Multiply 2 digit numbers with area models. 26x74

Answer: 6 10

Step-by-step explanation:

Answer:

thirty-one. nine hundred three tenths

Step-by-step explanation:

no sé ni hablar English pero espero te ayude

Answer:

D.

Step-by-step explanation:

End behavior : Left up and right down

Even degree with negative leading coefficient

Answer:

y = - 3x - 1

Step-by-step explanation:

Slope = 3/-1 = -3 (rise/run)

y-intercept= -1

y = -3x - 1

Answer:

(x - 1) (x^2 + 4x + 53)

Step-by-step explanation:

Common factor: x - 1

(x^3 + 3x^2+ 49x - 53) / (x - 1)

= (x^2 + 4x + 53) (x-1)

An algebraic expression for the given statement is 20-x.

The given statement is the difference of 20 and x.

We need to write an algebraic expression for the given statement.

An algebraic expression (or) a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division, etc.

Now, the difference of 20 and x =20-x

Therefore, an algebraic expression for the given statement is 20-x.

To learn more about an algebraic expression visit:

https://brainly.com/question/19245500.

#SPJ2

Answer:

1,800, 000, 000 ,000, 000 ,000, 000

simplified:

1.8e+21

Step-by-step explanation:

when it says 1e+20 that means there is 20 zeroes behind it:

100, 000, 000 ,000, 000 ,000, 000

Have a nice day!

Answer:

y = 1/2x + 3

Step-by-step explanation:

First we find the slope:

(y2 - y1)/(x2 - x1) =

3-0 / 0 + 6

3/6 = 1/2

then the y intercept is 0,3 so we add 3

y = 1/2x +3

Answer:

x=-2+9

Step-by-step explanation:

The first line is negative 2 and the second line is positive nine.

Answer:

.66 are in each bag.

Step-by-step explanation:

14/3 = 4.66666666667

then you grab the answer for 14/3 and divide by 7

this in turn will get you .66 repeated

so .66 of a pound is in each 7 bags.

Answer:

Step-by-step explanation:

You can find the perfect squares that are closest to this by listing the perfect squares and seeing which two this square would be between, which is the square root of 36 and the square root of 49:

[tex]\sqrt{36} < \sqrt{40} < \sqrt{49}[/tex]

Answer:

4.3 x[tex]10^{6}[/tex] meters

4.3x[tex]10^{9}[/tex] millimeters

Step-by-step explanation:

Answer:

9.45 (Jill)

Step-by-step explanation:

2.7 x 3.5 = 9.45

Lisa put the decimal in the wrong spot.

Answer:

La raíz cuadrada de cualquier número se puede expresar usando la fórmula: √y = y½.

Answer:

100

Step-by-step explanation:

Answer:

I think B is the answer ..........

Answer:

Hey mate.....can't see the attached picture....please check again

Answer:

what table??

Step-by-step explanation:

Answer:

pls mark as brainliest and follow

9514 1404 393

Answer:

  D: 21

Step-by-step explanation:

The first term is (a1). The third term is (a1)r². The product of these terms is ...

  (a1)(a1)r² = ((a1)r)², the square of the second term.

The missing term is √(7·63) = √441 = 21.

_____

Additional comment

In consideration of the above, you can also see that the common ratio can be found from ...

  a3/a1 = ((a1)r²)/(a1) = r² = 63/7 = 9

Then the common ratio is r = √9 = 3, and the second term is 7·3 = 21.

Answer:

2...

Step-by-step explanation:

1 + 1 = 2

Answer:

look at the explanation 20,440

Step-by-step explanation:

so the invested 2,800 $  and the interest rate is 1.46 so first what I would do is 1.46 times 5 = 7.3 then 7.3 x 2,800 =20,440

so I think the answer is 20,440

not sure if this is correct but I gave it my all

or you could just do 2800 time 5 time 1.46

Answer:

The answer is 77848.1336

Answer:

Step-by-step explanation:

We actually don't need to know all of the restrictions.

We know that a vertical stretch factor of 4 means multiplying a square root function by [tex]4[/tex]. So, the answer will be in the form [tex]y=4\sqrt{x+c}+k[/tex], where c and k are real numbers.

Aha! Only one of these conditions satisfy the restrictions, so we have that [tex]\boxed{y=4\sqrt{x+3}+7}[/tex] has to be the answer.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The Above statement is incorrect, because if the positive number is equal to the numerical value of negative number then their sum will be zero, and If the numerical value of positive number is greater than that of negative number then the sum will be a positive number, so the probability is of both three, the sum can be positive, negative as well as zero.

Answer:

The above statement is false.

Explanation:

If the positive number is greater than the negative, then it will stay positive.

Answer:

9

Step-by-step explanation:

x - 11 = - 2

x = - 2 + 11

= 11 - 2

x = 9

◻︎                                                                                                                            ◻︎

                                            Hello There!

We must make sure numbers are on the right side of the equation and x's (variables) are on the left:

x=-2+11

x=9

Hope this helps you! :)

Answered by:

[tex]GraceRosalia[/tex]

Answer: C

Step-by-step explanation:

No matter how big the number you are dividing by you cannot go below 0.

(positive division)

so that rules out A & B.

(D) 10 - 100 = -90.

(C) 1 - 100 = -99.

C has the least value.

Answer:

167°

Step-by-step explanation:

x = 167°

Answer:

10:A 11:D

Step-by-step explanation:

10)

g([tex](\sqrt{x+1}^2+3)/(\sqrt{x+1} )[/tex]

rewrite [tex]\sqrt{x+1}^2[/tex] as x +1

g [tex](\sqrt{x+1}^2)[/tex] = [tex]\frac{x+1+3}{\sqrt{x+1} }[/tex]

add 1+3

g[tex](\sqrt{x+1}^2)[/tex]=[tex]\frac{x+4}{\sqrt{x+1} }[/tex]

combine and symplify

[tex]g{\sqrt{x+1} } *\frac{{x+4 (\sqrt{x+1}) } }{{x+1} }[/tex]

reorder factors of the second side

[tex]g{\sqrt{x+1} } *\frac{{\sqrt{x+1} (x+4) } }{{x+1} }[/tex]

take out the root x+1

and you are left with A

11.

f(g(x))

substitue g into f

f([tex]f{\sqrt{x+3} } =\((\sqrt{x+3})^2 +9}[/tex]

rewrite sqrroot x+3 as x+3

[tex]f{\sqrt{x+3} } =\(x+3 +9}[/tex]

Now add 3+9

[tex]f{\sqrt{x+3} } =\(x+12}[/tex]

we get x+12

Now for domain

[tex]f{\sqrt{x+3} } =\((\sqrt{x+3})^2 +9}[/tex]

set the radicand root sqr x+3 >= 0 to find the expression defined

[tex]x+3\geq 0[/tex]

subtract 3 from both sides

[tex]x\geq 3[/tex]

turn it into interval notation

[-3,+∞)