Please Help Me, I don't understand this kind of math

Answer:

Step-by-step explanation:

(-4,-5) and (6,4)

Slope: (4 - - 5) / ( 6 - - 4) = 9/10

y-intercept= - 5 - (9/10)(-4)

= - 5 + 36/10 = -7/5

y = 9/10x - 7/5

The equation of the line is x + 10y -19 = 0.

We are given that;

The points of line segment= (6,4) and (-4,5)

Now,

To find the equation of a line given two points, we can use the two-point form formula:

y − y 1 = y 2 − y 1 x 2 − x 1 ( x − x 1)

where (x 1, y 1) and (x 2, y 2) are the two given points and (x, y) is any point on the line.

We have:

(x 1, y 1) = (6,4)

(x 2, y 2) = (-4,5)

Substituting these values into the formula, we get:

y − 4 = 5 − 4 -4 − 6 ( x − 6)

Simplifying and rearranging, we get:

y = -1/10 x + 19/10

This is the equation of the line in slope-intercept form. We can also write it in standard form by multiplying both sides by 10 and moving all terms to one side:

x + 10y -19 = 0

Therefore, by equation the answer will be x + 10y -19 = 0.

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Using the t-distribution, it is found that since the absolute value of the test statistic is less than the critical value for the two-tailed test, you cannot conclude that the mean sales differ between the two programs.

At the null hypothesis, it is tested if the mean sales do not differ between the two programs, that is, the subtraction of the means is 0, hence:

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

At the alternative hypothesis, it is tested if they differ, that is:

[tex]H_1: \mu_1 - \mu_2 \neq 0[/tex]

The mean and the standard errors for each sample are:

[tex]\mu_1 = 42, s_1 = 5.9675[/tex]

[tex]\mu_2 = 44.56, s_2 = 5.6177[/tex]

The distribution of the difference has mean and standard deviation given by:

[tex]\overline{x} = \mu_2 - \mu_1 = 44.56 - 42 = 2.56[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{5.9675^2 + 5.6177^2} = 8.1957[/tex]

The test statistic is:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.

Then:

[tex]t = \frac{2.56 - 0}{8.1957}[/tex]

[tex]t = 0.31[/tex]

The critical value for a two-tailed test, as we are testing if the mean is different of a value, with 9 + 9 - 2 = 16 df and a significance level of 0.05 is [tex]|t^{\ast}| = 2.12[/tex]

Since the absolute value of the test statistic is less than the critical value for the two-tailed test, you cannot conclude that the mean sales differ between the two programs.

A similar problem is given at https://brainly.com/question/13873630

Answer:

2/3 ​sandwich.

Step-by-step explanation:

No Explanation

Answer:

71

Step-by-step explanation:

25+2+2+2+2+1=34

28+2+2+2+2+1=37

sum=34+37

71

Answer:

3+2+2=7 year back

28-7=21

25-7=18

years old pls mark me as brainlist

Answer:

Sum of the interior angles = 1260°.

Step-by-step explanation:

Sum of the interior angles =  (n - 2)180° where n= number of sides

Sum of the interior angles = (9-2)180

Sum of the interior angles = 1260°

the first one is (B) i think

the second one is (B)

the third one is (B)

the fourth one is (A)

the fifth one is (A)

Answer 5-5.190 =-945 -2=-947 2-2=0+3 =3+7=-935

Step-by-step explanation:

Step-by-step explanation:

1. Not all rational numbers are whole numbers.  Whole numbers can be rational numbers, if expressed in fraction form.  For example, 1 can be expressed as [tex]\frac{1}{1}[/tex].  A set of rational numbers consists of a set of numbers written as a quotient of two integers, a and b, in the form [tex]\frac{a}{b}[/tex] , where b ≠ 0.  The reason why b ≠ 0 because division by zero is an undefined mathematical operation.

2. Irrational numbers differ from rational numbers in terms of its representation: while the rational numbers can be expressed as a ratio or in fraction form, irrational numbers cannot be expressed in fraction form.

Irrational numbers are a set of numbers for which its decimal representations is neither terminating, nor repeating.  A couple examples of irrational numbers are:  π and [tex]\sqrt{2}[/tex], as their decimal representations do not come to an end and doesn't have a block of repeating digits.

3. All real numbers are rational numbers. Real numbers comprise of natural numbers, whole numbers, integers, rational numbers, and irrational numbers.

Answer:

Step-by-step explanation:

Squares have equal length and widths

2t - 9 = 1 + t

2t - t - 9 + 9 = 1 + 9 + t - t

t = 10 s

Answer:

Domain: -10 < x < 10

Range: -2 < y < 8

Step-by-step explanation:

Hope this helps!

Answer:

Step-by-step explanation:

Answer:

y= 4/1x +1

Step-by-step explanation:

the number on the y axis is the b and you do rise over run to find m you rise (so you go up or down) 4 times and run( go to the sides) once.

rise 4

-------- = -----

run 1

Answer:

y = 3x + 1

Step-by-step explanation:

Slope: As it rises 3, it runs 1

Slope = Change in y/change in x

Slope = 3/1

y - intercept = 1 ,the point of intersection

Equation : y = mx + b

m = slope

b = y-intercept

Equation : y = 3x + 1

-Chetan K

Answer:

800

Step-by-step explanation:

800+799=1599

[tex] \: \: \: [/tex]

[tex]f(x) = 4[/tex]

[tex]x = R[/tex]

[tex] \: \: \: [/tex]

Answer:

y = 9/2 - 5/2(x)

Step-by-step explanation:

I think this is right

Answer:

ratio of long-sleeved shirts to short-sleeved shirts is 1:2 this is my answer that I thought of if you don't feel comfortable believing me just wait for another person to answer and see what they say.

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

The circle that passes through the vertices of triangle ΔABC (A, B, C) is the

circumscribing circle of triangle ΔABC.

The area of the circle that passes through vertices A, B, and C, is (C) 26·π

Reasons:

The given parameters are;

Side length of isosceles triangle ΔABC; [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex] = 3·√6

Radius of circle tangent to [tex]\overline{AB}[/tex] at B and [tex]\overline{AC}[/tex] at C = 5·√2

Required:

Area of the circle that passes through vertices A, B, and C

Solution:

Angle ∠BAO is given as follows;

[tex]\angle BAO = arctan\left(\dfrac{5 \cdot \sqrt{2} }{3 \cdot \sqrt{6}} \right) = \mathbf{arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)}[/tex]

Therefore;

[tex]\angle BOA = 90^{\circ} - arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)[/tex]

[tex]\overline{BC} = 2 \times 5 \cdot \sqrt{2} \times sin\left(90^{\circ} - arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right) = 15\cdot \sqrt{\dfrac{6}{13} }[/tex]

∠ABO' = ∠BAO' (Base angles of isosceles triangle ΔABO')

[tex]\angle BAO' = \angle BAO = \mathbf{arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)}[/tex]

Therefore;

[tex]\angle BO'A = 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)[/tex]

From sine rule, we have;

[tex]\dfrac{\overline{AB}}{sin \left(\angle BO'A \right)} = \mathbf{\dfrac{\overline{BO'}}{sin \left(\angle BAO' \right) \right)}}[/tex]

Which gives;

[tex]\mathbf{\dfrac{3 \cdot \sqrt{6} }{sin \left( 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right)}} = \dfrac{\overline{BO'}}{sin \left(arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right) \right)}[/tex]

Using a graphing calculator, we get;

[tex]\overline{BO'} = \dfrac{3 \cdot \sqrt{6} }{sin \left( 180^{\circ} - 2 \times arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right)\right)} \times sin \left(arctan\left(\dfrac{5 \cdot \sqrt{3} }{9} \right) \right) = \sqrt{26}[/tex]

The radius of the circumscribing circle [tex]\overline{BO'}[/tex] = √(26)

Therefore, area of the circumscribing circle, [tex]A_{O'}[/tex] = π·(√(26))² = 26·π

The area of the circle that passes through vertices A, B, and C, is (C) 26·π

Learn more here:

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The possible question options obtained from a similar question online are;

(A) 24·π (B) 25·π (C) 26·π (D) 27·π (E) 28·π

Answer:

34800, 350000, 300000

Step-by-step explanation:

5>=5

34800

7>=5

350000

4<=5

300000

9514 1404 393

Answer:

  5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

  ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is  ...

  b^2 -4ac

so the discriminant of your equation is ...

  10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

  100 +4ac = 0

  25 +ac = 0

  ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

  5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

Additional comment

Your problem statement does not require that 'a' be non-zero. If a=0, then the equation will have one real solution for any value of c.

If you restrict the solutions to integers, then possibilities include ...

  (a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

Answer:

The equation is 5x+10x=-5

Step-by-step explanation:

Answer:

x^2-3x-y+16?

Step-by-step explanation:

simplest form already, but can be converted into a proper polynomial.

x^2-3x-y+16

Answer: [tex]\frac{9}{x-1}[/tex]

Step-by-step explanation:

Since the denominators are the same, we can subtract the numerators.

[tex]\frac{x+1}{x-1}-\frac{x-8}{x-1}=\frac{(x+1)-(x-8)}{x-1}=\boxed{\frac{9}{x-1}}[/tex]

Answer: They are all divisible by 2.

Step-by-step explanation: They all have 2 in common. If you divide them by 2, they all work. Also, if you simplify all to the lowest number, they equal 2 except 2 itself which equals 1.

Answer:

divisible by 2 luv

Step-by-step explanation:

Answer:

Step-by-step explanation:

How do you find the answer for 30=6x+20?

30 = 6x + 20

10 = 6x

x = 10/6

5/4

------------------ check

30 = 6 * 10/6 + 20

30 = 10 + 20

30 = 30

the answer is good

Answer:

x<5   or  x<3/2

Step-by-step explanation:

2[tex]x^{2}[/tex]-13x+15<0

2[tex]x^{2}[/tex]-10x-3x+15<0

2x(x-5)-3(x-5)<0

(x-5)(2x-3)<0

x-5<0  or 2x-3<0

x<5  or  x<3/2

Answer:

i tink its a

Step-by-step explanation: