Neutrons are also known as____

neutrinos
photons
alpha particles
beta particles

Answers

Answer 1

Answer:

Beta Particles

Explanation:


Related Questions

in a railyard a train is being put together from freight cars.An empty freight car coasting 10 m/s strikes a loaded car that is stationary and the cars couple together. Each of the cars Haas a mass of 3000kg when empty and the loaded car contains 12000kg of canned soda . with what speed does the combination of the two cars start to move? ​

Answers

Answer:m1v1 + m2v2 = (m1f + m2f)vf. 3000kg(10.0m/s) + (15000kg)(0.0m/s) = (18000kg)(vf).

Explanation:

please help i’m so lost✋:
Place the following events describing the production of electrical energy from a nuclear fission reactor in the correct order. Write the numbers 1 (first) through 7 (fast) in the spaces provided.

Answers

The thermal energy from nuclear reactions is first converted to mechanical energy and finally to electrical energy for use by the community.

What is nuclear energy?

Nuclear energy is the energy produced as a result of changes that occur in the nucleus of atoms of elements. These changes are known as nuclear reactions.

Electrical energy can be generated from nuclear reactions.

The steps in the generation of electrical energy from nuclear reactions is as follows:

A neutron bombards a uranimu-235 isotope A uranium-235 atom splits, producing atoms with smaller nuclei, three neurons, and thermal energythermal energy released by the react ion is added to water superheated water passes through a thermal exchanger, where the thermal energy released boil a separate system of water to produce steam steam produced by boiling water causes the blade of a turbine to rotate The mechanical energy of the rotating turbine is transferred to an electric generator electricity from the generator is carried to the community through wires.

Therefore, the thermal energy from nuclear reactions is converted to electrical energy for use by the community.

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Tomas lives in Brazil. When he looks up to the night sky, he always sees the same side of the Moon. Why does this happen?
A
The Moon orbits the Earth in the same length of time that it takes to make one revolution on its axis.
B
The Moon is stationary on its axis as it orbits the Earth.
C
The Moon orbits the Earth in the same length of time that it takes for the Earth to orbit the Sun.
D
The Moon is stationary in the sky in relation to Earth.

Answers

Answer: The answer is C. Hope it helps!!, and if you get it wrong it's my fault

Question 2 (1 point)
This graph shows an object in free fall. Assume there is no air resistance. What is the only force acting on this object?

Answers

Answer:

Actually, there is  no force (felt by the object) acting on the object.

It is similar to an  object in orbit around the earth (weightlessness)

F = M a    describes the motion of the particle where

M a = M g    where the acceleration of the particle is equal to the force of gravity acting on the particle

From an external view the only force acting on the particle is M g and it produces an acceleration of M g

There is no force felt by the freely falling body. The cause of free fall is gravitational pull. Where Acceleration is equal to the gravitational acceleration. According to Newton's Law of Gravitation , two bodies attract each other due to their masses and separation , since earth is a very big body therefore the lit body falls towards the earth . Thus the graph plotted is a straight line.

What is Newton's law of Gravitation?

"The force acting between two bodies is directly proportional to product of masses and inversely proportional to the square of the separation ."

F= G.{m_{1} . m_{2} }/r^{2}.

Hence the only force by which the object is falling is gravitational pull.

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The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s. What is the acceleration of the particle at 3 s?​

Answers

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

[tex]v = \alpha + \beta {t}^{2} [/tex]

How to calculate acceleration

[tex]a = \frac{dv}{dt} \\ v = \alpha + \beta {t}^{2} \\ \frac{dv}{dt} = 0 + 2 \beta t \\ [/tex]

if Time is given as 3s

therefore, Acceleration is

[tex]a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times \beta \times 3 \\ a = 6 \beta [/tex]

Acceleration is

[tex]a = 6 \beta [/tex]

What is acceleration and velocity?

This is the change in velocity with respect to time.

Velocity is a vector quantity that denotes the rate of change of position with respect to time, or a speed with the directional component.

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Which term is used to describe the highest point on a transverse wave?

A. frequency

B. crest

C. trough

D. amplitude

Answers

Answer:

B. Crest

Explanation:

The high point of a transverse wave is a called the crest.

While on the surface of the earth a student has a weight of 450n if she is moved twice as far from the center of the earth then how does the new weight compare to her old?

Answers

Based on the fact that the student is moved twice as far from the center of the earth, her new weight will be 112.5 N.

What is her new weight?

When the student was moved by the same distance from the center of the earth, her weight was halved.

When she was then moved twice as far, her weight was halved again.

This means that her new weight is:

= 450 x 1/2 x 1/2

= 450 x 1/4

= 112.5 N.

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A 430 kg piano is to be slid up a 3.5 m frictionless plank at a constant speed. The plank makes an angle of 30° with the horizontal. Calculate the work done by the person sliding the piano up the plank.

Answers

Answer:

10628.87 1

Explanation:

3)
an electrical heater raises the temperature of a measured
quantity of water. six thousand joules of energy is absorbed
by the water from the heater in 30.0 seconds. what is the
minimum power rating of the heater?
a) 2.00 x10 w
c) 5.00 x10 w
b) 2.00 x10- w
d) 1.80 x 105w

Answers

the answer is a (2.00 x10 w)

what is a super moon?

Answers

When a full Moon occurs at the closest point to Earth during its orbit, it appears larger and brighter, becoming what is commonly known as a 'supermoon'

What do we mean by the diffraction limit of a telescope?.

Answers

Answer:

Diffraction Limit. The angular resolution that a telescope could achieve if it were limited only by the interference of light waves; it is smaller (i.e., better angular resolution) for larger telescopes.

Explanation:

Searched it up

VOTING BRAINLIEST FOR ANYONE WHO ANSWERS RIGHT!!
PLS HELP

Answers

Answer:

B

Explanation:

-1 e so the atomic number should increase so,

B. Np

Which statement describes the movement of water when a cell shrinks and shrivels due to osmosis?

Answers

Answer:

Water went out of the cell because the concentration of water inside the cell was higher than the concentration outside the cell describes the movement of water when a cell shrinks and shrivels due to [ osmosis. Expert answered|emdjay23|Points 175268| Log in for more information.

Explanation:

Water went out of the cell because the concentration of water inside the cell was higher than the concentration outside the cell.

when there is a higher concentration of water inside the cell, water will begin to move out of the cell, eventually creating a hypertonic solution in which the cell shrivels and shrinks.

Applying definitions Samantha ran 90 meters in 35 seconds to catch up with her dog. When she got to him, she played with him for 70 seconds before they walked back in 75 seconds. Did Saman tha travel at constant speed? What was Samantha's average speed?

Answers

No, Saman didn't travel at constant speed

v₁ = 90/35 = 2.57 m/s

v₂ = 0

v₃ = 90/75 = 1.2 m/s

Average speed = total distance/time

Average speed = (90+90)/(35+70+75) = 1 m/s

You catch a 219 g ball moving at 6.1 m/s. If you catch the ball in a time period of
0.138 s what is the magnitude of the average force you must supply to the ball to
stop the ball?
Answer in units of Newtons (N)

Answers

Answer:

The magnitude of the average force to supply to the ball in order to stop the ball is 9.68 N.

Explanation:

Let's think Newton's 2nd Law: F = ma.

We are given the mass of the ball: 219 g ⇒ .219 kg.

We are given the initial velocity, time, and final velocity of the ball ∴ we can solve for acceleration.

We are trying to find the force needed to stop the ball.

Let's find the acceleration of the ball first.

We have the initial velocity of the ball, 6.1 m/s.We have the time it would hypothetically take the ball to stop, .138 s.We have the final velocity of the ball, 0 m/s (since we are trying to stop the ball).

Now, we can plug these known values into this kinematic equation and solve for acceleration, a.

v = v₀ + at 0 = 6.1 + a(.138) -6.1 = .138a a = 44.2029 m/s²

Substitute acceleration and mass into F = ma and solve for the force.

F = (.219)(44.2029) F = 9.68 N

The magnitude of the average force to supply to the ball in order to stop the ball is 9.68 N.

What is the velocity of a wave with a frequency of 200 Hz and a wavelength of 5 m?

Answers

Answer:

5

Explanation:

because you do math and like, yeah

Explore the Sun-Earth-Moon option in the Model Simulation (second option). Explain the conditions necessary for an astronomical apocalypse.

Answers

The conditions necessary for an astronomical apocalypse are the shifting of earth from its orbit and collision of big star with earth.

Conditions necessary for happening of an astronomical apocalypse

The apocalypse event occurs due to climatic, nuclear war, plague or virus, zombie apocalypse or alien invasion but astronomical apocalypse occurs due to the shifting of earth from its orbit and collision of big star with earth.

So we can conclude that the conditions necessary for an astronomical apocalypse are the shifting of earth from its orbit and collision of big star with earth.

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You are riding a bicycle. if you apply a forward force of 172 n, and you and
the bicycle have a combined mass of 51 kg, what will be the forward
acceleration of the bicycle? (assume there is no friction.)
o a. 3.37 m/s2
b. 1.67 m/s2
c. 1.85 m/s2
d. 0.30 m/s2

Answers

Answer: D. 3.37m/s

Explanation:Just qnswerd iit

Savannah was swimming in a river. She swam downstream at a constant velocity for 10.0minutes. She swam 232meters in that time. What was her velocity?

Answers

I think it is 23.2, sorry if I'm wrong

conventionally anti clock wise torque is taken as?

Answers

Answer:

An anti-clockwise movement is taken as a positive and a clockwise moment is taken as a negative.

A 50 kg mass is sitting on a frictionless surface. an unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3 m/s.
a) what is the initial momentum of the mass?
b) what is the final momentum of the mass?
c) what was the force acting on the mass?
d) what was the impulse acting on the mass?

Answers

Answer:

Initial momentum: [tex]0\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

Final momentum: [tex]150\; {\rm kg \cdot m\cdot s^{-1}}[/tex].

Force on the mass (assuming that the force is constant): [tex]75\; {\rm N}[/tex].

Impulse on the mass: [tex]150\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

Explanation:

The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity (a vector) [tex]v[/tex].

The initial momentum of this mass was [tex]0\; {\rm kg \cdot m \cdot s^{-1}}[/tex] since the velocity of this object was initially [tex]0\; {\rm m\cdot s^{-1}}[/tex].

At [tex]v = 3\; {\rm m\cdot s^{-1}}[/tex], the momentum of this mass ([tex]m = 50\; {\rm kg}[/tex]) would be:

[tex]\begin{aligned}p &= m\, v \\ &= 50\; {\rm kg} \times 3\; {\rm m\cdot s^{-1}} \\ &= 150\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}[/tex].

Assume that the external force [tex]F[/tex] on this mass is constant. By Newton's Second Law of motion, the external force on this mass would be equal to the rate of change in the momentum of this mass.

Since the momentum of this mass increased by [tex]\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}[/tex] in [tex]\Delta t = 2\; {\rm s}[/tex], the external force on this mass would be:

[tex]\begin{aligned}F &= \frac{\Delta v}{\Delta t} \\ &= \frac{150\; {\rm kg \cdot m \cdot s^{-1}}}{2\; {\rm s}} \\ &= 75\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 75\; {\rm N}\end{aligned}[/tex].

The impulse of an external force on an object is equal to the change in the momentum of that object. Since the change in momentum of this mass was [tex]\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}[/tex], the corresponding impulse would also be [tex]150\; {\rm kg \cdot m\cdot s^{-1}}[/tex]:

[tex]\begin{aligned}J &= \Delta v \\ &= 150\; {\rm kg \cdot m\cdot s^{-1}} \\ &= 150\; {\rm N \cdot s}\end{aligned}[/tex].

A 1.2-kg mass is oscillating without friction on a spring whose spring constant is 3400 N/m. When the mass's displacement is 7.2 cm, what is its maximum acceleration

Answers

The maximum acceleration of the mass oscillating on the spring whose spring constant is 3400 N/m, is determined as 204 m/s².

Applied force on the spring

The force applied on the spring to cause the mass to displace to the given distance is determined by applying Hooke's law;

F = kx

F = (3400 N/m) x (0.072 m)

F = 244.8 N

Maximum acceleration

The maximum acceleration of the mass is determined from Newton's second law of motion as shown below;

F = ma

a = F/m

a = 244.8 / 1.2

a = 204 m/s²

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Net force of on a vehicle that is accelerating at a rate of one. 5 M/S squared is 1999 N what is the mass of the vehicle to the nearest kilogram

Answers

Well newtons first second law states that F = ma where F is the net force, m is the mass and a is the acceleration.
Since we want to find the mass we can rearrange to make m = F/a.
If we plug in the value we get 1999/1.5 which will give us 1332.666…kg and since we want it to the nearest kilogram we must round it to 1333kg.

Hope this helps

Why are choir concerts better in performance halls than in gymnasiums?

Please Mention the scientific terms.

Reflection, Refraction, Diffraction, Echo, Constructive Interference, Destructive Interference, Doppler Effect and Longitudional Waves.

Answers

Constructive interference in performance halls and the elimination of echoes are reasons why choir concerts better in performance halls than in gymnasiums.

What is constructive interference?

Constructive interference is a phenomenon which occurs when two waves travelling in same direction and which are in phase add up together to produce a wave of greater amplitude.

Constructive interference occurs in performance halls while destructive interference occurs in gymnasiums.

Also in performance halls, echoes are minimized due to the padded walls and the curtains while echoes which disturb choir concerts occur in gymnasiums.

Therefore, choir concerts better in performance halls than in gymnasiums because of constructive interference in performance halls and the elimination of echoes.

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problem: Asteroid Field.​

Answers

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun that did not resolve into a disc in a telescope and was not observed to have characteristics of an active comet such as a tail.

Continuous signals are characterized as . signals that are broken up into binary code are characterized as . an am/fm radio is a good example of technology. a smart phone is a good example of technology.

Answers

Continuous signals are characterized as analog signals that are broken up into binary code are characterized as digital.

An am/fm radio is a good example of analog technology. A smart phone is a good example of digital technology.

What is a Digital technology?

These are devices that generate, store or process data while analog is a continuous signal that represents physical measurements.

The examples of analog and digital technology are mentioned above and is the most appropriate choice.

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Answer:

Analog, Digital, Analog, Digital

Explanation:

edge 2022

The graph represents the relationship between the work done by a student running up a flight of stairs and the time of ascent.

I think the answer is B, I think im wrong.

Answers

Answer:

power

Explanation:

The slope would be  y/x    or   work / time   which is the definition of power

Most stars in the Milky Way's halo are _________. blue or white in color very young very old found inside molecular clouds

Answers

Answer:

Most stars in the Milky Way's halo are very old

very oldThere is no recycling of gas in the halo, so halo stars are quite old.

The requried, "Most stars in the Milky Way's halo are very old."

What is milk way's halo?

The Milky Way halo is a large, spherical region surrounding the disk of the galaxy, and it is believed to be composed primarily of ancient stars that formed early in the history of the galaxy.

Here,

These stars are typically metal-poor, which means they have lower abundances of elements heavier than hydrogen and helium compared to stars in the disk. They are also old, with estimated ages of several billion years or more.

The halo stars are believed to have formed in small, isolated systems that were later accreted by the Milky Way. They are widely dispersed and do not form dense concentrations like those found in the disk or in globular clusters.

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(HELP ASAP! WILL MARK BRAINLIEST) How would you paraphrase: A powerful practical and spiritual relationship between the people and their environment was forged by their dependence upon its resources.

Answers

Answer:

The people's reliance on the environment's resources generated a deep practical and spiritual link between them and it.

Explanation:

1. A 250g bullet is fired with a speed of 300m/s. if it stopped after hitting a target 150m away, (a) what is its initial kinetic energy? (b) What is the magnitude of the force that stopped it? 2. Determine the GPE of a 0.5kg object when it is raised (a.) 0.75m from the floor. (b) What happens to its GPE if we double the height? 3. How high could a 40kg mass be lifted if an energy of 2x10^6 J is used in lifting it?

Answers

Answer:

See below

Explanation:

KE = 1/2 m v ^2

    = 1/2 (250/1000) 300^2   j         the bullet is 250/1000  kg  ( assuming g is grams and not GRAINS - in which bullet weight is usually measured)

force to stop it is the same number

PE = mgh = .5 *9.81  *  .75 =

     doubling height will double PE

2 x 10^6  =  40 * 9.81  *  h      sove for 'h' in meters  

Initial kinetic energy is 11250 J and magnitude of force to stop bullet is 75 N.

The GPE for 0.75m height floor is 3.75J.

The GPE for double of 0.75m height is 7.5J.

The high on which 40 kg mass is lifted is 5000m.

What is kinetic energy?

The kinetic energy of an object is the energy that it possesses due to its motion.

[tex]KE = 1/2 m v ^2[/tex]

      [tex]=1/2 (250/1000) 300^2 J\\= 11250 J[/tex]

Work done,

[tex]W= fs\\\\f=\frac{W}{s}\\\\f=\frac{11250}{150}[/tex]

[tex]f=75 N[/tex]

What is GPE?

Gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity.

PE = mgh

    = .5 *9.81  *  .75

    = 3.75 J

Potential energy when height doubles = 7.5J

What is height to which object lift?

The potential energy is given by

[tex]PE = mgh\\\\h = PE/ mg\\\\h = 2*10^6 J /40*9.8\\\\h = 5000 m[/tex]

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