Plant and Snail Gizmo

Answers

Answer 1
What? Cool okay lol haha
Answer 2
Chose the plant to be the best answe chosen more than a plant

Related Questions

Integrated science please help ASAP!...

Answers

1: sewage
2: agriculture pollution
3: oil pollution
4: radioactive substances
5: river dumping
6: marine dumping
This is all I can find I hope this helps.

Answer:

SewageAgricultural pollutionOilRadioactive substanceRiver dumpingMarine dumpingLittering trash Industrial wasteMining activitiesChemical fertilizers

Explanation:

I hope this helps

Los muelles de un remolque están calibrados para soportar su peso, cuando se carga el remolque con 2100 kg, la fuerza ejercida es de 20580 N comprime los muelles de un remolque 5,5 cm a)Longitud que desciende el remolque si se carga con 28000 N b)Si ha descendido 4,2 cm la carga

Answers

Answer:

a) El remolque desciende 7.4 cm

b) La carga debe ser de 15715.6 N ó 1603.6 kg

Explanation:

Para los cálculos que involucren muelles, se aplica la Ley de Hooke, la cual relaciona el efecto de una Fuerza y el cambio de longitud que esta ejerce,  en un resorte de elasticidad dada.

Escrito en fórmula:

[tex]F=-k \cdot \Delta L[/tex]

Donde:

F es la fuerza ejercida

k es la constante elástica del muelle

ΔL es la variación de longitud del muelle

El problema indica que al cargar 2100 kg se ejerce una fuerza de 20580 N

Esto se corrobora con la 2da ley de Newton y asumiendo una aceleración de gravedad de 9.8 [tex]\frac{m}{s^{2} }[/tex]

[tex]F_{1} =m \cdot a\\F_{1}=2100kg \cdot 9.8\frac{m}{s^2}\\F_{1}=20580N[/tex]

Esta fuerza comprime o reduce la longitud del muelle en 5.5 cm. Usando estos datos en la Ley de Hooke, podemos obtener la constante elástica k:

[tex]F=-k \cdot \Delta L\\20580N=-k \cdot (-0.055m)\\\\k=\frac{20580N}{0.055m}\\k= 374181\frac{N}{m}[/tex]

Ahora ya tenemos los datos para resolver las preguntas:

a) Longitud que desciende el remolque si se carga con 28000 N

Aplicando directamente la formula de la Ley de Hooke:

[tex]F=-k \cdot \Delta L\\\Delta L=\frac{F}{-k} \\\Delta L= \frac{28000N}{-374181\frac{N}{m}} \\\Delta L=-0.074 m = -7.4cm[/tex]

b) Si ha descendido 4,2 cm la carga

En este caso debemos calcular la fuerza necesaria que haga descender el remolque 4.2cm. Nuevamente utilizando la Ley de Hooke con estos nuevos datos:

[tex]F=-k \cdot \Delta L\\F=-374181\frac{N}{m} \cdot (-0.042m)\\F=15715.6N[/tex]

Si queremos saber la carga en kilogramos:

[tex]F = m \cdot a\\m = \frac{F}{a} \\m = \frac{15715.6N}{9.8\frac{m}{s^2} }\\m= 1603.6 kg[/tex]

If a lever has a mechanical advantage of 5 and 50 N of force is used to lift a rock, what is the weight of the rock?

Answers

Green green tea hot green tea green orange

Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?

Answers

Answer:

See the answer below

Explanation:

If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.

If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.

A substance will take on the shape of an open container if it is a

liquid.
plasma.
gas.
solid.

Answers

The answer would be liquid if it is just requiring one answer

Answer:

liquid

Explanation:


[tex] \frac{1}{(1 - \sqrt{3) {}^{2} } } [/tex]

Answers

Answer:

\frac{2+\sqrt{3}}{2}

Explanation:

so we simplify tthe denominator first

[tex](1-\sqrt{3})^2=[/tex][tex]4-2\sqrt{3}[/tex]

so the new fraction is:[tex]\frac{1}{4-2\sqrt{3}}[/tex]

We'll ratinalize the fraction to get: [tex]\frac{2+\sqrt{3}}{2}[/tex]

A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction 5° north of east for an hour.

Answers

Answer:

first one 31

second one 23

Explanation:

on edge ;))

if the volume of a cube is 100cm3. what's the measurement of one of its length​

Answers

Answer:

100 cm

Explanation:

Answer:

4.64

Explanation:

The cube root of 100 is 4.64.

HIII DROPPING COINS YALL

Answers

Answer:

tysm

Explanation:

Answer:

OMG THANK U SO MUCH I NEEDED THEMMMMM

An object in motion will remain in motion and an object at rest will remain at rest until a greater force interrupts it. Explain this concept.

Answers

Answer:

A object, lets say a cup. This cup will never, ever move unless something or someone disturbs it. If something touches or hits this cup the cup will move. But, until the cup gets touched, nothing will EVER make it move.

