plsss help 6th grade math

Answer:

4

Step-by-step explanation:

because 2+2+2+2=8 pretty self explanatory

Answer:

13

Step-by-step explanation:

Answer: 325

Explanation:

Let the number of adult tickets be x

( since there are an unknown amount of tickets for adults, we already know how many student tickets there are)

Let the number of student tickets be x+60

710=x+x+60

710=2x+60

 -60        -60

650=2x

650/2

= 325

Adult tickets=325

Student tickets=385

The required value of  θ  for the trigonometric function cos(θ)=sin(θ/3-10) is 60°.

The  basic Trigonometric functions are sine, cosine, tangent, secant, cosecant and cotangent.

The given equation is,

cos(θ)=sin(θ/3-10)          (1)

To find the value of θ,

Change the whole equation into one trigonometric function,

Since, cos(θ)=sin(90-θ)

Substitute this value in equation (1)

sin(90-θ)=sin(θ/3-10)

⇒90-θ=θ/3-10

⇒4θ/3=80

⇒θ=60

The value of θ is 60°.

To know more about Trigonometric Function on:

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Answer:

30 and 8

Step-by-step explanation:

30 - 8 = 22

Answer:y = -0.6x + 5

Step-by-step explanation:

Answer:

yessir the one on top is right btw

Step-by-step explanation:

hope this helped

Answer:

18 MARK AS BRAINLIEST OR ELSE!!!!

Step-by-step explanation:

area = 1/2h(sum of bases)

area = 1/2x3(3+9)

area = 1/2 of 36

area = 18

Answer: 15

Step-by-step explanation: 5/6 times 18 = 15 hours

Answer:

f(3)= 4

Step-by-step explanation:

x= -3=0

x= 3

f(3)=(3+3)-2

f(3)= 6-2

f(3)= 4

Answer:

(x − π)⁷ / 5040

(x − 1)³ / 16

Step-by-step explanation:

Taylor series expansion of a function is:

f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(x₀) / n! (x − x₀)ⁿ

where f⁽ⁿ⁾(x₀) is the nth derivative evaluated at x₀.

For the first problem, f(x) = sin x and x₀ = π.  We want the seventh degree term, so n = 7.

The seventh degree term is therefore: f⁽⁷⁾(π) / 7! (x − π)⁷

Find the seventh derivative of sin x:

f(x) = sin x

f⁽¹⁾(x) = cos x

f⁽²⁾(x) = -sin x

f⁽³⁾(x) = -cos x

f⁽⁴⁾(x) = sin x

f⁽⁵⁾(x) = cos x

f⁽⁶⁾(x) = -sin x

f⁽⁷⁾(x) = -cos x

Evaluated at π, f⁽⁷⁾(x) = 1.  So the seventh degree term is (x − π)⁷ / 5040.

For the second problem, f(x) = √x and x₀ = 1.  We want the third degree term,  so n = 3.

The third degree term is therefore: f⁽³⁾(1) / 3! (x − 1)³

Find the third derivative of √x:

f(x) = √x

f⁽¹⁾(x) = ½ x^-½

f⁽²⁾(x) = -¼ x^-³/₂

f⁽³⁾(x) = ⅜ x^-⁵/₂

Evaluated at 1, f⁽³⁾(x) = ⅜.  So the third degree term is (x − 1)³ / 16.

Answer:

Exact form: x = [tex]\frac{10.8}{sin(57)}[/tex]

Rounded to the Nearest Tenth: x = 12.9

Step-by-step explanation:

In the right-angled triangle, we can use the trigonometry functions to find the length of a side or a measure of an angle

In the given figure

∵ ∠C is the right angle

∴ ΔACB is a right triangle

∵ m∠B = 57°

∵ AC = 10.8

∵ AC is the opposite side of ∠B

∵ AB is opposite to the right angle

∴ AB is the hypotenuse

∵ AB = x

→ We can use the function sine to find x

∵ sin∠B = [tex]\frac{opposite}{hypotenuse}[/tex]

∴ sin∠B = [tex]\frac{AC}{AB}[/tex]

→ Substitute the values of ∠B, AC, and AB in the rule of sine above

∴ sin(57°) = [tex]\frac{10.8}{x}[/tex]

→ By using cross multiplication

∵ x × sin(57°) = 10.8

→ Divide both sides by sin(57°)

∴ x = [tex]\frac{10.8}{sin(57)}[/tex]

∴ x = 12.87752356

→ Round your answer to the nearest tenth

∴ x = 12.9

Exact form: x = [tex]\frac{10.8}{sin(57)}[/tex]

Rounded to the Nearest Tenth: x = 12.9