MARKING BRAINLIEST PLZ HELP! You are given the following five lines:
Line 1: y=-2x + 9
Line 2: y= 1/2x + 1
Line 3: y= 2x + 2
Line 4: 6x - 3y = 6
Line 5: 4x + 2y = 4

Part A: Which two lines could be used to create a system of equations that has no solution? Explain your answer

Part B: Which two lines could be used to create a system of equations that has many solutions? Explain your answer

Part C: Which two lines could be used to create a system of equations that has one solution? Explain your answer​

Answer:

32

Step-by-step explanation:

QC = 16 and CS = 16 so 16 + 16 = 32

Answer:

23º = x

Step-by-step explanation:

One straight line is ALWAYS 180º

(called a linear pair)

So your equation is

157º + x = 180

subtract x on both sides

and you get

23º

That is a question about angles.

The first thing that we should to note is that a line do a straight angle. A straight angle is an 180° angle.

So, we can say that the sum of the angle a and the angle of 157° is equal to a straight angle. Let's make and solve a equation:

[tex]a + 157 = 180\\a = 180 - 57\\a = 23[/tex]

Therefore, the missing angle is 23°.

I hope I've helped. :D

Enjoy your studies. \o/

Answer:

b.angle 5 and angle 4

Step-by-step explanation:

b.angle 5 and angle 4

Answer:

Step-by-step explanation:

Answer:

adding both equations

4x+9y=5

-4x+7y=11

+ + =+

________

0 +16y=16

y=1

putting the value of y in first eqn

4x+9×1=5

4x=5-9

4x=-4

x=-1

so the x is -1 and y is 1

Answer:

..

Step-by-step explanation:

Answer:

Done! I already sent you the answer.

Step-by-step explanation:

By applying the definition of logarithm, you have

\log_x(64) = 3 \iff x^3 = 64logx(64)=3⟺x3=64

So, if you consider the cubic root of both sides, you have

x = \sqrt[3]{64} = 4x=364=4

Answer:

x

=

4

,

−

2

+

2

i

√

3

,

−

2

−

2

i

√

3

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

The difference between their volumes is [tex]237.375ft^3[/tex]

Step-by-step explanation:

The attachment completes the question.

For cube 1:

[tex]s_1 = 8ft[/tex]

For cube 2:

[tex]s_2 = 6.5ft[/tex]

Required

The difference in their volumes

First, we calculate the volume of box 1

[tex]V_1 = s_1^3[/tex]

Substitute 8 for s1

[tex]V_1 = 8^3[/tex]

[tex]V_1 = 512ft^3[/tex]

Next, we calculate the volume of box 2

[tex]V_2 = s_2^3[/tex]

Substitute 6.5 for s2

[tex]V_2 = 6.5^3[/tex]

[tex]V_2 = 274.625ft^3[/tex]

The difference is then calculated as:

[tex]Difference = |V_1- V_2|[/tex]

[tex]Difference = |274.625- 512|[/tex]

[tex]Difference = |-237.375|[/tex]

[tex]Difference = 237.375[/tex]

Hence, the difference between their volumes is [tex]237.375ft^3[/tex]

Answer:

I didn't receive enough information about this, but I hope this helps?

Step-by-step explanation:

A 50%?

B 50%?

This problem needs more information.  :3

Answer:

No

Step-by-step explanation:

3x-5= 4+2x

Or, x=4+5

x=9

Answer:

A.)x=6

B.)x=16

did u mean to solve it or do something else if this is not the way u mean i can do another way if u like

Answer:

+16

Step-by-step explanation:

It’s adding 16 every time

Answer:

The value for X is 25

Step-by-step explanation:

I hope this helps you out!

Answer:

150

Step-by-step explanation:

Answer:

a) Math and Dance

b) 3 students (Chau, Juan, Ivan)

c) Tome, Jose, Josh, Rita

Step-by-step explanation:

That was so easy homework :-) write in comments if it helped

Step-by-step explanation:

3.75x-5-8.75x+4.5+0.5

=3.75x-8.75x+4.5+0.5-5

=-5x+5-5

==-5x

Answer:

1×1÷11. 5×3=15. 7×7=49 3×5=15 I'm not really sure but is there's anything else

Answer:

I believe it is 8in

Step-by-step explanation:

someone correct me if I'm wrong

Answer:

Triangle ABC and triangle EDF

The similar triangles are Δ ABC ~ Δ EDF ~ Δ GHI, both the triangles are similar to Δ ABC.

Triangles are similar when their corresponding sides are equal ratios and their corresponding angles are congruent.

Given are triangles, Δ ABC, Δ EDF and Δ GHI,

Since, in Δ ABC and Δ EDF, two angles are shown congruent therefore, both are similar.

Also,

In Δ GHI,

∠ G + ∠ I = 129°

∠ H = 180° - 129°

∠ H = 43°

Since, we get, two angles congruent in both triangles Δ EDF and Δ GHI

Therefore, both the triangles Δ EDF and Δ GHI are similar,

Now,

Since, Δ ABC ~ Δ EDF and Δ EDF ~ Δ GHI,

Therefore, Δ ABC ~ Δ EDF ~ Δ GHI,

Hence, the correct option is "Both"

Learn more about similar triangles, click;

https://brainly.com/question/14926756

#SPJ2

Answer:c

Step-by-step explanation:

Answer:

subtract to eliminate x

Step-by-step explanation:

Answer:

49

Step-by-step explanation:

7*7=49

Answer:

C. and A.

Step-by-step explanation:

1/6 is a positive number so that is automatically greater than -0.33 and 0.3 is  It's like, the bigger the number next to the negative sign, the MORE NEGATIVE it is, making it SMALLER.

Reward for answering question correctly:

So am I gonna get brainliest?

Hi it's Mia! '^' Give the other person brainliest, They worked hard to get the answer you needed! Have a wonderful day! :)

Answer:

the answer for first question is b

Answer:

LCM of both polynomials=[tex]\mathbf{5m^3}[/tex]

Step-by-step explanation:

Least Common Multiple

We are given the polynomials

[tex]5m^7+ 35m^6+50m^5[/tex]

[tex]-20m^5-80m^4+100m^3[/tex]

Find the common factors of each polynomial, first the coefficients:

5 = 5

35 = 5*7

50 = 5*5*2

The common factor with the least exponent; 5

Now for the variables:

[tex]m^7, m^6, m^5[/tex]

The common factor with the least exponent; m^5

LCM of [tex]5m^7+ 35m^6+50m^5: 5m^5[/tex]

Similarly:

20 = 2*2*5

80=2*2*2*2*5

100 = 2*2*5*5

Common factor of the coefficients: 2*2*5=20

Common factor of variables: [tex]m^3[/tex]

LCM of [tex]-20m^5-80m^4+100m^3 = 20m^3[/tex]

LCM of both polynomials=[tex]\mathbf{5m^3}[/tex]

Answer:

22

Step-by-step explanation: