positively charged center of an atom

Answers

Answer 1

Answer:

the nucleus

Explanation


Related Questions

Distance meters Time (seconds) Trial Tria 2 Trials Average 3 053 059 0.52 055 6 106 719 104 Uning the values trom the data table calculate the speed of the object that traveled 3 meters Round your value to two decimal places past the Decimal 5 4545 m/s 0.18 m/s 0183333 ms 545ms​

Answers

Jsisisusuagahannananana this is worth 22 points g that’s crazy 25

Answer:

I'm pretty sure it's the last one, or D.

Explanation:

I did the math in my head so forgive me if I'm wrong :)

the reading on an electric meter was 2345 kWh, and one month later it was 3456 kWh. how much was the electric bill if the electricity costs $0.10 per kilowatt-hour?

Answers

An electric meter reads 2345 kWh and 3456 kWh a month later. At $0.10/kWh, the bill for this energy consumption will be $111.1.

What is a kiloWatt-hour?

A kiloWatt-hour (kWh) is a unit of energy equal to one kilowatt of power for one hour.

Step 1. Calculate the energy consumption in one month.

The energy consumption will be equal to the difference between both readings.

E = 3456 kWh - 2345 kWh = 1111 kWh

Step 2. Calculate the cost of the bill.

The cost of electricity is $0.10/kWh.

1111 kWh × $0.10/kWh = $111.1

An electric meter reads 2345 kWh and 3456 kWh a month later. At $0.10/kWh, the bill for this energy consumption will be $111.1.

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Which planet, other than earth, has visible water ice on it?.

Answers

Mercury has viable water and ice on it

Why is the ‘dark side’ of the moon a misnomer?

Answers

Answer:

For starters, “dark side” is a misnomer. The far side may be constantly facing away from Earth, but as it orbits the Earth it sometimes faces the sun just as the bright side does. Thus the far side is subject to the same day/night temperature extremes as the side facing Earth.

Explanation:

The far side may be constantly facing away from earth, but as it orbits the earth it sometimes faces the sun just as the bright side does

A golf club exerts an average force of 500N on a 0.1kg golf ball and the contact time is 0.01s.

What is the change in velocity of the golf ball?​

Answers

Answer:

[tex]50\; {\rm m\cdot s^{-1}}[/tex], assuming that the force on the golf ball was constant.

Explanation:

Assume that the force the golf club exerted on the golf ball a constant force of magnitude [tex]F[/tex]. Let [tex]\Delta t[/tex] denote the duration the club was in contact with the golf ball. The impulse of this force would be:

[tex]J = F\, \Delta t[/tex].

Let [tex]\Delta p[/tex] denote the change in the momentum of this golf ball. By the impulse-momentum theorem, this [tex]\Delta p\![/tex] would be equal to the impulse on the golf ball.

[tex]\Delta p = J = F\, \Delta t[/tex].

The momentum [tex]p[/tex] of this golf ball is the scalar product between the mass [tex]m[/tex] of this golf ball and the velocity [tex]v[/tex] of this golf ball. The mass of this golf ball stays the same. Thus, when the momentum of this golf ball changes by [tex]\Delta p[/tex], the velocity of this golf ball would change by [tex](\Delta p) / (m)[/tex].

The change in the velocity of this golf ball would thus be:

[tex]\begin{aligned}\Delta v &= \frac{\Delta p}{m} & \genfrac{}{}{0em}{}{(\text{change in momentum})}{}\\ &= \frac{J}{m} & \genfrac{}{}{0em}{}{(\text{impulse on the golf ball})}{}\\ &= \frac{F\, \Delta t}{m} \\ &= \frac{500\; {\rm N} \times 0.01\; {\rm s}}{0.1\; {\rm kg}} \\ &\approx 50\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

(Note that [tex]1\; {\rm N} = 1\; {\rm kg \cdot m^{2}\cdot s^{-2}}[/tex].)

why do we see optical illusion?​

Answers

Optical illusions occur because our brain is trying to interpret what we see and make sense of the world around us. Optical illusions simply trick our brains into seeing things which may or may not be real.

Optical illusions occur because our brain is trying to interpret what we see and make sense of the world around us. Optical illusions simply trick our brains into seeing things which may or may not be real.
Have a great day ;)

Which types of electromagnetic waves have longer wavelengths than the waves that make up visible light? select three options. radio waves gamma rays microwaves infrared light ultraviolet light x-rays

Answers

Answer:

infrared light have longe rwave length

The three electromegnetic waves that have longer wavelengths that make up visible light will be microwaves, radio waves, and infrared light.

What is an electromagnetic wave?

