Engineering High School

Question 6 (5 points)
A Tesla car weighs 250,000 Newtons Travels a distance of 64 M in 2
seconds (115 km / hour). The Voltage of the Battery of the car is 375
Volts. The Current is 32 kA.
What is the % Efficiency of the power

Question 6 (5 Points)A Tesla Car Weighs 250,000 Newtons Travels A Distance Of 64 M In 2seconds (115 Km

Answers

Answer 1

The efficiency of the power is 70%. This means that 70% of the energy supplied by the battery is used to move the car, and the remaining 30% is lost as heat and other forms of energy loss.

How to calculate the value

The efficiency of the power is calculated as follows:

Efficiency = Work output / Work input

The force is the weight of the car, which is 250,000 N, and the distance is 64 m. So the work output is:

Work output = 250,000 N * 64 m

= 16,000,000 J

The voltage is 375 V, the current is 32 kA, and the time is 2 seconds. So the work input is:

Work input = 375 V * 32 kA * 2 s = 23,040,000 J

The efficiency is then:

Efficiency = 16,000,000 J / 23,040,000 J = 70%

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Related Questions


Which of the following statements is not true about proper tire care?

Answers

Answer:

The answer is 'Tire tread depth can only be checked by a properly trained tire expert.'

Explanation:

Question 5 (5 points)
A Vex motor has a has a voltage of 9 volts running through it, and a
current of 15 mA. What is the power?
(Precision of 0.000)

Answers

The power of the Vex motor is 0.135 watts.

How to solve

The power of the Vex motor can be calculated using the formula:

Power (P) = Voltage (V) * Current (I)

Substituting the given values:

P = 9 volts * 15 mA

To simplify the calculation, we convert milliamperes (mA) to amperes (A):

P = 9 volts * 0.015 amperes

P = 0.135 watts

Therefore, the power of the Vex motor is 0.135 watts.


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Everyday materials that do a better job of filtering microscopic particles
​

Answers

The materials such as high-quality furnace filters, tightly woven cotton fabric, electrostatic cloth, and activated carbon are everyday options that provide effective filtration of microscopic particles.

There are several everyday materials that can effectively filter microscopic particles.

One commonly used material is high-quality furnace filters, which are designed to capture small particles and allergens. These filters consist of dense fibers that create a barrier, preventing microscopic particles from passing through.

Another effective material is tightly woven cotton fabric, such as quilting cotton or flannel. The tight weave of these fabrics can trap small particles, making them suitable for homemade face masks or air filtration systems.

Electrostatic cloth, like microfiber towels, also has excellent filtering capabilities. The fibers in these cloths carry an electric charge that attracts and captures particles, including microscopic ones.

Activated carbon is another material used for filtering microscopic particles. It works by adsorbing particles onto its surface through a process called adsorption. Activated carbon is commonly found in air purifiers, water filters, and respirators.

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Energy problem formulas
Potential Energy = mgh
v = velocity or speed
Kinetic energy = mv²
9 = 9.8 m/s²
m = mass in kg
(Precision of 1)
h = height in meters
You serve a volleyball with a mass of 3.1 kg. The ball leaves your hand
with a speed of 20 m/s.
a) Calculate Kinetic Energy
(Precision of 1)
b) How much work is being done to the system to create this kinetic
energy?


I need this asap

Answers

a. The kinetic energy is 620 J

b. The amount of work done is equal to the kinetic energy. In this case, the work done is 620 J.

How to calculate the value

a. The formula for kinetic energy is:

KE = 1/2mv²

where:

KE is the kinetic energy in joules (J)

m is the mass in kilograms (kg)

v is the velocity in meters per second (m/s)

In this case, we have:

m = 3.1 kg

v = 20 m/s

So, the kinetic energy is:

KE = 1/2(3.1 kg)(20 m/s)²

= 620 J

b) How much work is being done to the system to create this kinetic energy?

Work is done to the system to create kinetic energy. The amount of work done is equal to the kinetic energy. In this case, the work done is 620 J.

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