P(3) is approximately equal to 0.139.
(a) Yes, we can use the Poisson approximation to find P(30 < x < 35) because both np and n(1-p) are greater than or equal to 10, where n = 100 and p = 0.3. Therefore, the conditions for the Poisson approximation are satisfied.
Using Poisson approximation, we have:
λ = np = 100 x 0.3 = 30
P(30 < x < 35) ≈ P(X = 31) + P(X = 32) + P(X = 33) + P(X = 34)
= e^(-λ) * ([tex]λ^31[/tex] / 31!) + e^(-λ) * (λ^32 / 32!) + e^(-λ) * (λ^33 / 33!) + e^(-λ) * (λ^34 / 34!)
≈ 0.1885
(b) Using the normal approximation, we have:
µ = np = 100 x 0.3 = 30
σ = sqrt(np(1-p)) = sqrt(100 x 0.3 x 0.7) = 4.58
P(30 < x < 50) ≈ P((30 - µ)/σ < (x - µ)/σ < (50 - µ)/σ)
≈ P(-4.34 < Z < 4.34) [where Z is a standard normal random variable]
≈ 1
Therefore, P(30 < x < 50) is approximately equal to 1.
(c) Let x be a binomial random variable with n = 4 and P(0) = 0.0081.
We need to find P(3).
Let P(1) = q
Then, from the given information, we have:
P(0) = (1-q)^4 = 0.0081
Solving for q, we get:
q = 1 - (0.0081)^(1/4) ≈ 0.207
Now, using the binomial probability formula, we have:
P(3) = (4 choose 3) * q^3 * (1-q)^1
= 4 * 0.207^3 * 0.793
≈ 0.139
Therefore, P(3) is approximately equal to 0.139.
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Consider a sample of 53 football games, where 27 of them were won by the home team. Use a. 05 significance level to test the claim that the probability that the home team wins is greater than one-half
The calculated test statistic is 0.571. P 0.5, the null hypothesis.
A one-tailed z-test can be used to verify the assertion that there is a higher than 50% chance of the home side winning.
p > 0.5, where p is the percentage of football games won by the home team in the population.
The test statistic is calculated as:
(p - p) / (p(1-p) / n) = z
If n = 53 is the sample size, p = 0.5 is the hypothesized population proportion, and p is the sample fraction of football games won by the home team.
The percentage of the sample is p = 27/53 = 0.5094.
The calculated test statistic is:
z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53) = 0.571
We determine the p-value for this test to be 0.2826 using a calculator or a table of the normal distribution as a reference.
We are unable to reject the null hypothesis since the p-value is higher than the significance level of 0.05. Therefore, at the 5% level of significance, we lack sufficient data to draw the conclusion that there is a better than 50% chance of the home team winning.
The calculated test statistic is:
z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53)
= 0.571
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The dog shelter has Labradors, Terriers, and Golden Retrievers available for adoption. If P(terriers) = 15%, interpret the likelihood of randomly selecting a terrier from the shelter.
Likely
Unlikely
Equally likely and unlikely
This value is not possible to represent probability of a chance event
The likelihood of randomly selecting a terrier from the shelter would be unlikely. That is option B
How to calculate the probability of the selected event?The formula that can be used to determine the probability of a selected event is given as follows;
Probability = possible event/sample space.
The possible sample space for terriers = 15%
Therefore the remaining sample space goes for Labradors and Golden Retrievers which is = 75%
Therefore, the probability of selecting the terriers at random is unlikely when compared with other dogs.
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6. Caleb wants to buy a skateboard that costs $73.56. If sales tax is 7%, how much would his total purchase be?
Step-by-step explanation:
Total cost will be
$ 73.56 + 7% of 73.56
$ 73.56 + .07 * $73.56
(1.07) ( 73.56) = $ 78 . 71
Choose the correct description of the following quadratic formula hen compared to the parent function (x^2)
The description of the parabola of the quadratic function is:
It opens downwards and is thinner than the parent function
How to describe the quadratic function?The general formula for expressing a quadratic equation in standard form is:
y = ax² + bx + c
Quadratic equation In vertex form is:
y = a(x − h)² + k .
