Answer:C
Explanation:
I did the test
a sound wave has a frequency of 85 Hz and a wavelength of 4.2 m. Then the wave speed of the sound wave is 20.23 m/s. Hence option D is correct.
What is wave ?Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.
The wave speed is given by,
c = νλ
where λ is wavelength, ν is frequency.
Given,
frequency ν = 85 Hz
wavelength λ = 4.2 m
The speed of the wave,
c = 85 × 4.2 = 20.23 m/s
Hence option D is correct.
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How fast does the moon rotate around the Earth?
The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.
Answer:
approximately 27 days
The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis.
Explanation:
What are the benefits of evolution for the human population?
Answer:
I hope you fall down a 40 floor hotel resort onto the porch, and explode into the gushing body you are!
Explanation:
The brakes of a car are applied, causing it to slow down at a rate of 10 ft/s2. Knowing that the car stops in 300 ft, determine
(a) how fast the car was traveling immediately before the brakes were applied,
(b) the time required for the car to stop.
Answer:
(a) The velocity of the car before the brakes were applied is 77.46 ft/s
(b) The time required for the car to stop is 7.8 s
Explanation:
Given;
acceleration of the car, a = 10 ft/s²
distance traveled by the car, d = 300 ft
(a) the velocity of the car before the brakes were applied is given;
v² = u² + 2ad
v² = 0 + 2(10 x 300)
v² = 6000
v = √6000
v = 77.46 ft/s
(b) the time required for the car to stop
d = ut + ¹/₂at²
d = 0 + ¹/₂at²
d = ¹/₂at²
t² = 2d / a
t = √ ( 2d / a)
t = √ ( 2 x 300 / 10)
t = 7.8 s
Therefore, the time required for the car to stop is 7.8 s
The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.
Using the formula:
v² = u² + 2as
Where S is the distance = 300 ft, u is the initial velocity, a is the acceleration = -10 ft/s², v is the final velocity = 0 ft/s (stops)
0² = u² + 2(-10)(300)
0 = u² - 6000
u² = 6000
u = 77.46 ft/s
b)
v = u + at
0 = 77.46 - 10t
t = 7.75 s
The speed of the car immediately before the brakes were applied was 77.46 ft/s and it took 7.75 s for the car to stop.
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1. What does the horizontal axis ordinarily oscilloscope? The vertical measure on an axis?
2. What frequency should the function generator be set to if period of 25 us is a desired?
Answer:
vertical axis measures voltage while
The horizontal axis of an oscilloscope measures time
2) we are told that Period
T = 25 microseconds = 25*10^-6 s
So we also know that
frequency f = 1/T
So
= 1/(25*10^-6)
= 40,000 Hz
Translate the following sentence into an equation. "The distance traveled is the speed multiplied by the time." a) d = v * t a) d = v * t b) Δx = v * Δt c) v = d/t d) d=Δx*t
The correct answer is A) d = v * t
Explanation:
When writing an equation the goal is to represent the equality between different mathematical expressions or elements. Due to this, in an equation the symbol = is always used. Additionally, to translate a sentence into an equation, the variables should be represented using numbers or letters.
For example, in the sentence "The distance traveled is the speed multiplied by the time" there are three variables mentioned: distance, speed, and time. Also, these can be represented through the letters d (distance), v (speed or velocity), and t (time). Besides this, the sentence explains speed should be multiplied by time, which means it should be written as v × t or v * t and this is equivalent (=) to distance or t. According to this, the final equation would be d = v * t.
A woman walks 150 min 45 seconds. What was her average speed?
Answer:
0.3
Explanation: when you average out the number sthat is the answer you get
Write the following numbers in proper scientific notation:
1.) 36513
2.) 0.00050
3.) 8004
4.) 0.00000000406
Answer:
0.00050, 0.000000000406, 36513
In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a speed of 95 m/s. The planes maximum magnitude of acceleration is 7.07 m/s2 as it comes to a stop. (a) What is the minimum time interval needed for this plane to stop?
Answer:
t = 13.43 s
Explanation:
In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:
Vf = Vi + at
where,
Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)
Vi = Initial Velocity of the Plane = 95 m/s
a = deceleration of the plane = - 7.07 m/s²
t = minimum time interval needed to stop the plane = ?
Therefore,
0 m/s = 95 m/s + (- 7.07 m/s²)t
t = (95 m/s)/(7.07 m/s²)
t = 13.43 s
Describing Forms of Energy
Match each form of energy with its description.
nuclear energy
found when internal energy is
transferred
thermal energy
te
found in the nucleus of an atom
electrical energy
found in the flow of electrical charges
found in the bonds between atoms
chemical energy
Answer:
electrical energy-found in the flow of electrical charges
chemical energy-found in the bonds BTW atoms
thermal energy-found when internal energy is transferred
nuclear energy-found in the nucleus of an atom.
The correct match is: nuclear energy: found in the nucleus of an atom, thermal energy: found when internal energy is transferred, electrical energy: found in the flow of electrical charges, chemical energy: found in the bonds between atoms.
Nuclear energy: This type of energy is obtained from an atom's nucleus. It is released by processes such as nuclear fission or fusion, which utilise the energy held inside atomic nuclei.
Thermal energy is the energy associated with an object's or a system's temperature. When there is a temperature differential, it is a type of internal energy that is exchanged between objects.
Electrical energy is associated with the passage of electric charges, such as electrons, via a conductor.
Chemical energy is contained in the bonds that connect atoms and molecules. When these connections are broken or created, it is released or absorbed during chemical processes.
Thus, this can be the match for the given forms of energy.
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Which statement illustrates how engineering has influences society
Answer:
I think C but I'm not sure
The statement that illustrates how engineering has influences society is nuclear power plants provide cheap electricity to power people's homes. The correct option is A.
This claim serves as an example of how engineering has impacted society. Because they offer a practical and economical source of electricity for lighting up homes and other infrastructure, nuclear power plants have had a big impact on society.
The ability to create electricity from the energy held in atoms thanks to improvements in nuclear technology has boosted the availability and affordability of power for users.
This illustrates how advances in engineering can influence and enhance how society fulfils its energy needs.
Thus, the correct option is A.
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Summarize why psychology is considered a science.
because it uses a systematic method of asking and answering problems, and it attempts to develop solution to psychological problems.
Answer:
it uses a systematic method of asking and answering problems,
Explanation:
Air that initially occupies 0.22 m3 at a gauge pressure of 86 kPa is expanded isothermally to a pressure of 101.3 kPa and then cooled at constant pressure until it reaches its initial volume. Compute the work done by the air. (Gauge pressure is the difference between the actual pressure and atmospheric pressure.)
Answer:
total work done = -5960.8 J
Explanation:
given data
initial volume v1 = 0.22 m³
initial pressure p1 = 86 kPa
final pressue p2 = 101.3 kPa
solution
we apply here isothermal expansion that is express as
p1 × v1 = p2 × v2 ......................1
put here value
86 × 0.22 = 101.3 × v2
v2 = 0.1867 m³
and
work done will be here
w1 = p1 × v1 × ln([tex]\frac{p1}{p2}[/tex]) ....................2
w1 = 86 × 10³ × 0.22 × [tex]ln(\frac{86}{101.3})[/tex]
w1 = -3.097 × 10³ J
and
it is cooled to initial volume at constant pressure so here work done will be
w2 = p(v2 - v1) .................3
w2 = 86 × 10³ × ( 0.1867 - 0.22 )
w2 = -2863.8 J
so
total work done is
total work done = w1 + w2
total work done = -3097 + -2863.8
total work done = -5960.8 J
The fastest crossing of the Atlantic Ocean by an ocean liner was made on July 7,
1952. The ship, the S.S. United States, traveled 4727 km east by northeast in 3 days,
10 hours, and 40 minutes. Assume that the ship had traveled the same speed, but
directly east. What would the velocity of the S.S. United States be in kilometers per
hour?
