We have to calculate the value of the expression:
[tex]\frac{q}{4+8q}[/tex]when q = 8.
To calculate this, we replace q with its value and solve as:
[tex]\frac{q}{4+8q}=\frac{8}{4+8\cdot8}=\frac{8}{4+64}=\frac{8}{68}=\frac{2}{17}[/tex]Answer: 2/17
t, Decimal, Fractions a. 100 is what percent of 80? = 125% b. What is 1/20 as a decimal? What is that decimal as a percent? –5%
Explanation
Step 1
a) 100 is what percent of 80?
you can solve this by using a rule of three
Let
x represents the percent
then
[tex]undefined[/tex]Jane invested her savings in two investment funds. The $2000 that she invested in Fund A returned a 3% profit. The amount that she invested in Fund B returned a 10% profit. How much did she invest in fund B, if both funds together returned a 8% profit?
Fund A, Jane invested $2000 and has a profit of 3%
Profit at Fund A is :
[tex]\$2000\times0.03=\$60[/tex]at Fund B, let $x be the amount she invested that gives her a profit of 10%
The profit at Fund B is :
[tex]\$x\times0.10=\$0.10x[/tex]It is said that the total amount she invested returned a 8% profit
The total amount she invested is :
[tex]\$2000+\$x[/tex]and the 8% profit of her total investment is :
[tex](2000+x)\times0.08=160+0.08x[/tex]Now we need to equate the sum of her profits from Fund A and Fund B, and this must be equal to the 8% profit.
3% Profit at Fund A = $60
10% Profit at Fund B = $0.10x
8% Profit at both funds together = 160 + 0.08x
[tex]\begin{gathered} 60+0.10x=160+0.08x \\ 0.10x-0.08x=160-60 \\ 0.02x=100 \\ x=\frac{100}{0.02}=5000 \end{gathered}[/tex]Therefore, the amount she invested in Fund B is $5000
What are the x- and y-intercepts of a line with slope 2 passing through the point (1, 8)?
The x- and y-intercepts of a line with slope 2 passing through the point (1, 8) is x-intercept=(3,0) and y-intercept=(0,6) as defined "The slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b)."
What is slope intercept?The slope intercept form in math is one of the forms used to calculate the equation of a straight line, given the slope of the line and intercept it forms with the y-axis. The slope intercept form is given as, y = mx + b, where 'm' is the slope of the straight line and 'b' is the y-intercept.
Here,
Let (x1, y1) = (1, 8) and m = 2.
Then, y - y1 = m(x - x1)
y - (8) = 2(x -1)
y-8= 2(x-1)
y -8 = 2x -2
y = 2x + 6
y=(0,6)
x=(3,0)
According to the definition "The slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b)," the x- and y-intercepts of a line with slope 2 passing through the point (1, 8) are x-intercept=(3,0) and y-intercept=(0,6).
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The volume of a rectangular prism is 2 x cubed + 9 x squared minus 8 x minus 36 with height x + 2. Using synthetic division, what is the area of the base?
The base area of the prism is 2x² + 5x - 18
How to determine the area of the base?From the question, the given parameters are
Volume = 2 x cubed + 9 x squared minus 8 x minus 36
Height = x + 2
Rewrite properly as
Volume = 2x³ + 9x² - 8x - 36
Height = x + 2
The base area is calculated as
Base area = Volume/Height
Using the synthetic division, we have
Set the divisor to 0
x + 2 = 0
This gives
x = -2
So, we have the representation to be
-2 | 2 9 - 8 - 36
Write out 2
So, we have
-2 | 2 9 - 8 - 36
2
Multiply 2 and -2
This gives
-2 | 2 9 - 8 - 36
-4
2
So, we have
-2 | 2 9 - 8 - 36
-4
2 5
Repeat the process
So, we have
-2 | 2 9 - 8 - 36
-4 -10
2 5 -18
Repeat the process
So, we have
-2 | 2 9 - 8 - 36
-4 -10 36
2 5 -18 0
This means that
Base area = 2x² + 5x - 18
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raymond bought 5 rolls of toilet paper towels he got 99 4/3 inches of paper towels in all. how many meters of paper towels were on each roll? please help my grades go in tomorrow and i have a lot today that i dont know how and if i dont make a passing grade on my report card i have to quit band
The length of 5 rolls of toilet papers is 99 4/3
So, the length of one roll will be = 99 4/3 ÷ 5 = 20 1/15 inches
Find the center, vertices, foci, endpoints of the latera recta and equations of the directrices. Then sketch the graph of the ellipse.
