Answer:
[tex](-9,\, 17)[/tex] is in the second quadrant of a cartesian plane.
Step-by-step explanation:
The horizontal and vertical axes divides the cartesian plane into four quadrants. The quadrants are numbered counterclockwise, starting from the top-right corner:
[tex]\begin{array}{c|c}\text{second quadrant} & \text{first quadrant} \\\cline{1-2} \text{third quadrant} & \text{fourth quadrant}\end{array}[/tex].
(The quadrants do not include the two axes. Points on either axes are not in any of the quadrant.)
A point in the form [tex](x_{0},\, y_{0})[/tex] is on the right half of the plane (to the right of the vertical axis) if [tex]x_{0} > 0[/tex]. This point is on the vertical axis through the middle of the plane if [tex]x_{0} = 0[/tex]. Otherwise, if [tex]x_{0} < 0[/tex], this point would be on the left half of the plane (to the left of the vertical axis.)
The [tex]x[/tex]-coordinate of [tex](-9,\, 17)[/tex] is [tex]x_{0} = -9[/tex].
Since the [tex]x[/tex]-coordinate of this point is below zero ([tex](-9) < 0[/tex]), this point would be on the left-hand side of the origin to the left of the vertical axis.
Likewise, a point in the form [tex](x_{0},\, y_{0})[/tex] is above the horizontal axis if [tex]y_{0} > 0[/tex], on the horizontal axis if [tex]y_{0} = 0[/tex], and below the horizontal axis if [tex]y_{0} < 0[/tex].
The [tex]y[/tex]-coordinate of the given point [tex](-9,\, 17)[/tex] in this question is [tex]y_{0} = 17[/tex].
Since the [tex]y[/tex]-coordinate of this point is greater than zero ([tex]17 > 0[/tex]), this point would be above the horizontal axis.
Thus, the point [tex](-9,\, 17)[/tex] would be in the top-left quarter of the plane. The top-left quarter of the plane corresponds to the second quadrant, since this quadrant is the second quadrant after the first quadrant in the top-right corner. Hence, [tex](-9,\, 17)\![/tex] would be in the second quadrant of the plane.
Hello someone help me please
Answer:
b
Step-by-step explanation:
What is the value of the expression if q = 6 a n d r = 4
Answer:
66 (lmk if i'm wrong)
Step-by-step explanation:
9x6 + (16-4)
54 +12
66
1/5(x + 0.5) + 5.24 = 3/2x + 7/10(x + 2.2)
Solve for x
Answer:
x=19/10
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
1/5(x+0.5)+5.24=3/2x +x+7/10(x+2.2)
(1/5)(x)+(1/5)(0.5)+5.24=3/2x+(7/10)(x)+(7/10)(2.2)(Distribute)
1/5x+0.1+5.24=3/2x+7/10x+1.54
(1/5x)+(0.1+5.24)=(3/2x+7/10x)+(1.54)(Combine Like Terms)
1/5x+5.34=11/5x+1.54
Step 2: Subtract 11/5x from both sides.
1/5x+5.34−11/5x=11/5x+1.54−11/5x
−2x+5.34=1.54
Step 3: Subtract 5.34 from both sides.
−2x+5.34−5.34=1.54−5.34
−2x=
−19/5
Step 4: Divide both sides by -2.
−2x=−19/5
x= 19/10
Answer:
x= 19/10
Find the reciprocal of 4
Answer:
reciprocal of 4 = 1/4
Step-by-step explanation:
By definition, a reciprocal of a/b = b/a.
Since 4 is the same as 4/1, then it's reciprocal must be 1/4.
Answer:
1/4
Step-by-step explanation:
because 4 = 4/1
reciprocal means to flip it upside down 4/1 = 1/4
simplify the expression 8xy-(x+2xy)+3x
Answer:
6xy + 2x
Step-by-step explanation:
Simplify the expression.8xy-(x+2xy)+3x
If y=cosh(4tanh¯¹x) then dy/dx=
If you're like me and don't remember hyperbolic identities (especially involving inverse functions) off the top of your head, recall the definitions of the hyperbolic cosine and sine:
[tex]\cosh(x) = \dfrac{e^x + e^{-x}}2 \\\\ \sinh(x) = \dfrac{e^x - e^{-x}}2[/tex]
Then differentiating yields
[tex]\dfrac{\mathrm d(\cosh(x))}{\mathrm dx} = \dfrac{e^x-e^{-x}}2 = \sinh(x) \\\\ \dfrac{\mathrm d(\sinh(x))}{\mathrm dx} = \dfrac{e^x+e^{-x}}2 = \cosh(x)[/tex]
so that by the chain rule, if
[tex]y = \cosh\left(4\tanh^{-1}(x)\right)[/tex]
then
[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d\left(\cosh\left(4\tanh^{-1}(x)\right)\right)}{\mathrm dx} = \sinh\left(4\tanh^{-1}(x)\right) \dfrac{\mathrm d\left(4\tanh^{-1}(x)\right)}{\mathrm dx}[/tex]
Now, let [tex]z=4\tanh^{-1}(x)[/tex], so that (•) [tex]\tanh\left(\frac z4\right) = x[/tex].
Recall that
[tex]\tanh(x) = \dfrac{\sinh(x)}{\cosh(x)} = \dfrac{e^x-e^{-x}}{e^x+e^{-x}}[/tex]
and so the derivative of tanh(x) is
[tex]\dfrac{\mathrm d(\tanh(x))}{\mathrm dx} = \dfrac{(e^x+e^{-x})(e^x+e^{-x})-(e^x-e^{-x})(e^x-e^{-x})}{(e^x+e^{-x})^2} \\\\ = \dfrac{4\cosh^2(x)-4\sinh^2(x)}{4\cosh^2(x)} \\\\ = 1-\tanh^2(x) = \mathrm{sech}^2(x)[/tex]
where the last equality follows from the hyperbolic Pythagorean identity,
[tex]\cosh^2(x)-\sinh^2(x) = 1 \implies 1-\tanh^2(x) = \mathrm{sech}^2(x)[/tex]
Differentiating both sides of (•) implicitly with respect to x gives
[tex]\dfrac{\mathrm d\left(\tanh\left(\frac z4\right)\right)}{\mathrm dx} = \dfrac{\mathrm d(x)}{\mathrm dx} \\\\ \mathrm{sech}^2\left(\dfrac z4\right)\dfrac{\mathrm d\left(\frac z4\right)}{\mathrm dx} = 1 \\\\ \dfrac14 \mathrm{sech}^2\left(\dfrac z4\right) \dfrac{\mathrm dz}{\mathrm dx} = 1 \\\\ \dfrac{\mathrm dz}{\mathrm dx} = 4\cosh^2\left(\dfrac z4\right) \\\\ \dfrac{\mathrm dz}{\mathrm dx} = 4\cosh^2\left(\tanh^{-1}(x)\right)[/tex]
So, the derivative we want is the somewhat messy expression
[tex]\boxed{\dfrac{\mathrm dy}{\mathrm dx} = 4\sinh\left(4\tanh^{-1}(x)\right) \cosh^2\left(\tanh^{-1}(x)\right)}[/tex]
and while this could be simplified into a rational expression of x, I would argue for leaving the solution in this form considering how y is given in this form from the start.
In case you are interested, we have
[tex]\cosh\left(\tanh^{-1}(x)\right) = \dfrac1{\sqrt{1-x^2}}[/tex]
and you can instead work on differentiating that; you would end up with
[tex]\dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{16x^3+16x}{(x^2-1)^3}[/tex]
Add 2/5 + 3/6 + 1/4 0 1 11/60 O 13/20 o 17/20 1 13/60
Answer:
Step-by-step explanation:
-(8/11)/(-3/5) = -(8/11)*(-5/3)
-(8/11)*(-5/3) = 40/33 [ or 1 7/33]
I can't interpret the rest of the question. I see:
"Add 2/5 + 3/6 + 1/4 0 1 11/60 O 13/20 o 17/20 1 13/60"
PLZZZZZ HELP THIS IS DUE BY 8:00.Fred is trying to earn $35 to buy a basketball. He has saved $11.25. He earns $2.25 per hour doing yard work for his neighbor, and he earns $7.25 per hour selling sunglasses at the mall. Will Fred have enough to buy the basketball if he works in the yard for 2 hours and at the mall for 3 hours? Use the inequality 2.25y + 7.25z + 11.25 ≥ 35.
No, because the total will be $58.75.
No, because the total will be $21.25.
Yes, because the total will be $37.50.
Yes, because the total will be $26.25.
Answer:
the answer is d (the last one)
Step-by-step explanation:
2.25 * 2 = 4.5
+
7.25 * 3 = 21.75
= 26.25
he needs 35, so it's not enough
Directions: Use the information in the charts to answer the questions. Type of Fruit Cost Estimated Cost apple $1.75/pound 8.75 orange $2.35/pound 9.40 banana $1.50/pound 4.50 Annie bought 5 pounds of apples, 4 pounds of oranges, and three pounds of bananas. a. Round the prices to the nearest whole dollar to estimate how much money she spent. b. How much money did Annie actually spend? Write a numerical expression to represent the amount of money that Annie spent. Was your estimation an overestimation or underestimation? Why do you think that might be?
Estimates are used to make prediction about an actual value
Annie estimated spending $52Annie actually spent $48.25Your estimation is an overestimationThe chart is given as:
Fruit Cost Estimated
Apple $1.75/pound 8.75
Orange $2.35/pound 9.40
Banana $1.50/pound 4.50
The number of pounds of each fruit Annie bought are:
[tex]Apples= 5[/tex]
[tex]Orange = 4[/tex]
[tex]Banana = 3[/tex]
(a) The estimated amount
To do this, we make use of the estimated column.
So, we have:
[tex]Estimated = \sum Cost \times Pounds[/tex]
[tex]Estimated =1.75*5+8.75*4+1.50*3[/tex]
Approximate the prices
[tex]Estimated =2*5+9*4+2*3[/tex]
[tex]Estimated =52[/tex]
Hence, Annie estimated spending $52
(b) The actual amount spent
To do this, we make use of the cost column.
So, we have:
[tex]Actual = \sum Cost \times Pounds[/tex]
[tex]Actual =1.75*5+8.75*4+1.50*3[/tex]
[tex]Actual =48.25[/tex]
Hence, Annie actually spent $48.25
(c) The decision
By comparison, the estimated spending is greater than the actual amount spent.
Hence, your estimation is an overestimation
Read more about estimation at:
https://brainly.com/question/6768038
What is 0.579 x 10 to the power of 4
Answer:
5790
Step-by-step explanation:
Hope this helps! Pls give brainliest!
Answer:
5790
Step-by-step explanation:
0.579 × [tex]10^{4}[/tex]
Calculate 10 to the power of 4 and get 10000.
0.579 × 10000
Multiply 0.579 and 10000 to get 5790
5790
h(x)=17, x=?
H(x)=5x+2
I don't know how to find x?
Answer:
• If h(x) is 17, equate the whole function to 17
[tex]{ \tt{5x + 2 = 17}} \\ \\ { \tt{5x = 17 - 2}} \\ \\ { \tt{5x = 15}} \\ \\ { \boxed{ \tt{x = 3}}}[/tex]
4. Jason drove 200 miles in 8 hours. How many miles did Jason drive per
hour? (answer with just a number)
Answer:
25
Step-by-step explanation:
The figure shows a utility pole with an electrical line and a telephone line.
The angled wire is a tension wire.
Complete the table: for each angle pair given, identify the transversal and classify the angle pair. (Hint: Think of the utility pole as a line for these problems.)
Note: I’ll give you a lot of points for this
Answer:
Step-by-step explanation:
7. What is the value of z in the solution to the systems of linear equations shown below?
-x+ 2y + 2z= -4
4x +y-3z=13
x- 5y +z = -23
Step-by-step explanation:
[tex]1) \: \: - x + 2y + 2z = - 4 \\ 2z = - 4 + x - 2y \\ z = \frac{ - 4 + x - 2y}{2} \\ \\ 2) \: \: 4x + y - 3z = 13 \\ - 3z = 13 - 4x - y \\ z = \frac{13 - 4x - y}{ - 3} \\ \\ 3) \: \: x - 5y + z = - 23 \\ z = - 23 - x + 5y \\ [/tex]
What is the value of the expression g . (g + 1)^2 for g= 2 ?
Hello!
Answer:
g = 9
Step-by-step explanation:
(g+1)^2
Plug in 2 for g: (2+1)^2
Add 2 and 1: (3)^2
Simplify: (3 x 3)= 9
Hope this helps.
Multiply. (−6/35)⋅14/27 What is the product? Enter your answer as a fraction, in simplified form, in the box.
Answer:
-4/45
Step-by-step explanation:
[tex]\dfrac{-6}{35}*\dfrac{14}{27}=\dfrac{-6}{5}*\dfrac{2}{27}[/tex]
14 and 35 are given by 7th table.
[tex]= \dfrac{-2}{5}*\dfrac{2}{9}[/tex]
Now , 6 and 27 are given by 3rd table
[tex]=\dfrac{-4}{45}[/tex]
Answer:
-4/45
Step-by-step explanation:
2.03 Quiz: Multiply Signed Fractions
what number has the prime factorization 2 6th * 5 6th show your work
less than a number
Х
A, 12-x
B. 12x
C. X + 12
D. X-12
Answer:
D) X-12
Step-by-step explanation:
imagine that X = 2 or any number less than 12
A) 12 - X = 12 - 2 = 10
B) 12X = 12 ×2 = 24
C) X + 12 = 2 + 12 = 14
D) X - 12 = 2 - 12 = -10
So, the smallest number is (D)
Hope it's help.
Nolan’s car used 2 gallons to travel 50 miles. How far can he travel on 3 gallons?
Answer:
75 miles
Step-by-step explanation:
because half of 50 is 25 so 25x2 is 50 and 50 plus 25 is 75
Answer:
75
Step-by-step explanation:
count by 25's
25+25=50
50+25=75
The population P of a small town, measured in hundreds, is modeled by the inverse of the function P−1(t) = 10ln(50t − 1000), where t is measured in years. Find the equation to model the population and determine its initial value.
P = 5t +100 where P(0) = 100
P = 1/50 In(0.1t)+20
P = 1/500e^t + 20
P = 1/50e^0.1t + 20
Using the inverse function, it is found that the equation is:
[tex]P(t) = \frac{e^{0.1t}}{50} + 20[/tex]
It's initial value is 20.
---------------------------
We want to find the inverse of:
[tex]y = P^{-1}(t) = 10\ln{50t - 1000}[/tex]
To do this, we exchange y and t, and isolate y.
Then:
[tex]10\ln{50y - 1000} = t[/tex]
[tex]\ln{50y - 1000} = \frac{t}{10}[/tex]
[tex]e^{\ln{50y - 1000}} = e^{0.1t}[/tex]
[tex]50y - 1000 = e^{0.1t}[/tex]
[tex]50y = e^{0.1t} + 1000[/tex]
[tex]y = \frac{e^{0.1t} + 1000}{50}[/tex]
[tex]y = \frac{e^{0.1t}}{50} + \frac{1000}{50}[/tex]
[tex]P(t) = \frac{e^{0.1t}}{50} + 20[/tex]
It's initial value is:
[tex]P(0) = \frac{e^{0.1(0)}}{50} + 20 = 0.02 + 20 = 20.02[/tex]
Rounding, 20.
A similar problem is given at https://brainly.com/question/23950969
Answer:
P = 1/50e^0.1t + 20
Step-by-step explanation:
In a class of 28 students, 12 students packed their lunch. At this rate, how many students out of 336 would be expected to pack their lunch?
Answer:
144 students
Step-by-step explanation:
12/28=3/7
3/7*336=144
Unit rate is the quantity of an amount of something at a rate of one of another quantity.
If out of 28 students, 12 students packed their lunch.
The number of students who packed their lunch out of 336 students is 144 students.
What is a unit rate?It is the quantity of an amount of something at a rate of one of another quantity.
Example:
3 miles in 3 hours.
1 mile in one hour.
We have,
In a class of 28 students, 12 students packed their lunch.
We can write this as:
28 students = 12 students packed lunch ______(1)
We have to make 28 students into 336 students.
This can be done by multiplying 12 on both sides of the equation (1)
Multiply 12 on both sides.
12 x 28 students = 12 x 12 students packed lunch
336 students = 144 students packed lunch
Thus,
The number of students who packed their lunch out of 336 students is 144 students.
Learn more about unit rates here:
https://brainly.com/question/11258929
#SPJ5
Be Precise in the number 24.543, why is the value of each
4 different?
what is 5 +10 - 20 x 4
Answer:
-65 is the right answerrr
Helppppppppppppp need it now
Answer:
got
submited
showed
arrived
already filled
Step-by-step explanation:
What are the steps to solving this following equation? Put answer and steps.
(5) * (-9) * (-2)
Answer:
90
Step-by-step explanation:
you can multiply anything here in any order.
you could first do 5 times -9
5 * -9 = -45
and then multiply the -2 to the -45
-2 * -45 = 90
Graph the number on the number line. Then use your number line to find the
absolute value.
-3
10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3
O
-3
4 5 6 7 8 9 10
?
The absolute value of -3 is
Answer:
3
Step-by-step explanation:
The opposite of -3 is 3.
Enter the correct answer in the box
Simplify the expression (62)4
Answer:
62•4=248
[tex]63^{4} =2^{24}[/tex]
Step-by-step explanation:
I didn't know which one you needed so here's both.
How many solutions are there for this equation? Why?
Answer:
d
Step-by-step explanation:
PLEASE I NEED HELP WITH THIS SO I CAN PASS
Answer:
the answer is------------ 1/4.4.4
Find a10, for the geometric sequence an = 3(4)^n-1.
A. 262,144
B. 786,432
C. 1,048,579
D. 3,145,728