Answer:
q2
Explanation:
Both the reactants are gases at STP.
Equation:
2H2S + 302 → 2SO2 + 2H2O
As per this equation 2 moles (2 x 22.4 L) of H2S
need 3 moles (3 x 22.4 L) of oxygen for their
complete oxidation.
So, volume of oxygen needed for 2.8 L of H2S =
(2.8 x 3 x 22.4)/(2 x 22.4) = 4.2 L (answer)
(a) H₂O(g) represents water in the gaseous state. It is produced as a product of the reaction between hydrogen sulfide (H₂S) and oxygen (O₂).
What is gaseous state?Gaseous state refers to a substance existing as a gas. When a substance is in the gaseous state, its particles are not closely packed together like in a solid or liquid state. Instead, they are spread out and move freely, filling the available space.
(b) To calculate the volume of oxygen required to react with 50 cm³ of hydrogen sulfide, we need to use the stoichiometry of the reaction. From the balanced equation, we can see that the molar ratio between hydrogen sulfide (H₂S) and oxygen (O₂) is 2:3.
Given: Volume of hydrogen sulfide (H₂S) = 50 cm³
Using the molar ratio, we can set up the following proportion: 2 mol H₂S / 3 mol O₂ = 50 cm³ H₂S / x cm³ O₂
To find the volume of oxygen, we can solve for x:
x = (50 cm³ H₂S * 3 mol O₂) / 2 mol H₂S
Now, we need to convert the obtained moles of oxygen to volume using the ideal gas law. Since the volume is given in cm³, we can assume that the temperature and pressure are constant at standard conditions (typically 0°C and 1 atm).
Using the ideal gas law equation: PV = nRT
Assuming constant temperature and pressure, we can rearrange the equation as: V = (n * R * T) / P
Substituting the values: V = (moles of O₂ * 22.4 L/mol) / (1 atm)
Calculate the moles of O₂ using the obtained value from the proportion.
Finally, convert the volume from liters to cm³ by multiplying by 1000.
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The hydrochloric acid utilized in this experiment can often discolor gloves if it is spilled on them during use. If this does occur, what should be done in order to remedy this potentially hazardous situation?.
Option B: Apply some sodium bicarbonate to the gloves to neutralize them in order to address this potentially dangerous condition with hydrochloric acid.
What is hydrochloric acid?Muriatic acid, another name for hydrochloric acid, is an aqueous solution of hydrogen chloride. It's a really dull response with a strong odor. It is currently classified as a powerful acid. It is a component of stomach acid in the digestive systems of the majority of animal species, including humans.
In the food, textile, metallurgical, and rubber industries, hydrogen chloride (HCl) is typically employed as a bleaching agent to neutralize alkaline marketers. It quickly hydrolyzes when exposed to water and is far neutralized when released into the soil.
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Which chemical symbol represents a compound?
The compound is represented by formula comprising symbols of elements.
An element is represented by chemical symbol like oxygen is O, hydrogen is H calcium is Ca and so on.
The compound is represented by the formula comprising symbols of elements. Compound is made up of two or more elements join together. some of the example are given below :
water - H₂O , made up of oxygen atom and hydrogen atom
Ammonia - NH₄
Calcium carbonate - CaCO₃
Carbon dioxide - CO₂
Acetic acid - CH₃COOH
these are the some example of compound , formula of compound comprises the chemical symbol of elements.
Thus, The compound is represented by formula comprising symbols of elements.
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What protects the earth from the sun's rays
Answer
The Ozone Layer
Explanation
Higher up, in the stratosphere, the ozone layer absorbs solar ultra-violet radiation and affects how much of the Sun's heat is radiated back into space. The ozone layer shields us from the harmful effects of excessive UV radiation, which can lead to sunburn, skin cancer and eye damage.
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Using the table of average bond energies, determine the total bond energy for the reactants in the combustion of ethene: C2H4 + 3 O2 --> 2 CO2 + 2 H2O
Explanation:
Hydrogen bonds with carbon 4 times, carbon bonds with itself once, and oxygen bonds with itself 3 times.
Energy of reactants:
E = 4 * 413 + 347 + 3 * 495
= 3484kJ/mol
Answer:
Energy transferred in = 3484kJ/mol
7.110 Gasohol is a fuel containing liquid ethanol (C₂H₂O) thatburns in oxygen gas to give carbon dioxide and water gases.(7.4, 7.7,7.8)a. Write the balanced chemical equation.b. How many moles of O₂ are needed to completely react with 4.0 moles of C₂H₂O?c. If a car produces 88 g of CO2, how many grams of O₂ are used up in the reaction?d. If you burn 125 g of C₂H₂O, how many grams of CO₂ and H₂O can be produced?
Answer
a. C₂H₂O + 2O₂ → 2CO₂ + H₂O
b. 8 moles of O₂
c. 64 g of O₂
d. The grams of CO₂ produced is 262 g and the mass of H₂O produced is 53.6 g.
Explanation
a. The balanced chemical equation gasohol is a fuel containing liquid ethanol (C₂H₂O) that burns in oxygen gas to give carbon dioxide and water gases is:
[tex]C_2H_2O+2O_2\rightarrow2CO_2+H_2O[/tex]b. The moles of O₂ needed to completely react with 4.0 moles of C₂H₂O?.
The mole ratio of O₂ to C₂H₂O in the balanced equation is 2:1.
Therefore, 4.0 moles of C₂H₂O will completely react with (2 x 4) = 8 moles of O₂.
c. The mass in grams of O₂ that is used up in the reaction if a car produces 88 g of CO₂.
The molar mass of CO₂ = 44.01 g/mol
The molar mass of O₂ = 31.999 g/mol
The mole ratio of O₂ to CO₂ is 2:2
This implies (2 mol x 31.999 g/mol) = 63.998 g of O₂ is used up to produce (2 mol x 44.01 g/mol) = 88.02 g of CO₂
Therefore x g of O₂ will be used up to produce 88 g of CO₂
That is;
[tex]\begin{gathered} 63.998g\text{ }O₂=88.02g\text{ }CO₂ \\ \\ x=88g\text{ }CO₂ \\ \\ Cross\text{ }multiply\text{ }and\text{ }divide\text{ }both\text{ }sides\text{ }by\text{ }88.02g\text{ }CO₂ \\ \\ x=\frac{88g\text{ }CO₂}{88.02\text{ }CO₂}\times63.998g\text{ }O₂ \\ \\ x=63.9835grams \\ \\ x\approx64\text{ }g \end{gathered}[/tex]Hence, the mass in grams of O₂ that is used up in the reaction if a car produces 88 g of CO₂ is 64 g.
d. The grams of CO₂ and H₂O that can be produced if 125 g of C₂H₂O were burnt.
1 mole of C₂H₂O = 42.04 g
1 mole of CO₂ = 44.01 g
1 mole of H₂O = 18.01 g
Mass of CO₂ produced:
From the balanced, the mole ratio of C₂H₂O to CO₂ is 1:2
[tex]\begin{gathered} 42.02g\text{ }C₂H₂O=2\times44.01g\text{ }CO₂ \\ \\ 125g\text{ }C₂H₂O=x \\ \\ x=\frac{125g\text{ }C₂H₂O}{42.02g\text{ }C₂H₂O}\times88.02g\text{ }CO₂ \\ \\ x\approx262g\text{ }CO₂ \end{gathered}[/tex]The grams of CO₂ produced is 262 g.
Mass of H₂O produced:
From the balanced, the mole ratio of C₂H₂O to H₂O is 1:1
[tex]\begin{gathered} 42.02g\text{ }C₂H₂O=18.01g\text{ }H₂O \\ \\ 125g\text{ }C₂H₂O=x \\ \\ x=\frac{125g\text{ }C₂H₂O}{42.02g\text{ }C₂H₂O}\times18.01g\text{ }H₂O \\ \\ x\approx53.6grams \end{gathered}[/tex]The mass of H₂O produced is 53.6 g
when aluminum, al , metal is dipped in an aqueous solution of hydrochloric acid, hcl , hydrogen gas, h2 , is produced with the formation of an aluminum chloride, alcl3 , solution. write the balanced chemical equation showing the phases of reactants and products. express your answer as a chemical equation including phases.
The balanced reaction equation for this transformation looks like this:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
In order to write the balanced reaction equation for this redox reaction, we must first write what we know. Aluminum metal is solid (Al(s)), and it is reacting with aqueous hydrochloric acid (HCl(aq)). When elemental metals react with acids, this results in the formation of appropriate salts (in this case aluminum chloride, that will be dissolved in water, so AlCl₃(aq)) and elemental gaseous hydrogen (H₂(g)):
Al(s) + HCl(aq) → AlCl₃(aq) + H₂(g)
This reaction equation isn't balanced because we have different numbers of atoms for every element on the left and the right side (except for Al). The easiest way to begin balancing is to notice that chlorine atoms will be balanced if we add 3 in front of HCl:
Al(s) + 3HCl(aq) → AlCl₃(aq) + H₂(g)
However, we can see now that 3HCl cannot possibly produce the H₂ molecule. The smallest common multiple of 3 and 2 is 6, so we should have 6 hydrogen atoms on each side:
Al(s) + 6HCl(aq) → AlCl₃(aq) + 3H₂(g)
To balance the chlorine atoms we add 2 in front of AlCl₃, and then 2 in front of Al to balance aluminum, arriving at the balanced reaction equation:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
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Colin is helping the librarian return books to the shelves where they belong. He picks up books from the librarian’s desk, as shown in Figure A. He then carries them to the shelves, as shown in Figure B.
Two illustrations with the left one showing a boy lifting books up that have been sitting on a desk, and the second one showing a boy carrying books toward a bookcase on the right.
Explain why Figures A and B do or do not show work being done. Then, provide two examples (not including lifting or carrying) of how work could be done on the books.
]
The explanation of Figures A and B to do or do not show work being done is given below:
He is using energy to lift the books in picture A, which takes both force and motion to do so. In figure B, the books move along with him, and as such only effort is used to carry them. Hence, he is doing work only in Figure A.
The examples are:
A student pushing a book cart in a shopping mall.A girl lifting a bag on her back or her shoulder that is also filled with books.What is the definition of the term work done?The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force. Work is accomplished when we push a block with some force; the body moves more quickly.
Work completed is noted as an object must be subjected to a force and move in the direction of the force in order for work to be done on it.
Therefore, It should be converted to energy in order to move an object. Energy can be transferred by the use of force. This amount of energy that is delivered when a force is used to move an object is known as work that is done.
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57. For the reaction shown, calculate the theoretical yield ofthe product in grams for each of the initial quantities ofreactants.2 Al(s) + 3 Cl₂(g) 2 AlCl3(s)(a) 1.0 g Al; 1.0 g Cl₂(b) 5.5 g Al; 19.8 g Cl₂(c) 0.439 g Al; 2.29 g Cl₂
In this question, we have to calculate the theoretical yield of AlCl3, based on the following reaction:
2 Al + 3 Cl2 -> 2 AlCl3
In this reaction, we have the following molar ratios:
2 Al = 3 Cl2
2 Al = 2 AlCl3
3 Cl2 = 2 AlCl3
We have as the initial mass of the reactants:
1.0 grams of Al and 1.0 grams of Cl2
We need to find the limiting and excess reactants before the theoretical yield, and in order to find the limiting and excess reactants, we need to calculate the number of moles we have in 1.0 grams of each
Starting with Al, the molar mass of Al is = 27g/mol
27g = 1 mol of Al
1.0g = x moles of Al
27x = 1
x = 0.37 moles of Al in 1 gram of Al
According to the molar ratio between Al and Cl2, 2 moles of Al = 3 moles of Cl2, what if we have 0.37 moles of Al:
2 Al = 3 Cl2
0.37 Al = x Cl2
