Mark wants to continue using whole liters of paint and thinks he can create a mixture of green paint the is 38 liters. Evaluate Mark's thinking using mathematical reasoning.

The ratio from blue to yellow paint is 2:3
I need helpppppp ASAP

Answers

Answer 1

Answer: It's not possible to create 38 liters of green paint with whole liters of blue and yellow paint.

======================================================

Explanation:

The ratio of blue to yellow is 2:3. We have 2 parts blue and 3 parts yellow.

Multiply both parts by x to get 2x:3x

We have 2x parts of blue paint, and 3x parts of yellow paint.

x is some positive whole number.

In total, we have 2x+3x = 5x liters of paint. Set this equal to 38 and solve for x to get

5x = 38

x = 38/5

x = 7.6

We don't get a whole number, which contradicts how we set up x earlier. This must mean that Mark must use a fractional liters, instead of whole liters.

-------------------------

Here's another way to look at it:

Lets say he uses 2 liters of blue and 3 liters of yellow. This mixes to 2+3 = 5 liters of green.

Now let's say he uses 4 liters of blue and 6 of yellow. I multiplied both parts by 2. This mixes to 4+6 = 10 liters of green.

We continue this process to get the following

6 liters of blue + 9 liters of yellow = 15 liters of green8 liters of blue + 12 liters of yellow = 20 liters of green10 liters of blue + 15 liters of yellow = 25 liters of green12 liters of blue + 18 liters of yellow = 30 liters of green14 liters of blue + 21 liters of yellow = 35 liters of green16 liters of blue + 24 liters of yellow = 40 liters of green

As you can see, we don't land on 38 liters of green. We can get to 35 liters or 40 liters, but not 38. Each of the amounts of green are a multiple of 5.

This is confirmation that Mark will have to use some fractional amount of liters of blue and yellow paint.


Related Questions

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Answer:

8

Step-by-step explanation:

z/4 - 11 = -9

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Answer:

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Step-by-step explanation:

The distance formula is ↷

[tex] d\sqrt{(x_2 - x_1)^{2}+ (y_2 - y_1)^{2} } [/tex]

All we got to to do right now is plug in!

[tex] d = \sqrt{(x_2 - x_1)^{2}+ (y_2 - y_1)^{2} } \\ d = \sqrt{(3 - 3)^{2} + (9 - 4)^{2} } \\ d = \sqrt{(0)^{2} + (5)^{2} } \\ d = \sqrt{0 + 25} \\ d = \sqrt{25} \\ d = \sqrt{5} [/tex]

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Answers

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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The line plots shows the weights of 9 grapefruits. What is the difference in the total weight of all the 1 1/2 lb grapefruits and the total weight of all the 1 1/4 lb grapefruits? A 1/4lb B 2 lb C 4 1/2lb D 7 lb

Answers

Answer:

The difference of weight is [tex]2[/tex] pounds.

Step-by-step explanation:

Given:  The line plots shows the weights of [tex]9[/tex] grapefruits

To find: The difference in the total weight of all the [tex]1\frac{1}{2} lb[/tex]  grapefruits and the total weight of all the [tex]1 \frac{1}{4}lb[/tex] grapefruits.  

Firstly, we need to convert the given mixed fractions as following:

[tex]1\frac{1}{2} lb=\frac{2+1}{2}=\frac{3}{2}lb[/tex]

[tex]1\frac{1}{4} lb=\frac{4+1}{4}=\frac{5}{4}lb[/tex]

Now, we know that,

Point diagrams divide a sample into different classes, and allow to observe the frequencies of each class.

In this case, the different weights of the grapefruit constitute the classes. From a sample of 10 grapefruit, some will weigh  others weigh.

We need to observe the dot diagram to know how many  grapefruit we have of weight [tex]\frac{3}{2} lb[/tex] and how many  grapefruit we have of weight [tex]\frac{5}{4} lb[/tex]. In other words, we need to know, in the diagram, how many points there are about class of  [tex]\frac{3}{2} lb[/tex] and how many points there are about class of   [tex]\frac{5}{4} lb[/tex].

Then, the total difference between all grapefruit of  pounds and all grapefruit of pounds is calculated as follows:

[tex]x (1\frac{1}{2} ) - y (1\frac{1}{4} ) = Z[/tex]

Where

[tex]Z[/tex]: Weight difference

[tex]x[/tex]: Quantity of [tex]1\frac{1}{2} lb[/tex]  grapefruit

[tex]y[/tex]: Quantity of [tex]1\frac{1}{4}lb[/tex] grapefruit

Suppose that of the [tex]10[/tex] total grapefruits, [tex]3[/tex] of them weigh [tex]1\frac{1}{2} lb[/tex]  and [tex]2[/tex] of them weigh [tex]1 \frac{1}{4}[/tex]  pounds. This is: [tex]x=3[/tex] and [tex]y=2[/tex]

Now,

[tex]3(\frac{3}{2} )-2(\frac{5}{4} )[/tex]              

[tex]=\frac{9}{2} -\frac{5}{2}[/tex]                    

[tex]=\frac{4}{2}[/tex]            

[tex]=2[/tex]

Hence, for this case, the difference of weight is [tex]2[/tex] pounds.

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Answers

Answer:

I pretty sure its C. OD-2) = 18

Step-by-step explanation:

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