Answer:
ayussssaasssassbfjdbskgsvdksbjabsdvsjvsjhjsjajbdnjsjnsnsnsnbfndksbsjjjsjdhjjsjjsjkjsjsjbdhsjabdhdhksbshsjsjisisisjdbbdjsjsjjebwnnwjbsnbhejshvjrebbdjndnebensjHELLONODNDIDBIDDBDUDBDIjsjsExplanation:
jshshjabsjbrnejdjdhjsndjdhfisjshsidsnsndgjsbdjdvsjsvdudhwjgdusbsuwgshidsbhsgsuydisksvdudh
• An artery in a certain patient has been reduced to half its original inner diameter by bad cholesterol deposits on the inner artery wall. By what factor will the blood flow through the artery be reduced if the pressure differential across the artery has remained unchanged? (a) 0.065 (b) 0.625 (c) 0.622 (d) 0.0625
Answer:
C.
Hope it's helpful
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In the free-body diagram, the magnitude of the normal force is 40 N, the friction force is
25N, the net force is 80N: What is the magnitude of the applied force?
Answer:
Explanation:
F = 80 + 25 = 105 N
The mass of an object is 100mg. What is the object's mass in kg? Show your work
Answer:
0.0001 kg
Explanation:
The weight in Kilograms is equal to the milligrams divided by 1,000,000.
100 ÷ 1,000,000
What are the similarities between coral reefs and costal ecosystems
Answer:
A coral reef is an underwater ecosystem characterized by reef-building corals. Reefs are formed of colonies of coral polyps held together by calcium carbonate. ... Unlike sea anemones, corals secrete hard carbonate exoskeletons that support and protect the coral.
Coastal oceans are commonly defined as the areas from the shoreline to the outer edge of the continental margin. They connect the continents to the open ocean and serve as a link for transporting organic and inorganic, natural and anthropogenic material from land to sea.
Coastal oceans in tropical areas have similar characteristics to their temperate counterparts. ... Coral reefs are biologically diverse and rich habitats that occur in relatively nutrient-poor environments along coastlines. Areas that have too many nutrients often harbor too much algal growth to sustain coral growth.,
Explanation:
In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively charged particle that moves from A to B along path 1 is W1.
How much work is done on this particle if it later goes from A to B along path 2? Express your answer in terms of W1.
W2=??
Answer:
W2 = W1
Explanation:
work is independent of the path taken between the points.
!!! , ? ? ? (no silly answers please).
Answer:
hellooo
Explanation:
i think ummm
. . .
31) what is the energy required to change 20g of copper, whose specific heat is 0.39j/gc,
change from 20 to 40 degrees?
Explanation:
given :
m = 20 g
sh = 0.39 J/g°C
∆T = 40-20 = 20°C
Find the Energy!
solution :
E =m. sh. ∆T
= 20 × 0.39 × 20
= 156 J
So, energy required is
Energy = mass*sh*∆T
Energy = 20g*0.39j/g°c*20°
Energy = 156joule✅
~Physics#1
Which area of study involves how mechanics and motion affect sports performance?
1.) Momentum. 2.) Velocity. 3.) Biomechanics. 4. )Centripetal force.
Answer:
biomechanics
Explanation:
Biomechanics is part of the larger field of kinesiology, specifically focusing on the mechanics of the movement. 1 It is both a basic and applied science, encompassing research and practical use of its findings.
answer the question below
Answer:
1. Shield volcano
Runny,basaltic magma with low silica and low gas content. Has a broad,low profile.
2. Cinder cone volcano
Thick viscosity andesitic magma with high silica content and high gas content. Rapidly solidifying lava forms high,steep-sided cones.
3. Composite volcano
Medium viscosity rhyolitic magma with medium silicon content and medium gas content.Have flatter domes called cones.
Explanation:
Hope it helps you..
Your welcome in advance..(◍•ᴗ•◍)
PLEASE HELP ASAPPPPPPPPPPPPPPPPPPP
Answer:
Basketball
Explanation:
Im asuming basketball because a basketball has the least movement out of the rest of the answers.
What is the acceleration of a car that maintains a constant velocity of 24 m/s for 10 seconds?
a.
24 m/s2
b.
240 m/s2
c.
2.4 m/s2
d.
0 m/s2
A ball is thrown at a speed of 40m/s. If the ball has a mass of 0.33kg, what is the ball’s momentum?
Answer:63745.6573
Explanation:
How strong is a neutron star's gravity.
Answer:
About a thousand billion times! Because neutron stars are so dense, they have intense gravitational and magnetic fields. The gravity of a neutron star is about a thousand billion times stronger than that of the Earth. Thus the surface of a neutron star is exceedingly smooth; gravity does not permit anything tall to exist.
It's crazy strong.
draw the diagram of third class lever showing fulcrum, effort and load
Answer:
In a third class lever, the effort is located between the load and the fulcrum. If the fulcrum is closer to the load, then less effort is needed to move the load. If the fulcrum is closer to the effort, then the load will move a greater distance. ... These levers are useful for making precise movements.
The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
The frequency of rotation of Mars is 0.0000113 Hertz.
Given the following data:
Period = 1 day and 37 minutes.To find the frequency of rotation in Hertz:
First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.
Conversion:
1 day = 24 hours
24 hours to minutes = [tex]60[/tex] × [tex]24[/tex] = [tex]1440[/tex] minutes
[tex]1440 + 37 = 1477 \; minutes[/tex]
1 minute = 60 seconds
1477 minute = X seconds
Cross-multiplying, we have:
[tex]X = 60[/tex] × [tex]1477[/tex]
X = 88620 seconds
Now, we can find the frequency of rotation of Mars by using the formula:
[tex]Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}[/tex]
Frequency of rotation = 0.0000113 Hertz
Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.
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A golf ball is hit with an initial velocity of 20m/s at an angle of 30° to the horizontal. calculate;
the time of flight
Answer:
tcucugxojfjgfojcigxuogoudyifodtufukdutfuocyjxuogu
On a hike you walk 5000 m east, 3000 m north and 1000 m west at a constant speed of 1m/s calculate your velocity
Answer:
0.44 EST + 0.33 NTH
Explanation:
if this is incorrect and brainly removes the comments to try and sabotage you guys please report this for the sake of learning
in loading a long lorry a man lifts boxes each of weight 100N and height of 1.5M.how much energy is transfered when one box is lifted
Explanation:
energy=100×1.5=150 joules
If the ambient temp. is 75 F, what is it Centigrade?
Explanation:
We know
C/5 = F -32/9C/5 = 75 -32/9C/5 = 43/9C ≈ 25°Chelp me besties ok thx
Answer:
[tex]1 \\ 0.5 \times 500 \times 20 \times 20 \\ \ 2 \\ 0.5 \times 0.6 \times 100 \times 100 \\ 3 \\ 1000 \times 0.5 \times 10 \times 10 \\ 1000 \times 0.5 \times 20 \times 20 \\ 1000 \times 0.5 \times 30 \times 30 \\ 4 \\ 0.5 \times 40000 \times 30 \times 30 \\ 5 \\ \sqrt{ \frac{2}{0.1 \times 0.5} } [/tex]
what is the force the when does when Gravity pushes you
Answer:
Image result for what is the force the when does when Gravity pushes you
The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.
Explanation:
Image result for what is the force the when does when Gravity pushes you
The important thing to remember is that gravity is neither a push nor a pull; what we interpret as a “force” or the acceleration due to gravity is actually the curvature of space and time — the path itself stoops downward.
Answer:
It is called gravitational force.
Explanation:
[tex]{ \boxed{ \rm{F = \frac{GM_{a} m _{a}}{ {r}^{2} } }}}[/tex]
F is the gravitational forceMa is the mass of a planetary bodyma is mass lf body being attractedr is the separation distanceG is the universal gravitational constant→ Assume you are in space and you have a mass of ma, and you are r metres from the Earth of mass Ma. The force F will be experienced and you will tend to be pulled towards the Earth when you are in its gravitational field.
What is the Normal CSF for:
Leukocytes (per mm³)
% Neutrohils
Glucose (mg/dL)
Protein (mg/dL)
Please provide source if possible.
1. 5 WBC's per cubic millimeter.
3. 50 to 80 mg/100 mL
4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)
If a test were to be performed here are normal results:
Normal values typically range as follows:
Pressure: 70 to 180 mm H2O
Appearance: clear, colorless
CSF total protein: 15 to 60 mg/100 mL
Gamma globulin: 3% to 12% of the total protein
CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)
CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells
Chloride: 110 to 125 mEq/L
(Source: https://medlineplus.gov/ency/article/003428.htm)
Which statement best explains how a planet affects the orbit of a comet as the comet passes by the planet?
1. A 6-volt battery produces a current of 0.5 amps. What is the power in the circuit?
Answer:
hope this will help you
have a great day
Explanation:
please mark me as the brainliest
pleease help me please!!!
Answer:
4 filter funnel 7 round bottom flask sorry but that is all I know
David was driving at a velocity of 5 m/s. He accelerates to a velocity of 8 m/s in 4 seconds. What is the acceleration?
Identify the given variables and the unknown
x distance
t time
Vi initial velocity
Vf final velocity
a acceleration
F force
If David was driving at a velocity of 5 m/s and accelerates to a velocity of 8 m/s in 4 seconds, David's acceleration is 0.75 [tex]m/s^2[/tex].
Given the following data:
Initial velocity, Vi = 5 m/sFinal velocity, Vf = 8 m/sTime, t = 4 seconds.To find David's acceleration:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]
Where:
Vf is the final velocity.Vi is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]Acceleration = \frac{8\; - \;5}{4}\\\\Acceleration = \frac{3}{4}[/tex]
Acceleration = 0.75 [tex]m/s^2[/tex].
Therefore, the David's acceleration is 0.75 [tex]m/s^2[/tex].
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A plane moves 599 m northeast along a runway.
If the northern component of this displacement
is 89 m, how large is the eastern component?
The eastern component of the plane's displacement is 592.35 m.
The given parameters;
the resultant of the plane displacement = 599 mthe northern component of this displacement, Y = 89 mLet the eastern component of this displacement = XThe eastern component of the plane's displacement is calculated by applying Pythagoras theorem as follows;
X² + Y² = 599²
X² + 89² = 599²
X² = 599² - 89²
X² = 350880
X = √350880
X = 592.35 m
Thus, the eastern component of the plane's displacement is 592.35 m
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Select the correct answer.
What does the expression “75 meters per second southeast” best describe?
A.
acceleration
B.
distance
C.
speed
D.
velocity
Answer:
my answer would be A I'm not sure about that
Answer: The answer would be D. Velocity
Explanation: Velocity is measured in meters per second.
Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.
The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:
The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.
The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.
A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is
E = h νν
Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.
If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.
In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.
In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:
The general shape is that of a black body and the peaks are due to chemical compounds or elements in the star.
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a stone is dropped down an empty mine shaft. it takes 3 seconds to reach the bottom. assuming that the stone falls from rest and accelerates at 10m/s^2, calculate.
a) the maximum speed reached by the stone before hitting the bottom.
b) the average speed of the stone in flight.
c) the depth of the mine shaft.
Answer:
I think A. I had a similar question
Explanation: