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Answer:

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Answer:

e. 5.6 x 10^21 electrons.

Explanation:

In order to calculate the charge Q passing through the resistor for in a definite amount of time is

[tex]Q \ (\mathrm{coulombs}) \ = \ I \ (\mathrm{amperes}) \ \times \ t \ (\mathrm{seconds}) \\ \\ \-\hspace{2.22cm} = \ 3.0 \ \mathrm{A} \ \times \ 5.0 \ \mathrm{min} \ \times \ \displaystyle\frac{60 \ \mathrm{sec}}{1 \ \mathrm{min}} \\ \\ \-\hspace{2.22cm} = \ 900 \ \mathrm{C}[/tex]

Thus, using the law of quantization of electric charge, the number of electrons passing through the resistor during this time interval can be calculated.

[tex]Q \ = \ n \times e \\ \\ n \-\hspace{0.18cm} = \ \displaystyle\frac{Q}{e} \\ \\ n \-\hspace{0.18cm} = \displaystyle\frac{900 \ \mathrm{C}}{1.6 \times 10^{-19} \ \mathrm{C}} \\ \\ n \-\hspace{0.18cm} = 5.6 \times 10^{21} \ \ \mathrm{electrons}[/tex], where n denotes the number of electrons and e is the unit charge of an electron ([tex]1.6 \times 10^{-19} \ \mathrm{C}[/tex]).

Answer:

Explanation:

if you are pulling in the positive direction and Upward is also positive.

F = -0.96i + 0.58(9.8)j

F = -0.96i + 5.7j

F = √(-0.96² + 5.7²) = 5.8 N

You are pulling a sled with constant velocity by using a rope then the surface force the ground exerts on the sled will be 5.8 N.

The pulling force conveyed axially by a string, cable, chain, or another analogous object, or by either end of a rod, truss member, or another such three-dimensional object, is referred to as tension in physics. Another way to think of tension is as the action-reaction pair of forces acting at each end of the previous elements. Perhaps tension is the polar opposite of compression.

A restoring force may cause what is also referred to as tension when atoms or molecules are torn apart from one another at the atomic level and build up potential energy.

If you are moving upward and pushing in a positive way,

F = -0.96 i + 0.58(9.8) j

F = -0.96 i + 5.7 j

F = [tex]\sqrt{(-0.96^2 + 5.7^2)}[/tex]

F= 5.8 N

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Answer:

41.6m/s

Explanation:

P=mv

2500kg × 25m/s = 62500kgm/s

62500kgm/s ÷ 1500 kg = 41.6m/s

The total charge in this time is equal to 144 Coulomb.

Given the following data:

To calculate the total charge in this time:

First of all, we would convert the value of time in minutes to seconds.

Conversion:

1 minute = 60 seconds

3 minutes = 180 seconds

Mathematically, the quantity of charge is given by this formula:

[tex]Q=It[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]Q = 0.8 \times 180[/tex]

Quantity of charge, Q = 144 Coulomb.

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Answer:

960 watts

Explanation:

The symmetry operations of molecule AB₄ is tetrahedral  and they are :

To find the multiplication table we have to apply the multiplication table for Td symmetry ( attached below )

Given that molecule B lies at the corners of the square and molecule A lie at the center and is not coplanar with molecule B the symmetry operations of the molecules AB₄ will belong to a tetrahedral symmetry group which contains :

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Answer:

from someone watching the bulldozer from the cab of the truck or from elsewhere on the flatbed.

Explanation:

Answer:

1. D electron cloud

2. A nucleus

3. E electron

4. B neutron

5. C proton

Explanation:

electrons are located outside the nucleus. The nucleus holds the protons and neutrons. Protons have a positive symbol (+). electron cloud holds the electrons.

Explanation:

Electron cloud : D

Nucleus : A

Electron : E

Neutron : B

Proton : C

hope this helps you.

Answer:

Explanation:

Work is the area under the curve between the limits

W = ½(5)(8 - 5) = 7.5 J

The work done when an object moves from 5 m to 8 m is 7.5 J.

The work done in moving an object from one point to another is equal to the product of force and displacement of the object.

W = Fs

The work done on an object is equal to area under the curve

The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J

Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.

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Answer:

Water speed Plays a key role In determining The shape of it

Assuming each trial represents 1000years, and rock samples were found, the rock sample will be given half-life of

We know that the parent Isotope remaining is given by the expression

[tex]\frac{1}{2}^n[/tex]

where,

n = number of half lives passed

From the question, the parent Isotope remaining is [tex]25\%[/tex] lokium

[tex]0.25 = \frac{1}{4} = \frac{1}{2^2} = \frac{1}{2}^2[/tex]

Therefore,

[tex]\frac{1}{2}^2[/tex] means 2 half lives have passed.

If from the question,

1 half life = 1000years

Therefore,

The rock sample's age = [tex]2*1000 = 2000years[/tex]

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Answer:

the movement of snail on the ground is in random motion.

the strings of the guitar is in oscillatory motion.

the whirling of stone tied with a thread is in circular motion.

Answer:

Explanation:

F = GMm/d²

F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²

F = 5.5019685...x 10⁻¹⁰ N

round as appropriate, probably no more than 3 significant figures.

Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹

Answer:

Explanation:

The degree of hotness and coldness of air is known as temperature and is measured with a thermometer in degrees-Fahrenheit or degrees-Celsius. Mercury is the only one in the liquid state at room temperature. It is used in thermometers because it has a high coefficient of expansion. The flow of heat will be always from higher to lower temperature.

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Answer:

The main condition necessary for a controlled thermonuclear fusion:

The ions must be held together in close proximity at high temperature with a confinement time long enough to avoid cooling.

The ball was kicked with a speed of 38.4 m/s.

Using s = ut + 1/2gt², we find the time it takes the ball to reach the ground. Where

Substituting the values of the variables into the equation, we have

s = ut + 1/2gt²

75 m = (0 m/s)t + 1/2 × 9.8 m/s² × t²

75 m = 0 m + (4.9 m/s²) t²

75 m = (4.9 m/s²)t²

Dividing both sides by 4.9, we have

t² = 75 m/4.9 m/s²

t² = 15.306 s²

Taking square-root of both sides, we have

t = √15.306 s²

t = 3.91 s

The horizontal distance covered by the ball d = vt where

Since we require v, we make it subject of the formula.

So, v = d/t

Given that d = 150 m and t = 3.91 s, substituting these into v, we have

v = d/t

v = 150 m/3.91 s

v = 38.4 m/s

So, the ball was kicked with a speed of 38.4 m/s.

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Answer:

force is simply a push or a pull in a particular direction. The unit is N (newton)

Explanation:

hope this helped

Answer:

In physics force is an influence which changes the motion of an object which has mass

Its unit is N or kgms/2

Answer:

b rugby and basketball

Explanation:

basket ball was made by a white man

American Football originated from Soccer and Rugby. Hence, option (A) is correct.

American football, sometimes known as gridiron, is a team sport played by two teams of eleven players on a rectangular field with goalposts at each end. It is known simply as football in the United States and Canada. The defense, the team without the ball, seeks to halt the offense's movement and seize control of the ball for themselves.

The offence, the team in possession of the oval-shaped football, attempts to advance down the field by running with the ball or throwing it. The offence is awarded a new set of four downs to resume the drive if they successfully gain at least 10 yards in four downs or plays. If they fail, they forfeit the ball to the defense.

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Answer:

The net force on the hanging mass is thus

2 T Mg     18 6.6 N 11.4 N

, enough to accelerate it upward at

17 m/s2

. The angular acceleration of the pulley is thus

   

2 2

Explanation:

The tension in the rope on both sides of the pulley 20.21N.

To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:

(a) Is the tension in the rope the same on both sides of the pulley?

No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.

(b) Find the tension in the rope on both sides of the pulley:

Calculate the gravitational force on each mass:

Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).

Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.

Calculate the net force on the pulley:

Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.

Apply Newton's second law to the pulley:

For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.

Use the relationship between linear acceleration and angular acceleration:

α = a / r.

Equate the torque due to the tension to the moment of inertia times the angular acceleration:

τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.

Substitute the expression for α and solve for the net tension:

Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).

Now, substitute the expression for a from step 3 and solve for the net tension:

Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).

Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:

Tnet = (1/2 * Fnet).

Now, you can find the tensions on each side of the pulley:

Tleft = Tnet + Fhanging

Tright = Tnet - Fpulle

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Answer:

I believe The Knowledge that we apply everyday or based on these methods and discoveries may represent us

Explanation:

The magnitude of the potential difference between the two points is 840 V

To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.

Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, The magnitude of the potential difference between the two points is 840 V

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The speed of the block at point B = 6.36 m/s

Given data :

Mass ( m ) = 10 kg

Angle of inclination ( θ ) = 30°

Length of incline = 5 m

Determine the speed of the block at a point B on the incline

First step : Calculate the work done by frictional force

given that there is no friction on the horizontal plane. Vinclined = Vhorizontal

∴ Work done by frictional force ( Wf ) = F * L cos 180

                                                              = - ( μ_k * N ) L

                                                              = - (0.1 * 84.86   ) * 5  = - 42.4 Joule

where N = mg cos 30°

              = 10 * 9.8 * 0.866 = 84.86

Next step : Calculate the speed of the block at point B

applying work energy theorem

Wf = ΔK.E + ΔP.E

     = ( 1/2 mv² - 0 ) + ( 0 - mgh )

∴ - 42.48  = 1/2 mv² - mgh

1/2 mv² = mgh - 42.48

            = 10 * 9.8 * 5 sin 30° - 42.4

       v²  = 40.52

V ( speed of the block at point B ) = 6.36 m/s

Hence we can conclude that the speed of the block at point B = 6.36 m/s

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Attached below is the complete question related to your question

Answer:

Explanation:

ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted

½mv² = mgh

v = √(2gh)

v = √(2(9.81)2.1) = 6.4188... m/s

after impact, an impulse will result in a change of momentum.

There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.

FΔt = mΔv

(F - mg)Δt = m(vf - vi)

(F - mg) = m(vf - vi)/Δt

F = m(vf - vi)/Δt + mg

F = m((vf - vi)/Δt + g)

F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)

F = 12.14198...

F = 12.1 N

The magnitude of the average force the stone experiences, will be 12.1 N.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The given data in the problem is;

m is the stone mass = 1.05 kg

The height is h, = 2.1 m i

The time is, t = 1.83 s

Velocity decreased by 50%.

From the law of conservation of energy the kinetic energy is equal to the potential energy;

[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]

From Newton's second law of motion, the impulsive force is equal to the change in momentum;

[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]

Hence the magnitude of the average force the stone experiences, will be 12.1 N.

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Explanation:

1) If you spot something you think might be hazardous in your workplace, report it to your employer and safety rep straight away. Your employer should then decide what harm the hazard could cause and take action to eliminate, prevent or reduce that harm. Read more about risk assessments .

2) Complex hazards are understood as various combinations of sources of hazards that lead to the accident occurrences. ... The term "natural-technological" applies to both human-induced intensification of natural risks and any accidents in the technosphere triggered by natural processes or phenomena.

3)Risk Evaluation : To determine who may be harmed. Risk Control : Taking preventive measures to control the impact of risk.

In general, to do an assessment, you should:

Identify hazards.

Determine the likelihood of harm, such as an injury or illness occurring, and its severity. ...

Identify actions necessary to eliminate the hazard, or control the risk using the hierarchy of risk control methods.

Answer:

Instrumental error

Environmental error

Observational error

Theoritical error

Option B is correct.Increasing the distance between the particles by a factor of 3 decrease the force between two charged particles by a factor of 9.

The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.

The electric force is found as;

[tex]\rm F = \frac{K q_1q_2}{r^2}[/tex]

The electric force between the two charges is directly proportional to the product of the charge.

The electric force is inversely proportional to the square of the distance between them.

Increasing the distance between the particles by a factor of 3 decreases the force between two charged particles by a factor of 9

Hence, option B is correct.

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Answer:

HENCE, THE ANSWER IS A. :)

Explanation:

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Answer:

Explanation:

Is it a 30 kg ball or a 3 kg ball?

Does not matter as we don't have to do actual calculations

If all of the momentum is transferred out of a mass, the velocity remaining must be ZERO

Answer:

18375g

Explanation:

[tex]\boxed{density = \frac{mass}{volume} }[/tex]

[tex]∴ mass = density \times volume[/tex]

Let's find the volume of the rectangular block.

Volume

= length ×breadth ×height

= 3.5 ×6 ×2.5

= 52.5cm³

Mass of the block

= 350(52.5)

= 18375g

Answer:

Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.

Explanation: