perform the calculation then round to the appropriate number of significant digits
Answers
The given expression is,
[tex]\frac{308.45}{1.12}[/tex]On division we get,
[tex]\frac{308.45}{1.12}=275.4017[/tex]On rounding we get, 275.402.
Related Questions
Lincoln made 3 quarts of iced tea and Jasmine made 5 quarts of iced tea using the same recipe. Part A: How many cups of iced tea did Lincoln and Jasmine make all together? cho mark
Answers
Part A
number of ice tea lincoln made = 3 quarts
number of ice tea jasmine made = 5 quarts
Altogether we have = 8 quarts
But, there are four cups in 1 quart
Therefore, 8 quarts would give 8 x 4 cups = 32 cups
In conclusion, jasmine and lincoln made 32 cups of ice tea altogether.
Part B
There are 16 cups in one gallon
Lincoln and jasmine made 32 cups of ice tea
Therefore the number of gallons of ice tea they made is
=32/16 = 2gallons
Also, 1/2 bottle = 1 gallon
Therefore, the 2 gallons would give
[tex]\begin{gathered} =\frac{2}{\frac{1}{2}}=\frac{2}{0.5}=4 \\ \end{gathered}[/tex]Therefore the 2 gallons would give 4 bottles of ice tea
question: determine whether the function is one-to-one. If it is sketch the graph of its inverse.i already found out it is a one-to-one, i just don't know how to graph its inverse
Answers
The inverse function of f(x) = y is f(y) = x
This means, switch the coordinates of the points of the graph
If we choose a point on the given graph like (5, 3) it will be (3, 5) in the inverse function
Also, point (-5, -3) it will be (-3, -5) in the inverse function
You can plot them with point (0, 0) and draw the curve
Let me try to show it
It will be like that
A convenience store manager notices that sales of soft drinks are higher on hotter days, so he assembles the data in the table. (a) Make a scatter plot of the data. (b) Find and graph a linear regression equation that models the data. (c) Use the model to predict soft-drink sales if the temperature is 95°F.
Answers
ANSWER and EXPLANATION
a) First we have to make a scatter plot. We do this by plotting the calues of High Temperature on the x axis and Number of cans sold on the y axis:
b) We want to find and graph the linear regression equation that models the data.
The linear regression equation will be in the form:
y = a + bx
[tex]\begin{gathered} \text{where} \\ a\text{= }\frac{(\sum ^{}_{}y)(\sum ^{}_{}x^2)\text{ - (}\sum ^{}_{}x)(\sum ^{}_{}xy)}{n(\sum ^{}_{}x^2)\text{ }-\text{ (}\sum ^{}_{}x)^2} \\ \text{and b = }\frac{n(\sum ^{}_{}xy)\text{ - (}\sum ^{}_{}x)(\sum ^{}_{}y)}{n(\sum ^{}_{}x^2)\text{ }-\text{ (}\sum ^{}_{}x)^2} \end{gathered}[/tex]We have from the question that:
x = High Temperature
y = Number of cans added
So, we have to find xy and x^2. We will form a new table:
Now, we will find a and b:
[tex]\begin{gathered} a\text{ = }\frac{(4120)(39090)\text{ - (}554)(297220)}{8(39090)\text{ }-554^2} \\ a\text{ = }\frac{\text{ 161050800 - 164659880}}{312720\text{ - 306916}} \\ a\text{ = }\frac{-3609080}{5804} \\ a\text{ }\cong\text{-62}2 \end{gathered}[/tex][tex]\begin{gathered} b\text{ = }\frac{8(297220)\text{ - (554})(4120)}{5804} \\ b\text{ = }\frac{2377760\text{ - 2282480}}{5804} \\ b\text{ = }\frac{95280}{5804} \\ b\text{ }\cong\text{ 16} \end{gathered}[/tex]Therefore, the linear regression equation is:
y = -622 + 16x
Now, let us graph it using values of x (High Temperature):
That is the Linear Regression Graph.
c) To predict soft drink sales if the temperature is 95 degrees Farenheit, we will put the x value as 95 and find y. That is:
y = -622 + 16(95)
y = 898
The model predicts that 898 cans of soft drinks will be sold when the High Temperature is 95 degrees Farenheit.
4 ft 12 ft The pitch of the roof is
Answers
As shown : in the figure
The pitch of the roof is the angle between the roof and the horizontal line
As shown we have a right angle triangle
The opposite side to the angle = 4 ft
And the adjacent side to the angle = 12 ft
According to the given sides, we will calculate the angle using tan function
So, let the angle = x
So,
[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent} \\ \\ \tan x=\frac{4}{12}=\frac{1}{3} \\ \\ x=\tan ^{-1}\frac{1}{3}\approx18.435^o \end{gathered}[/tex]So, the pitch angle of the roof = 18.435
instead of writing the angle , just we will write the slope = rise/run
So, the pitch of the roof = 1/3
find the volume and total surface area of a right circular cone whose base diameter is 10 cm and whose altitude is 20 cm.
Answers
SOLUTION
Given the question in the question tab, the following are the solution steps to calculate the required measurements.
Step 1: write the given parameters
[tex]\begin{gathered} \text{diameter}=10\operatorname{cm},\text{altitude}=\text{height}=20\operatorname{cm} \\ r=\frac{d}{2}=\frac{10}{2}=5\operatorname{cm} \end{gathered}[/tex]Step 2: Calculate the volume of the right circular cone
[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ V=\frac{\pi\times5\times5\times20}{3} \\ V=\frac{500\pi}{3}=523.5987756 \\ V\approx523.5988\operatorname{cm}^3 \end{gathered}[/tex]Step 3: Calculate the total surface area of the right circular cone
[tex]\begin{gathered} \text{TSA}=\pi r(r+\sqrt[]{h^2+r^2)} \\ \text{TSA}=\pi(5)(5+\sqrt[]{20^2+5^2)} \\ \text{TSA}=5\pi(5+\sqrt[]{400+25)} \\ \text{TSA}=5\pi(5+\sqrt[]{425})=5\pi(5+20.61552813) \\ \text{TSA}=5\pi(25.615528134) \\ \text{TSA}=402.3677749 \\ \text{TSA}\approx402.3678cm^2 \end{gathered}[/tex]Hence, the volume and the total surface area of the given right circular cone are approximately 523.5988cm³ and 402.3678cm² respectively
The annual rainfall in a town has a mean of 54.11 inches and a standard deviation of 12.59 inches. Last year there was rainfall of 48 inches. How many standard deviations away from the mean is that? Round your answer to two decimal places.
Answers
SOLUTION
Mean=54.11, standard deviation = 12.59
X=48
Using the z formula
[tex]z=\frac{x-\mu}{\sigma}[/tex]Substituting values gives
[tex]z=\frac{48-54.11}{12.59}[/tex]Solve for z
[tex]z=-0.4853[/tex]This shows that the result shows that the value x=48 is 0.4853 standard deviation to the left of the mean.
What is the slope of this line? :(
Answers
Answer:
y=1/4x+1
Step-by-step explanation:
Answer:
m=1/4
Step-by-step explanation:
Got it correct
32Lucky Lanes Bowling Alley is putting this design on its roof.4 feet4 feet20 feet4 feet4 feet10 feet
Answers
In order to find the volume of the design, we want to find the volume of the figures that compound it:
Total volume = volume 1 + volume 2
Volume 1The volume of each box is given by the product of its sides:
side 1 x side 2 x side 3.
In this case, we have that
side 1 = 4 ft
side 2 = 4 ft
side 3 = 20 ft - 4 ft = 16 ft
Then,
side 1 x side 2 x side 3.
↓
volume 1 = 4 ft x 4 ft x 16 ft = 256 ft³
volume 1 = 256 ft³
Volume 2For the second part we have that:
side 1 = 4 ft
side 2 = 4 ft
side 3 = 10 ft
Then,
side 1 x side 2 x side 3.
↓
volume 2 = 4 ft x 4 ft x 10 ft = 160 ft³
volume 2 = 160 ft³
Total volumeThe total volume is given by
Total volume = volume 1 + volume 2
↓
Total volume = 256 ft³ + 160 ft³
Total volume = 416 ft³
Answer: 416 ft³
Evaluate h(x) at x = 6, x = 8, and x= 12. h(x)=1.31^×
Answers
Answer : h(6) = 5.054
h(8) = 8.673
h(12) = 25.542
Given that h(x) = 1.31^x
[tex]\begin{gathered} h(x)=1.31^x \\ \text{ find the value of h(6) when x = 6} \\ h(6)=1.31^6 \\ h(6)\text{ = 5.05}4 \\ \text{when x = 8} \\ h(8)=1.31^8 \\ h(8)\text{ = 8.67}3 \\ \text{when x = 12} \\ h(12)=1.31^{12} \\ h(12)\text{ = 25.54}2 \end{gathered}[/tex]Therefore,
h(6) = 5.054
h(8) = 8.673
h(12) = 25.542
10 ptsQuestion 3Find the measure of each interior angle. Round to the nearest hundredth.4x(6x - 90)(3x + 31)(7x+19)X=(4x)" =(6x - 90)(7x + 19)° =(3x + 31)º =
Answers
Alexandre, this is the solution:
Let's recall that the interior angles of a rhombus add up to 360 degrees.
Upon saying that, we have:
4x + 3x + 31 + 6x - 90 + 7x + 19 = 360
20x - 40 = 360
Adding 40 at both sides:
20x - 40 + 40 = 360 + 40
20x = 400
Dividing by 20 at both sides:
20x/20 = 400/20
x = 20
Now, we can calculate each of the angles and prove they add up to 360 degrees, as follows:
• 4x = 4 * 20 =, 80
,• 3x + 31 = 3 * 20 + 31 = 60 + 31 =, 91
,• 7x + 19 = 7 * 20 + 19 = 140 + 19 = ,159
,• 6x - 90 = 6 * 20 - 90 = 120 - 90 = ,30
80 + 91 + 159 + 30 = 360
I need help with solving this: what is the 8th term to 1,5,25,125,..
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
1,5,25,125,..
Step 02:
[tex]an=5^{n-1}[/tex]if n = 8
[tex]a_8=5^{8-1}=5^7=78125[/tex]The answer is:
8th term is 78125
multiply mentally to find the product
Answers
8 * 404 = 8(----- + 4)
At first, we will split 404 into two numbers one of them is 4
To find the other number subtract 4 from 404
404 - 4 = 400
8 * 404 = 8(400 + 4)
Now we will multiply 8 by 40 and 8 by 4
8(400 + 4) = 8 * 400 + 8 * 4
It is easy to find the product of 8 and 4
8 * 4 = 32
8 * 400 = 3200
Let us add them
3200 + 32 = 3232
The answer is 3232
A company charges $7 dor a t-shirt and ships any order for $22 a school principal ordered a number of t-shirts for the school store the total cost of the order was 1,520 how many t-shirts did the principal buy
Answers
the equation is
[tex]7x+22=1520[/tex]then solve for x
[tex]\begin{gathered} 7x+22-22=1520-22 \\ 7x=1498 \\ \frac{7x}{7}=\frac{1498}{7} \\ x=214 \end{gathered}[/tex]answer: the principal bought 214 t-shirts
Based on a recent study, the pH level of the arterial cord (one vessel in the umbilical cord) is normally distributed with mean 7.38 and standard deviation of 0.14. Find the percentageof preterm infants who have the following arterial cord pH levels.a. pH levels between 7.00 and 7.50.b. pH levels over 7.46A.The percentage of arterial cord pH levels that are between 7.00 and 7.50 is ____%.(Round to two decimal places as needed.)B.The percentage of arterial cord pH levels that are over 7.46 is ___%.(Round to two decimal places as needed.)
Answers
We have the pH level as a random normal variable with mean 7.38 and standard deviation of 0.14.
A) We have to calculate the percentage of infants that are expected to have pH levels between 7.00 and 7.50.
We can approximate this as the probability of selecting a random infant and it has a pH level within this interval.
Then, to calculate the percentage we will use the z-scores for each boundary of the interval:
[tex]z_1=\frac{X_1-\mu}{\sigma}=\frac{7-7.38}{0.14}=\frac{-0.38}{0.14}\approx-2.7143[/tex][tex]z_2=\frac{X_2-\mu}{\sigma}=\frac{7.5-7.38}{0.14}=\frac{0.12}{0.14}\approx0.8571[/tex]Then, we can use the standard normal distribution to look for the probabilities for each z-score and calculate the probability as:
[tex]\begin{gathered} P(7.00Given that the probability is 0.80099, we can express the percentage as:[tex]P=0.80099\cdot100\%=80.01\%[/tex]B) We now have to calculate the percentage that is above 7.46.
We start by calculating the z-score as:
[tex]z=\frac{X-\mu}{\sigma}=\frac{7.46-7.38}{0.14}=\frac{0.08}{0.14}\approx0.571428[/tex]Then, we can calculate the probability as:
[tex]P(X>7.46)=P(z>0.571428)\approx0.28385[/tex]This correspond to a percentage of 28.39%.
Answer:
A) 80.01%
B) 28.39%
3x - 4y = 65x + 8y = -1
Answers
If 200 is added to a positive integer I, the result is a square number. If 276 is added to to the same integer I, another square number is obtained. Find I.
Answers
Solution:
[tex]\begin{gathered} Let\text{ } \\ 200\text{ + I= x}^2----------\left(1\right) \\ 276+I\text{ =y}^2----------\left(11\right) \\ Subtract\text{ equation \lparen1\rparen from equation \lparen11\rparen} \\ 276+1-\left(200_+I\right?=y^2-x^2 \\ 76=\left(y-x\right?\left(y+x\right? \end{gathered}[/tex]Now y+x and y-x differ in 2x.
One of them is even, because their product is even, so the other must be even too.
76=2*2*19 and 19 is prime.
We can assume x,y>=0,
Thus, y+x=2.19, and y-x=2
from here y=20, x=18
Therefore,
[tex]\begin{gathered} 200+1=18^2 \\ 200+I=324 \\ I=324-200 \\ I=124 \end{gathered}[/tex]The answer is I = 124
if sound travels at 335 miles per second through air and a plane is 2680 miles away how long will the sound take to reach the people
Answers
It will take 8 seconds for the sound to reach the people
Here, we want to calculate time
Mathematically;
[tex]\begin{gathered} \text{time = }\frac{dis\tan ce}{\text{speed}} \\ \end{gathered}[/tex]With respect to this question, distance is 2680 miles while speed is 335 miles per second
Substituting these values, we have;
[tex]\text{time = }\frac{2680}{335}\text{ = 8}[/tex]On December 13, 2007, one South African rand was worth 0.15 U.S. dollars.(a) On that date, how many rand was 44.11 dollars worth?Round your answer to the nearest hundredth of a rand.rand(b) On that date, how many dollars was 168.18 rand worth?Round your answer to the nearest hundredth of a dollars. I need help with this math problem.
Answers
Explanation
Part A
Given that one South African rand was worth 0.15 U.S. dollars. 44.11 dollars will be worth
[tex]\frac{44.11}{0.15}=294.07[/tex]Answer: 294.07 rands
Part B
On that date, how many dollars was 168.18 rand worth?
[tex]168.18\times0.15=25.23[/tex]Answer: 25.23 dollars
Ethan's income is 4500 per month a list of some of his expenses appear below what percent of Ethan's expenses is food?
Answers
Ethan's earns 4500$ per month*
the amount spent on the food is 600 $
so percentage will be'
[tex]=\frac{4500}{600}=\frac{1500}{200}=7.5\text{ \%}[/tex]so the answer is the percentage amount spent on food is, 7.5 %
You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the length of a grass median that will be exactly as long as four parking spots and their dividing lines. One of these spots is a handicapped spot, which is 1018 feet wide and next to the curb. The other three spots are 838 feet wide. There are four dividing lines between the spots, and each measures 18 foot. What is the length of the grass median, D?
Answers
SOLUTION
From the given information:
one of the spots is
[tex]10\frac{1}{8}ft[/tex]Other three spots are
[tex]8\frac{3}{8}ft\text{ wide}[/tex]There are four dividing line of
[tex]\frac{1}{8}\text{foot}[/tex]The total length of the grass median is:
[tex]10\frac{1}{8}+3(8\frac{3}{8})+4(\frac{1}{8})[/tex]Calculate the value
[tex]\begin{gathered} \frac{81}{8}+3(\frac{67}{8})+\frac{4}{8} \\ =\frac{81}{8}+\frac{201}{8}+\frac{4}{8} \\ =\frac{81+201+4}{8} \\ =\frac{286}{8} \end{gathered}[/tex]Reduce the fraction
[tex]\frac{286}{8}=35\frac{6}{8}=35\frac{3}{4}[/tex]Therefore the length of the grass median is
[tex]35\frac{3}{4}[/tex]JCPenney sells jeans for $49.50 that cost $38.00. What is the percent markup on cost? Check the cost. (Round your answer to the nearest hundredth percent.)
Answers
The percent mark up on the cost is 30.26%.
How to find the percent mark-up on cost?JCPenney sells jeans for $49.50 that cost $38.00.
The percent mark up can be calculated as follows:
Mark up percentage is calculated by dividing the gross profit of a unit by the cost of that unit.
In other words, Mark-up percentage is the difference between a product's selling price and cost as a percentage of the cost.
Hence,
selling price = $49.50
cost price = $38.00
mark up = 49.50 - 38 = 11.5
Therefore,
percent mark up = 11.5 / 38 × 100
percent mark up = 1150 / 38
percent mark up = 30.2631578947
Therefore,
percent mark up = 30.26%
learn more on percent mark up here: brainly.com/question/12284542
#SPJ1
Find the perimeter of the isosceles triangle in simplest form. x2 + 20 units 2x units
Answers
The perimeter of an isosceles triangle is given by:
[tex]P\text{ = 2a + b}[/tex]From the question, b = 2x; a = x^2 + 20
[tex]P\text{ = 2a }+b=2(x^2+20)+2x=2x^2+40\text{ + 2x}[/tex][tex]P=2x^2\text{ + 2x + 40}[/tex]after a translation 8 units left
Answers
The given transformation is 8 units left.
The pre-image vertices are A(1,-4), B(1,-6), C(5,-6), and D(5,-4).
Using the transformation, we have:
[tex]\begin{gathered} A^{\prime}(1-8,-4)=A^{\prime}(-7,-4) \\ B^{\prime}(1-8,-6)=B^{\prime}(-7,-6) \\ C^{\prime}(5-8,-6)=C^{\prime}(-3,-6) \\ D^{\prime}(5-8,-4)=D^{\prime}(-3,-4) \end{gathered}[/tex]The image below shows the graph of the image
0.25(60) + 0.10x = 0.15(60 + x)
Answers
Answer: X = 120
Step-by-step explanation:
lol:
V = (−∞,∞)
X = 120
Triangle BCA is similar to Triangle STR . What is the value of x?
Answers
Sin the triangles are similar the ratio 4 to 6 should hold for any side, this means that:
[tex]\frac{4}{6}=\frac{x}{9}[/tex]Solving for x we have:
[tex]\begin{gathered} \frac{4}{6}=\frac{x}{9} \\ x=9(\frac{4}{6}) \\ x=\frac{36}{6} \\ x=6 \end{gathered}[/tex]Therefore. x=6.
Below, the two-way table is given for aclass of students.Freshmen Sophomore Juniors Seniors TotalMale 462. .Female 33246TotalIf a student is selected at random, find theprobability the student is a junior. Roundto the nearest whole percent.
Answers
The final answer is: 27%
We are asked to find the probability that a student chosen at random is a junior. This requires that we know the total number of students in each level from Freshmen to Seniors.
Totals:
Freshmen = 4 + 3 = 7
Sophomore = 6 + 4 = 10
Juniors = 2 + 6 = 8
Seniors = 2 + 3 = 5
Thus we can calculate the total number of students considered:
7 + 10 + 8 + 5 = 30 students in total.
Now we can calculate the probability as:
[tex]\begin{gathered} P(\text{choosing juniors) = }\frac{Number\text{ of Juniors}}{\text{Total Number of Students}} \\ \end{gathered}[/tex]The number of Juniors was calculated earlier as: Juniors = 8
We have the total number of students as 30
Therefore, we can solve:
[tex]P(\text{choosing juniors)=}\frac{8}{30}=\frac{4}{15}[/tex]But we were asked to round to the nearest whole percent, which means we are required to put the fraction into percentage.
The way we do this is to multiply the fraction by 100%
[tex]\begin{gathered} \frac{4}{15}\times100=26.6667. \\ \\ \therefore P(\text{choosing juniors)=27\% (to the nearest whole percent)} \end{gathered}[/tex]Therefore the final answer is: 27%
How far is the girl from the monument that is 30 ft high? Round your answer to a nearest foot. Show your work.
Answers
Given:
The diagram is shown alongside.
The height of the monument is 30 ft high.
The angle of elevation is 63 degrees
The objective is to find the distance between the monument and where the girl is standing.
Since it forms a right angled triangle so we can apply trigonometric ratios:
Now,
[tex]\tan 63^{\circ}=\frac{perpendicular}{\text{base}}[/tex]Perpendicular = 30 ft
Base = ?
Substituting the values,
[tex]\begin{gathered} \tan 63^{\circ}=\frac{30}{\text{base}} \\ \text{Base}=\frac{30}{\tan63^{\circ}} \\ \text{base}=\frac{30}{1.962610} \\ \text{base}=15.285767422\text{ ft} \end{gathered}[/tex]Therefore, the girl is at a distance of 15 ft from the monument.
Which table shows a proportional relationship between miles traveled and gas used?
Miles Traveled Gas Used
27.3 mi 1.5 gal
49.16 mi 3.8 gal
Miles Traveled Gas Used
120 mi 6.2 gal
180 mi 12.2 gal
Miles Traveled Gas Used
135 mi 7.4 gal
135.5 mi 7.9 gal
Miles Traveled Gas Used
270 mi 15 gal
135 mi 7.5 gal
Answers
Answer:
D
Step-by-step explanation:
270mi 15gal
135mi 7.5gal
135/270=0.5
7.5/15=0.5
or
135/7.5=18
270/15=18
Which of the following represents the translation of R (-3, 4), along the vector <7, -6> <-1, 3>.
Answers
Solution
Step 1:
The translation is a term used in geometry to describe a function that moves an object a certain distance.
Step 2:
Pre-mage R = (-3,4)
Step 3:
When moved along (7, -6) the new coordinates become:
R' = (-3+7 , 4 - 6 ) = (4 , -2)
R' = ( 4 , -2 )
Step 4:
When moved along (-1, 3) the new coordinates become:
R'' = ( 4-1 , -2+3 ) = ( 3 , 1 )
R'' = (3 , 1)
Final answer
[tex]R(-3\text{ , 4\rparen }\rightarrow\text{ R'\lparen4 , -2\rparen }\rightarrow\text{ R''\lparen3 , 1\rparen}[/tex](a) How high is the javelin when it was thrown? How do you know?(b) How far from the thrower does the javelin strike the ground?
Answers
The height of the javelin is given by
[tex]h(x)=-\frac{1}{20}x^2+8x+6[/tex]Here, x is the horizontal distance from the point at which the javelin is thrown.
a)
When the javelin is thrown, the horizontal distance from the point at which the javelin is thrown is zero. So, put x = 0 to find the height of the javelin when thrown. So, the distance:
[tex]\begin{gathered} h(0)=-\frac{1}{20}(0)^2+8(0)+6 \\ =0+0+6 \\ =6 \end{gathered}[/tex]Thus, the height of the javelin when it was thrown is 6 ft.
b)
When the javelin strikes the ground the value of h(x) is zero.
Find the value of x when h(x) is zero.
[tex]\begin{gathered} h(x)=0 \\ -\frac{1}{20}x^2+8x+6=0 \\ -x^2+160x+120=0 \\ x^2-160x-120=0 \end{gathered}[/tex]Now, the roots of the equation are x = 160.74 and x = -0.74.
The distance cannot be negative. So, the javelin is 160.74 ft far from the thrower when it strikes the ground.