The given equation of ellipse is,
[tex]\frac{(x-2)^2}{16}+\frac{y^2}{4}=1\text{ ---(1)}[/tex]The above equation can be rewritten as,
[tex]\frac{(x-2)^2}{4^2}+\frac{y^2}{2^2}=1\text{ ----(2)}[/tex]The above equation is similar to the standard form of the ellipse with center (h, k) and major axis parallel to x axis given by,
[tex]\frac{(x-h)^2}{a^2}+\frac{y^2}{b^2}=1\text{ ----(3)}[/tex]where a>b.
Comparing equations (2) and (3), h=2, k=0, a=4 and b= 2.
Hence, the center of the ellipse is (h, k)=(2, 0).
The coordinates of the vertices are given by,
[tex]\begin{gathered} (h+a,\text{ k)=(2+}4,\text{ }0)=(6,\text{ 0)} \\ (h-a,\text{ k)=(2-}4,\text{ }0)=(-2,\text{ 0)} \end{gathered}[/tex]Hence, the coordinates of the vertices are (6, 0) and (-2,0).
The coordinates of the co-vertices are given by,
[tex]\begin{gathered} (h,\text{ k+}b)=(2,\text{ }0+2)=(2,\text{ 2)} \\ (h,\text{ k-}b)=(2,\text{ }0-2)=(2,\text{ -2)} \end{gathered}[/tex]Hence, the coordinates of the co-vertices are (2, 2) and (2, -2).
The coordinates of the foci are (h±c, k).
[tex]\begin{gathered} c^2=a^2-b^2 \\ c^2=4^2-2^2 \\ c^2=16-4 \\ c^2=12 \\ c=2\sqrt[]{3} \end{gathered}[/tex]Using the value of c, the coordinates of the foci are,
[tex]\begin{gathered} \mleft(h+c,k\mright)=(2+2\sqrt[]{3},\text{ 0)} \\ (h-c,k)=(2-2\sqrt[]{3},\text{ 0)} \end{gathered}[/tex]Therefore, the coordinates of the foci are,
[tex](2+2\sqrt[]{3},\text{ 0) and }(2-2\sqrt[]{3},\text{ 0)}[/tex]The endpoints of the latus rectum is,
[tex]\begin{gathered} (h+c,\text{ k}+\frac{b^2}{a})=(2+2\sqrt[]{3},\text{ 0+}\frac{2^2}{4^{}}) \\ =(2+2\sqrt[]{3},\text{ 1)}^{} \\ (h-c,\text{ k}+\frac{b^2}{a})=2-2\sqrt[]{3},\text{ 0+}\frac{2^2}{4^{}}) \\ =(2-2\sqrt[]{3},\text{ 1}^{}) \\ (h+c,\text{ k-}\frac{b^2}{a})=(2+2\sqrt[]{3},\text{ 0-}\frac{2^2}{4^{}}) \\ =(2+2\sqrt[]{3},\text{ -1}^{}) \\ (h-c,\text{ k-}\frac{b^2}{a})=(2-2\sqrt[]{3},\text{ 0-}\frac{2^2}{4^{}}) \\ =(2-2\sqrt[]{3},\text{ -1}^{}) \end{gathered}[/tex]Therefore, the coordinates of the end points of the latus recta is,
[tex](2+2\sqrt[]{3},\text{ 1)},\text{ }(2-2\sqrt[]{3},\text{ 1}^{}),\text{ }(2+2\sqrt[]{3},\text{ -1}^{})\text{ and }(2-2\sqrt[]{3},\text{ -1}^{})[/tex]Now, the equations of the directrices is,
[tex]\begin{gathered} x=h\pm\frac{a}{e} \\ x=\pm\frac{a}{\sqrt[]{1-\frac{b^2}{a^2}}} \\ x=2\pm\frac{4}{\sqrt[]{1-\frac{2^2}{4^2}}} \\ x=2\pm\frac{4}{\sqrt[]{1-\frac{1^{}}{4^{}}}} \\ x=2\pm\frac{4}{\sqrt[]{\frac{3}{4}^{}}} \\ x=2\pm4\sqrt[]{\frac{4}{3}} \end{gathered}[/tex]Here, e is the eccentricity of the ellipse.
Therefore, the directrices of the ellipse is
[tex]x=2\pm4\sqrt[]{\frac{4}{3}}[/tex]Now, the graph of the ellipse is given by,
Graph of this line using intercepts. I need some help some assistance would be nice
Explanation:
The equation of the line is given below as
[tex]2x+3y=18[/tex]Step 1:
To determine the x-intercepts, we will put y=0 and solve for x
[tex]\begin{gathered} 2x+3y=18 \\ 2x+3(0)=18 \\ 2x+0=18 \\ 2x=18 \\ \frac{2x}{2}=\frac{18}{2} \\ x=9 \\ x-intercept=(9,0) \end{gathered}[/tex]Step 2:
To determine the y-intercept, we will put x=0 and solve for y
[tex]\begin{gathered} 2x+3y=18 \\ 2(0)+3y=18 \\ 0+3y=18 \\ \frac{3y}{3}=\frac{18}{3} \\ y=6 \\ y-intercept=(0,6) \end{gathered}[/tex]Hence,
The graph using the intercepts will be given below as
The sum of two numbers is 164. The second number is 24 less than three times the first number. Find the numbers.
How does basic algebra come to play in everyday life? Explain (or give examples) in at least two sentences
Explanation
1) Algebra can be used while cooking to estimate the amount of ingredients by solving some easy algebraic expressions of the head.
e.g 2 tea spoons of pepper out of a 1kg pack might be the right amount to spice a soup.
2) For example, a plumber may do some quick calculations to determine the number of pipes required for a house
e.g 5 pipes in the bathroom, two pipes in the toilet, three in the kitchen gives 10 pipes altogether.
For circle H, JN = x, NK = 8, LN = 4, and NM = 20.Solve for x.
Solution
Consider the illustration below
Using the idea of the illustration above,
[tex]JN\text{ x NK = LN x NM}[/tex][tex]\begin{gathered} x\text{ x 8 = 4 x 20} \\ 8x=80 \\ x=\frac{80}{8} \\ x=10 \end{gathered}[/tex]The answer is 10
To solve for the interest rate of your credit card, you need to understand which variables in the above formula you have. If your minimum monthly payment is $22 on the $1,000 credit card bill, which variables do you know the values of?
Type your response here:
The variables which are known from the information given in the task content are; The Monthly interest amount and the Principal.
What variables are known from the information given in the task content?It follows from the task content that the variables which are known are to be determined.
Since it is given in the task content that the minimum monthly payment is; $22, it follows that the interest amount is; $22.
Also, since the credit card bill is; $1,000, it follows that the principal on the credit card is; $1,000.
Hence, the variables which are known are;
The monthly interest amount andThe Principal amount.The variables above are therefore used to determine the interest rate of the credit card.
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11. Natalie budgets $165 for yoga training. She buys a yoga mat for $13.25 and pays $12 per yoga class. Fill in the boxes below to write an inequality to represent the number of classes, c, that Natalie can take and stay within her budget.
She has a budget of $165, so the total cost of the yoga mat and the classes has to be equal or less than $165.
[tex]C\le165[/tex]The cost is equal to the cost of the yoga mat ($13.25) and the cost of the classes ($12*c, being c the number of classes).
We can write this as:
[tex]C=13.25+12c[/tex]We then can combine both equations and get:
[tex]13.25+12c\le165[/tex]That inequality represents that the total expenses of Natalie have to be equal or less than $165.
Answer: 13.25 + 12c <= 165
how to find two consecutive whole numbers that square root 40 lies between
First, we need to identify the square root of the fisrt squared numbers:
[tex]\begin{gathered} \sqrt{1}=\text{ 1} \\ \sqrt{4}=2 \\ \sqrt{9}=3 \\ \sqrt{16}=4 \\ \sqrt{25}=5 \\ \sqrt{36}=6 \\ \sqrt{49}=7 \\ \sqrt{64}=8 \end{gathered}[/tex]Since 40 is a number between 36 and 49, we can say that the square root of 40 is between 6 and 7. So:
[tex]6<\sqrt{40\text{ }}<7[/tex]Solve the equation. f(x)=g(x) by graphing. f(x) = l x +5 l g(x) = 2x + 2 Select all possible solutions: No Solutions x=3 x=0 X=-1
As you can observe in the graph below, the given functions intercept at one point.
Hence, there is a unique solution and it's x = 3.There is a 40% chance that it will be cloudy tomorrow.
If it is cloudy, there is a 79% chance that it will rain.
What is the probability that it will rain?
