The property illustrated ca be classified as the transitive property of equality
Transitive property of equalityEquation are expressions separated by an equal sign. For transitive property, if two system of equation are equal, and the first is equal to the second, then they 2nd is equal to the third, they are transitive.
According to the transitive property of equality, two quantities that are equal to the same thing are equal to each other. For instance If x = 10 and 10 = y, then x = y.
Given that g = 3h and 3h = 16, then g = 16, then the property illustrated ca be classified as the transitive property of equality
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Let q = a / b and r = c / d be two rational numbers written in lowest terms. Let s = q + r and s = e / f be written in lowest terms. Assume that is not 0. Prove or disprove the following two statements. A.) If b and d are odd, then f is odd. B.) If b and d are even, then f is even.
Both the statements are true.
q = a/b and r = c/d.s = q + rs = a/b + c/ds = (ad + bc)/bde/f = (ad + bc)/bde = ad + bc and f = bda) If b and d are odd, we know that the product of two odd numbers is always odd, so f = b*d is odd.We can prove this because b*d = b*(d-1+1)b*(d-1+1) = b*(d-1) + bSince d is odd, d-1 is even, and therefore b*(d-1) is even. Since b is odd and the sum of an odd number and an even number is always odd, the above product is odd.b) If b and d are even, we know that the product of two even numbers is even, and therefore f = b*d is even.To learn more about numbers, visit :
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Please answer question 1 in the picture, I will mark brainliest
Answer:
B,
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
what is the ordered pair for -5, 6
The ordered pair for -5, 6 is (-5, 6)
How to determine the ordered pair for -5, 6?The expression is given as:
-5, 6
Ordered pairs are often represented by the parenthesis i.e. ( , )
Where the variables x and y are in the parenthesis
So, the proper representation of an ordered pair is
(x, y)
Substitute -5, 6 for x and y in (x, y)
(-5, 6)
Hence, the ordered pair for -5, 6 is (-5, 6)
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A 100-gallon fish tank fills at a rate of x gallons per minute. The tank has already been filling for 5 minutes. The
function f(x)-- 5 represents the remaining time in minutes needed to fill the tank. How is the graph of the pare
100
-
X
function f(x)-
-
100
transformed to create the graph of the function f(x)-- X
-5?
The function f(x)-- 5 represents the remaining time in minutes needed to fill the tank in the graph of the pare
Answer:
- Vertically stretching the parent function [tex]f(x) = \frac{1}{x}[/tex] .- A 5 unit right shift of the parent function [tex]f(x) = \frac{100}{x-5}[/tex] .Here are some function transformations:
1. The function is moved up by "k" units if [tex]f(x) + k[/tex].
2. The function is moved down "k" units if [tex]f(x) - k[/tex].
3. The function is moved "k" units to the right if [tex]f(x) - k\\[/tex] .
4. If [tex]f(x) + k[/tex], the function is "k" units to the left.
5. If [tex]bf(x)[/tex] and b>1, the function is b times more vertically stretched.
6. In the event that [tex]bf(x)[/tex] and 0<b<1 the function is vertically compressed by a factor of "b".
The following parent function is provided by the question:
[tex]f(x) = \frac{1}{x}[/tex] .We also know that the transformed function, which denotes the number of minutes still required to fill the tank, is:
[tex]f(x) = \frac{100}{x-5}[/tex] .Therefore, based on the transformations previously described, we can determine that the following produces the graph of the transformed function:
Answer:
- Vertically stretching the parent function [tex]f(x) = \frac{1}{x}[/tex] .- A 5 unit right shift of the parent function [tex]f(x) = \frac{100}{x-5}[/tex] .To learn more about graph please click on the link:
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The complete exercise is: " A 100 gallon fish tank fills at a rate of x gallons per minute. The tank has already been filling for 5 minutes. The function [tex]f(x) = \frac{100}{x-5}[/tex] represents the remaining time in minutes needed to fill the tank. How is the graph of the parent function [tex]f(x) = \frac{1}{x}[/tex] transformed to create the graph of [tex]f(x) = \frac{100}{x-5}[/tex] ?"
What happens to matter when it is an closed system.
Answer:
In thermodynamics, a closed system can exchange energy (as heat or work) but not matter, with its surroundings. An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.
Sherman has 3 cats and 2 dogs. He wants to buy a toy for eeach of his pets. Sherman has $22 dollars to spend on pet toys. How much can he spend on each pet? Write your answer as a fraction and as amount in dollars and cents.
Answer:
22/5
4 2/5
$4.40
Step-by-step explanation:
Answer:
4 4/10
Step-by-step explanation:
He has 5 pets in all (3 cats, 2 dogs)
Divide 22 with 5
22/5 = 4.4
He can spend $4.40, or in fraction form:
4 4/10 (Mixed fraction)
The variables x and y vary inversely. Use the given values to write an equation relating x and y. Then find y when x=3.
x=5, y=-4
an equation is y=___
When x=3, y=___
Show work
The equation is y = ₋20/x and when x = 3 then y = ₋ 6.6 .
Given x and y vary inversely.
The relationships between variables that are expressed as y = k/x, where x and y are two variables and k is a constant value, are known as inverse variation. According to this statement, if the value of one item rises, the value of the other quantity falls.
the value of x is = 3, we need to find the value of y.
then when x = 5 and y = ₋4
If y varies inversely as x then:
x × y = k (for some constant c)
If (x,y) = (5,₋4) then:
5 × ₋4 = k
₋20 = k
Therefore, xy = ₋20
then, y = ₋20/x ; is the equation of y.
when x = 3, then:
y = ₋20/3 or y = 6.6
Hence we get the required equation of y and the value of when x = 3 as y=₋20/x and y = ₋20/3 or y = 6.6
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8. The road transport company of Maldivies keep MVR 950 aside as a wage per day for the hired labourers. The company initially hires 10 laboures. Find out the income of each labourer.
The income of each laborer is MVR 95.
The total amount of money kept aside by the road transport company of Maldives is MVR 950.
Initial hiring of the laborer is 10.
Here we have to have to income of each laborer.
So, Income of each laborer = total income/number of laborer
= 950/ 10
= 95
Therefore the income of each laborer is MVR95.
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Anyone please solve for me
Answer:
A
Step-by-step explanation:
Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an (x, y) point. y ==2x² - 24r – 56
The solution of the given equation y ==2x² - 24r – 56 :
(6 , -128)
What is graphing technology?Graph technology aids in the discovery of unknown links in data that cannot be detected or examined using traditional methods. When the broad term graph is introduced as both a topic, it frequently blurs three distinct topics: graph theory, graph analytics, and graph data management.
Why is graphing useful?Graphs and charts are useful visual tools because they deliver information quickly and readily. It is hardly surprising, then, that graphs are widely utilized in print and electronic media. Data can be easier understood when displayed as a graph rather than a table since the graph can illustrate a pattern or comparison.
According to the given equation:y =2x² - 24x – 56
Solving for :
Parabola equation in polynomial form
ax² + bx + c for x = -b/(2a)
a = 2
b = -24
c = -56.
on solving we get
= -(- 24)/2* 2
= 6
The value of x = 6
putting the value of x to get y:
2x² - 24x – 56
2(6)² - 24(6) – 56
-128
the value of y = -128.
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A pollster would like to predict the mayoralty winner of a certain town. However, his budget for a quick survey is good only for 30 out of the 110 barangays of that town. Which statistics is more appropriate to use – descriptive or inferential? Justify your answer.
Inferential statistics are a better way to interpret the data.
Inferential statistics are regularly used to evaluate the variations among the remedy corporations. Inferential records use measurements from the pattern of topics within side the test to evaluate the remedy corporations and make generalizations approximately the bigger populace of topics.
There are many sorts of inferential records and every is suitable for a selected studies layout and pattern characteristics. Researchers must seek advice from the numerous texts on experimental layout and records to discover the proper statistical take a look at for his or her test. However, maximum inferential records are primarily based totally at the precept that a take a look at-statistic cost is calculated on the premise of a specific formula. That cost together with the levels of freedom, a degree associated with the pattern size, and the rejection standards are used to decide whether or not variations exist among the remedy corporations. The large the pattern size, the much more likely a statistic is to suggest that variations exist among the remedy corporations.
Therefore, we get that inferential statistics are a better way to interpret the data.
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Not sure how to solve this problem
Answer:
98
Step-by-step explanation:
For every 1 true or false question, there are 2 answers
so that means, it would mean you could do
7 x 7 = 49
then do 49 x 2 =
98
the reason you would do this is that you want to find all the possible answers chances.
- 4/7 + 2/7x - 14 + 4/7
Answer: 2x/7 -14
Step-by-step explanation:
- 4/7 + 2/7x - 14 + 4/7=
2/7x - 14 + 4/7 - 4/7=
2/7x - 14 = 2x/7 - 14
Which is the equation of a hyperbola centered at the origin with focus (-3,0) and vertex (-2,0)
Main answer:[tex]x^{2}[/tex]/4 - [tex]y^{2}[/tex]/5=1
Definition of Hyperbola=a symmetrical open curve formed by the intersection of a circular cone with a plane at a smaller angle with its axis than the side of the cone.
Formula=[tex](x-x1)^{2}[/tex]/[tex]a^{2}[/tex] - [tex](y-y1)^{2}[/tex]/[tex]b^{2}[/tex]=1
Given,
origin o(0,0) , focus s(-3,0) , vertex v(-2,0)
and , x1=0, y1=0
then, equation of hyperbola becomes= [tex]x^{2}[/tex]/[tex]a^{2}[/tex]-[tex]y^{2}[/tex]/[tex]b^{2}[/tex]=1
a is the distance between center and the vertex,
distance between o and v = 2
c is the distance between center and the focus,
distance between o and s =3
[tex]a^{2}[/tex]+[tex]b^{2}[/tex]=[tex]c^{2}[/tex]
4+[tex]b^{2}[/tex]=9
[tex]b^{2}[/tex]=5
Then the equation of hyperbola becomes=[tex]x^{2}[/tex]/4 -[tex]y{2}[/tex]/5=1
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Evaluate [tex]8^{10/}[/tex][tex]8^{2}[/tex] using the quotient of exponents property.
Answer:
16777216
Step-by-step explanation:
1) [tex]\frac{8^{10} }{8^2} = 8^{10-2}[/tex]
2) [tex]8^{10-2} = 8^8[/tex]
3) [tex]8^8[/tex] = 16777216
The difference between two positive numbers is 40 and the ratio of these integers is 1:3.Find the integers.
Answer:
A:B= 1:3
let A=1x,B=3x
A+B = x+3x
x+3x = 40
4x = 40
x=10
A=1(10)=10
B=3(10)=30
Step-by-step explanation:
Dont really know how to explain it well
HELP PLEASE PLEASE HELP SHOW WORK HELP PLS PLS PLS
Answer:
A = 8x, B = -a^2-2a-2
Step-by-step explanation:
own to place into her scrapbook. What is the area of each picture?
3 in.
5 in.
3 in.
Answer:
Step-by-step explanation:
3x5=15x3=45
Multiply
(2/5)(-5/4)
Enter your answer as a fraction, in simplest form, in the box.
Answer:
-1/2
Step-by-step explanation:
first, we multiply 2 and -5 which is -10, then we multiply 5 and 4 which is 20
so, we get -10/20 then the simplest form is -1/2
MARK ME BRAINLIEST IF IT HELPED :)
Polygon EFGH is a scaled copy of polygon ABCD.
Select ALL of the true statements.
(Select all that apply.)
The area of EFGH is twice the area of ABCD.
Segment FG is twice as long as segment CD.
Segment EF is twice as long as segment AB.
The scale factor from EFGH to ABCD is 2.
The length of segment AD is 8 units.
The following statements are true and correct:
Segment EF is twice as long as segment AB
The length of segment AD is 8 units
How to interpret dilation transformation?
Since quadrilateral ABCD is scaled to form quadrilateral EFGH, both are similar polygon.
Now, it is known that;
scale factor = ratio of any of their corresponding side
Thus;
Scale factor = GH/CD = 12/6 = 2
This means quadrilateral EFGH is twice the size of quadrilateral ABCD.
The shape of the original polygon remains the same while the size increases.
This implies that, all segments of quadrilateral ABCD increases proportionally times 2 to give us corresponding lengths of the segments of quadrilateral EFGH.
Since shape remains the same, their corresponding angles are congruent and the same in measure.
Therefore, the following statements are true and correct:
Segment EF is twice as long as segment AB; because (EF = AB*scale factor = 3*2 = 6)
The length of segment AD is 8 units because (EH = AD*scale factor = 8*2 = 16)
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PLEASE HELP WILL GIVE BRAINLIEST
Answer:
1302 for the first
-194 for second
Step-by-step explanation:
just do the operation
Hannah took a taxi from her house to the airport. The taxi company charged a pick-up fee of $1.90 plus $3.75 per mile. The total fare was $80.65, not including the tip. Write and solve an equation which can be used to determine mm, the number of miles in the taxi ride.
Answer: y=3.75x+1.9
Step-by-step explanation: the pick up fee would be the y-intercept and the per mile cost would be the slope.
The equation that can be used to determine the number of miles in the taxi ride is 1.90 + 3.75x = 80.65.
The number of miles traveled is 21 miles.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
We have,
Pick up fee charges = $1.90
Charges per mile = $3.75
Total fare = $80.65
The number of miles traveled = x
We can write an equation as:
1.90 + 3.75x = 80.65
The number of miles traveled:
1.90 + 3.75x = 80.65
Subtract 1.90 on both sides.
1.90 + 3.75x - 1.90 = 80.65 - 1.90
3.75x = 78.75
Divide both sides by 3.75.
x = 21.
Thus,
The equation that can be used to determine the number of miles in the taxi ride is 1.90 + 3.75x = 80.65.
The number of miles traveled is 21 miles.
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does anyone know how to solve this pre cal question Im super confused
Answer:
f(-3) = 3*-3 + 4 = -9 + 4 = -5
f(3) = 2*3 - 2 = 6 - 2 = 4
f(0) = 2*0 - 2 = 0 - 2 = -2
12. A summer soccer camp ordered a total of 84 soccer balls and t-shirts for the season. Soccer balls cost $25 each and t-shirts cost $9.50 each. If they payed $1,046 total for the purchase, how many of each item was ordered?
Answer:
16 Soccer balls
68 T-shirts
Step-by-step explanation:
Given information:
Total order = 84 itemsCost of a soccer ball = $25Cost of a t-shirt = $9.50Total bill = $1,046Define the variables:
Let x = the number of soccer balls ordered.Let y = the number of t-shirts ordered.Create two equations from the given information:
[tex]\textsf{Equation 1}: \quad x + y = 84[/tex]
[tex]\textsf{Equation 2}: \quad 25x+9.5y=1046[/tex]
Rewrite Equation 1 to make y the subject:
[tex]\implies y=84-x[/tex]
Substitute this into Equation 2 and solve for x:
[tex]\implies 25x+9.5(84-x)=1046[/tex]
[tex]\implies 25x+798-9.5x=1046[/tex]
[tex]\implies 15.5x+798=1046[/tex]
[tex]\implies 15.5x=248[/tex]
[tex]\implies x=16[/tex]
Substitute the found value of x into the rewritten form of Equation 1 and solve for y:
[tex]\implies y=84-16[/tex]
[tex]\implies y=68[/tex]
Solution
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Find the inverse of the linear function
Answer:
D [tex]y = - \frac{1}{4} x - \frac{1}{4} [/tex]
Step-by-step explanation:
See attached image for explanationIf T is the midpoint of SU what are ST, TU, and SU?
Answer:
Step-by-step explanation:
ST=SU
5x=3x+32
5x-3x=32
2x=32
x=32/2=16
ST=5×16=80
TU=80
SU=2×80=160
Select the expression that are equivalent to -3(g+2)
Answer:
Step-by-step explanation:
-3g-6
In a 40 hour work week marcie spends 15 hours answering phones what is the ratio of hours spent answering telephones to hours doing other types of work?
Out of 40 hours that Marcie works, 15 of those hours are spent answering phones. The problem asks that the hours spent answering telephones goes first in the ratio, so that will be the first number.
15 :
The last number is the total number of hours Marcie works.
15 : 40
A state park has an area of 112 acres. The table shows the estimated park populations for several animals. Find the population density in animals per acre for each animal?
Animal-Population
otter-35
raccoon-186
fox-9
bobcat-3
The population density of otter, raccoon, fox and bobcat is 0.3125, 1.66, 0.0803 and 0.0267 per acre
Total park area of the state park = 112 acres
Number of Otter = 35
Number of Raccoon = 186
Number of Fox = 9
Number of Bobcat = 3
The formula of population density is given by:
Population Density = Number of animals/Area of land
Population density of Otter in the park = 35/112 = 0.3125 Otter per acre
Population density of raccoon in the park = 186/112 = 1.66 Raccoon per acre
Population density of fox in the park = 9/112 = 0.0803 Fox per acre
Population density of bobcat in the park= 3/112 = 0.0267 bobcat per acre
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5/6 divided by 3/5 =
A. 18/25
B. -25/18
C. 25/18
D. -18/25
Answer:
5/6*5/3
25/18
so the answer is 25/18