Solution
For this case we can do the following:
2. Part of lines FE and AB
4. Transitive
1. Given
5. Definition of parallelogram
3. Opposite sides of a parallelogram are II
Bob buys a vase for $15 and spends $2 per flower.
4) Write an equation to represent the cost of buying flowers.
If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x
The cost of flower vase = $15
The cost of each flower = $2
Consider the number of flowers as x
Then the linear equation that represents the cost of buying flowers = The cost of flower vase + The cost of each flower × x
Substitute the values in the equation
The equation that represents the cost of buying flowers = 15+2x
Hence, If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x
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Use (60° - 45°) = 15° to find the exact value of cos 15º.vaV2 + V6V-V6(b)(c)4(d)4+ V62
Answer;
[tex]B\text{. }\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]Explanation;
Given that;
[tex](60^0-45^0)=15^0[/tex]Hence;
[tex]\text{Cos 15}^0=Cos(60^0-45^0)[/tex]According to trigonometry identity;
[tex]\begin{gathered} Cos(60^0-45^0\text{) = Cos60 Cos45 + Sin60Sin45} \\ Cos(60^0-45^0\text{) }=\frac{1}{2}(\frac{1}{\sqrt[]{2}})+\frac{\sqrt[]{3}}{2}(\frac{1}{\sqrt[]{2}}) \end{gathered}[/tex]Evaluate the result by finding the LCM
[tex]Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}[/tex]Rationalize;
[tex]\begin{gathered} Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}\times\frac{\sqrt[]{2}}{\sqrt[]{2}} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}(1+\sqrt[]{3})}{2\cdot2} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}+\sqrt[]{6}}{4} \end{gathered}[/tex]Hence the required reusult is;
[tex]\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]If mZABD = 70°, what are mZABC and mZDBC?
mZABC=
mZDBC=
(6x+3) D
B
(9x-8)
Please help me
Answer:
Step-by-step explanation:
ABD = ABC + DBC
Eqivalent to:
78 = (5x + 3) + (5x - 5)
78 = 5x + 5x + 3 - 5
78 = 10x - 2
80 = 10x (move -2 to the left side and get 78 + 2 = 80)
8 = x (80/10 = 8)
With x = 8,
ABC = 5x - 5 = 8*5 - 5 = 40 - 5 = 35
DBC = 5x +3 = 8*5 + 3 = 40 + 3 = 43
1. The population of Whatville is given by the y=83,000(1.04) where x is the years since 2010.a) What was the population in 2010?b) What is the population in 2020?c) When will the population reach 100,000? Show your work.
ANSWER:
a) 83,000 people
b) 122,860 people
c) 4.75 years
STEP-BY-STEP EXPLANATION:
We have that the population given by the following equation:
[tex]y=83000\cdot\mleft(1.04\mright)^x[/tex]a) What was the population in 2010?
Since no year has passed, the value of x would be 0.
Replacing:
[tex]\begin{gathered} y=83000\cdot(1.04)^0 \\ y=83000 \end{gathered}[/tex]The population in 2010 is 83,000 people
b) What is the population in 2020?
From 2010 to 2020 10 years have passed, therefore the value of x is 10
[tex]\begin{gathered} y=83000\cdot(1.04)^{10} \\ y=122860 \end{gathered}[/tex]The population in 2020 is 122,860 people
c) When will the population reach 100,000?
Since the population is 100,000 people, it is the value of y, therefore we must solve and calculate the value of x
[tex]\begin{gathered} 100000=83000\cdot\mleft(1.04\mright)^x \\ 1.04^x=\frac{100000}{83000} \\ \ln 1.04^x=\ln \frac{100}{83} \\ x\cdot\ln 1.04=\ln \frac{100}{83} \\ x=\frac{\ln \frac{100}{83}}{\ln 1.04} \\ x=4.75 \end{gathered}[/tex]Which means that for the population to be 100,000 people, 4.75 years would have to pass
The bases of the prism below are rectangles. If the prism's height measures 3 units and its volume is 198 units^3. solve for x
The volume of a rectangular prism is given by
V=L*W*H
where
V=198 units3
L=6 units
W=x units
H=3 units
substitute given values
198=(6)*(x)*(3)
solve for x
198=18x
x=198/18
x=11 unitsEach parking spot is 8 feet wide. A parking lot has 24 parking spots side by side. What is the width (measured in yards) of the parking lot? The shorter tree is
The width would be: 8ft*24 = 192 ft
Then, we have to convert the unit from ft to yards. Doing so,we have:
[tex]192ft\cdot\frac{1\text{ yard}}{3\text{ ft}}=64\text{ yards (Multiplying and dividing)}[/tex]The answer is 64 yards
Witch phrase best describes the position of the opposite of +4
To find the position that is opposite to +4, we need to consider 0 as a "mirror point", then we check which point has the same distance to 0 as the distance from +4 to 0:
The position which is opposite to +4 is the position -4.
This position is 4 units to the left of 0 and 8 units to the left of +4.
Looking at the options, the correct option is the second one.
HELP ASAP
What is the size of the smallest angle in Triangle A? Give your answer correct to one
decimal place. Show your calculations.
Answer:
A is an included angle between 3 and 5
NO LINKS!! Please help me with this probability question 3a
Answer:
b) 26%
Step-by-step explanation:
If a continuous random variable X is normally distributed with mean μ and variance σ², it is written as:
[tex]\large\boxed{X \sim\text{N}(\mu,\sigma^2)}[/tex]
Given:
[tex]\textsf{Mean}\;\mu=3550[/tex]
[tex]\textsf{Standard deviation}\:\sigma=870[/tex]
Therefore, if the weights of the cars passing over the bridge are normally distributed:
[tex]\boxed{X \sim\text{N}(3550,870^2)}[/tex]
where X is the weight of the car.
To find the approximate probability that the weight of a randomly-selected car passing over the bridge is less than 3000 pounds, find[tex]\text{P}(X < 3000)[/tex].
Calculator input for "normal cumulative distribution function (cdf)":
Upper bound: x = 3000Lower bound: x = –9999...μ = 3550σ = 870[tex]\implies \text{P}=0.2636333503[/tex]
[tex]\implies \text{P}=26\%[/tex]
Therefore, the approximate probability that the weight of a randomly-selected car passing over the bridge is less than 3000 pounds is 26%.
Which tool would be best to solve this problem?Pythagorean TheoremTriangle Angle Sum TheoremTangent RatioSine RatioCosine RatioUse that tool to solve for x. Show all work on the sketchpad or on your paper.
To get the value of x,
We use triangle sum theorem:
Triangle Sum Theorem:
The sum of all angles in a triangle is equal to 180 degrees.
In the triangle
We have 90 degree, 22 degree and one x
So,
x + 90 + 22 =180
x + 112 = 180
x = 180-112
x = 68 degree
Answer: x = 68
Rewrite the expression in lowest terms.
4x²-12x +9
________
4x2-9
A. -12 x
B. 4x-3
2x-3
C. 2x+3
2x-3
D. 2x-3
2x+3
answer is D
no real explanation its just math
The table represents the amount of money in a bank account each month. Month Balance ($) 1 2,215.25 2 2,089.75 3 1,964.25 4 1,838.75 5 1,713.25 What type of function represents the bank account as a function of time? Justify your answer.
The type of function that represents the bank account as a function of time is a linear function
How to determine the type of function?The table of values is given as
Month Balance ($)
1 2,215.25
2 2,089.75
3 1,964.25
4 1,838.75
5 1,713.25
From the above table of values, we can see that;
The balance in the bank account reduces each month by $125.5
This difference is calculated by subtracting the current balance from the previous balance
So, we have
Difference = 1,838.75 - 1713.25 =125.5
Difference = 1,964.25 - 1,838.75 =125.5
Difference = 2,089.75 - 1,964.25 =125.5
Difference = 2,215.25 - 2,089.75 =125.5
Functions that have a common difference are linear functions
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Answer:
It's not D I can tell you that but ig just go with the other guy's answer
Step-by-step explanation:
Mr. Edmonds is packing school lunches for a field trip for the 6th graders of Apollo Middle school. He has 50 apples and 40 bananas chips. Each group of students will be given one bag containing all of their lunches for the day. Mr. Edmonds wants to put the same number of apples and the same number of bananas in each bag of lunches. What is the greatest number of bags of lunches Mr.Edmonds can make? How many apples and bananas will be in each bag?
Solve the right triangle. Write your answers in simplified, rationalized form. DO NOT ROUND!
base = FG = root 30
perpendicular HG = x
angle = 45 degrees,
we know that
[tex]\text{tan}\theta=\frac{perpendicualr}{base}[/tex][tex]\tan 45=\frac{HG}{\sqrt[]{3}}[/tex][tex]\begin{gathered} 1=\frac{HG}{\sqrt[]{3}} \\ HG=\sqrt[]{3} \end{gathered}[/tex]so, the value of HG = root 3
(x+?)(x+3)=x squared+5x+6
The given expression is :
(x + ) (x + 3) = x² + 5x + 6
The polynomial is factorize and then written in the form of (x + ) (x + 3)
Let the missing number is "b" substitute in the equation and simplify :
(x + b ) (x + 3) = x² + 5x + 6
x² +bx + 3x + 3b = x² + 5x + 6
x² +x(b +3) + 3b = x² + 5x + 6
Comparing the constant term together :
3b = 6
Divide both side by 3
3b/3 = 6/3
b = 2
Since b is the missing term so, Missing term is 2
(x + 2 ) (x + 3) = x² + 5x + 6
Answer :(x + 2 ) (x + 3) = x² + 5x + 6
Write an equation or inequality and solve:32 is at most the quotient of a number g and 8
The quotient of a number g and 8 can be written as:
[tex]\frac{g}{8}[/tex]Since it is given that 32 is at most( this quotient, then it follows that:
[tex]32\le\frac{g}{8}[/tex]Next, solve the resulting inequality:
[tex]\begin{gathered} 32\le\frac{g}{8} \\ \text{Swap the sides of the inequality and change the sign:} \\ \frac{g}{8}\ge32 \end{gathered}[/tex]Multiply both sides of the inequality by 8. Note that the sign will not change since you are multiplying a positive number:
[tex]\begin{gathered} \Rightarrow8\times\frac{g}{8}\ge8\times32 \\ \Rightarrow g\ge256 \end{gathered}[/tex]Hence, the inequality is:
[tex]32\le\frac{g}{8}[/tex]The solution is:
[tex]g\ge256[/tex]Harriet found the number of At-Bats (AB) using the formula below
Here, we want to get what should have been written as step 1
As we can see from what is presented, she went directly to step 2 without writing out the individual product and summing them
So, we have the step 1 correctly written as;
[tex]0.520\text{ = }\frac{(28)\text{ + (94) +(3) + 240}}{AB}[/tex]Which is the image of vertex K after the parallelogram is rotated 180degrees about the origin?
Answer:
The image of vertex K is (3,-2)
Step-by-step explanation:
Rotated 180 degrees about the origin means that the value of x will not change, while y will have the same distance from the origin, but in a different direction.
Vertex K:
Value of x: x = 3
Value of y: y = 2
Distance from the origin: 2 - 0 = 2
Rotated, new coordinate: 0 - 2 = -2
The image of vertex K is (3,-2)
Find the measure of the indicated amgle to the nearest degree.
The correct option is
C. 69 degrees
Explanation:Let the indicated angle be represented by x, then
[tex]\begin{gathered} \cos x=\frac{Adjacent}{Hypotenuse}=\frac{13}{36} \\ \\ \\ x=\cos^{-1}(\frac{13}{36})\approx69^o \end{gathered}[/tex]The length is twice the sum of its width 3. What are the dimension of the rectangle if it’s area 216 square inches?
Assume that the width of the rectangle = x
Since the length is twice the sum of the width and 3, then
[tex]\begin{gathered} L=2(x+3) \\ L=2x+6 \end{gathered}[/tex]Since the area of the rectangle is 216 square inches, then
Multiply the length and the width, then equate the product by 216
[tex]\begin{gathered} (x)(2x+6)=216 \\ 2x^2+6x=216 \end{gathered}[/tex]Divide all terms by 2 to simplify
[tex]\begin{gathered} \frac{2x^2}{2}+\frac{6x}{2}=\frac{216}{2} \\ x^2+3x=108 \end{gathered}[/tex]Subtract 108 from both sides
[tex]\begin{gathered} x^2+3x-108=108-108 \\ x^2+3x-108=0 \end{gathered}[/tex]Now, let us factorize the trinomial into 2 factors
[tex]\begin{gathered} x^2=(x)(x) \\ -108=(-9)(12) \\ (x)(-9)+(x)(12)=-9x+12x=3x \end{gathered}[/tex]Then the factors are
[tex]x^2+3x-108=^{}(x-9)(x+12)[/tex]Equate them by 0
[tex](x-9)(x+12)=0[/tex]Equate each factor by 0, then find the values of x
[tex]x-9=0[/tex]Add 9 to both sides
[tex]\begin{gathered} x-9+9=0+9 \\ x=9 \end{gathered}[/tex][tex]x+12=0[/tex]Subtract 12 from both sides
[tex]\begin{gathered} x+12-12=0-12 \\ x=-12 \end{gathered}[/tex]Since the width can not be a negative number (no negative length)
Then the width of the rectangle = 9
Let us find the length
[tex]\begin{gathered} L=2(9)+6 \\ L=18+6 \\ L=24 \end{gathered}[/tex]Then the dimensions of the rectangle are 9 inches and 24 inches
how far a hawk can fly in 15 days
Answer : 1500 miles
According to the distance time relationship
Distance = Rate x time
From the figure given, the hawk flies 500 miles in 5 days
We can find our rate using the above parameters
Since, distance = rate x time
Rate = distance / time
Rate = 500 / 5
Rate = 100 miles / day
Since, the rate remains constant
How far the hawk can fly in 15 days can be calculated as follows
Time = 15 days
Rate = 100
Distance = ?
Disatnce = rate x time
Distance = 100 x 15
Distance = 1500 miles
The Hawk can fly 1500 miles in 15 days
A line's slope is -5. The line passes through the point (5, 30). Find an equation for this line in both point-slope and slope-intercept form A) An equation for this line in point-slope form is:B) An equation for this line in slope-intercept form is.
Answer:
y - 30 = 5(x - 5) (point slope form)
slope intercept form is y = 5x+5
Explanation:
Given the following
Slope m = -5
Point = (5, 30)
x0 = 5 and y= = 30
The equation of the line in point slope form is expressed as y-y0 = m(x-x0)
Substitute
y - 30 = -5(x - 5) (point slope form)
Express in slope intercept form (y = mx+c)
y - 30 = -5x + 25
y = -5x + 25 + 30
y = -5x + 55
Hence the equation of the line in slope intercept form is y = -5x+55
What is the y intercept of this equation10x+5y=30Write answer in (x,y)
The y intercept of a straight line is the point on the y axis where the line cuts the y axis.
Given equation of lineis
[tex]10x+5y=30[/tex]Putting x=0 in the above equation, we have,
[tex]\begin{gathered} 5y=30 \\ y=6 \end{gathered}[/tex]So, the y intercept is
[tex](0,6)[/tex]I need help with this and it is delivered at 3:30 pm and sadly I did not understand almost anything and I am confused.Problem 1
Reflection across the y-axis transforms the point (x,y) into (-x, y)
Applying this rule to points A, B, and C, we get:
A(-5, 6) → A'(5, 6)
B(3, 6) → B'(-3, 6)
C(-3, 2) → C'(3, 2)
Given that figure ABC was reflected, then figure A'B'C' is congruent with figure ABC
The graph shows the proportional relationship between the number of gems collected and the number of levels that have been completed in a video game.
Graph with x axis labeled game levels and y axis labeled gems collected. A line begins at 0 comma 0 and goes through points 6 comma 420 and 8 comma 560.
Determine the constant of proportionality for the relationship.
p = 70
p = 140
p equals 2 over 140
p = 0.0143
Answer: P = 70
Step-by-step explanation:
p = 70 because on the graph everytime the y number is the x number multiplied by 70.
70 x 2 = 140
70 x 4 = 280
70 x 6 = 420
70 x 8 = 560
70 x 10 = 700.
Heres the chart for proof
The constant of proportionality (p) for this proportional relationship is equal to: A. p = 70.
How to determine the constant of proportionality?In Mathematics, the graph of any proportional relationship is characterized by a straight line because as the values on the x-axis increases or decreases, the values on the y-axis increases or decreases simultaneously.
Mathematically, a proportional relationship can be represented by the following equation:
y = px
Where:
p is the constant of proportionality.y represents the gems collected.x represents the game levels.Next, we would determine the constant of proportionality (p) for the data points on this graph as follows:
p = y/x
p = 420/6 = 560/8
p = 70.
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A circle Is cut from a square piece of cloth as shown How many square inches of cloth are cut from the square 1,061.32in22,122.64in22,704.00in23,622.31in2
Answer: 2,122.64in².
Explanation
We want to know the measure of the circle in square inches, meaning that we have to calculate the area.
The area of a circle (A) is given by:
[tex]A=\pi r^2[/tex]where r represents the radius of the circle.
The diameter of the circle is a straight line that goes from one point of the circumference of a circle to an opposite point, passing through the center of the circle. The radius is half the diameter.
Based on the image, we can see that the circle is cut touching one point of each side of the square, meaning the diameter is what the side of the square measures:
Then, if the diameter is 52", then the radius is half that, 26".
Now, we can calculate the area:
[tex]A=\pi\cdot26^2[/tex][tex]A=3.14\cdot676[/tex][tex]A=2122.64in^2[/tex]For these problems, please show your algebraic work using logarithms. 1. Determine the doubling time for each situation listed below. a. A population is growing according to P = P_0e^0.2t b. A bank account is growing by 2.7% each year compounded annually.
Answer: We need to find the doubling time for population growth:
Population growth is given by
[tex]P=P_oe^{(0.2)t}[/tex]Where:
[tex]\begin{gathered} P\rightarrow\text{final} \\ P_o\rightarrow I\text{nitial} \end{gathered}[/tex]For the population to double, it implies that:
[tex]P=2P_o[/tex]Therefore:
[tex]\frac{P}{P_o}=\frac{2P_o}{P_o}=2=e^{(0.2)t}[/tex]Solving for time "t" gives:
[tex]2=e^{(0.2)t}\rightarrow\ln (2)=(0.2)t\rightarrow t=\frac{\ln (2)}{(0.2)}=3.46u[/tex]The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges to rent trucks plus an additional fee of for each ton of sugar. The second company charges to rent trucks plus an additional fee of for each ton of sugar.For what amount of sugar do the two companies charge the same? What is the cost when the two companies charge the same?
step 1
Find the equation of the line First Company
y=100.25x+6,500
where
y is the total charge
x is the number of ton of sugar
Second Company
y=225.75x+4,492
Part a)
Equate both equations
100.25x+6.500=225.75x+4,492
solve for x
225.75x-100.25x=6,500-4,492
125.50x=2,008
x=16
answer part a is 16 tonPart b) For x=16 ton
substitute the value of x in any of the two equations (the result is the same)
y=100.25(16)+6,500
y=$8,104
answer Part b is $8,104What is the slope: (-2, 1) (5,-2)
Answer: slope = -3/7
Step-by-step explanation:
m(slope) = (y2-y1)/(x2-x1)
m = (-2+-1)/(5--2)
m = (-2-1)/5+2)
m = -3/7
Simplify by writing the expression with positive exponents. Assume that all variables represent nonzero real numbers
Explanation
Let's remember some properties ofthe fractions ans exponents,
[tex]\begin{gathered} a^{-n}=\frac{1}{a^n} \\ (\frac{a}{b})^n=\frac{a^n}{b^n} \\ (ab)^n=a^nb^n \\ (a^n)^m=a^{m\cdot n} \end{gathered}[/tex]so
Step 1
[tex]\lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2[/tex]reduce by using the properties
[tex]\begin{gathered} \lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2 \\ \lbrack\frac{4q}{3^{-1}m^3p^2}\rbrack^2 \\ \lbrack\frac{3^1\cdot4q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{12q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{144q^2}{m^{3\cdot2}p^{2\cdot2}}\rbrack^{} \\ \lbrack\frac{144q^2}{m^6p^4}\rbrack^{} \end{gathered}[/tex]therefore, the answer is
[tex]\lbrack\frac{144q^2}{m^6p^4}\rbrack^{}[/tex]I hope this helps you