The correct option is d; A is false but R is true , Examples include wastewater (sometimes called effluent) released by a manufacturing, an oil refinery, or a wastewater treatment facility, as well as pollution from leaky septic systems, chemical and oil spills, and unlawful dumping.
What type of water pollution is sewage?Most sewage is liquid waste. It is the waste water created by human activity from places like homes, businesses, hospitals, and workplaces that includes both liquid and solid wastes. Water, which contains dissolved and suspended pollutants, makes up the majority of it. Wastewater arises from typical life processes: bathing, toilet flushing, laundry, dishwashing, etc.
It emanates from home and domestic sources. Commercial wastewater originates from non-domestic sources such beauty parlors, taxidermie, furniture restoration, music instrument washing facilities, and car body shops.
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Full Question ;
The following question consists of two statements- Assertion (A) and Reason (R), An the question by selecting the suitable option given below. Assertion (A): Sewage is the dirty water that is generated by human activities.
Reason (R): Biogas is used to generate electricity.
(a) both A and R are true, and R is the correct explanation of A
(b) both A and R are true, and R is not the correct explanation of A
(c) A is true but R is false.
(D) A is false but R is true
Enter your answer in the provided box.
Using the balanced equation for fermentation answer the following questions.
C6H12O6(aq)-> 2 C2H6O(aq) + 2 CO2(g)
How many grams of glucose are needed to form 2.0 mol of ethanol?
Answer:
Looking at the balanced equation for fermentation:
C6H12O6(aq) -> 2 C2H6O(aq) + 2 CO2(g)
We can see that 1 mol of glucose (C6H12O6) produces 2 mol of ethanol (C2H6O).
So, to form 2.0 mol of ethanol, we would need:
2.0 mol ethanol x (1 mol glucose / 2 mol ethanol) = 1.0 mol glucose
Therefore, we would need 1.0 mol of glucose to form 2.0 mol of ethanol.
To convert from moles of glucose to grams, we can use the molar mass of glucose, which is approximately 180.16 g/mol.
Mass of glucose needed = 1.0 mol x 180.16 g/mol = 180.16 g
Therefore, we would need 180.16 grams of glucose to form 2.0 mol of ethanol.
How many moles of copper 2 sulphate are present in the 100cm3 solution
We have 0.34 L of the remedy. A type of concentration known as % mass/volume shows how much solute is present in 100 mL of solution.
What is an example of mass to volume?Volume is the amount of space a thing occupies, whereas mass is the amount of stuff it contains. Example: Basketball and bowling balls have roughly the same volume, but the bowling ball has a lot more mass. Make sure you understand the distinction between mass and weight before utilising measurement words.
In this instance, there are 100 mL of solution and 25 g of CuSO4.
We can use the rule of three to determine the solution:
100 mL of solution holds 25 g of solute.
Our 85 g may fit in (85.100) /25, or 340 mL.
Volume is converted from mL to L.
1L / 1000mL = 0.34 L 340ml
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100.0 g of sample A has 77.6 g Xe
and 22.4 g F.
What is the percent by mass of Xe
in sample A?
The percent by mass of Xe in sample A is calculated as 77.6%.
What is the percent by mass?To calculate the mass percent of an element in compound, we divide the mass of element in 1 mole of compound by the molar mass of compound and multiply the result by 100.
The percent by mass of Xe in sample A can be calculated using the following formula:
percent by mass of Xe = (mass of Xe / total mass of sample) x 100%
Given mass of Xe is 77.6 g and total mass of sample is 100.0 g.
Putting these values into the formula, we get:
percent by mass of Xe = (77.6 g / 100.0 g) x 100% = 77.6%
Hence, the percent by mass of Xe in sample A is 77.6%.
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What is the process of making an object by adding new layers onto one another?
In chemical, deposition is the process of building an object by putting fresh layers on top of one another.
What is deposition?Deposition includes the direct transformation of a vapor into a solid without first going through the liquid phase. A layer of substance is added to the surface of a substrate during deposition; the substrate might be solid or liquid.
This method is employed in many different contexts, including the creation of protective coatings, optical coatings, and thin films for electrical devices. A number of methods, such as atomic layer deposition, physical vapor deposition, and chemical vapor deposition (CVD), can be used to deposit material (ALD).
What is Vaporizing?A phase change from the liquid phase to the vapor phase is called vaporization (or vaporization) of an element or molecule. Both evaporation and boiling result in sublimation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.
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the density of a fluid is given by the empirical equation p=70.5exp
the density fluid is given by the empirical equation p=70.5exp (82700000p) where rho is density (lbm/ft3)and p is the pressure (lbf/in2) a, what are the unit of 70.5 and 82700000
Answer:
The density equation is given by:
p = 70.5 * exp(82700000 * p)
where p is the pressure in pounds per square inch (lbf/in²) and ρ is the density in pounds per cubic foot (lbm/ft³).
To determine the units of the constants 70.5 and 82700000 in short, we can use dimensional analysis.
The unit of the exponential term is dimensionless, so we only need to consider the units of the constant term.
The unit of the density (ρ) is lbm/ft³, and the unit of the pressure (p) is lbf/in².
So, we can write the equation as:
ρ = (70.5 lbm/ft³) * exp(82700000 * p)
To get the units of the constant 70.5, we can divide both sides by the exponential term and simplify:
ρ / exp(82700000 * p) = 70.5 lbm/ft³
Therefore, the units of 70.5 are lbm/ft³.
To get the units of the constant 82700000, we can rearrange the equation and take the natural logarithm of both sides:
ln(ρ/70.5 lbm/ft³) = 82700000 * p
The units of the left-hand side are dimensionless, and the units of the right-hand side are 1/in². So, the units of the constant 82700000 are 1/in².
If I leave 800 mL of 0.70 M sodium chloride solution uncovered on a windowsill and 300 mL of the solvent evaporates, what will the new concentration of the sodium chloride solution be?
Answer:
the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.
Explanation:
To calculate the new concentration of the sodium chloride solution after 300 mL of solvent evaporates, we need to first determine how many moles of solute are present in the original solution:
moles of solute = concentration x volume
moles of solute = 0.70 M x 0.800 L
moles of solute = 0.56 moles
Next, we can calculate the new volume of the solution after 300 mL evaporates:
new volume = original volume - amount evaporated
new volume = 0.800 L - 0.300 L
new volume = 0.500 L
Finally, we can calculate the new concentration of the solution using the moles of solute and the new volume:
new concentration = moles of solute / new volume
new concentration = 0.56 moles / 0.500 L
new concentration = 1.12 M
Therefore, the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.
Given the following balanced equation, determine the mass of H2 if you start with 4.55x1025 molecules of C5H12.
C5H12-->C5H8+2H2
If you start with 4.55 x 10²⁵ molecules of C₅H₁₂, you would produce 1.82 x 10²⁶ g of H₂.
What is the mass of H₂ ?The balanced equation shows that for every one molecule of C₅H₁₂ that reacts, 2 molecules of H₂ are produced.
C₅H₁₂ --> C₅H₈ + 2H₂
To determine the mass of H₂ produced, we need to convert the number of molecules of C₅H₁₂ to molecules of H₂ using the stoichiometry of the balanced equation:
1 molecule of C₅H₁₂ produces 2 molecules of H₂
4.55 x 10²⁵ molecules of C₅H₁₂ x (2 molecules of H₂ / 1 molecule of C₅H₁₂) = 9.10 x 10²⁵ molecules of H₂
Now, to find the mass of H₂ produced, we need to use the molar mass of H₂, which is approximately 2 g/mol:
9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂
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Answer:
9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂
Explanation:
if 100.0 ml ethyl alcohol weighs 78.5g ;determine the volume in litres occupied by 1,59 kg of ethyl alcohol
Answer: 2.025
Explanation: Set up the ratio 100ml/78.5g = xml/1.59kg
Once you have your units in order, solve for x and then convert to liters and there you have your answer!
Study each picture that depicts the involvement of a particular gland in the endocrine system. Write down the name of the endocrine gland and explain its effect, according to its function.
The thyroid gland produces and secretes two hormones, thyroxine (T4) and triiodothyronine (T3), which are involved in regulating the body's metabolism.
What is thyroid gland?The thyroid gland is regulated by the pituitary gland, which secretes thyroid-stimulating hormone (TSH). When TSH binds to receptors on the thyroid gland, it stimulates the production and secretion of T4 and T3. These hormones play an important role in the growth and development of the body's tissues and organs, including the brain, heart, and muscles.
What is hyperthyroidism?If there is an overproduction of thyroid hormones, it can lead to hyperthyroidism, which can cause symptoms such as weight loss, nervousness, and rapid heartbeat. On the other hand, an underproduction of thyroid hormones can lead to hypothyroidism, which can cause symptoms such as fatigue, weight gain, and cold intolerance.
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A 3.1-mol sample of KCIO3 was decomposed according to the equation
2KCIO3(s)→ 2KC1(s) + 302(g)
How many moles of O₂ are formed assuming 100% yield?
a) 2.1 mol
b) 3.1 mol
c) 2.6 mol
Od) 4.7 mol
e) 1.6 mol
Answer:
It's (d) 4.65 ≃ 4.7
Explanation:
By understanding that a mole is the unit of amount of substance that equals Avogadro's number ([tex]N_a[/tex] = 6.022*10^23)
we make a ratio of moles as below:
2KClO3 --> 2KCl + 3O2
2 : 2 : 3
3.1 : ? : ?
part value = 3.1 / 2 = 1.55
number of moles of O2 yielded from this reaction = 1.55 * 3 = 4.65 moles
What does mass measure?
A. The space that a substance takes up.
B. The amount of energy in a substance
C. The phase of matter of a substance
D. The amount of matter (particles) in a substance
Use the following equation to answer the next question
P₂O5 + 3 H₂O → 2H3PO4
8. If you started the reaction with 55 g.of P₂O5 and 16 g. of H₂O, the H₂Qwould be your
limiting reactant.
How many grams of excess reactant would you have? *The molar mass of P₂O5 is 141.88
g/mol.
The limiting reactant would be H₂O.
The mass of the excess reactant would be 13.05 grams
Stoichiometric problemNumber of moles of P₂O5 = mass / molar mass
Number of moles of P₂O5 = 55 g / 141.88 g/mol
Number of moles of P₂O5 = 0.388 moles
Number of moles of H₂O = mass / molar mass
Number of moles of H₂O = 16 g / 18.02 g/mol
Number of moles of H₂O = 0.888 moles
Using the balanced chemical equation, we see that 1 mole of P₂O5 reacts with 3 moles of H₂O to produce 2 moles of H3PO4. Therefore, to react with all the P₂O5, we would need:
0.388 moles of P₂O5 × (3 moles of H₂O / 1 mole of P₂O5) = 1.164 moles of H₂O
Since we only have 0.888 moles of H₂O, it is the limiting reactant.
To determine the amount of excess P₂O5, we need to find how many moles of H₂O would be needed to react with all the P₂O5:
0.888 moles of H₂O × (1 mole of P₂O5 / 3 moles of H₂O) = 0.296 moles of P₂O5
The amount of excess P₂O5 is the initial moles of P₂O5 minus the moles of P₂O5 required to react with all the H₂O:
0.388 moles of P₂O5 - 0.296 moles of P₂O5 = 0.092 moles of excess P₂O5
Mass = 0.092 x 141.88 = 13.05 grams
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In a laboratory experiment you dissolved 1.02 g of an unknown, nonvolatile substance in a 25 mL of distilled water. Vapor pressure if purr water is 23.7 torr, and you measure the vapor pressure of the solution to be 22 torr. What is the molar mass of the solute?
Answer: We can use Raoult's Law to solve for the molar mass of the solute:
ΔP = P°_solvent x mole fraction of solute x vapor pressure of solute
Since the solute is nonvolatile, its vapor pressure is negligible and we can assume that it is equal to zero. Thus, we can simplify the equation to:
ΔP = P°_solvent x mole fraction of solute
Solving for the mole fraction of solute:
ΔP / P°_solvent = mole fraction of solute
Plugging in the values:
(23.7 torr - 22 torr) / 23.7 torr = mole fraction of solute
mole fraction of solute = 0.072
Now we can use the mole fraction of solute to calculate the moles of solute dissolved in the solution:
moles of solute = mole fraction of solute x moles of solvent
moles of solvent = (25 mL / 1000 mL) x (1 g/mL) / (18.015 g/mol) = 0.001385 mol
moles of solute = 0.072 x 0.001385 mol = 0.0001 mol
Finally, we can calculate the molar mass of the solute:
molar mass of solute = mass of solute / moles of solute
mass of solute = 1.02 g
molar mass of solute = 1.02 g / 0.0001 mol = 102 g/mol
Therefore, the molar mass of the solute is 102 g/mol.
