The resultant displacement of Noah from the question is 2.9 miles.
What is the resultant displacement?The displacement is a vector quantity. Recall that a vector quantity is going to posses both a magnitude and a direction as we can see. This implies that the result of the vector which is the single vector that has the combines effect in magnitude and direction as all the vectors put together would be obtained by a geometric rather than an algebraic method. We now have to apply the rules that are used to obtain the resultant vector in each of the cases that does apply here.
We are now told that he drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. The resultant of the vector in the North - South direction is; 1.85 miles - 0.35 miles = 1.5 miles.
Then the general resultant vector is obtained from;
R = √(1.5)^2 + (2.43)^2
R = 2.9 miles
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A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides
The free body diagram of the crate can be shown as,
Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.
how does heat move from the inside to the outside in the outer 30% of the sun? through neutrinos released by nuclear fusion by convection: hot gas rises and cool gas sinks by radiation: photons bounce around heating up the gas by sound waves
Heat moves from the inside to the outside in the outer 30% of the sun by hot gas rises and cool gas sinks by radiation.
Radiation is the exchange of heat vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is imperceptible. As it were a little parcel comes as obvious light.
Energy from the sun is exchanged through space and the earth's climate to the earth's surface. Since this vitality warms the earth's surface and environment, a few of it is or gets to be heat vitality.
Even though you're encompassed by discussion, the discussion has nothing to do with this exchange of heat.
Heat lights, that keep food warm, work in the same way. Radiation is the exchange of warm vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is undetectable.
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An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What is the rate of conversion of the electrical energy to other forms?
Therefore:
[tex]P_{out}:P_{in}=\frac{P_{out}}{P_{in}}=\frac{1600W}{5000W}=0.32[/tex]Answer:
1600W
a football player runs from a location 5m from the left sideline and 5m from his/her goal line to a location 35m from the left sideline and 60m from the goal-line. displacement is 63m. the player did not run in a straight line. at the start there is 1-minute left on the clock; at the end there is 50 seconds left on the clock. knowing only this information, what kinematic variables can we calculate?
Knowing only this information, the kinematic variable we can calculate is Vavg = 6.3 m/s. Option B - average velocity
velocity is the directional velocity of an object in movement as an illustration of its rate of trade in function as found from a selected body of reference and as measured by means of a specific standard of time.
The average velocity is defined because of the alternate in function or displacement (∆x) divided by the point durations (∆t) in which the displacement takes place. The common pace may be tremendous or negative relying upon the sign of the displacement.
As it is given that the player is not moving in a straight line then distance and Displacement will not same.
We know average velocity is the ratio of total displacement to the time and if both are known then it can find easily.
Hence average speed can't be found
Vavg = 63/(60-50) m/s
Vavg = 6.3 m/s
Instantaneous velocity is the velocity at a certain point of time that can't be found because there is only given initial & final locations
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a wire having mass per unit length of 0.460 g/cm carries a 2.12 a current horizontally to the south. what are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward? magnitude
The direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward is clock wise direction and 0.245T.
What is a magnetic field?The magnetic field is the area that is affected by magnetism and is located around a magnet. The magnetic field is a valuable tool for explaining the distribution of the magnetic force within and around a magnetic object in nature.
The mass per unit length of the wire = 0.460 g/cm = 0.046 kg/m
Current in the wire, A = 2.12 A (due south)
To find,
The minimal magnetic field's magnitude as well as its direction.
F = ILB = mg
B = mg/IL
B = 0.046 × 9.8 /2
B = 0.225T
B = 0.245T.
The right hand rule specifies the magnetic field's direction, which is clockwise around the wire.
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a soccer ball is kicked from the ground with an initial speed of 19.5 m/s at an upward angle of 45o. a player 55m away in the direction of the kick starts running to meet the ball at that instant. what must be his average speed if he is to meet the ball just before it hits the ground?
Answer:
R = V^2 sin 2θ / g range formula
R = 19.5^2 * 1 / 9.80 = 38.8 m
Vx = 19.5 cos 45 = 13.8 m/s horizontal speed
t = R / Vx = 38.8 / 13.8 = 2.81 sec
v = (55 - 38.8) / 2.81 = 5.76 m/s (about 12.9 mph)
a lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline and its light makes four revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p?
A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min
3*10/9*8pi = dx/dt
80pi/3 = dx/dt
dx/dt = 83.78 km/min
Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.
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An object took 15.3 seconds to strike the ground after it was released from a certain
height. Find the height of the object just prior to being released. Round to nearest hundredths
The object took 15.3 seconds to reach the ground when released.Then the height of the object just prior to being released will be 1147 m.
What is gravity?Gravity, g of is a downward force acting on a body which is moving or at rest at positioned at a height h from the surface.
Gravity is the downward acceleration of a moving body and it have value equal to 9.8 m/s². If the time taken to hit the ground when released from a height is t, then thee equation connecting this time, height h and g is written as follows;
h = 1/2 gt².
Hence, the height of the object prior to the point of releasing is calculated as follows:
h = 1/2 9.8 m/s² × (15.3 s )²
= 1147 m.
Therefore, height of the object just prior to being released will be 1147 m.
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an object is launched from ground level with an initial speed of 24.6 meters/second at an upward angle of 0.595 radians above the horizontal (90 degrees is about 1.57 radians). how far will it travel horizontally before hitting the ground?
The object will travel 55.67 meters horizontally before hitting the ground.
The object is launched with speed 24.6 meters/second.
The angle at which the object is launched is 0.595 radians.
We know,
90° = 1.57 radians
1 radian = 90°/1.57
So,
0.595 radians = 90°(0.595)/1.57
0.595 radians = 34°
The horizontally distance R travelled by the projectile can be given by,
R = U²sin2A/g
Where, U is the initial speed,
A is the angle at which object is launched,
g is acceleration due to gravity,
Putting all the values,
R = (24.6)²sin(68°)/10
R = 55.67 meters.
The horizontal range is 55.67 meters.
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a certain amount of work w is required to accelerate a motorcycle from rest to a speed v. how much work is required to accelerate the same motorcycle from rest up to a speed v/4?
The work required to move the motorcycle from rest to a speed of v/4 is 1/16 times of the initial work w.
As we already know, from the work energy theorem,
That work done by all the conservative forces and all the none conservative forces on the body is equal to the change in kinetic energy of that body.
So, in formula form, it can be written as,
W = ∆K
Where w is work done on the body and ∆K is the change in kinetic energy of the body.
So, if now we assume, that the work done to increase the velocity of the body from zero to V is w, then we can write,
w = 1/2mv² ..... Equation 1
m is the mass of the body.
Now, as per the question,
Let us say the work done needed to increase the speed of the body from rest to v/4 is w', then we can write,
w' = 1/2m(v/4)² ..... Equation 2
Now,
Dividing equation 2 by 1,
We get,
w'/w = 1/16
So, the value of w' is w/16.
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a cat slides down a slippery slanted roof at an acceleration of 2.2 m/s2 (it won't get hurt because it has nine lives). if it started at the top with zero initial speed, how far will the cat have slipped after 3 seconds? answer in meters and include two digits after the decimal point.
The cat will have slipped till the distance of 9.90 seconds in 3 seconds.
The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.
Now, using equation of motion,
S = Ut + 1/2at²
Where,
U is initial velocity of the body,
t is the time period of the body,
S is the displacement of the body,
a is the acceleration of the body.
Putting all the values,
S = 1/2at²
S = 1/2(2.2)(3)²
S = 9.90 meters.
The distance to which the cat will fall is 9.90 meters.
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Use the velocity vs time graph below for objects A and B to answer the given question.If A has the greater value pick answer choice AIf B has the greater value pick answer choice Bif A = B pick answer choice =.Which object has the greater Instantaneous Velocity at t = 5s?
Given the velocity versus time graph of an object.
From the graph, the velocity of object A is constant as the line representing its velocity is horizontal. The velocity of object a is decreasing with time. That is, object B is decelerating.
From the graph, at t=5 s the value of the instantaneous velocity of object A is 0 m/s.
And the value of the instantaneous velocity of object B is the same throughout the graph. And the value is 4 m/s.
Thus the value of the instantaneous velocity of object B is greater than that of object A.
Thus the correct answer is B has the greater value
what is the tension in a tow rope that is used to accelerate a 1700-kg car at 0.5 m/s2? (ignore the effects of friction.) a) assuming the tow rope is completely horizontal? b) assuming the tow rope is 400 above the horizontal?
The tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
F = m a
F = Net force
m = Mass
a = Acceleration
m = 1700 kg
a = 0.5 m / s²
∑ [tex]F_{x}[/tex] = m a
T = m a
T = 1700 * 0.5
T = 850 N
b ) Assuming the tow rope is 40° above the horizontal,
θ = 40°
Resolving the tension force into its horizontal component,
Tx = T cos θ
∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]
Tx = 1700 * 0.5
T cos 40° = 850
T = 1103.9 N
Therefore, the tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
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jim leaves his house and begins walking to his car in a straight line. he goes 2.0 m then returns to his house to get his keys. next, he leaves his house and travels 6.0 m to his car. what is jim's displacement?
Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m
Δx = x2 - x1
Δx = Displacement
x2 = Final position
x1 = Initial position
Considering the house as origin,
Final position = 6 m
Initial position = 0
Δx = 6 - 0
Δx = 6 m
Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.
Therefore, Jim's displacement is 6 m
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if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force. What is the reaction force in this situation?
A)Gravity from the ball pulls up on the Earth with 1.4 N of force.
B)Your fingers exerted an upward force of 1.4 N before they released the ball.
C)Once it hits the ground, normal force from Earth's surface will push up on the ball with 1.4 N
D)Air resistance pushes up on the ball with 1.4 N.
The reaction force in this situation occur once it hits the ground, and normal force from Earth's surface will push up on the ball with 1.4 N.
The correct answer is option (C)
What is Newton's third law of motion?Newton's third law of motion states that for every action there is equal and opposite reaction.
Mathematically, this law is given as;
Fa = Fb
where;
Fa is the force applied by object AFb is the reaction experienced by object BThe force applied by object is equal and opposite the reaction experienced by object B.
When an object placed on the floor, the weight of the object acts downward while the normal reaction of the object acts upwards.
Thus, if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force, the reaction force will occur once it hits the ground, as the normal force from Earth's surface will push up on the ball with 1.4 N.
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1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?
Answer:
Starting speed Vo = 6.7 m/s
Explanation:
Given:
t = 9.0 s
S = 30 m
___________
V₀ - ?
The path is numerically equal to the area of the figure lying under the velocity graph:
S = V₀* t / 2
Starting speed:
V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s
If the force of gravity acting on an object is 40N and the object has a mass of 2.8k, what is the acceleration due to gravity?
Answer:
0.07
Explanation:
2.8/40 = 0.07
Explain one recent idea that scientists have proposed for how the universe began. Consider the big bounce theory or the multiverse theory.
The most widely accepted theory about the universe is the big bang theory.
What is big bounce theory?The Big Bounce theory refers to the universe that is expanding and contracting, move back and forth in a big-picture timeline. The Big Bang theory was happened about 13.8 billion years ago when the universe began as a tiny, dense, ball that exploded. Many astronomers use the Big Bang theory to show how the universe began. But what caused this explosion in the first thing that is still a mystery. It has passed through many stages, which can be considered cosmological theories. The flat Earth, the geocentric model, heliocentricity, galactic centricity, the Big Bang, and the Inflationary Big Bang. In the Big Bounce theory, the universe is expanding and contracting, seesawing back and forth in a massively big-picture timeline more specific theory called "Big Bounce" theory proposes that the universe could collapse to the state where it is first started and then initiate another Big Bang.
So we can conclude that The Big Bang theory says that the universe came into being from a single more than 13 billion years ago.
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a first piece of rock which weiahs 5N, force F is applied to this first piece of rock and it produces an acceleration of a. now if there is a second rock. what force needs to be applied to the second piece of rock to produce an acceleration of 8a. mass of both rock is the same
The force that needs to be applied to the second piece of rock to produce an acceleration of 8a is 8F.
What is the relationship between the force, mass, and acceleration of an object?The relationship between the force, mass, and acceleration of an object is given in the formula below:
Force = mass * accelerationThe force on an object is directly proportional to its mass and acceleration.
However, the acceleration of an object when a constant force is applied is inversely proportional to the mass of the object.
Given two rocks that weigh 5 N each.
Force applied on the first rock, F produces an acceleration = a
F = ma
mass = constant
hence, F = a
For the second rock to have an acceleration 8a, the force applied will be:
F / a = Fx / 8a
Fx = 8 F
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a person threw a small bundle toward their friend on a balcony 10 meters above them. how fast did they throw it up?
The speed with which they threw the bundle is 14 m/s.
What is the speed of the bundle?We know that the speed of the bundle can be obtained from the use of the equations of kinematics. Now we can use the equation of the upward motion under gravity here.
Using;
v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Now;
v = 0 m/s at the maximum height
u^2 = 2gh
We now have;
u = √2gh
u = √ 2 * 9.8 * 10
u = 14 m/s
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A school bus moves 200 meters in 20 seconds, and another 100 meters in the next 10 seconds.
Calculate its average speed in m/s.
Answer: 300 m/s
Explanation:
So If it moves 200 metres in 20 seconds and then another 100 metres this is changing the total distance travelled to 300 metres. Also, it moves this distance extra distance in 10 seconds therefore the total time is 30 seconds.
speed = distance / time
speed = 300 / 30
speed = 10 m/s
After travelling a total of 300 metres and spending a total of 30 seconds in motion, the school bus travels at an average speed of 10 metres per second (m/s).
To figure out how fast the school bus was going on average, we need to know how far it went and how long it took to get there.
First, we add up the two lengths the school bus travelled: 200 metres plus 100 metres equals 300 metres.
Next, we add up how long it took to go both distances: 20 seconds plus 10 seconds equals 30 seconds.
Here's how to figure out the average speed:
Average Speed = Total Distance Travelled / Total Time Spent
Putting the numbers in:
Average Speed = 300 metres in 30 seconds
10 metres per second (m/s) is the average speed.
So, the school bus's usual speed is 10 m/s.
Average speed is the general rate of movement over a certain amount of time, no matter how it changes during the trip. In this case, the bus went 300 metres in 30 seconds, which means it went 10 m/s on average.
It's important to know that instantaneous speed is not the same as usual speed. Instantaneous speed is the speed of the bus at any given time during its trip. This speed could change as the bus speeds up, slows down, or stays at the same speed.
Calculating the average speed is helpful for figuring out how well something works generally, figuring out how efficient it is, and comparing different trips or types of transportation. But it might not take into account all the details of a given trip, such as different speeds or stops along the way. For a full picture of how the bus moves, it may be necessary to think about other things.
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A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
While traveling, an airplane passenger placed a bag of potato chips in his checked luggage that was placed in the baggage compartment where the air was not regulated. When he opened the luggage after landing, the bag had exploded and potato chips were everywhere in his luggage. Which gas law does this describe?.
While traveling, an airplane passenger placed a bag of potato chips in his checked luggage that was placed in the baggage compartment where the air was not regulated. When he opened the luggage after landing, the bag exploded and potato chips were everywhere in his luggage. Boyle's law explains this phenomenon.
According to Boyle's law, the volume of a gas and its pressure are inversely proportional to each other.
In a bag of potato chips, nitrogen gas is filled to prevent breakage and keep the flavor intact.
At Earth, the pressure of the gas inside the package is less than the surrounding pressure and it prevents the potato pouch from bloating up. However, at higher altitudes, pressure decreases, and the volume of the gases inside the bag expands under lower pressure and ultimately the bag explodes.
In general, when the pressure of the potato bag becomes greater than the surrounding pressure, then it explodes.
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a winter storm that blows cold wind at least 56 km/hr and has falling or blowing snow that reduces visibility to less than 400 m for at least three hours is classified as a(n) blank . multiple choice question.
Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.
What is Blizzards?A blizzard is a severe snowstorm that lasts for a long time—typically at least three or four hours—and is marked by strong sustained winds and low visibility. When snow is not falling but rather loose snow on the ground is lifted and blasted by strong winds, the weather is called a "ground blizzard." A blizzard, according to the National Weather Service, is a storm with heavy snowfall or snow that is blowing, winds that are greater than 35 mph (56 kph), and visibility that is less than 14 mile (0.4 km) for at least three hours. There is no snow falling during some blizzards, known as ground blizzards.To learn more about Blizzards refer to:
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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which body has more internal energy - a piece of ice at a temperature of 0 degrees or from the melting of this ice at the same temperature?
The melting ice at the same temperature will have greater internal energy as compared to the ice at 0° C.
What is internal energy?
In thermodynamics, the internal energy is a quantity or state function that characterizes a substance's energy when capillary effects and other external fields, such as electric and magnetic forces, are absent. The value of the energy depends on the substance's state, not the nature of the processes that brought it to that condition, just like any other state function.
The melting ice at the same temperature will have more internal energy as compared to the ice at 0° C because during the melting of ice the intermolecular particles will absorb energy while breaking their bond and because of this, the melting ice has greater kinetic energy as well.
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Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
The magnitude and direction of the net force are:
A: the net force is 3N in the downward direction,
B: the net force is zero,
C: The net force is 5N in the downward direction,
D: The net force is 4N in the right direction.
What is the net force?The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.
The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.
The mathematical expression can be written for the net force as:
[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]
For figure (A), the net force is equal to :
F = (2N - 2N) + (2N - 5N) = - 3N
So the magnitude of the force is 3N in the downward direction.
For figure (B), the net force is equal to :
F = (2N - 2N) + (5N - 5N) = 0
So the magnitude of the net force is equal to zero.
For figure (C), the net force is equal to :
F = (5N - 5N) + (5 N) = 5 N
So the magnitude of the net force is 5N in the downward direction.
For figure (D), the net force is equal to :
F = (2N - 2N) + (7N - 3N) = 4N
So the magnitude of the net force is 4N towards the right direction.
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a ball is thrown upward with initial velocity of 20 m/s. (a) how long is the ball in the air? (b) what is the greatest height reached by the ball? (c) when is the ball 15 m above the ground?
a) t = 4.08 s
b) Response = 20.39m
c) t = 0.991 and 3.087 seconds.
Initially, the vertical speed was 20 m/s.
(a) how long is the ball in the air?
The ball is tossed upward, rises to its highest point, and then hits the ground again.
Consequently, the end height will be equal to the starting height.
h = h o = Om
Use the equation s= ut + -at.
2764 – An = 14
Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.
Om = t - 0.5 * 9.81 m/s * 20 m/s
0 = 20 *t - 0.5 * 9.81 *t
20 *t=0.5*9.81 *t
20 = 0.5 * 9.81 *t
20 0.5*9.81
Answer (a): t = 4.08 s
(b) what is the greatest height reached by the ball?
Vertical velocity for the ball decreases to zero when it reaches its highest point.
Use the equation 2-u=295
-2ghmas for - u
(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *
02 – 20= -2*9.81 *
-20% = -2 *9.81 *
202 = 2 * 9.81 *
b) RESPONSE: H = 20.39m
(c) when is the ball 15 m above the ground?
The ball will be 15 meters above the earth on two separate occasions.
1. When climbing
2. When descending
Use the equation s= ut + -at.
2,264 – fn = 4
0.5 * 9.81 m/s * 15m = 20 m/s*t
15 = 20 *t - 0.5 * 9.81 *t
15 = 20t – 4.9057
4.905 – 20t + 15 = 0
Calculator-based quadratic equation solution
(c) t = 0.991 and 3.087 seconds.
Hence the answers are,
a) t = 4.08 s
b) RESPONSE: Hmar = 20.39m
c) t = 0.991 and 3.087 seconds.
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an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the three devices are in parallel when plugged into the same socket.) what current is drawn by the electric frying pan?
The current drawn by the electric frying pan is 27.295 A.
Power of toaster, P1 = 1800 W
Power of electric frying pan, P2 = 1400 W
Power of lamp, P3 = 75 W
Three devices are in parallel combination. So their Voltage difference is the same.
∆V = 120 Volt
Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A
Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A
Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A
Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A
Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.
The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.
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145-g baseball is dropped from a tree 12.0 m above the ground. (a) with what speed would it hit the ground if air resistance could be ignored? (b) if it actually hits the ground with a speed of what is the average force of air resistance exerted on it?
The required speed is 15.35 m/s, if air resistance is ignored.
The magnitude of average force of air resistance is 1.0341N.
a) V = √2gh
The required speed is
V = √2(9.8)(12)
V = 15.35m/s
b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])
W = (mg - f)h
( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))
(1.421 - f)12 = 4.64
Force of an air resistance = 1.0341N
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