please show all work
Evaluate the integral. Show your work for full credit. A. . La x sin x cos x dx B. 2x3 + x2 - 21x + 24 dac 22 + 2x - 8

Given that F(x) = f(x^2), where f is a function, and the values f(4) = 6, f'(4) = 2, and S'(12) = 3, we need to find F'(2), the derivative of F(x) at x = 2.

A derivative is a security with a price that is dependent upon or derived from one or more underlying assets. The derivative itself is a contract between two or more parties based upon the asset or assets. Its value is determined by fluctuations in the underlying asset. To find F'(2), we first need to apply the chain rule. According to the chain rule, if F(x) = f(g(x)), then F'(x) = f'(g(x)) * g'(x). In this case, F(x) = f(x^2), so we can rewrite it as F(x) = f(g(x)) where g(x) = x^2. Now, let's find the derivatives needed for F'(2). Since f(4) = 6, it means f(g(2)) = f(2^2) = f(4) = 6. Similarly, since f'(4) = 2, it means f'(g(2)) * g'(2) = f'(4) * 2 = 2 * 2 = 4. Lastly, since S'(12) = 3, it implies that g'(2) = 3. Using the information obtained, we can calculate F'(2) using the chain rule formula:

F'(2) = f'(g(2)) * g'(2) = 4 * 3 = 12.

Therefore, the derivative F'(2) is equal to 12.

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The given differential equation is [tex]r^2yy - 2r^3e^{1/r} = 0[/tex]. By solving this equation, we can find the solution for y with the initial condition y(1) = 2.

To solve the differential equation, we can use the method of separation of variables. We start by rewriting the equation as [tex]r^2yy - 2r^3e^{1/r} = 0[/tex]. Then, we rearrange the equation as [tex]r^2dy/dx - 2r^3e^{1/r} = 0[/tex].

Next, we separate the variables by dividing both sides by r² and multiplying by dx: (dy/dx) - (2re^(1/r))/r² = 0. Now, we integrate both sides with respect to x, giving us ∫(dy/dx) dx - ∫(2re^(1/r))/r² dx = ∫0 dx.

The integral of dy/dx with respect to x is simply y, so the equation becomes y - ∫(2r*e^(1/r))/r² dx = C, where C is the constant of integration.

To evaluate the integral, we need to simplify the expression (2r*e^(1/r))/r². We can rewrite it as 2e^(1/r)/r. The integral of 2e^(1/r)/r with respect to r is not straightforward, and it does not have a closed-form solution in terms of elementary functions.

Therefore, we need to approximate the solution numerically or by using approximation techniques. The initial condition y(1) = 2 can be used to determine the constant C and obtain a specific solution.

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The expression tan(cos^(-2)x) cannot be simplified further into an algebraic expression. It represents the tangent function applied to the reciprocal of the square of the - BFGV function of x.

The expression tan(cos^(-2)x) consists of two trigonometric functions: tangent (tan) and the reciprocal of the square of the cosine function (cos^(-2)x). The reciprocal of the square of the cosine function represents 1/(cos^2x), which can be rewritten as sec^2x (the square of the secant function). Therefore, the expression can be written as tan(sec^2x). However, there is no further algebraic simplification possible for this expression. It remains in the form of the tangent function applied to the square of the secant function of x.

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(a) By evaluating the expression for s3, it can be shown that s3 is equal to ln(8).

(b) By using mathematical induction, it can be shown that the general term sn is equal to ln(n+2).

(c) The series Σ ln(k(k+2)(k+1)) converges. To find its limit, we can take the limit as n approaches infinity of the general term ln(n+2), which equals infinity.

(a) To show that s3 = ln(8), we substitute k = 3 into the given expression and simplify to obtain ln(8).

(b) To prove that sn = ln(n+2), we can use mathematical induction. We verify the base case for n = 1 and then assume the formula holds for sn. By substituting n+1 into the formula for sn and simplifying, we obtain ln(n+3) as the expression for sn+1, confirming the formula.

(c) The series Σ ln(k(k+2)(k+1)) converges because the general term ln(n+2) converges to infinity as n approaches infinity.


