O EQUATIONS AND INEQUALITIESSolving a word problem with three unknowns using a linear...
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Given:
The sum of three numbers is 81, The third number is 2 times the second, The first number us 9 moe than the second.
Required:
We need to find all the numbers
Explanation:
Assume that a, b and c are the first, second and third numbers respectively.
By given ststement
[tex]\begin{gathered} a+b+c=81\text{ .....\lparen i\rparen} \\ c=2b\text{ .....\lparen ii\rparen} \\ a=b+9\text{ .....\lparen iii\rparen} \end{gathered}[/tex]substitute c and a in equation (i)
[tex]\begin{gathered} b+9+b+2b=81 \\ 4b=72 \\ b=18 \end{gathered}[/tex]now put value of b in equation (ii) and (iii)
[tex]c=2*18=36[/tex]and
[tex]a=18+9=27[/tex]FInal answer:
first number a = 27
second number b = 18
third number c = 36
Related Questions
Use the functions f(x) = 8x + 11 and g(x) = 4x² + 7x - 2 to evaluate the following:a. f(8) =b. f(-8)=c. g(6) =d. g(-7)=e. g(a) =
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Given:
f(x) = 8x + 11
g(x) = 4x² + 7x - 2
We are asked to evaluate using the following:
(a) f(8)
f(8) = 8(8) + 11
f(8) = 64 + 11
f(8) = 75
(b) f(-8)
f(-8) = 8(-8) + 11
f(-8) = -64 + 11
f(-8) = -53
(c) g(6)
g(6) = 4(6)² + 7(6) - 2
g(6) = 4(36) + 42 - 2
g(6) = 144 + 42 - 2
g(6) = 184
(d) g(-7)
g(-7) = 4(-7)² + 7(-7) - 2
g(-7) = 4(49) - 49 - 2
g(-7) = 196 - 49 - 2
g(-7) = 145
(e) g(a)
g(a) = 4(a)² + 7(a) - 2
g(a) = 4a² + 7a - 2
Write an expression for the sequence of operations described below.1)) multiply 7 by 8, then divide f by the resultDo not simplify any part of the expression.Submit
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We need to write an expression for the operations:
[tex]\begin{gathered} \text{ multiply 7 by 8} \\ \\ \text{dived f by the result} \end{gathered}[/tex]The first operation (multiplication) can be represented as:
[tex]7\cdot8[/tex]The second operation (the division of f by the previous result) can be represented as:
[tex]f\div(7\cdot8)[/tex]Notice that we need the parenthesis to indicate that the product is the first operation to be done.
Answer:
[tex]f\div(7\cdot8)[/tex]Given the following information about events A, B, and C, determine which pairs of events, if any, are independent andwhich pairs are mutually exclusive.
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Let's begin by identifying key information given to us:
[tex]\begin{gathered} P(A)=0.39 \\ P(B)=0.42 \\ P(C)=0.19 \\ P(A|B)=0 \\ P(C|B)=0.19 \\ P(A|C)=0.39 \end{gathered}[/tex]When two events A and B are independent we have it thus:
[tex]undefined[/tex]A vase is in the shape of a cone. The height is 12 inches and the diameter is 4.4 inches.
What is the lateral surface area to the nearest tenth of a square inch?
O
O
24.3 square inches
149.1 square inches
168.6 square inches
99.5 square inches
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84.27 square inch is the lateral surface area of cone.
Define lateral surface area.All of an object's sides, excluding its base and top, are considered its lateral surface. The size of the lateral surface is referred to as its area. This must be distinguished from the total surface area, which consists of the base and top areas as well as the lateral surface area. A figure's lateral area consists solely of the non-base faces. The lateral surface area of several forms, such as a cuboid, cube, cylinder, cone, and sphere, is discussed in this article.
Given,
Height = 12 inches
Diameter = 4.4 inches
Radius = 2.2 inches
Lateral surface area:
πr√h² + r²
3.14 × 2.2 √(12)² + (2.2)²
3.14 × 2.2 √144 + 4.84
3.14 × 2.2 √148.84
3.14 × 2.2(12.2)
3.14 × 26.84
84.27
84.27 square inch is the lateral surface area of cone.
