Answer:
it would have to be diagram C OR B
A student wishes to conduct an investigation on heat transfer that demonstrates convection, Which
method should the student use?
A.
Pour hot, colored water into a bowl of cooler water that is another color,
B.
Melt chocolate bars in a microwave at different settings,
C.
Leave a glass of ice water outside in the direct sunshine.
D.
Place a spoon that is room temperature on top of a hot burner on a stove,
Place the location of a watermelon in order from most to least potential energy.
aboard a flying airplane
2
on a roof
3
above a refrigerator
4
on the ground
5
on top of a table
it would be on the ground
What is the difference between distance and position?
Explanation:
HERE you go. hope this helps.
A 2000 kg truck and a 500 kg car are racing. The same amount of force is applied to each of them,
Answer:
Hh
Explanation:
Ghhhh
A car speeds up from 0.00 m/s to 60.0
m/s in 8.53 s.
The acceleration of the car is:
A. 512 m/s2
B. 8.53 m/s2
C. 68.5 m/s2
D. 7.03 m/s2
part 1 of 2
Bill kicks a rock off the top of his apartment
building. It strikes a window across the street
18 m away.
The acceleration of gravity is 9.8 m/s?.
If the window is 19 m below the position
where Bill contacted the rock, how long was
it in the air?
Answer in units of s.
part 2 of 2
How fast was it moving when it left Bill's
foot?
Answer in units of m/s.
Answer:
I got you.. i'm in middle school and had that same question.
Explanation:
Refer to the diagram shown below.
The vertical distance traveled is
s = 25 m
The initial vertical launch velocity is zero.
Therefore
s = (1/2)*g*t²
where g = 9.8 m/s²
t = the time of flight, s
That is,
0.5*9.8*t² = 25
t² = 25/4.9 = 5.102
t = 2.26 s
Answer: 2.26 s
What is Latin word for "little lumps?"
Answer:
tura paulo
Explanation:
sry if im wrong ;)
Under what circumstances will the distance traveled by an object be the same as the magnitude of the displacement of an object?
what do electrons move from
Answer:
Negatively charged, to positively charged parts
Explanation:
Electrons are negative, negative is attracted to positive.
Which object might have the pattern of magnetic domains shown in the
image?
114 114
114 114
11 11
A. Cotton fabric near a magnet
O B. A piece of iron, not near a magnet
O C. A piece of iron near a magnet
D. Cotton fabric, not near a magnet
Answer: a piece of iron near a magnet
Explanation:
change the following to celisus
a.-400f b.800f
please its urgent i will give u brainliest
A crane lifts a 75kg mass a height of 8 m. Calculate the gravitational potential energy gained by the mass (g = 9.8 N/kg.
A 8,000 kg amazon truck carrying a 3000 kg package is moving at 20 m/s along a level road as shown to the left. The driver applies the brakes to slow down. The truck travels 50 meters while applying the brakes for 3.0 seconds. The package does not slide on the back of the truck. a) Calculate the rate of acceleration b) Calculate the minimum coefficient of friction between packages and the truck
Answer:
(a) -6.67 [tex]m/s^2[/tex]
(b) 0.68
Explanation:
Given that the mass of the truck, [tex]m_1=8000[/tex] kg.
Mass of the package, [tex]m_2=3000[/tex] kg.
As the package does not slide, so the acceleration of both, truck as well as the package, is the same.
Let [tex]a\;\; m/s^2[/tex] is the acceleration of the combined mass, m.
[tex]m=m_1+m_2= 8000+3000=11000[/tex] kg.
The initial velocity of the combined mass, u= 20 m/s.
Time required to stop, t=3 seconds.
Final velocity, v=0.
Displacement traveled, s=50 m.
(a) As [tex]a=\frac {v-u}{t}[/tex]
[tex]\Rightarrow a=\frac{0-20}{3}=-\frac{20}{3} =6.67 m/s^2[/tex]
Hence the acceleration of the truck is [tex]-6.67 m/s^2.[/tex]
(b) Now, [tex]a=-6.67 m/s^2[/tex] is the acceleration of the package, this acceleration is due the frictional force, f.
Due to inertia, on application of break, the package have tendency to slide to left (in the direction of velocity). But the package does not slides, this is only due to the frictional force, f, which acts in the right direction ( opposite to the direction of velocity).
So, the magnitude of frictional force required on [tex]m_2[/tex] to avoid slide is
[tex]f=|m_2a|=\frac{20}{3}m_2\times(i)[/tex]
Now, let \mu be the minimum coefficient of the friction, so
The force due to friction, [tex]f_r= \mu N[/tex],
where [tex]\mu N[/tex] is the normal reaction.
[tex]N=m_2g[/tex], where g is the acceleration due to gravity.
So, [tex]f_r=\mu m_2g\cdots(ii)[/tex]
To avoid slide, [tex]f_r\geq f[/tex]
[tex]\Rightarrow \mu m_2g\geq\frac{20}{3}m_2[/tex] [from (i)and (ii)]
[tex]\Rightarrow \mu\geq \frac{20}{3\times 9.81}[/tex] [tex][ as \;g=9.81 m/s^2][/tex]
[tex]\Rightarrow \mu \geq 0.68[/tex]
Hence, the minimum value of coefficient of friction between packages and the truck os 0.68.
Physics help, please? :)
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a hill. Describe the action and reaction forces that cause the locomotive to move up the hill, such as the reaction force and gravity.
4. Is the force of the earth’s gravity on the sun stronger, weaker, or the same as the force of the sun’s gravity on the earth? Explain why the sun’s attraction affects the motion of the earth more than the earth’s attraction affects the sun’s motion. Employ Newton’s second and third laws in your answer.
If anyone could help me at all, with either question it would be greatly appreciated, Physics is my hardest subject, and I struggle with it.
Answer:
Explanation:
3. Newton’s third law explains how every action has an equal but opposite reaction, meaning that forces comes in pairs. While the locomotive’s wheels are pushing back against the ground as the action force, the ground is producing a reaction force towards the locomotive, propelling it forward. Another pair of forces that act on the locomotive is gravity and normal force. While gravity is pulling the locomotive towards the ground, the normal force the ground exerts on the locomotive is why the locomotive doesn’t fall through the ground.
4. The force of Earth’s gravity on the Sun is weaker than the force of the Sun’s gravity on Earth. The Sun’s attraction affects the motion of Earth more than the Earth’s attraction affects the Sun’s motion because according to Newton’s second law, force has mass as one of its factors. The Sun has a significantly higher mass than Earth, meaning that its force of gravity would also be significantly higher. Newton’s third law is why the Earth doesn’t get marginally closer to the Sun, stating that every action has an equal and opposite reaction. As the Sun is pulling Earth towards itself, Earth is pulling away from the Sun.
1. What are valence electrons used for by an element?
Answer:
An element's valence electron tells us about its ability to react and not react. More rules to this, but that's the gist of it. it also helps us form bonds
Explanation:
Valence electrons are used by an element for bonding and ionization, contributing to the element's chemical reactivity and behavior.
Valence electrons also play a vital role in ionization, which refers to the process of gaining or losing electrons to form ions. Elements tend to gain or lose electrons in order to achieve a stable electron configuration, typically by acquiring a full valence shell.
Metals, located on the left side of the periodic table, have fewer valence electrons, often one or two, and tend to lose them to form positive ions (cations). This characteristic makes them good conductors of electricity.
Nonmetals, located on the right side of the periodic table, have a nearly full valence shell and tend to gain electrons to achieve a stable configuration, forming negative ions (anions). Nonmetals generally do not conduct electricity as well as metals.
In summary, valence electrons are used by an element for bonding, where they participate in the formation of covalent and ionic bonds, and for ionization, where they are gained or lost to form ions and achieve a stable electron configuration.
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a supersonic aircraft travels faster than the speed of sound. What might be the top speed of such an aircraft? 200 Kilometers per hour 500 Kilometers per hour O 1000 Kilometers per hour O 1500 Kilometers per hour
1500 kpm
Which of the following is not an example of work?
