PLEASE HELP, WILL MARK BRANLIEST!!
The half-life of cobalt-60 is 10.47 min. How many grams of cobalt-60 remain after 104.7 min if you start with 1024g?

Answers

Answer 1

Answer: 1 gram

Explanation:

- the equation is 1024(.5)^10

• so 1024g is your initial amount and it’s the amount that is being decayed

• since it’s half-life, the decay factor is 0.5

• the half life is 10.47 minutes, so 10.47 minutes would be considered one round of half life.

-basically, if you were finding the half life after 10.47 minutes you would use the equation 1024(.5)^1.

-as said, it’s raised to the 1st power because 10.47 minutes is one round.

• since you’re looking for the amount after 104.7 minutes, the equation is raised to the 10th power because 104.7 / 10 = 10.47. so 104.7 is 10 rounds of half-life.

- so 1024(.5)^10 = 1

so the half-life of 1024g of Cobalt-60 after 104.7 minutes is 1

hope this helps :)


Related Questions

An intravenous a solution to replace potassium loss contains 35mEq/L each of K+and CL- . How many moles of CL- are in 1.8 L of the solution

Answers

The moles of Cl⁻ ions present in 1.8 L of the intravenous solution is 0.063 moles.

What are the moles of Cl⁻ ions in the intravenous solution?

The moles of Cl⁻ ions in the intravenous solution are calculated using the conversion factor between mEq/L to mmoles

The conversion between milliequivalents per Liter and millimoles per Liter is:

1 Millimole per Liter = 1 Milliequivalents per Liter.

Hence 35 mEq/L = 35 mmol/L

The mmoles of Cl⁻ ions in 1.8 liters of the intravenous solution will be:

moles of Cl⁻ ions = 35 mmol/L * 1.8 L

moles of Cl⁻ions = 63 mmoles

Converting to moles by dividing by 1000:

moles of Cl⁻ ions = 63 / 1000

moles of Cl⁻ ions = 0.063 moles.

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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
[] → CH3,CH3,(g) +O2,(g) → CO2,(g) + H2O(g)

Answers

[tex]$$\mathrm{CH}_3 \mathrm{CH}_3(y)+\mathrm{O}_2(q) \rightarrow \mathrm{CO}_2(q)+\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]

[tex]\begin{tabular}{l|l}$C=2$ & $C=1$ \\$H=6$ & $H=2$ \\$O=2$ & $0=3$\end{tabular}[/tex]

First balance carbon then balms oxygen and followed by hydrogen through adding odd number Infront  of the reactant and product.

[tex]$$2\mathrm{CH}_3 \mathrm{CH}_3(y)+7\mathrm{O}_2(q) \rightarrow 4\mathrm{CO}_2(q)+6\mathrm{H}_2 \mathrm{O}(\text { I })$$[/tex]

[tex]\begin{tabular}{l|l}$C=4$ & $C=4$ \\$H=12$ & $H=12$ \\$O=14$ & $0=14$\end{tabular}[/tex]

What is  stoichiometric coefficients?

Stoichiometry as the calculation of products and reactants in a chemical response. It is fundamentally concerned with numbers. Stoichiometry is an critical concept in chemistry that makes a difference us utilize adjusted chemical conditions to calculate sums of reactants and products. Here, we make utilize of proportions from the adjusted condition. In common, all the responses that take put are subordinate on one primary figure, how much substance is present. Stoichiometry makes a difference us determine how much substance is required or is present.

Stoichiometry helps us determine

Reactants Products mass Molecular weight Chemical equations Formula.

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Which of the following statements about effective nuclear charge is true?
Electrons in the same shell screen each other much more than those in core shells.
The valence electrons are very effective in screening the core electrons from the full charge of
the nucleus.
The effective nuclear charge experienced by valence electrons increases as we move right to
left across a period.
The effective nuclear charge experienced by valence electrons increases as we move left to
right across a period.

Answers

The valence electrons are very effective in screening the core electrons from the full charge of the nucleus statements about effective nuclear charge is true

Effective nuclear charge: What is it?

