Take into account the following formula for the simple interest:
[tex]I=P\cdot r\cdot t[/tex]where:
P: principal investment
r: interest rate
t: time
In order to determine the investments for both accounts, proceed as follow:
-Consider that both investments are represented by P1 and P2 respectively, then, you have:
[tex]\begin{gathered} P_1+P_2=22000 \\ P_2=22000-P_1 \end{gathered}[/tex]- Next, use the given values for parameters r and t for each investment:
8% = 0.08
11% = 0.11
t = 1 year
[tex]\begin{gathered} I_1=P_1\cdot0.08\cdot1=0.08P_1 \\ I_2=P_2\cdot0.11\cdot1=0.11P_2 \end{gathered}[/tex]- Next, consider that the sum of the total earnings is $1910, then:
[tex]I_1+I_2=1910[/tex]- Replace I1 and I2 by the expressions in terms of P1 and P2 and write down the resultant expression in terms of P1, as follow:
[tex]\begin{gathered} 0.08P_1+0.11P_2=1910 \\ 0.08P_1+0.11(22000-P_1)=1910 \\ 0.08P_1+2420-0.11P_1=1910 \\ -0.03P_1=-510 \\ P_1=\frac{510}{0.03}=17000 \end{gathered}[/tex]And for P2:
[tex]\begin{gathered} P_2=22000-P_1 \\ P_2=22000-17000=5000 \end{gathered}[/tex]Hence, the amount of money invested in each account was $5000 and $17000
how to get standar form from point 1,4 and a slope of 5
Using the equation and the ordered-pairs found previously, plot the points on the graph that would best satisfy theequation.y= 2^x
Given the following equation:
[tex]y=x^2[/tex]We will graph the given function using the points that will be written in ordered-pairs.
The given function is a quadratic function with a vertex = (0, 0)
We will graph the points using five points
The vertex and 4 points, 2 points before the vertex and 2 points after the vertex.
So, we will substitute x = -4, -2, 2, 4
[tex]\begin{gathered} x=-4\rightarrow y=16 \\ x=-2\operatorname{\rightarrow}y=4 \\ x=2\operatorname{\rightarrow}y=4 \\ x=4\operatorname{\rightarrow}y=16 \end{gathered}[/tex]So, the points are: (-4, 16), (-2, 4), (0, 0), (2, 4), (4, 16)
The graph using the points will be as follows:
Wayne has a bag filled with coins. the bag contains 7 quarters,8 dimes,3 nickels, and 9 pennies. he randomly chooses a coins from the bag. what is the probability that Wayne chooses a quarter or nickel?
Wayne has a bag filled with coins.
Number of quarters = 7
Number of dimes = 8
Number of nickels = 3
Number of pennies = 9
So, the total number of coins is
Total = 7 + 8 + 3 + 9 = 27
What is the probability that Wayne chooses a quarter or nickel?
How many coins are either quarter or nickel?
quarter or nickel = 7 + 3 = 10
So, the probability is
[tex]P(quarter\: or\: nickel)=\frac{10}{27}[/tex]Therefore, the probability that Wayne chooses a quarter or nickel is 10/27
Jason is making bookmarks to sell to raise money for the local youth center. He has 29 yards of ribbon, and he plans to make 200 bookmarks.Approximately how long is each bookmark, in centimeters?
The Solution:
The correct answer is 13.26 centimeters.
Explanation:
Given that Jason has 29 yards of ribbon, and he plans to make 200 bookmarks.
We are asked to find the approximate length (in centimeters) of each bookmark.
Step 1:
Convert 29 yards to centimeters.
[tex]\begin{gathered} \text{ Recall:} \\ \text{ 1 yard = 91.44 centimeters} \end{gathered}[/tex]So,
[tex]29\text{ yards = 29}\times91.44=2651.76\text{ centimeters}[/tex]Step 2:
To get the length of each bookmark, we shall divide 2651.76 by 200.
[tex]\text{ Length each bookmark = }\frac{2651.76}{200}=13.2588\approx13.26\text{ centimeters}[/tex]Therefore, the correct answer is 13.26 centimeters.
What is the y-intercept of the line x+2y=-14? (0,7) (-7,0) (0,-7) (2,14)
THIS IS URGENT
A line includes the points (2,10) and (9,5). What is its equation in point-slope form?
Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.
Answer:
Step-by-step explanation:
y = 13x -12
Rewrite 20 - 4x³ using a common factor.
O 4x(5-x²)
O4(5 - 4x³)
02x(10-2x²)
02(10-2x³)
Answer:
[tex]20 - 4 {x}^{3} = 4(5 - {x}^{3} )[/tex]
Rewrite 4x + 16 using a common factor.
Answer 4(x + 4)
1. Write the equation of a line perpendicular to thex 5and that passes through thepoint (6,-4).line y
The line we want has a slope that is the negative reciprocal of the slope of the line
y = -(1/2)x - 5
The slope of this line is -1/2. So, the slope of its perpendicular lines is 2. Therefore, their equations have the form:
y = 2x + b
Now, to find b, we use the values of the coordinates of the point (6, -4) in that equation:
-4 = 2*6 + b
-4 = 12 + b
b = -4 - 12 = -16
Therefore, the equation is y = 2x - 16.
Solve for x using the quadratic formula.3x^2 +10x+8=3
The quadartic equation is 3x^2+10x+8=3.
Simplify the quadratic equation to obtain the equation in standard form ax^2+bx+c=0.
[tex]\begin{gathered} 3x^2+10x+8=3 \\ 3x^2+10x+5=0 \end{gathered}[/tex]The coefficent of x^2 is a=3, coefficient of x is b=10 and constant term is c=5.
The quadartic formula for the values of x is,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Substitute the values in the formula to obtain the value of x.
[tex]\begin{gathered} x=\frac{-10\pm\sqrt[]{(10)^2-4\cdot3\cdot5}}{2\cdot3} \\ =\frac{-10\pm\sqrt[]{100-60}}{6} \\ =\frac{-10\pm\sqrt[]{40}}{6} \\ =\frac{-10\pm2\sqrt[]{10}}{6} \\ =\frac{-5\pm\sqrt[]{10}}{3} \end{gathered}[/tex]The value of x is,
[tex]\frac{-5\pm\sqrt[]{10}}{3}[/tex]2. Assume that each situation can be expressed as a linear cost function and find the appropriate cost function. (a) Fixed cost, $100; 50 items cost $1600 to produce. (b) Fixed cost, $400; 10 items cost $650 to produce. (c) Fixed cost, $1000; 40 items cost $2000 to produce. (d) Fixed cost, $8500; 75 items cost $11,875 to produce. (e) Marginal cost, $50; 80 items cost $4500 to produce. (f)Marginal cost, $120; 100 items cost $15,800 to produce. (g) Marginal cost, $90; 150 items cost $16,000 to produce. (h) Marginal cost, $120; 700 items cost $96,500 to produce.
Given:
Cost function is defined as,
[tex]\begin{gathered} C(x)=mx+b \\ m=\text{marginal cost} \\ b=\text{fixed cost} \end{gathered}[/tex]a) Fixed cost = $100, 50 items cost $1600.
The cost function is given as,
[tex]\begin{gathered} C=\text{Fixed cost+}x(\text{ production cost)} \\ x\text{ is number of items produced} \\ \text{Given that, }50\text{ items costs \$1600} \\ 1600=100\text{+50}(\text{ production cost)} \\ \text{production cost=}\frac{1600-100}{50} \\ \text{production cost}=30 \end{gathered}[/tex]So, the cost function is,
[tex]C=30x+100[/tex]b) Fixed cost = $400, 10 items cost $650.
[tex]\begin{gathered} 650=400+10p \\ 650-400=10p \\ p=25 \\ \text{ Cost function is,} \\ C=25x+400 \end{gathered}[/tex]c) Fixed cost= $1000, 40 items cost $2000 .
[tex]\begin{gathered} 2000=1000+40p \\ p=25 \\ C=25x+1000 \end{gathered}[/tex]d) Fixed cost = $8500, 75 items cost $11,875.
[tex]\begin{gathered} 11875=8500+75p \\ 11875-8500=75p \\ p=45 \\ C=45x+8500 \end{gathered}[/tex]e) Marginal cost= $50, 80 items cost $4500.
In this case we know the value of m = 50 .
Use the slope point form,
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(80,4500) \\ y-4500=50(x-80) \\ y=50x-4000+4500 \\ y=50x+500 \\ C=50x+500 \end{gathered}[/tex]f) Marginal cost=$120, 100 items cost $15,800.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(100,15800) \\ y-15800=120(x-100) \\ y=120x-12000+15800 \\ y=120x+3800 \\ C=120x+3800 \end{gathered}[/tex]g) Marginal cost= $90,150 items cost $16,000.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(150,16000) \\ y-16000=90(x-150) \\ y=90x-13500+16000 \\ y=90x+2500 \\ C=90x+2500 \end{gathered}[/tex]h) Marginal cost = $120, 700 items cost $96,500
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(700,96500) \\ y-96500=120(x-700) \\ y=120x-84000+96500 \\ y=120x+12500 \\ C=120x+12500 \end{gathered}[/tex]At one time, it was reported that 27.9% of physicians are women. In a survey of physicians employed by a large health system, 45 of 120 randomly selected physicians were women. Is there sufficient evidence at the 0.05 level of significance to conclude that the proportion of women physicians in the system exceeds 27.9%?Solve this hypothesis testing problem by finishing the five steps below.
SOLUTION
STEP 1
The hull hypothesis can written as
[tex]H_0\colon p=0.279[/tex]The alternative hypothesis is written as
[tex]H_1\colon p>0.279[/tex]STEP 2
The value of p will be
[tex]\begin{gathered} \hat{p}=\frac{X}{n} \\ \hat{p}=\frac{45}{120}=0.375 \\ \text{where n=120, x=}45 \end{gathered}[/tex]STEP3
From the calculations, we have
[tex]\begin{gathered} Z_{\text{cal}}=2.34 \\ \text{Z}_{\text{los}}=0.05 \end{gathered}[/tex]We obtained the p-value has
[tex]\begin{gathered} p-\text{value}=0.0095 \\ \text{level of significance =0.05} \end{gathered}[/tex]STEP4
Since the p-value is less than the level of significance, we Reject the null hypothesis
STEP 5
Conclusion: There is no enought evidence to support the claim
gus bought 2/3 pound of turkey and 1/4 pound of ham.The tukey cost 9 dollars per pound, and the ham cost 7 dollars per pound.In all,how much did Gus spend?
From the information given,
gus bought 2/3 pound of turkey. If tukey costs 9 dollars per pound, it means that the cost of 2/3 pound of turkey is
2/3 x 9 = 6
gus bought 1/4 pound of ham. If ham costs 7 dollars per pound, it means that the cost of 1/4 pound of ham is
1/4 x 7 = 7/4 = 1.75
Total amount spent = amount spent on turkey + amount spent on ham
Total amount = 6 + 1.75
Total amount = $7.75
How do I find the gif and distributive property
By using the GCF and distributive property, the sum of 15+27 = 42
The expression is
15 + 27
GCF is the greatest common factor, the greatest common factor is the highest number that divides exactly into two or more numbers.
The distributive property states that multiplying the sum of two or more variables by a number will produce the same result as multiplying each variables individually by the number and then adding the products together.
The expression is
= 15 + 27
= 3(5 + 9)
= 3 × 14
= 42
Hence, by using the GCF and distributive property, the sum of 15 + 27 = 42
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In exercises 1 and 2 , identify the bisector of ST then find ST
Given: The line segment ST as shown in the image
To Determine: The bisector of ST and the value of ST
Solution
It can be observed from the first image, the bisector of ST is line MW
[tex]\begin{gathered} ST=SM+MT \\ SM=MT(given) \\ MT=19(given) \\ Therefore \\ ST=19+19 \\ ST=38 \end{gathered}[/tex]For the second image, the bisector of ST is line LM
[tex]\begin{gathered} ST=SM+MT \\ SM=3x-6 \\ MT=x+8 \\ SM=MT(given) \\ Therefore \\ 3x-6=x+8 \\ 3x-x=8+6 \\ 2x=14 \\ x=\frac{14}{2} \\ x=7 \end{gathered}[/tex][tex]\begin{gathered} SM=3(7)-6=21-6=15 \\ MT=7+8=15 \\ ST=SM+MT \\ ST=15+15 \\ ST=30 \end{gathered}[/tex]For first exercise, the bisector is MW, ST = 38
For the second exercise, the bisector is LM, ST = 30r
Mark is roofing an old gymnasium that measures 270’x390’, and needs to calculate how many “squares “ he will need.(1 “square=100 ft square). The gym’s roof is a standard gable roof with 3’ of overhang on all sides. The roof angle measures 22.55 degrees from horizontal. How many squares of roofing does mark need ?
First, because of the roof having an inclination, we need to calculate the lenght of the surface we want to roof. The width will be the same.
