Please answer the question in the picture for brainliest

Answer: if that is easy why don't you do it anyways it's x=2(y−6)

Step-by-step explanation: y=

2

1

​

x+6

Swap sides so that all variable terms are on the left hand side.

2

1

​

x+6=y

Subtract 6 from both sides.

2

1

​

x=y−6

Multiply both sides by 2.

2

1

​

2

1

​

x

​

=

2

1

​

y−6

​

Dividing by  

2

1

​

 undoes the multiplication by  

2

1

​

.

x=

2

1

​

y−6

​

Divide y−6 by  

2

1

​

 by multiplying y−6 by the reciprocal of  

2

1

​

.

x=2y−12

SOLVE FOR Y

y=

2

x+12

​

Answer:

Step-by-step explanation:

The altitude of each plane can be expressed by an equation that adds the initial altitude and the product of time and its rate of climb.

  plane A: y = 4057 +60.75t

  plane B: y = 5000 +40.25t

__

We want to find the time when their altitudes are the same:

  4057 +60.75t = 5000 +40.25t . . . . equate the expressions for y

  20.50t = 943 . . . . . . . . . subtract (40.24t +4057)

  t = 46 . . . . . . . . . . . . divide by the coefficient of t

At t=46, the altitude of the planes will be ...

  y = 5000 +40.25(46) = 5000 +1851.5 = 6851.5

The planes are at the same altitude after 46 seconds.

Both planes will be at an altitude of 6851.5 feet.

Answer:

57

Step-by-step explanation:

There are 30 English

There are 28 German

There is one that speaks all 3

30 + 28 - 1 = 57

Answer:

10.1

Step-by-step explanation:

 292.9

   29

                                 29     ×  10

               2929

                290    This is the same as: 2929 / 290  or  2929 ÷ 290

                               = 10.1

WELL UNDERSTOOD????

Answer:

  a)  |sec(θ)|

  b) 2cot(2x)

Step-by-step explanation:

Trig identities are used to simplify these expressions. Several are used:

__

  [tex]\sqrt{1-\tan(180^\circ-\theta)\cot(90^\circ-\theta)}=\sqrt{1-(-\tan(\theta))\tan(\theta)}\\\\=\sqrt{1+\tan^2(\theta)}=\sqrt{\sec^2(\theta)}=\boxed{|\sec(\theta)|}[/tex]

__

  [tex]\dfrac{\cos(2x)\tan(x)}{\sin^2(x)}=\dfrac{\cos(2x)}{\sin^2(x)}\cdot\dfrac{\sin(x)}{\cos(x)}=\dfrac{\cos(2x)}{\sin(x)\cos(x)}\\\\=\dfrac{\cos(2x)}{\left(\dfrac{\sin(2x)}{2}\right)}=2\dfrac{\cos(2x)}{\sin(2x)}=\boxed{2\cot(2x)}[/tex]

Answer:

28/40

Step-by-step explanation:

12+21+7=40

21 times on its side

21/40 cannot be simplified

Finding the complex numbers and subtracting them, it is found that z2 - z1 = (0, -4).

They are in the format:

z = a + bi.

In which:

In a graph, the real part is the horizontal axis, while the imaginary part is the vertical axis. Hence, the numbers are given by:

To find the result of the subtraction, we subtract each part, hence:

z2 - z1 = (2,1) - (2,5) = (2 - 2, 1 - 5) = (0, -4).

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Answer:

The number is 380

Step-by-step explanation:

Let the number be 'x'

[tex]\sf \dfrac{x}{20}=x-361\\\\\text{multiply the entire equation by 20}\\\\20*\dfrac{x}{20}=20*(x-361)[/tex]

x  = 20x - 20*361

x = 20x - 7220

Now subtract '02x' from both sides

x - 20x = -7220

  -19x   =-7220

Divide both sides by (-19)

     x = (-7220) ÷ (-19)

    x = 380

The surface area of the given figure is 90 feet².

The area of a three dimensional object on it's outer surface is called the surface area of the object.

The given figure is a rectangular prism.

A rectangular prism consists of 4 rectangular lateral faces and 2 rectangular bases.

Surface area of the rectangular prism is the area of each of the faces.

Combining all these area, area of a rectangular prism can be found by the formula,

Area = 2 (lw + wh + lh)

where l is the length, w is the width and h is the height.

Given, l = 3 feet, w = 3 feet and h = 6 feet

Area = 2 [ (3 × 3) + (3 × 6) + (3 × 6)]

        = 2 (9 + 18 + 18)

        = 90 feet²

Hence the surface area is  90 feet².

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Answer:

AB=4

Step-by-step explanation:

[tex]\frac{10+x}{2}[/tex][tex]=7[/tex]

Multiply both sides by 2.

10+x=14

x=14-10

x=4

As the ball falls, the velocity of the ball increases with increase in distance

Given Data

It should be noted that when an object falls, it velocity increases from zero to the maximum just before it hits the ground from the initial point of lunch.

Note: For a projectile the ball might reach a zero velocity at maximum height

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Answer:

Part (a)

Given quadratic: [tex]y=x^2+2x-8[/tex]

Factored form

To factor, find two numbers that multiply to -8 and sum to 2: 4 and -2

Rewrite the middle term of the quadratic as the sum of these number:

[tex]\implies y=x^2+4x-2x-8[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies y=x(x+4)-2(x+4)[/tex]

Factor out the common term [tex](x+4)[/tex]:

[tex]\implies y=(x-2)(x+4)[/tex]

Zeros

The zeros of the quadratic polynomial are the x-coordinates of the points where the graph intersects the x-axis, i.e. when y = 0

[tex]\implies y=0[/tex]

[tex]\implies (x-2)(x+4)=0[/tex]

[tex]\implies (x-2)=0\implies x=2[/tex]

[tex]\implies (x+4)=0\implies x=-4[/tex]

Therefore, the zeros are 2 and -4

Vertex

The x-coordinate of the vertex is the midpoint of the zeros.

[tex]\textsf{midpoint}=\dfrac{-4+2}{2}=-1[/tex]

To find the y-coordinate of the vertex, substitute the found value of x into the given equation:

[tex]y=(-1)^2+2(-1)-8=-9[/tex]

Therefore, the vertex is (1, -9)

------------------------------------------------------------------------------------------------

Part (b)

Given quadratic:  [tex]y=-x^2-9x-14[/tex]

Factored form

To factor, first factor out -1:

[tex]y=-(x^2+9x+14)[/tex]

Now find two numbers that multiply to 14 and sum to 9: 7 and 2

Rewrite the middle term of the quadratic as the sum of these number:

[tex]y=-(x^2+2x+7x+14)[/tex]

Factorize the first two terms and the last two terms separately:

[tex]y=-(x(x+2)+7(x+2))[/tex]

Factor out the common term [tex](x+2)[/tex]:

[tex]y=-(x+7)(x+2)[/tex]

Zeros

The zeros of the quadratic polynomial are the x-coordinates of the points where the graph intersects the x-axis, i.e. when y = 0

[tex]\implies y=0[/tex]

[tex]\implies -(x+7)(x+2)=0[/tex]

[tex]\implies -(x+7)=0 \implies x=-7[/tex]

[tex]\implies (x+2)=0 \implies x=-2[/tex]

Therefore, the zeros are -7 and -2

Vertex

The x-coordinate of the vertex is the midpoint of the zeros.

[tex]\textsf{midpoint}=\dfrac{-7+(-2)}{2}=-4.5[/tex]

To find the y-coordinate of the vertex, substitute the found value of x into the given equation:

[tex]y=-(-4.5)^2-9(-4.5)-14=6.25[/tex]

Therefore, the vertex is (-4.5, 6.25)

308 miles

D= s x t

= 56 x 5.5

= 308 miles

30 minutes is half an hour (0.5 or 1/2)

Hope this helps!

Answer:

326.56 sq. units

Step-by-step explanation:

Calculating the slant height

Formula

Subbing in the values

Answer:

1,614,312.

Step-by-step explanation:

0.59% = 0.0059 as a decimal fraction.

Population in 2016 =  1,624,000 - 0.0059 *  1,624,000

= 1614312

Answer:

can you post the question but more clear please because I didn't understand

The sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

[tex]\rm MOE= Z{score}\times \frac{s}{\sqrt{n} }[/tex]

Where  Z_{score} is the z score at the confidence interval

             s is the standard deviation

             n is the number of samples.

We have:

MOE = 2% = 0.02 and

α = 1-0.95 = 0.05

Let's assume the value of p = 0.5, and q = 0.5

From the table:

Z_(0.05/2) = Z_(0.025) = 1.96

[tex]\rm n = 0.5\times0.5\frac{1.96^2}{0.02^2}[/tex]

n = 2401

For part (b):

p = 18% = 0.18, and q = 0.82

[tex]\rm n = 0.18\times0.82\frac{1.96^2}{0.02^2}[/tex]

n = 1417.5 = 1417

Thus, the sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%

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Answer:

Step-by-step explanation:

Answer:

There are 1.07 non winners in group A for every 1 non winner in group B

Or: 1.07:1

Or: 7% more non winners in group A

Step-by-step explanation:

Group A:

765*3/5 = 459 non winners

Group B:

716*3/5 = 429 non winners

Final Calculation:

459/429 = 1.07

Answer:

5 x 10 + 8 = f

Step-by-step explanation:

The reason it is 5 x 10 + 8 = f, is because each bunch has 10 and Ash has five.

In order to find how many flowers he has in 5 bunches is to multiply by how many flowers each bunch has.

Then he gets 8 more flowers which is why it has +8 in the equation.

The equation to get the total number of flowers is the last one:

f = 5*10 + 8

We know that Ash has 5 bunches of flowers, each one contains 10 flowers, so there we have:

5*10 = 50 flowers.

Then he adds 8 more flowers, then we can write the total number of flowers as:

f = 5*10 + 8.

So the equation that we need to use is the last one.

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The value of Betty's earnings of $55,000 in 1992 dolars is $44,141.25.

The consumer price index measures the changes in price of a basket of good.

CPI = (cost of basket of goods in current period / cost of basket of goods in base period) x 100

Value of the current earnings in 1992 dollars = $55,000 / 1.246 = $44,141.25

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Answer:

Area of given triangle is 939.15cm² and smallest altitude is 30.8cm

We are given three sides of a triangle, Let the sides be :

We can find the area of the triangle with its three sides using Heron's Formula

Heron's formula was founded by hero of Alexandria, for finding the area of triangle in terms of the length of its sides. Heron's formula can be written as:

[tex] \sf{ \pmb { \longrightarrow \: \sqrt{s(s - a)(s - b)(s - c)} }}[/tex]

where ( s ) :

[tex] \sf \longrightarrow s = \dfrac{a + b + c}{2} [/tex]

Therefore, for the given triangle first we will calculate ( s )

[tex] \begin {aligned}\quad & \quad \longmapsto \sf s = \dfrac{a + b + c}{2} \\ & \quad \longmapsto \sf s = \dfrac{35 + 54 + 61}{2} \\ & \quad \longmapsto \sf s = \dfrac{150}{2} \\ & \quad \longmapsto \sf s = 75cm \end{aligned}[/tex]

Now, Area of triangle will be:

[tex] \begin{aligned}&:\implies \sf\quad \sf \: A = \sqrt{s(s - a)(s - b)(s - c)} \\ &:\implies \sf\quad \sf \: A = \sqrt{75(75 - 35)(75 - 54)(75 - 61)} \\&:\implies \sf\quad \sf \: A = \sqrt{75 \times 40 \times 21 \times 14} \\ &:\implies \sf\quad \sf \: A = \sqrt{5 \times 5 \times 3 \times 3 \times 2 \times 2 \times 7 \times 7 \times 2 \times 2 \times 5} \\ &:\implies \sf\quad \sf \: A =5 \times 3 \times 2 \times 7 \times 2 \sqrt{5} \\ &:\implies \sf\quad \sf \: A =420 \times 2.23 \\ &:\implies \sf\quad \sf \boxed{ \pmb{ \sf A =939.15 {cm}^{2} }} \end{aligned}[/tex]

Also, we have to find the smallest altitude, and the smallest altitude will be on the longest side. So,

[tex] \begin{aligned}&:\implies \sf\quad \sf \: Area =939.15 \\ &:\implies \sf\quad \sf \: \dfrac{1}{2} \times b \times h =939.15 \\ &:\implies \sf\quad \sf \: \dfrac{1}{2} \times 61 \times h = 939.15 \\&:\implies \sf\quad \sf \: h =939.15 \times \dfrac{2}{61} \\&:\implies \sf\quad \sf \: h = \dfrac{1818.3}{61} \\ &:\implies \sf\quad \boxed{ \pmb{\sf \: h =30.79 \: (approx)}} \end{aligned}[/tex]

Answer:

Area = 939.15 cm² (2 d.p.)

Shortest Altitude = 30.79 cm (2 d.p.)

Step-by-step explanation:

Heron's Formula allows us to find the area of a triangle in terms its side lengths.

Heron's Formula

[tex]\sf Area = \sqrt{s(s-a)(s-b)(s-c)}[/tex]

where:

Given values:

Find the value of s:

[tex]\sf \implies s=\dfrac{a+b+c}{2}=\dfrac{35+54+61}{2}=75\:cm[/tex]

Substitute the values into the formula and solve for area:

[tex]\begin{aligned}\implies \sf Area & =\sf \sqrt{75(75-35)(75-54)(75-61)}\\& = \sf \sqrt{75(40)(21)(14)}\\& = \sf \sqrt{882000}\\& = \sf \sqrt{176400 \cdot 5}\\& = \sf \sqrt{176400}\sqrt{5}\\& = \sf 420\sqrt{5}\\& = \sf 939.15\:\:cm^2\:\:(2\:d.p.)\end{aligned}[/tex]

The altitude of a triangle is a perpendicular line segment drawn from a vertex of the triangle to the side opposite to it.

The shortest altitude of a triangle is drawn to the longest side.

Therefore, the shortest altitude will be the height of the triangle when the longest side is the base:

[tex]\begin{aligned}\textsf{Area of a Triangle} & = \sf \dfrac{1}{2} \times base \times height\\\implies \sf 420\sqrt{5} & = \sf \dfrac{1}{2} \times 61 \times altitude \\\implies \sf Altitude & = \sf \frac{2 \cdot 420\sqrt{5}}{61}\\& = \sf \dfrac{840\sqrt{5}}{61}\\ & = \sf 30.79\:\:cm\:\:(2\:d.p.)\end{aligned}[/tex]

[tex]6x^2-11x -7\\\\=6x^2+3x -14x -7\\\\=3x(2x+1) -7(2x+1)\\\\=(2x+1)(3x-7)[/tex]

Answer:

at least

Step-by-step explanation:

i don't know how to fully explain it, but by saying "atleast x" you're saying the minimum value it can be will be x. Maximum means it will not exceed that number, along with "not greater than" and "at most"

3. b) 85

The total surface area of the hemisphere is the sum of this curved surface area or the area of its base. The base of a hemisphere is circle of radius (r) equal as the radius of the sphere

Given,

hemisphere = 15

hight = 100

so, 100 - 15 = 85

a hemisphere is half of the sphere so to get a hemisphere from the sphere you divide by 2. the hight of the hemisphere is 15 feet so subtract that from the total of the 100 and you get 85.

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Answer:

1. sphere

2. divide by 2

3. 85

Step-by-step explanation:

The combined scores that correspond to 20th percentile is about 1206.

The combined scores that correspond to 75th percentile is about 1724.

The combined scores that correspond to 80th percentile is about 1780.

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given the mean 1493 and standard deviation 342.

a) 20th percentile has a z score of -0.84, hence:

-0.84 = (x - 1493)/342

x = 1206

b) 75th percentile has a z score of 0.675, hence:

0.675 = (x - 1493)/342

x = 1724

c) 80th percentile has a z score of 0.84, hence:

0.84 = (x - 1493)/342

x = 1780

The combined scores that correspond to 20th percentile is about 1206.

The combined scores that correspond to 75th percentile is about 1724.

The combined scores that correspond to 80th percentile is about 1780.

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Answer:

x+10=-3x+38

Step-by-step explanation:

subtract 10 from both sides Subtract the numbers then add 3x on both sides