In both forms, y is the y -coordinate, x is the x -coordinate, and a is the constant that tells you whether the parabola is facing up ( + a ) or down ( − a ), (h, k) are coordinates of the vertex
In this case, a is negative and as such it indicates that it opens downwards and is thinner than the parent function
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Please help me with this asap
Answer:
m = - 3 , b = 5
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line
m = [tex]\frac{-1-5}{2-0}[/tex] = [tex]\frac{-6}{2}[/tex] = - 3
the y- intercept b is the value of y on the y- axis where the line crosses
that is b = 5
Answer:
b = 5
m = -3
Step-by-step explanation:
y-intercept is where the line intersects the y-axis. So, the line intersects at (0,5).
So, y-intercept = b = 5
Choose two points on the line: (0,5) and (1,2)
x₁ = 0 ; y₁ = 5
x₂ = 1 ; y₂ = 2
Substitute the points in the below formula to find the slope.
[tex]\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]= \dfrac{2-5}{1-0}\\\\=\dfrac{-3}{1}[/tex]
[tex]\boxed{\bf m = -3}[/tex]
John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first
In the given case equation P(A|B) = 0.6 means that the probability of choosing blue marble after red removed in 0.6
Let the event where the second marble chosen is blue be = B
Therefore, the Probability P(B|A) =0.6
Bayes' Theorem states that the likelihood of the second event given the first event multiplied by the probability of the first event equals the conditional probability of an event dependent on the occurrence of another event.
In the given case,
P(A|B) = probability of occurrence of A given B has already occurred.
P(B|A) = probability of occurrence of B given A has already occurred.
Therefore,
P(A|B) = P(B|A) P(A)/ P(B)
The likelihood of selecting a blue marble after removing a red stone is 0.6, which is how the probability P(B|A)=0.6 is defined.
Complete question:
John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first. Let A be the event where the first marble chosen is red. Let B be the event where the second marble chosen is blue. What does equation P(A|B) = 0.6 mean ?
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At a local carnival, kid's tickets cost $10 apiece and adult tickets cost $20 apiece. These are the only two types of tickets sold. At the recent show, 29 total tickets were sold for a total revenue of $430. How many children’s tickets were sold?
There are 15 children’s tickets were sold.
Given that;
At a local carnival, kid's tickets cost $10 apiece and adult tickets cost $20 apiece.
And, These are the only two types of tickets sold. At the recent show, 29 total tickets were sold for a total revenue of $430.
Let number of children’s tickets = x
And, Number of adult tickets = y
Hence, We can formulate;
⇒ x + y = 29 .. (i)
And, 10x + 20y = 430
⇒ x + 2y = 43
⇒ x = 43 - 2y
Plug above value in (i);
⇒ x + y = 29
⇒ 43 - 2y + y = 29
⇒ 43 - 29 = y
⇒ y = 14
From (i);
⇒ x + y = 29
⇒ x + 14 = 29
⇒ x = 29 - 14
⇒ x = 15
Thus, There are 15 children’s tickets were sold.
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If AD= 4, find CD and CB
Step by step pls
The value of the sides are;
CB = 13.8
CD = 6. 9
How to determine the valuesTo determine the value of the sides of the triangle, we need to know the different trigonometric identities are;
sinetangentcosinecotangentcosecantsecantFrom the information given, we have that;
Using the sine identity, we have that;
tan 60 = CD/4
cross multiply the values, we have;
CD = 4(1.73)
multiply the values
CD = 6.9
To determine the value;
sin 30 = 6.9/CB
CB = 13.8
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find 2 positive number with product 242 and such that the sum of one number and twice the second number is as small as possible.
The two positive numbers with a product of 242 and the smallest possible sum of one number and twice the second number are 11 and 22.
To find two positive numbers with a product of 242, we can start by finding the prime factorization of 242, which is 2 x 11 x 11. From this, we know that the two numbers we're looking for must be a combination of these factors.
