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Research a type of plant tropism not presented in the lessons. Create a meme below that name and describes the tropism.

Answer:

-30°C = -22°F

-30°C = 243.15K

Explanation:

For converting Celsius to Fahrenheit, this is the equation-

(-30°C × 9/5) + 32 = -22°F

For converting Celsius to Kelvin, this is the equation-

-30°C + 273.15 = 243.15K

Answer:

all living organisms have cells fire does not

Answer:

it takes the train 1 hour and 75 minutes

Explanation:

you multiply the constant speed starting from 1 (which represents 1 hour) then you add as many decimal places as you need. Bit of a confusing explanation

Answer:

23936.5 N/m² or 23936.5 Pa

Explanation:

Unit conversion

Our dimensions

Solving

Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.

According to Arrhenius, a base is a species that releases OH⁻ ions in an aqueous medium.

Let's consider the basic reaction of NaOH.

NaOH(s) ⇒ Na⁺(aq) + OH⁻(aq)

NaOH is a strong base. This means that the concentration of OH⁻ will be equal to the initial concentration of NaOH, i.e. 3.0 × 10⁻³ M.

Then, we can calculate the pOH of the NaOH solution using the following expression.

pOH = -log [OH⁻] = -log 3.0 × 10⁻³ = 2.5

Sodium hydroxide is a soluble strong base. The pOH of a 3.0 × 10⁻³ M-sodium hydroxide solution is 2.5.

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Answer:2.5

Explanation:

Answer:The answer is B and CCC

Explanation:

Out of the given chemical changes, the two reactions which are faster are those mentioned in B and C as formation of rust and tarnishing of silver are slow reactions.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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Answer:

Heat or Enthalpy of reaction

Answer:

Partial pressure of carbon dioxide is high in the pulmonary capillaries.

Explanation:

Answer:

1.46 M

Explanation:

[A]t=−(0.0416 M/min) x (20.0 min)+2.29 M

[A]t=1.46 M

Answer:

Here all the given options are examples of complex carbohydrates.

Explanation:

As all these contains sugar, starch and fibre.

If the colored spheres are solutes, the overall direction of water would be out of the cell based on the principle of osmosis.

It is the movement of water molecules from the region of high water potential (low solutes) to the region of low water potential (high solute) through a selectively permeable membrane.

In the illustration, there are more colored spheres outside of the cell than inside of it. This means that there are more solutes outside the cell (lower water potential) than inside of the cell (higher water potential).

Thus, water will move from the inside of the cell to the outside until an equilibrium is established.

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Answer:

Light is a transverse wave.

Explanation:

Light waves are not considered mechanical waves because they don't involve the motion of matter. Most of the mathematics and properties of mechanical waves apply to light waves. Light waves are different from mechanical waves, however, because they can travel through a vacuum.

Explanation:

The difference between addition polymerization and condensation polymerization is that in addition polymerization the polymers are formed by the addition of monomers without any by-products whereas in condensation polymerization, the polymers are formed due to the condensation of more than one different monomers resulting in the formation of small molecules such as HCl, water, etc., as by-products.

a. For the given combination of reactants, the limiting reagents is F₂

b. The mass of HF that would be made is 106.65 g

From the question, we are to identify the limiting reagent and calculate the mass of HF made

First, we will write the balanced chemical equation for the reaction

3F₂ + NH₃ → 3HF + NF₃

This means 3 moles of F₂ reacts with 1 mole of NH₃ to produce 3 moles of HF and 1 mole of NF₃

From the given information,

We have 5.33 moles of F₂ and 2.22 moles of NH₃

Since,

3 moles of F₂ reacts with 1 mole of NH₃

Then,

5.33 moles of F₂ will react with 1.78 moles of NH₃

Therefore, NH₃ is in excess and F₂ is the limiting reagent

Hence, for the given combination of reactants, the limiting reagents is F₂

b. For the mass of HF that would be made

From the balanced chemical equation,

3 moles of F₂ reacts with 1 mole of NH₃ to produce 3 moles of HF

Then,

5.33 moles of F₂ will react with 1.78 moles of NH₃ to produce 5.33 moles of HF

Number of moles of HF produced = 5.33 moles

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of HF = 20.01 g/mol

∴ Mass of HF produced = 5.33 × 20.01

Mass of HF produced = 106.65 g

Hence, the mass of HF that would be made is 106.65 g

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Answer:

Keep the tap closed when not using it, and to not use it every day, like washing a car, you can clean it with a sponge and a bucket of water.

Explanation:

I don't know if this helps though.

Answer:

Approximately [tex]1.7\; {\rm L}[/tex].

Explanation:

Nitrogen [tex]{\rm N_{2}}\, (g)[/tex] reacts with hydrogen [tex]{\rm H_{2}}\, (g)[/tex] at a [tex]1:3[/tex] ratio to produce ammonia [tex]{\rm NH_3}\, (g)[/tex]:

[tex]{\rm N_{2}}\, (g) + 3\; {\rm H_{2}}\, (g) \to 2\; {\rm NH_{3}}\, (g)[/tex].

The ratio between the coefficient of [tex]{\rm N_{2}}\, (g)[/tex] and the coefficient of [tex]{\rm H_{2}}\, (g)[/tex] is:

[tex]\begin{aligned}\frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}[/tex].

Under the ideal gas assumptions, the same ratio would apply to the volume of [tex]{\rm N_{2}}\, (g)[/tex] and [tex]{\rm H_{2}}\, (g)[/tex] in this reaction:

[tex]\begin{aligned}\frac{V({\rm N_{2}})}{V({\rm H_{2}})} = \frac{n({\rm N_{2}})}{n({\rm H_{2}})} = \frac{1}{3}\end{aligned}[/tex].

[tex]\begin{aligned}V({\rm N_{2}})= \frac{1}{3}\, V({\rm H_{2}})\end{aligned}[/tex].

Given that [tex]V({\rm H_{2}}) = 5.0\; {\rm L}[/tex]:

[tex]\begin{aligned}V({\rm N_{2}}) &= \frac{1}{3}\, V({\rm H_{2}}) \\ &= \frac{1}{3}\times 5.0\; {\rm L} \\ &\approx 1.7\; {\rm L}\end{aligned}[/tex].

(Rounded to [tex]2[/tex] significant figures.)

Answer:

D

Explanation:

a. the mole of substance

b.a standard solution

in analytical chemistry standard solution is a solution containing a precisely known concentration of an element or a substance.

A known mass of solute is dissolved to make a specific volume. it is prepared using a standard solution,such as a primary standard.

hope this helps you

Answer:

great keep up the good work your teacher

mol = 0.75 L(750 ml) x 0.132 mol/L =0.099 mol

potassium carbonate: K₂CO₃ ⇒ MM = 138,205 g/mol

mass = 0.099 x 138.205 = 13.68 g

Answer:

B

Explanation:

Answer:

The correct answer is B.

They are structual isomers.

Answer:

Tundra :a vast, flat, treeless Arctic region of Europe, Asia, and North America in which the subsoil is permanently frozen.

Temperate grasslands are characterized as having grasses as the dominant vegetation.

Tropical rainforests are rainforests that occur in areas of tropical rainforest climate in which there is no dry season – all months have an average precipitation of at least 60 mm – and may also be referred to as lowland equatorial evergreen rainforest.

Answer:

10.77

Explanation:

The relationship between pH and pOH is

pH + pOH = 14

Plugging in the pOH makes

pH + 3.23 = 14

And solving for pH by subtracting 3.23 on both sides

pH = 10.77

Answer:

CO2 molecules don't really interact with sunlight's wavelengths. Only after the Earth absorbs sunlight and reemits the energy as infrared waves can the CO2 and other greenhouse gases absorb the energy.

Explanation:

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Carbon dioxide molecules don't directly react with the sunlight but they can absorb the energy in the form of infrared waves when it is emitted after reflection through the Earth's surface.

Infrared radiation (IR), sometimes referred to simply as infrared, is a region of the electromagnetic radiation spectrum where wavelengths range from about 700 nanometers (nm) to 1 millimeter (mm).

[tex]CO_2[/tex] molecules don't really interact with sunlight's wavelengths. Only after the Earth absorbs sunlight and reemits the energy as infrared waves can the [tex]CO_2[/tex] and some other greenhouse gases absorb the energy.

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765

Explanation:

C1V1=C2V2

10×85=1×V2

V2=850

V'=V2-V2

V'=850-85

V'=765ml

[tex] \text{V}_1 = 50 \text{ml }\\ \text{T}_1 = 200 \text{K} \\ \text{V}_2 = ? \\ \text{T}_2 = 400 \text{K}[/tex]

[tex] \text{The Value of V}_2[/tex]

[tex]\frac{ \text{V}_1}{ \text{T}_1} = \frac{ \text{V}_2}{ \text{T}_2}[/tex]

[tex] \frac{50}{200} =\frac{ \text{V}_2}{400} \\ \\ \fbox{cross multiplying} \\ \\ \implies 200 \times V_2 = 50 \times 400 \\ \\ \implies V_2 = \frac{50 \times 400}{200} \\ \\ \implies V_2 = \frac{50 \times \cancel{ 400} { \: \: \: }^{2} }{ \cancel{200}} \\ \\ \implies V_2 = 50 \times 2 \\ \\ \implies V_2 = 100[/tex]

[tex] \therefore \implies V_2 = 100 \text{ml}[/tex]

Answer:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

Explanation:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

An electromagnetic wave of a frequency between about [tex]10^4[/tex] and [tex]10^{11}[/tex]or [tex]10^{12}[/tex] Hz, as used for long-distance communication.

AM and FM Radio Broadcasting which involves transmitting sound to a wide audience.

Radar is a detection system that uses radio waves to get information about objects.

Bluetooth and wireless communication use radio waves to create connections between devices.

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