Brainiest is Appreciated.
What are the examples of tests performed on aspirin
Most frequently, a salicylates component is used to: Aid in the diagnosis of sudden or progressive aspirin toxicity. When you take a lot of aspirin at once, you might get acutely poisoned.
Can aspirin be detected in blood tests?Blood test results are frequently impacted by prescription medicines, non-prescription pharmaceuticals (such as aspirin, cold medicine, and vitamins), and alcohol consumption. In order to properly interpret the findings of your blood tests, your doctor needs a thorough and candid picture of your medication use.
What laboratory results does aspirin impact?Aspirin Reaction Units are used to report test findings (ARU). 350-549 ARU is the therapeutic range for people on an antiplatelet regimen to effectively suppress platelets. Those who are not taking aspirin or whose treatment is ineffectively suppressing platelet function have values of 550–700 ARU.
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Predicting the units of the solution to a basic quantitative... A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer. (0.22L)×(1 mL/10‐³ L)×(1.57g/mL)/(61.04 g/mol) = ?
Answer:
(0.22 L) × (1 mL/10^-3 L) × (1.57 g/mL) / (61.04 g/mol) = ?
First, let's simplify the units:
(0.22 L) × (1000 mL/1 L) × (1.57 g/mL) / (61.04 g/mol) = ?
(0.22 L) × (1570 g/mol) / (61.04 g/mol) = ?
Now we can cancel out the units of g/mol:
(0.22 L) × (1570/61.04) = ?
(0.22 L) × 25.73 = ?
5.66 L·g
Therefore, the units of the student's answer are L·g.
how many grams of sodium would you comsume if you ate 85 g or.this fiod
350 mg of sodium would be ingested if you consumed 85 g of the food. This is less than the 2,300 mg (or one teaspoon of table salt) daily limit that is advised.
What is sodium?The body needs sodium, a mineral, to maintain the proper balance of body fluids. It is an explosively reactive alkali group metallic element that is soft, light, and silvery-white. It reacts with water. Table salt and a number of processed foods both contain sodium. Table salt is created when sodium and chlorine are combined. Nonetheless, the body can get harmed by excess sodium.
The amount of sodium in various foods, and even within the same food category, varies greatly.
But, you can ascertain the salt content per serving, which is often represented in milligrams, by looking at the nutrition facts label or ingredient list of the meal (mg). So, using a proportion, you can determine how much salt is in 85 g of the food:
(x mg sodium) / (serving size in g) = (sodium per serving in mg) / (85 g)
The amount of sodium in 85 g of the food, expressed in milligrams, can be found by solving for x. You may divide this by 1000 to get grams.
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check bracket.The temperature of an/
(dt h)²-(q nn)²( ja ki)⁴ /oven being heated using a pulsed resistance heater varies as T = 120 + 5cos(25t+30°) where t is the time in seconds. The temperature of the oven is being measured with a ther mo couple having a time constant of 5 s. ( a ) What are the maximum and minimum temperatures indicated by the thermocouple? ( What is the maximum difference between the actual temperature and the indicated temperature? ( c ) What is the time lag between the actual temperature and the indicated temperature?
a. The maximum and minimum temperature of a thermocouple is [tex]-200^{o} C to 350^{o} C[/tex].
Therefore the difference between the actual and indicated temperature is indicated as [tex](125*5 = 625^{o} C/s)[/tex]
c.The time lag between the actual temperature and the indicate temperature is equal to the time constant of the thermocouple.
What do you mean thermocouple ?A sensor that detects temperature is a thermocouple. It is made up of two distinct metals that are attached at one end. A voltage is produced that is linked to temperature when the junction of the two metals is heated or cooled.
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what factors should you consider to determining what variables to measure for the control of chemical process? answer quantitatively
One should consider factors such as the process constraints, the process dynamics, and process output requirements.
What are process constraints?
Process constraints are limitations on the process variables due to physical, chemical, or economic factors. A constraint is a limitation or bias on the variability or possibilities of change in the sort of such elements. A constraint is an effort by a group of elements to reduce the degrees of freedom of the elements of a system.
