Answer:
the answer 3NH3+3O2->3NO+3H2O
what would immediately be used if your clothing caught fire or if a large chemical spill had occured on your clothing? group of answer choices laboratory sinks eye-wash fountain safety shower fire extinguisher
If yοur clοthing caught fire οr if a large chemical spill οccurred οn yοur clοthing, the apprοpriate immediate actiοn wοuld depend οn the specific situatiοn. Hοwever, the mοst suitable οptiοn frοm the given chοices wοuld be: Safety shοwer
What is a Chemical spills?Chemical spills can result in chemical expοsures and cοntaminatiοns. Whether a chemical spill can be safely cleaned up by labοratοry staff depends οn multiple factοrs including the hazards οf the chemicals spilled, the size οf the spill, the presence οf incοmpatible materials, and whether yοu have adequate training and supplies tο safely clean up the spill.
A safety shοwer is designed tο quickly rinse οff hazardοus substances frοm the bοdy in the event οf a chemical spill οr splash. It is equipped with a large οverhead shοwerhead οr multiple nοzzles that deliver a significant flοw οf water tο wash away the chemical and minimize the pοtential fοr injury οr further damage.
While a fire extinguisher may be used if yοur clοthing catches fire, it is impοrtant tο remember that "stοp, drοp, and rοll" is the recοmmended initial respοnse tο extinguish the flames οn yοur bοdy. The fire extinguisher shοuld be used if the fire cannοt be quickly cοntrοlled by οther means.
Labοratοry sinks, eye-wash fοuntains, and safety shοwers are primarily intended fοr emergency respοnse tο chemical spills οr splashes and prοvide immediate access tο water tο flush οff the chemicals and minimize pοtential harm.
Learn more about Chemical spills
https://brainly.com/question/30192023
#SPJ4
the formula for water is h2o. how many gramsof hydrogen atoms are in 7.0 grams of water? please answer to the nearest 0.01 grams. you do not need to include units in your answer.
There are approximately 0.78 grams of hydrogen atoms in 7.0 grams of water.
To determine the number of grams of hydrogen atoms in 7.0 grams of water [tex](H_2O)[/tex], we need to consider the molar mass of water and the ratio of hydrogen atoms in the formula.
The molar mass of water [tex](H_2O)[/tex] can be calculated by adding the atomic masses of hydrogen (H) and oxygen (O):
The molar mass of water [tex](H_2O) = 2 *[/tex] Atomic mass of hydrogen (H) + Atomic mass of oxygen (O)
Using the atomic masses from the periodic table:
The molar mass of water [tex](H_2O)[/tex] [tex]= 2 \times 1.01 \, \text{g/mol} + 16.00 \, \text{g/mol} = 18.02 \, \text{g/mol}\][/tex]
The molar mass of water is 18.02 g/mol.
Next, we can calculate the moles of water in 7.0 grams by dividing the given mass by the molar mass of water:
[tex]\[\text{Moles of water} = \frac{7.0 \, \text{g}}{18.02 \, \text{g/mol}} \approx 0.388 \, \text{mol}\][/tex]
Since there are two hydrogen atoms in each molecule of water, the number of moles of hydrogen atoms is twice the number of moles of water:
Moles of hydrogen atoms = 2 * Moles of water [tex]\approx 2 \times 0.388 \, \text{mol} \approx 0.776 \, \text{mol}\][/tex]
Finally, to determine the grams of hydrogen atoms, we multiply the moles of hydrogen atoms by the molar mass of hydrogen:
Grams of hydrogen atoms = Moles of hydrogen atoms * Molar mass of hydrogen
Using the atomic mass of hydrogen:
Grams of hydrogen atoms [tex]\[ = 0.776 \, \text{mol} \times 1.01 \, \text{g/mol} \approx 0.78276 \, \text{g}\][/tex]
Rounding to the nearest 0.01 grams:
[tex]\[\text{Grams of hydrogen atoms} \approx 0.78 \, \text{g}\][/tex]
Therefore, there are approximately 0.78 grams of hydrogen atoms in 7.0 grams of water.
To learn more about hydrogen atoms from the given link
https://brainly.com/question/30722024
#SPJ4
according to the following reaction, how many grams of oxygen gas are required for the complete reaction of 32.4 grams of carbon (graphite)? carbon (graphite) (s) oxygen (g) carbon dioxide (g)
To determine the grams of oxygen gas required for the complete reaction of 32.4 grams of carbon (graphite), we need to use the balanced equation and stoichiometry. The molar ratio between carbon and oxygen in the equation allows us to calculate the amount of oxygen gas needed.
The balanced equation for the reaction between carbon (graphite) and oxygen gas to form carbon dioxide is:
C (graphite) + O2 (g) -> CO2 (g)
From the balanced equation, we can see that the molar ratio between carbon and oxygen is 1:1. This means that for every 1 mole of carbon, we need 1 mole of oxygen gas.
To calculate the grams of oxygen gas required, we need to convert the given mass of carbon (32.4 grams) to moles using its molar mass. The molar mass of carbon is 12.01 g/mol.
Moles of carbon = mass of carbon / molar mass of carbon
Moles of carbon = 32.4 g / 12.01 g/mol ≈ 2.70 mol
Since the molar ratio between carbon and oxygen is 1:1, we need the same number of moles of oxygen gas.
Moles of oxygen gas = 2.70 mol
To convert the moles of oxygen gas to grams, we can use the molar mass of oxygen, which is approximately 32.00 g/mol.
Grams of oxygen gas = moles of oxygen gas x molar mass of oxygen
Grams of oxygen gas = 2.70 mol x 32.00 g/mol ≈ 86.4 g
Therefore, approximately 86.4 grams of oxygen gas are required for the complete reaction of 32.4 grams of carbon (graphite).
Learn more about equation here: https://brainly.com/question/29174899
#SPJ11
how many milliliters of solution are needed to supply 0.0233 moles of glucose from 0.643 m glucose solution?
We need 36.2 mL of the 0.643 m glucose solution to supply 0.0233 moles of glucose
To calculate the number of milliliters of solution needed to supply 0.0233 moles of glucose from a 0.643 m glucose solution, we need to use the formula:
moles of solute = molarity * volume (in liters)
First, let's calculate the moles of glucose needed:
moles of glucose = 0.0233 mol
Next, let's convert the molarity to moles per liter:
0.643 m = 0.643 mol/L
Now, we can rearrange the formula to solve for the volume:
volume (in L) = \frac{moles of solute }{molarity}
volume (in L) =\frca{ 0.0233 mol }{ 0.643 mol/L}
volume (in L) = 0.0362 L
Finally, we need to convert the volume from liters to milliliters:
volume (in mL) = 0.0362 L * 1000 mL/L
volume (in mL) = 36.2 mL
Therefore, we need 36.2 mL of the 0.643 m glucose solution to supply 0.0233 moles of glucose.
learn more about glucose Refer: glucose
#SPJ11
Which one of these statements about yogurt making is FALSE? Select one: a). The bacteria added to milk converts lactose to lactic acid, which reduces the pH of the system. b). The magnitude of the negative charge on the proteins decreases when the milk is acidified and the pH moves towards the isoelectric point. C). The desirable texture of yogurt is mainly the result of the formation of a network of physically cross-linked casein molecules. d). The casein molecules in milk are globular proteins that form cross-links with each other through hydrophobic attractions.
The FALSE statement about yogurt making is d). The casein molecules in milk are globular proteins that form cross-links with each other through hydrophobic attractions. In reality, casein molecules are not globular proteins; they are phosphoproteins that form cross-links through the interactions of their micelle structures.
The statement that is FALSE about yogurt making is d) The casein molecules in milk are globular proteins that form cross-links with each other through hydrophobic attractions. The correct statement is that the desirable texture of yogurt is mainly the result of the formation of a network of physically cross-linked casein molecules. The bacteria added to milk converts lactose to lactic acid, which reduces the pH of the system. This decrease in pH causes the magnitude of the negative charge on the proteins to decrease, moving the pH towards the isoelectric point. This is what causes the physically cross-linked casein molecules to form, resulting in the desirable texture of yogurt.
To know more about hydrophobic attractions visit:
https://brainly.com/question/31824394
#SPJ11
Consider the following reaction:
2NO2(g) → 2NO(g) + O2(g) rate = k [NO2]^2 where k = 0.25 M-1 s-1
A rigid 1.00 L reaction vessel initially contains only 0.50 moles NO2. How long would it take to form 0.20 moles of O2? Report answer in seconds to 2 significant figures
To determine the time it takes to form 0.20 moles of O2, we need to first find the initial concentration of NO2 and the final concentration of NO2 after the reaction.
Initial concentration of NO2 = (0.50 moles) / (1.00 L) = 0.50 M
Reporting the answer to 2 significant figures, the time it takes to form 0.20 moles of O2 is 1.6 s.
To solve this problem, we need to use the rate law equation and the given values to calculate the time required to form 0.20 moles of O2. The rate law equation for this reaction is rate = k [NO2]^2.
First, we need to calculate the initial concentration of NO2 in the reaction vessel. Since the vessel contains 1.00 L of gas and 0.50 moles of NO2, the initial concentration of NO2 is 0.50 M.
Next, we can use the rate law equation to calculate the rate of the reaction at the initial concentration of NO2:
rate = k [NO2]^2
rate = 0.25 M-1 s-1 x (0.50 M)^2
rate = 0.0625 M/s
To form 0.20 moles of O2, we need to calculate the time required at this rate:
0.20 moles O2 / 2 moles NO2 = 0.10 moles NO2 used
0.10 moles NO2 / (0.0625 M/s) = 1.6 s
Therefore, it would take 1.6 seconds (reported to 2 significant figures) to form 0.20 moles of O2 in the reaction vessel.
To know more about significant figures visit:
https://brainly.com/question/23396760
#SPJ11
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL. powdered drink mix is (C12H22O11).
To make a 1 molar solution of 100 mL, you would need approximately 34.23 grams of powdered drink mix ([tex]C_{12}H_{22}O_{11}[/tex]).
To determine the mass of powdered drink mix needed to make a 1.0 M solution, we need to use stoichiometry and the molar mass of the compound. In this case, the powdered drink mix is represented by the compound [tex]C_{12}H_{22}O_{11}[/tex] (sucrose).
The molarity (M) is defined as moles of solute per liter of solution. Therefore, for a 1.0 M solution with a volume of 100 mL (0.1 L), we have:
Moles of sucrose = Molarity × Volume = 1.0 mol/L × 0.1 L = 0.1 mol.
We calculate the molar mass of sucrose:
Molar mass of [tex]C_{12}H_{22}O_{11}[/tex]
= 12.01 g/mol × 12 + 1.01 g/mol × 22 + 16.00 g/mol × 11
= 144.12 g/mol + 22.22 g/mol + 176.00 g/mol
= 342.34 g/mol.
Finally, we can calculate the mass of powdered drink mix needed:
Mass of powdered drink mix
= Moles of sucrose × Molar mass of C12H22O11
= 0.1 mol × 342.34 g/mol
= 34.23 g.
Learn more about the calculation of molarity here:
https://brainly.com/question/31369939
#SPJ4
Indicate which of the following has the lowest standard molar entropy (S°).
CH4(g)
Na (s)
CH3CH2OH (l)
He (g)
H2O (s)
Among the given substances, the lowest standard molar entropy (S°) is associated with sodium (Na(s)).
The standard molar entropy (S°) is a measure of the degree of disorder or randomness in a substance at standard conditions (298 K and 1 bar). In general, substances with more complex molecular structures or larger numbers of atoms tend to have higher molar entropies.
Sodium (Na) exists as a solid at standard conditions. Solids typically have lower entropies compared to gases or liquids because their particles are more closely packed and have less freedom of movement. Therefore, Na(s) has the lowest standard molar entropy among the given options.
The other substances in the list include [tex]CH_4(g)[/tex] (methane gas), [tex]CH_3CH_2OH(l)[/tex] (ethanol liquid), He(g) (helium gas), and[tex]H_2O[/tex](s) (water ice). Methane and ethanol have larger and more complex molecular structures compared to sodium, making them more disordered and therefore having higher entropies. Both helium and water exist as gases at standard conditions and have higher entropies than solids.
In summary, among the given substances, sodium (Na(s)) has the lowest standard molar entropy due to its solid state and closely packed structure.
To learn more about standard molar entropy refer:
https://brainly.com/question/32252456
#SPJ11
a sample of c3h8 has 5.44×1024 h atoms. how many carbon atoms does the sample contain?
In the molecule C3H8 (propane), there are three carbon atoms (C) and eight hydrogen atoms (H). Given that the sample of C3H8 has 5.44×10^24 H atoms, we can use the ratio of the number of H atoms to the number of C atoms to determine the number of C atoms in the sample.
The ratio of H atoms to C atoms in C3H8 is 8:3. Therefore, we can set up the following proportion:
(8 H atoms) / (3 C atoms) = (5.44×10^24 H atoms) / (x C atoms)
Cross-multiplying and solving for x (the number of C atoms), we get:
8 * x = 3 * (5.44×10^24)
x = (3 * 5.44×10^24) / 8
x ≈ 2.04×10^24
Therefore, the sample of C3H8 contains approximately 2.04×10^24 carbon (C) atoms.
Learn more about propane here ;
https://brainly.com/question/14519324
#SPJ11
the following molecule is nonpolar. group of answer choices a. CO b. CO2 c. COCl2 d. H2S e. H2O
The molecule that is nonpolar among the options provided is (a) CO.
In order to determine the polarity of a molecule, we need to consider its molecular geometry and the polarity of its individual bonds.
(a) CO (carbon monoxide) has a linear molecular geometry, and the carbon-oxygen bond is polar due to the difference in electronegativity between carbon and oxygen. However, since CO is a linear molecule with symmetrical distribution of electron density, the polarities of the individual bonds cancel each other out, resulting in a nonpolar molecule overall.
(b) CO2 (carbon dioxide) has a linear molecular geometry as well, but it consists of two polar carbon-oxygen bonds. However, the molecule is linear and symmetrical, so the polarities of the two bonds cancel each other out, making CO2 a nonpolar molecule.
Know more about molecule here:
https://brainly.com/question/30465503
#SPJ11
In a 0.100 M solution of Carbonic Acid (H2CO3), what would be the concentration of the CO32 equilibrium?
Ka1 = 4.3 x 10^-7
Ka2 = 5.6 x 10^-11
The concentration of carbonate at equilibrium would be____
The concentration of the CO32- ion at equilibrium in a 0.100 M solution of carbonic acid (H2CO3) can be calculated using the equilibrium constants (Ka1 and Ka2) and the stoichiometry of the balanced equation. The concentration of CO32- at equilibrium would be approximately 1.55 * 10^-8 M.
The dissociation of carbonic acid (H2CO3) can be represented by the following equilibrium reactions:
H2CO3 ⇌ H+ + HCO3- (Ka1)
HCO3- ⇌ H+ + CO32- (Ka2)
Given that Ka1 = 4.3 * 10^{-7} and Ka2 = 5.6 *10^{-11}, we can use these equilibrium constants to determine the concentrations of HCO3- and CO32- at equilibrium.
Let x be the concentration of H+ ions at equilibrium. Since the concentration of carbonic acid is 0.100 M, the initial concentration of H+ ions is also 0.100 M.
Using the equilibrium expression for Ka1, we have:
Ka1 = \frac{[H+][HCO3-] }{ [H2CO3]}
4.3 * 10^{-7 }= \frac{x * (0.100 - x) }{0.100}
Simplifying the equation and solving for x, we find x ≈ 1.54* 10^{-3} M.
Now, using the equilibrium expression for Ka2, we have:
Ka2 =\frac{ [H+][CO32-] }{[HCO3-]}
5.6 *10^{-11} =\frac{ (1.54 * 10^{-3}) * (CO32- concentration) }{(1.54 * 10^{-3} - CO32- concentration)}
Solving for the CO32- concentration, we find it to be approximately 1.55 * 10^{-8} M.
Therefore, the concentration of the CO32- ion at equilibrium in a 0.100 M solution of carbonic acid would be approximately 1.55 * 10^{-8} M.
learn more about equilibrium Refer: https://brainly.com/question/30694482
#SPJ11
the ph of four different substances is shown below. substance ph shampoo 6 lemon juice 2 tomato juice 4 liquid drain cleaner 14 which substance is closest to being neutral on the ph scale? shampoo lemon juice tomato juice liquid drain cleaner
The substance closest to being neutral on the pH scale is shampoo, with a pH of 6.
A neutral pH is 7, so substances with a pH below 7 are considered acidic and those above 7 are considered basic. Lemon juice has a pH of 2, which is highly acidic, while tomato juice has a pH of 4, making it slightly acidic. Liquid drain cleaner, on the other hand, has a pH of 14, making it highly basic. Therefore, of the four substances listed, shampoo has the pH closest to neutral. The pH scale ranges from 0 to 14, with 7 being neutral. The four substances mentioned have the following pH levels: shampoo (6), lemon juice (2), tomato juice (4), and liquid drain cleaner (14). Among these substances, shampoo has a pH of 6, which is closest to the neutral pH level of 7. Therefore, shampoo is the substance that is closest to being neutral on the pH scale.
To know more about pH visit:
https://brainly.com/question/2288405
#SPJ11
table salt forms from sodium and chloride via hydrogen bonding. T/F
False. Table salt, or sodium chloride, forms from an ionic bond between sodium and chloride ions. This bond occurs as a result of the attraction between the positively charged sodium ion and the negatively charged chloride ion.
Hydrogen bonding, on the other hand, is a type of intermolecular bonding that occurs between molecules, not ions. It involves the attraction between a hydrogen atom bonded to a highly electronegative atom (such as oxygen or nitrogen) and a nearby electronegative atom in another molecule.
So, while hydrogen bonding may be involved in the formation of certain types of compounds, it is not involved in the formation of table salt.
To know more about ionic bond visit:
https://brainly.com/question/9075398
#SPJ11
Given the electrochemical reaction shown, what is the standard free energy change ΔG° if E˚ = +1.61 V? Mg | Mg2+(aq) || Zn2+(aq) | Zn
The standard free energy change (ΔG°) for the given electrochemical reaction is approximately -310,000 J/mol.
The electrochemical reaction given is Mg + Zn2+ → Mg2+ + Zn. To calculate the standard free energy change ΔG°, we can use the formula ΔG° = -nFE°, where n is the number of electrons transferred in the reaction, F is the Faraday constant (96,485 C/mol), and E° is the standard electrode potential. In this case, n = 2 because two electrons are transferred in the reaction, and E° = +1.61 V because it is given in the question. Plugging these values into the formula, we get: ΔG° = -2 x 96,485 C/mol x (+1.61 V) = -311,963 J/mol. Therefore, the standard free energy change ΔG° for the given electrochemical reaction is -311,963 J/mol. This indicates that the reaction is spontaneous and releases energy.
The standard free energy change (ΔG°) of an electrochemical reaction can be determined using the Nernst equation:
ΔG° = -nFE°
where n is the number of electrons transferred, F is the Faraday constant (96,485 C/mol), and E° is the standard cell potential.
In the given reaction, Mg is oxidized to Mg2+ and Zn2+ is reduced to Zn:
Mg → Mg2+ + 2e- (oxidation)
Zn2+ + 2e- → Zn (reduction)
The overall reaction is:
Mg + Zn2+ → Mg2+ + Zn
From the balanced equation, we can see that n = 2 electrons are transferred. Given E° = +1.61 V, we can now calculate ΔG°:
ΔG° = -2 * 96,485 C/mol * 1.61 V
ΔG° = -310,000 J/mol
To know more about electrochemical visit:
https://brainly.com/question/31606417
#SPJ11
A galvanic cell is powered by the following redox reaction:
3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq) = 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)
Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab.
Write a balanced equation for the half-reaction that takes place at the cathode.
Write a balanced equation for the half-reaction that takes place at the anode.
Calculate the cell voltage under standard conditions.
In the galvanic cell powered by the given redox reaction, the balanced equation for the half-reaction at the cathode is 2MnO4^-(aq) + 4H2O(l) + 3e^-(aq) -> 2MnO2(s) + 8OH^-(aq).
The balanced equation for the half-reaction at the anode is 6Cl^-(aq) -> 3Cl2(g) + 6e^-(aq).
The cell voltage under standard conditions can be calculated by finding the reduction potentials of the half-reactions and subtracting the anode potential from the cathode potential.
The half-reaction at the cathode can be determined by identifying the species that gains electrons and is reduced. In this case, MnO4^- is reduced to MnO2. The balanced equation for this half-reaction is 2MnO4^-(aq) + 4H2O(l) + 3e^-(aq) -> 2MnO2(s) + 8OH^-(aq).
The half-reaction at the anode involves the species that loses electrons and is oxidized. In this case, Cl^- is oxidized to Cl2. The balanced equation for this half-reaction is 6Cl^-(aq) -> 3Cl2(g) + 6e^-(aq).
To calculate the cell voltage under standard conditions, we need to find the reduction potentials of the half-reactions. The reduction potential of the cathode half-reaction is positive, while the reduction potential of the anode half-reaction is negative. By subtracting the anode potential from the cathode potential, we obtain the cell voltage.
Unfortunately, without specific electrochemical data from the ALEKS Data tab, I am unable to provide the exact calculation for the cell voltage. Please refer to the given electrochemical data to obtain the reduction potentials for MnO4^-/MnO2 and Cl^-/Cl2, and use them to calculate the cell voltage using the Nernst equation or standard reduction potentials.
learn more about galvanic cell Refer: https://brainly.com/question/29784751
#SPJ11
The solubility of PbBr2PbBr2 is 0.427 g per 100 mL of solution at 25 ∘∘C. Determine the value of the solubility product constant for this strong electrolyte. Lead(II) bromide does not react with water.
A) 5.4×10−45.4×10^-4
B) 2.7×10−42.7×10^-4
C) 3.1×10−63.1×10^−6
D) 1.6×10−61.6×10^−6
E) 6.3×10^−6
The solubility product constant (Ksp) for [tex]PbBr_2[/tex] can be calculated based on the given solubility information.
The solubility of [tex]PbBr_2[/tex] is given as 0.427 g per 100 mL of solution. To determine the value of Ksp, we need to convert the solubility in grams per liter (g/L).
First, we convert the volume from mL to L:
100 mL = 100/1000 L = 0.1 L
Next, we divide the mass of [tex]PbBr_2[/tex] by the volume in liters to obtain the solubility in g/L:
0.427 g / 0.1 L = 4.27 g/L
Since [tex]PbBr_2[/tex] is a strong electrolyte, it dissociates completely in water. Therefore, the concentration of Pb2+ ions and Br- ions in the solution will be equal to the solubility of [tex]PbBr_2[/tex] , which is 4.27 g/L.
The solubility product constant (Ksp) expression for PbBr2 is:
[tex]Ksp = [Pb^2+][Br-]^2[/tex]
Since the concentration of Pb2+ and Br- ions is the same and equal to the solubility (4.27 g/L), we substitute the values into the Ksp expression:
[tex]Ksp = (4.27 g/L)(4.27 g/L)^2 = 4.27^3 g^3/L^3[/tex]
Calculating the value of Ksp:
[tex]Ksp = 4.27^3 = 77.231 g^3/L^3[/tex]
The answer, rounded to the appropriate significant figures, is approximately [tex]7.7\times10^1 g^3/L^3[/tex], which corresponds to option D) [tex]1.6\times10^{−6}.[/tex]
To learn more about solubility refer:
https://brainly.com/question/23946616
#SPJ11
at standard temperature, the nernst equation can be rewritten to show that the nonstandard cell potential is equal to the standard cell potential minus:
The Nernst equation relates the potential of an electrochemical cell to the concentration of the species involved and the temperature. At standard temperature, which is usually taken as 25°C or 298 K, the Nernst equation simplifies to a form that is more commonly used.
At this temperature, the nonstandard cell potential can be calculated by subtracting the product of the gas constant (R), the temperature in kelvin, and the natural logarithm of the reaction quotient (Q) from the standard cell potential (E°).
In mathematical terms, the equation can be written as E = E° - (RT/nF) lnQ, where E is the nonstandard cell potential, E° is the standard cell potential, R is the gas constant, T is the temperature in kelvin, n is the number of electrons transferred in the reaction, F is Faraday's constant, and Q is the reaction quotient.
Therefore, at standard temperature, the nonstandard cell potential is equal to the standard cell potential minus the product of the gas constant, temperature in kelvin, and the natural logarithm of the reaction quotient. This equation is useful in determining the nonstandard potential of a cell at any temperature, as long as the values of Q, E°, and other relevant constants are known.
To know more about Nernst equation visit:
https://brainly.com/question/13043546
#SPJ11
identify the compound with the highest pka. ch2=ch2 ch3nh2 hc ≡≡ ch ch3ch3 ch3oh
The option A is correct answer which is CH₃CH₃.
What is Henderson-Hasselbalch equation?
The Henderson-Hasselbalch equation establishes a connection between the pH of acids (in aqueous solutions) and their pKa (acid dissociation constant).
pH = PKₐ + log [salt]/[Acid]
Where,
pH = Acidity of a buffer solution
pKₐ = Negative logarithm of Kₐ
Kₐ = Acid disassociation constant.
Hence, the highest pkₐ means lowest Kₐ which represent least acidic. Out of these compounds, CH₃CH₃ is least acidic because sp³ carbon is least acidic as compared to sp² C, sp C, N or O. Hence, pKₐ of A is Highest.
Hence, The option A is correct answer which is CH₃CH₃.
To learn more about pKₐ and Kₐ from the given link.
https://brainly.com/question/31084008
#SPJ4
Complete question is,
Which of the following has the highest pkₐ?
(a). CH₃CH₃
(b). HC ≡ CH
(c). CH₂ = CH₂
(d). CH₃OH
(e). CH₃NH₂
how many liters of co2 at stp are produced when 112.2 g of c8h16 are burned? c8h16(g) o2 (g) --> co2(g) h2o (g)
When 112.2 g of C_{8}H_{16} is burned, 179.2 L of CO_{2} is produced at STP.
The balanced chemical equation for the combustion of C_{8}H_{16}:
C_{8}H_{16}(g) + 12O_{2}(g) → 8CO_{2}(g) + 8H_{2}O(g)
Now, we can determine the moles of C8H16 by using its molar mass:
Molar mass of C_{8}H_{16} = (8 * 12.01) + (16 * 1.01) = 112.2 g/mol
Moles of C_{8}H_{16} = \frac{mass }{ molar mass} = \frac{112.2 g }{ 112.2 g/mol} = 1 mol
From the balanced chemical equation, we can see that 1 mol of C_{8}H_{16} produces 8 mol of CO_{2}. So, we have:
Moles of CO_{2} produced = 1 mol C_{8}H_{16} * (\frac{8 mol CO_{2} }{1 mol C_{8}H_{16}}) = 8 mol CO_{2}
Now, we can use the conditions of STP (standard temperature and pressure: 0°C and 1 atm) to find the volume of CO_{2} produced. At STP, 1 mol of any gas occupies a volume of 22.4 L. So, the volume of CO_{2} produced is:
Volume of CO_{2} = 8 mol CO_{2} * 22.4 L/mol = 179.2 L
This means that when 112.2 g of C_{8}H_{16} is burned, 179.2 L of CO_{2} is produced at STP. Therefore, the correct answer is: b. 179 L
learn more about combustion Refer: https://brainly.com/question/13153771
#SPJ11
complete question:
How many liters of CO2 at STP are produced when 112.2 g of c8h16 are burned? c8h16(g) o2 (g) --> co2(g) h2o (g)
a. 22.4L
b. 179 L
c. 10 L
d. 80.0L
select all the nontransparent pixels on the flowers layer and save it as a new selection named foreground.
To select all the nontransparent pixels on the flowers layer and save it as a new selection named foreground, you can follow these steps in most image editing software:
To select all the nontransparent pixels on the flowers layer and save it as a new selection named foreground, you can use the following steps:
1. Open the image in your preferred image editing software that supports layers and selection tools, such as Adobe Photoshop or GIMP.
2. Make sure the flowers layer is selected in the layers panel. If the layer is not visible, ensure it is visible by clicking the eye icon next to the layer.
3. Use the selection tool (e.g., Magic Wand tool or Lasso tool) to make a selection of the nontransparent pixels on the flowers layer. In most software, you can adjust the tolerance or feathering settings to refine the selection if needed.
4. Once the selection is made, go to the "Select" menu and choose "Save Selection." Give the selection a name, such as "foreground," and click "OK" to save it.
5. You now have a new selection named "foreground" that contains all the nontransparent pixels on the flowers layer. You can use this selection for further editing or apply adjustments specifically to the selected area.
Remember to consult the documentation or help resources of your specific image editing software for precise instructions as the steps may vary slightly between different applications.
To learn more about pixels refer:
https://brainly.com/question/29110282
#SPJ11
Titration of 15.00 mL of a weak, monoprotic acid solution requires 22.84 mL of a 0.09837M standardized NaOH solution. What is the molarity of the acid solution? (Show your work.)
The molarity of the acid solution is approximately 0.1499 M.
To determine the molarity of the acid solution, we can use the concept of stoichiometry in the neutralization reaction between the acid and base. The balanced equation for the reaction is:
acid + base → salt + water
From the given information, we can see that the acid is monoprotic, which means it donates only one proton (H+ ion) in the reaction. Therefore, the stoichiometry between the acid and base is 1:1.
First, let's calculate the number of moles of NaOH used in the titration:
moles of NaOH = concentration of NaOH × volume of NaOH used (in liters)
= 0.09837 M × 0.02284 L
= 0.002249 moles
Since the stoichiometry between the acid and base is 1:1, the number of moles of the acid is also 0.002249 moles.
Next, we need to calculate the molarity of the acid solution:
molarity of acid solution = moles of acid / volume of acid solution (in liters)
= 0.002249 moles / 0.01500 L
= 0.1499 M
Know more about molarity of the acid here:
https://brainly.com/question/30774637
#SPJ11
What Type Of Membrane Does A Calcium-Selective Electrode Use? a. LaF3 b. AgCl c. Liquid d. Glass
A calcium-selective electrode typically uses a glass membrane. A calcium-selective electrode is a type of ion-selective electrode (ISE) that is used to measure the concentration of calcium ions in a solution.
The electrode consists of a membrane that is selective to calcium ions and a reference electrode. The membrane is designed to only allow calcium ions to pass through while blocking other ions. This allows the electrode to selectively measure the concentration of calcium ions in a solution. The type of membrane used in a calcium-selective electrode is usually made of glass or liquid. Glass membranes are commonly used because they are highly selective and stable, providing accurate and reliable measurements. Liquid membranes, on the other hand, are less stable but are more flexible and can be customized to suit specific applications. The membrane of a calcium-selective electrode contains a calcium-sensitive ionophore, which is a chemical that binds to calcium ions and generates a measurable electrical signal.
To know more about electrodes
https://brainly.com/question/18251415
#SPJ11
What is the freezing point, in °C, of a 0.66 m solution of C4H10 in benzene?
FP (benzene) = 5.50 °C
Kf(benzene) = 5.12 °C/m
[?] °C
Hint: Remember significant figures are based on place value when adding or subtracting.
The freezing point of the 0.66 m solution of C4H10 in benzene is 2.1208 °C.
How do we calculate?The freezing point of a solution is:
ΔT = Kf × m
ΔT = change in temperature
Kf = the cryoscopic constant of the solvent
m = molality of the solution
We have the following parameters:
FP (benzene) = 5.50 °C
Kf (benzene) = 5.12 °C/m
m = 0.66 m
ΔT = Kf × m
ΔT = 5.12 °C/m × 0.66 m
ΔT = 3.3792 °C
Freezing Point of Solution = FP (benzene) - ΔT
Freezing Point of Solution = 5.50 °C - 3.3792 °C
Freezing Point of Solution = 2.1208 °C
Learn more about freezing point at:
https://brainly.com/question/30948897
#SPJ1
Cobalt ions form complex ions with water and chloride as shown in the reaction. The left side of the reaction is pink, and the right side of the reaction
is blue.
Co(H₂O)²+ + 4Cl + heat CoCl² + 6H₂O
Which statement about the system at equilibrium is correct?
(1 point)
O Cooling a purple solution will turn it pink.
O Adding hydrogen chloride (HCI) to a blue solution will turn it purple.
O Adding water to a purple solution will turn it blue.
O Heating a blue solution will turn it purple.
The correct statement about the system at equilibrium is Heating a blue solution will turn it purple. Thus, option A is correct.
In the given reaction, the left side (reactants) is pink, while the right side (products) is blue. The reaction involves the formation of complex ions of cobalt with water and chloride. The heat is shown as a reactant, indicating that it is required for the forward reaction to occur.
When the reaction is at equilibrium, it means the forward and backward reactions are occurring at the same rate. Heating a blue solution would provide the necessary energy to facilitate the reverse reaction, which involves the dissociation of the complex ions and the release of water molecules. This shift in the equilibrium would cause the solution to turn pink, indicating the presence of the Co(H₂O)²+ complex ions.
Therefore, heating a blue solution will turn it purple, which is the correct statement.
Learn more about reactant on:
https://brainly.com/question/30129541
#SPJ1
arrange the following elements in order of increasing electronegativity: aluminum, sulfur, phosphorus, silicon
To arrange the elements in order of increasing electronegativity, we need to refer to the periodic table. Electronegativity generally increases as you move across a period from left to right and decreases as you move down a group.
The elements given are aluminium (Al), sulfur (S), phosphorus (P), and silicon (Si). Let's arrange them in order of increasing electronegativity:
Aluminum (Al): Aluminum is a metal and generally has lower electronegativity compared to nonmetals. It is less electronegative than sulfur, phosphorus, and silicon.
Silicon (Si): Silicon is also a metalloid, and its electronegativity is slightly higher than that of aluminium but lower than sulfur and phosphorus.
Phosphorus (P): Phosphorus is a nonmetal and has a higher electronegativity than both aluminium and silicon.
Sulfur (S): Sulfur is a nonmetal and has the highest electronegativity among the given elements.
Arranging them in order of increasing electronegativity:
Aluminum (Al) < Silicon (Si) < Phosphorus (P) < Sulfur (S)
Learn more about electronegativity here ;
https://brainly.com/question/3393418
#SPJ11
Balance the following chemical equation H3O + CaCO3 -> H2O + Ca + CO2 Assume the coefficient of CO2 is 1. What is the balanced equation?
The balanced chemical equation is: 2H3O + CaCO3 -> 2H2O + Ca + CO2
To balance the given chemical equation, we need to make sure that the same number of atoms of each element is present on both sides of the equation.
The given equation is:
H3O + CaCO3 -> H2O + Ca + CO2
Let's start by balancing the carbon atoms first. The coefficient of CaCO3 already has one carbon atom, so we need to balance it with one carbon atom on the product side. We can achieve this by putting a coefficient of 1 in front of CO2.
H3O + CaCO3 -> H2O + Ca + 1CO2
Now let's balance the hydrogen atoms. We have three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance them, we can add a coefficient of 2 in front of H2O.
H3O + CaCO3 -> 2H2O + Ca + 1CO2
Finally, let's balance the oxygen atoms. We have three oxygen atoms on the left side and four oxygen atoms on the right side. To balance them, we can put a coefficient of 2 in front of H3O.
2H3O + CaCO3 -> 2H2O + Ca + 1CO2
Therefore, the balanced chemical equation is:
2H3O + CaCO3 -> 2H2O + Ca + CO2
In this balanced equation, the coefficient of CO2 is 1 as assumed.
To know more about coefficient visit:
https://brainly.com/question/1594145
#SPJ11
Please help!!
How many grams of precipitate will form when Na2SO4 reacts with 25 mL of 0.50 M Ba(NO3)2?
Approximately 2.92 grams of BaSO₄ precipitate will form when Na₂SO₄ reacts with 25 mL of 0.50 M Ba(NO₃)₂.
Given information,
Volume of Ba(NO₃)₂ = 25 mL
Molarity of Ba(NO₃)₂ = 0.50 M
The balanced chemical equation for the reaction between Na₂SO₄ and Ba(NO3)2 is: Na₂SO₄ + Ba(NO₃)₂ → BaSO₄ + 2NaNO₃
One mole of Na₂SO₄ reacts with one mole of Ba(NO₃)₂ to produce one mole of BaSO₄.
Number of moles of Ba(NO₃)₂ = Concentration × Volume
Number of moles of Ba(NO₃)₂ = 0.50 mol/L × 0.025 L
Number of moles of Ba(NO₃)₂ = 0.0125 mol
Molar mass of BaSO₄ = 137.33 + 32.07 + 4 × 16.00
Molar mass of BaSO₄ = 233.37 g/mol
The mass of the precipitate (BaSO₄) formed:
Mass of BaSO₄ = Number of moles of BaSO₄ × Molar mass of BaSO₄
Mass of BaSO₄ = 0.0125 × 233.37
Mass of BaSO₄ = 2.92 grams
Learn more about precipitate, here:
https://brainly.com/question/30904755
#SPJ1
cobalt-60 and iodine-131 are radioactive isotopes commonly used in nuclear medicine. how many protons, neutrons, and electrons are in atoms of these isotopes?
Cobalt-60 has 27 protons, 33 neutrons, and 27 electrons. Iodine-131 has 53 protons, 78 neutrons, and 53 electrons. These isotopes are used in nuclear medicine because of their radioactive properties.
Cobalt-60 emits gamma radiation and is used for cancer treatment, while iodine-131 is used for imaging and treating thyroid diseases. It's important to handle these isotopes carefully because they can be dangerous due to their high levels of radiation. Understanding the atomic structure of these isotopes is essential for the safe use of nuclear medicine in healthcare. Cobalt-60 and iodine-131 are radioactive isotopes used in nuclear medicine. Cobalt-60 has 27 protons, 33 neutrons, and 27 electrons, while iodine-131 has 53 protons, 78 neutrons, and 53 electrons. The number of protons determines the element, and the sum of protons and neutrons gives the atomic mass, which defines the isotope. Electrons match the number of protons to maintain a neutral charge in the atom.
To know more about radioactive visit:
https://brainly.com/question/1770619
#SPJ11
seventy five milimeters of a solution made up of 6.0g of naoh dissolved in 2.0l of water is titrated with 0.059m h3po4. how much h3po4 is needed to reach the endpoint
2.54 mL of 0.059 M H3PO4 is needed to reach the endpoint.
The balanced chemical equation for this reaction is:
3NaOH + H3PO4 → Na3PO4 + 3H2O
To find out how much H3PO4 is needed to reach the endpoint, we need to use the equation:
moles of NaOH = moles of H3PO4
First, we need to calculate the number of moles of NaOH in 75 mL of the solution:
mass of NaOH = 6.0 g
molar mass of NaOH = 40.0 g/mol
moles of NaOH = 6.0 g / 40.0 g/mol = 0.15 mol
Next, we need to calculate the number of moles of H3PO4 needed to react with 0.15 mol of NaOH:
moles of H3PO4 = moles of NaOH = 0.15 mol
Finally, we need to calculate the volume of 0.059 M H3PO4 needed to provide 0.15 mol of H3PO4:
moles of H3PO4 = M × L
0.15 mol = 0.059 M × L
L = 0.15 mol / 0.059 M = 2.54 L
Therefore, 2.54 mL of 0.059 M H3PO4 is needed to reach the endpoint.
To know more about chemical equation visit:
https://brainly.com/question/28792948
#SPJ11
what percent of commercial chemicals have been tested for toxicity
The percentage of commercial chemicals that have been tested for toxicity is unknown as there is no comprehensive database or study available to provide an accurate figure.
Determine pecentage of testing the toxicity of chemicals?Testing the toxicity of chemicals is a complex and time-consuming process, and there are numerous chemicals used in commercial products worldwide.
The sheer volume of chemicals, combined with the cost and time required for testing, makes it challenging to assess the exact percentage of chemicals that have undergone toxicity testing.
Furthermore, different regulatory bodies have different requirements for toxicity testing, adding further complexity to the issue. While some chemicals undergo extensive testing due to their known hazardous nature or regulatory requirements, many others have not been thoroughly assessed for toxicity.
It is crucial to prioritize and encourage comprehensive testing of commercial chemicals to ensure the safety of human health and the environment.
Therefore, the percentage of commercial chemicals tested for toxicity is unknown due to the lack of comprehensive data.
To know more about toxicity, refer here:
https://brainly.com/question/1563060#
#SPJ4