PLEASE HELP ;)
Who did it right?

Find the slope of the line perpendicular to 2x+3y=8

PLEASE HELP ;)Who Did It Right?Find The Slope Of The Line Perpendicular To 2x+3y=8

Answers

Answer 1

Answer:

Marissa.

Step-by-step explanation:

To find perpendicular slope you basically take the slope of the given line and reverse whatever sign it had previously. (If it was negative, it would become positive. If it was positive it would become negative.)

By doing -A/B it make the previous slope negative.

Brandon only flipped the fraction which would just result in the slope being slightly steeper, or in this case, less steep than the previous line, rather than making it perpendicular.

Hope this helps! Stay safe and if you have any questions feel free to ask!


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In triangle ABC, AB measures 25 cm and AC measures 35 cm. The inequality < s < represents the possible third side length of the triangle, s, in centimeters. The inequality < p < represents the possible values for the perimeter, p, of the triangle, in centimeters.

Answers

Answer:

The inequality 10 < s < 60 represents the possible third side length of the triangle, s in centimeters.

The inequality 70 < p < 120 represents the possible values for the perimeter p, of the triangle in centimeters.

Step-by-step explanation:

Firsts one The lower number has to be the difference between the bigger number and smaller number. In this case 35 - 25 = 10 and the s < 60 has to be the sum of both numbers.

Second one. I'm assuming it's just the sum of the two numbers to the first answer, and the second number is just the second number from the previous one, but multiplied by 2. Sorry that I couldn't go into too much detail about this one

The inequality that represents the possible third side length

[tex]10cm<s<60cm[/tex]

The inequality that represents the possible values for the perimeter

[tex]70cm<P<120cm[/tex]

Given :

In triangle ABC, AB measures 25 cm and AC measures 35 cm.

For any triangle , we know that the sum of measures of two sides is greater than the third side

Let 's' be the third side length

[tex]25+35>s\\60>s\\\\Also , s+25>35\\s>35-25\\s>10\\Inequality\; is \;\\10<s<60[/tex]

Now we find the perimeter when s=10

Perimeter = sum of all the sides

[tex]s=10\\P=25+35+10=70\\s=60\\P=25+35+60=120[/tex]

[tex]70<P<120[/tex]

Learn more : brainly.com/question/2605035

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Answers

This is the answerrrrr

Answer:   [tex]\frac{x^8}{256y^{20}}[/tex]

If the font is too small, it says x^8 all over top 256y^20 as one big fraction.

========================================================

Work Shown:

[tex]\left(\frac{5x^3}{20xy^5}\right)^4\\\\\\\left(\frac{x^2}{4y^5}\right)^4\\\\\\\frac{\left(x^2\right)^4}{(4^1)^4\left(y^5\right)^4}\\\\\\\frac{x^{2*4}}{4^{1*4}y^{5*4}}\\\\\\\frac{x^{8}}{4^{4}y^{20}}\\\\\\\frac{x^{8}}{256y^{20}}\\\\\\[/tex]

In triangle DEF, segment DJ is a perpendicular bisector of side EF. If EJ is 3y-8 and JF is 7y-40, what is the length of JF?

Answers

Answer: The length of JF = 16 units.

Step-by-step explanation:

Given: In triangle DEF, segment DJ is a perpendicular bisector of side EF.

i.e. DJ is perpendicular to EF and DJ divides EF into two equal parts EJ and JF. [The perpendicular bisector is a line that is perpendicular to a line segment and splits it into two congruent segments.]

If  EJ is 3y-8 and JF is 7y-40.

Then, [tex]3y-8=7y-40[/tex]

[tex]\Rightarrow\ 7y-3y=40-8\\\\\Rightarrow\ 4y=32\\\\\Rightarrow\ y=8 \text{ [Divide both sides by 4]}[/tex]

JF= 7(8)-40 =56-40= 16 units

Hence, the length of JF = 16 units.

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