The precipitate that will be formed : AgF
Further explanationOne indication of the double displacement reaction is the precipitation reaction
Solubility Rules:
• 1. soluble compound
All compounds of Li +, Na +, K +, Rb +, Cs +, and NH4 +
All compounds of NO₃⁻ and C₂H₃O₂⁻
Compounds of Cl−, Br−, I− except Ag⁺, Hg₂²⁺, Pb²⁺
Compounds of SO₄²⁻ except for Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺
• 2. insoluble compounds
Compounds of CO₃²⁻ and PO₄³⁻ except for Compounds of Li +, Na +, K +, Rb +, Cs +, and NH₄ +
Compounds of OH− except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺, Sr²⁺, and Ba²⁺
Reaction
NaF(aq) + AgNO₃(aq) →NaNO₃(aq)+ AgF(s)
From the solubility rules above, it has been shown that the salts of the Ag⁺ cations are insoluble salts
Which of the following has the larger atomic radius?
O Cs
O Ca
O Li
O Ba
Hope it helps
Determine the number of moles in 5.25x1024 formula units if lead (IV) oxide.
Answer:
8.72 mol PbO₂
General Formulas and Concepts:
Chemistry - Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:
Step 1: Define
5.25 × 10²⁴ formula units PbO₂
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[tex]5.25 \cdot 10^{24} \ formula \ units \ PbO_2(\frac{1 \ mol \ PbO_2}{6.022 \cdot 10^{23} \ formula \ units \ PbO_2} )[/tex] = 8.71803 mol PbO₂
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
8.71803 mol PbO₂ ≈ 8.72 mol PbO₂
Exactly how many planes contain points J, K, and N?
O 0
O 1
O 2
O 3
Answer:
0
Explanation:
Point J is on neither plane X or plane Y. Hope this helps you.
Answer:
3
Explanation:
How are Earth's continents related?
Please help due at 11:45!
Balance the following equation.
___ I + ___ O2 ___ I4O10
what is the density of a liquid if it's volume is 125 mL and it's mass is 50g?
Answer:
0.4g/ml
Explanation:
density= mass/volume
density=50g/125ml
density=0.4g/ml
How much work is required to pull a sled if you use 60J of work in 5 seconds?
Answer:
DO I Look Like santa too you how am i supposed to know How about this how about you goo.gle the answer wow smart
Explanation: