The volume in litres occupied by 1.59 Kg of ethyl alcohol given the data from the question is 2.03 L
How to determine the mole of 78.5 g of ethyl alcohol Mass of ethyl alcohol = 78.5 gMolar mass of ethyl alcohol = 46.07 g/molMole of ethyl alcohol =?Mole = mass / molar mass
Mole of ethyl alcohol = 78.5 / 46.07
Mole of ethyl alcohol = 1.7 mole
How to determine the mole of 1.59 Kg of ethyl alcohol Mass of ethyl alcohol = 1.59 Kg = 1.59 × 1000 = 1590 gMolar mass of ethyl alcohol = 46.07 g/molMole of ethyl alcohol =?Mole = mass / molar mass
Mole of ethyl alcohol = 1590 / 46.07
Mole of ethyl alcohol = 34.5 moles
How to determine the new volume Initial volume (V₁) = 100 mL = 100 / 1000 = 0.1 LInitial mole (n₁) = 1.7New mole (n₂) = 34.5 moles New Volume (V₂) =.?V₁ / n₁ = V₂ / n₂
0.1 / 1.7 = V₂ / 34.5
Cross multiply
1.7 × V₂ = 0.1 × 34.5
Divide both side by 1.7
V₂ = (0.1 × 34.5) / 1.7
V₂ = 2.03 L
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Human colour vision is “produced” by the nervous system based on how three different cone receptors interact with photons of light in the eye. These three different types of cones interact with photons of different frequency light, as indicated in the following chart: Cone Type Range of Light Frequency Detected S 6.00-7.49 x 1014 s-1 M 4.76-6.62 x 1014 s-1 L 4.28-6.00 x 1014 s-1 What wavelength ranges (and corresponding colours) do the three types of cones detect?
The colors and the corresponding wavelengths the three types of cones detect are:
Blue: 450–495 nmGreen: 495–570 nmRed: 620–750 nmWhat is the role of cones in Human vision?Human vision refers to the ability of humans to see and visualize objects in the environment in terms in texture, color, pattern, etc.
The cells of the human eye responsible for vision are the rods and cones.
The cones are responsible for color-vision while rods are responsible for black and white vision.
The three types of cones detect blue, green, and red colors corresponding to wavelengths given below:
Blue: 450–495 nmGreen: 495–570 nmRed: 620–750 nmTherefore, the cones in the eye detect blue, green and red colors.
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11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the following (unbalanced) reaction: NaOH +CO2-
Na2CO3 + H2O.
a. If the average human body discharges 925,0 g CO, per day, how many moles of NaOH are
needed each day for each person in the spacecraft?
b. How many moles of each product are formed?
For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as
a) Moles of NaOH =44.05
b) Moles of Na2CO3=21.0
Moles of H2O= 21.0What is the moles of NaOH and what moles of each product are formed?
Generally, the equation for the Chemical reaction is mathematically given as
2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)
Therefore
Moles of CO2= 925/44
Moles of CO2=21.0
Hence
Moles of NaOH = 2 x Moles of CO2
Moles of NaOH = 2x925/44
Moles of NaOH =44.05
In conclusion
Moles of Na2CO3 925/44
Moles of Na2CO3=21.0
And
Moles of H2O= 925/44
Moles of H2O= 21.0
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What is the pH when the [H+] is 1 x 10^-3 M
A. 2
B. 3
C. -3
D. 4
Answer:
3
Explanation:
PH = -Log [H+]
PH = -Log [1 × 10^-3]
PH = -Log [10^-3]
Log (10) = 1
PH = -(-3) Log (10)
PH = 3 × 1
PH = 3
PLEASE john travoltage is safe from getting a static electricity zap right now. there are two things that could change to increase his chances from getting zapped tell me what both if those things are
If he rubs his foot on the carpet or touches the metal doorknob it would increase his chances of being zapped.
Rubbing his feet would be friction.
Touching the doorknob would be potential energy.
Side note: I love the format for this question, was not expecting to see John Travolatge on here today >O< !!!
The measurement 0.41006 gram, rounded to four significant figures, is expressed as... 1) 0.4100 g
2) 0.410 g
3) 0.41 g
4) 0.4101 g
Answer:
option B = 0.410 g
Explanation:
hope this helps have hope i get brainliest
The change in enthalpy that occurs in the process of converting reactants to products in a chemical reaction is called the _____ of reaction.
Answer:
∆H or Enthalpy of the reaction
Explanation:
If ∆H is +ve
Reaction is exothermicExample:-Combustion, mixing sodium/potassium in waterIf ∆H is -ve
Reaction is endothermicEx:-Melting of iceHELP ME OUT PLS!!!!!!!!!!!!!
I. Car metal rusting slowly for a year.
II. Condensation of water vapor on a mirror during a 5-minute shower.
III. The formation of a precipitate in a test tube during a 10-second reaction.
IV. The oxidation of copper on the Statue of Liberty for more than 100 years.
23) Which of the processes above are examples of a chemical reaction?
A) I and II
B) III and IV
C) I, II, and III
D) I, III, and IV
Answer:
d) I, III, and IV
Explanation:
rust, copper oxidation, and percipitate from a chemical reaction are all, well, chemical reactions.
A firework is fired from the ground straight up on a planet with an acceleration due to gravity of 6.82 m/s/s. The firework will not explode until the moment where it would have started to move back down again. The initial speed of the firework is 69.5 m/s. Use this information to find the height at which the firework explodes and the time it will be traveling upward.
Answer:
h = 384.4 m
t = 8.5 s
Explanation:
The firework will explode at the highest point. Because it would start to move downward at the highest point. Using 3rd equation of motion:
2ah = Vf² - Vi²
where,
a = acceleration due to gravity at that planet = -10.56 m/s²
h = maximum height = ?
Vf = Final velocity = 0 m/s (since, firework stops at highest point)
Vi = Initial Velocity = 90.1 m/s
Therefore,
2(-10.56 m/s²)(h) = (0 m/s)² - (90.1 m/s)²
h = 384.4 m
Now, we use 1st equation of motion:
Vf = Vi + at
0 m/s = 90.1 m/s + (-10.56 m/s²)(t)
t = 8.5 ss
2.0 L of Carbon dioxide is heated from -25.0 °C to Standard Temperature.
What is the final volume of the gas?
The final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L.
How to calculate volume?The volume of a given gas can be calculated using the Charles law equation as follows:
V1/T1 = V2/T2
Where;
V1 = initial volumeV2 = final volumeT1 = initial temperatureT2 = final temperatureV1 = 2LV2 = ?T1 = -25°C + 273 = 248KT2 = 273K2/248 = V2/273
273 × 2 = 248V2
546 = 248V2
V2 = 546/248
V2 = 2.2L
Therefore, the final volume of the gas that was heated from -25.0 °C to standard temperature is 2.2L
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When you exercise strenuously, your body produces excess heat. Describe what your body does to help prevent your temperature from rising excessively and
explain why your body's response effective.
Answer:
Your body can cool itself by sweating. When sweat evaporates, it lowers your temperature
Explanation:
How would you correctly prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4?
Answer:
see below
Explanation:
.3 M/L ( .125 L) = .0375 mole required
.0375 mole / 2 mole / l = .01875 l required
take 18.75 ml of the 2.0 solution then dilute it to 125 ml
An empty beaker has a measured mass of 27.234 g. When some salt is added to the beaker, the combined mass is 35.9564 g. Calculate the mass of the salt only (show work), reporting your answer to the correct number of significant figures.
The mass of the salt only if 35.9564g is the combined mass of the beaker and the salt is 8.7224g
How to calculate mass?According to this question, an empty beaker has a measured mass of 27.234g. However, when some salt is added to the beaker, the combined mass is 35.9564g.
This means that to calculate the mass of the salt in the beaker, we have to subtract the mass of the empty beaker from the combined mass as follows:
mass of salt only = 35.9564g - 27.234g
mass of salt only = 8.7224g
Therefore, the mass of the salt only if 35.9564g is the combined mass of the beaker and the salt is 8.7224g.
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What are the extensive and intensive properties described in this experiment? Which properties would change and which would stay the same if you ran the experiment sing 7.5-ounce cans instead of 12- ounce cans?
Intensive properties do not change as the size of an object changes but Extensive properties change as the size of an object changes; here the properties can not change because the amount of the water stays the same
What are the difference between Extensive property and Intensive Property ?The physical properties of matter can be divided into intensive and extensive properties and the terms are introduced in 1917 by Richard C Tolman.
Intensive properties are independent of the presence of number of substance and they are bulk properties, here the Characteristic doesn’t change.
The size of intensive properties cannot change, examples are Density, temperature, pressure etc. It can not depend on the amount of matter and also intensive properties are fixed, countable.
Extensive properties are dependent on the presence of number of substance, easily identified, Size of Extensive properties changes and It can be computed.
extensive properties depend on the amount of matter, often changes and are not countable; For example Volume, size, mass, length, weight
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what is the pH of a solution that has a [H+]=1.75x10^-11
[tex]pH = - \log[\text{H}^{+}] = -\log \left(1.75 \times 10^{-11} \right) = 10.757[/tex]
A 0.563 M solution of the salt NaA has a pH of 11.56. Calculate the Ka value for the acid HA. Record your answer in scientific notation to 3 sig figs.
Answer:
[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]
Explanation:
Write the base reaction of NaA with water:
[tex]\displaystyle \text{A}^-_\text{(aq)}+\text{H$_2$O}_\text{($\ell$)}\rightleftharpoons \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)}[/tex]
Hence, the equilibrium constant expression for the reaction is:
[tex]\displaystyle K_b = \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]}[/tex]
Thus, to find Ka, we can find Kb and use the fact that Ka × Kb = Kw.
From the reaction and initial concentration of NaA, create an ICE chart:
[tex]\begin{tabular}{llllll} & A^- &\text{H$_2$O} & \rightleftharpoons & HA & OH^- \\I & 0.563 M & \---- & & 0 M & 0 M \\C & -\text{ $ x$} & \---- & & +\text{ $x$ M} & + \text{$x$ M} \\E & \text{(0.563 - $x$) M} & \---- & & \text{$x$ M} & \text{$x$ M} \end{tabular}[/tex]
Find [OH⁻] from the given pH:
[tex]\displaystyle \begin{aligned} \text{pH} +\text{pOH} & = 14.00 \\ \\ \text{pOH} & = 14.00 - \text{pH} \\ \\ & = 14.00 - (11.56) \\ \\ & = 2.44 \\ \\ -\log[\text{OH}^-] & = 2.44 \\ \\ [\text{OH}^-] &= 10^{-2.44} \\ \\ & =0.00363 \text{ M}= 3.63\times 10^{-3} \text{ M} = x\text{ M}\end{aligned}[/tex]
Solve for all species concentrations at equilibrium from the found x value:
[tex]\displaystyle [\text{HA}] = [\text{OH}^-] = 3.63\times 10^{-3} \text{ M}[/tex]
And:
[tex]\displaystyle \begin{aligned} \ [\text{A}^-] & = 0.563 - 3.63\times 10^{-3} \text{ M}\\ \\ & = 0.559\text{ M}\end{aligned}[/tex]
Find Kb:
[tex]\displaystyle \begin{aligned} \displaystyle K_b &= \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]} \\ \\ & = \frac{(3.63\times 10^{-3})(3.63\times 10^{-3})}{(0.559)}\\ \\ & = 2.36\times 10^{-5}\end{aligned}[/tex]
Find Ka:
[tex]\displaystyle \begin{aligned} K_a\cdot K_b & = K_w \\ \\ K_a & = \frac{K_w}{K_b} \\ \\ & = \frac{(1.00 \times 10^{-14})}{(2.36\times 10^{-5})} \\ \\ &= 4.24\times 10^{-10} \end{aligned}[/tex]
In conclusion:
[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]
The atomic weight of nitrogen is what ?
