O GRAPHS AND FUNCTIONSIdentifying solutions to a linear equation in two variables
Answers
Given:
Function is:
[tex]9x+2y=13[/tex]Find-:
Check for solution
Explanation-:
The value of "y" is:
[tex]\begin{gathered} 9x+2y=13 \\ \\ 2y=13-9x \\ \\ y=\frac{13-9x}{2} \end{gathered}[/tex]For (0,8)
Check value of "y" at x = 0 then,
[tex]\begin{gathered} x=0 \\ \\ y=\frac{13-9x}{2} \\ \\ y=\frac{13-9(0)}{2} \\ \\ y=\frac{13-0}{2} \\ \\ y=\frac{13}{2} \\ \\ y=6.5 \end{gathered}[/tex]So (0,8) it is not a solution.
Check (3,-7) the value of "x" is 3
[tex]\begin{gathered} x=3 \\ \\ y=\frac{13-9x}{2} \\ \\ y=\frac{13-9(3)}{2} \\ \\ y=\frac{13-27}{2} \\ \\ y=-\frac{14}{2} \\ \\ y=-7 \end{gathered}[/tex]So (3,-7) is the solution of function.
Check for (1 , 2) value of "x" is 1.
[tex]\begin{gathered} x=1 \\ \\ y=\frac{13-9x}{2} \\ \\ y=\frac{13-9}{2} \\ \\ y=\frac{4}{2} \\ \\ y=2 \end{gathered}[/tex]So, (1,2) is the solution.
Check for (4,-5) the value of "x" is 4.
[tex]\begin{gathered} x=4 \\ \\ y=\frac{13-9x}{2} \\ \\ y=\frac{13-9(4)}{2} \\ \\ y=\frac{13-36}{2} \\ \\ y=-\frac{23}{2} \\ \\ y=-11.5 \end{gathered}[/tex]So, (4,-5) is not a solution
Related Questions
A square room has a floor area of 49 square meters. The height of the room is 8 meters. What is the total area of all four walls?
Answers
The total area of all four walls is 224 square meters.
According to the question,
We have the following information:
A square room has a floor area of 49 square meters.
So, we have:
Area of square = 49 square meters
Side*side = 49
Side = [tex]\sqrt{49}[/tex] m
Side of the square = 7 m
Now, the side of the floor will be the width of the wall.
So, we have the width of the wall = 7 m.
The height of the room is 8 meters.
It means that the height of the wall is 8 m.
Area of 1 rectangular wall = length*width
Area of wall = 8*7
Area of 1 wall = 56 square meters
Now, the are of 4 walls will be (4*56) square meters or 224 square meters.
Hence, the total are of all four walls is 224 square meters.
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select the reason that best supports statement 6 in the given proof please help me image attached
Answers
Answer:
B. Distributive Property
Step-by-step explanation:
You want to know the reason in the proof that best supports the transition from 5. 99-3x = 12(x+2) to 6. 99-3x = 12x+24.
TransformationYou will notice that in the transition from
5. 99-3x = 12(x+2)
to
6. 99-3x = 12x+24
the expression 12(x+2) has been replaced by the expression 12x+24.
Distributive propertyThe property of addition and multiplication that makes it true that ...
12(x +2) = 12x +24
is the distributive property of multiplication over addition. That property tells you that parentheses can be eliminated by multiplying each of the terms inside by the factor outside.
Santa worked 3.5 hours, 6.9 hours, & 4.3 hours in the last three days. If he earns $7.1 an hour, how much did he earn in the last three days?
Answers
ANSWER:
$104.37
STEP-BY-STEP EXPLANATION:
To calculate the total profit, we must add the amount he earned each day, multiplying the salary by the number of hours, like this:
[tex]\begin{gathered} e=3.5\cdot7.1+6.9\cdot7.1+4.3\cdot7.1 \\ e=24.85+48.99+30.53 \\ e=104.37 \end{gathered}[/tex]Therefore, he earned in the last three days a total of $104.37
3. What is the vertical shift for the absolute value function below?F(x) 9|x + 1|+ 2
Answers
Answer:
The vertical shift is of 2 units up
Step-by-step explanation:
We have a function in the following format:
F(x) = a(x+b) + c
The vertical shift is given by c.