2x = 1.11
x = 1.11/2
x = 0.55 moles of Cl2 will be needed to react with 0.37 moles of Al
The molar mass of Cl2 is 70.9g/mol:
70.9g = 1 mol of Cl2
1.0g = x moles
70.9x = 1
x = 1/70.9
x = 0.014 moles
We have 0.014 moles of Cl2 in this reaction, and we needed 0.55 moles of Cl2, which means that Cl2 is the limiting reactant and Al is in excess
Using the number of moles of the limiting reactant, 0.014 moles, we will find the final mass of the product
First we need to know how many moles of AlCl3 we have, based on the molar mass between Cl2 and AlCl3, 3:2
3 Cl2 = 2 AlCl3
0.014 Cl2 = x AlCl3
3x = 0.028
x = 0.028/3
x = 0.009 moles of AlCl3
Now we have the number of moles of AlCl3, the molar mass is = 133.34g/mol
133.34g = 1 mol
x grams = 0.009 moles of AlCl3
x = 0.009 * 133.34
x = 1.20 grams of AlCl3
The theoretical yield of AlCl3 for 1.0 gram of Al and 1.0 gram of Cl2 will be 1.20 grams
which of the following will be the strongest oxidizing agent (weakest reducing agent)? a) chromium (0) b) chromium (ii) c) chromium (iii) d) chromium (iv) e) chromium (vi)
The strongest oxidizing agent is chromium (vi); option E.
What are oxidizing agents?Oxidizing agents are compounds that readily accept electrons and are reduced.
Oxidizing agents will oxidize other substances, resulting in an increase in the oxidation state of the compounds. However, they are themselves reduced as their oxidation states are reduced when they accept electrons.
Strong oxidizing agents are weak reducing agents.
Reducing agents readily give up electrons to other compounds, and hence are oxidized.
Transition elements are known for their variable oxidation states due to their ability to lose different numbers of electrons.
The higher the oxidation state of a transition element in a compound, the more oxidizing the compound will be.
Hence, a compound of a transition element in the highest oxidation state will be the most oxidizing.
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how many moles of permanganate were used? [2] 4. how many moles of iron were required to react with the permanganate? [1] 5. what is the mass of iron present in the initial sample? [1] 6. what is the mass percent of iron in the unknown iron sample? [2] 7. a student performed the experiment and got a higher mass percent than expected. other than human error or machine malfunctions, briefly explain a source of error from the experiment.
According to the balanced chemical equation, 2 moles of potassium permanganate produces 5 moles or oxidizes 5 moles of sulphite to sulphate ions. As a result, there are 0.639 moles of potassium.
In alkaline solution, KMnO4 reduces to green K₂MnO₄: 4 KMnO₄ + 4 KOH 4 K₂MnO₄ + O₂ + 2 H₂O. This reaction exemplifies hydroxide's uncommon role as a reducing agent. Mn₂O₇ is formed when concentrated sulfuric acid is added to potassium permanganate. One mole of KMnO₄ requires 5 moles of electrons in an acidic medium. Multiply equation (1) by 5 and equation (2) by 3 to balance the number of electrons. In an acidic medium, five moles of ferrous oxalate are oxidized by three moles of KMnO₄.
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.
One molecule of silver atoms contains the same number of items found in one mole of calcium atoms. TrueFalse
When they talk about items found, they refer to molecules. According to Avogadro, one mole of any substance, regardless of its type, contains the same amount of molecules equal to 6.022x10^23.
Now they tell us about a molecule of silver and a mole of calcium. In one mole of calcium, there will be 6.023x10^23 molecules, which is different from one molecule of silver, so the answer will be false
while performing a neutralization reaction, jonna added 23.61 ml of 0.120 m h2so4 to 48.16 ml of 0.309 m koh. what concentration of oh-, in m, that is unreacted in the solution after the neutralization is complete?
0.00925 moles OR 9.25103 moles of OH remain unreacted in the solution after the neutralization process is finished.