Explanation:
[tex]\longmapsto\: \green{ hello \: mate \: }[/tex]
Atomic weight of nitrogen is 23
Which jobs does the respiratory system do? Select all that apply. It brings oxygen into the blood. It removes carbon dioxide waste from the blood. It pumps blood throughout the body. It takes in oxygen from air or water.
Answer:
probably the last one should hbthrbwhdee.
Answer:
it brings oxygen into the blood and removes carbon dioxide
Explanation:
N2+3H2 → 2NH3
A) How many grams of NH3 can be produced from the reaction of 28g of N2 and 25g of H2?
I need the steps to the answer 34g
B) How much of the excess reagent is left over?
I need steps to the answer 19 g
Explanation:
N2 (g) + H2 (g) gives out NH3 (g)
Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.
Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)
N2 (g) + 3H2 (g) gives out 2NH3 (g)
The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.
Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.
So what do we do? Convert to
mols (remember the hint?).
28g N2 × 1 mol N2/ 2 × 14.007) g N2
= 0.9995 mol N2
At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have
N2.
After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.
Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:
1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3
= 34.0444 g NH3
Hope it helpz~
34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.
What is Mole?The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Mass of N₂ = 28g
Mass of H₂ = 25g
Moles of N₂ = mass / molar mass
= 28 / 28
= 1 mole
Moles of H₂ = 25 / 2
= 12.5 moles
Since the number of moles of N₂ is lesser, the amount of products formed depends on the moles of N₂.
From the reaction,
1 mole of N₂ gives 2 moles of NH₃
So, Mass of NH₃ in 2 moles = 2 × 17
= 34g
B) From the reaction,
1 mole of N₂ reacts with 3 moles of H₂.
The number of Moles of H₂ left = 12.5 - 3
= 9.5 moles
Mass of excess reagent left = moles left × molar mass of H₂
= 9.5 × 2
= 19g
Therefore, 34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.
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In which pair do both compounds exhibit predominantly ionic bonding?
A. RbCl and CaO
B. Kl and O3
C. Na2SO3 and BH3
D. NaF and H2O
E. PCl5 and HF
Answer:
In pair NaF and H2O both compounds exibit predominantly ionic bonding.
NaF and H[tex]_2[/tex]O exhibit predominantly ionic bonding. Therefore, the correct option is option D among all the given options.
What is ionic bond?Ionic bonding produces ionic, or electrovalent, combinations, which are best represented by compounds created between nonmetals and alkali as well as alkaline-earth metals.
The electrostatic attraction forces among opposing charges as well as repulsion between comparable charges position the ions in such a way that every positive charge is surround by negative ions as well as vice versa within ionic crystal structures of such a type.
In summary, the ions are organized in such a way that negative and positive charges alternate constantly balance one another, resulting in a total charge of zero for the entire material. NaF and H[tex]_2[/tex]O exhibit predominantly ionic bonding.
Therefore, the correct option is option D.
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Noah is conducting a science experiment and needs to analyze iron and sulfur. Which of the following will he compare to determine the amounts of each substance?
movement of the atoms in each substance
movement of the atoms in each substance
molecular mass of each substance
molecular mass of each substance
mass of each substance
mass of each substance
vibration of the atoms in each substance
vibration of the atoms in each substance
Answer:
molecular mass of each substance
molecular mass of each substance
Explanation:
A small rock with a mass of 13 g is dropped into a graduated cylinder containing 12 mL of water.
The water rises to 35 mL. What is the density of the rock?
The density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.
How to calculate density?The density of a substance can be calculated using the following formula:
Density = mass ÷ volume
According to this question, a small rock with a mass of 13 g is dropped into a graduated cylinder containing 12 mL of water. The water rises to 35 mL.
This means that the volume of the rock is 35 - 12 = 23mL
Density of the rock = 13g ÷ 23mL
Density = 0.57g/mL
Therefore, the density of the rock with a mass of 13 g and is dropped into a graduated cylinder containing 12 mL of water is 0.57g/mL.
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which of the following has the smallest radius? A, Mg B, Na+ C, Na D, Mg+
Answer:
Na+
Explanation:
it is least pull by the nuclear charge
Answer:
Na+
Explanation:
It is posetively charged and in the first column
6Li + N2 → 2Li3N chemical word equation
Answer:
this is an Oxidation-reduction
Explanation:
like is w reducing agent, N2 is an oxidizing agent
How much work, , must be done on a system to decrease its volume from 19.0 L to 11.0 L by exerting a constant pressure of 6.0 atm?
w = ________ kJ
Answer:
Explanation:
w = 16.0KJ
your welcome for the answer let me know ifyou need anymore help.
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Which part of the water cycle helps to cool the temperature the most?
runoff
infiltration
rainfall
evaporation ( Science )
If I react 6 units of AB with 10 units of CD in the equation below, what is the limiting reactant? 3AB + 4CD --> 2AD + 6CB
If 6 units of AB were reacted with 10 units of CD in the described equation, the limiting reactant would AB
Limiting reactantsThey are reactants that determine how far a reaction can go in terms of yield.
From the equation: 3AB + 4CD --> 2AD + 6CB
The mole ratio of AB to CD is 3:4
Thus, 6 units of AB will require 8 units of CD.
But 10 units of CD were reacted with only 6 units of AB. This means that CD is in excess by 2 units while AB will limit the yield of the reaction.
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Why are polar and non polar liquids immiscible?
Answer:
When both liquid molecules are polar then they can attract one another - which leads to mixing (miscibility).
When the molecular liquid is nonpolar, then the water molecules attract only one another while ignoring the nonpolar liquid. the result is that the two liquids are immiscible.
Explanation:
I hope it helps mark me brainliest^^
Answer:
They lack lack inter-molecular forces to disolve in the polar liquids.
Explanation:
Miscibility is the property of two substances to mix in all proportions (that is, to fully dissolve in each other at any concentration). Polar molecules like water will mix well with some other polar molecules but things like oil which are non polar do not mix well with polar molecules. This is because the oil and water lack inter-molecular forces to keep them mixed.
HCl(?) + H2O(?) → H3O+(?) + Cl-(?)
What is the phase label on Cl-?
Answer:
H30,+ion is known as Hydroniom Ion
Explanation:
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everyday
brainless this answer is correct
A science teacher asked her students to calculate the density of a toy cube. The mass of the cube was 120 grams and the height of the cube was 4 centimeters.
What was the density of the cube in cubic centimeters? (**At least 2 decimal places)
Explanation:
density=> ro=m/V
m=0,12kg
V=0,04m³=6,4.10^-5
=>0,12/6,4.10^-5=1875 kg/m³
A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball is dropped from rest and falls along the principal axis of the mirror. How much time elapses before the ball and its image are at the same location?
The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.
Image distanceThe position of the image formed is determined using the followimg mirror formula;
[tex]\frac{1}{f} = \frac{1}{v} + \frac{1}{u}[/tex]
where;
f is the focal length of the mirrorv is the image distanceu is the object distancef = R/2
f = 1.5/2
f = 0.75 m
When the ball and its image is in the same position, u = v
The position of the ball is calculated as;
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m[/tex]
Time of motion of the ballThe time taken for the ball to travel the caluclated distance is determined as;
h = ut + ¹/₂gt²
1.5 = 0 + ¹/₂(9.8)t²
1.5 = 4.9t²
t² = 1.5/4.9
t² = 0.306
t = 0.55 s
Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.
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