If c > 0, the shift is up.
If c < 0, the shift is down.
In this question:
F(x) = 9|x+1| + 2
So c = 2
The vertical shift is of 2 units up
Hello,Can you help me with question 1: Evaluate the given binomial coefficient
Answers
Solution:
Given the expression below
[tex](^8_3)[/tex]Applying the combination formula below
[tex]^nC_r=\frac{n!}{r!(n-1)!}[/tex]The binomial coefficient will be
[tex]=\frac{8!}{3!(8-3)!}=\frac{8!}{3!5!}=\frac{8\times7\times6\times5\times4\times3\times2\times1}{3\times2\times1\times5\times4\times3\times2\times1}=56[/tex]Hence, the answer is 56
write your answer in exponential form. 3^9 * 3^-3
Answers
Step 1
Given;
[tex]3^9\times3^{-3}[/tex]Required; To write the answer in exponential form
Step 2
[tex]\begin{gathered} Using\text{ the index law below;} \\ a^b\times a^c=a^{bc} \\ Hence,\text{ 3}^9\times3^{-3}=3^{9-3}=3^6 \end{gathered}[/tex]Answer;
[tex]3^6[/tex]Use the number line to video to find two other solutions to the inequality 7 + m < 20.
Answers
Answer:
m = 2 and m = 3
Explanation:
To find the solutions to the inequality, we need to isolate m. So, we can subtract 7 from both sides as:
7 + m < 20
7 + m - 7 < 20 - 7
m < 13
Therefore, any number that is less than 13, is a solution of the inequality.
For example: 2 and 3 are solutions of the inequality.
Given the sequence 4, -16, 64, -256..a) Write the explicit rule for the sequence. b) Find a7 c) Write the recursive rule for the sequence.
Answers
the given series is 4 -16 64 -256
that is
4 x -4 = -16 = -4^2
-16 x -4 = 64 = 4^3
64 x -4 = -256 = -4^4
so we can say that is every time the number is multiplied with -4,
for a7, as 7 is an odd number so the negative sign will be there from the above observations
-4^7 = -16384
the recursive rule will be'
[tex]a_n=a_{n-1}\times-4[/tex]A circular plot of land has a diameter of 16 yards. What is the area of theland? Use 3.14 for it.O A. 803.84 yd2O B. 50.24 yd2O C. 200.96 yd2O D. 25.12 yd2
Answers
The area of the circle can be calculated with the following formula
[tex]A=\pi\cdot r^2[/tex]First let's find the radius
[tex]\begin{gathered} r=\frac{16}{2}\text{yds} \\ r=8\text{yds} \end{gathered}[/tex][tex]\begin{gathered} A=\pi\cdot8^2 \\ A=3.14\cdot64 \\ A=200.96\text{ yd2} \end{gathered}[/tex]The answer would be 200.96 square yards
1 pur Una foto de 4 pulgadas por 6 pulgadas se coloca en un marco de imagen con un borde de ancho constante. Si el área del marco, incluida la imagen, es de 80 pulgadas cuadradas, ¿qué ecuación podría usarse para determinar el ancho del borde, x? *
Answers
Tenemos una foto de 4 x 6 pulgadas.
Tenemos un marco con borde de ancho constante, lo que significa que alrededor de la foto siempre tenemos un "espesor" constante, que llamaremos "e".
También sabemos que el area total del marco es 80 pulgadas cuadradas.
Podemos dibujar esto así:
El marco tiene un ancho total de 4+2e y un largo de 6+2e.
Entonces, podemos calcular el espesor "e" a partir de calcular el area del marco e igualarlo a 80 pulgadas cuadradas. El area del marco sera igual al ancho por el largo:
[tex]\begin{gathered} A=(4+2e)(6+2e)=80 \\ 4\cdot6+4\cdot2e+2e\cdot6+2e\cdot2e=80 \\ 24+8e+12e+4e^2=80 \\ 4e^2+20e-56=0 \\ 4(e^2+5e-14)=0 \\ e^2+5e-14=0 \end{gathered}[/tex]Debemos aplicar la ecuación cuadrática para calcular e:
[tex]\begin{gathered} e=-\frac{b}{2a}\pm\frac{\sqrt[]{b^2-4ac}}{2a} \\ e=-\frac{5}{2}\pm\frac{\sqrt[]{5^2-4\cdot1\cdot(-14)}}{2} \\ e=-\frac{5}{2}\pm\frac{\sqrt[]{25+56}}{2} \\ e=-\frac{5}{2}\pm\frac{\sqrt[]{81}}{2} \\ e=-\frac{5}{2}\pm\frac{9}{2} \\ e_1=-\frac{5}{2}-\frac{9}{2}=-\frac{14}{2}=-7 \\ e_2=-\frac{5}{2}+\frac{9}{2}=\frac{4}{2}=2 \end{gathered}[/tex]e=-7 no es una solución válida, ya que el espesor debe ser positivo.
Entonces, la solución es e=2.
Respuesta: el ancho del borde es 2 pulgadas.
(6 x 10^-2)(1.5 x 10^-3 + 2.5 x 10^-3)1.5 x 10^3
Answers
Given the expression:
[tex]\left(6*10^{-2}\right)\left(1.5*10^{-3}+2.5*10^{-3}\right)1.5*10^3[/tex]Let's simplify the expression.
To simplify the expression, we have:T
[tex]\begin{gathered} (6*10^{-2})(1.5*10^{-3}+2.5*10^{-3})1.5*10^3 \\ \\ =(6*10^{-2})(4.0*10^{-3})1.5*10^3 \\ \\ =(6*4.0*10^{-2-3})1.5*10^3 \\ \\ =(24.0*10^{-5})1.5*10^3 \end{gathered}[/tex]Solving further:
Apply the multiplication rule for exponents.
[tex]\begin{gathered} 24.0*1.5*10^{-5+3} \\ \\ =36*10^{-2} \\ \\ =0.36 \end{gathered}[/tex]ANSWER:
[tex]0.36[/tex]Helen has a box of marbles. 1/2 of the marbles are yellow. 1/8 of the
marbles are red. The rest of the marbles are blue. Helen pulls one marble
out of the box at random, records its color, replaces it, and mixes up the
marbles again. If she does this 400 times, how many blue marbles should
she expect to pull out?
Answers
Answer:
150 blue marbles
Step-by-step explanation:
Hello!
If 1/2 of the marbles are yellow, and 1/8 of the marbles are red, then 3/8 of the marbles should be blue.
The percentages are as given:
Yellow = 50%Red = 12.5%Blue = 37.5%To calculate the possible number of blue marbles out of the 400 marbles, we can find 37.5% of 400, as there is a 37.5% chance of getting blue for each turn.
Calculate37.5% of 4000.375 * 400150Helen should expect to pick out 150 blue marbles.
Function A and Function B are linear functions.
Which statement is true?
The y-value of Function A when x = -2 is greater than the y-value of Function B when x = -2.
The y-value of Function A when x = -2 is less than the y-value of Function B when x = -2.
Answers
Answer:
Step-by-step explanation:
The y-value of Function A when x = - 2 is less than the y-value of Function B when x = - 2.
Brady needs to fill his daughter's sandbox that is 5 feet by 7 feet. He wants to buy sand bags to fill the sand 2 feet deep. He compares the prices found for sand at two different stores.PART AWhat is the unit rate that store X is selling for? ____ lbs/dollarPART BWhich store is offering the better price?____PART CBrady finds online that it takes 100 pounds of sand to fill 1 cubic foot. Using the better priced store, compute how much it will cost him to purchase enough sand to fill the sandbox. Use the volume formula, V = I × w × h, to determine your answer.$____from____
Answers
The sand box is rectangular with
Wide= 5feet
Length= 7feet
He wants to fill the box with a depth of 2 feet
Use appropriate identities to rewrite the following expression in terms containing only first powers ofsine.4tanx1 + tan2x
Answers
The given question is
[tex]\frac{4\tan x}{1+\tan ^2x}[/tex]Use the identity
[tex]1+\tan ^2x=\sec ^2x[/tex]Then replace the denominator by sec^2 (x)
[tex]\frac{4\tan x}{\sec ^2x}[/tex]Since sec is the reciprocal of cos, then
[tex]\sec ^2x=\frac{1}{\cos ^2x}[/tex]Replce sec^2(x) by 1/cos^2(x)
[tex]\frac{4\tan x}{\frac{1}{\cos ^2x}}[/tex]Since denominator of denominator will be a numerator
[tex]4\tan x\times\cos ^2x[/tex]Use the value of tan
[tex]\tan x=\frac{\sin x}{\cos x}[/tex]Replace tan by sin/cos
[tex]4\times\frac{\sin x}{\cos x}\times\cos ^2x[/tex]Reduce cos(x) up with cos(x) down
[tex]\begin{gathered} 4\times\sin x\times\cos x= \\ 4\sin x\cos x \end{gathered}[/tex]Use the identity
[tex]\sin (2x)=2\sin x\cos x[/tex][tex]4\sin x\cos x=2(2\sin x\cos x)[/tex]Replace 2 sin(x)cos(x) by sin(2x)
[tex]2(2\sin x\cos x)=2\sin 2x[/tex]The answer is
2 sin(2x)
2x^3+ 15^2+ 27x + 5= x^2+ 5x + 12x + 5
Answers
To determine if the equation is true we multiply the expression on the right side by the denominator on the left; if the result is the numerator on the left then the equation is true:
[tex]\begin{gathered} (2x+5)(x^2+5x+1)=2x^3+10x^2+2x+5x^2+25x+5 \\ =2x^3+15x^2+27x+5 \end{gathered}[/tex]Since the result is the numerator on the left side we conclude that the equation is true.
Find two unit vectors orthogonal to both j-k and i+j.
Answers
The two unit vectors orthogonal to both j-k and i+j are [tex]\frac{i}{\sqrt{3} }- \frac{j}{\sqrt{3} } -\frac{k}{\sqrt{3} }[/tex]
Let a bar = j- k = < 0,1,-1>
b bar = i+j = <1,1,0>
the cross product a x b bar is orthogonal to both a and b bar
= i ( 0-(-1) ) -j ( 0-(-1) ) + r (0-1)
= i-j-k
A unit vector is a vector whose length is 1 unit
There the unit vector is :
[tex]\frac{i-j-k}{\sqrt{1^2+(-1)^2+(-1)^2} } = \frac{i-j-k}{\sqrt{3} }[/tex]
= [tex]\frac{i}{\sqrt{3} }-\frac{j}{\sqrt{3} }-\frac{k}{\sqrt{3} }[/tex]
The second unit vector orthogonal to both a and b bar would be negative of the previous vector.
= [tex]-\frac{i}{\sqrt{3} }-\frac{j}{\sqrt{3} }-\frac{k}{\sqrt{3} }[/tex]
Hence the two unit vectors orthogonal to both j-k and i+j are [tex]\frac{i}{\sqrt{3} }- \frac{j}{\sqrt{3} } -\frac{k}{\sqrt{3} }[/tex]
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Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this section to solve the following exercise.The number of ducks and pigs in a field totals 37. The total number of legs among them is 98. Assuming each duck has exactly two legs and each plg has exactly fourlegs, determine how many ducks and how many pigs are in the field.ducks?pigs?
Answers
Lets call x to the number of ducks
and y the number of pigs.
Then:
[tex]2x+4y=98[/tex]Because there are 2 legs per duck and 4 legs per pig.
If the total of animals is 37, then:
[tex]x+y=37[/tex]Then:
[tex]x=37-y[/tex]And replacing on the first equation we get:
[tex]2(37-y)+4y=98[/tex][tex]74-2y+4y=98[/tex][tex]2y=98-74[/tex][tex]2y=24[/tex][tex]y=\frac{24}{2}[/tex][tex]y=12[/tex]There are 12 pigs and therefore 25 ducks.
Consider the following functions. Find the domain. Express your answer in interval notation.
Answers
Explanation:
[tex]\begin{gathered} f(x)\text{ = - }\sqrt[]{6-x} \\ g(x)\text{ = 4 - x} \\ (g\text{ - f)(x) = g(x) - f(x)} \end{gathered}[/tex][tex]\begin{gathered} (g\text{ -f)(x) = }4-\text{ x - (-}\sqrt[]{6\text{ - x}}) \\ (g\text{ -f)(x) = 4 - x + }\sqrt[]{6-x} \end{gathered}[/tex][tex]undefined[/tex]26÷2.40=10.833333 round to the nearest cent
Answers
26÷ 2.40= 10.833333
Nearest cent means ,2 numbers after decimal point
Then it is 10.83
count 2 numbers to right ,and discard rest of 3333
Then answer is = 10.83
How many arrangements of the word NEWFOUNDLAND are there?Page 5 of 12Previous PageNext Page
Answers
Step 1:
Concept
Number of way of arranging n different objects = n!
Step 2:
Word = NEWFOUNDLAND
N = 3
E = 1
W = 1
F = 1
O = 1
U = 1
D = 2
L = 1
A = 1
Step
Number of ways of arranging the word NEWFOUNDLAND
[tex]\begin{gathered} \text{ = }\frac{12!}{3!\text{ 2!}} \\ =\text{ }\frac{12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}{3\times2\times1\times2\times1} \end{gathered}[/tex][tex]\begin{gathered} \\ =\text{ }\frac{479001600}{12} \\ =\text{ 39916800 ways} \end{gathered}[/tex]7. Reflect AABC over the y-axis, translate by (2, -1), and rotate the result 180° counterclockwise aboutthe origin. Plot AA'B'C' on the grid below. (1 point)tyTransformation rule:420А,PreimageABCImage A'B'CImage A"B"C"Image A'B'C'-22,-12,44, 2lifelongGeometry ACredit 2L4L - Geometry A (2020)Page 57
Answers
Reflection rule over y - axis is given as
(x , y) ------------ (-x, y)
This implies that the y - axis will remain the same and the x - axis will be negated
Pre image ABC at point (2, -1)
The reflection over y - axis will be
ABC A'B'C' A''B''C'' A'''B'''C'''
(2, -1) -----------------(-2, -1) ----------------------(2, -1) -------------------(-2, -1)
ABC A'B'C' A''B''C'' A'''B'''C'''
(2, -4) (-2, -4) (2, -4) (-2, -4)
What is the amplitude of the graph g(x)=f(x)+2 Where f(x)=cos x
Answers
In the cosine equation
[tex]y=AcosB(x-C)+D[/tex]A is the amplitude
B is using it to find the period
C is the phase shift
D is the vertical shift
Since the given function is
[tex]g(x)=cos(x)+2[/tex]A = 1
B = 1
C = 0
D = 2
The amplitude is 1
The answer is 1
Help
Show work please
Answers
Answer:
check the attached files.
A company borrows $13,000 at 5% for 90 days. Find (a) the amount of interest due and (b) the total amount that must be paid after 90 days. (a) The interest due is $ (Simplify your answer. Do not round until the final step. Then round to the nearest cent as needed.)