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The calculation involves finding the definite integral of 2πy√[tex](1 + (dy/dx)^2)[/tex] dx over the interval [0, 3/4].

To find the surface area generated when the curve y = 16x - 7 is revolved about the y-axis over the interval [0, 3/4], we can use the formula for the surface area of revolution. The formula is given by:

A = 2π ∫[a,b] y √(1 + (dy/dx)^2) dx

In this case, we need to find the definite integral of y √([tex]1 + (dy/dx)^2[/tex]) with respect to x over the interval [0, 3/4].

First, let's find dy/dx by taking the derivative of y = 16x - 7:

dy/dx = 16

Next, we substitute y = 16x - 7 and dy/dx = 16 into the surface area formula:

A = 2π ∫[0, 3/4] (16x - 7) √(1 + 16^2) dx

Simplifying the expression inside the integral:

A = 2π ∫[0, 3/4] (16x - 7)  √257 dx

Now, we can evaluate the integral to find the surface area. Integrating (16x - 7)  √257 with respect to x over the interval [0, 3/4] will give us the exact numerical value of the surface area.

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the equation of the desired plane is x - 2y + z = 0.

To find the equation of the plane that passes through the line of intersection of the planes x - z = 3 and y - 2z = 1 and is perpendicular to the plane x y - 4z = 4, we need to determine the normal vector of the desired plane.

First, let's find the direction vector of the line of intersection between the planes x - z = 3 and y - 2z = 1. We can rewrite these equations in the form Ax + By + Cz = D:

x - z = 3 => x - 0y - z = 3 => x + 0y - z = 3 (1)

y - 2z = 1 => 0x + y - 2z = 1 => 0x + y - 2z = 1 (2)

The direction vector of the line of intersection can be obtained by taking the cross product of the normal vectors of the two planes:

n1 = [1, 0, -1]

n2 = [0, 1, -2]

Direction vector of the line of intersection = n1 x n2 = [0 - (-1), -2 - 0, 1 - 0] = [1, -2, 1]

Now, we need to find the normal vector of the desired plane, which is perpendicular to the plane x y - 4z = 4. We can read the coefficients from the equation:

n3 = [1, 1, -4]

Since the plane we want is perpendicular to the given plane, the dot product of the normal vector of the desired plane and the normal vector of the given plane is zero:

n3 • [1, -2, 1] = 1(1) + 1(-2) + (-4)(1) = 1 - 2 - 4 = -5

Therefore, the equation of the plane passing through the line of intersection of the planes x - z = 3 and y - 2z = 1 and perpendicular to the plane x y - 4z = 4 is:

1x - 2y + 1z = 0

This can be simplified as:

x - 2y + z = 0

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To ensure that the sum of a series is accurate to within 0.0002, we need to find the point at which adding more terms does not significantly change the sum.

Let's assume that the series we're dealing with converges. To ensure that the sum is accurate to within 0.0002, we need to find a point where adding more terms won't significantly change the value of the sum. In other words, we want to reach a point where the sum of the remaining terms is less than or equal to 0.0002.

Let's consider an example to illustrate this concept. Suppose we have a series with the following terms: 0.1, 0.05, 0.025, 0.0125, ...

We can start by calculating the sum of the first two terms: 0.1 + 0.05 = 0.15. Next, we add the third term:

0.15 + 0.025 = 0.175.

Continuing this process, we add the fourth term:

0.175 + 0.0125 = 0.1875.

At this point, we can observe that adding the fifth term, 0.00625, will not change the sum significantly. The difference between the sum of the first four terms and the sum of the first five terms is only 0.00015, which is less than our desired accuracy of 0.0002. Therefore, we can conclude that including the first five terms in the sum will ensure an accuracy within 0.0002.

In general, the number of terms required for a desired level of accuracy depends on the specific series being considered. Some series converge more rapidly than others, which means that fewer terms are needed to achieve a given level of accuracy.

Additionally, there are mathematical techniques and formulas, such as Taylor series expansions, that can be used to approximate the sum of certain types of series with a desired level of accuracy.

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Complete Question:

How many terms are required to ensure that the sum is accurate to within 0.0002?

a. ∫5x²√(2x²+1)dx = (1/2)∫√u du where u=2x²+1

b. ∫x².5(201²)dx = (2/7)∫u.5du where u=x³

a. To use the substitution method, we first choose a part of the integrand to substitute. Let u be equal to 2x²+1, so du = 4x dx. We can manipulate the integrand by factoring out 5x and substituting u and du.

∫5x²√(2x²+1)dx = 5∫x√(2x²+1)xdx = 5/4∫√u du (since 4x dx = du)

To evaluate the integral, we simplify the new integral involving u.

5/4∫√u du = 5/4 * (2/3)u^(3/2) + C

Substituting back for u,

5/4 * (2/3)(2x²+1)^(3/2) + C

b. Similarly, we choose a part of the integrand to substitute, so we let u = x³, so du = 3x² dx. Then we can manipulate the integral by factoring out x² and substituting u and du.

∫x².5(201²)dx = ∫x²(201²)√x dx = 201²∫u.5/2 du (since 3x² dx = du)

Again, we simplify the new integral by raising u to the power of 7/2 and multiplying by 2/7.

201²∫u.5/2 du = 2/7 * 201² * (2/7)u^(7/2) + C

Substituting back for u,

(4/49) * 201² * x^7/2 + C

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The slope of the catenary curve y = 50 cosh(x) at a specific point can be found using calculus techniques.

In this case, the catenary curve represents the shape of a telephone line between two poles that are 12 meters apart. To find the slope of the curve at a specific point (x, y), we need to take the derivative of the function y = 50 cosh(x) with respect to x. The derivative of cosh(x) is sinh(x), so the derivative of y = 50 cosh(x) is dy/dx = 50 sinh(x). To approximate the slope at a specific point i, we substitute the x-coordinate of that point into the derivative expression. Therefore, the approximate value of the slope at point i is dy/dx = 50 sinh(i).

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Answer:

First, we can simplify the expression by multiplying the x terms together and the y terms together. This gives us y^(5+3) * x^(-5-3) = y^8 / x^8.

Therefore, the solution to the expression y^5 / x^-5 * x^-3 * y^3 is (y^8) / (x^8).

The language of "giving fractions like wholes" is not completely accurate because fractions represent parts of a whole, not complete wholes.

When students give fractions common denominators to add them, they are finding a common unit or denominator that allows for easier comparison and addition. However, referring to this process as "giving fractions like wholes" can be misleading. Fractions represent parts of a whole, not complete wholes.

A more accurate representation of a whole number and a fraction combined is a mixed number. A mixed number combines a whole number and a proper fraction, representing a complete quantity. For instance, 1 1/4 is a mixed number where 1 represents a whole number and 1/4 represents a fraction of that whole. Using mixed numbers provides a clearer understanding of the relationship between whole numbers and fractions, as it distinguishes between complete wholes and fractional parts.

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we can say that the congruence `x² ≅ 1 (mod p)` has a solution if and only if `p = 2` or `p ≅ 1 (mod 4)`. Hence, the solution is p = 2 or p ≅ 1 (mod 4).

The given congruence `x² ≅ 1 (mod p)` has a solution if and only if `p = 2` or `p ≅ 1 (mod 4)`.

A solution is a value or set of values that can be substituted into an equation to make it true.

For example, the solution to the equation `x² - 3x + 2 = 0` is `x = 1` or `x = 2`.

Solution for the given congruence: The given congruence is `x² ≅ 1 (mod p)`.

We need to find the value of `p` for which the congruence has a solution.

Now, if the congruence `x² ≅ 1 (mod p)` has a solution, then we can say that `x ≅ ±1 (mod p)` because `1² ≅ 1 (mod p)` and `(-1)² ≅ 1 (mod p)`.

This implies that `p` must divide the difference of `x - 1` and `x + 1` i.e., `(x - 1)(x + 1) ≅ 0 (mod p)`.

This gives us two cases:

Case 1: `p` divides `(x - 1)(x + 1)` i.e., either `p` divides `(x - 1)` or `p` divides `(x + 1)`. In either case, we get `x ≅ ±1 (mod p)`.

Case 2: `p` does not divide `(x - 1)` or `(x + 1)` i.e., `p` and `x - 1` are coprime and `p` and `x + 1` are coprime as well.

Therefore, we can say that `p` divides `(x - 1)(x + 1)` only if `p` divides `(x - 1)` or `(x + 1)` but not both.

Now, `(x - 1)(x + 1) ≅ 0 (mod p)` implies that either `(x - 1) ≅ 0 (mod p)` or `(x + 1) ≅ 0 (mod p)`.

Therefore, we get two cases as follows:

Case A: `(x - 1) ≅ 0 (mod p)` implies that `x ≅ 1 (mod p)` and `x ≅ -1 (mod p)`.

Case B: `(x + 1) ≅ 0 (mod p)` implies that `x ≅ -1 (mod p)` and `x ≅ 1 (mod p)`.

Thus, we can conclude that if the congruence `x² ≅ 1 (mod p)` has a solution, then either `x ≅ 1 (mod p)` and `x ≅ -1 (mod p)`, or `x ≅ -1 (mod p)` and `x ≅ 1 (mod p)`.

Therefore, we can say that `p` must be such that it divides `(x - 1)(x + 1)` but not both `(x - 1)` and `(x + 1)` simultaneously. Hence, we get the following two cases:

Case 1: If `p = 2`, then `(x - 1)(x + 1)` is always divisible by `p`.

Therefore, `x ≅ ±1 (mod p)` for all `x`.

Case 2: If `p ≅ 1 (mod 4)`, then `(x - 1)` and `(x + 1)` are not both divisible by `p`.

Hence, `p` must divide `(x - 1)(x + 1)` for all `x`.

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The problem involves finding the value of the integral Sº [2f(x) + 3g(x)] dx, given that the integral of f(x) / x f(x) dx is equal to 35 and the integral of g(x) dx is equal to 12.

To solve this problem, we can use linearity and the properties of integrals.

Linearity states that the integral of a sum is equal to the sum of the integrals. Therefore, we can split the integral Sº [2f(x) + 3g(x)] dx into two separate integrals: Sº 2f(x) dx and Sº 3g(x) dx.

Given that the integral of f(x) / x f(x) dx is equal to 35, we can substitute this value into the integral Sº 2f(x) dx. So, Sº 2f(x) dx = 2 * 35 = 70.

Similarly, given that the integral of g(x) dx is equal to 12, we can substitute this value into the integral Sº 3g(x) dx. So, Sº 3g(x) dx = 3 * 12 = 36.

Finally, we can add the results of the two integrals: 70 + 36 = 106. Therefore, the value of the integral Sº [2f(x) + 3g(x)] dx is 106.

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58.67% of the people Surveyed preferred show A.

The percentage of people surveyed who preferred show A, we need to consider the total number of people surveyed and the number of people who preferred show A.

Let's calculate the total number of people surveyed:

Total men surveyed = 62 + 58 = 120

Total women surveyed = 70 + 35 = 105

Now, let's calculate the total number of people who preferred show A:

Men who preferred show A = 62

Women who preferred show A = 70

To find the total number of people who preferred show A, we add the number of men and women who preferred it:

Total people who preferred show A = 62 + 70 = 132

To calculate the percentage of people who preferred show A, we divide the total number of people who preferred it by the total number of people surveyed, and then multiply by 100:

Percentage = (Total people who preferred show A / Total people surveyed) * 100

Percentage = (132 / (120 + 105)) * 100

Percentage = (132 / 225) * 100

Percentage ≈ 58.67%

Approximately 58.67% of the people surveyed preferred show A.

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However, note that this is different from drawing a red three or a three of any suit, which would have a probability of 6/52 or 3/26.

1. The probability of drawing a red four is 2/52 or 1/26, as there are two red fours in the deck.
2. The probability of drawing a heart is 13/52 or 1/4, as there are 13 hearts in the deck.
3. The probability of drawing a 4 or a heart is the sum of the probabilities of drawing a 4 and drawing a heart, minus the probability of drawing the 4 of hearts (which was counted twice). This is (4/52 + 13/52 - 1/52) or 16/52 or 4/13.
4. The probability of not drawing a club is 39/52 or 3/4, as there are 39 non-club cards in the deck.
5. The probability of drawing a red or a four is the sum of the probabilities of drawing a red card and drawing a four, minus the probability of drawing the 4 of hearts (which was counted twice). This is (26/52 + 4/52 - 1/52) or 29/52 or 7/13.
6. The probability of drawing a red and a 3 is 2/52 or 1/26, as there are two red threes in the deck.

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The approximate radius of the ball is 4.8 inches

From the question, we have the following parameters that can be used in our computation:

Surface area formule, SA = 4πr²

Surface area = 289

using the above as a guide, we have the following:

SA = 289

substitute the known values in the above equation, so, we have the following representation

4πr² = 289

So, we have

πr² = 72.25

So, we have

r² = 23.0095

Take the square root of both sides

r = 4.8

Hence, the approximate radius of the ball is 4.8 inches

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The equation of the osculating circle at the local minimum of the function f(x) = 2[tex]x^3[/tex] + 6[tex]x^2[/tex] - 9x - 14 can be determined by finding the second derivative.

To find the equation of the osculating circle at the local minimum of a function, we need to follow these steps:

1. Find the second derivative of the function f(x) to determine the curvature.

2. Set the second derivative equal to zero and solve for x to find the x-coordinate of the local minimum.

3. Substitute the x-coordinate into the original function f(x) to find the corresponding y-coordinate of the local minimum.

4. Calculate the curvature at the local minimum by evaluating the absolute value of the second derivative.

5. Use the formula for the equation of a circle, which states that a circle can be represented as[tex](x - a)^2[/tex] +[tex](y - b)^2[/tex] = [tex]r^2[/tex], where (a, b) is the center and r is the radius.

6. Substitute the coordinates of the local minimum into the equation of the circle and use the curvature as the radius to determine the equation of the osculating circle.

Without specific values for the local minimum, it is not possible to provide the exact equation of the osculating circle in this case.

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The first-order partial derivatives of f(x, y) are ∂f/∂x = 12x^2y^2 - 6x + 5y^2 and ∂f/∂y = 8x^3y - 6xy + 10xy^2. The second-order partial derivatives are ∂²f/∂x² = 24xy^2 - 6, ∂²f/∂y² = 8x^3 + 20xy, and ∂²f/∂x∂y = 24x^2y - 6x + 20y^2.

The first-order partial derivatives of the function f(x, y) = 4x^3y^2 – 3x^2 + 5xy^2 can be calculated as follows:

∂f/∂x = 12x^2y^2 - 6x + 5y^2

∂f/∂y = 8x^3y - 6xy + 10xy^2

To find the second-order partial derivatives, we differentiate the first-order partial derivatives with respect to x and y:

∂²f/∂x² = 24xy^2 - 6

∂²f/∂y² = 8x^3 + 20xy

∂²f/∂x∂y = 24x^2y - 6x + 20y^2

By applying the Mixed Partial Derivative Theorem, we can check if the mixed partial derivatives are equal:

∂²f/∂x∂y = 24x^2y - 6x + 20y^2

∂²f/∂y∂x = 24x^2y - 6x + 20y^2

Since the mixed partial derivatives ∂²f/∂x∂y and ∂²f/∂y∂x are equal, we can conclude that fxy = fyx for this function.

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Therefore, the two positive coterminal angles are 5π/4 and 13π/4, and the two negative coterminal angles are -11π/4 and -19π/4.

To find the coterminal angles, we can add or subtract multiples of 2π (or 360°) to the given angle to obtain angles that have the same initial and terminal sides.

For the angle -3π/4 radians, adding or subtracting multiples of 2π will give us the coterminal angles.

Positive coterminal angles:

-3π/4 + 2π = 5π/4

-3π/4 + 4π = 13π/4

Negative coterminal angles:

-3π/4 - 2π = -11π/4

-3π/4 - 4π = -19π/4

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When the diameter of the sphere is 60 mm, its radius is 30 mm. The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius.

