Please help me I need this done

Answer:

n = 16

Step-by-step explanation:

Given the proportion, n/28 = 4/7:

Cross multiply the two fractions:

7n = 28 × 4

7n = 112

Divide both sides by 7 to solve for n:

7n/7 = 112/7

n = 16

Therefore, the value of n = 16.

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Answer:

  4

Step-by-step explanation:

The equation is in slope-intercept form:

  y = mx +b

where m is the slope (average rate of change).

In the given equation, m = 4.

The average rate of change is 4.

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125/3

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1) 4m+3j, 2 terms.

2) -11x+6y+9, 2 terms

3) [tex]11g^5+6g^4-4gh\\[/tex], 2 terms

Answer:

6g = -86

Divide each term in 6 g = − 86 by 6 and simplify.

Exact Form: g = -43/3

Decimal Form: g = −14.¯3

Mixed Number Form:

g = −14 1/3

—————————————————————

g= -16

Vertical line at x = −16

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Answer:

  1 ÷ 6

Step-by-step explanation:

1/6 is a division expression. It means "one divided by six."

The slash (/) can be replaced by the "divided by" symbol (÷), if you like.

  1/6 = 1 ÷ 6 . . . . means "one divided by six"

Answer:

$1715

Step-by-step explanation:

1/5 + 1/ 7 = 12/ 35

So, he is left with 23/35 of his salary

if 23/35 of his salary is 1127

his whole salary is 1715

Answer:

farthur

Step-by-step explanation:

Answer: An isosceles triangle has two sides of equal length. The length of one of the equal sides is two more than 3 times the length of the third side. If the perimeter is 46m, find the length of each side.

Step-by-step explanation:

Hope this helps!

Answer:

Step-by-step explanation:

The perimeter is equal to the lengths of all the sides.

Let x equal the two sides that are equal to each other.

Then the 3rd side is 2x - 1 which is 2 times the length of the equal side minus 1.

So the perimeter 23 = x + x + (2x-1)

Now solve for x

23 = x + x + 2x - 1

add 1 to both sides

24 = x + x + 2x

24 = 4x

x = 6

The two equal sides would be 6 feet each

The other side would be 2(6) - 1 = 11

The perimeter is 6 + 6 + 11 = 23

Answer:

75

Step-by-step explanation:

divide 4 by 300 and then you will get the answer of 75. I'm so sorry if this is wrong

Step-by-step explanation:

f(x) = x² + 2ax + a² - a

g(x) = 4 - x²

f(x) = g(x)

x² + 2ax + a² - a = 4 - x²

2x²+2ax+a²-a -4 =0

the equation has two different solutions

=> (2a)² - 4(2)(a²-a-4) > 0

4a²-8a²+8a +32 >0

-4a²+8a+32 > 0

a²-2a-8 >0

(a-4)(a+2) < 0

the answer should be

-2 < a < 4

Answer:

10 and 1 fourth

Step-by-step explanation:

41 over 4 = 41/4 so you divide 41 by 4 which is 10 R1 so its 10 wholes, 1 and 4

Answer: if the x is negative the answer will be positive but if -10 is the only negative it would be negative. The way I remember is if their is a even amount of negatives is will be positive if theirs a odd amount it would be negative . Hope this helps :)

Step-by-step explanation:

Answer:

creo que la respuesta es 3,333.33 mph

Step-by-stepStep-by-step explanation:

Answer:

A 5-pound roast would take about 187.5 minutes to cook.

Divide 150 minutes by 4 pounds and you get 37.5 minutes. This would be how long it takes to cook each pound. So, you multiply 5 pounds by 37.5 and you get 187.5 minutes for a 5-pound roast to cook.

A.

So it is less than 1

B.

We can change -3 to 3 or -2 to 2.

This will result in:

(a) The value of given expression "((1/4)⁻³)⁻²" is less than 1, and (b) To make value greater than 1, change second exponent to positive; to make it equal to 1, change first exponent to 0.

Part (a) : Starting from the innermost exponent, (1/4)⁻³ simplifies to 4³, which is 64.

So, ((1/4)⁻³)⁻² becomes (64)⁻², which is 1/4096. Since 1/4096 is less than 1, the value of the expression is less than 1.

Part (b) : To change the value to greater than 1:

Change the second exponent to a positive value, making it ((1/4)⁻³)²,

This simplifies to (4³)², which is 4096.

To change the value to equal 1:

Change the first exponent to 0, making it ((1/4)⁰)⁻². This simplifies to (1)⁻², which is 1.

Learn more about Expression here

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Answer:

2

Step-by-step explanation:

Degree of the monomial is the highest power in the monomial.

Highest power in the monomial - 1.57k^2 is 2.

So, the degree of the monomial - 1.57k^2 is 2.

Answer:

5

Step-by-step explanation:

Answer:

The rate of change is 1.

The equation of a line and y-intercept form is

y = mx + b, where m = the slope of the line.

and our given equation y = x - 2 the slope of the line is 1 in other words y = 1x - 2

Answer:

0

Step-by-step explanation:

Answer:

Step-by-step explanation: about a boy who fell for a girl that was twice his age and yeah something about that :)

...........................

Answer:

the answer F or D

Step-by-step explanation:

Answer:

I believe your answer should be B.) I hope this helps! :D

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Answer:

  136

Step-by-step explanation:

15 seconds is 1/4 minute. We can find the number of copies by multiplying the rate by time:

  (32 copies/min)(4.25 min) = 136 copies

The machine can make 136 copies in 4 minutes 15 seconds.

Answer:-18 mm sugar

Step-by-step explanation:

Thanks me later

Rewrite f(x) as a nested exponential-logarithm expression :

[tex]\left(\ln(3x)\right)^{2x} = \exp\left(\ln\left(\ln(3x)\right)^{2x}\right)[/tex]

(where [tex]\exp(x) = e^x[/tex])

One of the properties of logarithms lets us drop the exponent as a coefficient:

[tex]\exp\left(\ln\left(\ln(3x)\right)^{2x}\right) = \exp\left(2x\ln\left(\ln(3x)\right)\right)[/tex]

Now, by the chain rule, we have

[tex]f(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \implies \\\\ f'(x) = \left(\exp\left(2x\ln\left(\ln(3x)\right)\right)\right)' \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2x\ln\left(\ln(3x)\right)\right)'[/tex]

By the product rule,

[tex]f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(   (2x)' \ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)'   \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(   2\ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)'   \right)[/tex]

By the chain rule again,

[tex]f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + 2x \cdot \dfrac1{\ln(3x)} \cdot \left(\ln(3x)\right)'  \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2x}{\ln(3x)} \cdot \dfrac1{3x} \cdot (3x)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{3\ln(3x)} \cdot 3 \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)[/tex]

Then simplify this to

[tex]f'(x) = \boxed{\left(\ln(3x)\right)^{2x} \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)}[/tex]