1.a man pushing a heavy box across the floor
2.an air hockey puck traveling at a constant speed
3.a magnet repelling a 4.compass needle
ship movement that causes ripples in the water
Answer:
3 a is the ans i think so ....
What is the value of the initial horizontal velocity?
Answer:
9.8 m/s/s
Explanation:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; its valueis 9.8 m/s/s, down, The vertical velocity of a projectile changes by 9.8 m/s each second, Thehorizontal motion of a projectile is independent of its vertical motion.
Answer:
the horizontal component of the velocity, however, retains its initial value v0x=+115 m/s throughout the entire descent.
Explanation:
since the plane also travels at a constant horizontal velocity of +115 m/s, it remains directly above the falling package.
A 56 kg diver runs and dives from the edge of a cliff into the water which is located 4.0 m below. If she is moving at 8.0 m/s the instant she leaves the cliff, determine the following.
Her gravitational potential energy relative to the water surface when she leaves the cliff
Her kinetic energy when she leaves the cliff
Her total mechanical energy relative to the water surface when she leaves the cliff
Her total mechanical energy relative to the water surface just before she enters the water.
The speed at which she enters the water.
Answer:
1) 2197.44 J
2) 0 J
3) 2197.44 J = Constant
4) 2197.44 J
5) Approximately 8.86 m/s
Explanation:
The given parameters are;
The mass of the diver, m = 56 kg
The height of the cliff, h = 4.0 m
The speed with which the diver is moving, vₓ = 8.0 m/s
The gravitational potential energy = Mass, m × Height of the cliff, h × Acceleration due to gravity, g
1) Her gravitational potential energy = 56 × 4.0 × 9.81 = 2197.44 J
2) The kinetic energy = 1/2·m·u²
Where;
u = Her initial velocity = 0 when she just leaves the cliff
Therefore;
Her kinetic energy when she just leaves the cliff = 1/2 × 56 × 0² = 0 J
3) The total mechanical energy = Kinetic energy + Potential energy
The total mechanical energy is constant
Her total mechanical energy relative to the water surface when she leaves the cliff = Her gravitational potential energy = 2197.44 J = Constant
4) Her total mechanical energy relative to the water surface just before she enters the water = 2197.44 J
5) The speed with which she enters the water, v, is given from, v² = u² + 2·g·h
Where;
u = The initial velocity at the top of the cliff before she jumps= 0 m/s
∴ v² = 0² + 2 × 9.81 × 4 = 78.48
v = √78.48 ≈ 8.86 m/s
The speed with which she enters the water, v ≈ 8.86 m/s
1) Her gravitational potential energy relative to the water surface when she leaves the cliff is; GPE(leaves cliff) = 2195.2 J
2) Her kinetic energy when she leaves the cliff is; KE = 0J
3) Her total mechanical energy relative to the water surface when she leaves the cliff is; ME_total = 2195.2 J
4) Her total mechanical energy relative to the water surface just before she enters the water is; ME_total = 2195.2 J
5) The speed at which she enters the water is; v = 8.85 m/s
We are given;
Mass of the diver; m = 56 kg
Height of the cliff; h = 4 m
Speed at which she is moving; vₓ = 8 m/s
1) Formula for gravitational potential energy is;
GPE = mgh
where;
m is mass
g is acceleration due to gravity
h is height
Thus;
GPE = 56 × 4 × 9.8
GPE(leaves cliff) = 2195.2 J
2) The formula for kinetic energy when she leaves the cliff is;
KE = ¹/₂mu²
Where;
m is mass
u = initial velocity = 0 m/s
Thus;
KE = ¹/₂ × 56 × 0²
KE(leaves cliff) = 0 J
3) The total mechanical energy relative to the water surface when she leaves the cliffis;
ME_total = GPE(leaves cliff) + KE(leaves cliff)
Thus;
ME_total = 2195.2 + 0
ME_total = 2195.2 J
4) Her total mechanical energy relative to the water surface just before she enters the water is same as that when she leaves the cliff = 2195.2 J
5) The speed with which she enters the water, v, is gotten from newtons third equation of motion;
v² = u² + 2gh
Thus;
v² = 0² + (2 × 9.8 × 4)
v² = 78.4
v = √78.4
v = 8.85 m/s
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How does Health & Physical Education relate to any other subject you now study in
school?
Answer:
Health relates to science because
in science you study, research, and knowledge in this case, health science, which helps you under stand more about how humans and animals function. And Physical education relates to science because , you study the way of human movement, think of push-ups as a example.
I hope I helped U ´꓃ ` U
unit of power is derived unit why
Answer:
it was given the name Newton (N). from this, the derived unit of energy (or work) is defined ,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction . It was given the name Joule (J).
Explanation:
the value of g is greater at the poles than at the equator why
Answer:
because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.
What does it mean for objects to be at different temperatures?
Define potential energy. Give its mathematical formula and SI unit.
Answer:
The type of mechanical energy that is possessed due to the virtue of motion or state of a body is known as potential energy.
Its formula: PE= mgh
Its SI unit is joule.
Hope it helps you..
A skler is traveling fast down a mountain slope. The table shows data
collected on the skier at a particular instant.
Mass
64 kg
608 N
Weight
Velocity
21 m/s, forward
Force of friction between skis and snow
6 N, backward
Force of air resistance
0.5 N, backward
Which values affect the net force on the skier?
A. The skier's weight and the force of air resistance
B. The force of friction between the skis and the snow and the force
of air resistance
C. The skier's velocity and the force of friction between the skis and
the snow
D. The skier's weight, the force of friction between the skis and snow,
and the force of air resistance
Answer:
D. The skier's weight, the force of friction between the skis and snow,
and the force of air resistance
Explanation:
If two objects, such as the the skier, and skies undergo a fast velocity downward, the net force is the total force or newtons which are all components of weight as apparent to mass and gravity, friction, which is the contact force of the skis on the snow, and air resistance which limits the air resistance is the opposite force acting on the object I'm the air relative to the density of air, cross sectional area of the object, the coefficient of drag which is based on the density of the object, it's area, and dynamic air pressure.
A block of cheese Bhangs from the ceiling by rope 1 A wheel of cheese Whangs from the block of
cheese by rope 2
What is the correct free body diagram for the block of cheese B?
URGENT
Answer:
Explanation:
KHAN ACADEMY
The correct free body diagram is option (B). There will only be two forces acting on cheese B.
Given that Cheese B hangs on rope 1. The weight of the cheese is balanced by the tension force on the rope. That is, the cheese experiences a force in the upward direction due to the tension on rope 1.Similarly, a wheel of cheese W hangs from block B by a rope 2. This rope has a tensional force that is balanced by the weight of the cheese W. This causes a downward pull on block B due to the tension on rope 2.By representing the tensional forces by the ropes 1 and 2 as [tex]F_{T1}[/tex] and [tex]F_{T2}[/tex] respectively, the correct free body diagram will be option B.
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Attachment Lab:Conservation of Linear Momentum
Answer:
This is what I got the teacher hasn’t graded it yet so sorry if it’s not right
Explanation:
A metal ball has a mass of 2.05 kg and a volume of 6.8 cm. What is its density? Remember
Answer:
the density is 0.301 :)
During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average acceleration during this period?
Answer:
[tex]\boxed {\boxed {\sf 2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{\Delta v}{t}[/tex]
The time is 1.25 seconds. The change in velocity is the difference between the initial velocity and the final velocity.
[tex]\Delta v=v_f-v_i[/tex] The final velocity is 7.5 m/s and the initial velocity is 5.0 m/s[tex]\Delta v =7.5 \ m/s-5.0 \ m/s=2.5 \ m/s[/tex][tex]\Delta v= 2.5 \ m/s\\t=1.25 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{2.5 \ m/s}{1.25 \ s}[/tex]
Divide.
[tex]a=2 \ m/s^2[/tex]
The sprinter's average acceleration is 2 meters per second squared.
Answer: 2 m/s^2
Explanation: Hope this helps :)
relationship between voltage, resistance and current in a circuit
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
Answer:
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
Explanation: