Answer:
○ [tex]\displaystyle \pi[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3[/tex]
OR
[tex]\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:2x,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(2x + \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-1\frac{3}{4}\pi, 0],[/tex]from there to [tex]\displaystyle [-\frac{3}{4}\pi, 0],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Answer:
[tex]\pi[/tex]
Step-by-step explanation:
The trigonometric function shown on the graph is a continuous function, and so its period is the length of one wave of the function (i.e. the horizontal distance between a peak and the next peak, or a trough and the next trough).
From inspection of the graph, the horizontal distance between one peak and the next of the given function is [tex]\pi[/tex].
Therefore, the period of this trigonometric function is [tex]\pi[/tex]
21b-32+7b-20b=?
Tell fast pls
21b-32+7b-20b=
21b + 7b - 20b - 32
8b - 32
Hello!
21b-32+7b-20b=
21b +7b -20b -32
= 28b -20b - 32
= 8b -32
The center of the sphere is C and its circumference is 7pi centimeters.
Find the radius of the sphere. Find the diameter of the sphere.
Answer:
384800 square centimeters (cm²); 3.848 × 107 square millimeters (mm²); 1.48572E-5 square miles (mi²); 46.0217 square yards (yd²)
Step-by-step explanation:
write 45920 in word form
Answer:
forty five thousand and nine hundreds twenty
Step-by-step explanation:
what is the measurement of DA (parallelogram)
obcjkaosicabkajiuhcabaca
Please help!! <3
Thanks in advance!!
Use the graph that shows the solution to f(x)=g(x).
f(x)=−(x+2)(x−2)
g(x)=2|x+2|
What is the solution to f(x)=g(x)?
Select each correct answer.
−2
0
2
4
Answer: -2, 0
Step-by-step explanation:
The graph this represents this system is the second graph since the vertex of the absolute value function is at x=-2.
So, to find the solutions, we can find the intersection points. These are at x=-2 and x=0.
3x+4y=36
Y=-1/2+8
How do I solve this?
Answer:
x = 2
Step-by-step explanation:
3x+4y=36
Y=-1/2+8
Now we substitute y with -1/2+8.
3x + 4(-1/2+8) = 36
3x + 4(7.5) = 36
3x + 30 = 36
3x = 6
x = 2
Have an amazing day!!
Please rate and mark brainliest!
Find the area of each triangle b= 12.4cm. h= 18 cm
[tex] \frac{1}{2} \times b \times h \\ \frac{1}{2} \times 12.4 \times 18 \\ 6.2 \times 18 \\ 111.6 {cm}^{2} [/tex]
Omar thinks his pet goldfish, Finn, might be lonely. So, Omar buys another goldfish to keep Finn company. He also buys a large 10-gallon tank so the two fish can swim together. If Finn currently lives in a 2-quart fish bowl, how many times bigger is his new tank than his old bowl?
Answer:
i think 20 times bigger
Step-by-step explanation:
Answer:
times 20
Step-by-step explanation:
2 quart to 10 gallon
4 quarts= 1 gallon
So 2quarts x 20 quarts= 40 quarts= 10 gallons
On your way to a tournament, you meet six knights, each accomplished by six squires. Each squire leads two horses by reins, and on each horse are seated two young children. How many people and animals are going to the tournament?
Answer:
72
Step-by-step explanation:
Answer: 12 animals 36 people , in total 48 its so easy just adding and multiplying :)
Step-by-step explanation:6 knights 6 squires =12, then animals human people 6 time animals 2 is 12 animals then more humans 2 times 12 the horses is 24 in total add up humans 24+12=36 and animals is 12 so 36 people, and 12 animals in total 36+12 is 48
Segments that appear to be tangent are tangent to both circles, and CD=32. Find AC.
Answer:
x=8.4
i looked it up:)
The cpi is currently 153. if a coffee maker costs $31.90 today, how much did one cost in 1983, to the nearest cent? a. $20.85 b. $21.20 c. $26.60 d. $48.81
its C
One coffee maker's cost in 1983 was $20.85 if the current CPI is 153 option (a) is correct.
