Need this asap will give brainliest

Step-by-step explanation:

This is the equation for a circle in the form :

(x-h)^2 + (y-k)^2  =   r^2     where h,k is the center and r is the radius

center = 5.2,-3.7    and radius = sqrt (49) = 7

The answer choice which belongs in the green box and is the longest side of the triangle as required is; 11.06.

It follows from the task content that since the sum of angles in a triangle is; 180°, the missing angle measure is; 180 - 51 - 109° = 20°.

Consequently, it follows from the sine law that;

4 / sin 20° = x / sin 109°

x = 4 sin 109° / sin 20°

x = 11.06.

Ultimately, the number that belongs in the green box is; 11.06.

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The value of x is 9

To find the value of x for which the rational expression is equal to zero, we need to set the numerator equal to zero:

x - 9 = 0

Solving for x:

x = 9

Therefore, the value of x = 9.

Looking at the denominator (x - 4)(x + 4), we see that it contains two factors: (x - 4) and (x + 4). For the entire expression to equal zero, either the numerator or one of the factors in the denominator must equal zero.

Setting each factor in the denominator equal to zero:

x - 4 = 0 or x + 4 = 0

x = 4 or x = -4

These are the valid values of x for which the rational expression is equal to zero.

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The linear function equation, y = m·x + c, indicates;

6. The growth in the y-values over each unit x-value interval is a difference of m units.

Part I. Please find attached the graph of y = x + 3, created with MS Excel, which shows that the differences between the y-values is 2 units over each x-value interval of 2 units.

a) The difference between the x-values is; k

The difference between the y-values is; m·k

The difference in the y-value is; m·k

Please find attached the completed tables in the following section

The equation of a linear function is; y = m·x + c

Where;

m = The slope of the graph = (y₂ - y₁)/(x₂ - x₁)

(x₁, y₁), and (x₂, y₂), are ordered pair of data on the graph of the linear function

c = The y-intercept of the linear function

(y₂ - y₁)/(x₂ - x₁) = m

(y₂ - y₁) = m × (x₂ - x₁)

Δy = m × Δx

When Δx = 1, we get;

Δy = m

Therefore, the y-value of a linear function increases by m, the slope value, when the x-value increases by 1, which indicates that the linear function grows by equal differences over the same interval of the input value of the function

Part I; Please find a graph of the linear function, y = 1·x + 3, which shows that each equivalent interval of 2 units in the x-axis, produces a difference in the y-value or y-axis of 2 units.

a) Considering the interval p and p + k, let y₁ represent the y-value at p and let y₂ represent the y-value at p + k, we get;

Slope, m = (y₂ - y₁)/((p + k) - p) = (y₂ - y₁)/k  

Therefore;

(y₂ - y₁)/k = m

(y₂ - y₁) = m × k

Therefore, the increase in the y-value, for an increase in the x-value of k is a constant,  m·k =  (y₂ - y₁)

Therefore the difference in the y-value for the specified x-values is a constant m·k

The possible equation in the question obtained from a similar question on the website is; y = -(1/2)·x + 10

The completed tables are;

[tex]\begin{tabular}{ | c | c | c | c | }\cline{1-4}& Interval; p = 2& p+ k = 6&\\ \cline{1-4}x-value & 2 & 6 & 4 \\\cline{1-4}y-value & y = (-1/2)\cdot (2)+10 =9 & y = (-1/2)\cdot (6)+10=\underline{7} & -2 \\\cline{1-4}\end{tabular}[/tex]

[tex]\begin{tabular}{ | c | c | c | c | }\cline{1-4}& Interval; p = 10& p+ k = 14&\\ \cline{1-4}x-value & 10 & 14 & 4 \\\cline{1-4}y-value & y = (-1/2)\cdot (10)+10 =\underline{ 5 }& y = (-1/2)\cdot (14)+10=3 & -2 \\\cline{1-4}\end{tabular}[/tex]

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Answer:

b + 2 < -30

Step-by-step explanation:

But if it needs to be simplified the answer is b < -32

8. Option (A) is correct as line XB is a radius

9. Option (D) is correct as line BD is a tangent line

The radius is the straight line from the center of the circle to the circumference and according to the tangent to a circle theorem, a line is tangent to a circle if and only if the line is perpendicular to the radius drawn to the point of tangency

8. The only option that represents a radius is the line from the center X to the point B on the circle circumference.

9. The line from the point B to the point D is called is a tangent to the circle

Therefore, line XB is a radius and line BD is a tangent line.

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The test statistic and critical value needed to test the claim that the success is independent of the type of treatment are 9.750 and critical value is 6.635.

The expected value for each cell is calculated as follows:

E = row total * column total / grand total

The grand total is 150.

The row totals are 83 and 67.

The column totals are 86 and 64.

The expected values are as follows:

Successful: 60 * 86 / 150 = 36.4

Unsuccessful: 60 * 64 / 150 = 29.6

Surgery treatment

Successful: 67 * 86 / 150 = 49.6

Unsuccessful: 67 * 64 / 150 = 27.4

The test statistic is calculated as 9.750

The critical value is calculated as follows:

α = 0.01

df = (r-1)(c-1) = (2-1)(2-1) = 1

x²(α, df) = 6.635

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The work done in stretching the spring from 10 centimeters to 40 centimeters is 9000 joules.

To determine the work done in stretching the spring from 10 centimeters to 40 centimeters, we need to understand the relationship between force, displacement, and work.

In this case, we are given that a force of 450 newtons stretches the spring by 30 centimeters.

We can use this information to calculate the spring constant (k) using Hooke's Law, which states that the force applied to a spring is directly proportional to the displacement it undergoes.

Hooke's Law: F = kx

Where:

F is the force applied,

k is the spring constant, and

x is the displacement of the spring.

We can rearrange the equation to solve for k:

k = F / x

k = 450 N / 30 cm

k = 15 N/cm

Now that we have the spring constant, we can calculate the work done in stretching the spring from 10 cm to 40 cm using the formula for work:

Work [tex]= (1/2)k(x2^2 - x1^2)[/tex]

Where:

k is the spring constant,

x1 is the initial displacement, and

x2 is the final displacement.

Plugging in the values:

Work [tex]= (1/2)(15 N/cm)(40 cm^2 - 10 cm^2)[/tex]

Work [tex]= (1/2)(15 N/cm)(1200 cm^2)[/tex]

Work [tex]= (1/2)(15 N/cm)(1200 cm^2)[/tex]

Work = 9000 N·cm or 9000 joules (since 1 N·cm = 1 joule)

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Answer:

To find out how many megabytes have been downloaded, we can multiply 287 by 0.144 (which represents 14.4% as a decimal).

The calculation is:

287 x 0.144 = 41.328

Rounded to the nearest tenth, the number of megabytes downloaded is 41.3.

The slope constraint for the zip line is 6 to 8 feet of vertical change for every 100 feet of horizontal change.

So, if the vertical change is 7 feet, the horizontal change must be between 7/6 and 7/8 of a hundred feet, or between 11.67 and 12.5 feet.

For Zip line A, the horizontal distance is 120 feet. So, the vertical change of 7 feet is within the slope constraint.

For Zip line B, the horizontal distance is 140 feet. So, the vertical change of 7 feet is within the slope constraint.

For Zip line C, the horizontal distance is 150 feet. So, the vertical change of 7 feet is within the slope constraint.

Therefore, LaTisha's claim is correct. The vertical change of 7 feet will satisfy the slope constraint for all three locations.

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Miguel has 3 friends and he packed sandwiches for everyone to share equally means that Miguel packed 3 sandwiches for each camper.

If Miguel packed 4 sandwiches, then he would have packed 1 sandwich for each camper:

Number of sandwiches per camper = Total number of sandwiches / Number of campers

There are 4 campers, so plug that into the equation to get:

Number of sandwiches per camper = Total number of sandwiches / 4

Solve for the total number of sandwiches by multiplying both sides of the equation by 4:

Total number of sandwiches = Number of sandwiches per camper × 4

So, the total number of sandwiches is 4 × Number of sandwiches per camper.

Each camper will get 1 sandwich, so plug that into the equation to get:

Total number of sandwiches = 1 × 4

Which means there are a total of 4 sandwiches.

Therefore, Miguel packed 1 sandwich for each camper.

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The statement "Once we give up the full Comprehension Schema, Russell's Paradox is no longer a threat" implies that by leaving out the unrestricted version of the Schema of Comprehension (which gives room for the construction of sets based on any property), one can be able to avoid meeting up Russell's Paradox.

Russell discovered the contradiction that arises when analyzing the collection of sets that lack themselves as components. A contradiction arises due to the paradoxical situation of attempting to ascertain if the set includes itself or not.

By adopting the Subset Schema, which limits the creation of sets based on certain criteria, we can steer clear of the paradox and depart from the comprehensive Comprehension Schema.

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2.63 is the value or quotient of 616/265 using long division.

We have to find the value of 616/265

In the given division the numerator is a dividend and the number in the denominator is a divisor.

616 is the dividend and 265 is the divisor.

When we perform long division the quotient will be 2.63 which is the require value.

       2.63  

____________

265 | 616

-530

______

860

-795

______

650

-530

______

120

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Answer:

First, we need to figure out how many circular rugs can fit in the living room without overlap.

One way to approach this is to find the area of each circular rug (using the formula A = πr^2, where r = 3 feet since the diameter is 6 feet).

A = π(3)^2 = 28.26 square feet

Next, we can find the area of the living room:

A = 12 x 18 = 216 square feet

To figure out how many circular rugs can fit, we can divide the living room area by the rug area:

216/28.26 ≈ 7.64

Since we can't have partial rugs, we need to round down, which means Shannon can fit 7 circular rugs in her living room without overlap.

The total area covered by the circular rugs would be:

7 x 28.26 = 197.82 square feet

Therefore, the closest answer choice to the nearest square foot is A) 170 ft².

Answer:A

Step-by-step explanation:

She can put 2 circles together width wise because 6+6 = 12

She can put 3 circles together length wise because 6+6+6 = 18

So she can put 6 circles in total.

The area of one circle is found with the equation A=πr^2

The diameter is 6ft, so the radius is 3ft, so

A=π*3ft^2

A=28.26ft²

This is the area of one circle. We need to find the area of 6 because 6 can fit in total.

28.26ft² * 6= 169.56 ft²

a. The total length of the painted white line in the javelin throwing arena is approximately 255.984 meters.

b. The total area of grass in the shaded landing area of the javelin throwing arena is approximately 1624.6 square meters.

To find the total length of the painted white line, we need to calculate the length of the two straight segments and the two circular arcs.

a) Total length of the painted white line:

Let's break it down into components:

1. The two straight segments: Each straight segment is 95 meters long, and there are two of them.

Length of straight segments = 2 * 95 = 190 meters

2. The two circular arcs:

The throwing arena is a sector of a circle with a radius of 100 meters. The angle of the sector can be calculated using trigonometry. The angle can be found by taking the inverse cosine of the ratio of the adjacent side (which is the radius minus the throwing line distance) to the hypotenuse (which is the radius).

Angle (in radians) = cos⁻¹((radius - throwing line distance) / radius)

Now, the length of each circular arc can be calculated using the formula for the length of an arc of a circle:

Length of circular arc = radius * angle

Let's calculate the angle first:

Angle (in radians) = cos⁻¹((100 - 5) / 100)

Angle = cos⁻¹(95 / 100)

Angle ≈ 0.32492 radians

Now, we can calculate the length of each circular arc:

Length of each circular arc = 100 * 0.32492 ≈ 32.492 meters

Since there are two circular arcs, the total length of the painted white line is:

Total length = 190 (straight segments) + 2 * 32.492 (circular arcs)

Total length ≈ 255.984 meters

b) Total area of grass in the shaded landing area:

The shaded landing area is the sector of the circle with a radius of 100 meters and the angle we calculated above.

The formula to calculate the area of a sector of a circle is:

Area of sector = (angle / 2π) * π * radius²

Area of the shaded landing area = (0.32492 / (2π)) * π * 100²

Area of the shaded landing area ≈ (0.32492 / 2) * 10000

Area of the shaded landing area ≈ 1624.6 square meters

So, the total area of grass in the shaded landing area is approximately 1624.6 square meters.

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The law of sines indicates that, where the angle of elevation of the Sun is 73°, the length of the shadow of the tree is 20 ft, and the inclination of the tree is 5°, the length of the tree is 51.1 ft. The correct option is therefore;

(C) 51.1 ft.

The law of sines states that the ratio of the length of a side in a triangle to the sine of the angle facing that side is equivalent for the three sides of a triangle.

The length of the shadow = 20 feet

Angle of elevation to the Sun = 73°

The angles formed by the triangle formed by the tree are;

73°, (90 - 5) = 85°, (180 - 85 - 73) = 22°

Let l represent the length of the tree. The law of sines indicates that we get;

20/(sin(22)) = l/sin(73)

Therefore; l = sin(73°) × (20/(sin(22°))) ≈ 51.1 feet

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The value of x for the second triangle if it is the reduction of the first drawing is 6.3 feet.

Given two triangles.

Also given that, the scale drawings given are the reduction of the figure.

Most probably, the second triangle must be formed after a reduction with a scale factor of k.

Let k be the required scale factor.

The value of k can be found by taking the ratio of the corresponding sides.

k = 5.2 / 10.4

  = 0.5

So all the corresponding sides will be half of the first triangle.

x = 0.5 × 12.6

  = 6.3 feet

Hence the value of x is 6.3 feet.

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Answer: The expression can be simplified by combining the fractions with a common denominator:

(x - 9)/(x - 4) + (x^2 - x + 5)/(x - 4)

To add these fractions, we need to find a common denominator, which in this case is (x - 4). Therefore, we can rewrite each fraction with the common denominator:

[(x - 9) + (x^2 - x + 5)] / (x - 4)

Simplifying the numerator:

(x - 9 + x^2 - x + 5) / (x - 4)

Combining like terms:

(x^2 - 2x - 4) / (x - 4)

Hence, the simplified expression is (x^2 - 2x - 4) / (x - 4).

It implies that the collection of all ordered pairs (x, y) formed by taking an element from the set x and an element from the set y is a subset of the set containing all possible subsets of the Cartesian product of sets X and Y.

The expression "y^x ⊂ p(X x Y)" represents a subset relationship between two sets.

Let's break it down:

"y^x" represents the set of all possible ordered pairs (x, y) where x is an element of the set x and y is an element of the set y. This set represents the Cartesian product of the sets x and y.

"⊂" denotes a subset relationship. If we have two sets A and B, A ⊂ B means that every element in A is also an element of B. In other words, A is a subset of B.

"p(X x Y)" represents the power set of the Cartesian product of sets X and Y. The power set of a set is the set of all possible subsets of that set.

Therefore, "y^x ⊂ p(X x Y)" means that the set of all possible ordered pairs (x, y) where x is an element of the set x and y is an element of the set y is a subset of the power set of the Cartesian product of sets X and Y.

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Segments MS and QS are therefore congruent by the definition of bisector. Therefore, the correct answer option is: D. MS and QS.

In Mathematics and Geometry, a perpendicular bisector is a line, segment, or ray that bisects or divides a line segment exactly into two (2) equal halves and forms an angle that has a magnitude of 90 degrees at the point of intersection.

This ultimately implies that, a perpendicular bisector bisects a line segment exactly into two (2) equal halves, in order to form a right angle that has a magnitude of 90 degrees at the point of intersection.

Since line segment NS is a perpendicular bisector of isosceles triangle MNQ, we can logically deduce the following congruent relationships;

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Complete Question:

The proof that ΔMNS ≅ ΔQNS is shown. Given: ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. Prove: ΔMNS ≅ ΔQNS

We know that ΔMNQ is isosceles with base MQ. So, MN ≅ QN by the definition of isosceles triangle. The base angles of the isosceles triangle, ∠NMS and ∠NQS, are congruent by the isosceles triangle theorem. It is also given that NR and MQ bisect each other at S. Segments _____ are therefore congruent by the definition of bisector. Thus, ΔMNS ≅ ΔQNS by SAS.

NS and NS

NS and RS

MS and RS

MS and QS

The measure of angle C is 13°.

To find the measure of angle C in the given circle, we need to use the properties of angles subtended by arcs in a circle.

Given information:

m∠J = 88° (angle J)

mArc DF = 62° (arc DF)

mArc BD = 136° (arc BD)

We can start by using the fact that the measure of an angle formed by a chord and an arc is equal to half the measure of the intercepted arc.

Since mArc DF = 62°, the measure of angle DJF (angle formed by chord DF and arc DF) is 62°/2 = 31°.

Next, we can use the fact that angles subtended by the same arc are equal.

Since mArc BD = 136°, angle BJD (angle formed by chord BD and arc BD) is also 136°.

Now, let's find angle BCD (angle formed by chord BD and chord CD). The sum of angles in a triangle is 180°, so angle BCD = 180° - angle DJF - angle BJD.

Angle BCD = 180° - 31° - 136°

Angle BCD = 180° - 167°

Angle BCD = 13°

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Using binomial probability, the probability is 0.8897

Using binomial probability formula, we can determine the number of defective batteries

In this case, n = 1,200 (the sample size) and p = 0.006 (the probability of finding a defective battery).

We want to find the probability of finding 5 or fewer defective batteries, which is equivalent to finding the cumulative probability up to 5.

Let's calculate this probability:

P(X ≤ 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

Using the binomial probability formula:

[tex]P(X = k) = C(n, k) * p^k * (1 - p)^(^n ^- ^k^)[/tex]

where C(n, k) represents the number of combinations of n items taken k at a time.

Plugging the values and solving;

P(X ≤ 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) =

[tex]C(1200, 0) * 0.006^0 * (1 - 0.006)^(^1^2^0^0 ^- ^0^)\\+ C(1200, 1) * 0.006^1 * (1 - 0.006)^(^1^2^0^0 ^- ^1^)\\+ C(1200, 2) * 0.006^2 * (1 - 0.006)^(1^2^0^0 ^- ^2^)\\+ C(1200, 3) * 0.006^3 * (1 - 0.006)^(^1^2^0^0 ^- ^3)\\+ C(1200, 4) * 0.006^4 * (1 - 0.006)^(^1^2^0^0 ^- ^4)\\+ C(1200, 5) * 0.006^5 * (1 - 0.006)^(^1^2^0^0 ^- ^5^)[/tex]

To calculate these probabilities, we need to use a combination formula to determine the number of combinations. The combination formula is given by:

C(n, k) = n! / (k! * (n - k)!)

Now let's calculate the probability:

[tex]P(X \leq 5) = \\C(1200, 0) * 0.006^0 * (1 - 0.006)^(^1^2^0^0 ^- ^0^)\\+ C(1200, 1) * 0.006^1 * (1 - 0.006)^(^1^2^0^0 ^- ^1^)\\+ C(1200, 2) * 0.006^2 * (1 - 0.006)^(^1^2^0^0 ^- ^2^)\\+ C(1200, 3) * 0.006^3 * (1 - 0.006)^(^1^2^0^0 ^- ^3^)\\+ C(1200, 4) * 0.006^4 * (1 - 0.006)^(^1^2^0^0 ^- ^4^)\\+ C(1200, 5) * 0.006^5 * (1 - 0.006)^(^1^2^0^0 ^- ^5^)[/tex]

Using a calculator or statistical software to perform the calculations, we find that the probability is approximately 0.8897 when rounded to four decimal places

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[tex]\tan(y )=\cfrac{\stackrel{opposite}{6}}{\underset{adjacent}{4}} \implies \tan( y )= \cfrac{3}{2} \implies \tan^{-1}(~~\tan( y )~~) =\tan^{-1}\left( \cfrac{3}{2} \right) \\\\\\ y =\tan^{-1}\left( \cfrac{3}{2} \right)\implies y \approx 56.31^o \\\\[-0.35em] ~\dotfill\\\\ \tan(x )=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{6}} \implies \tan( x )= \cfrac{2}{3} \implies \tan^{-1}(~~\tan( x )~~) =\tan^{-1}\left( \cfrac{2}{3} \right) \\\\\\ x =\tan^{-1}\left( \cfrac{2}{3} \right)\implies x \approx 33.69^o[/tex]

Make sure your calculator is in Degree mode.

Derek is saving money for the down payment on a used car. So far, he has saved $200. His parents have said they help him put aside money, they will pay him 6% interest each month on the money Derek has saved. It will take Derek approximately 28 months to save at least $1,000 for the down payment on the used car if the only additions to his savings account are his parents' interest payments.

Month Process

0 Derek saves $200 (initial savings)

1 Derek receives 6% interest on $200 (interest = $200 * 0.06 = $12), total savings = $200 + $12 = $212

2 Derek receives 6% interest on $212 (interest = $212 * 0.06 = $12.72), total savings = $212 + $12.72 = $224.72

3 Derek receives 6% interest on $224.72 (interest = $224.72 * 0.06 = $13.48), total savings = $224.72 + $13.48 = $238.20

4 Derek receives 6% interest on $238.20 (interest = $238.20 * 0.06 = $14.29), total savings = $238.20 + $14.29 = $252.49

5 Derek receives 6% interest on $252.49 (interest = $252.49 * 0.06 = $15.15), total savings = $252.49 + $15.15 = $267.64

6 Derek receives 6% interest on $267.64 (interest = $267.64 * 0.06 = $16.06), total savings = $267.64 + $16.06 = $283.70

It will take Derek approximately 28 months to save at least $1,000 for the down payment on the used car if the only additions to his savings account are his parents' interest payments.

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Answer: 0.07

Step-by-step explanation:

To find the relative frequency of people in the sample whose place of residence is suburban and whose highest degree is a two-year degree, we need to calculate the ratio of the number of people with those characteristics to the total sample size.

Looking at the contingency table, we can see that the number of people in the suburban category with a two-year degree is 21.

The total sample size is given as 311.

Therefore, the relative frequency can be calculated as:

Relative frequency = (Number of people in suburban category with two-year degree) / (Total sample size)

= 21 / 311

≈ 0.0676

Rounded to two decimal places, the relative frequency is approximately 0.07.

The solution after resolving into factors are,

⇒ 8 (a - 3b) (a - b)

We have to given that,

Resolve into factors the expression,

⇒ (3a - 5b)² - (a + b)²

Now, We can simplify for resolving the factors as,

⇒ (3a - 5b)² - (a + b)²

Since, WE know that,

⇒ x² - y² = (x - y) (x + y)

Hence,

⇒ (3a - 5b)² - (a + b)²

⇒ [(3a - 5b) - (a + b)] [ (3a - 5b) + (a + b)]

⇒ [3a - 5b - a - b] [4a - 4b]

⇒ (2a - 6b) (4a - 4b)

⇒ 2 (a - 3b) × 4 (a - b)

⇒ 8 (a - 3b) (a - b)

Thus, The solution after resolving into factors are,

⇒ 8 (a - 3b) (a - b)

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The pine cone is 20 feet above the ground after about 1.58 seconds.

To solve the equation h = -16t² + 60 for t, we can rearrange the equation as follows:

-16t² + 60 = h

Subtract 60 from both sides:

-16t² = h - 60

Divide both sides by -16:

t² = (h - 60) / -16

Take the square root of both sides:

t = ±√((h - 60) / -16)

Since time cannot be negative in this context, we can ignore the negative square root:

t = √((h - 60) / -16)

We are given that the pine cone is 20 feet above the ground, so we substitute h = 20 into the equation:

t = √((20 - 60) / -16)

Simplifying:

t = √(-40 / -16) = √(2.5)

t = 1.58 seconds

Therefore, the pine cone is 20 feet above the ground after about 1.58 seconds.

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The correct formula for finding the break-even point is option C:

Break even point = (0.01)(#of points)(P)/monthly savings.

In this formula, the break-even point is calculated by multiplying the number of points (#of points), the price per unit (P), and a factor of 0.01, then dividing it by the monthly savings.

It's important to note that the break-even point is the level of sales or production at which total costs and total revenue are equal, resulting in neither profit nor loss. The formula above provides a way to determine the break-even point by considering the relevant variables.

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Answer:

  y < 2x +6

Step-by-step explanation:

You want an inequality for the given graph.

Here are some steps you can follow, in no particular order.

When you have this information, you can write the inequality in slope-intercept form.

When the boundary line is dashed, the inequality symbol you use will not include the "or equal to" case. It will be one of < or >.

When the shading is below the line, the values of y that satisfy the inequality will be less than (<) those on the boundary line. If shading is above, the y-values will be greater than (>) those on the line.

The slope and intercept go into the inequality like this:

  y < mx + b . . . . . . where m is the slope, and b is the y-intercept

For a dashed line, shaded below, with m=2 and b=6, the inequality is ...

  y < 2x +6

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Additional comment

There are two points identified on the boundary line: (-2, 2) and (0, 6). The slope formula can be used to find the slope:

  m = (y2 -y1)/(x2 -x1)

  m = (6 -2)/(0 -(-2)) = 4/2 = 2

The point (0, 6) on the y-axis is the y-intercept. The y-value there is 6.

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