To find how fast the volume is increasing, we need to take the derivative of V with respect to time, which gives dV/dt = 4πr^2 (dr/dt). Substituting the given values, we get dV/dt = 4π(30)^2 (2) = 7200π mm^3/s. Therefore, the volume of the sphere is increasing at a rate of 7200π mm^3/s when the diameter is 60 mm. The radius of a sphere is increasing at a rate of 2 mm/s. When the diameter is 60 mm, the radius is 30 mm. The volume of a sphere is given by the formula V = (4/3)πr³. Using the chain rule, dV/dt = (4/3)π(3)r²(dr/dt), where dV/dt is the rate of volume increase and dr/dt is the rate of radius increase. Plugging in r = 30 mm and dr/dt = 2 mm/s, we get dV/dt = 4π(30)²(2) = 7200π mm³/s. So, the volume is increasing at a rate of 7200π mm³/s when the diameter is 60 mm.

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To find the velocity and acceleration at time t for the cougar's position function s = 1 - 61t + 9t^2, we need to differentiate the function with respect to time.

a) Velocity:

To find the velocity, we differentiate the position function with respect to time:

v(t) = ds/dt

Given that s = 1 - 61t + 9t^2, we can differentiate it term by term:

ds/dt = d(1 - 61t + 9t^2)/dt

= 0 - 61 + 18t

= -61 + 18t

So, the velocity function is v(t) = -61 + 18t.

b) Change of Direction:

The cougar changes direction when its velocity changes sign. Therefore, we need to find the time t when v(t) = 0:

-61 + 18t = 0

18t = 61

t = 61/18

So, the cougar changes direction at t = 61/18 seconds.

c) Acceleration:

To find the acceleration, we differentiate the velocity function with respect to time:

a(t) = dv/dt

Given that v(t) = -61 + 18t, we can differentiate it term by term:

dv/dt = d(-61 + 18t)/dt

= 0 + 18

= 18

So, the acceleration function is a(t) = 18.

Since the acceleration is a constant value of 18, the cougar's speed does not change over time. It neither speeds up nor slows down.

To summarize:

a) Velocity: v(t) = -61 + 18t

b) Change of Direction: t = 61/18 seconds

c) Acceleration: a(t) = 18

d) The cougar does not speed up or slow down.

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If a square matrix has a determinant equal to zero, it is defined as a singular matrix.

A singular matrix is a square matrix whose determinant is zero. The determinant of a matrix is a scalar value that provides important information about the matrix, such as whether the matrix is invertible or not. If the determinant is zero, it means that the matrix does not have an inverse, and hence it is singular.

A non-singular matrix, on the other hand, has a non-zero determinant, indicating that it is invertible and has a unique inverse. Non-singular matrices are also referred to as invertible or non-degenerate matrices.

Therefore, the correct answer is option a. Singular matrix, as it describes a square matrix with a determinant equal to zero.

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For the function f(u, v) = 5u²v - 3uv³, the value of f(1, 2) is 4. The partial derivative fu(1, 2) is 10v - 6uv² evaluated at (1, 2), resulting in 14. The partial derivative fv(1, 2) is 5u² - 9uv² evaluated at (1, 2), resulting in -13.

To find f(1, 2), we substitute u = 1 and v = 2 into the function f(u, v). Plugging in these values, we get f(1, 2) = 5(1)²(2) - 3(1)(2)³ = 10 - 48 = -38.

To find the partial derivative fu, we differentiate the function f(u, v) with respect to u while treating v as a constant. Taking the derivative, we get fu = 10uv - 6uv². Evaluating this expression at (1, 2), we have fu(1, 2) = 10(2) - 6(1)(2)² = 20 - 24 = -4.

To find the partial derivative fv, we differentiate the function f(u, v) with respect to v while treating u as a constant. Taking the derivative, we get fv = 5u² - 9u²v². Evaluating this expression at (1, 2), we have fv(1, 2) = 5(1)² - 9(1)²(2)² = 5 - 36 = -31.

