PLEASE HELP ME

Directions: Construct a frequency distribution with six intervals for the given data below. Then determine the following: (10 points) a. Range b. Class size c. interval with highest frequency

Number of kilograms of rice consumed by 30 families in a month

60 33 21 57 24 54 52 50 42 60 20 39 23 42 29 46 40 25 38 35 43 35 38 38 28 58 20 ​

Answer:

There would be 104 rooms on 4 floors in total.

Step-by-step explanation:

If there were 26 rooms on 2 floors, then you multiply 26 x 4, the result would be 104 rooms on 4 floors in total.

Answer:

52 rooms

Step-by-step explanation:

you could set up a proportion to solve this

26 rooms/ 2 floors = ?/4 floors

to find the answer for the question mark you can divide the amount of rooms by floors and get 13.

With the 13 you can multiply that by 4 to get 52 rooms. You basically used the 13 as the amount of increase

i hope this helped

if you have anymore questions feel free to ask again:3

Answer:

Infinitely many

Step-by-step explanation:

Given:

[tex]y + 12 = y + 10 + 2[/tex]

Solve:

Subtract y from  both sides

[tex]y+12-y=y+10+2-y[/tex]

Simplify

[tex]12=10+2[/tex]

Now add : 10 + 2

[tex]12=12[/tex]

Both side are equal

Since both sides are equal then answer = Infinitely many

[RevyBreeze]

Answer:

The probability scale for this question is not 100% sure to buy shoes so the scale is given to be even chance(1/2).

Step-by-step explanation:

Answer:

  180 cm^2

Step-by-step explanation:

For similar figures the ratio of areas is the square of the ratio of linear dimensions.

We take "tripled in size" to mean that the linear dimensions of the larger rectangle are 3 times those of the smaller rectangle. That means the area of the larger rectangle will be 3² = 9 times the area of the smaller one.

  Area = (3²)(20 cm²) = 180 cm² . . . . area after tripled in size

[tex]sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \qquad cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1-cos(30^o)}{2}}\implies \sqrt{\cfrac{1-\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2-\sqrt{3}}{2}~~}{2}}[/tex]

[tex]\sqrt{\cfrac{2-\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2-\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2-\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1+cos(30^o)}{2}}\implies \sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2+\sqrt{3}}{2}~~}{2}} \\\\\\ \sqrt{\cfrac{2+\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2+\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ sin\left( \frac{30^o}{2} \right)~~}{cos\left( \frac{30^o}{2} \right)}\implies \cfrac{~~\frac{\sqrt{2-\sqrt{3}}}{2} ~~}{\frac{\sqrt{2+\sqrt{3}}}{2}}\implies \cfrac{\sqrt{2-\sqrt{3}}}{2}\cdot \cfrac{2}{\sqrt{2+\sqrt{3}}} \\\\\\ \cfrac{\sqrt{2-\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \blacktriangleright \sqrt{\cfrac{2-\sqrt{3}}{2+\sqrt{3}}} \blacktriangleleft[/tex]

Answer:

Since the least number of digits in the number is 2 decimal places

Round 3.0478 to 2 dp

3.05+4.92=7.97

B is the answer

Step-by-step explanation:

Give brainliest please

Answer:

B

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

There are a few different ways we can approach this problem.  

The easiest way is to flip the second fraction and multiply:

[tex]\dfrac{18}{5} \div \dfrac{3}{25}=\dfrac{18}{5} \times \dfrac{25}{3}=\dfrac{18 \times 25}{5 \times 3}[/tex]

To do this without a calculator, rewrite 18 as 6 x 3 and 25 as 5 x 5:

[tex]\dfrac{18 \times 25}{5 \times 3}=\dfrac{6 \times 3 \times 5 \times 5}{5 \times 3}[/tex]

Now we can cancel out the common factors of 5 and 3 from the numerator and denominator, and are left with:

[tex]\implies 6 \times 5 =30[/tex]

The quotient obtained from the division of given fractions is 30.

Given that, 18/5 divided by 3/25.

Dividing fractions is nothing but multiplying the fractions by reversing one of the two fraction numbers or by writing the reciprocal of one of the fractions. By reciprocal we mean, that if a fraction is given as a/b, then the reciprocal of it will b/a.

Here, 18/5 ÷ 3/25

= 18/5 × 25/3

= 6/1 × 5/1

= 30/1

Therefore, the quotient obtained from the division of given fractions is 30.

Learn more about the division of fractions here:

brainly.com/question/17205173.

#SPJ6

Answer:

  A, D

Step-by-step explanation:

You want to know the bound for the values of Sn and Tn, given their definitions as ...

  [tex]\displaystyle S_n=\sum_{k=1}^n{\dfrac{n}{n^2+kn+k^2}}\\\\T_n=\sum_{k=1}^{n-1}{\dfrac{n}{n^2+kn+k^2}}[/tex]

All we need to do to determine the correct answer choices is evaluate the sums for some value of n.

For n=2, the value of S2 is ...

  S2 = 2/(4+2+1) +2/(4+4+4) = 2/7 +2/12 = 19/42 ≈ 0.4524

For n=2, the value of T2 is ...