The selection of variables to measure for the control of a chemical process can be quantified using a process flow diagram and a process control hierarchy. The process flow diagram shows the process variables and their relationships, while the process control hierarchy shows the control loops and the measurement and control variables for each loop. The number and type of variables to measure depend on the complexity of the process, the desired control objectives, and the available instrumentation and control technologies.
Therefore, process constraints, the process dynamics, and process output requirements are the factors.
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reduction of: 3-methylpentan-2-one
Spell out the full name of the compound.
Give the systematic name for each of the following organic molecules and enter it in the space provided. Be sure to include appropriate punctuation.
A complex molecule known as an organic is composed primarily of carbon atoms joined to other elements and/or other carbon atoms.
What is organic molecules?Although the distinction between "organic" and "inorganic" is disputed, many authors in the field of chemistry believe that any chemical compound that contains carbon-hydrogen or carbon-carbon bonds is considered to be an organic compound. Methane is an example of an organic compound, but opinions on whether carbon halides without hydrogen (such as carbon tetrachloride, are organic or inorganic vary from author to author.
Millions of organic substances have been identified as a result of carbon's capacity to catenate (form strands with other carbon atoms).
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The vapor pressure of mercury at 25 degrees Celsius is 1.85 mmHg . Calculate the vapor pressure in atm and torr . Round each of your answers to 3 significant digits.
The vapor pressure of mercury at 25°C is 1.85 torr. To convert the vapor pressure of mercury from mmHg to atm, we can use the conversion factor 1 atm = 760 mmHg:
Why does vapour pressure exist?A liquid's molecules enter the gaseous phase when heated because they have enough kinetic energy to overcome the forces holding them in the liquid. By doing this, they produce a population of molecules in the vapour phase above the liquid, which leads to the creation of a pressure—the liquid's vapour pressure.
1.85 mmHg x (1 atm / 760 mmHg) = 0.00243 atm (rounded to 3 significant digits)
Therefore, the vapor pressure of mercury at 25°C is 0.00243 atm.
To convert the vapor pressure of mercury from mmHg to torr, we can simply use the definition that 1 torr = 1 mmHg:
1.85 mmHg = 1.85 torr (rounded to 3 significant digits)
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A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: 3+ 2 Cr³+ (aq) + 3Ca (s) → 2Cr (s) + 3 Ca²+ (aq) 3+ Suppose the cell is prepared with 4.01 M Cr³+ in one half-cell and 1.96 M Ca 2+ Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. in the other.
Which is one use for infrared waves?
A)To provide heat for pets or livestock
B)To power nuclear weapons
C)To operate a machine that cooks food quickly
D)To light desk lamps
A contraption that swiftly prepares food is run by infrared rays. Microwaves employ infrared rays to heat meals by warming any water that may be present.
What are some uses for infrared and microwave technology?Numerous food production processes, including drying, boiling, heating, peeling, polyphenol recovery, freeze-drying, antioxidant recovery, microbiological inhibition, sterilizing grains, baking bread, roasting food, making juices, and cooking food, all use infrared technology.
What are some uses and applications for infrared waves?Infrared radiation has the ability to ease or release muscle tension and encourage local blood circulation in the body. Infrared radiation has been used in conventional and modern medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.
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Two elements, and , combine to form two binary compounds. In the first compound, 23.3 g of combines with 3.00 g of . In the second compound, 7.00 g of combines with 4.50 g of . Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is , what is the formula of the first compound?
Compound I:
Answer:
To show that the data are in accord with the law of multiple proportions, we need to determine the ratios of the masses of to in each compound and see if they are in small whole number ratios.
For the first compound:
Mass of : 23.3 g
Mass of : 3.00 g
Ratio of masses: 23.3 g / 3.00 g = 7.77
For the second compound:
Mass of : 7.00 g
Mass of : 4.50 g
Ratio of masses: 7.00 g / 4.50 g = 1.56
These ratios are not in small whole number ratios, which indicates that the formula for the first compound cannot be determined by simple inspection. However, the fact that the ratios are different is in accord with the law of multiple proportions, which states that when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in small whole number ratios.
Let's assume that the formula for the second compound is . This means that the ratio of to in the compound is 2:1. From the data provided, we know that there are 4.50 g of in the compound, which means there must be twice as much in the compound. Therefore, there are 9.00 g of in the compound.
To determine the formula of the first compound, we can subtract the mass of from the total mass of the compound:
Mass of : 23.3 g
Mass of : 3.00 g
Total mass: 26.3 g
Mass of : 26.3 g - 3.00 g = 23.3 g
So the ratio of to in the first compound is:
Mass of : 23.3 g
Mass of : 3.00 g
Ratio of masses: 23.3 g / 3.00 g = 7.77
We can divide this ratio by the ratio of to in the second compound to get the ratio of the two compounds:
Ratio of first compound: 7.77
Ratio of second compound: 2.00
The ratio of the two compounds is not a small whole number ratio, which suggests that the formula for the first compound is more complex than a simple binary compound. Therefore, we cannot determine the formula of the first compound from the data provided.
Answer:
the formula of the first compound is A2.08B0.78, which we can simplify to A2B.
Explanation:
To determine if these data are in accord with the law of multiple proportions, we need to compare the ratios of the masses of one element to the fixed mass of the other element in each compound:
For the first compound:
mass ratio of A:B = 23.3 g / 3.00 g = 7.77
For the second compound:
mass ratio of A:B = 7.00 g / 4.50 g = 1.56
If the ratios of the masses of one element to the fixed mass of the other element are simple whole number ratios, then the data are in accordance with the law of multiple proportions. We can see that the ratios calculated above are not simple whole numbers, so the law of multiple proportions does not appear to be satisfied.
To determine the formula of the first compound, we can assume that the formula is AxBy, where x and y are the subscripts that we need to determine. We can set up a system of equations based on the mass ratios:
23.3 g of A combines with 3.00 g of B:
(23.3 g A) / (x mol A) = (3.00 g B) / (y mol B)
7.77 mol A / mol B = (23.3 g A) / (3.00 g B)
7.77 (y/x) = 23.3 / 3.00
y/x = 3/7.77
7.77 g of A combines with 1.00 g of B:
(7.77 g A) / (x mol A) = (1.00 g B) / (y mol B)
1.56 mol A / mol B = (7.77 g A) / (1.00 g B)
1.56 (y/x) = 7.77 / 1.00
y/x = 5/2
Now we have two equations for y/x that we can solve simultaneously:
y/x = 3/7.77
y/x = 5/2
Setting these two expressions equal to each other, we get:
3/7.77 = 5/2x
x = 2.08
Now that we know x, we can use one of the equations for y/x to solve for y:
y/x = 3/7.77
y/2.08 = 3/7.77
y = 0.78
Therefore, the formula of the first compound is A2.08B0.78, which we can simplify to A2B.
Hello what are the answers to these?
The kinetic energy is the energy of an object in motion.
What is kinetic energy?Kinetic energy is a form of energy that an object possesses due to its motion. It is defined as the energy that an object has as a result of its mass and velocity.
We know that;
KE = 1/2mv^2
PE = mgh
1) KE = 0.5 * 2300 * (32)^2
= 1177600 J
2) PE = 31 * 2.2 * 9.8
= 52.6 J
3) PE = mgh
h = PE/mg
h = 65000/525 * 9.8
h = 12.6 m
4) KE = 1/2mv2
m = 2KE/v^2
m = 2 * 370/(6.5)^2
m = 17.5 Kg
5) KE = 0.5 * 75000 * (11500)^2
KE = 4.96 * 10^12 J
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What does volume measure?
A. The space a substance takes up
B. The amount of energy in a substance
C. The phase of matter of a substance
D. The amount of matter (particles) in a substance
Volume is the measure of the space a substance takes up, hence the correct option is A.
Various types of measurementsNominal, ordinal, interval, and ratio measurements are the four main types of measurement.
An object or event's attributes are quantified through measurement so that they can be compared to those of other things or events. In other words, measurement is the process of comparing a physical quantity to a fundamental reference quantity of the same kind to determine how big or small it is.
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At 99.0 °C and 748 torr, a sample of a volatile liquid is vaporizedcompletely in a 250 mL flash. The condensed vapor weighs 1.097 grams. Calculate the molar mass of the gas.
Answer:
To calculate the molar mass of the gas, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:
PV = nRT
where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in kelvin.
