N2 + H2 -> NH3
How many moles of H2 gas are used to make 36.5 grams of NH3?

55.03 moles of KCI are produced when 6743 grams of [tex]KClO_{3}[/tex] decomposes

To determine the number of moles of KCl produced when 6743 grams of [tex]KClO_{3}[/tex] decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of [tex]KClO_{3}[/tex]

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of [tex]KClO_{3}[/tex] is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of [tex]KClO_{3}[/tex]:

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2[tex]KClO_{3}[/tex] -> 2 KCl + 3 O2,

we can see that for every 2 moles of [tex]KClO_{3}[/tex], we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of [tex]KClO_{3}[/tex] since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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If you're attempting to synthesize 2 benzyl pentanoic acid from acetoacetic ester, keep in mind that you can do so fairly quickly by following these simplified instructions:

From its pungent free scent to its solid state at temperatures ranging from 118 120°C, acetoacetic ester (better known as ethyl acetoacetate) offers significant value for those working within organic synthesis.

As one of many potent ketones utilized by researchers around the globe its unique properties make it ideal for building complex molecules essential for modern medicine and more.

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Approximately 1.167 grams of the 25% (m/m) NaCl solution would contain 0.250 moles of sodium chloride.

To determine the mass of a 25% (m/m) sodium chloride (NaCl) solution containing 0.250 moles of sodium chloride, we need to consider the concentration and molar mass of NaCl.

The percentage (m/m) concentration indicates the mass of solute (NaCl) present per 100 grams of the solution. Therefore, a 25% (m/m) NaCl solution contains 25 grams of NaCl per 100 grams of the solution.

First, we calculate the mass of NaCl in the given solution:

Mass of NaCl = (25% / 100%) x Mass of solution

= (25 / 100) x Mass of solution

Next, we can determine the mass of the solution required to have 0.250 moles of NaCl using the molar mass of NaCl, which is approximately 58.44 g/mol.

Mass of NaCl = Moles x Molar mass

Mass of solution x (25 / 100) = 0.250 moles x 58.44 g/mol

Now, we can solve for the mass of the solution:

Mass of solution = (0.250 moles x 58.44 g/mol) / (25 / 100)

= 1.167 g

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To calculate the entropy (ΔS), enthalpy (ΔH), and free energy change (ΔG) for the reaction under standard conditions, we can use the given values:

ΔH = ΣH(products) - ΣH(reactants)

= (-74.8 kJ/mol + 0 kJ/mol) - (-487.0 kJ/mol)

= 412.2 kJ/mol

ΔS = ΣS(products) - ΣS(reactants)

= (213.6 J/(mol K) + 0 J/(mol K)) - (159.8 J/(mol K))

= 53.8 J/(mol K)

ΔG = ΔH - TΔS

= 412.2 kJ/mol - (298 K) * (53.8 J/(mol K) / (1000 J/kJ))

= 412.2 kJ/mol - 16.0 kJ/mol

= 396.2 kJ/mol

Therefore, under standard conditions, the values for the reaction are:

ΔH = 412.2 kJ/mol

ΔS = 53.8 J/(mol K)

ΔG = 396.2 kJ/mol

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Answer:

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Explanation:

Potassium has 4 energy levels and 1 valence electron.

The periodic table can tell you the number of valence electrons and the number of energy levels an atom has. The group number tells the number of valence electrons, while the period number tells the number of energy levels.

Answer:

limiting reagent is 02

mass of CO2 is 11g

Explanation:

the limiting reagent is the reagent which is consumed completely

no of mole of CH2 = m in g / molar mass

= 46.0/(12+2)

= 3.285 moles.

no of mole of O2 = 32/32

= 1 mole

from the reaction

1 mole of CH2 ==> 2 mol of O2

3.285 mol ==> 1/2 mol

3.285 mol ==> 0.5 mol

:. since O2 has the lowest mol , it's the limiting reagent

the limiting reagent mol will be used to find the no of mole of CH2

2 mol of O2==> 1 mol of CO2

0.5 mol ==> 0.5/2

0.25 mole of CO2

mass = 0.25 * ( 12+32)

= 11g

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The empirical mass of the compound, given that the molecular formula of the compound is N₂O₂, is 60 g/mol

First, we must understand here that empirical mass of a compound is simply the molar mass of the compound.

This means that if we obtain the molar mass of a compound, then we have equally obtain the empirical mass of the compound.

Now, we shall obtain the molar mass of the compound. Details below:

Molar mass of N₂O₂ = (14 × 2) + (16 × 2)

Molar mass of N₂O₂ = 28 + 32

Molar mass of N₂O₂ = 60 g/mol

From the above, the molar mass of the compound is 60 g/mol

Thus, we can conclude that the empirical mass of the compound is 60 g/mol

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Answer:

As the temperature of water increases, the speed of sound waves traveling through it also increases. Therefore, if the water temperature increases from 0°C to 20°C, the speed of the sound wave traveling through it will increase.

The speed of a sound wave in water will increase if the water's temperature increases from 0°C to 20°C due to increased particle collisions resulting from higher kinetic energy.

The best statement that describes how the speed of a wave will change if the water temperature increases from 0°C to 20°C is - The wave speed will increase because the particles will collide more frequently.

This is because an increase in temperature of a fluid (like water) results in an increase in the speed of sound through it. When the temperature increases, the kinetic energy of the particles also increases. As a result, these molecules move around faster, thereby leading to increased collisions which essentially helps the sound wave to propagate faster. So, the speed of the sound wave increases with an increase in temperature.

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Answer:

Cyan is the color on the visible light spectrum that has more energy than green

Explanation:

Green's energy is 2.25,

Orange's energy is 2.06,

Cyan's energy is 2.48,

Yellow's energy is 2.14,

Red's energy is from 1.77 to 1.91,

13 atm

Ideal gas laws let us calculate different values for gases.

Boyle's Law

One of the ideal gas laws is Boyle's law. Boyle's law states that pressure and volume are inversely proportional. This means that as pressure increases, volume decreases and vice versa. In equation form, Boyle's law is:

This means to find the original pressure, all we have to do is plug in the known values and solve for P₁.

Solving for P

Firstly, let's plug in the known volumes and pressure.

Then, divide both sides by 2.7 to find the original pressure.

Since this equation is based on measured values, we should round to significant figures. Rounded to 2 sig figs, the original pressure was 13 atm.

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. Here the number of O atoms is not balanced. The correct option is B.

A balanced chemical equation is one in which the number of atoms on each side (the reactant and product side) of the equation are equal. The law of conservation of mass states that when a chemical reaction takes place, the mass of the reactants and products should be equal.

Each element has the same number of atoms as before the chemical reaction. Therefore, the chemical equation must be in equilibrium.

Here the balanced equation is:

3 HCIO → HCIO ₃ + 2HCI

Thus the correct option is B.

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Weight is best defined as the force of gravity on an object (option C).

Weight is the force on an object due to the gravitational attraction between it and the Earth (or whatever astronomical object it is primarily influenced by).

Weight is different from mass being that weight is a dependent on the gravitational force of the object's habitation, however, mass is not.

For example, the mass of an object on Earth can be 10kg, however, the weight of the object is 100N because the gravitational force of the Earth is 10m/s².

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When the volume of the system is decreased, the pressure will increase, causing the reaction to shift in the direction that produces fewer gas molecules. In this case, the reaction shifts towards the formation of CO2, increasing the concentration of all species (CO, O2, and CO2).

After each event listed, the changes in concentration for each species to reach equilibrium can be determined:

Increasing the concentration of CO:

CO will decrease (↓)

O2 will not change (blank)

CO2 will increase (↑)

Increasing the concentration of CO2:

CO will not change (blank)

O2 will not change (blank)

CO2 will increase (↑)

Decreasing the volume of the system:

CO will increase (↑)

O2 will increase (↑)

CO2 will increase (↑)

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To break the bonds in the hydrogen molecules in the reaction N2(g) + 3H2(g) → 2NH3(g), approximately 1305 kJ of energy needs to be supplied.

In order to break the bonds in the hydrogen molecules (H2), energy needs to be supplied to overcome the attractive forces between the atoms within the molecules. Breaking bonds requires an input of energy and is an endothermic process.

In the given chemical reaction, N2(g) + 3H2(g) → 2NH3(g), the hydrogen molecules (H2) are broken as the reactants, N2 and H2, are converted into ammonia (NH3).

Breaking one H2 molecule requires the energy equivalent to the bond dissociation energy (also known as bond energy) of the H-H bond. The bond dissociation energy is the energy required to break one mole of a particular bond in a gaseous molecule.

The bond dissociation energy for the H-H bond is approximately 435 kJ/mol. This means that it takes approximately 435 kJ of energy to break one mole of H-H bonds.

In the given reaction, three moles of H2 molecules are involved. Therefore, the total energy required to break the bonds in the hydrogen molecules is:

Energy required = 3 moles * 435 kJ/mol = 1305 kJ

So, to break the bonds in the hydrogen molecules in the reaction N2(g) + 3H2(g) → 2NH3(g), approximately 1305 kJ of energy needs to be supplied.

It's important to note that breaking bonds requires energy input, while forming bonds releases energy. In this reaction, the formation of new bonds in the ammonia (NH3) molecules will release energy, resulting in an overall exothermic reaction. The energy change of the reaction, often referred to as the enthalpy change (ΔH), will depend on the difference between the energy required to break the bonds and the energy released when new bonds are formed.

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The identifications of any other ions that may be present remain inconclusive.

Based on the observations mentioned, we can deduce the possible ions present in the substance A and the respective reactions involved.

1. Heating in dry tube with blue and red litmus paper - There was no reaction as the blue litmus paper remained blue, indicating that the substance is not acidic and the red litmus paper turned blue, indicating that the substance is basic. Therefore, the substance could be a base or a neutral substance.

2. Addition of sodium hydroxide solution - The addition of NaOH dropwise to A resulted in the further alkalization of the substance if it was initially a base. No gas was evolved during this reaction. The reaction could be represented as follows:  

        A + NaOH → A⁻ + Na⁺ + H₂O                                                                                                                  

Here, A could be a metal cation or the conjugate base of an organic acid.

3. Addition of barium chloride solution followed by dilute hydrochloric acid - The addition of a few drops of barium chloride solution to A would test for the presence of sulphate ion (SO₄²⁻). The white precipitate that formed in dilute hydrochloric acid solution that remained is barium sulphate (BaSO₄) as per the following equation:

        Ba²⁺ + SO₄²⁻ → BaSO₄(s)

4. Green precipitate formed - No information is provided on which ions may be present that produced a green precipitate.

Based on the given observations, the substance A is most likely a base or neutral substance that did not evolve any gas upon the addition of NaOH. The presence of the sulphate ion (SO₄²⁻) was confirmed later by the formation of a white precipitate of BaSO₄ that remained unchanged in dilute hydrochloric acid solution. However, the identifications of any other ions that may be present remain inconclusive.

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The half-life constant of a first order reaction is 12 minutes. if the initial concentration of reactant is 0.352M, it takes 12 minutes for it to decrease to 0.176M

The duration it takes for half of the radioactive atoms in a sample to decay is known as the half-life in the context of radioactive decay. Because they are unstable, radioactive substances spontaneously undergo radioactive decay, changing over time into new elements or isotopes.

A radioactive substance's half-life is one of its distinctive characteristics. For instance, if the half-life of a radioactive isotope is one hour, half of the initial quantity would have degraded after one hour, half of the remaining quantity would have degraded after another hour, and so on.

The duration it takes for the concentration of a reactant to reduce by half in a first-order reaction is known as the half-life in the context of chemical reactions.

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The artificial transmutation is described as  process which leads to the formation of a new element with a different atomic number mass number.

The example can be seen in the  artificial transmutation of nitrogen-14 where  alpha particles  are  bombarded  to create oxygen-17 .

The artificial transmutation of transuranic elements has is very beneficial as it has helped to manage radioactive waste.

The  artificial transmutation of nitrogen-14  where  alpha particles  are  bombarded  to create oxygen-17 and a proton is shown in the reaction below:

14N + 4He → 17O + 1H

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Explanation:

You've not brought out the question

An increase in temperature during the reaction is an indication that the reaction released chemical energy

The increase in temperature during a reaction in a closed system indicates that the reaction releases chemical energy.

This is because an increase in temperature indicates that energy is being released into the surroundings, and the only way that can happen in a closed system is if it is released by the reaction taking place within the system.

In other words, the correct answer is C. The reaction releases chemical energy.

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The alpha particles have the lowest penetrating power, followed by beta particles, while gamma rays possess the highest ability to penetrate substances.

In increasing order of their ability to penetrate substances, the different types of radioactive decay are:

Alpha particle: Alpha particles consist of two protons and two neutrons and are relatively large and heavy. Due to their size and positive charge, they have limited penetrating power and can be easily stopped by a sheet of paper or a few centimeters of air.

Beta particle: Beta particles are high-energy electrons (beta-minus decay) or positrons (beta-plus decay) emitted during radioactive decay. They have greater penetrating power than alpha particles but are still relatively easily stopped by a few millimeters of aluminum or a few meters of air.

Gamma ray: Gamma rays are electromagnetic waves with high energy and frequency. They have the highest penetrating power among the three types of radioactive decay. Gamma rays require thick layers of dense materials such as lead or concrete to significantly reduce their intensity.

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150 grams of NaOH is approximately equal to 2.256 x 10^24 particles of NaOH.

To convert grams of NaOH to particles of NaOH, we need to use the concept of molar mass and Avogadro's number. The molar mass of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) together. It can be determined as follows:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can use the molar mass to convert grams of NaOH to moles. Since 1 mole contains Avogadro's number (approximately 6.022 x 10^23) particles, we can determine the number of particles as follows:

150 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (6.022 x 10^23 particles / 1 mol NaOH) ≈ 2.256 x 10^24 particles

It's important to note that this calculation assumes the substance is pure NaOH and that the molar mass and Avogadro's number are accurate.

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The chemical equations are as completed below:

1. N₂ + 3 H₂ → 2 NH₃

2. 2 KClO₃ → 2 KCl + 3 O₂

The complete chemical equations are as follows:

3. 2 NaCl + F₂ → 2 NaF + Cl₂

4. 2 H₂ + O₂ → 2 H₂O

5. Pb(OH)₂ + 2 HCl → 2 H₂O + PbCl₂

6. 3 ABr₂ + K₂SO4 → 2 KBr + Al₂(SO4)₃

7. CH₄ + 2 O₂ → CO₂ + 2 H₂O

8. C₃H₂ + ⁵/₂ O₂ → 3 CO₂ + H₂O

9. C₃H₁₂ + ⁹/₂ O₂ → 3 CO₂ + 6 H₂O

10. FeCl₃ + 3 NaOH → Fe(OH)₃ + 3 NaCl

11. 4 P + 3 O₂ → 2 P₂O₃

12. 2 Na + 2 H₂O → 2 NaOH + H₂

13. 2 Ag₂O → 4 Ag + O2

14. S₄ + 6 O₂ → 4 SO₃

15. C₃H₈O + 5 O₂ → 3 CO₂ + 4 H₂O

16. 2 K + MgBr₂ → 2 KBr + Mg

17. 2 HCl + CaCO₃ → CaCl₂ + H₂O + CO₂

18. HNO₃ + NaHCO₃ → NaNO₃ + H₂O + CO₂

19. 2 H₂O + O₂ → 2 H₂O₂

20. 2 NaBr + CaF₂ → 2 NaF + CaBr₂

21. H₂SO₄ + 2 NaNO₂ → 2 HNO₂ + Na₂SO₄

Therefore, the correct answer is as given above. It could then be concluded that the above chemical equations are now balanced.

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Explanation:

The balanced equation is

2  H2        +    02 ======> 2 H2 O

so it takes twice as many H2 moles as O2 to complete the reaction

  the chemist does not have enough  H2 (needs 8 moles)   , so H2 is the limiting reactant .

HCN, Na2SO4: Combination of compounds.

Mg3N2: Chemical compound.

CO2, H2O: Dissolution or hydration reaction.

Cu, Zn(NO3)2: Single-replacement reaction.

Na, N2: Combination of elements.

Let's analyze each chemical combination to determine the type of reaction involved:

HCN, Na2SO4:

The combination of hydrogen cyanide (HCN) and sodium sulfate (Na2SO4) does not represent a specific chemical reaction. It is simply the combination of two compounds.

Mg3N2:

Mg3N2 represents a chemical compound, magnesium nitride. It does not indicate a specific reaction.

CO2, H2O:

The combination of carbon dioxide (CO2) and water (H2O) represents a chemical reaction known as hydration or dissolution. When carbon dioxide dissolves in water, it forms carbonic acid (H2CO3), which can further dissociate into hydrogen ions (H+) and bicarbonate ions (HCO3-).

Cu, Zn(NO3)2:

The combination of copper (Cu) and zinc nitrate (Zn(NO3)2) represents a single-replacement reaction. Copper displaces zinc from the compound, resulting in the formation of copper nitrate (Cu(NO3)2) and zinc metal (Zn).

Na, N2:

The combination of sodium (Na) and nitrogen gas (N2) does not represent a specific reaction. It is simply the combination of two elements.

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Q ≈ -2000 J

Temperature changes can be used to calculate heat transfer. Please note that since the question is based on measured values I rounded for significant figures.

Heat Transfer

In heat transfer, energy can be gained or lost. When energy is gained, temperature increases. However, when energy is lost, temperature decreases. Since the water decreased in temperature, it must have lost energy. This means that Q will be negative. Q represents the transfer of energy, which is measured in joules.

Calculating Energy

To calculate heat transfer we can use the equation q = m·c·ΔT.

For this question, we know that the mass is 75.0g. Specific heat is a constant that every substance has. These values can be found in data tables. For liquid water, c = 4.184. Finally, the change in temperature is -7°C.

In this scenario, 2196.6 joules of energy were lost. Since -7 has one sig fig, this answer can be rounded to 2000 J.

The produce 1 mole of AgCl, we would have approximately 6.022 × 10^23 particles of silver chloride.

To determine the number of particles of silver chloride produced, we need to consider the balanced chemical equation and the stoichiometry of the reaction involved.

The balanced chemical equation for the formation of silver chloride (AgCl) is:

2 AgNO3 + NaCl → AgCl + 2 NaNO3

From the equation, we can see that two moles of silver nitrate (AgNO3) react with one mole of sodium chloride (NaCl) to produce one mole of silver chloride (AgCl).

To calculate the number of particles, we need to know the number of moles of silver chloride. Let's assume that we have 'x' moles of AgCl.

According to the balanced equation, the molar ratio between AgCl and AgNO3 is 1:2. So, if 'x' moles of AgCl are produced, then '2x' moles of AgNO3 must react.

Now, if we know the molar mass of AgCl, we can convert the moles of AgCl to particles using Avogadro's number (6.022 × 10^23 particles/mol).

To provide an accurate answer in 125 words, I'll need to make some assumptions. Let's assume we have 1 mole of AgCl. Then, the number of particles of AgCl would be:

1 mole AgCl × (6.022 × 10^23 particles/mol) = 6.022 × 10^23 particles.

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Complete Question

How many grams of silver chloride are produced from 5.0 g of silver nitrate reacting with an excess of barium chloride in the reaction

2AgNO3 +BaCl2 →2AgCl +Ba(NO3)2?

One structural difference between oligosaccharides and polysaccharides is the number of monosaccharide units they consist of. Oligosaccharides have a relatively small number of monosaccharide units (typically 3 to 10), while polysaccharides have a larger number of monosaccharide units (often hundreds or thousands).

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