It is given that the CPI is currently 153 if a coffee maker costs $31.90 today. It is required to find how much did one cost in 1983.
What is CPI?It is defined as the tool to measure inflation that indicates between two periods how much cost is increased. It can be represented by [tex]\rm CPI_t[/tex] for the given time 't'
The formula for finding the CPI:
[tex]\rm CPI_t = \frac{C_t}{C_0}\times 100[/tex]
Where [tex]\rm c_t[/tex] is the cost in the current market
[tex]c_0[/tex] is the cost at the given period.
We have in the question:
[tex]\rm c_t = \$31.90\\\\\rm CPI_t = 153[/tex]
Putting these values in the CPI formula, we get:
[tex]\rm 153= \frac{31.90}{C_0}\times 100\\\\\rm c_0 = \frac{3190}{153} \\\\\rm c_0 = \$20.84 \approx \$20.85[/tex]
Thus, one coffee maker's cost in 1983 was $20.85 if the current CPI is 153.
Learn more about the CPI here:
https://brainly.com/question/26682248
A cylinder has a base diameter of 16cm and a height of 20cm. What is its volume in cubic cm, to the nearest tenths place?
Answer:
4021.76
Step-by-step explanation:
v= πr^2h
3.142x8×8×20
Nathan is going to invest in an account paying an interest rate of 4. 9% compounded continuously. How much would Nathan need to invest, , for the value of the account to reach $34,000 in 9 years?
[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$34000\\ P=\textit{original amount deposited}\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ t=years\dotfill &9 \end{cases} \\\\\\ 34000=Pe^{0.049\cdot 9}\implies 34000=Pe^{0.441}\implies \cfrac{34000}{e^{0.441}}=P\implies 21875.35\approx P[/tex]
HELP ME PLEASE!!! i cant do this and it is due in 10 minutes.
25% of 7th grade classrooms are math classrooms. The 7th grade area has three math classrooms. How many classrooms are there in the seventh grade area?
Answer:
12 classroomsStep-by-step explanation:
25% of classrooms is 3, find 100%
25% ⇒ 3100% ⇒ xSince 100% is 4 times 25%, the corresponding number will also be 4 times greater:
x = 4*3 = 122022
Question 4
20 pts
nts
Linel and line mare parallel lines that are cut by a transversal.
Let mZ1 = (x+97)° and m2 = (2x+32)". What is mZ1?
12
m
2.
55
ооо
162
65
130
Answer: B
Step-by-step explanation:
These are vertical angles, so x+97=2x+32, meaning x=65.
So, the measure of angle 1 = 65 + 97 = 162 degrees
The value of m∠1, given that m∠1 = x + 97 and m∠2 = 2x + 32 is 162° (2nd option)
How to determine the value of m∠1?First, we shall list out the given parameters from the question. This is given below:
m∠1 = (x + 97)° m∠2 = (2x + 32)°Angle 1 (m∠1 ) =?Next, we shall obtain the value of x. Details below:
m∠1 = m∠2 (vertically opposite angle)
x + 97 = 2x + 32
Solving for x, we have:
97 - 32 = 2x - x
65 = x
Thus,
x = 65
Now, we shall obtain the value of m∠1 as follow:
m∠1 = x + 97
x = 65
Therefore,
m∠1 = 65 + 97
= 162°
Thus, the value of m∠1 is 162° (2nd option)
Learn more about vertically opposite angle:
https://brainly.com/question/29747440
#SPJ2
x=? degrees
WHAT IS THE ANSWER
HELP ASAPPP
Inga, Kai, and Jason volunteer in the school library. They want to find the average number of pages of a library book. It would be unreasonable to calculate the number of pages in every book to find the average. They decide they need to find a valid sample.
Inga suggests choosing 100 books from the history section to get a sample.
Kai suggests randomly selecting 100 books from the library’s entire catalog.
Jason suggests using 100 books from the teen fiction section to get a sample.
Who suggested the best way to produce a random sample that is not biased?
Answer:
Kai suggested the best way to produce a random sample that is not biased
Step-by-step explanation:
Answer:
The answer is Kai suggested the best way to produce a random sample that is not biased
Step-by-step explanation:
Solve: log2(3x 8) = 5 which is an equivalent equation? 25 = 3x 8 52 = 3x 8 25 = [log2(3x 8)]2 52 = [log2(3x 8)]5
The value of the equivalent equation will be 32=3x+8
What will be the value of x?It is given in the question that
[tex]\rm Log_2(3x+8)=5[/tex]
Now from the antilog property property
[tex]\rm x=Log_by[/tex] can be written as below
[tex]b^x=y[/tex]
So the value of [tex]\rm Log_2(3x+8)=5[/tex] will be
[tex]2^5=3x+8[/tex]
[tex]3x+8=32[/tex]
Thus the value of the equivalent equation will be 32=3x+8
To know more about Antilog property follow
https://brainly.com/question/24556465
Answer:
I did it on edgeinuity
Step-by-step explanation:
136<5(-2-4b)-6
-5(1-3x)-3>112
-4(3n+2)-6>-86
-120<4(6+3p)+6p
116<-3(1-5n)+2n
Answer:
x<
−97
45
Answer:
b<
−38
5
n>
−22
3
p>
16
3
n>7
subtract, need help again! thanks a lot.
[tex]\quad\qquad\qquad\huge\underline{\boxed{\sf Aηswer☂ }}[/tex]
Here's the solution ~
# First[tex]\qquad \sf \dashrightarrow \: \sqrt{8} - \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: ( \sqrt{2 \times 2 \times 2} )- \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2\sqrt{ 2} - \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ 2} [/tex]
# Second[tex]\qquad \sf \dashrightarrow \: \sqrt[3]{24} - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: (\sqrt[3]{2 \times 2 \times 2 \times 3}) - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2\sqrt[3]{3} - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt[3]{3} [/tex]
# Third[tex]\qquad \sf \dashrightarrow \: \sqrt[]{125} - \sqrt{45} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt[]{5 \times 5 \times 5} - \sqrt{3 \times 3 \times 5} [/tex]
[tex]\qquad \sf \dashrightarrow \: 5 \: \sqrt[]{5 } - 3\sqrt{ 5} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2 \: \sqrt[]{5 } [/tex]
# Fourth[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{96 } - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{2 {}^{5} \times 3} - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: 2\sqrt[5]{3} - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{3} [/tex]
# Fifth[tex]\qquad \sf \dashrightarrow \: \: \sqrt[]{75} - \sqrt{27} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[]{3 \times 5 \times 5} - \sqrt{3 \times 3 \times3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 5 \sqrt{3} - 3 \sqrt{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2 \sqrt{3} [/tex]
4. Which statement is true for a preimage and its rotated image in the coordinate plane?
A.They are congruent.
B. They are exactly 4 units apart in the coordinate plane.
C. They were rotated around the origin since that is the only point in the plane you can use as the center of rotation.
D. They are two different sizes.
Answer:
C, they are congruent.
Step-by-step explanation:
Rotation only changes the position of the image, not the size. :)
Answer:
C. They were rotated around the origin since that is the only point in the plane you can use as the center of rotation.
explanation:
when you think about it and look at the other problems, they are all going around the center of the grid when rotated, specifically the key word is when rotated, when they are translated they go anywhere they want.
A rectangular piece of paper has an area of 117 square inches and a perimeter of 44 inches. What are the dimensions of the paper?
Answer:
13x9
Step-by-step explanation:
half of perimeret of rectangle L+W
half of perimeter of rectangle = 44/2 = 22
L+W=22
LxW=117
Think of 2 numbers that added =22 and multiplied =117
13+9 =22
13x9 =117
ASAP ANSWER PLEASE! 20 POINTSS!
A cylindrical shaped silo has a diameter of 18 feet and a height of 4 feet. How much water can the silo hold, in terms of π?
Refer to your STAAR 8th Grade Math Reference sheet for the appropriate formula.
Question 3 options:
162π ft3
324π ft3
648π ft3
12962π ft3
Answer:
th answer is 324
Step-by-step explanation:
i took the test
Vbb. Pls help 50 points
Answer:
6468 mm²
Step-by-step explanation:
Given:
21 mm = length of the shortest of the small rectangleLet y = length of the longest of the small rectangleTherefore, the area of the small rectangle is:
= width × length
= 21 × y
= 21y mm²
From inspection of the larger rectangle
longest side length = 4 × 21 = 84 mmshortest side length = (2y + 21) mmTherefore, the area of the larger rectangle is:
= width × length
= 84(2y + 21)
= 168y + 1764 mm²
We know that the area of the larger rectangle is 11 times the area of the smaller rectangle. Therefore,
⇒ 11 small rectangles = larger rectangle
⇒ 11(21y) = 168y + 1764
⇒ 231y = 168y + 1764
⇒ 63y = 1764
⇒ y = 28
Therefore, the missing side length of the smaller rectangle is 28 mm.
Finally, to find the area of the larger rectangle, substitute the found value of y into the found expression for its area:
⇒ area = 168y + 1764
⇒ area = 168(28) + 1764
⇒ area = 4704 + 1764
⇒ area = 6468 mm²
PLEASE HURRY! (pt 2)
A bag of tokens contains 99 red, 77 green, and 77 blue tokens. What is the probability that a randomly selected token is blue or green? Enter your answer as a fraction.
Answer:
14/23
Step-by-step explanation:
There are 253 tokens in all. Since 77 are blue and 77 are green, the probability of selecting either a blue token or a green token is 154/253, which reduces to 14/23.
pls pls pls pls pls pls pls
The inverse, converse and contrapositive of a statement are used to determine the true values of the statement
How to determine the inverse, converse and contrapositiveAs a general rule, we have:
If a conditional statement is: If p , then q .
Then:
Inverse -> If not p , then not q .Converse -> If q , then p .Contrapositive -> If not q , then not p .Using the above rule, we have:
Statement 1
Inverse: If a parallelogram does not have a right angle, then it is not a rectangle. Converse: If a parallelogram is a rectangle, then it has a right angle.Contrapositive: If a parallelogram is a not rectangle, then it does not have a right angle.All three statements above are true
Statement 2
Inverse: If two angles of one triangle are not congruent to two angles of another, then the third angles are not congruent. Converse: If the third angles of two triangle are congruent, then the two angles are congruent to two angles of anotherContrapositive: If the third angles of two triangle are not congruent, then the two angles are not congruent to two angles of anotherAll three statements above are also true
Read more about conditional statements at:
https://brainly.com/question/11073037
23
Machine A and machine B both make car parts.
Machine A makes 6 parts every 10 minutes.
Machine B makes 13 parts every 15 minutes.
On Monday
machine A makes parts for 12 hours
machine B makes parts for 10 hours
Work out the total number of parts made by the two machines on Monday.
Answer:
A makes 10 parts in 1 hour
B makes 4 parts in 1 hour.
then,
A makes 120 parts in a hour.
B makes 48 parts in a hour
Hope this helps!
Mark Brainlest!!!!!
Step-by-step explanation:
What time is it on the clock?
Answer:
About 2:18
The minute hand points toward the [tex]\frac{1}{4}[/tex] marker, meaning that is 15 minutes.Count the other ticks, and that's 18.Since the hand is not exactly on the 3, that means it is 2:00With this information, we can make a hypothesis or come to a conclusion that the clock says 2:18
In the parallelogram shown, find the measure of ∠A.
Answer: 40 degrees
Step-by-step explanation: