The cost of mailing a letter in 1938 was 530 cents while it cost 43 cent in 1988
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The cost of mailing a letter went up 1133% over the fifty-year period 1938-1988. If it cost 43¢ to mail a letter to a Canadian address in 1988
Let x represent the cost of mailing the letter in 1938, hence:
x = 43 + 1133% of 43 = 43 + 487.19 = 530 cent
The cost of mailing a letter in 1938 was 530 cents while it cost 43 cent in 1988
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4. Solve the inequality and graph the solution. Show work
3k > 5k + 12
Answer:
Your answer is k< -6
Step-by-step explanation:
Joel borrowed $18,000 for 6 years at simple interest to purchase a vehicle. If Joel repaid a total of $20,953.80, at what rate did he borrow the money?
Enter the percent with the percent symbol. If the percent is not a whole value, enter it as a decimal where the last digit is not zero and there is a zero before the decimal point for values less than 1. For example, if the answer is .35%, 0.35% should be entered. Round the percent to the nearest thousandth of a percent if needed.
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$20953.80\\ P=\textit{original amount deposited}\dotfill & \$18000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &6 \end{cases} \\\\\\ 20953.80=18000[1+(\frac{r}{100})(6)]\implies \cfrac{20953.80}{18000}=1+\cfrac{6r}{100}[/tex]
[tex]\cfrac{20953.80}{18000}=\cfrac{100+6r}{100}\implies \cfrac{2095380}{18000}=100+6r\implies \cfrac{11641}{100}=100+6r \\\\\\ \cfrac{11641}{100}-100=6r\implies \cfrac{1641}{100}=6r\implies \cfrac{1641}{600}=r \\\\\\ \cfrac{547}{200}=r\implies \stackrel{\%}{2.735} = r[/tex]
Im stuck on this problem. Please explain how you got your answer
The function [tex]y=0.3^x[/tex] represents exponential growth with the initial value equal to 1, the decay factor equal to 0.3, and the rate equal to 0.7.
Population Growth Equation
The formula for the Population Growth Equation is:
[tex]P_f=P_o*(1+\frac{R}{100}) ^t[/tex]
Pf= future population
Po=initial population
r=growth rate
t= time (years)
growth or decay factor = (1 ±r)
When 1+R > 1, the equation represents growth, while 1+R < 1 the equation represents decay.
The question gives:
[tex]y=0.3^x[/tex], then
Pf=y
Po= 1
[tex](1+\frac{R}{100}) =0.3[/tex] , thus
[tex](100+R}) =30\\ \\ R=-100+30\\ \\ R=-70[/tex]
r= -70%= -0.7
decay factor= (1-0.7)=0.3
Therefore,
1+R will be = 1+(-0.7)=1 - 0.7 =0.3
When 1+R >1, the function represents exponential growth.
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A rectangular shape of dimension 95 m by 75 is drawn to a scale 1cm to 10m. Find the area of the drawing.
Scaled dimensions
95/10=9.5cm75/10=7.5cmArea:-
Length ×Breadth9.5(7.5)71.25cm²The area of the drawing is 71.25 square cm.
What is Area of Rectangle?The area of Rectangle is length times of width.
The actual dimensions of the rectangle are 95 m by 75 m.
The drawing is made to a scale of 1 cm to 10 m, which means that each centimeter on the drawing represents 10 meters.
Let us find the area of the drawing
First calculate the area of the rectangle in real life, and then scale it down using the ratio of 1 cm to 10 m.
The area of the rectangle in real life is:
95 m × 75 m = 7125 square meters
To scale this down to the drawing, we need to divide both dimensions by 10.
The area of the drawing is
(95 m / 10) × (75 m / 10)
= 9.5 cm × 7.5 cm
= 71.25 square cm
Therefore, the area of the drawing is 71.25 square cm.
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Give me full working and explanation! And I give you stars and I mark you as brainliest for sure. Best deal here.
1st clock timing
1 : 152nd clock timing
2 : 003rd clock timing
3 : 304th clock timing
4 : 4530.
formula for discount: original price - final price
discount: $700 - $505.75 = $194.25In percentage:
[tex]\rightarrow \sf \dfrac{194.25}{700} *100[/tex]
[tex]\rightarrow \sf 27.75\%[/tex]
ii)
3($194.25) = $582.75 discount
In percentage: same. 27.75%
find a polynomial equation of the lowest degree with rational coefficients whose one root is (cbrt 2 + 3*cbrt 4)
Answer:
poly Gon have [tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex][tex] \huge\color{blue}{ \rule{1pt}{999999pt}}[/tex]
Describe another way you can find 18 = 3.
Answer:
divided by 3 on both sides
Can you help me with this one
Answer:
??
Step-by-step explanation:
pls type the question properly have a good day:-)
Kevin works 2 hours more than emily each time they work together. Using this information, complete the table
If Kevin works two more hours than Emily, the correct number of hours that complete the table are 6, 5, 8, and j.
How many hours do Kevin and Emily work?The number of hours can be expressed as:
The number of hours Emily works = K - 2 or the number of hours Kevin works minus 2.The number of hours Kevin works = E + 2 or number of hours Emily works plus 2.What are the missing numbers?Emily = Kevin4 hours = 6 hous (E+2)5 hours (K-2) = 7 hours 6 hours = 8 hours (E+2)h= j (E+2)Learn more about mathematics in: https://brainly.com/question/15209879
A can of vegetables is 4.5 in. high and has a diameter of 3 in. Find the volume of the can to the nearest tenth of a unit. Use 3.14 for π.
Answer:
i dont know i tried really really hard i wish i could help
Step-by-step explanation:
P varies inversely with Q, and P=12 when Q=8. Find P when Q=3.
Answer:
32
Step-by-step explanation:
Given :
P ∝ Q⁻¹ or P ∝ 1/QFinding the propotionality constant
P = k/Q12 = k/8k = 12 * 8 = 96Finding P in Case (ii)
P = k/QP = 96/3P = 32Jorden has $275 in his bank account. The bank will pay Jorden 4% interest per year on the value of his account. If Jorden doesn’t add to his account or withdraw any money, how much will he have in his account after one year?
Answer: $11.00
Step-by-step explanation: Please see attached PDF.
Can someone help me please?
Answer:
[tex]\bold{ \sf \theta = \dfrac{\pi }{9} , \ \ \dfrac{2}{9} \pi , \ \dfrac{7 \pi }{9}, \ \ \dfrac{8\pi }{9}, \ \dfrac{13\pi }{9}, \ \dfrac{14\pi }{9}}[/tex]
Explanation:
[tex]\dashrightarrow \ \ \sf 2sin(3\theta) = \sqrt{3}[/tex]
[tex]\dashrightarrow \ \ \sf sin(3\theta) = \dfrac{ \sqrt{3}}{2}[/tex]
[tex]\dashrightarrow \ \ \sf 3\theta = sin^{-1}(\dfrac{ \sqrt{3}}{2})[/tex]
[ your calc should be in radian mode [R] ]
[tex]\dashrightarrow \ \ \sf 3\theta = \dfrac{\pi }{3} , \ \ \dfrac{2}{3} \pi , \ \ \dfrac{7 \pi }{3}, \ \ \dfrac{8\pi }{3}, \ \dfrac{13\pi }{3}, \ \dfrac{14\pi }{3}[/tex]
[tex]\dashrightarrow \ \ \sf \theta = \dfrac{\pi }{9} , \ \ \dfrac{2}{9} \pi , \ \ \dfrac{7 \pi }{9}, \ \ \dfrac{8\pi }{9}, \ \dfrac{13\pi }{9}, \ \dfrac{14\pi }{9}[/tex]
someone please help i literally have no idea how to do this
Answer:
I don't know if this is all the way right but I hope it is.
Step-by-step explanation:
Step 1.
Put the data in order to find the median.
Median = 72
Find the Lower Quartile and the Upper Quartile. These are the medians of the lower and upper halves.
Lower Quartile = 66
Upper Quartile = 79
Next put those points on your number line and mark your smallest and
greatest values, the median, and the Quartiles.
I need help on this
Answer:
a) 1/8
b) 8
Step-by-step explanation:
a) 1/2 x 1/2 x 1/2 = 1/8
b) since the exponent is negative it becomes positive when placed in the denominator
so 1/2 ^-1 is equal to 1/1 ÷ 1/2 which is equal to 2
therefore, (1/2)^-3 is equal to 2 x 2 x 2 or 8
A tree is 7 feet tall. If it grows 9 inches each year, how tall will the tree be in 10 years
Answer:
174 in.
14.5 ft.
Step-by-step explanation:
1. 7ft = 84in
2. 9in x 10 = 90
3. 84in + 90in = 174 in
1.5 = 0.25 + g
solve the equation and find the value of the variable
Answer:
its easy it should be 1.25 or well that the answer I got
Find the measure of each missing side length. Round to the nearest tenth.
Answer:
x = 24.0
Step-by-step explanation:
We will need to use one of the trigonometric ratios to find x.
If we use 58 as the reference angle, we can use tan to find x, as [tex]tan=\frac{opposite}{adjacent}[/tex]
[tex]tan (58)=\frac{x}{15}\\ 15*tan(58)=x\\x=24.005\\x=24.0[/tex]
Which is the equation for line B?
A. y= 4/3x
B. y=3/4x
C. y=3/2x
Answer:
b. y = 3/4x
Step-by-step explanation:
you can count it on the graph or use the slope formula
please help!! i'll give a brainliest
Answer:
Answer is -1
have a nice hope it helps.
ANSWER ASAP, ILL GIVE BRAILIEST
Which measurement goes from one outside edge all the way across to the other outside edge?
Diameter
Circumference
Radius
Answer:
circumference
Step-by-step explanation:
circumference shows us how sowmthing goes around. like have you ever been to the doctor and they said theyre checking a babys head circumference? theyre checking it all over.
y’all please help!!! gradpoint & will give lotsss of points :((
Answer:
f(-8) = 64
Step-by-step explanation:
Given conditions :
f(x) = { x², if x < 0}or f(x) = {∛x, if x > 0}We have x = -8
⇒ It follows x < 0
Therefore, substituting x = -8 in the function :
f(-8) = (-8)²f(-8) = 64Is this triangle acute, right or obtuse?
Answer:
acute
Step-by-step explanation:
Check using the Pythagorean Theorem:
A^2 + B^2 ≟ C^2
9^2 + 115 ≟ 11^2
196 > 121,
so this triangle is acute because the sum of each leg squared is longer than the length of the hypotenuse squared.
A triangle has sides with lengths of 9 miles, 12 miles, and 15 miles. Is it a right triangle?
Answer:
The three sides 9 in, 12 in, and 15 in do represent a right triangle. Since the square of the hypotenuse is equal to the sum of the squares of the other two sides, this is a right triangle.
Step-by-step explanation:
15² = 9² + 12²
225 = 81 + 144
225 = 225
so it is an right angled triangle....
( using : if the sum of the squares of the smaller two sides is equal to the square of the largest side, then the traingle is a right triangle.)
Year 7 > T.12 Find what percent one number is of another: word problems
Frank's Tea Shop has caffeinated tea and decaffeinated tea. The tea shop served 30
caffeinated teas and 10 decaffeinated teas. What percentage of the teas served were
caffeinated?
Write your answer using a percent sign (%).
Submit
Answer:
8995{c-(-12)4} valva a 2 b 5 c -7
1&5<y x=(2,0)
The yearbook club had a meeting. The meeting had 8 people, which is one-fourth of the club. How many people are in the club?
Answer:
32
Step-by-step explanation:
Since we know 8 = 1/4
We can convert the 1/4 into a percentage:
8 = 25%
To get to 100% which is the full club we have to multiply both sides by 4:
8×4 = 25% ×4
32 = 100%
So there are 32 people in the club.
Steve drove 130 miles from Portland to Tacoma in 2 hours. If he continues to drive at the same speed, how long will it take him to drive 390? IS IT PROPORTIONAL
b) If you were to roll the dice 100 times, how often would you expect to get doubles?
If you're rolling a single cube, then ...
-- There are 6 possible out comes.
-- One of them (5) is a multiple of 5 .
-- The probability of rolling it is (1/6) = 16-2/3 % .
If everything is acting perfectly random, then ion 100 rolls,
you'd expect to succeed 16 or 17 times.
If you're rolling a pair of cubes, then ...
-- There are (6 x 6) = 36 possible outcomes.
-- There are seven ways to get a multiple of 5.
(1+4), (4+1), (2+3), (3+2), (4+6), (6+4), (5+5)
-- The probability of rolling one of those is
(7/36) = 19-4/9 % .
If everything is acting perfectly random, then in 100 rolls,
you'd expect to succeed 19 or 20 times.
A car dealership sells cars that were made in 2015 through 2020. Let the cars for sale be the domain of a relation R where two cars are related if they were made in the same year. (a) Prove that this relation is an equivalence relation. (b) Describe the partition defined by the equivalence classes.
The given relation obeys reflexive, symmetric, and transitive properties, therefore, it is in relation to equivalence relation.
How is the equivalence relation depicted?Let the domain of the relation is car(x) belongs to 2015 , 2016, 2017, 2018, 2019, 2020
To prove equivalence relation, we need to prove reflexive, symmetric, transitive properties.
Reflexive relation: x is related to x
Here car(x) is made in 2015, so, car(x)) is in R where R is reflexive relation.
Symmetric relation: x is related to y implies y is related to x
Here (car(x) , car(y)) is in R , i.e car(x) and car(y) are made in same year. R obeys symmetric property
Transitive property: x is related to y and y is related to z then x is related to z. Here (car(x),car(y)), (car(y), car(z)) is in R. Therefore (car(x) , car(z)) is in R
Therefore, the given relation obeys reflexive, symmetric, and transitive properties, therefore, it is in relation to equivalence relation.
B. The cars which are made in the same year are in one equivalence class all cars are made in overall 6 years. We get 6 equivalence classes. These classes are partitions, so we have six partitions
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Pls help!!!!!!!!!!!!!!!!!!!!!!!