Ming rental car for her bike to carry tools and Wood to school for a science project her toolbox weighs 20 pounds in the car can make carry messing with 5050 pounds each woodboard weighs 3 pounds W represent the number of words she can carry

Answer:

a. 1.5

b 1.6 or 1.7

c. 90

Step-by-step explanation:

a. the initial height is 1.5 m (x=0)

b. the maximum height occurs at x = 20, probably 1.6 or 1.7 m

c. the arrows reaches 90 m when it lands (y=0)

hope this helps.

Answer:

248[tex]mm^{2}[/tex]

Step-by-step explanation:

Instead of calculating for the hexagon, divide it into 5 separate triangles with a 8mm base and 5.5mm height.  Calculate using the "half base times height" formula and multiply it by five for the hexagon's area:

[tex]\frac{1}{2}((b)(h)) (5)\\\frac{1}{2}((8)(5.5)) (5)\\\\ \frac{1}{2}(44) (5)\\\\(22)(5)\\110[/tex]

This is the area of the pentagonal pyramid's base.  Now for the sides calculate the area of an individual side (triangle with base 8mm and height 6.9mm) then multiply by 5 for the area of all the sides:

[tex]\frac{1}{2}((b)(h)) (5)\\\\\frac{1}{2}((8)(6.9)) (5)\\\\\frac{1}{2}(55.2) (5)\\\\(27.6) (5)\\\\138\\[/tex]

For the total surface area of this shape add these values together for 110+138=248mm[tex]mm^{2}[/tex]

I hope that this helps :)

The type of triangle is an obtuse triangle.

Given that a triangle has side lengths of 7, 8, and 12.To classify the type of triangle, we have to check the Pythagorean theorem. As we know that the Pythagorean theorem states that "In a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

"Using this theorem, we will determine the type of triangle: Let's calculate the squares of the sides.7² = 49, 8² = 64, 12² = 144. According to the Pythagorean theorem, In the right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

(Hypotenuse)² = (Perpendicular)² + (Base)² = 49 + 64 = 113 Here, the hypotenuse is √113 ≈ 10.63.As 12² > 7² + 8² and 12² > 7² + 8², the triangle is an obtuse triangle. Thus, the type of triangle is an obtuse triangle.

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If m LM = 105°, then m KL = 75° because opposite angles in a parallelogram are congruent.

If m LA = 70°, then m KLA = 110° because consecutive angles in a parallelogram are supplementary. Therefore, m ALK = 70°.

If m LK = 120°, then m KAL = 60° because consecutive angles in a parallelogram are supplementary. Therefore, m ALM = 120°.

If XE = 12 cm and diagonals XL and EA bisect each other at O, then AO = OL = 6 cm because the diagonals of a parallelogram bisect each other.

Using the parallelogram law, AL² = AX² + XL² + 2(AX)(XL)cos(LAX), and since LAX is congruent to LEX, we have cos(LAX) = cos(LEX) = -1/2. Substituting the given values and solving for AL, we get AL = sqrt(421) cm.

If AX = 15 cm, then LX = EA = 15/2 = 7.5 cm because the diagonals of a parallelogram bisect each other. Using the Pythagorean theorem, we have LE² = LX² + XE² and substituting the given values, we get LE = sqrt(193.5) cm.

If XO = 5 cm, EO = 6 cm, and diagonals XL and EA bisect each other at O, then AO = OL = 5 cm and XL = EA = 2AO = 10 cm because the diagonals of a parallelogram bisect each other.

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Complete Question:

A. Find the measures of the other three angles of parallelogram MAKE if:

m LM = 105°

m LA = 70°

m LK = 120°

B. In parallelogram AXEL, diagonals XL and EA bisect each other at point O. Find:

The length of AL if XE = 12 cm

The length of LE if AX = 15 cm

The length of XL and EA if XO = 5 cm and EO = 6 cm.

If Beef costs $4.30 per pound and chicken costs $3.40 per pound then the three pounds of chicken costs $10.20.

The cost of chicken is $3.40 per pound. To find the cost of 3 pounds of chicken, we can multiply the price per pound by the number of pounds:

Cost of 3 pounds of chicken = 3 pounds × $3.40/pound

Cost of 3 pounds of chicken = $10.20

Therefore, the cost of 3 pounds of chicken is $10.20.

Cost refers to the amount of money, time, or resources that are required or expended in order to produce or acquire something. In business, cost is often associated with expenses or the monetary value of inputs such as labor, materials, and equipment that are used to produce goods or services. It can also refer to the price that a consumer pays to purchase a product or service. In general, cost is a measure of the sacrifice that is required to achieve a particular goal or outcome.

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The prοbability οf getting at least 1 red marble is 85/121.

In science, the prοbability οf an event is a number that indicates hοw likely the event is tο οccur. It is expressed as a number in the range frοm 0 and 1, οr, using percentage nοtatiοn, in the range frοm 0% tο 100%. The mοre likely it is that the event will οccur, the higher its prοbability.

The prοbability οf nοt getting a red marble in the first draw is 6/11. The prοbability οf nοt getting a red marble in the secοnd draw is alsο 6/11. Therefοre, the prοbability οf getting nο red marbles in twο draws is (6/11) x (6/11) = 36/121.

The prοbability οf getting at least οne red marble in twο draws is 1 - the prοbability οf getting nο red marbles. Sο, the prοbability οf getting at least οne red marble is: 1 - 36/121 = 85/121

Therefοre, the prοbability οf getting at least 1 red marble is 85/121.

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There are 2850 milliliters of milk left in the bottle after Clara poured 650 milliliters of milk from the bottle

Clara poured 650 milliliters of milk out of a bottle

The bottle originally held 3 1/2 litres of milk
Convert 3 1/2 to decimal

= 3 + 1/2

= 3 + 0.5

= 3.5

The first step is to convert the original volume to milliliters

Multiply the value in liters by 1000

= 3.5 × 1000

= 3500 milliliters

The next step is to subtract 650 from 3500

= 3500 - 650

= 2850

Hence the amount of milk left in the bottle is 2850 milliliters

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A. 43,200 can be written as multiple of a power of 10 as 4.32 x 10⁴.

B. 4,000 can be written as 4 x 10³

C. 2,800,000 can be written as 2.8 x 10⁶.

In mathematics, an expressiοn in pοwer refers tο a mathematical expressiοn that includes a base raised tο an expοnent. The base is the number οr variable being raised tο a pοwer, and the expοnent is the superscript number indicating hοw many times the base is being multiplied by itself.

Fοr example, in the expressiοn 2³, the base is 2 and the expοnent is 3. This means that we multiply 2 by itself 3 times, which gives us a value οf 8. Similarly, in the expressiοn x⁴, the base is x and the expοnent is 4. This means that we multiply x by itself 4 times, which gives us a value οf x multiplied by x multiplied by x multiplied by x.

Expressiοns in pοwer can be used in variοus mathematical οperatiοns, such as multiplicatiοn, divisiοn, additiοn, and subtractiοn . They are alsο cοmmοnly used in algebraic equatiοns and in scientific nοtatiοn tο represent very large οr very small numbers.

A. 43,200 can be written as 4.32 x 10⁴. This means that the number is equal to 4.32 times 10,000.

B. 4,000 can be written as 4 x 10³. This means that the number is equal to 4 times 1,000.

C. 2,800,000 can be written as 2.8 x 10⁶. This means that the number is equal to 2.8 times 1,000,000.

D. Five thousand can be written as 5 x 10³. This means that the number is equal to 5 times 1,000.

E. 60 million can be written as 6 x 10⁷. This means that the number is equal to 6 times 10,000,000.

F. 45 billion can be written as 4.5 x 10¹⁰. This means that the number is equal to 4.5 times 10,000,000,000.

G. 0.00000123 can be written as 1.23 x 10⁻⁶. This means that the number is equal to 1.23 divided by 1,000,000.

H. 0.00038 can be written as 3.8 x 10⁻⁴. This means that the number is equal to 3.8 divided by 10,000.

I. 0.002 can be written as 2 x 10⁻³. This means that the number is equal to 2 divided by 1,000.

In summary, by expressing each of these numbers as a multiple of a power of 10, we can better understand the magnitude of the number and compare it to other numbers more easily.

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Your complete question is :-

Write each expression as a multiple of a power of 10:

A 43,200

B 4,000

C. 2,800,000

D. Five thousand

E 60 million

F 45 billion

G. 0.00000123

H. 0.00038

I 0.002​

The amounts due on December 31, 2026 are: Bond payable (09/30/2026 installment) = $29,897,000, Bond payable (other than 09/30/2026 installment) = $90,313,578.19,Interest payable = $622,578.19

We can break down the problem into two parts: first, calculating the amount of bonds payable that are due on September 30, 2026 (the first installment), and second, calculating the amount of bonds payable and interest payable that are due on any other date.

Bond payable due on September 30, 2026:

The total amount of bonds payable outstanding is $119,588,000. The installment due on September 30, 2026 is $29,897,000. Therefore, the amount of bonds payable that is due on September 30, 2026 is:

$29,897,000

Bond payable and interest payable due on any other date:

The total amount of bonds payable outstanding is $119,588,000. The first installment of $29,897,000 is due on September 30, 2026, which leaves $89,691,000 of bonds payable outstanding.

The bonds pay 12% interest every September 30th, so we need to calculate the interest payable for the period from September 30, 2026 to any other date. Let's assume we want to calculate the bond payable and interest payable due on December 31, 2026 (the end of the year).

The period from September 30, 2026 to December 31, 2026 is 92 days (or 3 months). The annual interest rate is 12%, so the daily interest rate is:

12% / 365 = 0.0328767%

The interest payable for 92 days is therefore:

$89,691,000 x 0.0328767% x 92/365 = $622,578.19

Adding this to the outstanding bonds payable gives:

Bond payable (other than 09/30/2026 installment) = $89,691,000 + $622,578.19 = $90,313,578.19

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Assuming Janie's parents have AGI of $177,600, the American Opportunity Tax Credit that Janie's parents can claim for her is $2,500.

The American Opportunity Tax Credit (AOTC) is a tax credit that allows taxpayers to reduce their federal income tax liability for qualified education expenses paid for an eligible student.

To calculate the AOTC, the following formula can be used:

AOTC = 100% of the first $2,000 of qualified education expenses + 25% of the next $2,000 of qualified education expenses

The maximum amount of AOTC that can be claimed per eligible student is $2,500.

To determine the AOTC that Janie's parents can claim, we first need to calculate their Modified Adjusted Gross Income (MAGI). MAGI is calculated by adding certain deductions back to their AGI. Assuming they have no deductions, their MAGI would be the same as their AGI, which is $177,600.

Since the tuition and fees paid by Janie's parents ($11,100) are less than $4,000, they can claim the full AOTC of $2,500.

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Answer:2 hours 20 minutes

Step-by-step explanation:divide 60 by 3

Sorry, now you know that he spends 20 minutes a day combing his hair. You multiply 20 time 7( for the 7 days in a week) = 140. You want to convert minutes to hours and 2 hour is 120 minutes so the answer is 2 hours and 20 minutes

Answer: A) 20 minutes

              B)2 and 1/3 hours

Step-by-step explanation:

A) 1/3 of an hour is 20 minuets because 60÷3=20

   This means that 20 minutes are spent combing his hair each day

B) He spends 20 minutes combing his hair each day so 20×7=140

   140÷60=2 and 1/3 hours per week

Answer:

Increase both dimensions by 2 meters: (x+2)^2

Decrease both dimensions by 2 meters: (x-2)^2

Increase one dimension by 2 meters and decrease the other dimension by 2 meters: (x+2)(x-2)

Step-by-step explanation:

Answer:

d = 3h - 6

Step-by-step explanation:

h = d/3 + 2

Subtract 2 from both sides to isolate the term involving d:

h - 2 = d/3

Multiply both sides by 3 to eliminate the fraction:

3(h - 2) = d

Simplifying the right-hand side, we get:

d = 3h - 6

Therefore, the formula in terms of d is:

d = 3h - 6.

The relation between sine, cosine and tangent, along with the adjacent and opposite side lengths, is presented in this answer.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

The problem is incomplete, hence I identified the keywords and related them.

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The right response is: Because there is precisely one value of P for every value of z, the relationship is a function. The value that a function produces after accepting one or more input values is known as the output value of the function.

The right response is:

Because there is precisely one value of P for every value of z, the relationship is a function.

Each input value (in this case, z) in a function has a single related output value (P in this case). This requirement is met by the relation stated since there is exactly one value of P for each value of z.

The output value of a function given an input value x is denoted as f(x) in mathematical notation. This is the value that is obtained after applying the function to the input value.

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Answer:

y=10x+24

Step-by-step explanation:

y-4=10(x-(-2))

y-4=10(x+2)

y-4=10x+20

y=10x+24

Answer:

y= -2x

Step-by-step explanation:

m=y2-y1/x2-x1

m=-6-4/3-(-2)

m=-2

y= mx+q

y= -2x+q

-6= -2(3)+q

-6+6= q

q= 0

Therefore y= -2x

Answer:

y = 3x - 10

Step-by-step explanation:

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x is zero).

See the attached worksheet.  Let's calculate slope, m.  Slope is defined as the Rise/Run, or change in y over the change in x.  Assuming that the data are points on a straight line, we can pick any two points to determine slope.  Let's use (25,65) and (28,74).  See the worksheet.  The slope,m, is shown to be 3.  Now we can write:

  y = 3x + b

To find b, the y-intercept, we can use the above expression and substitue any of the given points for x and y, leaving b as the only unknown.  Let's use point (25.65):

 y = 3x + b

65 = 3*(25) + b      [for point (25,65)]

 65 = 75 + b

  b = - 10

The equation is therefore y = 3x - 10

(a) (65+5x)m², (b) 15+2+x+5+(15−x)+5+2=44m is the perimeter, (c) Rs.250(x+21) , (d) Rs.150(15−x) (e) 5x=35 ⇒x=7m

In an algebraic expression, variables are represented by letters or symbols, and constants are represented by numerical values. The variables can be used to represent unknown values that need to be solved for, while the constants provide fixed values.

Algebraic expressions are used extensively in algebra and other mathematical fields to represent relationships between variables and to solve equations.

(a)

length of bedroom =x m

Breadth of bedroom =5 m

And, length of kitchen =15−(x+2)=13−x m

Breadth of kitchen =5 m

So, Area of both kitchen and bedrooms =2× times of area of bedroom + area of kitchen

=2(5×x)+(13−x)×5

=10x+(65−5x)

=(65+5x)m²

(b)

From figure,

Perimeter of the living room

=15+2+x+5+(15−x)+5+2=44m

(c)

From figure,

Total area of both living the room and the bedrooms =(5×x)+(7×15)=(5x+105)m²

The cost of carpeting is Rs. 50/m²

Therefore, total cost of carpeting

=(5x+105)×50=Rs.250(x+21)

(d)

Total area, bathroom and kitchen

=(15−x)×5m²

The cost of tiling is Rs. 30/m²

Therefore, total cost of tilling

=(15−x)×5×30=Rs.150(15−x)

(e)

Given, Area of floor of each bedroom 35 m²

So, Area of one bedroom

=5xSq.m

∴5x=35

⇒x=7m

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After dilatiοn , the cοοrdinates are  J'(-2,2), K'(2,2) , L'(4,4) and  M'(0,4).

Resizing an item uses a transitiοn called dilatiοn. Dilatiοn is used tο enlarge οr cοntract the items. The result οf this transfοrmatiοn is an image with the same shape as the οriginal. Yet, there is a variatiοn in the shape's size. The initial shape shοuld be stretched οr cοntracted during a dilatatiοn. The phrase "scale factοr" describes this transitiοn.

Here the given vertices cοοrdinate οf the image is

J(-4,4) , K(4,4) , L(8,8) and M(0,8).

Scale factor = [tex]\frac{1}{2}[/tex]

If the coordinate (x,y) and scale factor k then dilation of coordinate is (kx,ky). Then,

=> J(-4,4) --> J'[tex](\frac{1}{2}\times -4,\frac{1}{2}\times 4)[/tex] = J'(-2,2).

=> K(4,4) --> K'[tex](\frac{1}{2}\times 4,\frac{1}{2}\times 4)[/tex] = K'(2,2)

=> L(8,8) --> L'[tex](\frac{1}{2}\times 8,\frac{1}{2}\times 8)[/tex] = L'(4,4)

=> M(0,8) --> M'[tex](\frac{1}{2}\times 0,\frac{1}{2}\times 8)[/tex] = M'(0,4).

Hence after dilation the coordinates are  J'(-2,2), K'(2,2) , L'(4,4) and  M'(0,4).

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The quantity of water in milliliters left in the water bottle after pouring 400 milliliters of water in glass is 4100 milliliters.

Milliliter is the smaller unit of quantity in the SI unit. One liter is equal to thousand times of one milliliter. It is given that the bottle contains 4.5 liters of water which means there is 4500 milliliters of water in it. Since Kevin pours 400 milliliters of water in the glass, this means 400 milliliters was emptied from the water bottle and hence the remaining amount can be calculated by subtracting the amount of water taken out from the bottle from the total amount.

Therefore the arithmetic equation will be as follows:

Amount of water left in bottle = Total quantity of water in the bottle - Water emptied out

Amount of water left in bottle = 4500 - 400 = 4100 milliliters

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Calculating the distance between locations C and D will provide us with the vector CD's magnitude, which we will then use to determine the vector CD's direction and magnitude. Thus, 5 miles in size, with a direction of roughly 53.13 degrees, is the CD.

The size and direction of a vector are two different sorts of information. A vector's length is measured by its magnitude, and its direction indicates its direction of travel. The most popular way to express vector direction is in degrees, though it can be expressed in other ways as well. Vector examples include acceleration and velocity. A vector's length is considered to be its magnitude.

The distance formula between the given two points (x1, y1) and (x2, y2) is:

d = √((x2 - x1)² + (y2 - y1)²)

Plugging in the values for points C and D, we get:

d = √((0 - (-4))² + (1 - 4)²)

= √(16 + 9)

= √(25)

= 5 miles

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Answer:

Area of white circle = 346.36 cm²

Step-by-step explanation:

Area of a circle = πr² where r is the radius

r = diameter/s

For the green circle, d = 42, r = 21

A = π(21)² = 1,385.44 cm²

The white circle has a diameter half of the green circle = 42/2 = 21 cm
So radius of white circle = 21/2 = 10.5 cm

Area of white circle = π (10.5)² = 346.36 cm²

We can use the tangent function to solve this problem. Let h be the height of the skyscraper.

First, we need to find the length of the adjacent side of the right triangle formed by Sadie, the base of the skyscraper, and the point where she is standing. This length is the horizontal distance between Sadie and the base of the skyscraper, which is 275 meters.

Next, we can use the tangent of the angle of elevation to find the ratio of the opposite side (the height of the skyscraper) to the adjacent side:

tan(36°) = h/275

Solving for h, we get:

h = 275 tan(36°)

Using a calculator, we find:

h ≈ 198.64 meters

Therefore, the height of the skyscraper is approximately 198.64 meters.

Answer: 201.49

Step-by-step explanation:

Answer:

1. 5√3

2. (25√3)/2

3. 21.65

Step-by-step explanation:

1. x = 10 * cos(30 degree) = 5√3

2. area = x * y = (10 * sin(30 degree)) * (10 * cos(30 degree)) = 25/2 * √3

3. Use calculator

Answer:

Use a calculator for you to get an answer

A triangle has three straight sides that meet at a point. The sides' lengths are adjustable, however the longest side's length cannot be longer than the sum of the lengths of the other two sides.

A triangle has three straight sides that meet at a point. The sides' lengths are adjustable, however the longest side's length cannot be longer than the sum of the lengths of the other two sides.

In the triangle ΔFUN,

∠F is an angle formed by the vertices F, U, and N.

∠U is an angle formed by the vertices F, U, and N.

The included sides of ∠F and ∠U are:

The included side of ∠F is UN.

The included side of ∠U is FN.

The included angles of ∠F and ∠U are:

Therefore, The included angle of ∠ F is ∠FUN, which is formed by the sides FU and UN. The included angle of ∠U is ∠NUF, which is formed by the sides NU and UF.

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Answer:

We can solve this system of equations using substitution or elimination.

Using substitution, we can solve for one variable in terms of the other in one equation and substitute that expression into the other equation. For example, we can solve the first equation for x in terms of y:

2x + 5y + 1 = 0

2x = -5y - 1

x = (-5/2)y - 1/2

Now we can substitute this expression for x into the second equation:

3x + 7y = 1

3((-5/2)y - 1/2) + 7y = 1

-15/2 y - 3/2 + 7y = 1

9.5y = 5

y = 5/9.5 = 1/1.9

Now we can substitute this value of y back into either equation to solve for x:

x = (-5/2)y - 1/2

x = (-5/2)(1/1.9) - 1/2

x = -2.632

So the solution to the system of equations is x = -2.632 and y = 1/1.9.

Answer: y < 5x+6

Step-by-step explanation:

The dividends per share on preferred stock for four years is $0.12, $0.12, $0.12, $0.12 and for common stock is $0.057, $0.152, $0.220, $0.220.

To calculate the dividends per share for each class of stock, we need to first determine the total dividends paid in each year.

For the preferred stock, the dividends are cumulative, which means any unpaid dividends from previous years must be paid before any dividends can be paid to common stockholders. Therefore, we need to calculate the total amount of unpaid dividends for each year before we can determine the amount available for common stockholders.

To calculate the unpaid dividends for the preferred stock in each year, we need to multiply the number of shares of preferred stock by the dividend rate (3%) and subtract the dividends paid in that year.

Unpaid dividends for preferred stock:

1st year: (80,000 x $20 x 0.03) - $33,000 = $9,600

2nd year: (80,000 x $20 x 0.03) - $72,000 - $9,600 = $9,600

3rd year: (80,000 x $20 x 0.03) - $100,000 - $9,600 = $9,600

4th year: (80,000 x $20 x 0.03) - $100,000 - $9,600 = $9,600

Now we can calculate the total dividends available for common stockholders in each year by subtracting the unpaid dividends for preferred stock from the total dividends paid in that year.

Total dividends available for common stockholders:

1st year: $33,000 - $9,600 = $23,400

2nd year: $72,000 - $9,600 = $62,400

3rd year: $100,000 - $9,600 = $90,400

4th year: $100,000 - $9,600 = $90,400

Finally, we can calculate the dividends per share for each class of stock by dividing the total dividends by the number of shares outstanding.

Dividends per share:

Preferred stock:

1st year: $9,600 / 80,000 = $0.12 per share

2nd year: $9,600 / 80,000 = $0.12 per share

3rd year: $9,600 / 80,000 = $0.12 per share

4th year: $9,600 / 80,000 = $0.12 per share

Common stock:

1st year: $23,400 / 410,000 = $0.057 per share

2nd year: $62,400 / 410,000 = $0.152 per share

3rd year: $90,400 / 410,000 = $0.220 per share

4th year: $90,400 / 410,000 = $0.220 per share

Therefore, the dividends per share on each class of stock for each of the four years are as follows:

Preferred stock (dividends per share)

1st Year: $0.12 per share

2nd Year: $0.12 per share

3rd Year: $0.12 per share

4th Year: $0.12 per share

Common stock (dividends per share)

1st Year: $0.057 per share

2nd Year: $0.152 per share

3rd Year: $0.220 per share

4th Year: $0.220 per share

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