Let's take a look at the situation:
Since we're on a right triangle, we can say that:
[tex]\cos (22.25)=\frac{G}{R}[/tex]Solving for R,
[tex]\begin{gathered} \cos (22.25)=\frac{G}{R}\rightarrow R\cos (22.25)=G \\ \\ \Rightarrow R=\frac{G}{\cos (22.25)} \end{gathered}[/tex]Since we already know that the lenght of the gym's floor is 390',
[tex]\begin{gathered} R=\frac{390^{\prime}}{\cos (22.25)} \\ \\ \Rightarrow R=421.38^{\prime} \end{gathered}[/tex]We get that the lenght of the surface we want to roof is 421.38'
Now, let's take a look at the surface we want to roof:
Since the roof is a standard gable roof with 3’ of overhang on all sides, we add 6' to each dimension:427
Our total roofing area would be:
[tex]427.38^{\prime}\cdot276^{\prime}=117956.88ft^2[/tex]We then divide this total area by the area of one of our "squares":
[tex]\frac{117956.88}{100}=1179.56[/tex]We round to the nearest integer from above, since we can't buy a fraction of a square.
(this is called ceiling a number)
[tex]1179.56\rightarrow1180[/tex]Therefore, we can conclude that Mark needs 1180 squares of roofing.
1. Is this figure a polygon?2. Is this polygon concave or convex?3. Is this polygon regular, equiangular, Equilateral, or none of these?4. What is the name of this polygon?
A polygon is a closed shape with straigh sides, then
2. Is the figure a polygon? YES.
Since the figure is a polygon
1a. Is this polygon concave or convex? It is concave. A concave polygon will always have at least one reflex interior angle, tha is, it has on interior angle greater than 180 degrees.
1b. Is this polyogn regular, equiangular, equilateral or none of these? The marks on the picture mean that all the sides have the same length. This is the definition of equilateral. Then the answer is equilateral.
1c. What is the name of this polygon? We can see it has 4 equal sides and is concave, then his name is Concave Equilateral Quadrilateral.
The ship leaves at 18 40 to sail to the next port.
It sails 270 km at an average speed of 32.4 km/h
Find the time when the ship arrives.
Answer:
Step-by-step explanation:
Given:
t₁ = 18:40 or 18 h 40 min
S = 270 km
V = 32.4 km/h
____________
t₂ - ?
Ship movement time:
t = S / V = 270 / 32.4 ≈ 8.33 h = 8 h 20 min
t₂ = t₁ + t = 18 h 40 min + 8 h 20 min
40 min + 20 min = 60 min = 1 h
18 h +8 h = 26 h = 24 h + 2 h
2 h + 1 h = 3 h
t₂ = 3:00
The ship will arrive at the destination port at 3:00 the next day.
Answer:
32.4 - 27.0 = 5.4
18.40 + 54 =
7hrs:34mins
The ship arrived at
7:34pm
What is the current population of elk at the park?
Given the following function:
[tex]\text{ f\lparen x\rparen= 1200\lparen0.8\rparen}^{\text{x}}[/tex]1200 represents the initial/current population of elk in the national park.
Therefore, the answer is CHOICE A.
Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent% markdown = 40Reduced price = $144$ markdown = ?
The given information:
% mark up = 40
Reduced = $144
Markdown = ?
The formula for percentage markup is given as
[tex]\text{ \%markup }=\frac{markup}{actual\text{ price}}\times100[/tex]Let the actual price be x
Hence,
Reduced price = 60% of actual price
[tex]60\text{\% of x = 144}[/tex]Solving for x
[tex]\begin{gathered} \frac{60x}{100}=144 \\ x=\frac{144\times100}{60} \\ x=240 \end{gathered}[/tex]Therefore, actual price = $240
Inserting these values into the %markup formula gives
[tex]40=\frac{\text{markup}}{240}\times100[/tex]Solve for markup
[tex]\begin{gathered} 40=\frac{100\times\text{markup}}{240} \\ 40\times240=100\times\text{markup} \\ \text{markup}=\frac{40\times240}{100} \\ \text{markup}=96 \end{gathered}[/tex]Threefore, markup = $96
The lengths of adult males' hands are normally distributed with mean 189 mm and standard deviation is 7.4 mm. Suppose that 15 individuals are randomly chosen. Round all answers to 4 where possible.
a. What is the distribution of ¯x? x¯ ~ N( , )
b. For the group of 15, find the probability that the average hand length is less than 191.
c. Find the first quartile for the average adult male hand length for this sample size.
d. For part b), is the assumption that the distribution is normal necessary? No Yes
Considering the normal distribution and the central limit theorem, it is found that:
a) The distribution is: x¯ ~ N(189, 1.91).
b) The probability that the average hand length is less than 191 is of 0.8531 = 85.31%.
c) The first quartile is of 187.7 mm.
d) The assumption is necessary, as the sample size is less than 30.
Normal Probability DistributionThe z-score of a measure X of a variable that has mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure X is above or below the mean of the distribution, depending if the z-score is positive or negative.From the z-score table, the p-value associated with the z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]. The mean is the same as the population mean.For sample size less than 30, such as in this problem, the assumption of normality is needed to apply the Central Limit Theorem.The parameters in this problem are given as follows:
[tex]\mu = 189, \sigma = 7.4, n = 15, s = \frac{7.4}{\sqrt{15}} = 1.91[/tex]
Hence the sampling distribution of sample means is classified as follows:
x¯ ~ N(189, 1.91).
The probability that the average hand length is less than 191 is the p-value of Z when X = 191, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
Z = (191 - 189)/1.91
Z = 1.05
Z = 1.05 has a p-value of 0.8531, which is the probability.
The first quartile of the distribution is X when Z has a p-value of 0.25, so X when Z = -0.675, hence:
[tex]Z = \frac{X - \mu}{s}[/tex]
-0.675 = (X - 189)/1.91
X - 189 = -0.675 x 1.91
X = 187.7 mm.
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Finding a specify term of a geometric sequence given the common ratio and first term
A geometric sequence is defined as:
[tex]\begin{gathered} a_1=a*r^0=a*r^{1-1}, \\ a_2=a*r^1=a*r^{2-1}, \\ a_3=a*r^2=a*r^{3-1}, \\ ... \\ a_7=a*r^6=a*r^{7-1}, \\ ... \end{gathered}[/tex]Where r ≠ 0 is the common ratio and a ≠ 0 is the first term of the sequence.
From the statement, we know that r = 2/3 and the first term is a = 5.
Replacing these numbers in the expression of the 7th term, we get:
[tex]a_7=5*(\frac{2}{3})^6=5*\frac{64}{729}=\frac{320}{729}.[/tex]Answer320/729
Find the length of AB given that DB is a median of the triangle AC is 46
ANSWER:
The value of AB is 23
STEP-BY-STEP EXPLANATION:
We know that AB is part of AC, and that DB cuts into two equal parts (half) since it is a median, therefore the value of AB would be
[tex]\begin{gathered} AB=\frac{AC}{2} \\ AB=\frac{46}{2} \\ AB=23 \end{gathered}[/tex]Radicals and Exponents Identify the choices that best completes the questions 3.
3.- Notice that:
[tex]\sqrt[]{12}=\sqrt[]{4\cdot3}=2\sqrt[]{3}\text{.}[/tex]Therefore, we can rewrite the given equation as follows:
[tex]2\sqrt[]{3}x-3\sqrt[]{3}x+5=4.[/tex]Adding like terms we get:
[tex]-\sqrt[]{3}x+5=4.[/tex]Subtracting 5 from the above equation we get:
[tex]\begin{gathered} -\sqrt[]{3}x+5-5=4-5, \\ -\sqrt[]{3}x=-1. \end{gathered}[/tex]Dividing the above equation by -√3 we get:
[tex]\begin{gathered} \frac{-\sqrt[]{3}x}{-\sqrt[]{3}}=\frac{-1}{-\sqrt[]{3}}, \\ x=\frac{1}{\sqrt[]{3}}\text{.} \end{gathered}[/tex]Finally, recall that:
[tex]\frac{1}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3}\text{.}[/tex]Therefore:
[tex]x=\frac{\sqrt[]{3}}{3}\text{.}[/tex]Answer: Option C.
Write a quadratic function whose graph passes through (3,6) and has the vertex (-2,4) what is the value of Y
The representation of a quadratic eqauation in vertex form is
[tex]y=a(x-k)^2+h[/tex]The given vertex is,
[tex](k,h)=(-2,4)[/tex]And the given point through which the graph passes is,
[tex](x,y)=(3,6)[/tex]Substitute the values in the formula of quadratic equation.
[tex]\begin{gathered} 6=a(3-(-2))+4 \\ 6=a(3+2)+4 \\ 6=5a+4 \\ 5a=6-4 \\ 5a=2 \\ a=\frac{5}{2} \end{gathered}[/tex]Hence, the equation in vertex form will be,
[tex]\begin{gathered} y=\frac{5}{2}(x-(-2))+4 \\ y=\frac{5}{2}(x+2)+4 \end{gathered}[/tex]What is the vertex of the parabola with thefunction rule f(x) = 5(x − 4)² + 9?
The equation f(x) = a(x - h)^2 + k gives the vertex of the parabola--it is (h, k).
In this question, h = 4 and k = 9. So the vertex is at (4, 9).
true or false 16/24 equals 30 / 45
True.
Given:
The equation is, 16/24 = 30/45.
The objective is to find true or false.
The equivalent fractions can be verified by, mutiplying the denominator and numerator of each fraction.
The fractions can be solved as,
[tex]\begin{gathered} \frac{16}{24}=\frac{30}{45} \\ 16\cdot45=24\cdot30 \\ 720=720 \end{gathered}[/tex]Since both sides are equal, the ratios are equivalent ratios.
Hence, the answer is true.
The seventh term of a geometric sequence is 1/4 The common ratio 1/2 is What is the first term of the sequence?
Answer:
16
Explanation:
The equation for the term number n on a geometric sequence can be calculated as:
[tex]a_n=a_{}\cdot r^{n-1}[/tex]Where r is the common ratio and a is the first term of the sequence.
So, if the seventh term of the sequence is 1/4 we can replace n by 7, r by 1/2, and aₙ by 1/4 to get:
[tex]\frac{1}{4}=a\cdot(\frac{1}{2})^{7-1}[/tex]Then, solving for a, we get:
[tex]\begin{gathered} \frac{1}{4}=a(\frac{1}{2})^6 \\ \frac{1}{4}=a(\frac{1}{64}) \\ \frac{1}{4}\cdot64=a\cdot\frac{1}{64}\cdot64 \\ 16=a \end{gathered}[/tex]So, the first term of the sequence is 16.
Could I assistance receive some on this question it’s very confusing
We need to translate the vertex F of triangle BDF. When we translate it 2 units to the left and 4 units down, we obtain the point F'.
We know that triangle BDF has vertices B(4,3), D(6,3), and F(6,1).
The first coordinate of each point represents its x-coordinate (the distance from the y-axis). And the second coordinate of each point represents its y-coordinate (the distance from the x-axis).
So, this triangle is shown below:
Now, we need to translate the point F 2 units to the left, to obtain the redpoint below. And then translate it 4 units down, to obtain F' (the yellow point):
Therefore, the F' has coordinates:
F'(4,-3)
I don't get any of this help me please
Using scientific notation, we have that:
a) As an ordinary number, the number is written as 0.51.
b) The value of the product is of 1445.
What is scientific notation?An ordinary number written in scientific notation is given as follows:
[tex]a \times 10^b[/tex]
With the base being [tex]a \in [1, 10)[/tex], meaning that it can assume values from 1 to 10, with an open interval at 10 meaning that for 10 the number is written as 10 = 1 x 10¹, meaning that the base is 1.
For item a, to add one to the exponent, making it zero, we need to divide the base by 10, hence the ordinary number is given as follows:
5.1 x 10^(-1) = 5.1/10 = 0.51.
For item b, to multiply two numbers, we multiply the bases and add the exponents, hence:
(1.7 x 10^4) x (8.5 x 10^-2) = 1.7 x 8.5 x 10^(4 - 2) = 14.45 x 10².
To subtract two from the exponent, making it zero, we need to multiply the base by 2, hence the base number is given as follows:
14.45 x 100 = 1445.
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A man realizes he lost the detailed receipt from the store and only has the credit card receipt with theafter-tax total. If the after-tax total was $357.06, and the tax rate in the area is 8.2%, what was the pre-tax subtotal?
Answer: the pre-tax subtotal is $330
Explanation:
Let x represent the pre tax total
If the tax rate in the area is 8.2%, it means that the amount of tax paid is
8.2/100 * x = 0.082x
pretax total + tax = after tax subtotal
Given that after tax subtotal is $357.06, then
x + 0.082x = 357.06
1.082x = 357.06
x = 357.06/1.082
x = 330
the pre-tax subtotal is $330