Answer:
3.16%
Step-by-step explanation:
a*(79/100)*40/100
3.16a/100
3.16%
Answer:
O. 316
Step-by-step explanation:
40/100 × 79/100 =0.316
b. Find a pair of numbers that have a sum of 50 and will produce the largest possible product. Example: +_ = 50 (sum) so _* _ = _ (maximum area) and (enter answers from the sum)
A pair of numbers that have a sum of 50
Let the number is x, so the other number is 50 - x
Let f(x) be the largest product so:
[tex]f(x)=\text{ x(50-x)}[/tex]Simplify the expression :
[tex]\begin{gathered} f(x)=\text{ x(50-x)} \\ f(x)=50x-x^2 \end{gathered}[/tex]Diffrentiate with respect to x
[tex]\begin{gathered} f(x)=\text{ x(50-x)} \\ f(x)=50x-x^2 \\ \text{ Diffrentiate with respect to x} \\ f^{\prime}(x)=50-2x \\ \text{Apply derivative equal to zero:} \\ 50-2x=0 \\ 50=2x \\ x=25 \end{gathered}[/tex]Now for to check for the f(x) is maximum for x = 25
Calculate the second derivative and put x = 25 is the f(x) is negative then the multiplication f(x) is maximum
[tex]\begin{gathered} f^{\prime}(x)=50-2x \\ \text{ Differentiate with respect to x} \\ f^{\prime}^{\prime}(x)=0-2 \\ \text{ Substitute x = 25} \\ f^{\doubleprime}(25)=-2 \\ f^{\doubleprime}(25)<0 \\ \text{Thus the function f(x) is maximum for x = 25} \end{gathered}[/tex]Thus, the first number is 25
Second number is : 50 -x = 50-25 = 25
Numbers are 25, 25
Answer : 25 + 25 =50 (sum)
25 * 25 = 625 (maximum possible product)
Jelani filled an aquarium with blocks that were each one cubic foot in size. He filled the bottom layer of the aquarium with 21 blocks. He then stacked three more blocks on top of the bottom layer. The partially filled aquarium is shown below. What is the total volume, in cubic feet, of the aquarium?
Answer:
The total volume of the aquarium is;
[tex]84\text{ }ft^3[/tex]Explanation:
Given the figure in the attached image.
The bottom of the aquarium was covered with 21 blocks with 1 cubic foot each.
Each face of the cubic blocks will have a surface area of 1 square foot each.
So, the surface area of the base of the aquarium will be;
[tex]\begin{gathered} A=21\times1ft^2 \\ A=21\text{ }ft^2 \end{gathered}[/tex]Recall that volume equals base area multiply by the height of the aquarium;
[tex]V=A\times h[/tex]From the figure, the height of the aquarium requires 4 blocks, which makes the height 4 ft;
[tex]h=4ft[/tex]So, we can now substitute the values of the height and the base area to calculate the total volume of the aquarium;
[tex]\begin{gathered} V=A\times h \\ V=21ft^2\times4ft \\ V=84\text{ }ft^3 \end{gathered}[/tex]Therefore, the total volume of the aquarium is;
[tex]84\text{ }ft^3[/tex]6. Find the domain and range of V(x) in this context.7. Think of V(x) as a general function without the constraint of modeling the volume of a box. What would be the domain and range of V(x)?8. Use correct notation to describe the end behavior of V(x) as a function without context.
We have , that measure of the side of the square is x
Therefore
l=26-2x
w=20-2x
h=x
Therefore the Volume function is
[tex]V=(26-2x)(20-2x)x[/tex]Then we simplify
[tex]V(x)=4x^3-92x^2+520x[/tex]6.In the context of obtaining a Volume we can't have negative numbers for x and for the function by observing the graph
Domain
[tex]0\le x\le10[/tex]Therefore for the range
[tex]0\: 7.Because we have a polynomial
the domain without the constrain
[tex]-\infty\: the range without the constrain[tex]-\infty\: 8.Since the leading term of the polynomial is 4 x^{3}, the degree is 3, i.e. odd, and the leading coefficient is 4, i.e. positive. This means
[tex]\begin{gathered} x\to-\infty,\text{ }f(x)\to-\infty \\ x\to\infty,f(x)\to\infty \end{gathered}[/tex]Find the equation of the line, in slope-intercept form, that passes through the points (-2, -4) and (2,8).A) y = 1/3x + 22/3B) y = 3x + 14C) y = 3x + 2 D) y = - 3x + 14
The equation of a line in the slope intercept form is expressed as
y = mx + c
where
m = slope
c = y intercept
The formula for calculating slope is expressed as
m = (y2 - y1)/(x2 - x1)
where
x1 and y1 are the x and y coordinates of the initial point
x2 and y2 are the x and y coordinates of the final point
From the information given, the initial point is (- 2, - 4) and final point is (2, 8)
Thus,
x1 = - 2, y1 = - 4
x2 = 2, y2 = 8
By substituting these values into the slope formula,
m = (8 - - 4)/(2 - - 2) = (8 + 4)/(2 + 2) = 12/4 = 3
We would find the y intercept, c by substituting m = 3, x = - 2 and y = - 4 into the slope intercept equation. We have
- 4 = 3 * - 2 + c
- 4 = - 6 + c
Adding 6 to both sides of the equation,
- 4 + 6 = - 6 + 6 + c
c = 2
By substituting m = 3 and c = 2 into the slope intercept equation, the equation of the line is
C) y = 3x + 2
Victoria and her children went into a grocery store and she bought $9 worth of applesand bananas. Each apple costs $1.50 and each banana costs $0.50. She bought a totalof 8 apples and bananas altogether. Determine the number of apples, x, and thenumber of bananas, y, that Victoria bought.Victoria boughtapples andbananas.
We will determine the solution as follows:
*First: From the text, we have the following expressions:
[tex]x+y=8[/tex]&
[tex]1.50x+0.5y=9[/tex]Here x represents apples and y represents bananas.
*Second: From the first expression, we solve for either x or y, that is [I will solve for ]:
[tex]x+y=8\Rightarrow x=8-y[/tex]*Third: Now, using the value for x, we replace in the second expression and solve for y, that is:
[tex]1.50x+0.5y=9\Rightarrow1.50(8-y)+0.5y=9[/tex][tex]\Rightarrow12-1.50y+0.5y=9\Rightarrow-y=-3[/tex][tex]\Rightarrow y=3[/tex]*Fourth: We replace the found value of y on the first expression and solve for x:
[tex]x+y=8\Rightarrow x+3=8[/tex][tex]\Rightarrow x=5[/tex]So, the number of apples was 5 and the number of bananas was 3.
During a tropical storm, the temperature decreased from 84° to 63º. Find the percent decrease in temperature during the storm. (a) 33% (b) 25% (c) 40% (d) 75%
To find the percentage of decrease, first, we divide.
[tex]\frac{63}{84}=0.75[/tex]This means 63° represents 75% of 84°. In other words, the temperature decreased by 25%.
Hence, the answer is B.Steven read a total of 8 books over 4 months. After belonging to the book club for 7 months,how many books will Steven have read in all?
If he reads 8 books over 4 months it means that he reads 2 books per month. So, if we multiply this ratio by the 7 months we would find that he reads 14 books over 7 months.
The answer is 14 books.
Julie can run 3 laps in 9 minutes. At this rate, how many laps can she run in 24 minutes?
Answer:
Julie can run 12 laps
Step-by-step explanation:
9 min = 3 laps
9 x 2 = 18 = 6 laps
9 cant fit into 24 again
24 - 18 = 6
6 + 6 = 12 laps
If y = (x/x+1)5, then dy/dx
The value of dy/dx is 5x^4 / (x + 1)^6.
What is the derivative?
A function's sensitivity to change with respect to a change in its argument is measured by the derivative of a function of a real variable.
The given function is y = (x / (x + 1))^5
Taking derivative on both sides,
dy/dx = d/dx (x / (x + 1))^5)
Using chain rule,
dy/dx = 5(x / x + 1)^4 x d/dx (x / x + 1)
Using the quotient rule of derivative,
d/dx (x / x + 1) = 1 / (x + 1)^2
So,
dy/dx = 5(x / x+1)^4 x (1 / (x + 1)^2)
dy/dx = 5x^4 / (x + 1)^6
Therefore, the derivative of the given function is, dy/dx = 5x^4 / (x + 1)^6.
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What is the value of Negative 3mn + 4m minus 3 when m = 2 and n = negative 4?
SOLUTION
STEP 1: Write the given expression
[tex]-3mn+4m-3[/tex]STEP 2: Write the given values
[tex]\begin{gathered} m=2 \\ n=-4 \end{gathered}[/tex]STEP 3: Evaluate the given expression
[tex]\begin{gathered} -3(2)(-4)+4(2)-3=24+8-3 \\ 32-3=29 \end{gathered}[/tex]Hence, the answer is 29
3x + 9 ≤ 30answer the solution
Shown below are the scatter plots for four different data sets.Answer the questions that follow. The same response may be the correct answer for more than one question.
Solution:
Given the scatter plots below:
A scatter plot will have a negative correlation if the points form line that slants from from left to right. In other words, the variable y decreases, as x increases.
When the line formed slants from right to left, the scatter plot will have a positive correlation. In other words, the variable y increases as variable x increases.
When the points are scattered randomly, there's no correlation or relationship between the variables in the scatter plot.
Thus,
1. Dataset that indicates the strongest positive linear relationship between its two variables.
Answer: The dataset in figure 4
2. Dataset that whose correlation coefficient is closest to zero.
Answer: The dataset in figure 1.
3. Dataset that whose correlation coefficient is closest to -1.
Answer: The dataset in figure 2.
Gor trapezoid HJKL, T and S are midpoint of the legs. If HJ = 14 and LK = 42, find TS.
First, we are going to divide the figure and named new points X and Y as:
Now, we know that TS is the sum of TX and XS.
TS = TX + XS
Adittionally, TX has the same length of HJ, so:
TX = HJ = 14
Now, we want to know the length of YK, and we can calculate it using the following equation:
LK = LY + YK LY is also equal to HJ, so LY = 14
42 = 14 + YK
42 - 14 = YK
28 = YK
Finally, since T and S are midpoints, the length of XS is the half of the length of YK. It means that XS is:
XS = YK/2
XS = 28/2
XS = 14
Therefore, TS is equal to:
TS = TX + XS
TS = 14 + 14
TS = 28
Answer: TS = 28
3. There are two city buses in Saratoga. Bus A completes its route in 25 minutes. Bus B completes its route in 40 minutes. Both of their routes end at the bus station. If both buses leave the bus station at the same time in the morning, how many minutes will pass before the two buses meet at the train station?
To find the answer, we have to find the LCM of 25 and 40.
To get LCM, we
Write each number as prime factors
take the prime factor that occurs greatest number of time
take the product of those
Thus,
25 = 5 * 5
40 = 2 * 2 * 2 * 5
2 occurs 3 times and 5 occurs 2 times (greatest).
hence,
LCM(25, 40) = 2 * 2 * 2 * 5 * 5 = 200
So,
200 mins will pass before the two buses meet
Can someone help me with this geometry question? I will provide more information.
So you are given a triangle ABC and you need to build another one DEF that meets the following:
[tex]\begin{gathered} AB=DE \\ m\angle E=90^{\circ} \\ EF=BC \end{gathered}[/tex]First of all we should find the lengths of sides AB and BC. For this purpose we can use the coordinates of points A, B and C. The length of AB is the distance between A and B and the length of BC is the distance between B and C. The distance between two generic points (a,b) and (c,d) is given by:
[tex]\sqrt[]{(a-c)^2+(b-d)^2}[/tex]Then the length of AB is:
[tex]AB=\sqrt[]{(1-1)^2+(6-1)^2}=\sqrt[]{0+5^2}=5[/tex]And that of BC is:
[tex]BC=\sqrt[]{(1-5)^2+(1-1)^2}=\sqrt[]{4^2}=4[/tex]Then the triangle DEF must meet these three conditions:
[tex]\begin{gathered} DE=5 \\ EF=4 \\ m\angle E=90^{\circ} \end{gathered}[/tex]Since there is no rules about its position we can draw it anywhere. For example you can choose E=(-4,1). Then if D=(-4,6) we have that the length of DE is 5:
[tex]DE=\sqrt[]{(-4-(-4))^2+(6-1)^2}=\sqrt[]{0+5^2}=5[/tex]And if we take F=(0,1) we get EF=4:
[tex]EF=\sqrt[]{(-4-0)^2+(1-1)^2}=\sqrt[]{16}=4[/tex]Then a possibility for triangle DEF is:
As you can see it also meets the condition that the measure of E is 90°. And that would be part A.
In part B we have to use the pythagorean theorem to state a relation between the sides of DEF. For a right triangle with legs a and b the theorem states that its hypotenuse h is given by:
[tex]h^2=a^2+b^2[/tex]We can do the same for DEF. Its legs are DE and EF whereas its hypotenuse is DF so we get:
[tex]DF^2=DE^2+EF^2[/tex]And that's the equation requested in part B.