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I solved the attached equation as 7000 but it seems to ask for a “solution set” did I answer properly?
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The solution set does have only one element: {7000}
Can u please help me solve ? I'm reviewing for a final, ty
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Part A
we have that
Both students verify the identity properly
student A ----> expand the left side of the identity
student B ----> expand the right side of the identity
but the result is the same
both students proved that the given equation is an identity
Part B
Identities[tex]\begin{gathered} sin^2x+cos^2x=1\text{ ----> identity N 1 in step 3} \\ cos^2x=1-sin^2x \end{gathered}[/tex]and
[tex]cscx=\frac{1}{sinx}\text{ -----> identity N 2 step 5}[/tex]Write a equation that passes through the points (2,5) (-3,5)
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Line equation: y = 5
Slope: 0
Intercept: 5
Formule:
. Equation : y = mx + b
. Slope: m = () / ()
writing equations in slope-intercept form common core algebra 1question 1
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The equation of the line in the slope-intercept form is y = mx + b, where "m" is the slope and "b" is the y-intercept.
"b" is the point (0, yi).
"m" can be found using 2 points P₁ (x₁, y₁) and P₂ (x₂, y₂), according to the formula below:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, to solve this question, follow the steps below.
(a) First graph
Step 01: Find the y-intercept and another point in the graph.
To find the points in the graph, choose a x-value and find its corresponding y-value.
Choosing x = 0, y = 2.
P₁ = (0, 2).
Choosing x = -3, y = -2.
P₂ = (-3, -2).
Step 02:
In AUVW, VW = UV and mZU = 74º. Find mZV.
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We will find the measure of angle V as follows:
*From theorem we have that angles that are opposite to congruent sides are congruent. So, Angle W will also have a measure o 74°. Now, we also have that the sum of all internal angles of a triangle add 180°, so the following is true:
[tex]U+V+W=180\Rightarrow74+V+74=180[/tex]Now, we solve for V:
[tex]\Rightarrow V=32[/tex]So, the measure of angle V is 32°.
Graph the inequality on a number line
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Hope this helps :)
Find the perimeter of the rectangle. Write your answer in scientific notation.Area = 5.612 times 10^14 cm squared9.2 times 10^7cm is one side of the perimeter
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Answer: Perimeter = 1.962 x 10^8 cm
Explanation:
The first step is to calculate the width of the rectangle. Recall,
Area = length x width
width = Area /length
From the information given,
Area = 5.612 times 10^14 cm squared
Length = 9.2 times 10^7cm
Thus,
width = 5.612 times 10^14 /9.2 times 10^7
width = 6.1 x 10^6
The formula for calculating the perimeter is
Perimeter = 2(length + width)
Thus,
Perimeter = 2(9.2 x 10^7 + 6.1 x 10^6)
Perimeter = 1.962 x 10^8 cm
2. The area of the arena is 2160 in.2 a) Will the arena fit on the rug? Show your work and explain your answer below. b) If the length of the arena is 60 inches, what is the width? c) If the arena fits, and is placed exactly in the middle of the rug, how much standing room on the rug could a drive have? Use your measurements from above to help you. ? 3. If 15 robots can fit on the arena floor at one time, how much space does each robot take up?
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Answers:
2a. The arena will fit on the rug
b. Width = 36 in
c. Standing room: 4 in
3. 144 in²
Explanation:
2. Part a.
First, we need to convert the measures of the rug to inches, so taking into account that 1 ft = 12 in, we get
Length = 6 ft x 12 in/ 1ft = 72 in
Width = 4 ft x 12 in/ 1 ft = 48 in
Then, the area of the rug will be
Area = Length x Width
Area = 72 in x 48 in
Area = 3456 in²
Therefore, the area of the arena, which is 2160 in² is lower than the area of the rug. It means that the area will fit on the rug.
Part b.
