Question 1

Sione just landed a great job as an engineer where he will make $55,000 a year. The

company he will work for guarantees a 3% pay increase each year so it's employees

salaries keep up with inflation. At the end of the 1* year Slone will have made $55,000

dollars.

1. What is the recursive function that will represent this situation?

a. m(t) = m(t - 1) + 0.03, m(1) = 55000

b. m(t) = m(t-1). 0.03, m(1) - 55000

c. m(t) = m(t-1) + 1.03, m(1) - 55000

d. m(t) = m(t-1). 1.03, m(1) = 55000

Answer:

Step-by-step explanation:

The weights in pounds of the defensive linemen were :

254,311, 297, 323, 260, 242, 300, 252, 303, 274

Ascending order: 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

The weights in pounds of the offensive linemen were :

310 ,315, 305, 318, 298, 301, 321, 332, 320

Ascending order:298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

a)

Offensive line       Stem        Defensive line

                               24     |            2

                               25     |            2 , 4

                               26     |            0

                               27     |            4

         8             |      29     |           7

      1,5              |      30     |           0,3

     0,5,8           |      31      |           1

     0,1               |      32     |           3

      2                |      33     |

Five number summary of offensive line:

1) minimum: 298

2) maximum: 332

3)

Lower quartile:298 ,301 ,305 ,310

Q1 is the median of lower quartile

[tex]Q1=\frac{301+305}{2}=303[/tex]

4)

Upper quartile:318 ,320 ,321 ,332

Q3 is the median of upper quartile

[tex]Q3=\frac{320+321}{2}=320.5[/tex]

5)

Q2 is the median

 298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

Mid value =[tex]\frac{9+1}{2}[/tex]=5th term = 315

Q2=315

Five number summary of defensive line:

1) minimum: 242

2) maximum: 323

3)

Lower quartile:242 ,252 ,254 ,260 ,274

Q1 is the median of lower quartile

Q1=254

4)

Upper quartile:297 ,300 ,303 ,311 ,323

Q3 is the median of upper quartile

Q3=303

5)

Q2 is the median

 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

Mid value =\frac{274+297}{2}=285.5

Q2=285.5

c) Mean weight of offensive line = [tex]\frac{298+301+305+310+315+318+320+321+332}{9}=313.33[/tex]

Mean weight of defensive line = [tex]\frac{242+252+254+260+274+297+300+303+311+323}{10}=281.6[/tex]

Mean weight of offensive line is more

So, Offensive group of players tends to be heavier

Answer:

54.7599

Step-by-step explanation:

Answer:

I think it is 3x-7y=-28

Answer:

[tex]A = 97.50 + H[/tex]

Step-by-step explanation:

Given

Stocks: AT&T and IBM HockUnx

Required

Determine the algebraic expression

Represent AT&T with A and IBM HockUnx with H.

Since AT&T is 97.5 more than IBM HockUnx;

The required expression is:

[tex]A = 97.50 + H[/tex]

Answer:

[tex]x = 4y[/tex]

Step-by-step explanation:

Given

[tex]y = kx[/tex]

See attachment for options.

Required

Determine which of the options answers the question

Analyzing the option one after the other:

[tex]\frac{x}{y} = 4[/tex]

Multiply through by y

[tex]y * \frac{x}{y} = 4 * y[/tex]

[tex]x = 4y[/tex]

Divide through by 4

[tex]\frac{x}{4} = \frac{4y}{4}[/tex]

[tex]\frac{x}{4} = y[/tex]

This can be rewritten as

[tex]y = \frac{x}{4}[/tex]

[tex]y = \frac{1}{4} x[/tex]

By comparison with [tex]y = kx[/tex]

we have:

[tex]y = y[/tex]

[tex]x = x[/tex]

[tex]k = \frac{1}{4}[/tex]

Hence: this answers the question.

Answer:

162 is greater than 130.. if that's what your are talking about..

Answer:

C.50

Step-by-step explanation:

It would be 50 because there are 2 sides to the coin. So if you take 100/2 you get 50. that would be the best estimate answer in my opinion

Number of times the coin will land heads will be 50

Number of trials or observation when each trial has the same probability of attaining one particular value. It determines the probability of observing a specified number of successful outcome in a specific number of trial.

Here , number of times the coin had tosses: 100

P(probability of getting a head in a coin ) : number of time head can come when flipped once / total number of observations

 since , head can come once and there are two possibility either head or tail

hence P= 1/2

this implies number of times heads land up = n*P = 100 *(1/2) = 50

option c) 50

Let us learn more about binomial distribution:

https://brainly.com/question/13634543?referrer=searchResults

#SPJ2

Answer:

2

Step-by-step explanation:

Slope equation: (y2-y1)/(x2-x1)

y2 = 4, y1 = -2, x2= 5, x1 = 2

4 – -2 = 6

5 - 2=3

6/3 = 2

Answer:  y=759

Step-by-step explanation:

y = (25 - 2) (35 - 2)

y = (23) (33)

y = 759

Answer:

y = 759

Step-by-step explanation:

subtract the numbers

y = 23 (35 - 2)

y = 23 x 33

Multiply the numbers

y = 759

Solution

y = 759

Answer:

32 hours and 15 minutes or 32.4

Step-by-step explanation:

12 divided by 10 = 1.2

27 x 1.2 = 32.4 or 32 hours and 15 minutes

Answer:

he can make 6 goodie bags

Step-by-step explanation:

Answer:

$651.36

Step-by-step explanation:

13.57x48

Answer:

a

Step-by-step explanation:

Answer:

x=2

Step-by-step explanation:

12=12 2=2

the sides have the same x

Answer:

|-3|, |-3.52|, |8|, |-11|

Step-by-step explanation:

Hope this helps my guy

Answer:

Well, this is fairly simple.

Step-by-step explanation:

Those |  | on either side of all the numbers are absolute value lines.

Those things are everyone's best friend. They turn every number positive, and essentially make your day better.

So, using that knowledge, I can look at your numbers and tell you with confidence that the correct order is |-3|, |-3.52|, |8|, |-11|.

If I'm wrong, go ahead, shoot me. Sounds lovely.

Answer:

x= 4.3125

Step-by-step explanation:

Answer:

x=4+7i and x=4-7i

Step-by-step explanation:

Rewrite the given quadratic equation by completing the square.

x^2-8x=-65

x^2-8x+16=-65+16

x^2-8x+16=-49

(x-4)^2=-49

Now, solve the equation by applying the square root property and isolating x.

(x-4)^2=-49

√(x-4)^2 = √-49

x-4=+7i

x=4+7i

So, the solutions to the given quadratic equation are x+4+7i and x=4-7i.

Answer:

a

Step-by-step explanation:

Answer:will hope it help to find the answer with an unqualified

Step-by-step explanation:

Answer:

b y= 3x+6 is the ans but not sure

Step-by-step explanation:

Given data

Let the cheese be x

And strawberry be y

So

6x+6y=96-------1

x+4y=52----------2

Solving 1 and 2 simultaneously

Let us multiply equation 2 by 6 we have

6x+6y=96

6x+24y=312

-0-18y=-216

18y=216

y=216/18

y=12

Put y=12 in equation 2

x+4*2=52----------2

x+8=52

x=52-8

x=44

cheese =44

strawberry =12

Answer: I'd go with Option (C.<3 AND 4, <6 AND 4)

Answer: The answer is D

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that the cost of the ticket is

$43.32

and the price decrease is by $0.25

let the cost be C

and let the number of losses be L

the expression for the cost we be

C=43.32-0.25L

for the number of losses which is 22 we have

C=43.32-0.25(22)

C=43.32-5.5

C=37.82

Therefore the price after 22 losses is $37.82

Answer:

$x/3

Step-by-step explanation:

Answer:

Step-by-step explanation:

The number of rectangles and combinations:

Total

Now the number of,

Rectangles and combinations are,

→ 1 rectangle = 6

→ 2 rectangles = 5

→ 3 rectangles = 4

→ 4 rectangles = 3

→ 5 rectangles = 2

→ 6 rectangles = 1

Then the total number is,

→ 6+5+4 + 3+2+1

→ 15 + 6 = 21

Hence, total number is 21.

Answer:

q1 (1,-3)

r1 (3,3)

s1 (0,2)

t1 (-2,-1)

Step-by-step explanation:

When a shape is reflected, it must be reflected across a line

The vertices for [tex]\mathbf{rx-axis}[/tex] of qrst are:

The given parameters are:

[tex]\mathbf{q = (1,3)}[/tex]

[tex]\mathbf{r = (3,-3)}[/tex]

[tex]\mathbf{s = (0,-2)}[/tex]

[tex]\mathbf{s = (-2,1)}[/tex]

The transformation rule is given as:

[tex]\mathbf{rx-axis}[/tex]

The above rule means that the vertices are reflected over the x-axis

The rule of the transformation is:

[tex]\mathbf{(x,y) \to (x,-y)}[/tex]

So, we have:

[tex]\mathbf{q(1,3) \to q'(1,-3)}[/tex]

[tex]\mathbf{r(3,-3) \to r'(3,3)}[/tex]

[tex]\mathbf{s(0,-2) \to s'(0,2)}[/tex]

[tex]\mathbf{t(-2,1) \to t'(-2,-1)}[/tex]

Hence, the vertices for [tex]\mathbf{rx-axis}[/tex] of qrst are:

[tex]\mathbf{q'(1,-3)}[/tex]

[tex]\mathbf{ r'(3,3)}[/tex]

[tex]\mathbf{ s'(0,2)}[/tex]

[tex]\mathbf{t'(-2,-1)}[/tex]

Read more about reflections at:

https://brainly.com/question/938117

Answer:

y=-1.9x-1

Step-by-step explanation: