine if it is salt or XYZ. Give step by step directions on exactly how you will separate your mixture of white powder, iron fillings, and sand.
The steps in the separation include;
Use of magnetaddition of water and filtrationEvaporationSeparation techniquesSeparation techniques has to do with how to obtain a substance in the presence of other substances. In this case, we have the substance XYZ mixed with iron filling and sand.
The separation process begins by using a magnet to remove all the iron fillings. Secondly, water is added and the substance XYZ dissolve in water since it is ionic. The sand can be separated form the solution by filtration.
Lastly, the solution is evaporated and the pure XYZ is obtained and sent to the police lab for analysis.
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A hot tungsten filament emit electromagnetic radiation within
A hot tungsten filament emit electromagnetic radiation within the bulb because the tungsten is present within the bulb.
What temperature does a tungsten filament glow at?Due to its high melting point, tungsten can be heated to 3000°C where it glows white hot providing very good brightness due to the presence of argon.
So we can conclude that a hot tungsten filament emit electromagnetic radiation within the bulb.
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Electromagnetic radiation is made up of electromagnetic field waves. A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
What is electromagnetic radiation?Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are all examples of electromagnetic waves.
When tungsten is heated to a temperature of around 3000 °C, the tungsten starts to emit lights. Tungsten when used in a bulb as a filament then because of its high melting point when electricity is passed through it, it starts to shine white-hot and provides extremely good brightness due to the presence of argon.
Hence, A hot tungsten filament emits electromagnetic radiation in the presence of Argon.
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A fish swimming at a constant speed of 0.5 m/s suddenly notices a shark
appear behind it. Five seconds later, the fish is swimming in the same
direction at a speed of 3.5 m/s. Calculate the fish's acceleration?
PLEASE HELP <33
Use F = 1/T as your basis:
10. A stroboscope is set to flash every 8.00×10−5s. What is the frequency of the flashes?
The answer is 12,500 Hz but please show your work.
Now
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{8\times 10^{-5}}[/tex]
[tex]\\ \rm\rightarrowtail \nu=0.125(10^5)[/tex]
[tex]\\ \rm\rightarrowtail \nu=12500s^{-1}[/tex]
[tex]\\ \rm\rightarrowtail \nu=12500Hz[/tex]
A laser beam is used to levitate a metal disk against the force of earth's gravity.
(a) derive an equation giving the required intensity of light, i, in terms of the mass m of the disk, the gravitational acceleration g, the speed of light c, and the cross-sectional area of the disk a. assume the disk is perfectly reflecting and the beam is directed perpendicular to the disk. (do not substitute numerical values; use variables only.)
i =
(b) if the disk has mass 3.89 g and radius 2.40 cm, find the necessary light intensity.
(c) give two reasons why using light pressure as propulsion near earth's surface is impractical.
The necessary light intensity of the disk if the disk has mass 3.89 g and radius 2.40 cm is 6.483 x 10^12cd.
Calculations and Parameters:a. Given that:
i= intensity of light m= mass of disk g= gravitational acceleration c= speed of light a= cross-sectional area of the diskI = P/A
= Force x Speed/Area
Gravitational force, F= GM1M2/r^2
F= ma, F= mg
I= mg x c/q
That is,
i= mass x gravitational acceleration x speed/area
b.
Mass= 3.89g
Radius, r= 2.40cm
i=?
i= mg x c/a
Speed of light= 3.0 x 10^8 m/s
Area, a= /pi r^2
= 3.142 x (0.024)^2
= 3.142 x 0.000576
= 0.0018m^2.
i= 3.89 x 10 x 3.0 x 10^8/0.0018
i= 6.483 x 10^12cd.
c. Light has no mass, therefore, it lacks momentum and cannot exert pressure for propulsion of materials.
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Hello people ~
The sound in the audible range is called
(a) ultrasonic sound
(b) sonic sound
(c) subonic sound
(d) light sound
Answer:
Sonic sound
Human audible range is from 20Hz to 20000Hz or 20kHzAbove or beneath that range we can't hear .Bats can hear below it and dogs can hear above itAn apple weighing 1 N fall a distance of 1 m how much work is done on the Apple by the force of gravity
Explanation:
work = Force×distance
Force in this question is equal to the weight (force of gravity)
work = 1 × 1 = 1 J
Jole is the unit of work
Hydroelectric dams generate electricity by a. water impoundment, in which dam operators control the rate of water flow to turbines. b. converting the kinetic energy of the water impounded behind a dam into potential energy. c. using generators that are placed on the bottom of a river. d. using the energy of the river to produce steam. e. using run-of-the-river systems, in which turbines are placed into the natural water flow.
Hydroelectric dams generate electricity makings use of run-of-the-river systems, in which turbines are placed into the natural water flow.
What are Hydroelectric dams?Generally, Hydroelectric dams produce electricity by making use of turbines and generators, in a process where mechanical energy is produced when moving water turns the rotors of a turbine.
In conclusion, Hydroelectric dams use run-of-the-river systems, in which turbines are placed into the natural water flow.
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Emma wants to drive forward in her car. What does she need to do other than place her vehicle's gear in Drive and accelerate
She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate
How we drive a car?We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.
So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.
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Find the kinetic energy k of the block at the moment labeled b. express your answer in terms of k and a.
The position of the object can be used to find the kinetic energy in terms of k and a.
What is kinetic energy?The term kinetic energy refers to the energy of an object that is in motion. The question is incomplete hence the syetem is not shown and the value of the kinetic energy can not be found in terms of k and a.
Hence, when the system is shown, we can look at the position of the system and use it to obtain the value of the kinetic energy in terms of k and a.
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Answer:
K = 3/8k(A)^2
Explanation: Potential Energy --> Conservation of Energy
Because block B is at A/2, U = 1/2k(A/2)^2 which equals U = 1/8k(A)^2.
Now that you have the equation for potential energy, you can find kinetic energy in terms of the spring constant (k) and amplitude (A).
K = 3/8 k A^2
My Noacid performs a physics lab to determine the speed of sound inside a tube. She blocks off one end of the 120. 0 cm tube with a book and places a microphone at the other end. When she snaps her finger she determines the time for the sound to get back to the microphone is. 00695 s. What was the speed of sound that day
The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
Speed of the sound
The speed of the sound wave can be determined by applying echo formula as shown below;
v = 2d/t
where;
d is the distance traveled by the sound wave = 120 cm = 1.2 mt is the time when the sound wave was heard = 0.00695 sSubstitute the given parameters and solve for speed.
v = (2 x 1.2)/(0.00695
v = 345.32 m/s
Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.
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Extension Question
If the scale used to measure the mass of the unknown material maxes out at a
lower value than the actual mass of the material, then...
o the measured specific heat will be greater than the actual specific heat.
o the measured specific heat will be less than the actual specific heat.
The measured specific heat will be less than the actual specific heat if a lower value is gotten than the actual mass.
What is Specific heat capacity?This is defined as the quantity of heat needed to raise a substance's temperature by 1 degree Celsius.
If a substance has a low specific heat capacity , it loses water easily which makes the mass when measured to be smaller than the actual value.
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Which property of the water molecule causes two water molecules to be attracted to each other? (2 points)
Polar bonds between H and O atoms
Ionic bonding between water molecules
Hydrogen bonds between H atoms
Ionic bonding between O atoms
Answer:
hydrogen bonding between H atoms.
Explanation:
How long does it take for jupiter to rotate on its axis.
Answer:
10 hours.
Every 10 hours, Jupiter will rotate at least once. It takes 12 years for Jupiter to make a revolution. This is because Jupiter is a gas, non-solid planet and also has a very large mass.
Answer: 10 Hours
Explanation:
Jupiter is the fastest spinning planet in the solar system
What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Answer:
ν = E/h = 4.56x10-19 J / 6.626x10-34 Jsec-1
ν = 6.88x1014 s-1
Explanation:
The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
What is a frequency?The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.
Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,
[tex]\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma = 6.88 \times 10^{14}\ s^{-1}[/tex]
Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
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Given the velocity v= ds dt and the initial position of a body moving along a coordinate line, find the body's position at time t
For the body's position at time t is mathematically given as
s(t)=4.9t^2+5t+16
What is the body's position at time t
Generally, the equation for the velocity is mathematically given as
v=ds/dt
v=9.8t+5 as velocity
s=4.9t^2+5t+c
s(0)=16
16=c
s(t)=4.9t^2+5t+16
In conclusion the body's position at time t
s(t)=4.9t^2+5t+16
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The body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
What is the distance?A numerical representation of the distance between two items or locations is called distance. A physical length or an approximation based on other considerations in physics or common usage can be referred to as distance.
We have:
[tex]\rm v = \frac{ds}{dt}[/tex]
[tex]\rm v = 9.8t+5[/tex] is the velocity
[tex]\rm s = 4.9t^2+5t+c[/tex] is the speed
At t = 0 s(0) = 16
16 = c
[tex]\rm s = 4.9t^2+5t+16[/tex]
Thus, the body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.
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Which describes the vector calculation giving the magnetic force on a charged particle moving through a magnetic field?.
Which describes the vector calculation giving the magnetic force on a charged particle moving through a magnetic field? It is the cross product of the velocity vector and the magnetic field vector, which gives a vector perpendicular to those vectors.
project: weather forcasting
Instructions
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B that is the correct answer
Which terrestrial planet exhibits retrograde rotation?.
Answer:
Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.
If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars
(The planet will be on the side of the earth that is opposite that of the sun)
The rotational inertia of a sphere of mass m and radius r about a diameter is 25mr2. The rotational inertia about an axis tangent to the sphere is
The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².
Parallel axis theoremAccording to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.
The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²
The product of its mass and the square of the distance between the two parallel axis = MR²
Rotational inertia about an axis tangent to the sphereMoment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²
= ⁷/₅MR²
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The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].
What is a moment of inertia?The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
M is the sphere's mass.
R is the radius of a sphere
According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;
[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]
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Part B
At your sink, turn on your faucet slowly, until you have achieved a steady drip, drip, drip of lukewarm water. Make sure you can visually see and count the drips. Align the center of the bar of soap with the dripping water and set it down. Make sure the soap is in a sturdy location and does not move during the experiment. The soap represents a rock, and the dripping faucet represents precipitation.
While the soap is being weathered, calculate the number of drips that hit it in a minute. Do this by using your stopwatch to count the number of drips that occur in 10 seconds, and then multiply that number by 6 (because there are 60 seconds in a minute, 6 × 10 = 60). What is the number of drips hitting your bar of soap per minute?
The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips
Control ExperimentationData
Number of Drips Recorded = 20 drips per 10 secondsIn one minute(60 seconds), the number of drips recorded will beCalculation for the number of drips per minute
= 20*6
= 120 drips
What is Control Experiment
Control experiment are carried out to minimize the effects of variables other than the independent variable
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When do things move faster? Day or night?
I believe most activity takes place during daylight hours.So the life move fast in day. If we talk about the -Sound. At night , the air is denser due to humidity (obviously nights are cooler). sound requires medium to travel and so DENSER the medium,FASTER the sound travels.
meters/second?
A car accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is what meters/second squared
Answer:
the acceleration of the car is 3 m/s².
Explanation:
The wavelengths of visible light vary from about 300 nm to 700 nm. what is the range of frequencies of visible light in a vacuum?
a) 90 hz to 210 hz
b) 9*10^10 hz to 2.1*10 hz
c) 4.28*10^5 hz to 1*10^6 hz
d) 4.29*10^14 hz to 1*10^15 hz
The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
Frequency of the visible light
The frequency of the visible light is determined by using the following formulas relating speed of light and frequency of light.
c = fλ
where;
c is speed of lightf is frequency of lightλ is the wavelengthFrequency of light at 300 nm wavelengthf = c/λ
f = (3 x 10⁸) / (300 x 10⁻⁹)
f = 1 x 10¹⁵ Hz
Frequency of light at 700 nm wavelengthf = c/λ
f = (3 x 10⁸) / (700 x 10⁻⁹)
f = 4.29 x 10¹⁴ Hz
Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
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Should the kinetic coefficient of friction and the static coefficient change with a different mass
Explanation:
No. Surface contact area also no. The main issue is the types of materials in contact. Surface roughness somewhat matters. Certain surfaces such as ice are special in that pressure melts the ice.
How are physical descriptions and physical properties similar?
Answer:
A physical property and physical description are similar because the changes in a physical property of a system can be used to describe its changes between momentary states.
A physical property is is defined as any property that is measurable, and also whose value describes a state of a physical system.
Examples of physical properties include;
density,
hardness,
melting and boiling points, and
thermal conductivity
A physical description is observed physical properties usually represented by a specific class, compound or elements.
Both physical property and physical description are similar because the changes in a physical property of a system can be used to describe its changes between momentary states.
Answer:
A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.