The area of the arena is equal to
Area = Length x Width
To find the width of the area, we need to solve the equation for the width, so
Width = Area/Length
So, replacing Area = 2160 in² and Length = 60 in, we get
Width = 2160 in² / 60 in
Width = 36 in
Therefore, the width of the area is 36 in.
Part c.
The measures that we get from parts a and b can be represented as
Therefore, the missing length can be calculated as:
(48 in - 36 in)/2 = 12 in/ 2 = 6 in
Therefore, a drive will have 6 in of standing room.
3.
Finally, to know how much space each robot take up, we need to divide the area of the arena by 15, so
2160 in²/ 15 = 144 in²
Therefore, each robot take 144 in²
Rosa receives money from her relatives every year on her birthday. Last year, she received a total of $350. This year, she received $441. What is the percent of increase in Rosa’s annual birthday money?
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Answer:
26%
Step-by-step explanation:
use a online percentage calculator
An ice cream truck began its daily route with 95 gallons of ice cream. The truck driver sold 58% of the ice cream. How many gallons of ice cream were sold? round to nearest gallon
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Start making the percentage as a fraction
[tex]\begin{gathered} 58\text{\%}=\frac{58}{100} \\ \end{gathered}[/tex]multiply the fraction by the total of the daily routine
[tex]95\cdot\frac{58}{100}=55.1\approx55gallons[/tex]Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this section to solve the following exercise.A shirt and a tie together cost $68. The shirt costs $30 more than the tie. What is the cost of the shirt (in dollars).
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Let x and y be the cost of a shirt and a tie, respectively; therefore, the two equations are
[tex]\begin{gathered} x+y=68 \\ \text{and} \\ x=30+y \end{gathered}[/tex]We have two variables and two equations; we need to solve the system of equations to find the values of x and y.
Solve using the substitution method.
Use the second equation into the first equation, as shown below
[tex]\begin{gathered} x=30+y \\ \Rightarrow(30+y)+y=68 \\ \Rightarrow30+2y=68 \\ \Rightarrow2y=68-30=38 \\ \Rightarrow y=\frac{38}{2} \\ \Rightarrow y=19 \end{gathered}[/tex]Now, use this value of y in the second equation
[tex]\begin{gathered} y=19 \\ \Rightarrow x=30+y=30+19 \\ \Rightarrow x=49 \end{gathered}[/tex]Remember that x is the cost of a shirt and y is the cost of a tie. Therefore, the answers are
Cost of a shirt: $49
Cost of a tie: $19
One can verify the answer by noticing that a shirt and a tie cost $49+$19=$68, and that a shirt costs $30+$19=$49
Slove for p 14 = -(p - 8)
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Solve:
[tex]\begin{gathered} 14=-(p-8) \\ -14=p-8 \\ -14+8=p \\ p=-14+8 \\ p=-6 \end{gathered}[/tex]p=-6
A survey stopped men and women at random to ask them where they purchased groceries, at a local grocery store or online.Grocery OptionsStoreOnlineTotalWomen231235Men221537Total452772What percent of the people surveyed shop at a local grocery store? Round your answer to the nearest whole number percent
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Given:
A survey stopped men and women at random to ask them where they purchased groceries, at a local grocery store or online. Grocery Options
Store Online Total
Women 23 12 35
Men 22 15 37
Total 45 27 72
Required:
To find the percentage of the people surveyed shop at a local grocery store.
Explanation:
The total number of people is 75.
And the total number of people surveyed shop at a local grocery store is 45.
Now the percentage of the people surveyed shop at a local grocery store is,
[tex]=\frac{45}{72}\times100[/tex][tex]\begin{gathered} =62.5\% \\ \\ \approx63\% \end{gathered}[/tex]Final Answer:
63% of the people surveyed shop at a local grocery store.
find the coordinates of point P that lies on the line segment MQ, M(-9,-5) , Q(3,5), and partitions the segment at a ratio of 2 to 5
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What is the equation of the line that passes through the point (8,-6) and has a
slope of o?
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The equation is y = -6
given the tableau, circle the pivot and explain how you found it
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The equations are
[tex]2x_1+3x_2+6x_3+S_2=22[/tex][tex]3x_1+5x_2+3x_3+S_1=20_{}[/tex][tex]-3x_2-1x_3+S_1+Z\text{ = 24}[/tex]The smallest negative number is the pivot column
so the smallest negative number is -3 and hence the pivot column is
3
5
-3
The row pivot hence = 5
so pivot will be (x= -3 and S = 5)
write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the equation(-3, -5); y = -5x+2
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The equation is y = -5x-20.
GIven:
The equation is, y = -5x + 2.
A point on the line is (-3, 5).
The objective is to write an equation that passes throught the point and parallel to the given equation.
For parallel lines the product of slope values will be equal.
From the given equation, consider the slope of the equation as, m1 = -5.
Then, the slope of the parallel line will also be, m2 = -5.
Then, the equation of parallel line can be written as,
[tex]\begin{gathered} y=m_2x+b \\ y=-5x+b \end{gathered}[/tex]Here b represents the y intercept of the parellel line.
To find the value of b, substitute the given points in the above equation.
[tex]\begin{gathered} -5=-5(-3)+b \\ -5=15+b \\ b=-5-15 \\ b=-20 \end{gathered}[/tex]Now, substitute the value of b in the equation of parellel line.
[tex]y=-5x-20[/tex]Hence, the equation of parellel line is y = -5x-20.
I'm graphing and I need to find out how mutch it costs for 4.5 inches of the construction. and the construction is $25.50 per inch
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You have to determine the cost for 4.5 inches of the construction using the graph.
The height is on the y-axis, and the cost is on the x-axis.
First, locate 4.5 in the y-axis, which is the value in the midpoint between 4 and 5.
Draw a horizontal line until you intersect with the line, then draw a vertical line from the function until the x-axis:
The line crosses the x-axis at the midpoint between values 102 and 127.5 to determine the value at this point you have to average both costs:
[tex]\frac{127.5+102}{2}=\frac{229.5}{2}=114.75[/tex]The cost of 4.5 inches of construction is $114.5
Write 0.000000000054 in scientific notation
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Answer:
5.4 × 10^-11
Step-by-step explanation:
9. The Elite Vacuum Company has determined its cost for making vacuums to beC = 24V + 1000, where C is the cost in dollars and V is the number of vacuums.If the cost must be between $49,000 and $121,000, how many vacuums can they makeper week? (You must set up and solve an inequality.)
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We are given the relationship between the cost in dollars (C) and the number of vacuums (V) to be:
[tex]C\text{ = 24V + 1000}[/tex]From the constraint, we have that the cost(C) must be greater than $49000 and less than $121000
Writing this as inequality:
[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000 } \\ 24V\text{ + 1000 }\leq\text{ 121000} \end{gathered}[/tex]Solving the linear inequalities for V:
[tex]\begin{gathered} 24V\text{ + 1000 }\ge\text{ 49000} \\ 24V\text{ }\ge\text{ 49000 - 1000} \\ 24V\text{ }\ge\text{ 48000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\ge\text{ }\frac{48000}{24} \\ V\text{ }\ge\text{ 2000} \end{gathered}[/tex]Similarly for the second inequality:
[tex]\begin{gathered} 24V\text{ + 1000 }\leq\text{ 121000} \\ 24V\text{ }\leq121000\text{ - 1000} \\ 24V\text{ }\leq\text{ 120000} \\ \text{Divide both sides by 24} \\ \frac{24V}{24}\text{ }\leq\text{ }\frac{120000}{24} \\ V\text{ }\leq5000 \end{gathered}[/tex]Hence, the number of vacuums they can make per week can be between 2000 and 5000 or in inequality:
[tex]2000\text{ }\leq\text{ V }\leq\text{ 5000}[/tex]Answer:
Between 2000 and 5000 vacuums
The shorter leg of a right triangle is 9cm shorter than the longer leg. The hypotenuse is 9cm longer than the longer leg. Find the side lengths of the triangle.Length of the shorter leg: _ cmLength of the longer leg:__ cmLength of hypotenuse __ cm
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Explanation:
let the longer leg = x
The shorter leg = 9cm shorter than the longer leg
The shorter leg = x - 9
hypotenuse = 9cm longer than the longer leg
hypotenuse = x + 9
Using pythagoras theorem:
hypotenuse² = shorter leg² + longer leg²
(x + 9)² = x² + (x - 9)²
Expanding:
x² + 9x + 9x + 81 = x² + x ² - 9x -9x + 81
x² + 18x + 81 = 2x² -18x + 81
collect like terms:
18x + 18x + 81 - 81 = 2x² - x²
36x + 0 = x²
x² - 36x = 0
x(x - 36) = 0
x = 0 or (x - 36) = 0
x = 0 or x = 36
if x = 0
shorter side = x - 9 = 0 - 9 = -9
Since the length cannot be negative, x = 36
The longer leg = x = 36 cm
The shorter leg = x - 9 = 36 - 9
The shorter leg = 27cm
The hypotenuse = x + 9 = 36 + 9
The hypotenuse = 45 cm
write the following comparison as a ratio reduced to lowest terms. 21 quarters to 13 dollars
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In order to calculate the ratio of these values, let's divide them, using the fraction form:
[tex]\text{ratio}=\frac{21}{13}[/tex]Since the numbers 21 and 13 don't have any common factor, the fraction is already in the lowest terms.
So the ratio is 21:13
Use the formula for n^P_r to evaluate the following expression.
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Use the following formula:
[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]Then, for 11P6:
[tex]\begin{gathered} _{11}P_6=\frac{11!}{(11-6)!}=\frac{11!}{5!}=\frac{5!\cdot6\cdot7\cdot8\cdot9\cdot10\cdot11}{5!} \\ _{11}P_6=6\cdot7\cdot8\cdot9\cdot10\cdot11=332640 \end{gathered}[/tex]Hence, the result is 332640
If the inflation has been 2.7%, how much more do you have to pay this year foran item that cost $11.50 last year?
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Given data:
The cost of the item is $11.50.
The inflation percentage is 2.7%.
Increase in the price is,
[tex]\begin{gathered} =11.50\times(\frac{2.7}{100}_{}) \\ =11.50\times0.027 \\ =0.3105 \end{gathered}[/tex]Total amount to be paid last year,
[tex]\begin{gathered} =11.50+0.3105 \\ =11.8105 \end{gathered}[/tex]Therefore you will have to pay $ 0.3105 more.
Which equation represents a line that passes through the two points in thetable?O A. y+3= (x+3)OB. y-3-(x-3)O G. y+3=(x+3)C.OD.y-3-(x-3)X36y35
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The first step is to choose one option and rewrite it in the explicit form
I will choose the second option:
[tex]y-3=\frac{2}{3}(x-3)[/tex][tex]y=\frac{2}{3}(x-3)+3[/tex][tex]y=\frac{2}{3}x-2+3[/tex][tex]y=\frac{2}{3}x+1[/tex]Now replace the x points in the equation to verify if it satisfies their respective value in y
For x=3
[tex]y=\frac{2}{3}(3)+1=\frac{6}{3}+1=2+1=3[/tex]For x=3 satisfy y=3
Now x=6
[tex]y=\frac{2}{3}(6)+1=\frac{12}{3}+1=4+1=5[/tex]For x=6 satisfy y=5
So the answer is b.
8% of the students at Jemerson Middle School are absent because of illness. If there are 150 students in the school, how many are absent? 12015128
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12 students
Explanation
when you have 8% , it means 8 of every 100 students are absent
find the decimal form
[tex]8\text{ \% = }\frac{8}{100}=0.08[/tex]then, to find the 8% of any number, just multiply the number by 0.08
Step 1
If there are 150 students in the school, how many are absent?
[tex]\begin{gathered} \text{absent}=\text{total}\cdot0.08 \\ \text{absent}=150\cdot0.08 \\ \text{absent}=12 \end{gathered}[/tex]so, 12 students are absent