First, we need to convert the temperature to kelvin:
T = 99.0 °C + 273.15 = 372.15 K
Next, we can calculate the number of moles of gas using the ideal gas law:
n = PV/RT
where P is the pressure in atmospheres (we convert 748 torr to atmospheres by dividing by 760 torr/atm), V is the volume in liters (we convert 250 mL to 0.25 L), R is the ideal gas constant, and T is the temperature in kelvin:
n = (748/760) × 0.25 L / (0.0821 L·atm/mol·K × 372.15 K) = 0.0105 mol
Finally, we can calculate the molar mass of the gas by dividing the mass of the condensed vapor (1.097 g) by the number of moles:
molar mass = mass/number of moles = 1.097 g / 0.0105 mol = 104.38 g/mol
Therefore, the molar mass of the gas is approximately 104.38 g/mol.
Explanation:
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It takes 29.61 mL of 0.246 M sodium hydroxide to titrate 10.00 mL of sulfuric acid solution. What is the molarity of sulfuric acid?
Answer:
The balanced equation for the reaction between sodium hydroxide and sulfuric acid is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From this equation, we can see that one mole of sulfuric acid reacts with two moles of sodium hydroxide.
The amount of sodium hydroxide used in the titration is:
n(NaOH) = C(NaOH) x V(NaOH) = 0.246 M x 29.61 mL = 0.007298 moles of NaOH
Since two moles of NaOH react with one mole of H2SO4, the amount of H2SO4 present in the sample is:
n(H2SO4) = 0.007298 moles of NaOH / 2 = 0.003649 moles of H2SO4
The volume of the sulfuric acid solution used in the titration is 10.00 mL. Therefore, the molarity of the sulfuric acid solution is:
M(H2SO4) = n(H2SO4) / V(H2SO4) = 0.003649 moles / 10.00 mL = 0.3649 M
So, the molarity of sulfuric acid is 0.3649 M.
How many atoms of oxygen are in 30.5 grams of Fe2O3?
Answer: Atoms of oxygen in 30.5 grams of Fe2O3 = 7.65 x 10^22 atoms
Explanation: To determine the number of atoms of oxygen in 30.5 grams of Fe2O3, we first need to calculate the number of moles of Fe2O3, and then use the mole ratio between Fe2O3 and O atoms to calculate the number of O atoms.
The molecular weight of Fe2O3 can be calculated by adding the atomic weights of two Fe atoms and three O atoms:
Molecular weight of Fe2O3 = (2 x atomic weight of Fe) + (3 x atomic weight of O)
= (2 x 55.85 g/mol) + (3 x 16.00 g/mol)
= 159.69 g/mol
So, 30.5 g of Fe2O3 is equal to:
Number of moles = Mass / Molecular weight
= 30.5 g / 159.69 g/mol
= 0.191 moles
The mole ratio between Fe2O3 and O atoms is 3:2. This means that for every 3 moles of Fe2O3, there are 2 moles of O atoms. Therefore, the number of moles of O atoms in 0.191 moles of Fe2O3 is:
Number of moles of O atoms = 2/3 x 0.191 moles
= 0.127 moles
Finally, we can use Avogadro's number to convert the number of moles of O atoms into the actual number of O atoms:
Number of O atoms = Number of moles x Avogadro's number
= 0.127 moles x 6.022 x 10^23 atoms/mol
= 7.65 x 10^22 atoms
Therefore, there are 7.65 x 10^22 atoms of oxygen in 30.5 grams of Fe2O3.
Compared with the rate of water loss before soaking, what difference, if any, would you expect in the rate of water loss after soaking the hand in alcohol? (Clue: Fats are soluble in alcohol.)
Lipids dissolve in alcohol, a solvent. It removes the skin's lipids, particularly from the stratum corneum.
Because the lipids that normally prevent water loss are removed during alcohol soaking, the rate of water loss increases.
Why does alcohol evaporate water?Therefore, water may evaporate more slowly than other liquids despite having a lower molecular weight. The molecules of ethyl (rubbing) alcohol, which are more loosely bound than those of water, evaporate almost five times faster than water. Lower-energy, lower-temperature molecules are left behind when energetic molecules leave a liquid.
Question incomplete:The rate of water loss from the skin of a hand was measured. Following the measurement, the hand was soaked in alcohol for 15 minutes. After all the alcohol had been removed from the hand, the rate of water loss was again measured. Compared with the rate of water loss before soaking, what difference, if any, would you expect in the rate of water loss after soaking the hand in alcohol?
Learn more about alcohol:
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