What are neutralization reactions?In a neutralization reaction, an acid and a base mix chemically to yield salt and water as the final products. During a neutralization process, H+ and OH- ions interact to produce water.
The balanced chemical equation is
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
Now determine the number of moles
For H₂SO₄
Volume = 23.61 mL = 0.02361L
Concentration = 0.120M
From the formula,
Number of moles = Concentration × Volume
∴ Number of moles of H₂SO₄ = 0.120 × 0.02361
Number of moles of H₂SO₄ = 0.0028332 moles
For KOH
Volume =mL = 48.16ml = 0.04816 L
Concentration = 0.309 M
∴ Number of moles of KOH = 0.309 × 0.04816
Number of moles of KOH = 0.01488144 moles
From the equation of reaction,
0.0028332 moles of H₂SO₄ will neutralize 2× 0.0028332moles KOH
2× 0.0028332 = 0.0056664 moles
This means only 0.0056664 moles of KOH reacted
The amount of unreacted OH moles will now be discussed.
Number of unreacted OH moles equals the total number of OH moles at the start of the reaction. Quantity of OH that reacted in moles
∴ Number of moles of unreacted OH⁻ = 0.01488144 moles - 0.0056664 moles
Number of moles of unreacted OH⁻ ≅ 0.00925 moles OR 9.25×10⁻³ moles
Hence, the number of moles of OH⁻ that are unreacted in the solution after the neutralization is complete is 0.00925 moles OR moles 9.25×10⁻³.
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How many atoms are in 3Mg(OH)2?
Answer:
15
Explanation:
Number of atoms of Mg = 3
Number of atoms of O = 3 × 2 = 6
Number of atoms of H = 3 × 2 = 6
So, total atoms = 3 + 6 + 6 = 15
when one mole of caffeine(c8h10n4o2)is burned in air 4960 kj of heat is released. 5.00g of caffeine is burned in a bomb calorimeter. the temperature is observed to increase by 11.37oc. what is the heat capacity of the calorimeter in kj/oc?
Answer:
Explanation:It is given that burning one mole of caffeine gives heat.
The given mass of caffeine is 5g.
Molar mass of caffeine can be calculated as shown below.
Calculate the number of moles of caffeine burned as follows:
Q = mc ΔT
0.0258 ×4.96 × 103 × 284.37
= 3.64 × 104J/°C
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The pressure of 6.0 L of an ideal gas in a flexible container is decreased to one third of its original pressure and its absolute temperature is decreased by one half. What is the final volume of the gas?
The final volume of the gas is 9L
Volume is the space occupied within the boundaries of an object in three dimensional space
P, V and T is the initial pressure volume and temperature of the ideal gas respectivelyX be the final volume of ideal gasIdeal gas equation establishes a relation between pressures, volumes, and temperatures of different conditions
Using the ideal gas equation
PV = nRT .....1
Ideal gas equation for initial condition will be:
PV = nRT......2
Ideal-Gas Equation for final conditions will be:
(P/3)X = nR(T/2)
On dividing equation 1 and 2
PV = nRT / (P/3)X = nR(T/2)
3V/X = 2
X = 3V/2
Putting the value of V = 6L
X = 3(6L)/2 = 9L
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what is the volume in liters of 3.75 moles of o2 gas
The volume of 3.75 moles of oxygen gas at STP is 84.05L.
How to calculate volume?The volume of a gas can be calculated using the ideal gas law equation as follows:
PV = nRT
Where;
P = pressureV = volumen = number of molesR = gas law constantT = temperatureAt standard temperature and pressure (STP), the temperature and pressure of an ideal gas is 273K and 1 atm respectively.
1 × V = 3.75 × 0.0821 × 273
V = 84.05L
Therefore, 84.05L is the volume of the ideal oxygen gas.
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Metals will always form _________________ ions, called _______________.
Answer: 1. Positive ions
2. They're called Cations
explanation: Cations are positive ions and anions are negative ions. Metals always form positive ions as they lose electrons to be like the Nobel gases - with full outer shells.
Select the correct answer. what is the chemical formula of magnesium bromide? a. mgbr2 b. mgbr c. mg2br2 d. mg2br
The correct chemical formula of magnesium bromide is MgBr₂.
Ionic bonds are formed by transfer of electrons between metal and non metals.
Electronic configuration of magnesium:
[Mg] :12 : 1s², 2s², 2p⁶, 3s²
Magnesium atom will lose two electron to gain noble gas configuration and form magnesium cation with +2 charge.
[Mg²⁺] : 1s², 2s², 2p⁶
Electronic configuration of bromine:
[Br] : 35 : 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵
Bromine atom will gain one electron to gain noble gas configuration and form bromide ion with -1 charge.
[Br⁻] : 36 : 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶
In magnesium bromide, two electrons from metal gets transferred to bromine atom and thus form an ionic bond to give MgBr₂.
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When acetyl-coa containing radioactively labeled carbon atoms is fed to cells, the co2 produced is not initially radioactive. However, molecules of citrate and oxaloacetate are radioactive. Only after some time has passed will radioactive co2 be released. What is the best explanation for this observation?.
Acetyl-co A containing radioactively labeled carbon atoms when fed to cells produce Co2 which are not radioactive but molecules of citrate and oxalo acetate are radioactive because citrate and oxalo acetate are part of the Krebs Cycle, which is responsible for generating energy in cells.
The Krebs Cycle involves a series of reactions in which acetyl-co A is broken down to generate energy. The carbon atoms in acetyl-co A are gradually transferred to other molecules in the cycle, including citrate and oxalo acetate. As the carbon atoms are transferred, they become radioactive. Eventually, the carbon atoms are transferred to Co2, which is then released from the cells.
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a 9.791 gram sample of an organic compound containing , and is analyzed by combustion analysis and 14.35 grams of and 5.876 grams of are produced. in a separate experiment, the molar mass is found to be 60.05 g/mol. determine the empirical formula and the molecular formula of the organic compound.
The empirical formula of the compound is CH₂O, and the molecular formula of the compound is C₂H₄O₂.
All of the carbon in the compound is converted into carbon dioxide (14.35 g) and all the hydrogen in the compound is converted to water (5.876 g). This means that we can use these masses to find the masses of carbon, hydrogen, and oxygen in the original compound.
First, we calculate the mass of carbon in carbon dioxide and the mass of hydrogen in water, using their respective molar masses (M(CO₂) = 44 g/mol; M(H₂O) = 18 g/mol):
12 g of carbon : 44 g of carbon dioxide = X : 14.35 g of carbon dioxide
X = 12 g of carbon * 14.35 g of carbon dioxide / 44 g of carbon dioxide
X = 3.914 g of carbon
2 g of hydrogen : 18 g of water = X : 5.876 g of water
X = 2 g of hydrogen : 5.876 g of water / 18 g of water
X = 0.6529 g of hydrogen
Because the compound contains carbon, hydrogen and oxygen, we can now calculate the mass of oxygen in the compound:
m(O) = m(sample) - m(C) - m(H)
m(O) = 9.791 g - 3.914 g - 0.6529 g
m(O) = 5.224 g
Now we use these masses to calculate the number of moles (n) for each of the elements, using their respective molar masses (M(C) = 12 g/mol, M(H) = 1 g/mol, M(O) = 16 g/mol):
n = m/M
n(C) = m(C) / M(C)
n(C) = 3.914 g / 12 g/mol
n(C) = 0.3284 mol
n(H) = m(H) / M(H)
n(H) = 0.6529 g / 1 g/mol
n(H) = 0.6529 mol
n(O) = m(O) / M(O)
n(O) = 5.224 g / 16 g/mol
n(O) = 0.3265 mol
We divide each of these amounts by the smallest of them (0.3265 mol) to obtain the molar ratio of the elements:
carbon: 0.3284 mol / 0.3265 mol = 1.006
hydrogen: 0.6529 mol / 0.3265 mol = 2.000
oxygen: 0.3265 mol / 0.3265 mol = 1.000
These integers are indexes in the empirical formula of the compound - CH₂O
The molar mass of this empirical formula is:
12 g/mol + 2 * 1 g/mol + 16 g/mol = 30 g/mol
We divide the molar mass of the compound by the molar mass of the empirical formula:
60.05 g/mol / 30 g/mol = 2.002
So, we multiply the indexes by 2 to obtain the molecular formula - C₂H₄O₂
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a stock solution of silver nitrate (agno3) is prepared by adding 97.364 g of silver nitrate to a 1000.00 ml volumetric flask and it is filled to the line with water. a 79.763 ml aliquote of the stock solution is added to a 200.00 ml volumetric flask and it is filled to the line with water. what is the molarity of the solution in the 200.00 ml flask?
