Answers
By definition, the probability of an event has to be between 0 and 1.
Given that definition the options 1.01, -0.9, -5/6 and 6/5 cannot be the probability of an event.
Related Questions
A manufacturer pays its assembly line workers $11.06 per hour. In addition, workers receive a piece of work rate of $0.34 per unit produced. Write a linear equation for the hourly wages W in terms of the number of units x produced per hour. Linear equation: W = _______ What is the hourly wage for Mike, who produces 17 units in one hour? Mike’s wage = _________
Answers
Let's assume the following variables.
x = number of units produced
It is stated in the problem that for every unit produced, there is an additional wage of $0.34. Hence, on top of $11.06 per hour wage, there will be an additional of $0.34x per hour. In equation, we have wage per hour:
[tex]W=11.06+0.34x[/tex]If Mike was able to produce 17 units, our x here is 17. Let's plug this value to the formula.
[tex]W=11.06+0.34(17)[/tex]Then, solve.
[tex]\begin{gathered} W=11.06+5.78 \\ W=16.84 \end{gathered}[/tex]Therefore, Mike's hourly wage is $16.84.
Use U-Subscription to solve the following polynomial. Compare the imaginary roots to the code breaker guide. Hi this is a project and this is one of the questions, I have the guide so ignore the code piece part.
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We will substitute the variable x with the variable u using the following relation:
[tex]u=x^2[/tex]Then, we can convert the polynomial as:
[tex]4x^4+2x^2-12=4u^2+2u-12[/tex]We can use the quadratic equation to calculate the roots of u:
[tex]\begin{gathered} u=\frac{-2\pm\sqrt[]{2^2-4\cdot4\cdot(-12)}}{2\cdot4} \\ u=\frac{-2\pm\sqrt[]{4+192}}{8} \\ u=\frac{-2\pm\sqrt[]{196}}{8} \\ u=\frac{-2\pm14}{8} \\ u_1=\frac{-2-14}{8}=-\frac{16}{8}=-2 \\ u_2=\frac{-2+14}{8}=\frac{12}{8}=1.5 \end{gathered}[/tex]We have the root for u: u = -2 and u = 1.5.
As u = x², we have two roots of x for each root of u.
For u = -2, we will have two imaginary roots for x:
[tex]\begin{gathered} u=-2 \\ x^2=-2 \\ x=\pm\sqrt[]{-2} \\ x=\pm\sqrt[]{2}\cdot\sqrt[]{-1} \\ x=\pm\sqrt[]{2}i \end{gathered}[/tex]For u = 1.5, we will have two real roots:
[tex]\begin{gathered} u=1.5 \\ x^2=1.5 \\ x=\pm\sqrt[]{1.5} \end{gathered}[/tex]Then, for x, we have two imaginary roots: x = -√2i and x = √2i, and two real roots: x = -√1.5 and x = √1.5.
Answer:
Let u = x²
Equation using u: 4u² + 2u - 12
Solve for u: u = -2 and u = 1.5
Solve for x: x = -√2i, x = √2i, x = -√1.5 and x = √1.5
Imaginary roots: x = -√2i and x = √2i
Real roots: x = -√1.5 and x = √1.5
i need help in this please
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The isosceles right is given in the diagram below
We are to rotate clockwise about point B as the origin
Rotating ABC 180° Clockwisely, we have
Rotating ABC 270° clockwise about B, we have
We now combine the four triangles together in the diagram below
I need some help. Could someone explain it to me?
Answers
Problem
We have the following table given:
x y
0 2
1 6
4 -9
8 8
Solution
We know that the domain correspond to the value of x in the relationship and then the correct answer for this case would be:
2
0
Jusrt 2,9 are the values in the domain of the function
The zookeeper records how many scoops of peanuts she feeds the elephant for several days . Tuesday 21 Wednesday 19 5/8.
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Explanation:
We want to know the difference between the amount of scoops she fed the elephant on Wednesday and on Tuesday:
[tex]21-19\frac{5}{8}[/tex]We can write the second number as an improper fraction:
[tex]21-(19\cdot\frac{8}{8}+\frac{5}{8})=21-(\frac{152}{8}+\frac{5}{8})=21-\frac{157}{8}[/tex]And now substract the two numbers:
[tex]\begin{gathered} 21-\frac{157}{8}=\frac{21\cdot8}{8}-\frac{157}{8} \\ 21-\frac{157}{8}=\frac{168}{8}-\frac{157}{8} \\ 21-\frac{157}{8}=\frac{168-157}{8}=\frac{11}{8} \end{gathered}[/tex]Answer:
She fed the elephant 11/8 scoops of peanuts more on Tuesday than on Wednesday
Hi, can you help me to solve thisexercise, please!!For cach polynomial, LIST all POSSIBLE RATIONAL ROOTS•Find all factors of the leading coefficient andconstant value of polynonnal.•ANY RATIONAL ROOTS =‡ (Constant Factor over Leading Coefficient Factor)6x^3+7x^2-3x-1
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1) We can do this by listing all the factors of -1, and the leading coefficient 6. So, we can write them as a ratio this way:
[tex]\frac{p}{q}=\pm\frac{1}{1,\:2,\:3,\:6}[/tex]Note that p stands for the constant and q the factors of that leading coefficient
2) Now, let's test them by plugging them into the polynomial. If it is a rational root it must yield zero:
[tex]\begin{gathered} 6x^3+7x^2-3x+1=0 \\ 6(\pm1)^3+7(\pm1)^2-3(\pm1)+1=0 \\ 71\ne0,5\ne0 \\ \frac{1}{2},-\frac{1}{2} \\ 6(\pm\frac{1}{2})^3+7(\pm\frac{1}{2})^2-3(\pm\frac{1}{2})+1=0 \\ 2\ne0,\frac{7}{2}\ne0 \\ \\ 6(\pm\frac{1}{3})^3+7(\pm\frac{1}{3})^2-3(\pm\frac{1}{3})+1=0 \\ 1\ne0,\frac{23}{9}\ne0 \\ \frac{1}{6},-\frac{1}{6} \\ 6(\frac{1}{6})^3+7(\frac{1}{6})^2-3(\frac{1}{6})+1=0 \\ \frac{13}{18}\ne0,-\frac{5}{3}\ne0 \end{gathered}[/tex]3) So the possible roots are:
[tex]\pm1,\pm\frac{1}{2},\pm\frac{1}{3},\pm\frac{1}{6}[/tex]But there are no actual rational roots.
Write the sentence as an equation. 136 is equal to 194 times b Type a slash (/) if you want to use a division sign.
Answers
Given the sentence 136 is equal to 194 times b, we are to write this statement as an equation.
Let us take it one after the other.
For 194 times b, this can be written as;
= 194 * b
= 194b .
Since 136 is equal to the exxpression, the final equation will be gotten by simply equationf 136 to 194b as shown;
136 = 194b
You can then re-arrange
194b = 136
Hence the reuired equation is 194b = 136
there are 3 members on a hockey team (including all goalie) at the end of a hockey game each member if the team shakes hands with each member of the opposing team. how many handshakes occur?
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Which statement best reflects the solution(s) of the equation? X/ x-1 - 1/ x-2 = 2x-5/x^2-3x+2 There is only one solution: x=4. The solution x=1 is an extraneous solution. There are two solutions: x=2 and x=3. There is only one solution: x=3. The solution x=2 is an extraneous solution. There is only one solution: x=3. The solution x=1 is an extraneous solution.
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The best reflects solution of the equation is, There is only one solution: x = 3. The solution x = 2 is an extraneous solution.
What is extraneous solution?
An extraneous solution is a root of a converted equation that is not a root of the original equation because it was left out of the original equation's domain is referred to as a superfluous solution.
We are given the following equation,
(x / x - 1) - (1 / x - 2) = (2x - 5)/(x^2 - 3x + 2)
Solving the given equation we have,
(x^2 - 3x + 1) / (x^2 - 3x + 2) = (2x - 5) / (x^2 - 3x + 2)
x^2 - 3x + 1 = 2x - 5
x^2 - 5x + 6 = 0
x^2 - 3x - 2x + 6 = 0
x(x - 3) - 2(x - 3) = 0
(x - 3)(x - 2) = 0
(x - 3) = 0, (x - 2) = 0
x = 3, x = 2
At x = 2 the denominator of the equation will be 0. So solution of the equation is not valid at x = 2.
Therefore, x = 3 is the only one solution. The solution x = 2 is an extraneous solution.
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Let f(x) = 2x² + 14x – 16 and g(x) = x+8. Perform the function operation and then find the domain of the result.(x) = (simplify your answer.)
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We need to find the following division of the functions f(x) and g(x):
[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=\frac{2x^2+14x-16}{x+8}[/tex]We can note that the numerator can be rewritten as
[tex]2x^2+14x-16=2(x^2+7x-8)=2(x+8)(x-1)[/tex]Then the division can be written as:
[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=\frac{2(x+8)(x-1)}{x+8}[/tex]From this result, we can cancel out the term (x+8) from both sides and get,
[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=2(x-1)[/tex]Therefore, the result of the division is:
[tex]\frac{f}{g}(x)=2(x-1)[/tex]which domain is all real numbers:
[tex]x\in(-\infty,\infty)[/tex]could you please help me answer this please and thank you it's about the rectangular prism....
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ANSWER:
[tex]A_T=8+8+20+20+40+40[/tex]STEP-BY-STEP EXPLANATION:
In this case, what we must do is calculate the face area and then add each face, like this:
The area of each area is the product between its length and its width, therefore
[tex]\begin{gathered} A_1=2\cdot4=8 \\ A_2=10\cdot4=40 \\ A_3=10\cdot2=20_{} \\ A_4=10\cdot4=40 \\ A_5=10\cdot2=20_{} \\ A_6=2\cdot4=8 \end{gathered}[/tex]The total area would be the sum of all the areas, if we organize it would be like this:
[tex]A_T=8+8+20+20+40+40[/tex]What is the equation of the following line written in slope-intercept form? Oy=-3/2x-9/2
Oy=-2/3x+9/2
Oy=3/2x-9/2
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The equation of the line in slope-intercept form is: C. y = -3/2x - 9/2
How to Write the Equation of a Line?If we determine the slope value, m, and the y-intercept value of the line, b, we can write the equation of a line in slope-intercept form as y = mx + b by substituting the values.
Slope of a line (m) = change in y / change in x.
y-intercept of a line is the point on the y-axis where the value of x = 0, and the line cuts the y-axis.
Slope of the line in the diagram, m = -3/2
y-intercept of the line, b = -9/2.
Substitute m = -3/2 and b = -9/2 into y = mx + b:
y = -3/2x - 9/2 [equation in slope-intercept form]
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Graphed the dilated image of quadrilateral MNOP using a scale factor of 3 and the origin as the center of dilation
Answers
To dilated the figure by a scale factor 3 and center origin
Multiply the coordinates of each point by 3
The image of the point (x, y) is (3x, 3y)
Knowledge CheckUse the distributive property to remove the parentheses.--7(-5w+x-3)X 5
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The distributive property states that:
[tex]k\cdot\left(a+b+c\right?=k\cdot a+k\cdot b+k\cdot c.[/tex]In this problem, we have the expression:
[tex]-7\cdot(-5w+x-3)=(-7)\cdot(-5w+x-3).[/tex]Comparing this expression with the general expression of the distributive property, we identify:
• k = (-7),
,• a = -5w,
,• b = x,
,• c = -3.
Using the general expression for the distributive property with these values, we have:
[tex]\left(-7\right)\cdot(-5w)+\left(-7\right)\cdot x+\left(-7\right)\cdot(-3).[/tex]Simplifying the last expression, we get:
[tex]35w-7x+21.[/tex]AnswerApplying the distributive property to eliminate the parenthesis we get:
[tex]35w-7x+21[/tex]Hi I need help with this
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On a particular college campus, 22% of the students belong to a fraternity or sorority. If 56 college students are randomly chosen:a. What is the probability that 16 are members of a fraternity or sorority?Round to at least three decimal places.Incorrectb. What is the mean of this distribution? Round to at least one decimal.Incorrectc. What is the standard deviation of this distribution? Round to at least one decimal
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Explanation
Part A
From the question,
[tex]\begin{gathered} p=\frac{22}{100};q=1-\frac{22}{100} \\ p=0.22;q=0.78 \\ Also,n\text{ =56} \end{gathered}[/tex]Using the binomial probability distribution formula;
[tex]undefined[/tex]Identity two angles that are marked congruent to each other on the diagram below.(Diagram is not to scale.)Mthth& congruent toSub Arwwer
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Congruency in this context is a term that describes a pair of angles as being identical.
In our shape, we have a parallelogram and
the marketing department of a company has determined that the profit for selling x units of a product is appropriated by function f(x)= 15× -600
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You have the following function for the profit for selling x units of a product:
f(x) = 15x - 600
in order to determine the profit for 15,600 units, replace x = 15,600 into the previous function and simplify:
f(15,600) = 15(15,600) - 600 = 233,400
Hence, the profit for 15,600 units is $233,400
Explain why m<1>m<3.which statement below can be made, according to the corollary to the Triangle Exterior Angle Theorem?
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In the given image you have that m∠1 is lower than angle m∠3 becasue it is clear that angle ∠1 is an angle greater than 90° and angle ∠3 is lower than 90°. Then m∠1 > m∠3.
Now, in order to determine which of the given statements is true for the given figure, you take into account that the exterioir angle theorem stablishes that the measure of an exterior angle of the triangle is greater that any of the measure of the remote interioir angles of the triangle.
Thus, you can notice that the measure of the external angle ∠1 is greater than the measure either angle ∠4 or angle ∠2.
Hence, following statement is true:
m∠1 > m∠4 and m∠1 > m∠2
solve on a map. 1 inch equals 14.7 miles. if two cities are 3.5 inches apart on the map, how far are they actually apart? (round to a decimal)
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On a map. 1 inch equals 14.7 miles
1 inch = 14.7 miles
Two cities are 3.5 inches apart on the map
Distance between two cities = 3.5 inches
[tex]\begin{gathered} \text{ 1 inch = 14.7 miles} \\ \text{ Then for 3.5 inches in miles : Multiply 3.5}\times14.7\text{ } \\ 3.5\text{ inches=3.5}\times14.7\text{ miles} \\ 3.5\text{ inches=}51.45\text{ miles} \end{gathered}[/tex]So, the distance between two cities is 51.45 miles
Answer : 51.45 miles
g(x)= x^2+3h(x)= 4x-3Find (g-h) (1)
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Given:-
[tex]g(x)=x^2+3,h(x)=4x-3[/tex]To find:-
[tex](g-h)(1)[/tex]At first we find the value of (g-h)(x), so we get,
[tex]\begin{gathered} (g-h)(x)=g(x)-h(x) \\ =x^2+3-(4x-3) \\ =x^2+3-4x+3 \\ =x^2-4x+6 \end{gathered}[/tex]So the value of,
[tex](g-h)(x)=x^2-4x+6[/tex]So the value of (g-h)(1) is,
[tex]\begin{gathered} (g-h)(x)=x^2-4x+6 \\ (g-h)(1)=1^2-4\times1+6 \\ (g-h)(1)=1-4+6 \\ (g-h)(1)=7-4 \\ (g-h)(1)=3 \end{gathered}[/tex]So the required value is,
[tex](g-h)(1)=3[/tex]
How many ones are between 1 and 1,000,000 (inclusive)?
Answers
There are 600,001 ones are between 1 and 1,000,000.
By using the below process we can find the number of ones between 1 and 1,000,000.
The number of times a digit 2 to 9 digit appears in numbers 1 to [tex]10^n = n(10^(^n^-^1^))[/tex].
The number of times the digit 1 appears in numbers in numbers 1 to [tex]10^n = n(10^(^n^-^1^)) + 1[/tex]
Therefore, the number of times a digit 1 appears in numbers 1 to 1,000,000 [tex]= 6(10^(^6^-^1^)) + 1\\= 6(10^5) + 1\\= 600,000 + 1\\= 600,001[/tex]
Therefore, there are 600,001 ones are between 1 and 1,000,000.
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True or False-Choose "A" for true or "B" for false.40. The inverse property of addition states that a number added to its reciprocal equals one.41. The associative properties state that the way in which numbers are grouped does notaffect the answer.42. The identity property of addition states that zero added to any number equals thenumber.43. The distributive property is the shortened name for the distributive property ofmultiplication over addition.44. The commutative property of addition states that two numbers can be added in anyorder and the sum will be the same.45. is the multiplicative inverse of35346. One is the identity element for addition.
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Given
Statements
Find
Correctness of statements
Explanation
40) False (sum of number and its opposite is 0)
41)True
42) True
43) True
44) True
45) True
46) False (One is Identity Element for multiplication)
Final Answer
40) False
41)True
42) True
43) True
44) True
45) True
46) False
Translate this phrase into an algebraic expression.Six less than the product of 13 and Mai's heightUse the variable m to represent Mai's height.