To minimize the sum of one number and twice the second number, we need to choose the two factors that are closest in value. In this case, that would be 11 and 22 (twice 11). So the two positive numbers we're looking for are 11 and 22.
To check that these numbers have a product of 242, we can multiply them together: 11 x 22 = 242.
Now we need to check that the sum of 11 and twice 22 is smaller than the sum of any other combination of factors. The sum of 11 and twice 22 is 55. If we try any other combination of factors, the sum will be larger. For example, if we chose 2 and 121 (11 x 11), the sum would be 244.
Therefore, the two positive numbers with a product of 242 and the smallest possible sum of one number and twice the second number are 11 and 22.
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Two concentric circles form a target. The radii of the two circles measure 8 cm and 4 cm. The inner circle is the bullseye of the target. A point on the target is randomly selected.
What is the probability that the randomly selected point is in the bullseye?
Enter your answer as a simplified fraction in the boxes.
Answer:
1/4
Step-by-step explanation:
it came to me in a dream.
1/4 or 25% is the probability that the randomly selected point is in the bullseye.
What is probability?Probability is a number that expresses the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.
The area of the bullseye is the area of the inner circle with a radius of 4 cm. Similarly, the area of the entire target is the area of the outer circle with a radius of 8 cm.
The area of a circle is given by the formula A = πr², where A is the area and r is the radius.
Therefore, the area of the bullseye is:
A_bullseye = π(4 cm)² = 16π cm²
And the area of the entire target is:
A_target = π(8 cm)² = 64π cm²
So, the probability that the randomly selected point is in the bullseye is the ratio of the area of the bullseye to the area of the target:
P(bullseye) = A_bullseye / A_target
P(bullseye) = (16π cm²) / (64π cm²)
P(bullseye) = 1/4
Therefore, the probability that the randomly selected point is in the bullseye is 1/4 or 25%.
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SOMEONE HELPPPPPPPPPLLP
Answer: 2
Step-by-step explanation:
Priya’s cat is pregnant with a litter of 5 kittens. Each kitten has a 30% chance of being chocolate brown. Priya wants to know the probability that at least two of the kittens will be chocolate brown. To simulate this, Priya put 3 white cubes and 7 green cubes in a bag. For each trial, Priya pulled out and returned a cube 5 times. Priya conducted 12 trials. Here is a table with the results:
trial number outcome
1 ggggg
2 gggwg
3 wgwgw
4 gwggg
5 gggwg
6 wwggg
7 gwggg
8 ggwgw
9 wwwgg
10 ggggw
11 wggwg
12 gggwg
How many successful trials were there? Describe how you determined if a trial was a success.
Based on this simulation, estimate the probability that exactly two kittens will be chocolate brown.
Based on this simulation, estimate the probability that at least two kittens will be chocolate brown.
Write and answer another question Priya could answer using this simulation.
How could Priya increase the accuracy of the simulation?
The probability that at least two of the kittens will be chocolate brown is 0.3087.
We have,
Number of kittens = 5
Each kitten has a 30% chance of being chocolate brown.
So, p = 0.5 and q= 1-0.3 = 0.7
Now, P(X =2) = C( 5, 2) 0.3² (0.7)³
= 5! / 2!3! (0.09) (0.343)
= 10 x 0.03087
= 0.3087
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What’s the answer I need help asap?
The coordinate point (8, -15) is lies in fourth quadrant.
The given coordinate point is (8, -15).
Part A: Here, x-coordinate is positive that is 8 and the y-coordinate is negative that is -15.
Quadrant IV: The bottom right quadrant is the fourth quadrant, denoted as Quadrant IV. In this quadrant, the x-axis has positive numbers and the y-axis has negative numbers.
So, the point lies in IV quadrant.
Part B:
Here r²=x²+y²
r²=8²+(-15)²
r²=64+225
r²=289
r=√289
r=17 units
So, the radius is 17 units
Therefore, the coordinate point (8, -15) is lies in fourth quadrant.
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A high speed train travels a distance of 503 km in 3 hours.
The distance is measured correct to the nearest kilometre.
The time is measured correct to the nearest minute.
