there's 240 candy bars 1/4 of candy bars are snickers 1/3 of the candy bars are twix 1/8 of the candy bars are hershey. how many candy bars are Mars? explain not with a lot of words but in numbers please.
Answer:
you have to add all the fractions of the candy1/4+1/3+1/8
=17/24
subtract from 1Step-by-step explanation:
1-17/24
=7/24
multiply with the total number of candy7/24×240
=70
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What scale factor was applied to the first rectangle to get the resulting image?
Enter your answer as a decimal in the box.
Answer:
2.5
Step-by-step explanation:
the length has increased by 7.5/3 = 2.5.
so the scale factor is 2.5
Use the Law of Sines to find the length of side b in AABC. Round to the nearest tenth. Show your work.
Consider ▲ ABC.
B
28°
112°
37
The length of side b in triangle ABC is 18.7 units.
What is the law of sines?In Mathematics and Geometry, the law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.
In Mathematics and Geometry, the law of sine is modeled or represented by this mathematical equation (ratio):
[tex]\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}[/tex]
In this context, the value of b can be determined as follows;
sin112/37 = sin28/b
b = 37sin28/sin112
b = 17.3705/0.9272
b = 18.7 units.
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Select all of the words for which the probability of selecting the letter A at random is 13
Responses
CAB
CAB
ANT
ANT
BANK
BANK
ALPINE
ALPINE
ABOARD
ABOARD
ABRASIONS
ABRASIONS
BASEBOARDS
The words for which the probability of selecting the letter A at random is 1/3 are:
a) CAB
b) ANT
c) ABOARD
Given data ,
Let the probability of selecting the letter A at random be P ( A ) = 1/3
Now , the number of letters in the words CAB are = 3
The number of A's in the word CAB = 1
So , the probability is P ( A ) = 1/3
Now , Now , the number of letters in the words ANT are = 3
The number of A's in the word ANT = 1
So , the probability is P ( A ) = 1/3
And , Now , the number of letters in the words ABROAD are = 6
The number of A's in the word ABROAD = 2
So , the probability is P ( A ) = 2/6 = 1/3
Hence , the probability is solved
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Lorri had a gross income of $3256.15 during each pay period in 2010. If she got paid monthly, how much of her pay was deducted for FICA in 2010?
Solve for x and graph the solution on the number line below.
V
V
VI
11 2x-5 or 2x-5 > 15
IV.
Inequality Notation:
Number Line:
or
-12 -10 -8 -6
-4
-2
O
2
4
6
8
10 12
x ≤ 8 or x > 10 is the solution of the inequality 11 ≥ 2x - 5 or 2x - 5 > 15.
To solve the compound inequality 11 ≥ 2x - 5 or 2x - 5 > 15, we will solve each inequality separately and then combine the solutions.
Solve the first inequality: 11 ≥ 2x - 5
Add 5 to both sides to isolate 2x:
11 + 5 ≥ 2x
16 ≥ 2x
Divide both sides by 2:
8 ≥ x
So the solution to the first inequality is x ≤ 8.
Solve the second inequality: 2x - 5 > 15
Add 5 to both sides to isolate 2x:
2x > 15 + 5
2x > 20
Divide both sides by 2:
x > 10
So the solution to the second inequality is x > 10.
Combining the solutions, we have x ≤ 8 or x > 10.
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What is the area of the figure? In Units
Answer:
Area = 40
Perimeter = 26
Step-by-step explanation:
length = 8
width = 5
Area = 8 x 5 = 40
Perimeter = 2(8 + 5) = 26
What is the solution to this system?
3x+2y=6
-4x+ 5y = 15
4-3-2-1
1 2 3 4 5
-
S
Answer:
solution: (0,3)
Step-by-step explanation:
You can find the solution when the two lines intersect.
The circumference of the cylinder below is 4 cm and the height is 6 cm. What is the curved surface area of the cylinder? If your answer is a decimal, give it to 1 d.p. circumference 4 cm Height 6 cm
The curved surface area of the cylinder is 24 cm².
We have,
To find the curved surface area of a cylinder, we need to know its height (h) and the circumference of its base (C).
Given:
Circumference (C) = 4 cm
Height (h) = 6 cm
The formula to calculate the curved surface area of a cylinder is A = Ch, where A is the curved surface area, C is the circumference, and h is the height.
Substituting the given values:
A = 4 cm x 6 cm
A = 24 cm²
Therefore,
The curved surface area of the cylinder is 24 cm².
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(~Q → P) ⋀ ~P
Truth Table
| P | Q | ~Q | ~Q → P | ~P | (~Q → P) ⋀ ~P |
|---|---|----|--------|----|----------------|
| T | T | F | T | F | F |
| T | F | T | T | F | F |
| F | T | F | T | T | T |
| F | F | T | F | T | F |
To construct a truth table for the logical statement (~Q → P) ⋀ ~P, we need to consider all possible truth values for the variables Q and P. The symbol "~" represents negation or "not" in logic, so ~Q denotes "not Q" and ~P denotes "not P".
In the above table, we first list all possible truth values for P and Q and then determine the truth values for ~Q, ~Q → P, and ~P based on these values. Finally, we evaluate the logical statement (~Q → P) ⋀ ~P based on the truth values for (~Q → P) and ~P to determine the overall truth value of the statement for each combination of P and Q.
The output of the above truth table shows that the statement (~Q → P) ⋀ ~P is true only in one case when P is false and Q is true. In all other cases, the statement is false. Therefore, we can infer that the statement is not always true and hence it is not a tautology. The statement is only true in one specific case where P is false and Q is true.
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Any idea.???????
Here are four shapes
Rhombus and equilateral triangle will fit in regular circle and rectangle will fit in quadrilateral circle.
A Venn diagram is a diagram that helps us visualize the logical relationship between sets and their elements and helps us solve examples based on these sets. A Venn diagram typically uses intersecting and non-intersecting circles (although other closed figures like squares may be used) to denote the relationship between sets.
Here, rhombus and equilateral triangle are regular, and rectangle and triangle are not regular.
Therefore, rhombus and equilateral triangle will fit in regular circle and rectangle will fit in quadrilateral circle.
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1. Simplify: |-11 +3|
Answer
A-8
B -14
C 8
D 14
Answer: C
Step-by-step explanation:
|-8| = 8
In the figure below, S is the center of the circle. Suppose that JK = 20, LM = 3x + 2, SN = 12, and SP = 12. Find the
following.
The values from figure is,
x = 2
NS = 3.5
We have to given that,
In the figure below, S is the center of the circle.
And, Suppose that JK = 16, MP = 8, LP = 2x + 4, and SP = 3.5.
Now, We know that,
By figure,
MP = LP
Substitute the given values,
8 = 2x + 4
8 - 4 = 2x
4 = 2x
x = 4/2
x = 2
Hence, We get;
LM = MP + LP
LM = 8 + (2x + 4)
LM = 8 + 2 x 2 + 4
LM = 8 + 4 + 4
LM = 16
Since, We have JK = 16
Hence, We get;
NS = SP
This gives,
NS = 3.5
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Ochenta y nueve en número romano ??
Answer:
LXXXIX
Step-by-step explanation:
ochenta y nueve es 89.
89 en numero romano es LXXXIX.
Rectangle CDEF has vertices C (-10, 10),D (5, 10), E (5, 5), and F (-10, 5). It is dilated 5 by a scale factor of centered at (0, 0) to
produce rectangle C'D'E'F'. What is the perimeter in units of rectangle C'D'E'F?
The perimeter of the dilated rectangle C'D'E'F' is 200 units.
To find the perimeter of the dilated rectangle C'D'E'F', we need to determine the new coordinates of its vertices after the dilation.
Given that the scale factor is 5 and the dilation is centered at (0, 0), each coordinate of the original rectangle CDEF will be multiplied by 5 to obtain the corresponding coordinate of the dilated rectangle C'D'E'F'.
The original coordinates of CDEF are:
C (-10, 10)
D (5, 10)
E (5, 5)
F (-10, 5)
To find the coordinates of the dilated rectangle C'D'E'F', we multiply each coordinate by 5:
C' = (-10 × 5, 10 × 5) = (-50, 50)
D' = (5 × 5, 10 × 5) = (25, 50)
E' = (5 × 5, 5 × 5) = (25, 25)
F' = (-10 × 5, 5 × 5) = (-50, 25)
Now, we can calculate the perimeter of the dilated rectangle C'D'E'F' by summing the lengths of its sides.
Length of side C'D':
√[(-50 - 25)² + (50 - 50)²] = √[(-75)² + 0²] = √[5625] = 75
Length of side D'E':
√[(25 - 25)² + (50 - 25)²] = √[0² + 625] = √[625] = 25
Length of side E'F':
√[(25 - (-50))² + (25 - 25)²] = √[75² + 0²] = √[5625] = 75
Length of side F'C':
√[(-50 - (-50))² + (25 - 50)²] = √[0² + 625] = √[625] = 25
Now, we add up the lengths of all four sides to find the perimeter:
Perimeter = C'D' + D'E' + E'F' + F'C'
= 75 + 25 + 75 + 25
= 200
Therefore, the perimeter of the dilated rectangle C'D'E'F' is 200 units.
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Does 10, 15, 18 equal a right triangle
Answer:
Not a right triangle
Step-by-step explanation:
[tex]10^2+15^2\stackrel{?}{=}18^2\\100+225\stackrel{?}{=}324\\325\neq324[/tex]
As the sides of the triangle do not follow the Pythagorean Theorem, then the triangle is not a right triangle.
Please Help 8x + 1
115⁰
Both the angles are supplementary angles hence the value of x is 8°.
To solve for the value of x in the given scenario, we can use the fact that the interior angles between two parallel lines are supplementary, meaning they add up to 180 degrees.
Given:
Angle 1: (8x + 1)
Angle 2: 115°
Since these two angles are supplementary, we can set up the equation:
(8x + 1) + 115 = 180
Now we can solve for x by simplifying and isolating the variable:
8x + 1 + 115 = 180
8x + 116 = 180
8x = 180 - 116
8x = 64
To isolate x, we divide both sides of the equation by 8:
8x/8 = 64/8
x = 8
Therefore, the value of x is 8.
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The average fourth grader is about three times as tall as the average newborn baby. If babiesare on average 45cm 7mm when they are born, What is the height of the average fourth grader?
The average fourth grader is about three times as tall as the average newborn baby. If babies are on average 45 cm 7 mm when they are born, 137 cm 1 mm is the height of the average fourth grader.
Given information,
Baby height is typically 45 cm. 7 mm 45 cm Since there are 10 millimeters in a centimeter, 7 mm is equal to 45.7 cm.
Assume that a fourth-grader is x inches tall.
The average height of a newborn baby (x) = 3 times the height of a fourth-grader.
A fourth-grader's height (x) is equal to 3 x 45.7.
A fourth-grader's height is equal to (x)=137.
Fourth-grader height (x) = 137 cm 1 millimeter
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HELP !!! URGENTTTTT PLS ANSWER!!!
Answer: z=3
Step-by-step explanation:
The perimeter of the rectangle below is 202 units. Find the value of x.
5x +3
4x - 1
∆ACB is bisected by segment CP. m
What is the approximate area of ∆ACB?
NO SPAM OR I WILL REPORT YOU AND BAN YOU IMMEDIATELY
Where the above is given, Area of Δ ACB ≈ 282.62
Why is this so?
The area of a triangle is given as
Area = 1/2 Base x Height
In this case,
Base = AB
Height = CP
Thus, it is correct to state that Area of Δ ACB = 1/2AB * CP.
How is this so?
First we need to find the height and hypotenuse of the triangle.
that is CP and CB.
CB = a/Cos (63)
CB = 26.43227
CP = √(CB²-PB²)
CP = √(26.4322711750232² - 12²)
CP = 23.55133
Area of ΔPCB = (CP x PB)/2
(12 × 23.551326066062)/ 2
= 141.30796
Since ΔPCB = ΔPCA
and ΔACB = ΔPCB + ΔPCA
Thus,
Area of ΔACB = 141.30796 + 141.30796 = 282.61592
≈ 282.62
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Full Question:
Although part of your question is missing, you might be referring to this full question:
See attached image.
a rocket is launched in the air. Its height in feet is given by h=-16t^2+128t where t represents the time in seconds after launch. What is the appropriate domain for this solution?
The quadratic function has the following domain: 0 ≤ t ≤ 8.
How to find the domain of a quadratic equation
Herein we find a quadratic equation that models the height of the rocket in time. The domain is the set of all values of t such that all values of h exist.
Mathematically speaking, the domain of quadratic equations is the set of all real numbers, but physically speaking, this domain is formed by the set of all non-negative numbers such that h ≥ 0. The domain is found by algebra properties:
h = - 16 · t² + 128 · t
h = - 16 · t · (t - 8)
Then, the domain of the quadratic function is: 0 ≤ t ≤ 8.
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Given the number pattern: 20; 18: 14; 8;
a) Determine the nth term of this number pattern.
b) Determine the value of T12 in this number pattern.
c) Which term in this number pattern will have a value of - 36?
A quadratic number pattern has a second term equal to 1, a third term equal to -6 and a fifth term equal to - 14.
a) Calculate the second difference of this quadratic number pattern.
b) Hence, or otherwise, calculate the first term of this number pattern.
Answer:
tn = -n² +n +20; t12 = -112; t8 = -362; 10Step-by-step explanation:
You have two problems involving quadratic sequences. For the sequence that starts 20, 18, 14, 8, ..., you want the n-th term, the 12-th term, and the term number of -36. For the sequence with terms 2, 3, and 5 having values 1, -6, and -14, you want the second difference and the first term.
1. 20, 18, 14, 8The first attachment shows the first and second differences of this sequence each begin with -2. The first of differences at level n can be put into a formula for the n-th term:
∆0 +(n -1)(∆1 +(n -2)/2(∆2 + ...))
We have (∆0, ∆1, ∆2) = (20, -2, -2), so the expression for the n-th term is ...
tn = 20 +(n -1)(-2 +(n -2)/2(-2))
(a) tn = -n² +n +20
Listing the first 12 terms, we find the 12th term is ...
(b) t12 = -112
Locating the term -36 in the list, we find ...
(c) -36 is term 8
2. x, 1, -6, y, -14For a quadratic sequence the third differences are zero. The second attachment shows us the third differences for this sequence are ...
-3(y +11) = 0 ⇒ y = -11
y -x +21 = 0 ⇒ x = 10
That attachment also shows us the second differences are x-8 (or y+13):
x -8 = 10 -8 = 2
(a) The second difference is 2.
(b) The first term is 10.
__
Additional comment
The ability of this free calculator app to perform arithmetic symbolically and to find differences of successive list elements is very helpful for solving questions related to sequences. The linear and quadratic regression capabilities can also be useful for some questions. It pays to know your tools.
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Help me please!!! what is the volume of this figure? I will mark you brainliest!
The volume of the trapezoidal prism is 420 cm³
What is volume?Volume is the amount of space that is occupied by a three dimensional shape or object.
The volume of a trapezoidal prism is the product of the base area and its height.
For the trapezoidal prism:
Area of base = (1/2)(15 + 5) * 7 = 70 cm²
Volume of Prism = Area of base * height = 70 cm² * 6 cm = 420 cm³
The volume of the figure is 420 cm³
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In the year 2000, population
In the year 2000, it was estimate that the population of the world was 6, 082, 966, 429 people.
What was the world population in 2000 ?Based on data provided by the table give, the global population in the year 2000 was estimated to be around 6, 082, 966, 429 individuals. This remarkable figure, serving as a testament to the expansive tapestry of humanity, reflects the vastness and intricacy of our interconnected world during that period.
Within the context of demographic analysis, the United Nations diligently compiled and analyzed extensive data to derive this population estimate for statistical reasons.
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The full question is:
In the year 2000 the world population was
Find the volume of a cone of radius 3.5cm and vertical height 12 cm.
Answer:
Volume ≈ 153.93804 cm^3
Rounded to the nearest whole number, the volume of the cone is approximately 154 cm^3.
Step-by-step explanation:
Let z=f(u,v)=sinucosv
, u=4x2−5y
, v=3x−5y
,
and put g(x,y)=(u(x,y),v(x,y))
. The derivative matrix D(f∘g)(x,y)=
(
,
To find the derivative matrix of the composition of functions f∘g, we need to compute the partial derivatives of f with respect to u and v, and then evaluate them at the point (u(x, y), v(x, y)). Let's calculate the partial derivatives first:
∂f/∂u = cos(u)cos(v)
∂f/∂v = -sin(u)sin(v)
Now, let's substitute u = 4x^2 - 5y and v = 3x - 5y into the partial derivatives:
∂f/∂u = cos((4x^2 - 5y))cos((3x - 5y))
∂f/∂v = -sin((4x^2 - 5y))sin((3x - 5y))
The derivative matrix D(f∘g)(x, y) is a 1x2 matrix (a row vector) where each entry represents the partial derivative of f∘g with respect to x and y, respectively.
D(f∘g)(x, y) = (∂f/∂u ∂f/∂v) evaluated at (u(x, y), v(x, y))
D(f∘g)(x, y) = (cos((4x^2 - 5y))cos((3x - 5y)), -sin((4x^2 - 5y))sin((3x - 5y)))
can someone answer the ones i got wrong please
When a student is selected at random, the solution for the various possible outcome would be given below as follows:
p(pass or did not study)=0.409
p(pass or did study)=0.312
p(fail and pass)= 0.201
p(pass or fail)= 1
How to calculate the possible outcome of the following given event?The formula that is used to calculate probability = possible outcome/sample space.
The total number of scores of the statistics students = 93
For p(pass or did not study):
possible outcome = 38
sample size = 93
probability = 38/93 = 0.409
For p(pass or did study):
possible outcome = 29
sample size = 93
probability = 29/93 = 0.312
For p(fail and pass):
p(fail) = 26/93
p(pass) = 67/93
probability = 26/93× 67/93
= 1742/8649
= 0.201
For p(pass or fail);
P(pass) = 67/93
P(fail) = 26/93
Probability of pass or fail = 67/93+26/93
= 93/93 = 1
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thomas has a cube with the numbers 3,4,5,7,8 and 9 written on its faces. he rolls the cube twice and records the outcome. What is the probability that both numbers are greater than 5.
a) 1/9 b)1/4 c)1/5 d)1/16
Answer:
None of the options provided (a, b, c, d) matches the correct probability. The correct probability is 1/18.
Step-by-step explanation:
Beth and Kelly spent the same total amount of money for dog sitting while on vacation. Beth took her dog, Pockets, to Rover Sleepover and was charged $24.50 per day and a fee of $90.50 for food and cleaning. Kelly took her dog, Monty, to Pet Palace and was charged $32 per day and a $45.50 cleaning fee.
How many days were Beth and Kelly on vacation?
Beth and Kelly were on vacation for 6 days. both spent same amount of money for dog sitting while on vacation.
Let's assume the number of days Beth and Kelly were on vacation is represented by 'd.'
For Beth:
Total cost for dog sitting = (Cost per day * Number of days) + Cleaning and food fee
24.50d + 90.50
For Kelly:
Total cost for dog sitting = (Cost per day * Number of days) + Cleaning fee
32d + 45.50
Since both Beth and Kelly spent the same amount, we can set their total costs equal to each other and solve for 'd':
24.50d + 90.50 = 32d + 45.50
Rearranging the equation:
24.50d - 32d = 45.50 - 90.50
-7.50d = -45
Dividing both sides by -7.50:
d = -45 / -7.50
d = 6
Therefore, both Beth and Kelly were on vacation for 6 days.
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