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If m is the Mai's height you can write for the given description:
13m - 6
The previous expression means six less than the product of 13 and Mai's height.
help meeeeeeeeee pleaseee !!!!!
Answers
The values of the functions are determined as:
a. (f + g)(x) = 3x² + 2x
b. (f - g)(x) = -3x² + 2x
c. (f * g)(x) = 6x³
d. (f/g)(x) = 2/3x
How to Determine the Value of a Given Function?To evaluate a given function, substitute the equation for each of the functions given in the expression that needs to be evaluated.
Thus, we are given the following functions as shown above:
f(x) = 2x
g(x) = 3x²
a. To find the value of the function (f + g)(x), add the equations for the functions f(x) and g(x) together:
(f + g)(x) = 2x + 3x²
(f + g)(x) = 3x² + 2x
b. To find the value of the function (f - g)(x), find the difference of the equations of the functions f(x) and g(x):
(f - g)(x) = 2x - 3x²
(f - g)(x) = -3x² + 2x
c. To find the value of the function (f * g)(x), multiply the equations of the functions f(x) and g(x) together:
(f * g)(x) = 2x * 3x²
(f * g)(x) = 6x³
d. To find the value of the function (f/g)(x), find the quotient of the equations of the functions f(x) and g(x):
(f/g)(x) = 2x/3x²
(f/g)(x) = 2/3x.
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May I please get help with this. I have tried multiple times but still could not get the correct or at least accurate answers
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step 1
Find out the value of y
we have that
y+75=180 degrees ------> by same side ineterior angle
PLS HELP WILL ASAP WILL GIVE BRAINLIST
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Answer:
if the bottom side is 4n + 15, then n=8
n times 5 is 40
40+7=47
Step by step
The parallelogram rule says the opposite sides are equal length so our equation is
4n + 15 = 5n + 7
Subtract 5n from both sides to combine variable
4n - 5n + 15 = 5n - 5n + 7
Combine
-n + 15 = 7
Subtract 15 from both sides to solve
-n + 15 -15 = 7 -15
-n = -8
n = 8
Now substitute 8 for n in the KL expression
5n + 7
5(8) + 7
40 + 7 = 47
Side KL is 47 units
what is the density of a 10g box measuring 10 cm by 5 cm by 5 cm
Answers
Answer:1 g/cm^3
Step-by-step explanation:
Ryan's car used 9 gallons to travel 396 miles. How many miles can the car go on one gallon of gas?On the double number line below, fill in the given values, then use multiplication or division to find the missing value.
Answers
Given:
At 9 gallons, it can travel 396 miles.
Find: At one gallon, it can travel ___ miles.
Solution:
First, let's fill in the number line with the information we have.
Then, to find the missing value ?, let's do cross multiplication.
[tex]\begin{gathered} ?\times9=1\times396 \\ ?\times9=396 \end{gathered}[/tex]Then, divide both sides of the equation by 9.
[tex]\begin{gathered} \frac{?\times9}{9}=\frac{396}{9} \\ ?=44 \end{gathered}[/tex]Therefore, on 1 gallon of gas, the car can travel 44 miles.
(A) The lines have different slopes and intersect at one point?(B) The lines have the same slope and y intercept.?(C) The lines are parallel and do not intersect.?(D) The lines have the same slope and y-intercept.?(E) Infinitely many solutions.?(F) They are the same line.? (G) No Solution ? (H) One solution.?
Answers
Recall that if two lines have the same slop then these two lines are parallel to each other.
the y-intercept is an x-coordinate of the point where the line intersects at the y-axis.
Consider graph 1.
The line intersects at one point and has different slopes, hence this has one solution.
(A) and (H) is true for graph 1.
Consider graph 2.
The lines have the same slope, therefore parallel but there is no y-intercept point.
This have infinitely many solutions.
They are also the same line.
(E) and (F) is true for this graph 2.
Consider graph 3.
The lines have the same slope and they are parallel.
It gives B) is correct
They do not intersect since parallel does not intersect each other.
It gives C) is correct
There is no solution since they do not intersect.
It gives G) is correct.
These lines have intercepted at -1 and -4.
It gives D) is correct
B), D), C), G), D) are correct for graph 3.
Results:
Options Graph
A) 1
B) 3
C) 3
D) 3
E) 2
F) 2
G) 3
H) 1