The molarity of the silver nitrate solution in the 200.00 mL flask is 0.22856 M.
To calculate the molarity of the solution in the 200.00 mL flask, we must need the number of moles present and the volume (200.00 mL = 0.20000 L).
To obtain the number of moles present, we can calculate the mass of AgNO₃ in the 200.00 mL sample and then use the molar mass of silver nitrate (M = 169.87 g/mol) to calculate the number of moles.
So, if there's 97.364 g of silver nitrate in the 1000.00 mL flask, we can use a simple proportion to calculate the mass present in 79.763 mL:
97.364 g : 1000.00 mL = X : 79.763 mL
X = 97.364 g * 79.763 mL / 1000.00 mL = 7.7660 g
This same mass is present in the final 200.00 mL solution, as it is merely diluted. So, we can now calculate the number of moles (n) of silver nitrate:
n = m/M
n = 7.7660 g / 169.86 g/mol
n = 0.045712 mol
Finally, we can use this to calculate the molarity (c) of the final solution:
c = n/V
c = 0.045712 mol / 0.20000 L = 0.22856 M
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how do chandeliers use energy
Answer:
as they use multiple bulbs in conjunction chandeliers don't need higher watt bulbs and are usually not used as often as other lights
Explanation:
hope this helps
New crust is found at the center of the _____, proving the movement of the seafloor and the surface of the Earth.
A. ocean
B. Himalayan Mountains
C. Earth
D. mid-ocean ridge
Answer: The newest, thinnest crust on Earth is located near the center of mid-ocean ridge—the actual site of seafloor spreading
Answer:
D. mid-ocean ridge
Explanation:
how does the atmospheric pressure change as you move from places of high elevation to low elevation?
On moving from places of high elevation to a place of low elevation, the atmospheric pressure increases as the amount of air over unit area increases.
What is pressure?Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.
There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .
It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.
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When zinc is immersed in hydrocholoric acid
Answer:
Zinc is more reactive than lead, iron and silver so, zinc reacts with hydrochloric acid to form Zn2+ ions.
Answer:
zn2+
Explanation:
the reason for this answer is that when hydrochloric acid and zinc come together they react to form a stronger ion
The Conduction and Convection Gizmo shows two flasks of colored water, one blue and one yellow. Select Copper and Solid chunk from the dropdown lists. (This means the two flasks are separated by a solid piece of copper, and the two liquids cannot touch each other.)
Use the sliders to make What happens?
The Conduction and Convection Gizmo shows two flasks of colored water, one blue and one yellow. Select Copper and Solid chunk from the dropdown lists his means the two flasks are separated by a solid piece of copper, and the two liquids cannot touch each other then temprature tries to become the even/leveled
Conduction is the process to transfer heat from one substances to another by direct contact and convention means a rise and sink due to temprature and density differences this is called convention and when two flasks are separated by a solid piece of copper, and the two liquids cannot touch each other then to use the sliders to make one flask hotter than other and the temprature tries to become the even/leveled
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a compound is analyzed and found to contain 12.1% carbon, 16.2% oxygen, and 71.7% chlorine (by mass). calculate the empirical formula of this compound.
Answer:
COCl2 Phosgene
Explanation:
Which sentence most accurately describes the daily growth rate of plants? (1 point)
Answer: D- average change in plant height, divided by, the number of days.
(i had to look up the test you were talking about to find what the answer choices were.)
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you add 13.90 ml of 0.370 m ba(oh)2(aq) to 45.00 ml of 0.300 m hydrochloric acid, hcl(aq). if necessary use ka and kb values from the equation sheet provided chem iii eqn sheet a. enter the formula of the chemical species predominantly present in solution that will determine the ph. formula h3o preview: h3o (aq) b. what is the ph? 0.848
The predominant chemical species affecting the pH is H₃O⁺, but the pH value of the resulting solution is actually 1.26.
To calculate the pH value of the resulting solution we need the number of moles of H⁺ ions (n) and the volume of the solution (V). The volume is easy - it is the sum of the volumes of the barium hydroxide solution (13.90 mL = 0.01390 L) and the hydrochloric acid solution (45.00 mL = 0.04500 L)
V(total) = V(Ba(OH)₂) + V(HCl)
V(total) = 0.01390 L + 0.04500 L = 0.05890 L
Now we need to calculate the number of moles of H⁺ (H₃O⁺) ions. The number of moles of H⁺ ions in the HCl solution is:
n(H⁺) = c(HCl) * V(HCl)
n(H⁺) = 0.300 M * 0.04500 L = 0.0135 mol
On the other hand, the number of moles of OH⁻ ions is double the number of moles of barium hydroxide, because 1 mol of barium hydroxide releases 2 moles of OH⁻ ions:
n(OH⁻) = 2 * c(Ba(OH)₂) * V(Ba(OH)₂)
n(OH⁻) = 2 * 0.370 M * 0.01390 L = 0.010286 mol
The number of moles of H⁺ ions is greater than the number of moles of OH⁻ ions, so after the neutralization, we will have an excess of H⁺ ions:
n(H₃O⁺) = n(H⁺) - n(OH⁻)
n(H₃O⁺) = 0.0135 mol - 0.010286 mol = 0.003214 mol
We can now finally calculate the concentration of H₃O⁺ ions in the final solution:
c(H₃O⁺) = n(H₃O⁺) / V(total)
c(H₃O⁺) = 0.003214 mol / 0.05890 L = 0.05457 M
From this, we can find the pH value of the solution:
pH = -log(c(H₃O⁺))
pH = -log(0.05457)
pH = 1.26
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in a beaker, 0.57 mol of potassium iodide and 0.52 mol of lead (ii) nitrate are dissolved in water. a reaction occurs, and a white precipitate is observed. calculate the mass (in grams) of the precipitate formed
The white precipitate formed is lead iodide (PbI₂) of mass 131.38g
What is a precipitate reaction?The term "precipitation reaction" may be described as "a chemical response taking place in aqueous solution wherein ionic bonds integrate to shape an insoluble salt". These insoluble salts fashioned in the course of precipitation reactions are referred to as precipitates. Precipitation reactions are normally double displacement reactions with the formation of stable residues referred to as precipitates.
One of the first-class examples of precipitation reactions is the chemical response among potassium chloride and silver nitrate, which precipitates stable silver chloride. This is an insoluble salt fashioned as a made from precipitation reactions. The chemical components for this precipitation response is proven below.
AgNO3(aqueous) + KCl(aqueous) —–AgCl(precipitate) + KNO3(aqueous)
For the given case,
The balanced reaction is as follows:
Pb(NO₃)₂ (aq) + 2KI (aq) → 2KNO₃ (aq) + PbI₂ (s)
This tells us that for every mole of lead iodide (PbI₂) produced, it requires 2 moles of potassium iodide (KI).
If you have 0.57 mole of KI, they will produce: 0.57/2 = 0.285 mol of PbI₂
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
mass of lead iodide (PbI₂) = Number of moles × molar mass
Mass of lead iodide = 0.285 × 461.01
Mass of lead iodide = 131.38g
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