Explanation:

I hope this helps!!

A 1.0 kg ball has a potential energy of 10 J and falls to the ground. What is the velocity right before it hits the ground?

a)20 m/s
b)10 m/s
c)4.5 m/s
d)15 m/s

Answers

Answer:

10m/s

Explanation:

A rock has a mass of 3.1 kg. What is its weight on earth

Answers

Answer:

W = 30.38 N

Explanation:

Given that,

Mass of a rock, m = 3.1 kg

We need to find the weight of the rock on the surface of Earth. Weight of an object is given by :

W = mg

g is the acceleration due to gravity, g = 9.8 m/s²

W = 3.1 kg × 9.8 m/s²

= 30.38 N

So, the weight of the rock on the Earth is 30.38 N.

Please help which one !!

Answers

Answer:

4th one

Explanation:

How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg

Answers

Answer:

Q = 364.25 kcal

Explanation:

In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.

1. RISE IN TEMPERATURE OF ICE:

First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:

Q₁ = mC₁ΔT₁

where,

Q₁ = Heat absorbed while increasing temperature of ice = ?

m = mass of ice = 0.5 kg

C₁ = specific heat of ice = 0.5 kcal/kg k

ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k

Therefore,

Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)

Q₁ = 2.5 kcal

2. MELTING OF ICE:

Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:

Q₂ = m(Latent Heat of Fusion of Ice)

where,

Q₂ = heat Absorbed during melting of ice = ?

Therefore,

Q₂ = (0.5 kg)(79.7 kcal/kg)

Q₂ = 39.85 kcal

3. RISE IN TEMPERATURE OF WATER:

Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:

Q₃ = mC₃ΔT₃

where,

Q₃ = Heat absorbed while increasing temperature of water = ?

m = mass of water = 0.5 kg

C₃ = specific heat of water = 1 kcal/kg k

ΔT₃ = change in temperature of ice = 100 - 0 = 100 k

Therefore,

Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)

Q₃ = 50 kcal

4. VAPORIZATION OF WATER:

Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:

Q₄ = m(Latent Heat of Vaporization of Water)

where,

Q₄ = heat Absorbed during vaporization of water = ?

Therefore,

Q₄ = (0.5 kg)(539 kcal/kg)

Q₄ = 269.5 kcal

5. RISE IN TEMPERATURE OF STEAM:

Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:

Q₅ = mC₅ΔT₅

where,

Q₅ = Heat absorbed while increasing temperature of steam = ?

m = mass of steam = 0.5 kg

C₅ = specific heat of steam = 0.48 kcal/kg k

ΔT₅ = change in temperature of ice = 110 - 100 = 10 k

Therefore,

Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)

Q₅ = 2.4 kcal

Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:

Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal

Q = 364.25 kcal

How do you compare the mass of proton, neutron, and
electron?

Answers

Answer:Explanation:

Protons and neutrons have very similar mass, while electrons are far lighter, approximately 11800 times the mass. Protons are positively charged, neutrons have no electric charge, electrons are negatively charged. The size of the charges is the same, the sign is opposite.

Why is it possible to see yourself in an object that reflects light, but not in one that scatters light?

Answers

Reflection is when light bounces off an object. If the surface is smooth and shiny, like glass, water or polished metal, the light will reflect at the same angle as it hit the surface. This is called specular reflection. ... Most of the things we see are because light from a source has reflected off it.

Charles, the 75 kg trampoline artist, lands on a trampoline with a speed of 9.0 m/s.
If the trampoline behaves like a spring with a spring constant of 52,000 N/m, what maximum distance will Charles push down the trampoline before bouncing back up? (Hint: at maximum compression, Charles is not moving.)

Answers

Answer:

The maximum distance Charles will push down the trampoline ≈ 0.342 m

Explanation:

The given parameters are;

The mass of the trampoline artist, m = 75 kg

The speed with which the trampoline artist lands, v = 9.0 m/s

The value of the spring constant of the trampoline, k = 52,000 N/m

Let x represents the maximum distance Charles will push down the trampoline

Therefore, we have;

Kinetic energy = 1/2·m·v²

The kinetic energy with which the trampoline artist lands  = 1/2 × 75 × 9.0² = 3037.5

The kinetic energy with which the trampoline artist lands  =  3037.5 J

The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands

∴ 1/2 × 52,000 × x² = 3037.5

∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342

The maximum distance Charles will push down the trampoline = x ≈ 0.342 m

Where are alkaline earth metals found on the periodic table?

Group 1
Group 2
Groups 3–12
Group 17

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

I had a feeling

A red 120 kg bumper car moving at 4 m/s collides with a green 100 kg bumper car moving at 3 m/s. The red bumper car bounces off at 2 m/s. What is the green car's final velocity?​

Answers

we can utilize the equation pi=pf (p=momentum). because p=mv, we can sub in the initial masses and velocities as well as the finals in order to form an equation. this results in 120(4)+100(3)=120(2)+100x. this can be simplified to 540=100x, or x=5.4 m/s.

SOMEONE PLEASE HELP WITH THIS QUESTION!!!!

Answers

Answer:

A 1

B 3

c 4

d 3

Explanation:

we are chaimpon boy i topped my school by cheating so donot study chill and watch movies like of sunny leon and Sabita bhabi

what makes up a atom

Answers

Answer:

They're typically made up of three main parts: protons, neutrons and electrons. Think of the protons and neutrons as together forming a “sun”, or nucleus, at the centre of the system. The electrons orbit this nucleus, like planets. If atoms are impossibly small, these subatomic particles are even more so.

Explanation:

hope i helped.

Answer:

Atoms consist of a nucleus made of protons and neutrons orbited by electrons. ... We now know that atoms are made up of three particles: protons, neutrons and electrons — which are composed of even smaller particles, such as quarks.

Explanation:


An object starts at 16 m/s with an acceleration of 4.5 m/s? How far does it go in 9.0 seconds?

Answers

648 because 16 times 4.5 is 72 and that times 9 is 648

why is thouching the live wire of an appliane when it is connecfed to the mains dangerous

Answers

Answer: The live wire is the most dangerous one, since it is at 230 V. it should never touch the earth wire (unless the insulation is between them, of course!), because this would make a complete circuit from your mains supply to the ground (earth). A shock or fire would be highly likely.

Explanation:

Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3

Answers

Answer:

2,3,1

Explanation:

There are 3 laws of Kepler.

First law = The path of each planet around the sun is an ellipse with the sun at one focus.

Second law =  As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.

Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.

Hence, the correct order for Kepler's law is: 2,3,1

A car of mass 1000 kg travelling at a velocity of 25 m/s collides with another car of mass 1500kg which is at rest. The two cars stick and move off together. What is the velocity of the two cars after the collision?​

Answers

Answer:

The velocity of the two cars is 10 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=m.v

If we have a system of bodies, then the total momentum is the sum of them all

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If some collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum  takes the form:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

If both masses stick together after the collision at a common speed v', then:

[tex]m_1v_1+m_2v_2=(m_1+m_2)v'[/tex]

The car of mass m1=1000 Kg travels at v1=25 m/s and collides with another car of m2=1500 Kg which is at rest (v2=0).

Knowing both cars stick and move together after the collision, their velocity is found solving for v':

[tex]\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]

[tex]\displaystyle v'=\frac{1000*25+1500*0}{1000+1500}[/tex]

[tex]\displaystyle v'=\frac{25000}{2500}[/tex]

v' = 10 m/s

The velocity of the two cars is 10 m/s after the collision.

Please find attached photograph for your answer.

when it comes to graphs I am no genius lol​

Answers

Answer:

Option B

Explanation:

Displacement  = Area under the velocity-time graph

So to find the displacement of a particle from 7 to 8 seconds we take the triangle and calculate its area.

[tex]Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(base)*(height) \\\\Area\ of\ a\ right\ angled\ triangle = \frac{1}{2}*(1)*(3) \\\\Area\ of\ a\ right\ angled\ triangle = 1.5[/tex]

So the displacement is 1.5 meters

I have an uploaded image so you can understand it better hope it helps

How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?

Answers

Answer:

100 Watts

Explanation:

These equations are needed to work out the answer:

power= work done/ time takenwork done= force* distanceforce= mass* acceleration

force: 10 kg* 2m/s= 20

work done: 20* 10m=200

power: 200/2=100

What connects the colon to the anus?AColon B Anus C Rectum D Biceps​

Answers

The answer is C. Rectum.

Answer:

You have a severe case.

Explanation:

My anus smells foul, like poop or diarrhea. Why? Like your anus might be tired of making the same old sensational brown. No fear needed! Anus Maker is here! With this app, you can post poop photos for help if you need! No more foul sensational browns! Start your free Anus Maker trial today!

which one?? please someone quick!​

Answers

Answer:

i think its second law of motion.

Explanation:

Answer:

it’s the second law

Explanation:

Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by dEdt=q2a26πϵ0c3 where c is the speed of light.Part AIf a proton with a kinetic energy of 5.0 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.530 m , what fraction of its energy does it radiate per second?(dE/dt)⋅1sE =

Answers

Answer:

 P /K = 1,997 10⁻³⁶  s⁻¹

Explanation:

For this exercise let's start by finding the radiation emitted from the accelerator

       [tex]\frac{dE}{dt}[/tex] = [tex]\frac{q^{2} a^{2} }{6\pi \epsilon_{o} c^{2} }[/tex]

the radius of the orbit is the radius of the accelerator a = r = 0.530 m

let's calculate

       \frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]

      P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W

Now let's reduce the kinetic energy to SI units

       K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J

the fraction of energy emitted is

      P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹

      P /K = 1,997 10⁻³⁶  s⁻¹

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