By considering bounds, work out the average speed, in km/minute, of the
train to a suitable degree of accuracy.
You must show your working.
To gain full marks you need to give a one-sentence reason for
your final answer - the words 'both' and 'round should be in your sentence.
Total marks: 5
The average speed of the train is both greater than or equal to 2.3928 km/minute and less than or equal to 3.3567 km/minute.
To find the average speed of the train, we divide the distance traveled by the time taken:
Average speed = distance / time
= 503 km / 180 minutes
= 2.7944... km/minute
Since the distance is measured correct to the nearest kilometer, the actual distance could be as low as 502.5 km or as high as 503.5 km. Similarly, since the time is measured correct to the nearest minute, the actual time taken could be as low as 2.5 hours or as high as 3.5 hours.
To find the maximum average speed, we assume that the distance traveled is 503.5 km and the time taken is 2.5 hours.
Maximum average speed = 503.5 km / 150 minutes = 3.3567... km/minute
To find the minimum average speed, we assume that the distance traveled is 502.5 km and the time taken is 3.5 hours.
Minimum average speed = 502.5 km / 210 minutes = 2.3928... km/minute
Therefore, the average speed of the train is both greater than or equal to 2.3928 km/minute and less than or equal to 3.3567 km/minute.
Rounding to two decimal places, the average speed of the train is 2.79 km/minute.
Reason: Both 2.79 km/minute and the minimum and maximum average speeds are correct to the nearest hundredth of a kilometer per minute and take into account the maximum possible error in the measurements.
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}); if
A student is studying the wave different elements are similar to one w
Atem
NUMPA
199
Atem a
dices
Atom 2
NQ
Alam 4
Which two atoms are of elements in the same group in the periodic table?
The two atoms are of elements in the same group in the periodic table include the following: D. Atom 1 and Atom 2.
What is a periodic table?In Chemistry, a periodic table can be defined as an organized tabular array of all the chemical elements that are typically arranged in order of increasing atomic number (number of protons), in rows.
What are valence electrons?In Chemistry, valence electrons can be defined as the number of electrons that are present in the outermost shell of an atom of a specific chemical element.
In this context, we can reasonably infer and logically deduce that both Atom 1 and Atom 2 represent chemical elements that are in the same group in the periodic table because they have the same valence electrons of six (6).
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Complete Question:
A student is studying the ways different elements are similar to one another. Diagrams of atoms from four different elements are shown below.
Which two atoms are of elements in the same group in the periodic table?
The word “element” is defined as
The word “element” is defined as the items in a set
Defining the word “element”From the question, we have the following parameters that can be used in our computation:
The word “element”
By definition, the word “element” is defined as the items in a set
Take for instance, we have
A = {1, 2, 3}
The set is set A and the elements are 1, 2 and 3
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he classical dichotomy is the separation of real and nominal variables. the following questions test your understanding of this distinction. taia divides all of her income between spending on digital movie rentals and americanos. in 2016, she earned an hourly wage of $28.00, the price of a digital movie rental was $7.00, and the price of a americano was $4.00. which of the following give the real value of a variable? check all that apply.
In the given scenario, the nominal variables are Taia's income, the price of a digital movie rental, and the price of an americano. The real variables would be Taia's income adjusted for inflation, the real price of a digital movie rental, and the real price of an americano.
To calculate the real value of a variable, we need to adjust it for inflation using a suitable price index. As the question does not provide any information about inflation, we cannot calculate the real value of any variable.
Therefore, none of the options given in the question would give the real value of a variable.
Hi! I'd be happy to help you with this question. In the context of the classical dichotomy, real variables are quantities or values that are adjusted for inflation, while nominal variables are unadjusted values.
In the given scenario, Taia spends her income on digital movie rentals and americanos. We have the following information for 2016:
1. Hourly wage: $28.00 (nominal variable)
2. Price of a digital movie rental: $7.00 (nominal variable)
3. Price of an americano: $4.00 (nominal variable)
To determine the real value of a variable, we need to adjust these nominal values for inflation. However, the question does not provide any information about the inflation rate or a base year for comparison. Thus, we cannot calculate the real values for these variables in this scenario.