Answers
We have to use the simple interest formula
[tex]I=P\times r\times t[/tex]Where P = 13,000, r = 5% (0.05), t = 90 (0.25 years). Let's replace these values to find the interest
[tex]I=13,000\times0.05\times0.25=162.50[/tex](a) The amount of interest is $162.50.(b) The total amount that must be paid after 90 days is $13,162.50.Because we have to add the total interest with the amount borrowed.
m(25+2)(x-7)(4%-8)"y =
Answers
From the figure we can obtain 2 equations:
[tex](2y+2)+(4x-8)=180[/tex]and
[tex](9x-7)+(4x-8)=180[/tex]first lets simplify both equations:
for the first;
[tex]2y+4x=186[/tex]and for the second one:
[tex]9x+4x=195\Rightarrow13x=195\Rightarrow x=\frac{195}{13}=15[/tex]Now we have that x=15 and we can substitute x for 15 in the first equation to find y:
[tex]2y+4(15)=186\Rightarrow2y=126\Rightarrow y=63[/tex]so the final answe is: x=15 and y=63
Rob earns $4200 per month at his new job. He pays the following taxes: 6.2% for social security 1.45% for Medicare 16% for federal income tax • 5.5% for state income tax Calculate his annual net income.
Answers
Answer:
$35,708.4
Explanation:
His net income will be the total that he earns less the taxes.
So, we need to calculate how much money does Rob pays for each tax.
Therefore, 6.2% of 4200 is equal to:
[tex]4200\times6.2\text{ \% =4200 }\times\frac{6.2}{100}=260.4[/tex]It means that Rob pays $260.4 each month for social security,
In the same way, 1.45% of 4200 is equal to:
[tex]4200\times1.45\text{ \% = 4200}\times\frac{1.45}{100}=60.9[/tex]16% of 4200 is equal to:
[tex]4200\times16\text{ \% = 4200}\times\frac{16}{100}=672[/tex]5.5% of 4200 is equal to:
[tex]4200\times5.5\text{ \% = 4200}\times\frac{5.5}{100}=231[/tex]Now, we can calculate the net income per month as:
$4200 - $260.4 - $60.9 - $672 - $231 = $2975.7
Finally, his annually net income will be the net income per month multiplied by 12 months:
$2975.7 x 12 = $35,708.4
So, the answer is $35,708.4
What is the solution to the equation below?A.x = B.x = C.x = D.x =
Answers
Explanation
We are given the following equation:
[tex]\sqrt{5x-2}-1=3[/tex]We are required to determine the value of x.
This is achieved thus:
[tex]\begin{gathered} \sqrt{5x-2}-1=3 \\ \text{ Add 1 to both sides} \\ \sqrt{5x-2}-1+1=3+1 \\ \sqrt{5x-2}=4 \\ \text{ Square both sides } \\ (\sqrt{5x-2})^2=4^2 \\ 5x-2=16 \\ \text{ Collect like terms } \\ 5x=16+2 \\ 5x=18 \\ \text{ Divide both sides by 5} \\ \frac{5x}{5}=\frac{18}{5} \\ x=\frac{18}{5} \end{gathered}[/tex]Hence, the answer is:
[tex]x=\frac{18}{5}[/tex]A bag contains 3 gold marbles, 10 silver marbles, and 23 black marbles. You randomly select one marblefrom the bag. What is the probability that you select a gold marble? Write your answer as a reduced fractionPlgold marble)
Answers
ANSWER
P(gold marble) = 1/12
EXPLANATION
In total, there are:
[tex]3+10+23=36[/tex]36 marbles in the bag, where only 3 are gold marbles.
The probability is:
[tex]P(\text{event)}=\frac{\#\text{times the event can happen}}{\#\text{posible outcomes}}[/tex]In this case, the number of posible outcomes is 36, because there are 36 marbles in the bag. The number of times the event can happen is 3, because there are 3 gold marbles:
[tex]P(\text{gold marble)}=\frac{3}{36}=\frac{1}{12}[/tex]which example would be likely to give a valid conclusion?
Answers
Given: Different statement
To Determine: Which of the statement would give a valid conclusion
Solution
Please note that the statement must be a true representation of the population