Answer:
The speed would be about 80.8 km/h
Explanation:
Notice that the ship really traveled northeast (at 45 degrees north from East) covering eastwards 4727 km.
That means (by using the East projection in a right angle triangle) that the total distance was (the hypotenuse of the right angle) :
[tex]Distance= \frac{4727}{cos(45^o)} \approx 6685\,\,km[/tex]
Then the velocity of the ship was the quotient between this distance divided the time it took. Now,notice that the time is given in days, hours, and minutes, but we need the final velocity answer in km per hour. Then we reduce the given time to hours:
3 days + 10 hours + 40 min = 3 (24) h + 10 h + (40/60) h = 248/3 hours which is approximately 82.7 hours.
Then this record speed is the quotient:
6685 km / 82.7 h = 80.8 km/h
In which direction does centripetal force act on an object? in the opposite direction of the tangential speed of the object in the same direction of the tangential speed of the object toward the outside of the circle in which the object is moving toward the center of the circle in which the object is moving
Answer:
towards the center of the circle
(which appears to be the last option in your list of possible answers)
Explanation:
The centripetal force points always towards the center of the circle described by the object moving.
The direction of centripetal force acting on an object is always towards the center of the circle in which the object is moving.
The given problem is based on the concept and fundamentals of centripetal force. When an object is known to move around a circular path, then there is a force comes to play acting towards the centre of circular path, known as centripetal force.
In other words, the centripetal force is also known termed as the force that tends to act on a body moving in a circular path and is directed towards the centre around which the body is moving.For example - Motion of merry go round and the motion of roller skates on the rink floor are the examples of centripetal force, where the force always acts in the direction, center of the circular track.Thus, we can conclude that the direction of centripetal force acting on an object is always toward the center of the circle in which the object is moving.
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An airplane with a hot-wire anemometer mounted on its wing tip is to fly through the turbulent boundary layer of the atmosphere at a speed of 50 m/sec. The velocity fluctuations in the atmosphere are of order 0.5 m/sec, the length scale of the large eddies is about 100 m. The hot-wire anemometer is to be designed so that it will register the motion of the smallest eddies.What is the highest frequency the anemometer will encounter
Answer:
0.55 hz
Explanation:
Given that the plane fly through the turbulent boundary layer of the atmosphere at a speed of 50 m/sec. And the velocity fluctuations in the atmosphere are of order 0.5 m/sec, the length scale of the large eddies is about 100 m.
The maximum speed attained will be
Maximum speed = 50 + 0.5 = 5.5 m/s
The Length = 100m
Speed = FL
Where F = frequency
Substitute speed and distance length into the formula
55 = 100F
F = 55/100
F = 0.55 Hz
Therefore, the highest frequency the anemometer will encounter will be 0.55 Hz
Answer:
40079 Hz
Explanation:
1. The first step is to calculate energy dissipation ∈=u^3/l and here u is fluctuating velocity
∈=(0.5^3)/100 = 0.00125 m^2/s^3
2. Find out the length scale of the small eddies
η=(viscosity/∈)^1/4
η=(1.470e-5/0.00125)^1/4 = 0.00126 m
3. The frequency associated with these small-scale eddies will be the greatest frequency the anemometer will encounter, thus:
u_max=f_max * η
u_max = u + u' = 50+0.5=50.5 m/s
f_max = u_max/η = 50.5/0.00126 = 40079 Hz
This is the heighest frequency the anemometer will encounter.
Two balls are thrown against a wall. Ball 1 has a much higher speed than ball 2.
Explain how the energy of the two balls is different.
Let both the balls have the same mass equals to m.
Let [tex]v_1[/tex] and [tex]v_2[/tex] be the speed of the ball1 and the ball2 respectively, such that
[tex]v_1>v_2\;\cdots(i)[/tex]
Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.
The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, [tex]v[/tex], is [tex]\frac 12 m v^2[/tex]
and the potential energy is due to the change in height is [tex]mgh[/tex] [where [tex]g[/tex] is the acceleration due to gravity]
So, the total energy of ball1,
[tex]=\frac 12 m v_1^2 + mgh\;\cdots(ii)[/tex]
and the total energy of ball1,
[tex]=\frac 12 m v_2^2 + mgh\;\cdots(iii)[/tex].
Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)
So, [tex]\frac 12 m v_1^2 >\frac 12 m v_2^2[/tex]
Now, from equations (ii) and (iii)
The total energy of ball1 hi higher than the total energy of ball2.
how do accelerating objects act
Explanation:
They speed up, slow down, or change direction.
Answer:In order for object to be accelerating, the net force (sum of all forces) acting on the object has to be non-zero. According to Newton's Second Law of Motion, Force = Mass x Acceleration. ... If the object is sitting motionless on the ground, then the net force (sum of all forces) acting on it is zero.
Explanation:
(7%) Problem 14: A robot cheetah can jump over obstacles. Suppose the launch speed is vo = 4.74 m/s, and the launch angle is 0 = 25.5
degrees above horizontal.
What is the maximum height in meters?
Is the following hypothesis scientific? Why? "Intelligent life exists on other planets
somewhere in the universe."
Answer:
yes
Explanation:
The hypothesis is scientific because there is no solid evidence to draw out the theory. Therefore the idea of other intelligence on other planets is scientific until found unworthy or scientifically proven wrong enough. Hope this helps a little:)
A car moves from rest with an acceleration of 0.2ms
Find its velocity when it has moved a
distance of 50m
From the problem we notice that the question
does not involver. Therefore, the required equation
is)
Explanation:
Given:
Δx = 50 m
v₀ = 0 m/s
a = 0.2 m/s²
Find: v
The problem does not involve time. Therefore, the required equation is:
v² = v₀² + 2aΔx
Plug in values and solve:
v² = (0 m/s)² + 2 (0.2 m/s²) (50 m)
v = 4.47 m/s
The velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
To find the velocity of the car when it has moved a distance of 50 meters, we can use the following equation of motion:
v² = u² + 2as
Where:
v = final velocity
u = initial velocity (which is 0 in this case as the car starts from rest)
a = acceleration
s = distance traveled
Plugging in the values into the equation:
v² = 0² + 2(0.2)(50)
v² = 0 + 20
v² = 20
Taking the square root of both sides:
v = √20
v = 4.47 m/s
Therefore, the velocity of the car when it has moved a distance of 50 meters is approximately 4.47 m/s.
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A cheetah accelerates from rest at a rate of 9 m/s^2 for 3s. How far does it travel in this time? Assume the cheetah moves in a
straight line.
a) 27.0 m
b) 40.5 m
c) 13.5 m
d) 54.0 m
Answer:
b) 40.5 m
Explanation:
Given:
v₀ = 0 m/s
a = 9 m/s²
t = 3 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (3 s) + ½ (9 m/s²) (3 s)²
Δx = 40.5 m
Add these two velocity vectors to find the magnitude of their resultant vector. A. 4.6 meters/second B. 0.8 meters/second C. 2.2 meters/second D. 7.0 meters/second
The magnitude of the resultant vector is D, 7.0 meters/second, and the direction is to the left.
How to find magnitude?To add these two velocity vectors, find the magnitude and direction of each vector. The magnitude of the first vector is 5.8 meters/second, and the direction is to the right. The magnitude of the second vector is 1.2 meters/second, and the direction is to the left.
To find the magnitude of the resultant vector, add the magnitudes of the two vectors. The magnitude of the resultant vector is 5.8 meters/second + 1.2 meters/second = 7.0 meters/second.
To find the direction of the resultant vector, find the angle between the two vectors. The angle between the two vectors is 180 degrees. The direction of the resultant vector is 180 degrees from the first vector, which is to the left.
Therefore, the magnitude of the resultant vector is 7.0 meters/second, and the direction is to the left.
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A student has a displacement of 304 m north in 180 s. What was the student's average velocity?
Given : Unknown: Equation: Substitution: Solve:
Subject is Physics
Answer:
v = 1.69 m/s
Explanation:
Given that,
Displacement of the student is 304 m due North and it takes 180 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
[tex]v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s[/tex]
Hence, the student's average velocity is 1.69 m/s.
The student's average velocity will be "1.69 m/s".
Displacement and Velocity:The main distinction between velocity as well as speed would be that velocity, like speed, seems to have a direction and therefore it is a vector quantity.
This same distance travelled together along a straight line throughout a particular direction from either the beginning point is defined as displacement. Because displacement has both size as well as the direction, it's a vector quantity.
Given values:
Displacement, d = 304 mTime, t = 180 sWe know,
The velocity (v):
= [tex]\frac{Displacement}{Time}[/tex]
By substituting the values, we get
= [tex]\frac{304}{180}[/tex]
= [tex]1.69 \ m/s[/tex]
Thus the answer above is correct.
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Physics question URGENT PLEASE!!!
[tex]\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}[/tex]
Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.
Which of the following is not a type of kinetic energy
Forces of 6lbs and 4lbs act on an object. What is the maximum and minimum net force on the object? Explain your answer.
i cant understand your question define briefly
Do you think a hurricane can be considered to be a heat machine? Why?
Answer:
No
Explanation:
Hurricanes always do not bring heat. For example, Hurricane Sandy brought snow.
it is required that an object weighing 8N be moved up ward at an acceleration of 2m/s what is the upward force needed
Answer:
F = 1.6 N
Explanation:
Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:
F = ma
where,
F = Force Required to Move the Object Upward = ?
m = mass of object
a = upward acceleration = 2 m/s²
but, we know that weight of object is given as:
Weight = mg
8 N = m(9.8 m/s²)
m = 0.8 kg
using values in the equation:
F = (0.8 kg)(2 m/s²)
F = 1.6 N
Which statement describes a question that can guide the design of a
scientific investigation?
A. It asks about a cause-and-effect relationship between two
variables.
B. It asks about how the observations will be organized,
C. It asks about whether a controlled variable is necessary.
D. It asks about the preferred outcome of the investigation.
Answer:
The correct answer is:
It asks about a cause-and-effect relationship between two variables (A)
Explanation:
Scientific investigations are aimed as developing a hypothesis and proving the validity or not of the hypothesis developed. In order for these hypotheses to be tested, experiments must be done, and the experiments are designed based on the identification of a cause-and-effect relationship existing between two variables to be tested, where the "cause" is varied to various degrees and the "effect" of the variation is recorded. Therefore, knowing the cause-and-effect relationship will guide the experimental design, which will be aimed at manipulating the causes to see how these manipulations affect the second variable.
Answer:
A
Explanation:
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (about 2.0×1012.0×101 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 295.0295.0 × 106 m and the planet has a radius of 3.603.60 × 106 m, calculate the moon's radial acceleration acac .
Answer:
The value is [tex]a_r = 3.81 *10^{-3} m/s^2[/tex]
Explanation:
Generally the moon's radial acceleration is mathematically represented as
[tex]a_r = r * w^2[/tex]
Here [tex]w[/tex] is the angular velocity which is mathematically represented as
[tex]w =\frac{2 \pi }{ T}[/tex]
substituting [tex]1760 * 10^3 \ seconds[/tex] for T(i.e the period of the moon ) we have
[tex]w =\frac{2 * 3.142 }{ 1760 * 10^3}[/tex]
=> [tex]w = 3.57 *10^{-6} \ rad/s [/tex]
From the question r(which is the radius of the orbit ) is evaluated as
[tex]r = R + H[/tex]
substitute [tex]3.60 * 10^6 m[/tex] for R and [tex]295.0 * 10^6 \ m[/tex] H
[tex]r = 295.0 * 10^6 +3.60 * 10^6[/tex]
=> [tex]r = 2.986 *10^{8} \ m [/tex]
So
[tex]a_r = 2.986 *10^{8} * ( 3.57 *10^{-6} )^2[/tex]
[tex]a_r = 3.81 *10^{-3} m/s^2[/tex]