pls help me with Question B only​

Pls Help Me With Question B Only

Answers

Answer 1

a. The nth term of the sequence is  11 - 3n.

b. The nth term of the sequence is  14- 5n.

How to find the nth term of a sequence?

The sequence is an arithmetic progression. Therefore, the expression for the sequence can be represented as follows:

nth term = a + (n + 1)d

where

n = number of termsd = common differencea = first term

Therefore,

a.

a = 8

d = 11 - 8 = - 3

Therefore,

nth term = 8 + (n - 1)-3

nth term = 8  - 3n + 3

nth term = 11 - 3n

b.

a = 19

d = 14 - 19 = -5

nth term = 19 + (n - 1)-5

nth term = 19 - 5n - 5

nth term =  14 - 5n

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Related Questions

Find the distance between the two points rounding to the nearest tenth (if necessary). ( 8 , − 4 ) and ( − 1 , − 2 ) (8,−4) and (−1,−2)

Answers

Let help you with that.

To find the distance between two points, we can use the distance formula:

```

d = √(x2 - x1)2 + (y2 - y1)2

```

Where:

* `d` is the distance between the two points

* `x1` and `y1` are the coordinates of the first point

* `x2` and `y2` are the coordinates of the second point

In this case, the points are (8, -4) and (-1, -2):

```

d = √((8 - (-1))^2 + ((-4) - (-2))^2)

```

```

d = √(9^2 + (-2)^2)

```

```

d = √(81 + 4)

```

```

d = √85

```

```

d = 9.2 (rounded to the nearest tenth)

```

Therefore, the distance between the two points is 9.2 units.

Answer:

Step-by-step explanation:

whts the image of point A after it is dilated with a scale factor r=13 from center O .

Answers

The image of point A after it is dilated with a scale factor 3 is (6, 12)

Dilation is a transformation, which is used to resize the object.

A scale factor is when you enlarge a shape and each side is multiplied by the same number. This number is called the scale factor.

Let the coordinates of A are (2, 4)

We have to find the coordinates of point A after dilation with scale factor 3

A'=(3×2, 3×4)

=(6, 12)

Hence,  the image of point A after it is dilated with a scale factor 3 is (6, 12)

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(1 point) Use the ratio test to determine whether ? + 2 converges or diverges (a) Find the ratio of successive terms. Write your answer as a fully simplified fraction. For n 2 11. +! lim = lim 00 00 (b) Evaluate the limit in the previous part. Enter co as infinity and -20 as -infinity. If the limit does not exist, enter DNE. Lim a. (c) By the ratio test, does the series converge, diverge, or is the test Inconclusive? Choose 00 (1 point) For the following alternating series, Σα, = 0. 45 - (0. 45) (0. 45) (0. 45) 31 +. 5! 7! how many terms do you have to compute in order for your approximation your partial sum) to be within 0. 0000001 from the convergent value of that series?

Answers

To ensure that the error is less than 0.0000001, we need to compute at least the first 6 terms of the series. This will give us a partial sum that is within 0.0000001 of the actual sum.

(a) The ratio of successive terms of the series is:

[tex]|a[n+1]/a[n]| = |(-1)^(n+1)*(n+2)/(n+1)(1/2)|[/tex]

Simplifying this expression, we get:

[tex]|a[n+1]/a[n]| = (n+2)/(2(n+1))[/tex]

(b) To evaluate the limit of this expression as n approaches infinity, we can divide the numerator and denominator by n:

[tex]|a[n+1]/a[n]| = [(n/n)(1+2/n)] / [(2/n)(1+1/n)][/tex]

Taking the limit as n approaches infinity, we get:

[tex]lim n- > ∞ |a[n+1]/a[n]| = lim n- > ∞ [(n/n)(1+2/n)] / [(2/n)(1+1/n)[/tex]]

= 1/2

Therefore, the limit of the ratio of successive terms is 1/2.

(c) Since the limit of the ratio of successive terms is less than 1, by the ratio test, the series ? + 2 converges.

To approximate the alternating series Σα, = 0. 45 - (0. 45) (0. 45) (0. 45) 31 +. 5! 7! within 0.0000001 of the convergent value, we need to determine how many terms of the series we need to compute. We can use the alternating series error bound theorem to estimate the error:

|Rn| <= |an+1|

where Rn is the error term (the difference between the nth partial sum and the actual sum), and an+1 is the first neglected term in the series.

To find the first neglected term, we can look at the pattern of the series:

a0 = 0.45

a1 = -0.2025

a2 = 0.025641

a3 = -0.0007716

a4 = 0.00003857

a5 = -0.00000298

The absolute value of the terms is decreasing, so the error is bounded by the absolute value of the first neglected term. In this case, the first neglected term is a6 = 0.00000025.

