( Mathematical sentences can describe real-world problems. Note the following inequalities and real-world problems. Write either the inequality or real-world problem that corresponds to the given information. Do not simplify any inequalities.
(a) Real-World Problem: Toy cars cost c dollars. Stan had $3. He purchased 3 toy cars with his money. Frank had $6. He purchased 8 toy cars with his money. After their purchases, Stan had more money than Frank

Inequality:

(b) Inequality: 3x + 2 < 2x + 10

Real-World Problem: ​

Answer: 6, 21, 3

Step-by-step explanation:

2:7:1

Also, 2x 7x and 1x or just x

2x+7x+x = 30

10x = 30

x=3

So the three numbers: 2(3):7(3):1(3) OR 6:21:3

Answer:

Step-by-step explanation:

-8x-y=16;3x-y=5 | | x-y=11;2x+y=4 | | -8x-8=-40y;50y-10=10x | | 0=-11y+8x+33;-1+4/9x+1/3y=0 | | 0=-16+4x+4y;0=28-7y+7x | | 3x-y=9;-3x+y=-9 | | -4x+y=8;4x-y=8 | | x=2y-8;-2x+3y=14 | | y=2x;y=2x-3 | | x-3y=2;7x+y=36 | | 2x+5y=16;2x+3y=8 | | 2c+5p=16;2c+3p=8 | | x/5;7/4 | | -(x-2)=3(y+1);2x+3=4y-1 | | 4x-12y=17;2x+6y=1 | | 1A+4C=85;3A+2C=105 | | 2x-11y=7;3x-9y=7 | | 40-2x;X=3 | | x+y=220;2x+4y=520 | | 3p+2b=29;5p+3b=47.50 | | 4x+2y=23.50;2x+4y=18.50 | | t=2r+3;5r-4t=6 | | x+y=5157.50;y-x=917.50 | | x+y=177;x=97 | | x+y=55;x+10=181 | | x+y=10;x-y=4 | | 1/5x+1/3y=14/15;1/5x+4y=78/5 | | 8x+16y=3520;-8x-8y=2560 | | 1/25x-1/100y=7/5;1/4x+4/25y=66/5 | | -2x+5y=5;-4x+10y=0 | | 1/2x+1/3y=-5/3;1/2x+4y=2 |

| 3x+2y=-3;x=21-8y | | 5x-y=27;x+y=9 | | 36x-4y=16;y=9x+4 | | -15x-10y=1;15y=1+10x | | 3x+7y=9;x=2-2y | | 2x+y=8;y=2x | | x-2y=10;x | | x+y=2;x-y=2 | | 7x-y=27;9x-4y=3 | | x+y=480;x-y=400 | | 3x+2y=78.39;2x+3y=74.61 | | 11x+15y=6912;-11x-11y=-6336 | | 1.6x+1.6y=160;x-y=10 | | y=-1/2x-5;6x-2y=24 | | x+y=4;y-x=4 | | 5x=22-y;7x=35+2y | | 3x=12+2y;-6/5x+y=-9/5 | | 3x+2y=0;12x+2=6y | | 2x-5y=-9;5x+2y=50 | | x+y=4;x+y=-2 | | 7x-y=41;x+5y=47 | | 2x-y=7;9y=2x-31 | | x+y=11;6x-y=10 | | 0.1x+0.5y=-0.8;0.8x-0.6y=7.4 | | 1/3x+1/2y=1/6;1/3x+2y=5/3 | | 16x-10y=4;8x=5y+2 | | 15x-20y=7;10y=-3+5x | | x=5y-5;-2x+10y=10 | | 5x-27=-y;4x-y=0 | | 5x-27=-1y;4x-1y=0 | | 4x+5y=3;x=3-2y | | 6x+2y=10;12x+4y=21 | | x+y=5;3x+2y=10 | | -12x+14z=-14;-14x-14z=98 |

Answer:

Step-by-step explanation:

H

Answer:

55860

Step-by-step explanation:

This way super dupper easy

Answer:

V is approximately 11.81

Step-by-step explanation:

We use the sine rule

V/sin 98 = 10/sin 57

Cross multiply

V * sin 57 = 9.90268068

V = 9.90268068/sin 57

V= 11.80759295

V ~ 11.81

Answer:

[tex] \huge \frac{7}{8} \\ [/tex]

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

[tex]m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\[/tex]

From the question we have

[tex]m = \frac{ - 9 - - 2}{ - 10 - - 2} = \frac{ - 9 + 2}{ - 10 + 2} = \frac{ - 7}{ - 8} = \frac{7}{8} \\ [/tex]

We have the final answer as

[tex] \frac{7}{8} \\ [/tex]

Hope this helps you

Answer:

7/8

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

4.7

Step-by-step explanation:

Answer:

if you are on the exam on A PE X, the answer is 9/10

Step-by-step explanation:

hope this helps!!  

:)

Answer:

[tex] \big \: slope = - 3[/tex]

Step-by-step explanation:

[tex] \boxed {slope = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} }[/tex]

HERE,

[tex]slope = \frac{( - 6) - 3}{( - 1) - ( - 4)} [/tex]

[tex] = \frac{ - 9}{3} [/tex]

[tex] = - 3[/tex]

Therefore,

[tex] \green{\boxed { \red{ \bold{slope \: = - 3}}}}[/tex]

Answer:

?

Step-by-step explanation:

Answer:

r+2t

Step-by-step explanation:

hope this helps :)

Answer: 402

Step-by-step explanation:

165 + 237 = j

Answer:

165+237= 402

Step-by-step explanation:

in one week he did 165 and in the second week he did 237, so you add them together to get the total.

equation: j= 165 + 237

Answer:

c. y = 2x + 4

Step-by-step explanation:

Hope you got it.

I think it's ''4 4/5"..

Answer:

The discounted price would be 16290 as 18100 times 10 over 100 is 1810 so subtract that from 18100 and you get 16290

Step-by-step explanation:

Also if you could please check out our you tube channel called  Evimero Academy

Answer:

Yes, they are congruent. Theorem: SSS

Step-by-step explanation:

The triangles are congruent because it is given that they have 2 sides that are the same (hence the matching tick marks). In the diagram, you can also see that they share a side. Since all three sides on both triangles are the same, the two triangles are congruent by the SSS theorem.

Answer: Yes they are congruent, By SSS

Step-by-step explanation:

2 sides are marked as congruent, and the 3rd side is congruent to itself by the reflexive property of equality.

Answer:

well 5% of 600 is 30. so if you make 600 phone calls and an average of 5% of those calls are people signing up, then that would be 30.

Answer:

The alternative hypothesis is

      [tex]H_a : p_1 \ne \ p_2[/tex]

The rejection region is the region outside the interval

         [tex]-1.96 < z_{critical} < 1.96[/tex]

Step-by-step explanation:

From the question we are told that

    The significance level is  [tex]\alpha = 0.05[/tex]

     The null hypothesis is  [tex]H_o : p_1 = p_2[/tex]

      The  alternative hypothesis is  [tex]H_a : p_1 \ne \ p_2[/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Hence the rejection region is the region outside the interval [tex]-1.96 < z_{critical} < 1.96[/tex]

The alternative hypothesis is, [tex]H _a; \ P_1\neq P_2[/tex] .

And the rejection region is the region outside the interval is [tex]-1.96< Z_c_r_i_t_i_c_a_l <1.96[/tex] .

Given that,

If the decision is to reject the null hypothesis of no difference between two population proportions at the 5% level of significance.

We have to determine,

What is the alternative hypothesis and rejection region?

According to the question,

The significance level is,  [tex]\alpha = 5 \ percent = 0.05[/tex]

The null hypothesis is [tex]H_0 ; P_1 = P_2[/tex]

The alternative hypothesis is, [tex]H _a; \ P_1\neq P_2[/tex]

In the normal distribution table, the critical value [tex]\dfrac{\alpha}{2}[/tex] is,

[tex]Z _\frac{\alpha}{2} = 1.96[/tex]

Hence, the rejection region is the region outside the interval is [tex]-1.96< Z_c_r_i_t_i_c_a_l <1.96[/tex] .

To know more about the Hypothesis click the link given below.

https://brainly.com/question/21620502

Answer:

n

Step-by-step explanation:

Answer:A

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

Answer:

1)y=20-6=14

2)X=12+10=22

3)answer stated

4)n=14

5)10

6)15

7)26

8)15

9)80

10)stated

11)35

12)4

13)45

14)12

15)50

1. y + 6 = 20

subtract 6 from both sides

y = 14

2. x - 10 = 12

add 10 to both sides

x = 22

3. 12 + 2 = 15

false

4. 2 + n = 16

subtract 2 from both sides

n = 14

5. a + 4 = 14

subtract 4 from both sides

a = 10

6. m - 5 = 10

add 5 to both sides

m = 15

7. 4 + b = 30

subtract 4 from both sides

b = 26

8. 10 + c = 25

subtract 10 from both sides

c = 15

9. x - 60 = 20

add 60 to both sides

x = 80

10. 9 - 16 = 4

false

11. x - 15 = 20

add 15 to both sides

x = 35

12. w + 14 = 18

subtract 14 from both sides

w = 4

13. r - 18 = 27

add 18 to both sides

r = 45

14. 13 + k = 25

subtract 13 from both sides

k = 12

15. f - 16 = 34

add 16 to both sides

f = 50

I think you had some typos in there but I think this should get you started, you should be able to figure out the rest

Answer:

The one with u-o, u, u+2o

Step-by-step explanation:

Answer:

gh = x+9

Step-by-step explanation:

Answer:

0.0250047

Step-by-step explanation:

Given that :

Proportion who need correction glasses = 70%

Number of trials = 7

Probability that exactly 2 needs correction glasses :

Using a binomial probability formula :

P(success) = p = proportion who need glasses = 0.7

P(x =x) = nCr * p^x * (1 - p)^(n - x)

P(x = 2) = 7C2 * 0.7^2 * 0.3^(7 - 2)

P(x = 2) = 7C2 * 0.7^2 * 0.3^5

P(x = 2) = 21 * 0.49 * 0.00243

P(x = 2) = 0.0250047