Therefore, the values are:

a) f(1, 2) = -38

b) fu(1, 2) = -4

c) fv(1, 2) = -31

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To determine if a set of ordered pairs represents a function, we need to check if each input (x-value) is associated with exactly one output (y-value).

Let's analyze each set of ordered pairs:

{(-6,-5), (-4, -3), (-2, 0), (-2, 2), (0, 4)}

In this set, the input value -2 is associated with two different output values (0 and 2). Therefore, this set does not represent a function.

{(-5,-5), (-5,-4), (-5, -3), (-5, -2), (-5, 0)}

In this set, the input value -5 is associated with different output values (-5, -4, -3, -2, and 0). Therefore, this set does not represent a function.

{(-4, -5), (-3, 0), (-2, -4), (0, -3), (2, -2)}

In this set, each input value is associated with a unique output value. Therefore, this set represents a function.

{(-6, -3), (-6, -2), (-5, -3), (-3, -3), (0, 0)}

In this set, the input value -6 is associated with two different output values (-3 and -2). Therefore, this set does not represent a function.

Based on the analysis, the set {(-4, -5), (-3, 0), (-2, -4), (0, -3), (2, -2)} represents a function since each input value is associated with a unique output value.

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The maximum displacement of the object is -0.5 ft, and it occurs when the object is pulled down 1 ft below the equilibrium position and released.

Based on the information provided, I will address the part of the question related to finding the maximum displacement of the object when it is pulled down 1 ft below the equilibrium position and released.

To find the maximum displacement of the object, we can use the principle of conservation of mechanical energy.

The potential energy stored in the spring when it is stretched is converted into kinetic energy as the object oscillates. At the maximum displacement, all the potential energy is converted into kinetic energy.

Let's assume that the equilibrium position is at the height of zero. When the object is pulled down 1 ft below the equilibrium position, it has a displacement of -1 ft.

To find the maximum displacement, we need to determine the amplitude of oscillation, which is half the total displacement. In this case, the amplitude would be -1 ft divided by 2, resulting in an amplitude of -0.5 ft.

The maximum displacement occurs when the object reaches the extreme point of its oscillation. In this case, it would occur at a displacement of -0.5 ft from the equilibrium position.

The information provided in the question about cos 801 and sin 81 is unrelated to the calculation of the maximum displacement. If you have additional questions or need further clarification, please let me know.

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The required equation is y = Ce^t  where C = ±e^C2.

Given (1, y ) = y i + x j.

To find the equation of flow lines, solve the system of differential equation.

That implies

dx/dt = 1. --(1)

dy/dt = y. ----(2)

Integrating the first equation with respect to t gives,

x = t + c1

Integrating the second equation with respect to t gives,

ln|y| = t +c2.

Applying the exponential function to both sides,  we have,

|y| = e^(t+c2)

Considering the absolute value, we get

case 1: y>0

y = e^(t+c2)

y = e^t × e^c2

Case - 2 y< 0

y = -e^(t +c2)

y = -e^t × e^c2

By combining both the cases,

y = Ce^t  where C = ±e^C2.

This represents the general equation of the flow lines.

Hence, the required equation is y = Ce^t  where C = ±e^C2.

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The probability that the gambler will win her bet is approximately 0.00476, or 0.476%.

To calculate the probability of the gambler winning her bet, we need to determine the total number of possible outcomes and the number of favorable outcomes.

In this case, there are seven horses, and the gambler must pick the top three finishers in the correct order. The total number of possible outcomes can be calculated using the concept of permutations.

The first-place finisher can be any one of the seven horses. Once the first horse is chosen, the second-place finisher can be any one of the remaining six horses. Finally, the third-place finisher can be any one of the remaining five horses.

Therefore, the total number of possible outcomes is: 7 * 6 * 5 = 210

Now, let's consider the favorable outcomes. The gambler must correctly pick the top three finishers in the correct order. There is only one correct order for the top three finishers.

Therefore, the number of favorable outcomes is: 1

The probability of the gambler winning her bet is given by the number of favorable outcomes divided by the total number of possible outcomes:

Probability = Number of favorable outcomes / Total number of possible outcomes

Probability = 1 / 210

Simplifying the fraction, the probability is:

Probability = 1/210 ≈ 0.00476

Therefore, the probability that the gambler will win her bet is approximately 0.00476, or 0.476%.

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If function y= [tex](2r^2 + 1) arctan(r) - √r[/tex] then the derivative can be found as y' = [tex]4r * arctan(r) + (2r^2 + 1) / (1 + r^2) - 1 / (2√r).[/tex]

(i) To find y', we differentiate y with respect to r using the chain rule:

y = (2r^2 + 1) arctan(r) - √r

Applying the chain rule, we have:

y' = (2r^2 + 1)' * arctan(r) + (2r^2 + 1) * arctan'(r) - (√r)'

= 4r * arctan(r) + (2r^2 + 1) * (1 / (1 + r^2)) - (1 / (2√r))

= 4r * arctan(r) + (2r^2 + 1) / (1 + r^2) - 1 / (2√r)

Therefore, y' = 4r * arctan(r) + (2r^2 + 1) / (1 + r^2) - 1 / (2√r).

(ii) To find y', we differentiate y with respect to r using the chain rule:

y = sinh(2r log(r))

Using the chain rule, we have:

y' = cosh(2r log(r)) * (2 log(r) + 2r / r)

= 2cosh(2r log(r)) * (log(r) + r) / r.

Therefore, y' = 2cosh(2r log(r)) * (log(r) + r) / r.

(b) To find y' using logarithmic differentiation, we take the natural logarithm of both sides of the equation:

ln(y) = ln(x^3 * 6^2 * cosh(a * 2x))

Using logarithmic properties, we can rewrite the equation as:

ln(y) = ln(x^3) + ln(6^2) + ln(cosh(a * 2x))

Differentiating implicitly with respect to x, we have:

(1/y) * y' = 3/x + 0 + (tanh(a * 2x)) * (a * 2)

Simplifying further, we obtain:

y' = y * (3/x + 2a * tanh(a * 2x))

Substituting y = x^3 * 6^2 * cosh(a * 2x), we have:

y' = x^3 * 6^2 * cosh(a * 2x) * (3/x + 2a * tanh(a * 2x))

Therefore, y' = x^3 * 6^2 * cosh(a * 2x) * (3/x + 2a * tanh(a * 2x)).

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The given function is f(x, y) = - 3+ 2x - 32 - 2y + 7y. We are required to find the critical point of the function. The critical point is a point at which the function attains a maximum, a minimum, or an inflection point.

To find the critical point of a function of two variables, we differentiate the function partially with respect to x and y.

If there is a solution to the simultaneous equations formed by setting these partial derivatives equal to zero, then it is a critical point.

Partial derivative with respect to x isf_x(x,y) = 2 and the partial derivative with respect to y isf_y(x,y) = 5.

Now, we have to set these partial derivatives equal to zero and solve for x and y as shown below;2 = 05 = 0.

The above set of simultaneous equations does not have a solution.

Thus, there is no critical point.

Hence, the answer is that the critical point is a saddle point.

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a) To determine if the set S = {(1, 4, -3), (-2, 0, 6), (2, 6, -6)} is linearly dependent or independent, we can check if there exists a non-trivial solution to the equation a(1, 4, -3) + b(-2, 0, 6) + c(2, 6, -6) = (0, 0, 0). If such a non-trivial solution exists, S is linearly dependent; otherwise, it is linearly independent.

b) To determine if S spans R3, we need to check if any vector in R3 can be expressed as a linear combination of the vectors in S. If every vector in R3 can be written as a linear combination of the vectors in S, then S spans R3.

To perform the calculations, we solve the equation a(1, 4, -3) + b(-2, 0, 6) + c(2, 6, -6) = (0, 0, 0) and check if there exists a non-trivial solution. If there is a non-trivial solution, S is linearly dependent. If not, S is linearly independent. Furthermore, if every vector in R3 can be expressed as a linear combination of the vectors in S, then S spans R3.

Now, let's proceed to the detailed explanation and calculations.

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