Therefore, to ensure that the error is less than 0.0000001, we need to compute at least the first 6 terms of the series. This will give us a partial sum that is within 0.0000001 of the actual sum.

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The larger of two
complementary angles is
10 degrees more than the
smaller angle. What is the
degree measure of the
larger angle?

Answers

The degree measure of the larger angle is 50⁰.

What are complementary angles?

Complementary angles are two angles whose sum is 90 degrees.

So we have two angles; let the smaller angle = x

then bigger angle = (x + 10)

The two angles will add up to 90 degrees;

x + (x + 10) = 90

2x + 10 = 90

2x = 90 - 10

2x = 80

x = 80/2

x = 40⁰

The measure of the larger angle = 40⁰ + 10⁰ = 50⁰

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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
f(x) = x3eâ9x

Answers

To find the critical numbers of the function f(x) = x^3e^(-9x), we need to find the values of x where the derivative of the function is equal to zero or does not exist. These values correspond to the relative maxima, minima, or inflection points of the function.

To find the derivative of the function, we can use the product rule and the chain rule of differentiation. The derivative of f(x) is given by:

f'(x) = 3x^2e^(-9x) - 9x^3e^(-9x)

To find the critical numbers, we need to set f'(x) equal to zero and solve for x:

3x^2e^(-9x) - 9x^3e^(-9x) = 0

Factorizing out e^(-9x), we get:

3x^2 - 9x^3 = 0

Simplifying further, we get:

x^2(3 - 9x) = 0

Thus, the critical numbers of the function are x = 0 and x = 1/3. At x = 0, the function has a relative minimum, while at x = 1/3, the function has a relative maximum. To determine the nature of these critical points, we can use the second derivative test or examine the sign of the derivative in the intervals around the critical points.

Overall, finding the critical numbers of a function is an important step in analyzing its behavior and determining its extrema or points of inflection. By setting the derivative equal to zero and solving for x, we can identify the critical points and then use additional tests or analysis to determine their nature and significance.

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- Prices Shanes of company 9 of company on different days in a month were found to be 163 9163, 164, 164,1695, te 165, 169, 170, 171. Test whether the mean price of the shares in the moth is 165

Answers

Is not enough evidence to conclude that the mean price of the shares in the month is different from 165.

To test whether the mean price of the shares in the month is 165, we will perform a one-sample t-test.

The null hypothesis H0: μ = 165, where μ is the true population mean price of the shares in the month.

The alternative hypothesis Ha: μ ≠ 165.

We will use a significance level of α = 0.05.

First, we will calculate the sample mean and sample standard deviation:

sample mean (x) = (163 + 163 + 164 + 164 + 165 + 169 + 170 + 171) / 9 = 166.11

sample standard deviation (s) = √[((163-166.11)² + (163-166.11)² + (164-166.11)² + (164-166.11)² + (165-166.11)² + (169-166.11)² + (170-166.11)² + (171-166.11)²) / (9-1)] = 2.791

Next, we will calculate the t-statistic:

t = (x - μ) / (s / √n) = (166.11 - 165) / (2.791 / √9) = 1.441

Using a t-table or a calculator, we find that the p-value associated with a t-statistic of 1.441 and 8 degrees of freedom is approximately 0.186.

Since the p-value is greater than the significance level of 0.05, we fail to reject the null hypothesis. There is not enough evidence to conclude that the mean price of the shares in the month is different from 165.

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Willy the whale is 245 feet below sea level. He descends 83 feet, then he ascends 103 feet. Fill in the blanks below to create an equation to calculate his position relative to sea level. Then type your answer to that equation. Be sure to type the equation in the SAME ORDER that his movements are written above. DO NOT TYPE SPACES OR PARENTHESIS. Question Blank 1 of 4 type your answer... Question Blank 2 of 4 type your answer... Question Blank 3 of 4 type your answer... = Question Blank 4 of 4 type your answer... feet.

Answers

The equation that can be used to calculate Willy the whale's position relative to sea level.

Question Blank 1 of 4; -245, Question Blank 2 of 4; -83, Question Blank 3 of 4; +103, Question Blank 4 of 4; -225

What is the sea level?

The sea level is the level of the sea, which is taken as the zero mark on the number line.

The level of Willy the whale below sea level = 245 feet

The level Willy the whale descends = 83 feet

The level wheely the whale ascends = 103 feet

Therefore, the level to which Willy the whale starts = -245 feet

The level Willy the whale descends to = (-245 - 83) feet = -328 feet

The level to which Willy the whale then ascends to = -328 feet + 103 feet = -225 feet

The equation to calculate the position of Willy the whale is therefore;

-245 - 83 + 103 = -225

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what expression is equivalent to 9^-4

Answers

Answer:

1/6561

Step-by-Step Explanation:

you get 1/6561 when you simplify 9^-4

Factor. (6x+4)

A.2(3x+2)
B. 3x+2
C. 3(2x+1)
D. 2(x+2)

Answers

The factor of (6x+4) is 2(3x+2).

aki ola In the figure below AB=24cm,BD=17cm,AD=13cm and ACD=90Degrees. find CD

Answers

The Length of CD is 27.875 cm.

We have,

AB=24 cm, BD= 17 cm, AD = 13 cm

and, ACD=90Degrees

Using Pythagoras theorem

AD² = AC² + CD²

13² = AC² + (x-17)²

169 = AC² + x² + 289 - 34x

- x² + 34x - 120 = AC²

AC² = (x-4)(x-30)

Again,

AB² = AC² + CB²

24² = (x-4)(x-30) + x²

576 =  - x² + 34x - 120 + x²

34x = 696

x= 10.875

Thus, the length of CD is

= 10.875 + 17

= 37.875 cm

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Jax came to your bank to borrow 8,500 to start a new business. Your bank offers him a 30-month loan with an annual simple interest rate of 4.35%

Answers

The simple interest after 30 months is $924. 375

How to determine the simple interest

To determine the simple interest value, we need to know the formula for calculating it

The formula for simple interest is represented as;

S.I =PRT/100

The parameters of the equation are;

SI is the simple interest.P is the principal amount.R is the interest rate.T is the time taken

From the information given, we have;

Substitute the values

Simple interest = 8500 × 2.5 × 4.35/100

Multiply the values

Simple interest = 92437.5/100

Divide the values

Simple interest = $924. 375

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HELP ME PLEASEEEE!!!

Answers

1.
a: x = 1
b: (1, -7)
c: minimum
d: (0, -8)

2.
a: x = 2
b: (2, 16)
c: maximum
d: (0, 12)

(Competing patterns among coin flips) Suppose that Xn, n 2 1 are i.i.d. random variables with P(X1 = 1) = P(X1 = 0) = }. (These are just i.i.d. fair coin flips.) Let A = (a1, a2, a3) = (0,1, 1), B = (b1, b2, b3) = (0,0, 1). Let TA = min(n 2 3: {X,-2, Xn-1, Xn) = A} be the first time we see the sequence A appear among the X, random variables, and define Tg similarly for B. Find the probability that P(TA < TB). (This is the probability that THH shows up before TTH in a sequence of fair coin flips.)

Answers

The probability of A appearing before B is [tex]\frac{4}{7}[/tex].

To find the probability that TA < TB, we can use the fact that the probability of a certain pattern appearing in a sequence of coin flips is independent of the position in the sequence. In other words, the probability of A appearing at time n is the same as the probability of A appearing at time n+k for any k.

Using this fact, we can set up a system of equations to solve for the probability of TA < TB. Let p be the probability of A appearing before B, and q be the probability of B appearing before A. Then we have:

[tex]p = \frac{1}{2} + \frac{1}{2q}[/tex]  (since the first flip can be either 0 or 1 with equal probability)
[tex]q= \frac{1}{4p} + \frac{1}{2q} + \frac{1}{4}[/tex] (if the first two flips are 0, the sequence B has appeared; if the first flip is 1 and the second is 0, the sequence is neither A nor B and we start over; if the first flip is 1 and the second is 1, we have a new chance for A to appear before B)

Solving for p, we get:
[tex]p=\frac{4}{7}[/tex]

Therefore, the probability of A appearing before B is [tex]\frac{4}{7}[/tex].

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Sociologists say that 85% of married women claim that thee husband's mother is the biggest bune of contention in their marriages (sex and money are lower-rated areas of contention). Suppose that nine married women are having coffee together one morning. Find the following probabilities (for each arwat, enter a number. Round your sneware to three decimal places.)
(a) All of them dislike their mother-in-law.
(b) None of them dislike their mother-in-law.
(c) As dislike their mother-in-law
(d) No more than dk of them dalk their mother in law.

Answers

The probability that no more than 6 women dislike their mother-in-law is very low, at 0.00002

We can model the number of women who dislike their mother-in-law out of a sample of 9 married women using a binomial distribution with parameters n=9 and p=0.85.

(a)   [tex]P(all 9 women dislike their mother-in-law) = (0.85)^9 = 0.322[/tex]

(b) [tex]P(none of the 9 women dislike their mother-in-law) = (1-0.85)^9 = 0.0001[/tex]

(c) P(at least one woman dislikes her mother-in-law) = 1 - P(none of the 9 women dislike their mother-in-law) = 1 - 0.0001 = 0.9999

(d) P(no more than 6 women dislike their mother-in-law) = P(X <= 6) where X follows a binomial distribution with parameters n=9 and p=0.85. We can use a calculator or binomial distribution table to find:

P(X <= 6) = 0.00002

Therefore, the probability that no more than 6 women dislike their mother-in-law is very low, at 0.00002.

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ASAP PLSSS DUE TODAY I REALLY REALLY NEED HELP!!!!!!!!!!!!

1. A standard cereal box has roughly the following dimensions: 9 in. x 2 in. x 12 in. What is the volume of the box in cubic inches?
- 23
-216
-75
-144
-300

2. For the same cereal box with dimensions of 9 in. x 2 in. x 12 in, what is the surface area in square inches?
- 23
-216
-75
-144
-300
3. Calculate the cost of manufacturing this cereal box if cardboard costs $0.01 per square inch.
-3.00
- 2.16
- 0.75
- 1.44
- 2.86
4. A spherical container is designed to hold as much volume as the rectangular prism above. Its radius is 3.7 in. Find the surface area of the sphere rounded to the nearest square inch.
172 square inches
216 square inches
141 square inches
128 square inches
5. Using your answers from above, which design would cost less in packaging
The rectangular prism with dimensions of 9 in. x 2 in. x 12 in
the sphere with a radius of 3.7 in.
6. A family-size cereal box in the shape of a rectangular prism with dimensions of 13 in x 10 in x 3 in holds 390 cubic inches of cereal. If the packaging is redesigned to be a cylinder with a height of 5 inches, what would be the approximate radius so that it still holds the same volume of cereal?
7 inches
4 inches
6 inches
5 inches
7. A travel-size cereal box has dimensions of 3 in. x 1.5 in. x 4.5 in. If it is redesigned to be a cube with the same surface area, what would be the length of each side in the cube?
3.2 inches
6.4 inches
2.9 inches
2.2 inches
8. For the two designs in question #7, which one holds more volume?
the rectangular prism with dimensions of 3 in. x 1.5 in. x 4.5 in.
the cube with a side length from the answer in #7
9. What are some factors that a cereal company may consider in creating their packaging?
How well it stacks for shipping and storing on shelves
How easy it is to hold and pour
How much advertising space there is on the front of the design
All of the above

Answers

Volume of the box in cubic inches is B, 216surface area is D, 300 cost of manufacturing is A, 3.00.surface area of the sphere is A, 1729 in. x 2 in. x 12 in. would cost less in packaging.B, 4 inchesD, 2.2 inches.How to calculate volume and surface area?

1. The volume of the box is given by:

Volume = length x width x height = 9 in. x 2 in. x 12 in. = 216 cubic inches

So, the answer is 216 cubic inches.

2. The surface area of the box is given by:

Surface Area = 2lw + 2lh + 2wh = 2(9)(12) + 2(9)(2) + 2(2)(12) = 216 + 36 + 48 = 300 square inches

So, the answer is 300 square inches.

3. The surface area of the cereal box is 300 sq. in.

If cardboard costs $0.01 per square inch, then the cost of manufacturing this cereal box would be:

300 sq. in. x $0.01/sq. in. = $3.00

Therefore, the correct answer is -3.00.

4. The volume of the rectangular prism is given by:

Volume = length x width x height = 9 in. x 2 in. x 12 in. = 216 cubic inches

To find the surface area of the sphere, use the formula:

A = 4πr²

Plugging in r = 3.7 in.:

A = 4π(3.7 in.)² ≈ 172.11 square inches

Rounding this to the nearest square inch gives us:

A ≈ 172 square inches

5. The rectangular prism with dimensions of 9 in. x 2 in. x 12 in. would cost less in packaging.

6. The volume of the cylinder is given by:

Volume = πr²h = 390 cubic inches

Solving for r:

r ≈ 4 inches

Therefore, the approximate radius of the cylinder should be 4 inches to hold the same volume of cereal as the rectangular prism.

7. The surface area of the travel-size cereal box is given by:

Surface Area = 2lw + 2lh + 2wh = 2(3)(1.5) + 2(3)(4.5) + 2(1.5)(4.5) = 9 + 27 + 13.5 = 49.5 square inches

To find the length of each side in the cube with the same surface area, we use the formula:

Surface Area of Cube = 6s²

49.5 = 6s²

s ≈ 2.2 inches

So, the length of each side in the cube would be approximately 2.2 inches.

8. The rectangular prism with dimensions of 3 in. x 1.5 in. x 4.5 in. holds more volume than the cube with a side length of approximately 2.2 inches.

9. Some factors that a cereal company may consider in creating their packaging include how well it stacks for shipping and storing on shelves, how easy it is to hold and pour, and how much advertising space there is on the front of the design.

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Jonahs grandmother gave him $125 for his birthday. He used 14% of the money to buy Music on iTunes

Answers

Answer:

Jonah used $17.50 (14% of $125) to buy music on iTunes.

Step-by-step explanation:

Exercise 1. Consider a Bernoulli statistical model, where the probability of a success is the parameter of interest and there are n independent observations x = {21, ...,21} where xi = 1 with probability and Xi = 0) with probability 1-0. Define the hypotheses H. : 0 = 0, and HA: 0 = 0 A, and assume a = 0.05 and 0< 04. (a) Use Neyman-Pearson's lemma to define the rejection region of the type no > K (b) Let n = 20, 0o = 0.45, 0 A = 0.65 and 2-1 (i = 11. Decide whether or not H, should be rejected. Hint: use the fact that nX ~ Bin (n. 6) when Ii ind Bernoulli(). [5] 1 (c) Using the same values, calculate the p-value. [5] (d) What is the power of the test? (5) 回 (e) Show how the result in (a) can be used to find a test for H, : 0 = 0.45 versus HA: 0 > 0.45. [5] (f) Write down the power function as a function of the parameter of interest. [5] (g) Create an R function to calculate it and plot for 0 € [0,1]. [5]

Answers

(a) According to Neyman-Pearson's lemma, the rejection region of the type I error rate (α) for testing H0: θ = θ0 against HA: θ = θA, where θ0 < θA, is given by:

{X: f(x; θA) / f(x; θ0) > k}

where f(x; θ) is the probability mass function (PMF) of the distribution of the data, given the parameter θ, and k is chosen such that the type I error rate is α.

For this problem, we have H0: p = 0 and HA: p > 0.4, with α = 0.05. Therefore, we need to find the value of k such that P(X ∈ R | H0) = α, where R is the rejection region.

Using the fact that X follows a binomial distribution with n trials and success probability p, we have:

f(x; p) = (n choose x) * p^x * (1-p)^(n-x)

Then, the likelihood ratio is:

L(x) = f(x; pA) / f(x; p0) = (pA / p0)^x * (1-pA / 1-p0)^(n-x)

We want to find k such that:

P(X ∈ R | p = p0) = P(L(X) > k | p = p0) = α

Using the distribution of L(X) under H0, we have:

P(L(X) > k | p = p0) = P(X > k') = 1 - Φ(k')

where Φ is the cumulative distribution function (CDF) of a standard normal distribution, and k' is the value of k that satisfies:

(1 - pA / 1 - p0)^(n-x) = k'

k' can be found using the fact that X ~ Bin(n, p0) and P(X > k') = α, which yields:

k' = qbinom(α, n, 1-pA/1-p0)

Therefore, the rejection region R is given by:

R = {X: X > qbinom(α, n, 1-pA/1-p0)}

(b) We have n = 20, p0 = 0.45, pA = 0.65, and X = 11. Using the rejection region R defined in part (a), we have:

R = {X: X > qbinom(0.05, 20, 1-0.65/1-0.45)} = {X: X > 12}

Since X = 11 is not in R, we fail to reject H0 at the 5% level of significance.

(c) The p-value is the probability of observing a test statistic as extreme as the one computed from the data, assuming H0 is true. For this problem, the test statistic is X = 11, and we want to find the probability of observing a value as extreme or more extreme than 11, under the null hypothesis H0: p = 0. Using the binomial distribution with p = 0.45, we have:

p-value = P(X >= 11 | p = 0) = 1 - P(X <= 10 | p = 0)

= 1 - pbinom(10, 20, 0.45)

= 0.151

Therefore, the p-value is 0.151, which is greater than the level of significance α = 0.05, so we fail to reject H0.

Question 1: Prove that each of the following sets is compact by showing that they are closed and bounded. (a) A finite set {(1,..., an} CR. (b) The set {arctan(n): n E N} U{T/2}.

Answers

Both sets (a) and (b) are compact because they are closed and bounded.

To prove that each of the following sets is compact, we will show that they are both closed and bounded.

For set (a), which is a finite set {(a1, ..., an)} ⊂ R:

1. Closed: A finite set is closed because it contains all its limit points. In a finite set, every point is isolated, meaning that no point is a limit point. Therefore, the set is closed.
2. Bounded: Since the set is finite, we can find a minimum and a maximum value among its elements. By defining an interval [min, max], we can show that the set is bounded.

For set (b), which is the set {arctan(n): n ∈ N} ∪ {π/2}:

1. Closed: The set of arctan(n) has a limit point at π/2 as n approaches infinity. However, π/2 is included in the set, so it contains all its limit points and is closed.
2. Bounded: The arctan function has a horizontal asymptote at π/2 as n approaches infinity, and the minimum value of the set is arctan(1). Therefore, the set is bounded by the interval [arctan(1), π/2].

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Hi, can someone please help me with this math problem

Answers

D

3000000/60000=500

A magazine article reported that college students spend an average of $100 on a first date. A university sociologist believed that number was too high for the students at the university. The sociologist surveyed 32 randomly selected students from the university and obtained a sample mean of $92.23 for the most recent first dates. A one-sample -test resulted in a -value of 0.026. Which of the following is a correct interpretation of the -value? If the mean amount of money that students from the university spend on a first date is $100, the probability is 0.026 that a randomly selected group of 32 students from the university would spend a mean of $92.23 or less on their most recent first dates.

Answers

Answer:

If the mean amount of money that students from the university spend on a first date is $100, the probability is 0.026 that a randomly selected group of 32 students from the university would spend a mean of $92.23 or less on their most recent first dates.

Step-by-step explanation:

Edwin wrote the word MATHEMATICS on separate index cards. What is the probability of pulling out a “M” and then an “A”, If you do not replace the first letter?
Show all work.

Answers

So the chances of him pulling a M first is 2/11 if he pulls a M first the chances of him pulling a A is 2/10 or 1/5

(5 MARKS) Prove that F (c)(A + B) → (Vx) A (3.c)B. 4. (5 MARKS) All the sets in this problem are subsets of N. For any ACN, let us use the notation ADES N-A

Answers

To prove F(c)(A + B) → (Vx) A (3.c)B, we need to show that if the union of sets A and B is finite, then there exists an element x in A such that for all elements y in B, (x, y) is in the relation C.

Assume F(c)(A + B) is true. Then for any (x, y) in C, x belongs to A + B, which means x belongs to either A or B. If x belongs to A, then we have found an element x in A such that for all elements y in B, (x, y) is in C, and we are done. If x belongs to B, then we need to find another element in A such that the condition holds.

Since A and B are finite, their union A + B is also finite. Let n be the size of A + B. Then there are n distinct elements in A + B, say a1, a2, ..., an. Since there are more elements in A than in B (or equal if they have the same size), there must be at least one element of A among a1, a2, ..., an. Call this element x.

Now, consider any element y in B. Since x belongs to A + B and y belongs to B, their sum x + y belongs to A + B as well. But we know that x + y cannot be equal to x, since y is not in A. Therefore, x + y must be equal to one of the remaining n-1 elements of A + B, say ai. But then ai - x = y, so (x, y) is in C.

Therefore, we have shown that F(c)(A + B) → (Vx) A (3.c)B is true.

For the second part of the question, we need to show that for any set A in N, there exists a set B in N such that A is a subset of B and B is infinite.

Let B be the set of all natural numbers greater than the maximum element in A. Then A is clearly a subset of B, and B is infinite since it contains all natural numbers greater than a certain number.

Therefore, we have shown that for any set A in N, there exists a set B in N such that A is a subset of B and B is infinite.

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Mary earned the following test scores (out of 100 points) on the first four tests in her algebra class: 88 , 94 , 95 , and 92 . Her mean test score is 92.25 What score would Mary need to earn on the fifth test in order to raise her mean test score to 93 ?

Answers

Mary needs to score 96 on the fifth test to raise her average test score from 92.25 to 93.

Let's use the formula for the mean

mean = (sum of all scores) / (number of scores)

We can rearrange this formula to solve for the sum of all scores

sum of all scores = mean x number of scores

We know that Mary's mean test score is currently 92.25 and she has taken four tests, so

sum of all scores = 92.25 x 4 = 369

To raise her mean test score to 93, Mary needs the sum of all five test scores to be

sum of all scores = 93 x 5 = 465

To find out what score Mary needs to earn on the fifth test, we can subtract the sum of her first four test scores from the required sum of all five test scores

score on fifth test = sum of all five tests - sum of first four tests

score on fifth test = 465 - 369

score on fifth test = 96

Therefore, Mary needs to earn a score of 96 on the fifth test in order to raise her mean test score to 93.

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Write an equation of the perpendicular bisector of the segment with the endpoints (2,1) and (6,3)

Answers

Answer:

Step-by-step explanation:

Answer

Equation of a straight line

y = -0.33x + 4.995

Answer:

Step-by-step explanation:

Find the midpoint of the segment by using the formula [(x1 + x2)/2, (y1 + y2)/2]. The midpoint is [(2 + 6)/2, (1 + 3)/2] = (4, 2).

Find the slope of the segment by using the formula (y2 - y1)/(x2 - x1). The slope is (3 - 1)/(6 - 2) = 1/2.

Find the negative reciprocal of the slope by flipping the fraction and changing the sign. The negative reciprocal is -2/1 or -2.

Find the equation of the perpendicular bisector by using the point-slope form y - y1 = m(x - x1), where m is the negative reciprocal and (x1, y1) is the midpoint. The equation is y - 2 = -2(x - 4).

Simplify the equation by distributing and rearranging. The equation is y = -2x + 10. This is the equation of the perpendicular bisector in slope-intercept form.

dude someone hurry up and help please

Answers

The proportion that can be used to find the length of the side y for the similar triangle DEF is y/16 = 38/32, which makes option C correct.

What are similar triangles

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

The side DE corresponds to AB, also the side DF corresponds to AC, so;

DE/AB = DF/AC

y/38 = 16/32

by cross multiplication;

y/16 = 38/32

Therefore, the proportion that can be used to find the length of the side y for the similar triangle DEF is y/16 = 38/32.

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Student's Practice Question 2012
2. If |=|≤1, determine the maximum modulus (=) max
(a) ƒ(=)=z²-2=+3, (b) ƒ(z) =z²+= −1, (c) ƒ (z) z+1/2z-1 (d) cos(z)

Answers

The maximum modulus is the maximum value of |z| within the given domain.

To find the maximum modulus, we need to find the point(s) within the unit circle where the modulus is the highest.

(a) ƒ(z) = z² - 2z + 3

We can write ƒ(z) as ƒ(z) = (z - 1)² + 2, which is a parabola that opens upwards. The maximum modulus occurs at the vertex, which is located at z = 1, and the maximum modulus is ƒ(1) = 2.

(b) ƒ(z) = z² + z - 1

We can write ƒ(z) as ƒ(z) = (z + 1/2)² - 5/4, which is a parabola that opens upwards. The maximum modulus occurs at the vertex, which is located at z = -1/2, and the maximum modulus is ƒ(-1/2) = 1/4.

(c) ƒ(z) = (z + 1)/(2z - 2)

We can write ƒ(z) as ƒ(z) = 1/2 + 3/(2z - 2), which is a hyperbola that opens downwards. The maximum modulus occurs at the point where the real part of z is 1/2, and the imaginary part of z is 0, which is located at z = 1. The maximum modulus is ƒ(1) = 2.

(d) ƒ(z) = cos(z)

The maximum modulus of cos(z) occurs at z = 0 or z = π, where the modulus is 1.

Therefore, the maximum modulus for each function is:

(a) 2

(b) 1/4

(c) 2

(d) 1

Note: The modulus of a complex number z is defined as |z| = sqrt(x^2 + y^2), where x and y are the real and imaginary parts of z, respectively. The maximum modulus is the maximum value of |z| within the given domain.

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find the GCF of the following two monomials: 20xyz, 30x^2z
i need an answer asap ​

Answers

The GCF of 20xyz and 30x^2z is: 2*5*x*z = 10xz

How to find the GCF of the following two monomials: 20xyz, 30x^2z

To find the greatest common factor (GCF) of 20xyz and 30x^2z, we can factor out the common factors that they share.

Identifying the common factors in the two monomials:

20xyz = 2 * 2 * 5 * x * y * z

30x^2z = 2 * 3 * 5 * x * x * z

The GCF is the product of the common factors raised to the lowest power that they appear in both monomials.

Therefore, the GCF of 20xyz and 30x^2z is:

2 * 5 * x * z = 10xz

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Jaydin set a reading goal for the summer. She will read 25 pages on the first day. Each of the
following days, she reads 7 more pages than she read on the previous day.
Which equation best represents the number of pages she will read on day n?

Answers

The only way I could see the picture of
We know that Jaydin reads 25 pages on the first day. On the second day, she reads 7 more pages than she read on the first day, which is 25 + 7 = 32 pages. On the third day, she reads 7 more pages than she read on the second day, which is 32 + 7 = 39 pages. We can see that the number of pages she reads each day is increasing by 7.

Therefore, the equation that represents the number of pages Jaydin will read on day n is:

y = 25 + 7(n - 1)

Simplifying the equation, we get:

y = 7n + 18

So, the equation that best represents the number of pages Jaydin will read on day n is y = 7n + 18.

using the digits 1-6, at most one time each, crrate an exponential function of base e whose derivative at x=3 is 2using the digits 1-6, at most one time each, create an exponential function of base e whose derivative at x=3 is 2y=e^(ax-b)

Answers

The exponential function of base e whose derivative at x=3 is 2y=e^(ax-b) is y = e^(4x - 5).

To create an exponential function of base e using the digits 1-6 at most one time each, with the condition that its derivative at x=3 is 2.

Given the function y = e^(ax-b), let's find its derivative:

1. Differentiate the function with respect to x: dy/dx = a * e^(ax-b)
2. Plug in x = 3 and set dy/dx = 2: 2 = a * e^(3a-b)

Now, we need to find the values of a and b using the digits 1-6, at most one time each. Let's use a = 4 and b = 5, as they seem reasonable and satisfy the single-use condition:

2 = 4 * e^(12 - 5)
2 = 4 * e^7

Now divide both sides by 4:
2/4 = e^7
1/2 = e^7

So, our exponential function using the digits 1-6 at most one time each and satisfying the given condition is                    y = e^(4x - 5).

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Question 5: ( 10 +2 +4 +4 marks ) a. Consider the parabola f(x) = x2 - 4x +3
i) Write the equation in vertex form.
ii) Find the vertex and axis of symmetry. iii) Find the x-intercept and the y-intercept
b.write the quadratic functiion for the parabola that has vertex (-3,2) and passes through (1,4)

Answers

i) The equation in vertex form is f(x) = (x - 2)² - 1.

ii) The vertex of the parabola is (2, -1).

iii)The x-intercepts are (1, 0) and (3, 0) and the y-intercept is (0, 3).

b. The quadratic function is: f(x) = (1/8)(x + 3)² + 2.

Quadratic functions and parabolas:

A quadratic function is a function of form f(x) = ax² + bx + c, where a, b, and c are constants and a ≠ 0. The graph of a quadratic function is a U-shaped curve called a parabola.

The vertex of a parabola is the point where the parabola changes direction. It lies on the axis of symmetry, which is a vertical line that divides the parabola into two equal halves.

Here we have

The parabola f(x) = x² - 4x +3

a. Consider the parabola f(x) = x^2 - 4x + 3

i) To write the equation in vertex form, we complete the square:

f(x) = x² - 4x + 3

= (x² - 4x + 4) - 1

= (x - 2)² - 1

Therefore, the equation in vertex form is f(x) = (x - 2)² - 1.

ii) The vertex of the parabola is (2, -1). The axis of symmetry is the vertical line passing through the vertex, which is x = 2.

iii) To find the x-intercepts, we set f(x) = 0:

(x - 2)² - 1 = 0

(x - 2)² = 1

x - 2 = ±1

x = 1, 3

Therefore, the x-intercepts are (1, 0) and (3, 0).

To find the y-intercept, we set x = 0:

f(0) = 0² - 4(0) + 3 = 3

Therefore, the y-intercept is (0, 3).

b. To write the quadratic function for the parabola that has vertex (-3, 2) and passes through (1, 4), we use the vertex form of the quadratic equation:

f(x) = a(x - h)² + k,

where (h, k) is the vertex.

Substituting the given values, we get:

f(x) = a(x + 3)² + 2

To find the value of a, we substitute the point (1, 4) into the equation:

4 = a(1 + 3)² + 2

2 = 16a

a = 1/8

Therefore,

i) The equation in vertex form is f(x) = (x - 2)² - 1.

ii) The vertex of the parabola is (2, -1).

iii)The x-intercepts are (1, 0) and (3, 0) and the y-intercept is (0, 3).

b. The quadratic function is: f(x) = (1/8)(x + 3)² + 2.

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A.i. The equation in vertex form is f(x) = (x - 2)² - 1.

ii. The axis of symmetry is the vertical line passing through the vertex, which is x = 2.

iii. The x-intercepts are x = 1 and x = 3. The y-intercept is y = 3.

B. The quadratic function for the parabola is:

f(x) = (1/8)(x + 3)^2 + 2.

How did we arrive at these values?

a.

i) To write the equation in vertex form, we need to complete the square. The general vertex form of a parabola is given by f(x) = a(x - h)² + k, where (h, k) represents the vertex.

Let's complete the square for the given parabola f(x) = x² - 4x + 3:

f(x) = x² - 4x + 3

= (x² - 4x + 4) - 4 + 3 [Adding and subtracting (4/2)² = 4 to complete the square]

= (x - 2)² - 1

So, the equation in vertex form is f(x) = (x - 2)² - 1.

ii) Comparing the equation f(x) = (x - 2)² - 1 with the vertex form f(x) = a(x - h)² + k, we can see that the vertex is (h, k) = (2, -1). The axis of symmetry is the vertical line passing through the vertex, which is x = 2.

iii) To find the x-intercepts, set f(x) = 0 and solve for x:

(x - 2)² - 1 = 0

(x - 2)² = 1

x - 2 = ±√1

x - 2 = ±1

x = 2 ± 1

So, the x-intercepts are x = 1 and x = 3.

To find the y-intercept, set x = 0 in the equation:

f(0) = (0 - 2)² - 1

= (-2)² - 1

= 4 - 1

= 3

So, the y-intercept is y = 3.

b.

To write the quadratic function for the parabola with a vertex at (-3, 2) and passing through (1, 4), use the vertex form of a parabola.

The vertex form of a parabola is f(x) = a(x - h)² + k, where (h, k) represents the vertex.

Using the given vertex (-3, 2):

h = -3 and k = 2.

Substituting the values of h and k:

f(x) = a(x - (-3))² + 2

= a(x + 3)² + 2

Now, use the point (1, 4) to find the value of 'a'.

Substituting x = 1 and f(x) = 4 in the equation:

4 = a(1 + 3)² + 2

4 = a(4²) + 2

4 = 16a + 2

16a = 4 - 2

16a = 2

a = 2/16

a = 1/8

Therefore, the quadratic function for the parabola is: f(x) = (1/8)(x + 3)² + 2.

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