Question 2 (1 point)
A group of friends is cooking an exotic stew in a house in South Florida. One of the
steps of the recipe is that they have to cool off the cooking mixture from 81.70 °C to
49.10 °C. The pot is too big to put it in a fridge for cooling down faster, the cooking
mixture weighted 34.6 kg. Fortunately, one of the friends remembered
thermochemistry and suggested that they put the pot in the small pool that is at the
house to cool it off faster. The pool was not heated and its temperature before
putting the pot with the stew was 19.24 °C. Given that the mass of water in the pool
was 4,825.6 kg, and the specific heat capacity of the pool is 4.30 J/(g°C) and that of
the cooking mixture is 4.20 J/(g°C), what is the final temperature of the pool after
the cooking mixture cooled down to the temperature needed by the recipe?
Your Answer:
Answer
units

Explanation:

hello

the answer is b

O or oxygen has 16 molar mass and C or carbon has 12

so CO2 or carbon dioxide=(2×O)+C=(2×16)+12=46

Answer:

[tex]\fbox{c = - 4.01 \: joule/g°C}[/tex]

Step by step explanation:

Given:

Mass of given sample (m) = 2.50 g

Initial temperature (T1) = 25°C

Final temperature (T2) = 20°C

Heat Energy Q = 12 cal

To find:

[tex]Specific \: Heat \: c = \: ?[/tex]

Solution:

We know that,

Specific heat of any substance is directly proportional to the mass and change in temperature.

Represented by equation,

[tex]Q = mc \triangle T[/tex]

Where,

Q = Heat Energy

m = mass of given sample

c = specific heat

∆T = change in temperature

Substituting corresponding values,

[tex]Q = mc \triangle T \\ 12 = 2.5\times c \times (20-25) \\ c = \frac{12}{2.5 \times ( - 5)} \\ c = - 0.96 \: cal/g°C \\ [/tex]

We also know that,

[tex]1 \: cal = 4.184 \: joules[/tex]

multiplying above answer by 4.184,

[tex]c = - 0.96 \times 4.184 \\ \fbox{c = - 4.01 \: joule/g°C}[/tex]

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Answer:

c

Explanation:

lol

Answer:

the sun i think because the sun has the greatest gravitational pull

Answer:

C. can be turned on and off

Explanation:

An electromagnet becomes magnetic when it is part of a complete electric circuit. A switch is a part of an electric circuit that completes or break the circuit turning the circuit on and off.

(*) Sorry for my late answer but I hope this helps others that are looking for this.

I got 100%  ;)

Answer:

[tex]{\rm Ba^{2+}} \, (aq) + {\rm {SO_4}^{2-}}\, (aq) \to {\rm BaSO_{4}}\, (s)[/tex].

Explanation:

Make use of the fact that calcium sulfate [tex]{\rm CaSO_{4}}[/tex] and magnesium sulfate [tex]{\rm MgSO_{4}}[/tex] are much more soluble in water than barium sulfate [tex]{\rm BaSO_{4}}[/tex].

When sulfate ions [tex]{\rm {SO_{4}}^{2-}}[/tex] are added to dilute solutions containing [tex]{\rm Ba^{2+}}\, (aq)[/tex], [tex]{\rm Ca^{2+}}\, (aq)[/tex], and [tex]{\rm Mg^{2+}}\, (aq)[/tex], precipitation would be visible only in the solution with [tex]{\rm Ba^{2+}}\, (aq)\![/tex]. Barium sulfate would be the precipitate.

[tex]{\rm Ba^{2+}} \, (aq) + {\rm {SO_4}^{2-}}\, (aq) \to {\rm BaSO_{4}}\, (s)[/tex].

This ionic equation is balanced as it conserves both the atoms and the charges on the ions.

Factors that will increase product formation are;

The position of chemical equilibrium is affected by the following factors:

When equilibrium is altered by an external factor, the reaction shifts to annul the effect of that change.

For the reversible exothermic synthesis, low temperature and high pressure will shift the reaction farthest toward the products.

For the reaction of the 2.0g piece of Mg with HNO3. increasing the surface area of magnesium metal as well as increasing the concentration of HNO3 would produce the GREATEST reaction rate.

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Answer:

Explanation:

Answer:

car hornsss

Explanation:

they loud asl

Answer:

B

Explanation:

By finding how quickly the ice pathes melt you are able to tell how well the salt dissolves in water (ice is the solid form of H2O). Different types of salts will melt the ice at different speeds.

This is also the only answer choice that correlates with melting points so :)

Answer:

i believe 223

Explanation:

T2 + 500k = 223 C*

Answer:

Lim reag = NO        .07 mole of O2 left over

Explanation:

From the equation, you need twice as many moles of NO as O2

  2 x moles O2 =     2 * .503 moles = 1.06 moles of NO needed....you do not have enough so this is the limiting reagent    O2 will be left over

    1/2 * .866 = .433  moles of O2 used    .503 - .433 = .07  mole O2 leftover

Taking into account the definition of a system of linear equations and molar mass, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values ​​of the unknowns must be sought, with which when replacing, they must give the solution proposed in both equations.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

Being the molar masses of the compounds:

and considering the definition of molar mass of a compound, the system of equations to be solved is

[tex]\left \{ {{3mA + mB=98.33\frac{g}{mole} } \atop {mA + 2mB=62.77\frac{g}{mole} }} \right.[/tex]

where mA and mB are the molar masses of elements A and B respectively.

There are several methods to solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

Isolating the variable mB from the first equation:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA

and substituting in the second equation, you get:

mA + 2× (98.33 [tex]\frac{g}{mole}[/tex] - 3mA)=62.77[tex]\frac{g}{mole}[/tex]

Solving:

mA + 2× 98.33 [tex]\frac{g}{mole}[/tex] - 2×3mA=62.77[tex]\frac{g}{mole}[/tex]

mA + 196.66 [tex]\frac{g}{mole}[/tex] - 6mA=62.77[tex]\frac{g}{mole}[/tex]

mA - 6mA=62.77[tex]\frac{g}{mole}[/tex] - 196.66 [tex]\frac{g}{mole}[/tex]

(-5)mA= - 133.89 [tex]\frac{g}{mole}[/tex]

mA= (- 133.89 [tex]\frac{g}{mole}[/tex] )÷ (-5)

mA= 26.778 [tex]\frac{g}{mole}[/tex]

Remember that mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3mA, replacing the value of mA:

mB= 98.33 [tex]\frac{g}{mole}[/tex] - 3×(26.778 [tex]\frac{g}{mole}[/tex])

mB= 80.334 [tex]\frac{g}{mole}[/tex]

mB= 17.998 [tex]\frac{g}{mole}[/tex]

Finally, the molar masses of elements A and B are 26.778 [tex]\frac{g}{mole}[/tex] and 17.998[tex]\frac{g}{mole}[/tex] respectively.

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Answer:

b.exothermic and entropy is decreasing

Answer:

A

Explanation:

it can occur between two hydrogen bonds

Answer:

c. energy from splitting energy

Explanation:

The volume, in Liters, that would be required to obtain 0.500 moles of Br ions from 1.40 M FeBr2 will be 0.36 L

Recall that:

Molarity = mole/volume

In this case, molarity = 1.40 M and moles = 0.500 moles

Thus:

Volume = mole/molarity = 0.500/1.40 = 0.36 L

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Answer:

Si, Sn, Cs

Explanation:

                       Atomic no.          Atomic radius

Silicon Si_______14___________0.117
Tin         Sn______50___________0.140
cesium Cs______55___________0.262

Silicon is the smallest among these

Explanation:

36.5 g of HCl occupies 2.24×10-2m3 . ∴ 73 g of HCI at STP will occupy 2.24×10-236.5×732=4.48×10-2m3.

Answer:

If temperature stays the same, the amount of carbon dioxide dissolved in the ocean would increase.

Explanation:

The carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) and the carbon dioxide dissolved in the ocean ([tex]{\rm CO_{2}}\, (aq)[/tex]) are in a solution equilibrium:

[tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex].

Assume that the concentration of carbon dioxide in the air ([tex]{\rm CO_{2}}\, (g)[/tex]) increased while temperature stayed the same.

By Le Ch[tex]^{}[/tex]atelier's Principle, the solution equilibrium [tex]{\rm CO_{2}}\, (g) \rightleftharpoons {\rm CO_{2}}\, (aq)[/tex] would shift to offset this increase in [tex]{\rm CO_{2}}\, (g)[/tex] concentration. Specifically, this equilibrium would reduce the amont of [tex]{\rm CO_{2}}\, (g)\![/tex] in the system by converting more atmospheric [tex]{\rm CO_{2}}\, (g)\!\![/tex] to [tex]{\rm CO_{2}}\, (aq)\![/tex] dissolved in the ocean. Therefore, the concentration of [tex]{\rm CO_{2}}\, (aq)\!\![/tex] dissolved in the ocean would increase.

Explanation:

Zn + Sn3(PO4)4 = Zn3(PO4)2 + Sn - Balanced Chemical Equation

4.3 is limiting

is the answer

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Answer: Smelling salts and oxygen are introduced into a metal catalyst-containing tube (platinum). Typically warmed to get the reaction started. The alkali is then oxidized to produce nitric oxide.

Answer:

The Ostwald process is a chemical process used for making nitric acid. Wilhelm Ostwald developed the process, and he patented it in 1902. The Ostwald process is a mainstay of the modern chemical industry, and it provides the main raw material for the most common type of fertilizer production

Explanation:

The first stage of the Ostwald process involves the catalytic oxidation of ammonia into nitric oxide, using platinum as the catalyst. The nitric oxide is then transferred to a different oxidizing tower, where it is oxidized into nitrogen dioxide

Temperature and pressure control the phase of a substance. A phase diagram is a graph of pressure versus temperature that shows in which phase a substance exists under different conditions of temperature and pressure. A phase diagram typically has three regions, each representing a different phase, and three curves that separate each phase.

In a phase diagram, the three regions correspond to the three common phases of matter: solid, liquid, and gas. The curves that separate each phase are known as phase boundaries or phase transition lines. These curves represent the conditions (specific combinations of pressure and temperature) at which phase transitions occur, such as melting (solid to liquid), boiling (liquid to gas), or sublimation (solid to gas).

Each phase boundary on the phase diagram represents the equilibrium between two phases, and the triple point, where all three phase boundaries intersect, represents the conditions where all three phases coexist in equilibrium.

Phase diagrams are essential tools in understanding the behavior of substances under different temperature and pressure conditions and are used in various fields, including chemistry, physics, and materials science. They provide valuable information about the stability and existence of different phases and the conditions under which phase transitions occur.

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For a gas made up of homonuclear diatomic molecules escapes through a pinhole 0.378 times as fast as He gas, the chemical formula of the gas  is mathematically given as

N2(nitrogen gas)

Generally, the equation for the rate to molar relationship  is mathematically given as

\frac{r1}{r2}=\frac{mm2}{mm1}

Thereofore

\frac{r}{r2}=0.378

Hence

0.378=\sqrt{\frac{4.00268}{Mx2}}

Mx2=28.013g/mol

In conclusion,The name of gas with a molar mass of 28.013g/mol is N2

Therefore, the chemical formula of the gas. is N2

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For a [Cd2+]=0.00190 M and [Au3+]=0.788 M conc, the cell potential  is mathematically given as

Ecell=1.98V

Generally, the equation for the  Chemical reaction is mathematically given as

Cd2+(aq) + 2e – → Cd(s)

Au3+(aq) + 3e– → Au(s)

Therefore

Ecell=Ecell-0,0582/nlog

Therefore

Ecell=Ered-Eoxy

Ecell=1.498-(-0.403)

Ecell=1.901

In conclusion

Ecell=1,901-0,0592/6log(0,0016/0.88)^2

Ecell=1.98V

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Answer:

the image is not clear....

expect what to have?!?!?!?