  T2 = 2/(4+2+1) = 2/7 ≈ 0.2857 . . . . . 1/(3n) less than the value of Sn

Both of these values are less than π/(3√3) ≈ 0.6046.

The correct answer choices are ...

  A) Sn < π/(3√3)

  D) Tn < π/(3√3)

__

Additional comment

For the purpose here, it is not necessary to determine the limiting value of either Sn or Tn. It is only necessary to demonstrate which side of the given value the terms of either sequence lie.

<95141404393>

Answer:

Cite evidence from the text to explain Her as role in Greek mythology

Answer:

the 45 degree angle is in the first quadrant, the coordinates are (√2/2, √2/2) (square root of 2 on the top, 2 on the bottom)

Answer:

-40-42i

Step-by-step explanation:

9-42i+49i^2=9-42i-49=-40-42i

Answer:I drew a quadratic function with a vertex and axis of symmetry, hope this helps

Answer:

Step-by-step explanation:

The usual English meanings of the words "reduction" and "enlargement" apply to geometrical figures.

Figure A'B'C'D' is smaller than figure ABCD, so represents a reduction.

__

Every coordinate of every image point is half as far from the origin in A'B'C'D' as in the original figure ABCD. For example, the x-coordinate of C' is 2, and the x-coordinae of C is 4. The dilation factor is the ratio of these values:

  k = Cx'/Cx = 2/4 = 1/2

The scale factor is 1/2.

Answer:

Median

Step-by-step explanation:

I know that you can't do Range, since it's skewed right.

The mean can't be it since it's also not representative when it's skewed right.

I'd say Median, or IQR at first glance but if you look at a graph, the IQR might follow with the skewed and move over a bit.

That leaves Median.

The correct statistical measure which represents the spread of the data best is, Median.

Given that;

The data for the heights of players on a basketball team is skewed right.

Since, We know that;

For the data for the heights of players on a basketball team is skewed right,

We can use Median for the spread of the data best.

Hence, The correct statistical measure which represents the spread of the data best is, Median.

Learn more about the median visit:

https://brainly.com/question/26177250

#SPJ2

Step-by-step explanation:

2. since there are 15 shirt

the probability of her wearing a blue shirt is 5/15

the probability of her wearing a blue shirt is 4/15

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].

Identify the vectors:

[tex]u=\langle-10,-7\rangle[/tex]

[tex]v=\langle-8,4\rangle[/tex]

Compute the dot product:

[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]

Find the square of the magnitude of vector v:

[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]

Find the projection of vector u onto v:

[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]

Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]

Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]

Thus, C is the correct answer

Problem 3

We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:

[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]

Next, we find the magnitude of the vector:

[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]

And finally, we find the direction of the vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].

Thus, A is the correct answer

Problem 4

Add the vectors:

[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]

Determine the magnitude of the vector:

[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]

Find the direction of the vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].

Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]

Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].

This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]

Add the vectors:

[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].

Thus, B is the correct answer

Answer:

a) 3

b) 1/3

Step-by-step explanation:

I've never used Brainly math before, but I can help you out with the work for these problems.

Part A

3(x + 1) - x = 15

3x + 3 - x = 15

4x + 3 = 15

4x = 12

x = 3

Part B

5(x + 2) - 2x = 11

5x + 10 - 2x = 11

3x + 10 = 11

3x = 1

x = 1/3

Hope this helps!

Step-by-step explanation:

a) 7/10

b) 9/10

c) 4/10 = 2/5

d) 9/10

e) 2/10 = 1/5

I hope it helped you

Answer: 3

Step-by-step explanation:

go in evenly

Answer:

(10,  20)

(25,  12)

(15,  20)

Step-by-step explanation:

Hopes this helps! :)

Answer:

the correct answers are,

(15, 16)

(25, 12)

(5, 20)

Answer:

e): m=18.50d + 25

Step-by-step explanation:

24/8 = 3

the 24 to 8 gear = 3:1 ratio which is greater than 2:1

Answer:

Depends on how many points the star has. For example, a 5 pointed star will have 5 lines of symmetry. Knowing this, you should be able to count using a diagram or drawing of the star

Answer:  cash, paychecks, checks

Step-by-step explanation:

(: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (:

Answer:

I Think the answer is B I'm sorry if I'm wrong

Answer:

<1 = 88° , <2 = 129°, <3 = 82°, <4 = 147°, <5 = 94°, <6 = 86°

Step-by-step explanation:

<1 + 92° = 180°

<1 = 88°

<2 + 51° = 180°

<2 = 129°

<3 + 98° = 180°

<3 = 82°

<4 + 33° = 180°

<4 = 147°

<1 + <2 + <3 + <4 + <5 = 540°

88° + 129° + 82° + 147 + <5 = 540°

<5 = 94°

<5 + <6 = 180°

94° + <6 =180°

<6 = 86°

Answer:

53

Step-by-step explanation:

[tex]sum \: of \: angles = 180 \\ 180 = 74 + 2x \: where \: x \: is \: the \: measure \: of \: the \: other \: angles \\ 180 - 74 = 2x \\ 106 = 2x \\ x = \frac{106}{2} \\ x = 53[/tex]

Always welcome