In summary, we do not have enough information to determine the real value of any variable in this case. Please provide the inflation rate or base year if you'd like me to help you calculate the real values.
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Assume that adults have IQ scores that are normally distributed
with a mean of 97.6 and a standard deviation of 20.9. Find the
probability that a randomly selected adult has an IQ greater than
133.2.
The probability that a randomly selected adult has an IQ greater than 133.2 is 0.0436 or 4.36%.
To find the probability that a randomly selected adult has an IQ greater than 133.2, assuming adults have IQ scores that are normally distributed with a mean of 97.6 and a standard deviation of 20.9, follow these steps:
1. Calculate the z-score: z = (X - μ) / σ, where X is the IQ score, μ is the mean, and σ is the standard deviation.
z = (133.2 - 97.6) / 20.9
z ≈ 1.71
2. Use a z-table or a calculator to find the area to the left of the z-score, which represents the probability of having an IQ score lower than 133.2.
P(Z < 1.71) ≈ 0.9564
3. Since we want the probability of having an IQ greater than 133.2, subtract the area to the left of the z-score from 1.
P(Z > 1.71) = 1 - P(Z < 1.71) = 1 - 0.9564 = 0.0436
So, the probability that a randomly selected adult has an IQ greater than 133.2 is approximately 0.0436 or 4.36%.
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Find an equation of the tangent plane to the given surface at the specified point.z=2(x-1)^2 + 6(y+3)^2 +4, (3,-2,18)
The equation of the tangent plane to the given surface at the specified point (3, -2, 18) is z - 18 = 8(x - 3) - 12(y + 2).
To find the equation of the tangent plane to the given surface at the specified point (3,-2,18), we first need to find the partial derivatives of z with respect to x and y:
∂z/∂x = 4(x-1)
∂z/∂y = 12(y+3)
Then, we can evaluate these partial derivatives at the given point (3,-2,18):
∂z/∂x = 4(3-1) = 8
∂z/∂y = 12(-2+3) = -12
Next, we can use these partial derivatives and the point (3,-2,18) to write the equation of the tangent plane in point-normal form:
z - z0 = ∂z/∂x(x - x0) + ∂z/∂y(y - y0)
Plugging in the values we found:
z - 18 = 8(x - 3) - 12(y + 2)
Simplifying:
8x - 12y - z = -22
Therefore, the equation of the tangent plane to the given surface at the point (3,-2,18) is 8x - 12y - z = -22.
To find an equation of the tangent plane to the given surface z = 2(x - 1)^2 + 6(y + 3)^2 + 4 at the specified point (3, -2, 18), follow these steps:
1. Calculate the partial derivatives of the function with respect to x and y:
∂z/∂x = 4(x - 1)
∂z/∂y = 12(y + 3)
2. Evaluate the partial derivatives at the specified point (3, -2, 18):
∂z/∂x(3, -2) = 4(3 - 1) = 8
∂z/∂y(3, -2) = 12(-2 + 3) = -12
3. Use the tangent plane equation to find the tangent plane at the specified point:
z - z0 = ∂z/∂x(x - x0) + ∂z/∂y(y - y0)
where (x0, y0, z0) = (3, -2, 18)
4. Plug in the values and simplify the equation:
z - 18 = 8(x - 3) - 12(y + 2)
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Use technology or a z-score table to answer the question.
The expression P(z < 2.04) represents the area under the standard normal curve below the given value of z. What is the value of P(z < 2.04)
Step-by-step explanation:
Using z-score table the value is .9793 (97.93 %)
A researcher computes the computational formula for SS, as finds that ∑x = 22 and ∑x2 = 126. If this is a sample of 4 scores, then what would SS equal using the definitional formula?
4
5
104
If this is a sample of 4 scores, then By using the definitional formula, SS equals 5. Your answer: 5.
Using the definitional formula, SS can be calculated as:
SS = ∑(x - X)2
where X is the sample mean.
To find X, we can use the formula:
X = ∑x / n
where n is the sample size.
Given that ∑x = 22 and n = 4, we can calculate X as:
X = 22 / 4 = 5.5
Now, we'll plug these values into the formula:
SS = 126 - (22)² / 4
Calculate (∑x)² / n:
(22)² / 4 = 484 / 4 = 121
Now we can plug in the values into the formula for SS:
SS = ∑(x - X)2
= (1-5.5)2 + (2-5.5)2 + (3-5.5)2 + (4-5.5)2
= (-4.5)2 + (-3.5)2 + (-2.5)2 + (-1.5)2
= 20.5
Therefore, SS equals 20.5.
So, using the definitional formula, SS equals 5. Your answer: 5.
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Consider the polynomial function f(x) - x4 -3x3 + 3x2 whose domain is(-[infinity], [infinity]). (a) Find the intervals on which f is increasing. (Enter you answer as a comma-separated list of intervals. ) Find the intervals on which f is decreasing. (Enter you answer as a comma-separated list of intervals. ) (b) Find the open intervals on which f is concave up. (Enter you answer as a comma-separated list of intervals. ) Find the open intervals on which f is concave down. (Enter you answer as a comma-separated list of intervals. ) (c) Find the local extreme values of f. (If an answer does not exist, enter DNE. ) local minimum value local maximum value Find the global extreme values of f onthe closed-bounded interval [-1,2] global minimum value global maximum value (e) Find the points of inflection of f. Smaller x-value (x, f(x)) = larger x-value (x,f(x)) =
The answers are:
(a) f is decreasing on (-∞, 0) and increasing on (0, ∞).
(b) f is concave up on (-∞, ∞).
(c) Local minimum value at x = 0, local maximum value DNE.
(d) Global minimum value is -2 at x = -1, global maximum value is 22 at x = 2.
(e) There are no points of inflection.
(a) To find where the function is increasing or decreasing, we need to find the critical points and test the intervals between them:
[tex]f(x) = x^4 + 3x^3 + 3x^2\\f'(x) = 4x^3 + 9x^2 + 6x[/tex]
Setting f'(x) = 0, we get:
[tex]0 = 2x(2x^2 + 3x + 3)[/tex]
The quadratic factor has no real roots, so the only critical point is x = 0.
We can test the intervals (-∞, 0) and (0, ∞) to find where f is increasing or decreasing:
For x < 0, f'(x) is negative, so f is decreasing.
For x > 0, f'(x) is positive, so f is increasing.
Therefore, f is decreasing on (-∞, 0) and increasing on (0, ∞).
(b) To find where the function is concave up or concave down, we need to find the inflection points:
f''(x) =[tex]12x^2 + 18x + 6[/tex]
Setting f''(x) = 0, we get:
0 = [tex]6(x^2 + 3x + 1)[/tex]
The quadratic factor has no real roots, so there are no inflection points.
Since the second derivative is always positive, f is concave up everywhere.
(c) To find the local extreme values, we need to find the critical points and determine their nature:
f'(x) = [tex]4x^3 + 9x^2 + 6x[/tex]
At x = 0, f'(0) = 0 and f''(0) = 6, so this is a local minimum.
There are no local maximum values.
(d) To find the global extreme values on [-1, 2], we need to check the endpoints and the critical points:
f(-1) = -2, f(0) = 0, f(2) = 22
The global minimum value is -2 at x = -1, and the global maximum value is 22 at x = 2.
(e) To find the points of inflection, we need to find where the concavity changes:
Since there are no inflection points, there are no points of inflection.
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please help asap!!!!
Answer:
Step-by-step explanation:
1, 3 and 4
You are getting ready to retire and are currently making $79,000/year. According to financial experts quoted In the lesson, what is the minimum that you should have saved in retirement accounts if this is your salary? Show all your work
According to Financial experts you should save between 10% to 15% of your annual income for retirement. For a salary of $79,000/year, the minimum saved should be between $790,000 to $948,000.
Financial experts generally recommend that you should aim to save between 10% to 15% of your income each year for retirement. For a salary of $79,000 per year, this means saving between $7,900 to $11,850 annually.
Assuming you have been saving for retirement throughout your working years and are ready to retire, financial experts suggest that you should have saved at least 10 to 12 times your current annual income to maintain your pre-retirement standard of living. Therefore, the minimum you should have saved in retirement accounts is
$79,000 x 10 = $790,000 (using the conservative end of the range)
or
$79,000 x 12 = $948,000 (using the more aggressive end of the range)
Therefore, the minimum you should have saved in retirement accounts if you are currently making $79,000/year is between $790,000 to $948,000, depending on the end of the range you choose to follow.
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find the minimum sample size when we want to construct a 95% confidence interval on the population proportion for the support of candidate a in the following mayoral election. candidate a is facing two opposing candidates. in a preselected poll of 100 residents, 22 supported candidate b and 14 supported candidate c. the desired margin of error is 0.06.
The minimum sample size needed to construct a 95% confidence interval with a margin of error of 0.06 for the population proportion supporting candidate A is 268 residents.
To find the minimum sample size for a 95% confidence interval on the population proportion supporting candidate A, we'll need to use the following terms: sample size (n), population proportion (p), margin of error (E), and confidence level (z-score).
First, let's determine the proportion supporting candidate A from the preselected poll:
100 residents - 22 (supporting B) - 14 (supporting C) = 64 (supporting A)
So, the proportion p = 64/100 = 0.64.
For a 95% confidence interval, the z-score is 1.96 (found using a standard normal distribution table or calculator).
Now, we can use the formula for sample size calculation:
n = (z² × p × (1-p)) / E²
Substituting the values:
n = (1.96² × 0.64 × 0.36) / 0.06²
n ≈ 267.24
Since sample size must be a whole number, we round up to the nearest whole number, which is 268.
Therefore, the minimum sample size needed to construct a 95% confidence interval with a margin of error of 0.06 for the population proportion supporting candidate A is 268 residents.
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After deducting grants based on need, the average cost to attend the University of Southern California (USC) is $29,000. Assume
deviation is $8,500. Suppose that a random sample of 80 USC students will be taken from this population. Use z-table.
a. What is the value of the standard error of the mean?
(to nearest whole number)
b. What is the probability that the sample mean will be more than $29,000?
(to 2 decimals)
c. What is the probability that the sample mean will be within $500 of the population mean?
(to 4 decimals)
d. How would the probability in part (c) change if the sample size were increased to 120?
(to 4 decimals)
population standard
The probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.
To find the answers using the z-table, we need to calculate the standard error of the mean and then use it to determine the probability.
a. The standard error of the mean (SE) is calculated using the formula:
SE = σ / sqrt(n),
where σ is the standard deviation and n is the sample size.
Given that the standard deviation is $8,500 and the sample size is 80, we can calculate the standard error of the mean:
SE = 8,500 / sqrt(80) ≈ 950.77.
Rounding to the nearest whole number, the value of the standard error of the mean is 951.
b. To find the probability that the sample mean will be more than $29,000, we need to calculate the z-score and then look up the corresponding probability in the z-table.
The z-score is calculated using the formula:
z = (x - μ) / SE,
where x is the sample mean, μ is the population mean, and SE is the standard error of the mean.
In this case, x = $29,000, μ = population mean (unknown), and SE = 951.
Since the population mean is unknown, we assume that it is equal to the sample mean.
z = (29,000 - 29,000) / 951 = 0.
Looking up the probability in the z-table for a z-score of 0 (which corresponds to the mean), we find that the probability is 0.5000.
However, since we want the probability that the sample mean will be more than $29,000, we need to find the area to the right of the z-score. This is equal to 1 - 0.5000 = 0.5000.
Therefore, the probability that the sample mean will be more than $29,000 is 0.50 (or 50% when expressed as a percentage) to 2 decimal places.
To find the probability that the sample mean will be within $500 of the population mean, we need to calculate the z-scores for the upper and lower limits and then find the area between these z-scores using the z-table.
c. Let's assume the population mean is equal to the sample mean, which is $29,000. We want to find the probability that the sample mean falls within $500 of this value.
The upper limit is $29,000 + $500 = $29,500, and the lower limit is $29,000 - $500 = $28,500.
To calculate the z-scores for these limits, we use the formula:
z = (x - μ) / SE,
where x is the limit value, μ is the population mean, and SE is the standard error of the mean.
For the upper limit:
z_upper = ($29,500 - $29,000) / 951 ≈ 0.526
For the lower limit:
z_lower = ($28,500 - $29,000) / 951 ≈ -0.526
Now, we look up the probabilities associated with these z-scores in the z-table. The area between the z-scores represents the probability that the sample mean will be within $500 of the population mean.
Using the z-table, we find that the probability corresponding to z = 0.526 is approximately 0.6991, and the probability corresponding to z = -0.526 is approximately 0.3009.
The probability that the sample mean will be within $500 of the population mean is the difference between these two probabilities:
Probability = 0.6991 - 0.3009 ≈ 0.3982.
Therefore, the probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.
To determine how the probability would change if the sample size were increased to 120, we need the population standard deviation (σ). Unfortunately, the value of the population standard deviation was not provided.
The population standard deviation is a crucial parameter for calculating the standard error of the mean (SE) and determining the probability associated with the sample mean falling within a certain range around the population mean.
Without knowing the population standard deviation, we cannot calculate the new standard error of the mean or determine the exact change in the probability. The population standard deviation is necessary to estimate the precision of the sample mean and quantify the spread of the population values.
In general, as the sample size increases, the standard error of the mean decreases, resulting in a narrower distribution of sample means. This reduction in standard error typically leads to a higher probability of the sample mean falling within a specific range around the population mean.
To determine the specific change in the probability, we would need to know the population standard deviation (σ). Without that information, we cannot provide a precise answer to part (d) of the question.
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an online used car company sells second-hand cars. for 30 randomly selected transactions, the mean price is 2900 dollars. part a) assuming a population standard deviation transaction prices of 290 dollars, obtain a 99% confidence interval for the mean price of all transactions. please carry at least three decimal places in intermediate steps. give your final answer to the nearest two decimal places.
We can say with 99% confidence that the true mean price of all transactions is between $2,799.16 and $3,000.84.
To obtain a 99% confidence interval for the mean price of all transactions, we can use the formula:
CI = ± z*(σ/√n)
Where:
= sample mean price = 2900 dollars
σ = population standard deviation = 290 dollars
n = sample size = 30
z = z-score for a 99% confidence level = 2.576 (from the standard normal distribution table)
Substituting these values into the formula, we get:
CI = 2900 ± 2.576*(290/√30)
CI = 2900 ± 100.84
CI = (2799.16, 3000.84)
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Why a sample is always smaller than a population?
Answer:
A sample is a subset of the population.
For the month of February, Mr. Johnson budgeted $350 for groceries. He actually spent $427. 53 on groceries. What is the approximate percent error in Mr. Johnson’s budget?
Please could you explain this??? with an answer I really need it
The approximate percentage error is 22.1514%.
Formulate: (427.53−350)÷350
Calculate the sum or difference: 77.53/350
Multiply both the numerator and denominator with the same integer:
7753/35000
Rewrite a fraction as a decimal: 0.221514
Multiply a number to both the numerator and the denominator:
0.221514×100/100
Write as a single fraction: 0.221514×100/100
Calculate the product or quotient: 22.1514/100
Rewrite a fraction with denominator equals 100 to a percentage:
22.1514%
Percent error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage. In other words, the percent error is the relative error multiplied by 100.
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7. a) List three pairs of fractions that have a sum of 3\5.
The three pairs of fraction whose sum is 3/5 are
1/5 + 2/5-2/5+1-6/5+9/5We have to find pairs of fractions that have a sum of 3/5.
First pair:
1/5 + 2/5
= 3/5
Second pair:
= -2/5 + 1
= -2/5+ 5/5
= 3/5
Third pair:
= -6/5 + 9/5
= 3/5
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