EM waves are another name for electromagnetic waves. Electromagnetic radiations are made up of electromagnetic waves created when an electric field collides with a magnetic field.

Electromagnetic waves may alternatively be defined as the combination of oscillating electric and magnetic fields. Maxwell's equations are solutions to electromagnetic waves.

Of all electromagnetic waves, radio waves have the longest wavelength.

Hence the three electromegnetic waves that have longer wavelengths that make up visible light will be microwaves, radio waves, and infrared light.

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friction causes kinetic energy to be converted into
A. Potential energy
B. Thermal energy
C.mechanical energy
D. Electrical energy
Which one is it pls help me

Answers

Answer:

Thermal Energy

Explanation:

When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy. Otherwise known as thermal energy.

A (1.03x10^2)-mA current is used to charge up a parallel plate capacitor. A large square piece of paper is placed between the plates and parallel to them so it sticks out on all sides. What is the value of the integral ∮B⃗ .ds⃗ around the perimeter of the paper? Express your result in T.m with three significant figures.

Answers

Since a 1.03 × 10² mA current is used to charge up the parallel plate capacitor and a large square piece of paper is placed between the plates and parallel to them so it sticks out on all sides, the value of ∫B.ds around the perimeter of the paper is 1.29 × 10⁻⁷ Tm

Ampere's Law

This shows the relationship between the magnetic field, B, the path of integration, ds and the current enclosed by the magnetic field, i.

Ampere's law is given mathematically as

∫B.ds = μ₀i where

B = magnetic field, ds = arc length of path of integration, μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A and i = current enclosed by the path of integration, ds.

Given that for the large square piece of paper, the current used to charge the capacitor is

i = 1.03 × 10² mA = 1.03 × 10² × 10⁻³ A = 1.03 × 10⁻¹ A and ds = path length around the perimeter of the paper

The value of ∫B.ds around the perimeter of the paper

Since ∫B.ds = μ₀i

Substituting the values of the variables into the equation, we have

∫B.ds = μ₀i

∫B.ds = 4π × 10⁻⁷ Tm/A × 1.03 × 10⁻¹ A

∫B.ds = 4.12π × 10⁻⁸ Tm

∫B.ds = 12.94 × 10⁻⁸ Tm

∫B.ds = 1.294 × 10⁻⁷ Tm

∫B.ds ≅ 1.29 × 10⁻⁷ Tm

So, the value of ∫B.ds around the perimeter of the paper is 1.29 × 10⁻⁷ Tm

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use convention factors to convert
20kHz to Hz​

Answers

Answer:

20kHz = 20000Hz

Explanation:

The frequency in hertz (Hz) is equal to the frequency in kilohertz (kHz) times 1000

He much current is needed to operate a radio with a power of 80 watts when a potential difference of 135v is applied across itl

Answers

Answer:

593 mAmps

Explanation:

Power = 80 watts =  VI

               80 = 135 I

                 80/135 = I =

how is the effect of balanced forces different from that of unblanced forces on the motion of an object

Answers

Answer:

Balanced forces do not result in any change in motion.

Explanation

forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion. friction the force that opposes the motion or tendency toward motion of two objects that are in contact.

Answer:

balanced forces are equal in size and opposite in direction

Hello people ~
Question: A hemisphere is uniformely charged positively. The electric field a point on a diameter away from the centre is directed

(a) perpendicular to the diameter

(b) parallel to the diameter

(c) at an angle tilted towards the diameter

(d) at an angle tilted away from the diameter​

Answers

As the electric field is present at a point on diameter the electric field intensity at the electric field components are parallel to the diameter hence they cancel out .

So the field is directed perpendicular towards the diameter

Option A

Question #3:

A sample of helium behaves as an ideal gas as it is heated at constant pressure from 293 K to 363 K. If 70 J of work is done by the gas during this process, what is the mass of the helium sample? The universal gas constant is 8.31451 J/mol · K. Answer in units of g.

Answers

For a sample of helium behaves as an ideal gas as it is heated at constant pressure from 293 K to 363 K, the mass of the helium sample  is mathematically given as

n= 0.0986 g

What is the mass of the helium sample?

Generally, the equation for the ideal gas  is mathematically given as

PV=nRT

Therefore

W = P*(V2-V1)

W=nR(T2- T1)

n = W / (R*(T2 - T1) )

n= 4g/mol ∙ 16 J / (8.3145J/molK ∙ (351K - 273K) )

n= 0.0986 g

In conclusion, the mass of the helium sample

n= 0.0986 g

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An electron (me = 9.1 x 10-31 kg) traveling south at a constant speed of 5.0 x 106 m/s enters a
region where the downward component of earth's magnetic field is 3.5 x 10-5 T. What is the
magnitude and direction of the acceleration of the electron at this instant?

Answers

Answer:

F = Q V X B

V X B = south X downard = East - deflection is West

Since Q is negative the deflection = West

a = F / m = Q V B / m

a = 1.6E-19 * 5*E6 * 3.5E-5 / 9.1E-31

a = 1.6 * 5 * 3.5 / 9.1 * 10^13 m/s^2 = 3.1 * 10^13 m/s^2

During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.​

Answers

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

What is anomalous expansion of water?

Anomalous expansion of water is a property of water in which water expands instead of contracting.

Anomalous expansion of water makes water less dense. The major effect of this anomalous expansion it will still remain less dense and at the surface of water.Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.

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Which statement describes the law of conservation of energy

Answers

Answer:

law of action and riactiond

How well do you think a model can demonstrate the principles of stratigraphy?

Answers

Stratigraphy is a discipline aimed at identifying layers of sedimentary and/or volcanic rocks, which is mainly based on the principle of superposition.

What is stratigraphy?

Stratigraphy refers to the science based on the identification of different layers in sedimentary and/or volcanic rocks.

Stratigraphy as a discipline is mainly cemented on the principle of superposition, which indicates that older layers of sediment are located on the bottom.

Stratigraphy allows us to understand the geological past of a region, which is important in different disciplines such as biogeography.

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Water vapor is an important greenhouse gas in Earth's atmosphere. The map here shows the average amount of water vapor in a column of atmosphere during one month in 2015.

Based on the data in the map where would you expect temperatures on Earth to be warmest?

• At higher altitudes
• Over the poles
• At the equator.
• Over landmasses​

Answers

Answer:

The answer in C- At the equator

Explanation:

just took the test and got it correct

Based on the data in the map, the temperatures on Earth to be warmest will be at equator. The third option is correct.

What is greenhouse gas?

The gases which get easily trapped inside the glasses and increase the temperature of the atmosphere causing the global warming level to increase overall.

Water vapor is an important greenhouse gas in Earth's atmosphere. The map here shows the average amount of water vapor in a column of atmosphere during one month in 2015.

Based on the data in the map, the temperatures on Earth to be warmest will be at equator.

Thus, third option is correct.

Learn more about greenhouse gas.

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8.
A microscopic view of a sheet of paper is shown in the diagram at the
right. Would you expect this sheet of paper to cause light to undergo
regular or diffuse reflection?
Explain.
9.
From what type of surface do you think it would be easier to read?
From pages, which are rough, or from pages which are smooth and
glossy?
Explain your answer.
A microscopic view
of a sheet of paper.
10. Driving at night offers a great example of diffuse vs. regular reflection. A dry road is a diffuse
reflector, while a wet road is not. On the diagrams below, sketch the reflected light off a wet and dry
surface.
Dry Surface
Wet Surface
Why would the wet road appear to the driver to be darker than the dry road?
11. The diagram below contrasts the reflection of light off a smooth surface (left) with the reflection of
light off a rough surface (right). Compare the two diagrams and explain why the reflected rays for a
rough surface do not result in the formation of an image.

Answers

Based on the nature of reflection of light from surfaces, smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

What is reflection of light waves?

Reflection of light waves refers tobtye bouncing back of light waves when they hit a shiny surface.

Depending on the nature of the surface, reflection of light waves can either be regular if diffuse.

Smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

Based on the properties of reflection:

A microscopic view of a sheet of paper shows that the surface is rough, thus it would produce diffuse reflection. Rough pages are easier to read from than smooth and glossy surfaces because they produce diffuse reflection while reading off smooth surface causes a glare due to intense regular reflectionA wet road appears darker because more light passes through and it reflects less light and looks darkerdiffuse reflection do not all pass through the principal focus, thus an image is not formed off a rough surface

Therefore, it can be concluded that the rough surfaces produce diffuse reflection while smooth and glossy surfaces produce regular reflection.

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You need to move a large refrigerator. It has a mass of 300 kg. You want to accelerate it at a rate of 3 m/s/s. What force must you apply?

Answers

Answer:

900 N

Explanation:

F = ma

  = 300 (3) = 900 N

a 20-kg object travelling at 20 m/s collides head on with an 18-kg object travelling at 17 m/s.If they were locked together after the collision, what is their velocity?.​

Answers

Answer:

2.47 m/s

Explanation:

Momentum = Mass X Velocity

If they were locked together, it means its a perfectly inelastic collision. Therefore,

Total momentum before = Total momentum after

Total momentum before = (20 X 20) - (18 X 17)

= 94

Total momentum after = 94

Y = Object speed after collision

94 = (20+18)Y

Y = 2.47368421 m/s

A satellite is in elliptical orbit with a period of 8.00 x l-0a s about a planet of mass 7.00 x t024 kg. At aphelion, at radius 4.5 x 1-07 m, the satellite's angular speed is 7.L58 x 10-s rad/s. What is its angular speed at perihelion

Answers

Given that the satelite's angular speed is given,The angular speed at the perihelion is : 9.2426 * 10⁻⁵ rad/s

Given data:

Satellite period = 8 * 10⁴ s

mass of planet (Wa)  = 7 * 10²⁴ kg

Radius of Aphelion ( Ra ) = 4.5 * 10⁷ m

satellite angular speed ( Vp )= 7.158 * 10⁻⁵ rad/s

Determine the angular speed at the perihelion

Applying kepler's law

VpRp = VaRa

where:

Vp = ( Ra / Rp ) Va

and

Wp = Vp / Rp  = ( RA / Rp )² Wa  ---- ( 1 )

Note : Assuming a is distance from the center oto the end of the satelite

Rp = 2a - Ra  ---- ( 2 )

Next step : determine the value of a

applying the formula below

a = [tex](\frac{T\sqrt{Gmplanet} }{2\pi } )^{2/3}[/tex] --- ( 3 )

where ; T = 8 * 10⁴ s,  G = 6.67 * 10⁻¹¹ ,  Mplanet = 7 * 10²⁴ kg

input values into ( 3 )

a = 42300747.03 m

Final step : determine the angula speed at perihelion

Back to equation ( 1 ) and ( 2 )

Wp = ( RA / 2a - Ra  )² Wa  

      = 9.2426 * 10⁻⁵ rad/s.

Hence we can conclude that Given that the satelite's angular speed is given,The angular speed at the perihelion is : 9.2426 * 10⁻⁵ rad/s

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why empty tin-cans ocillating for a longer time​

Answers

Answer: When you speak into the can, your voice creates air vibrations that travel into the can, vibrate the bottom of the can, which in turn vibrates the string all the way over to the other can, in turn vibrating the other can's bottom, then the air again.

Explanation:

a doctor measures the temperature of a patient to be 101 degrees . what is this temperature in kelvins

Answers

Answer:

the answer is 374.15 kelvins

If the same object was taken to each of the planets, where would it weigh the most and where would it weigh the least

Answers

Answer:

it way the most on jupiter and the least on mars

Explanation:

What happens when a mixture is separated
A) A substance is lost
B) A new substance is formed
C) The substances stay the same
D) The mass of the substances change

Answers

Answer:

the answer would be c

Explanation:

a 65 kg climber on top of Mount Everest (8800 m high). what is the gravitational potential energy?

Answers

Answer:

He has 5,609,404 J of potential energy

Explanation:

P.E. = M*G*H

65 * 9.8^2 * 8800

The potential energy of the climber whos weight is 65 kg at a height of 8800 m is 5.6 × 10⁶ Joules.

What is Potential energy?

The potential energy of a body is defined as that generated by virtue of its position which is the form of energy stored in an object when it is at rest. When a body stops its motion, its kinetic energy is converted into potential energy.

Potential energy is related to the mass 'm' and height 'h' of the object from the ground and the acceleration due to gravity g is expressed as:

PE = m g h.

For above given information, mass of the climber = 65 Kg

Height of the mountain = 8800 m

g = 9.8 m/s²

Thus, PE = 65 kg × 8800 m × 9.8 m/s² = 5.6 × 10⁶ Joules.

Thus, the potential energy of the climber will be 5.6 × 10⁶ Joules.

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a material used by living things for growth and other life functions is a?

Answers

Answer:

I believe it wouled be Nutrients

Explanation:

hope this helps if not please let me know

Delusions of grandeur is the false belief that __________. a. one is being manipulated b. emphasizes self-importance c. emphasizes self-manipulation d. one is being harassed

Answers

The delusion of grandeur is a false belief that emphasizes self-importance. Option b is correct.

What are delusions?

Delusions are characterized as persistent, erroneous beliefs that contradict reality. A person in a delusional condition is unable to let go of their convictions, despite opposing facts.

Misinterpretation of circumstances frequently reinforces delusions. Many illusions are accompanied by some degree of paranoia.

One of the most prevalent is delusions of grandeur. It's when you imagine you have more power, riches, intelligence, or other great qualities than you actually do.

The delusion of grandeur is a false belief that emphasizes self-importance.

Hence option b is correct.

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Answer:

B. emphasizes self-importance

Explanation:

got it right on edge 2022

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