The attractive positive charge of nuclear protons acting on valence electrons is known as effective nuclear charge. Due to the shielding effect, the effective nuclear charge is always smaller than the total amount of protons in a nucleus. In comparison to all other periodic table trends, effective nuclear charge lags behind.

Although a fluorine atom's nucleus has a 9-volt charge Z, the core electrons—four from the 1s and 2s orbitals—and some of the 7 electrons in the 2p orbitals—screen the valence electrons noticeably. Therefore, the cation of sodium has the highest effective nuclear charge.

Effective nuclear charge lowers down a group and rises from left to right across a period in the periodic table.

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what is the pH solution containing 0.3 M HCOOH and 0.52 M HCOOK?

Answers

First, we need the reaction to start the exercise.

HCOOH(aq) + H2O(l) = H3O+(aq) + HCOO-(aq)

HCOOK => HCOO- + H+

------------------------------------------------------------------------

pH)

We have here an ionic equilibrium, HCOOH is a weak acid.

pKa = 3.77 (from tables)

The concentration of HCOOH 0.3 M

The concentration of HCOO- = 0.52 M HCOOK.

If we propose Ka for HCOOH(aq)

[tex]Ka\text{ = }\frac{\lbrack H_3O^+\rbrack x\lbrack HCOO-\rbrack^{_{}}}{\lbrack HCOOH\rbrack}[/tex]

We clear (H3O+) and we apply -log and we get this:

[tex]pH\text{ = }pKa+log(\frac{[HCOO^-]}{[HCOOH]})[/tex][tex]pH=3.77+log(\frac{[0.52]}{[0.30]})\text{ }[/tex]

Answer: pH = 4.01

--------------------------------------------------------------------------------------------------

pOH)

pH + pOH = 14

(This formula appears from the ionic equilibrium of water)

pOH = 14 - 4.01 = 9.99

Answer: pOH= 9.99

--------------------------------------------------------------------------------------------------

What is the pressure, in mmHg, of a 4.50 g sample of O2 gas, which has a temperature of 33.0 °C, and a volume of 2600 mL?

Answers

We are going to assume that the gas behaves like an ideal gas, so we can apply the following equation:

[tex]\begin{gathered} PV=nRT \\ P=\frac{nRT}{V} \end{gathered}[/tex]

Where,

P is the pressure of the gas in atm

V is the volume of the gas in liters, 2600mL=2.6L

n is the number of moles

R is a constant, 0.08206atm.L/mol.K

T is the temperature in Kelvin, 33.0°C=306.15K

Now we need to find the moles of O2 to plug into the equation. We divide the grams by the molar mass of O2. The molar mass of O2 is 31.9988g/mol.

[tex]\begin{gathered} molO_2=4.50g\times\frac{1molO_2}{MolarMass,gO_2} \\ molO_2=4.50g\times\frac{1molO_2}{31.9988gO_2}=0.140molO_2 \end{gathered}[/tex]

We substitute the values in the ideal gas equation:

[tex]\begin{gathered} P=\frac{nRT}{V} \\ P=\frac{0.140molO_2\times0.08206\frac{atm.L}{mol.K}\times306.15K}{2.6L} \\ P=1.36atm \end{gathered}[/tex]

Now, we convert the atm to mmHg:

[tex]\begin{gathered} P=1.36atm\times\frac{760mmHg}{1atm} \\ P=1033mmHg \end{gathered}[/tex]

Answer: The pressure of the gas is 1033mmHg

Write the correct formula for the following compound:

zinc phosphate

Answers

The correct formula of zinc phosphate is Zn₃(PO₄)₂.

What is chemical formula?

Chemical formula is a notation indicating the number of atoms of each element present in a compound.

The chemical or molecular formula shows the type of atoms of an element in a chemical compound and the number of each atoms in the element.

Zinc phosphate is a compound that possess the following elements:

Zinc (Zn)Phosphorus (P)Oxygen (O)

This means that the chemical formula of zinc phosphate will show the number of atoms of zinc, phosphorus and oxygen present in the compound.

Therefore, this means that the chemical formula of the compound is Zn₃(PO₄)₂.

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when the solute particles mixed with water what do they become

Answers

Answer:

the water becomes solvent, and the mixture becomes the solution.

Explanation:

Answer:

a solution

Explanation:

solute and solvent(water) put together would produce a solution

How many moles of sulfur dioxide in 85 grams sulfur dioxide?

Answers

Answer:

1.33 moles

Explanation:

[tex]n = \frac{mass}{molar \: mass} [/tex]

note Molar Mass according to websearch is 64 066

you could calculate this using the individual elements on a periodic table (sulfur and oxygen) and their masses

[tex]n = \frac{85}{64.066} [/tex]

[tex]n = 1.33[/tex]

A student dissolves a white crystalline solid substance in water to form a solution. When a conductivity meter is immersed in the solution, the reading recorded was 35.80 mSiemens/cm. Which of the following compounds could be the solute in this solution?

Answers

ANSWER

STEP-BY-STEP EXPLANATION

What is TRUE about the precipitin test?

A.
It determines if blood is type A, B, or O.

B.
It uses hydrogen peroxide to make a chemical reaction.

C.
It requires a very small amount of blood.

D.
It can only be used on blood that is still wet.

Answers

Precipitin test is used to determine antigens and human blood from other sources. It is widely used in forensic laboratories. Thus we can determine the blood groups such as A, B,O etc.

What is precipitin?

Precipitin is an antibody which precipitates when other antigens binds with it. Thus, antigens from other source can be easily determined using precipitin reaction.

Precipitin reaction involves a specific serological precipitation of an antigen . Varying amounts of the antigen is added to the serum source where each antigen molecule extensively bound to the antibody excess zone.

A small antibody - antigen complex is formed there with  crosslinking reaction. The advantages of this test is that very small amount of test sample is needed and about fifty specimens can be easily tested within few minutes.

Therefore, the precipitin test can used to determine the antigen type of blood A, B or O. Hence, option A is correct.

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Answer: A

Explanation:

Calculate the percent nitrogen in NH4NO3.Group of answer choices17.5%8%60%28%35%

Answers

In order to find the percent composition for Nitrogen in NH4NO3, we will need to work with all the masses from this compound, so let's list them below:

NH4NO3 = 80.04 g/mol

N = 14 grams, but we have 2 nitrogens, therefore = 28 grams

H = 1 gram, 4 Hydrogens = 4 grams

O = 16 grams, 3 Oxygens = 48 grams

Now we take the total mass of the compound as 100% and check how much it will be made by Nitrogen:

80.04 g = 100%

28 g = x %

x = 34.98%, which we can round up to 35% therefore the answer will be letter E

Complete the second column of the table.Express your answer using two significant figures.

Answers

Avogadro's Law is

[tex]\frac{V_1}{n_1}=\frac{V_2}{n_2}[/tex]

In the second column of the table, we have to find n1 when V1 = 51 mL, V2 = 13 mL, and n2 = 2.68x10^-4 mol. Solve the equation for n1.

[tex]\begin{gathered} n_1=\frac{V_1\cdot n_2^{}}{V_2}=\frac{51mL\cdot2.68\times10^{-4}mol}{13mL} \\ n_1=11\times10^{-4}mol \\ n_1=0.0011mol \end{gathered}[/tex]

Therefore, the number of moles of n1 is 0.0011 moles.

What is the percent mass of 42.5 g KCl dissolved in 122.5 g water?

Answers

Answer

% mass of KCl = 25.76%

Explanation

Given:

mass of KCl = 42.5 g

mass of water = 122.5 g

Required: The % mass of KCl

Solution:

Step 1: Calculate the total mass

42.5 g + 122.5 g = 165 g

Step 2: Calculate the % of KCl

%KCl = (42.5/165)*100

%KCl = 25.76%

Calculate the wavelength and energy of light that has a frequency of 1.1 * 10^17 Hz

Answers

The wavelength and the energy would be 2.72 × 10⁻⁹  meter 6.886 × 10⁻¹⁷ Joules and respectively if the light has s a frequency of 1.1 × 10¹⁷ Hz.

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave.

C = λν

As given in the problem we have to calculate the energy of the light if the frequency of light is  1.1 × 10¹⁷ Hz

The wavelength of the light = 3 × 10⁸ / 1.1 × 10¹⁷

                                               = 2.72 × 10⁻⁹  meter

The energy of the light = h ν

                                       = 6.26 × 10⁻³⁴ × 1.1 × 10¹⁷

                                        = 6.886 × 10⁻¹⁷ Joules

Thus, the wavelength and the energy would be 2.72 × 10⁻⁹  meter 6.886 × 10⁻¹⁷ Joules and respectively if the light has s a frequency of 1.1 × 10¹⁷ Hz.

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Please help me with this question. ​

Answers

Answer:1=B

2=A

Explanation:

Drag each tile to the correct location.
What types of mixtures are these?
peanuts and almonds mixed
food coloring dissolved in water
cup of tea and sugar
together in a bowl
a bucket full of sand and gravel
Homogeneous Mixture
Heterogeneous Mixture

Answers

Hetergeneous mixture   peanuts and almonds mixed ,a bucket full of sand and gravel. Homogeneous Mixture -food coloring dissolved in water together in a bowl,cup of tea and sugar .          

A Heterogeneous Mixture: what is it?

When the composition of a mixture is not constant throughout the mixture, the mixture is said to be heterogeneous. A variety of  make up vegetable soup. Each mouthful of soup will have variable proportions of the soup's various veggies and other ingredients.

Describe homogenous mixture using an example.

For illustration A mixture of sugar and water, or salt and water, both of which have the same component ratio throughout the mixture, are examples of homogenous mixes.

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11) A sample of carbon dioxide has a volume of 26 mL at 11 °C and 623 torr. How many grams of CO2 are in the sample?

Answers

Explanation:

We have a gas sample of carbon dioxide and we know its volume, the pressure and the temperature. We can find the number of moles of that sample using the ideal gas law.

P * V = n * R * T

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas law and T is the temperature.

R = 0.082 atm*L/(mol*K)

Since R is in atm*L/(mol*K) we have to convert the volume from mL to L, the temperature from °C to K and the pressure from torr to atm.

1000 mL = 1 L

V = 26 mL = 26 mL * 1 L/(1000 mL)

V = 0.026 L

760 torr = 1 atm

P = 623 torr = 623 torr * 1 atm/(760 torr)

P = 0.820 atm

T = (273.15 + 11 ) K

T = 284.15 K

Now we can replace these values in the formula and solve it for n to find the number of moles that are present in the sample.

P * V = n * R * T

n = P * V/(R * T)

n = 0.820 atm * 0.026 L/(0.082 atm*L/(mol*K) * 284.15 K)

n = 0.000915 mol

Finally we can convert the moles of the sample into grams using the molar mass of carbon dioxide.

molar mass of C = 12.01 g/mol

molar mass of O = 16.00 g/mol

molar mass of CO₂ = 1 * 12.01 g/mol + 2 * 16.00 g/mol

molar mass of CO₂ = 44.01 g/mol

mass of CO₂ = 0.000915 mol * 44.01 g/mo

mass of CO₂ = 0.040 g

Answer: There are 0.040 g of carbon dioxide in the sample.

predict the product of this combination reaction. Include thephysical state of the product and balance the reaction. Hint: You have aluminumand sulfide ions in your product. What are the charges of those ions? How wouldyou write the formula so that the charges cancel?

Answers

We are asked to predict a reaction having two solids as reactants. The reaction occurs in the solid phase. Initially the elements are in their natural state, so they will have an oxidation state equal to 0.

This is a combination reaction, so the product will be a combination of aluminum and sulfur.

When combined, aluminum has an oxidation state of +3, this means that it gives up its electrons. Sulfur has an oxidation state of -2. The resulting product will be aluminum sulfide (Al2O3). so, the reaction will be:

[tex]Al_{(s)}+S_{8(s)}\rightarrow Al_2^{+3}S_3^{-2}[/tex]

We must balance the equation.

Let's start with sulfur. We multiply each sulfur-containing molecule by its opposite. In other words, we multiply the S8 molecule by 3 and we multiply the S3 molecule by 8.

And to balance the aluminum we must multiply the aluminum molecule by 16. So, the balanced equation will be:

[tex]16Al_{(s)}+3S_{8(s)}\rightarrow8Al_2^{+3}S_{3(s)}^2[/tex]

So, the answer, in summary, will be:

We obtain a product with the formula Al2O3. Al is an ion with a charge of +3, and S is an ion with a charge of -2.

For each pair of bonds, indicate the more polar bond, and use an arrow to show the direction of polarity in each bond.a. C-O and C-Nb. P-Br and P-Clc. B-O and B-Sd. B-F and B-I

Answers

To calculate how polar a bond is we can look at the difference in electronegativity. An electronegativity greater than 1.7 represents an ionic bond, a bond less than 1.7 will be a covalent bond.

Let's see wich is the wich is the electronegativity of each element:

C=2.55

O=3.44

N=3.04

The difference of electronegativity of each pair of bonds will be:

Polar bonds are covalent bonds that have a difference in electronegativities. The greater the difference in electronegativity, the greater the polarity.

So, in this case, C-O bond will be more polar that C-N bond, the polarity.

The direction of the polarity will go towards the more electronegative element. So, we will have:

Answer: The most polar bond will be the C-O bond and the direction of polarity will be toward oxygen for the C-O bond and toward nitrogen for the C-N bond.

Water is a polar solvent; gasoline is a non-polar solvent. Which compound will dissolve in gasoline? Check all that apply.

CCl4
NaCl
NaOH
KCl

Answers

Answer:

[tex]\blue{\boxed{\red{\sf CCl_4 \: will \: dissolve \: in \: gasoline}}}[/tex]

Explanation:

The simple concept that would be applied is

'Like Dissolves Like.'

According to this, the polar solvent will dissolve the polar solutes and the non-polar solvent will dissolve the non-polar solutes.

classification of given compounds as polar or non-polar,

[tex]\begin{gathered}\boxed{\begin{array}{c|c} \bf Polar & \bf Non-polar \\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf NaCl & \sf CCl_4 \\ \\ \sf NaOH & \sf - \\ \\ \sf KCl & \sf - \end{array}} \\ \end{gathered}[/tex]

Also, the given data says water is a polar solvent while gasoline is a non-polar solvent. From all the information we have, we can conclude that CCl4 is the only compound that will dissolve in gasoline.

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need help with this pleaseeeeeeeeeeeeeeWhat trends do you see in the organisms of the ecosystem if youdecrease sunlight A. Increase in energy storage moleculesB. Decrease in H2OC. Decrease in energy storage moleculesD. Increase in CO2

Answers

Answer:

Explanations:

Answer:

Explanations:

A saturated solution of MgF2 is prepared at 27°C. After equilibrium has been reached, the concentrationof magnesium ions in the solution is found to be 1.2 x 10-3 M. Type in the correct values for A and B inthe ICE table.A:Mg2+(aq)2F (aq)1SolidAMBMB:DONEс-Dissolvedsolid+?M+?MELess solid?M?MIntro

Answers

Answer:

A: 0

B: 0

Explanation:

Initially the concentration of Mg+2 ions and F- ions is zero. The ICE table is:

Can you help show me the conversion works for this problem in my online homework please?

Answers

There are 2.04*10^-4 moles of hydrogen.

To start the calculation it is necessary to use the molar mass of glycine:

- Glycine molar mass: 75.08 g/mol.

From the formula of glycine, we know that in 75.08g of glycine, there are 5 moles of hydrogen. So, in 3.06*10^-3g of glycine will be another amount of hydrogen, and we can calculate it with a mthematical Rule of Three:

[tex]\begin{gathered} 75.08\text{gGlycine}-5\text{molHydrogen} \\ 3.06\cdot10^{-3}\text{gGlycine}-x=\frac{3.06\cdot10^{-3}\text{gGlycine}\cdot5\text{molHydrogen}}{75.08\text{gGlycine}} \\ x=2.04\cdot10^{-4}\text{molHydrogen} \end{gathered}[/tex]

So, there are 2.04*10^-4 moles of hydrogen in 3.06*10^-3g of glycine.

There are 215.0 mol of an unknown gas stored at a temperature of 1110 K in a large, 395 L container. R=0.0821 L·atm/(mol·K) In atm, what is the approximate pressure of the gas?

Answers

Answer:

To solve this problem we use the ideal gas equation:

[tex]P.V=n.R.T[/tex]

Where:

P is the pressure of the gas

V is the volume of the container (395 L)

n is the number of moles present (215 mol)

R is the ideal gas constant (0.0821 L.atm/mol.K)

T is the temperature of the gas (1110 K)

So to calculate the pressuere we have to use the equation and the data:

[tex]\begin{gathered} P=\frac{n.R.T}{V} \\ P=\frac{215mol\text{ . }0.0821\frac{L.atm}{mol.K}\text{ . }1110K}{395L} \\ P=\text{ 49.6 atm} \end{gathered}[/tex]

So the answer is 49.6 atm.

Farmers use primarily two fertilizers - ammonium nitrate and ammonium phospate. Which contains a greater percentage of nitrogen by mass? Write the formula for ammonium nitrate:-----------------------------------------------------------||________________________________First, let's add up the total molar mass of ammonium nitrate below:-----------------------------------------------------------||________________________________Now, let's calculate the percentage of nitrogen in ammonium nitrate:-----------------------------------------------------------||________________________________Now, let's write the formula for ammonium phosphate:-----------------------------------------||______________________First, let's add up the total molar mass of ammonium phosphate below:-----------------------------------------------------------||________________________________Now, let's calculate the percentage of nitrogen in ammonium phosphate:-----------------------------------------------------------||________________________________Which contains a greater percentage of nitrogen by mass?

Answers

Answer:

The nitrogen in ammonium nitrate contains a greater percentage of nitrogen by mass

Explanations:

The formula for ammonium nitrate is given as NH4NO3.

Determine the molar mass of NH4NO3

Molar mass = 14 + 4(1) + 14 + 3(16)

Molar mass .= 14 + 4 + 14 + 48

Molar mass of NH4NO3 = 80g/mol

Determine the percentage of nitrogen in the compound

%N = 28/80 * 100

%N = 35%

The formula for ammonium phosphate is (NH4)3PO4

Determine the molar mass of (NH4)3PO4

Molar mass = 3(14) + 4(3) + 4(16) + 3(31)

Molar mass = 42 + 12 + 64 + 31

Molar 1ass = 149g/mol

Determine the percentage of nitrogen in ammonium phosphate:

%N = 42/149 * 100

%N = 28.18%

Hence the nitrogen in ammonium nitrate contains a greater percentage of nitrogen by mass

You heat 3.939 g of a mixture of Fe3O4 and FeO to form 4.197 g Fe2O3. The mass of oxygen reacted is

Answers

Explanation:

A mixture of differet iron oxides is heated and they it absorbs oxygen from the air to form iron (II) oxide. The reaction can be represented like this:

2 Fe₃O₄ + 2 FeO + O₂ ----> 4 Fe₂O₃

The mass of the mixture of Iron oxides is 3.939 g. The mass of Fe₂O₃ formed is greater than the original mass, it is 4.197 g. That means that the sample absorbed oxygen.

mass of Fe₃O₄ + mass of FeO = 3.939 g

mass of Fe₂O₃ = 4.197 g

The law of conservation of mass states that no mass is loss or created in a chemical reaction. A mass balance can be written:

mass of Fe₃O₄ + mass of FeO + mass of O₂ = mass of Fe₂O₃

The known values can be replaced in the equation, and it can be solved for mass of O₂ to obtain the answer to the problem.

mass of Fe₃O₄ + mass of FeO + mass of O₂ = mass of Fe₂O₃

mass of O₂ = mass of Fe₂O₃ - (mass of Fe₃O₄ + mass of FeO)

mass of O₂ = 4.197 g - 3.939 g

mass of O₂ = 0.258 g

Answer: the mass of oxygen reacted is 0.258 g

In order to both shift the equilibrium and increase the amount of NH3, we should

Answers

Answer:

D. 2 and 3 only.

Explanation:

First let's remember the Le Chatelier's Principle: Le Chatelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish equilibrium.

Let's see the reaction:

[tex]N_2+3H_2\leftrightarrows2NH_3,\text{ }\Delta H=-92\text{ kJ.}[/tex]

You can note that this reaction is exothermic. If we want the equilibrium to move to the left, we have to increase the temperature. In this case, we don't want that because we want to increase the concentration of NH3 and this means that the equilibrium goes to the right, so we have to decrease the temperature.

In the case of pressure, if we want to reach the equilibrium to the right, where is NH3, we have to increase the pressure because the pressure will move in such a way as to decrease the pressure again.

The answer would be D. 2 and 3 only.

Fe2O3 + 3H2 = 2Fe + 3H2OCalculate how many grams of iron can be made from 24.5 grams of iron (III) oxide.

Answers

Explanation:

Iron (III) oxide will react with hydrogen gas to produce iron and water. They will react according to the following equation.

Fe₂O₃ + 3 H₂ -----> 2 Fe + 3 H₂O

We have to find the grams of Fe that can be made from 24.5 g of Fe₂O₃. So, first we have to convert those grams into moles using the molar mass of iron (III) oxide.

molar mass of Fe₂O₃ = 159.69 g/mol

mass of Fe₂O₃ = 24.5 g

moles of Fe₂O₃ = 24.5 g * 1 mol/(159.69 g)

moles of Fe₂O₃ = 0.153 mol

Fe₂O₃ + 3 H₂ -----> 2 Fe + 3 H₂O

According to the coefficients of the equation, we know that 1 mol of Fe₂O₃ will react with 3 moles of H₂ to give 2 moles of Fe and 3 moles of H₂O. So the molar ratio between Fe₂O₃ and Fe is 1 to 2. We can use that relationship to find the number of moles of Fe that can be made from 0.153 moles of Fe₂O₃.

1 mol of Fe₂O₃ : 2 moles of Fe molar ratio

moles of Fe = 0.153 moles of Fe₂O₃ * 2 moles of Fe/(1 mol of Fe₂O₃)

moles of Fe = 0.306 moles

So we found that we can produce 0.306 moles of Fe from 0.153 moles of Fe₂O₃ or 24.5 g of it. Finally we can convert the 0.306 moles of Fe into grams using the molar mass of Fe.

molar mass of Fe = 55.85 g/mol

mass of Fe = 0.306 moles * 55.85 g/mol

mass of Fe = 17.1 g

Answer: 17.1 g of iron can be made from 24.5 g of iron (III) oxide.

16.Solid carbon dioxide (dry ice) passes directly into the gaseous state. The name for this process is...Select one:a. boiling.b. evaporation.c. melting.d. sublimation.

Answers

Answer:

[tex]D[/tex]

Explanation:

Here, we want to select the correct option

We evaluate each of the options as follows:

a) Boiling

It is a state that occurs when the vapor pressure equals atmospheric pressure for liquid substances

b) Evaporation

Evaporation occurs when liquid substances change directly into the gaseous state

c) Melting is the change from the solid state to the liquid state

d) Sublimation is the direct change of a substance from the solid to the vapor state. We can see this in iodine and naphthalene

How many coulombs of charge are needed to produce 53.5 mol of solid zinc?

Answers

The charge of 10,325,500 coulombs is needed to produce 53.5 mol of solid zinc.

What is the coulomb charge?

The coulomb is the unit of electric charge in the International System of units and is represented by 'C'. In the S.I., it is equal to the electric charge delivered by a 1-ampere constant current in 1 second and to elementary charges, about 6.2×10¹⁸ e.

The coulomb in terms of the ampere and second can be described as 1 C = 1 A × 1 s. The SI base units fixed the numerical value of the elementary charge expressed in coulombs.

Solid zinc can be formed by chemical reactions:

Zn²⁺  +  2e⁻   →  Zn (s)

One mole of zinc is produced by using two moles of electrons.

One mole of electrons is equal to one faraday electricity.

Then, the total electrons required = 2×53.5 = 107 F

The charge (in coulombs) on one mole of electrons = 96500 C

Amount of charge required to form zinc = 96500 × 107 = 10,325,500 C

Learn more about coulomb, here:

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