Marjorie's unknown substance is sodium chloride NaCl.
The substance is insoluble in CCl₄. The density of the substance is 2.2 g/mL.
Solubility:
The fact that the chemical is insoluble in CCl₄ (tetrachloromethane), as indicated in the statement, indicates that the substance is polar in nature. Only C₁₀H₈ of the choices is soluble in CCl₄ since they are both non-polar by nature and related substances dissolve similarly. C₁₀H₈ is therefore disregarded.
Density:
There are now only three possibilities left. SiO₂, FeCl₃, and NaCl. The student discovered that the material has a density of 2.20 g/ ml. This is quite similar to sodium chloride's density (i.e., 2.165 g/mL). As a result, sodium chloride is most likely the material the student is working with.
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What is a concept or principle from the natural sciences that is relevant to John Snow's work on Aesthetics?
We will immediately say that right here idea or idea or precept from the from the herbal sciences college students, herbal sciences- that could be a relevant that is real occasion to snow's paintings on Anaesthetics. the scholars is thereto substances.
Propofol, etomidate, and ketamine are the intravenous sedative-hypnotic retailers typically used to result in standard anesthesia, at the same time as adjuvant dealers, eg, opioids, lidocaine, midazolam are frequently used to complement the effects of the primary sedative-hypnotic induction agent.
Examples consist of an epidural to ease the pain of childbirth or at some stage in a cesarean phase, a spinal for hip or knee surgical procedure, or an arm block for hand surgical treatment. preferred anesthesia: This remedy makes you subconscious and insensitive to ache or other stimuli.
Propofol is the maximum usually used IV fashionable anesthetic. In lower doses, it induces sleep whilst allowing a affected person to maintain respiration on their personal. It's far regularly utilized by anesthesiologist for sedation similarly to anxiolytics and analgesics.
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Why is it important to have only one independent variable and to control the
other variables when performing science experiments
Scientists cannot pinpoint the changes or variations in the results to a single source when more than one variable is altered during an experiment. The outcomes can be attributed to the independent variable directly by examining and modifying each variable separately.
You can evaluate the outcomes of your experiment to determine how much one adjustment impacted the outcome by testing just one variable at a time. You won't be able to identify the variable that caused the outcome if you're testing two variables simultaneously. A controlled variable is one that is kept constant with the goal of not affecting how an experiment turns out. Controlling any factors that can affect an experiment's outcomes allows us to be certain that the altered variable is what caused our results.
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Fill in the blanks substance X Y Z MASS(g) 10.0 50.0 volume cm 20.0 5.0 density 10.0 4.0
Density of X = 0.5 g/cm³
Volume of Y = 5 cm³
Mass of Z = 20 g
As we know Density is the substance's mass per unit of volume. So according to the given values of X,Y and Z we can calculate density, mass and Volume.
For X:
Volume of X = 10g
Mass of X = 50cm³
Density =Mass ÷ Volume
Density = 10 /50
Density = 0.5 g/cm³
For Y
Mass of Y = 50g
Density of Y = 10g/cm³
Volume = Mass / Density
Volume = 50 / 10
Volume = 5 cm³
For Z:
Volume of Z = 5 cm³
Density of Z =4 g/cm³
Mass of Z = Volume ×Density
Mass of Z = 4×5
Mass of Z = 20g
Complete question is
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The density is quantitative method to measure the mass and volume of a substance.
The formulae of density is mass of a substance per unit volume.
1) For X
The mass of X = 10.0gm
The volume of X = 20.0 cm³
Then density of X = mass/ volume
Density of X = 20/10
Density of X = 2 g/ cm³
2) For Y
The mass of Y = 50gm
density of Y = 10 gm/cm³
volume of Y = mass /density
Volume of Y = 50/10
Volume of Y = 5cm³
3) For Z
The volume of Z = 5 cm³
The density of Z = 4 gm/cm³
The mass of Z = density ×volume
The mass of Z = 5× 4
The mass of Z = 20 gm
The density of X = 2 g/ cm³
The Volume of Y = 5cm³
The Mass of Z = 20 gm
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ILL GIVE BRAINLIEST TO THE FIRST ANSWER!!!!
For this and the following two questions, determine the mass of an object (in Gg) if it has a density of
2.007 g/cm3 and the dimensions are 20. cm x 20.0 cm x 70.0 cm. What is the right-most significant figure after performing the calculation in scientific notation?
Answer:
Your mom
Explanation:
Julie I think that this is the most easiest question someone has every asked in my whole entire life. I think you should really go to a lower class and will benefit you more. I wish you some what of some success!!!!
Mass of the object is 5.6196 * 10^4 g.
What is density?The term density has to do with the ratio of the mass to the volume of a substance. The density is an intrinsic property of a substance which could be used to identify a substance.
Mass of the substances = ?
Volume of the substance = 20. cm x 20.0 cm x 70.0 cm =28000 cm^3
Density of the substance = 2.007 g/cm3
Density = mass/volume
mass = density * volume
mass = 2.007 g/cm3 * 28000 cm^3
mass = 5.6196 * 10^4 g
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CH₂-CH3
CH3-CH₂-CH-CH-CH₂-CH3
-CH-CH-
CH₂-CH3
What is this compound?
The compound is-
CH₂-CH3 = C2H5 = it is ethyl radical
CH3-CH₂-CH-CH-CH₂-CH3= Hex-3-ene
-CH-CH- = acetylene or ethyne
CH₂-CH3 = ethyl radical
Acetylene, commonly referred to as ethyne, is an alkyne with a linear structure and a triple bond.Acetylene is an alkyne chemical. Between the two carbon atoms, there is a triple bond. Ethyne is another name for it. Its molecular weight is 26.04 g/mol, and it is just marginally soluble in water. Because it has a triple bond, the molecule is unsaturated. The acetylene molecule's carbon atoms go through so hybridization to create sp hybridized orbitals that interact with two hydrogen atoms. A sigma bond and two pi bonds make up the triple bonds in alkynes. The head-on overlap of the two molecular orbitals creates sigma bonds, whereas the head-on overlap ofTo know more about Acetylene visit : https://brainly.com/question/20529866
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Rank each of the following elements by the common number of single bonds the element makes when it bears no formal charge. Each element is from
the second row of the periodic table F,O,N,C,NE
In this ranking we would have; C > N > O > F > Ne.
What is the formal charge?The term formal charge has to do with the charge that an atom appears to have in compound. We can obtain the formal charge from the formula;
Formal charge = [# of valence electrons] – [electrons in lone pairs + 1/2 the number of bonding electrons]
Let us now consider the atoms; F, O, N, C, Ne. We have to rank the atoms by the common number of single bonds the element makes when it bears no formal charge.
In this ranking we would have; C > N > O > F > Ne.
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The electron configuration of phosphorus is [Ne] 3s23p3. The correct electron dot structure of phosphorus should contain_?__ dots.
Answer:
since neon has 10 electrons, phosphorous would contain 10 + 2 + 3 = 15 electrons, with 5 being valence electrons.
aka 15 dots in total, with 5 dots in the valence electron shell
Suppose you have two samples that are equal in weight, 17.8
g Ti
and 17.8
g Fe2O3
.
Calculate the number of moles of each substance.
Considering the definition of molar mass, the number of moles of Ti and Fe₂O₃ are 0.087 moles and 0.11 moles respectively.
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
The molar mass of a compound is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.
Molar mass of TiThe molar mass of Ti is 204.37 g/mole.
Molar mass of Fe₂O₃You know the molar mass of the elements is:
Fe= 55.85 g/moleO= 16 g/moleSo, the molar mass of the compound Fe₂O₃ is calculated as:
Fe₂O₃= 2× 55.85 g/mole + 3× 16 g/mole
Solving:
Fe₂O₃= 159.7 g/mole
Number of moles of each substanceYou can apply the following rules of three:
If by definition of molar mass 204.37 grams of Ti are contained in 1 mole, 17.8 grams of Ti are contained in how many moles of Ti?moles of Ti= (17.8 grams× 1 mole)÷ 204.37 grams
moles of Ti= 0.087 moles
If by definition of molar mass 159.7 grams of Fe₂O₃ are contained in 1 mole, 17.8 grams of Fe₂O₃ are contained in how many moles of Fe₂O₃?
moles of Fe₂O₃= (17.8 grams× 1 mole)÷ 159.7 grams
moles of Fe₂O₃= 0.11 moles
Finally, the number of moles of Ti and Fe₂O₃ are 0.087 moles and 0.11 moles respectively.
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What is the mass of a sample of copper with a volume of 4.5 cubic centimeters?
The mass of a sample of copper with a volume of 4.5 cubic centimeters is 40.32 grams.
A substance's density is defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be used. Mass divided by volume is the formula for density in mathematics: ρ = m / v , where ρ is the density, m is the mass, and V is the volume.
So, ρ = m/v
8.96 = m / 4.5
40.32 g = mass
Therefore, the mass of a sample of copper with a volume of 4.5 cubic centimeters is 40.32 grams.
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ionic equation for the reaction between aqueous solution of potassium carbonate and dilute sulphuric acid
Answer:
Ionic equation for the reaction of Potassium Carbonate (aqueous) with dilute Sulphuric Acid gives Potassium Sulphate, Carbon Dioxide and Water.
What is ionic equation?
Ionic equations are chemical equations that represent the electrolytes in aqueous solution as dissociated ions, similar to molecular equations which express compounds as molecules. Usually, this is a salt that has been dissolved in water; in the equation, the ionic species are denoted by (aq) to denote that they are in aqueous solution.
Complete balanced chemical equation is given below:
K₂CO₃ (aq) + H₂SO₄ → K₂SO₄ (aq) + CO₂ + H₂O
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How many atoms or molecules are in 10 grams of table salt?
Answer:
1.03 x 10²³ atoms NaCl
Explanation:
To find the amount of table salt (NaCl) in atoms, you need to (1) convert grams to moles (using the molar mass) and then (2) convert moles to atoms (using Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units.
(Step 1)
Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol
10 grams NaCl 1 mole
------------------------ x ----------------------- = 0.17 moles NaCl
58.44 grams
(Step 2)
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
0.17 moles NaCl 6.022 x 10²³ atoms
-------------------------- x -------------------------------- = 1.03 x 10²³ atoms NaCl
1 mole
Can someone tell me how to do this. Also just answer the first one so I can get it
Answer:
it is 3 in a half inches long i hope this helped
A scientist is trying to discover information about an unknown metal in a compound. The formula for the compound is believed to be XBr3 where X is the unknown metal. The scientist determined that a 4.727 g sample of this compound contains 5.317×10−2 mol Br . Calculate the atomic mass of the unknown metal, X .
Atomic Mass=
What is the identity of the metal? Provide the name or symbol of the element.
Metal:
The atomic mass of the element X is 56 and the element can be seen to be iron.
What is the identity of element X?In this problem, we are given a compound to obtain the identity of the unknown element therein.
We already can relate that;
Number of moles = mass/molar mass
Number of moles Br = 0.04806 moles
Molar mass of Br could be obtained as 79.9 g/mol
We have;
Mass = Number of moles x molar mass
= 0.04806x 79.9
= 3.84 g
Mass of X = 4.735 - 3.84
= 0.895 g
Given that there are 3 moles of Br for every 1 mole of X. We have 0.04806 mole of Br present in 4.735 g, then the number of moles of X present would be:
0.04806/3 = 0.01602 moles
Molar mass = mass/mole
= 0.895/0.01602
= 55.87 or 56 g/mol
Hence, the element X is iron
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Complete the equation for the equilibrium present in the region bc X(s)=?
The following equality statistic is available for the BC X (s) region states:
The following data is obtained using the equilibrium diagram:
shows the various categories that can be found in various temperatures and shapes.
It demonstrates how one object can solidly melt over another.
Describes the amount of the temperature at which the material system solidifies or solidifies.
The rate of reaction is equal to the rate of reaction in an equilibrium situation.
Examples of equilibrium include a book on the table, liquid in a tightly sealed container, full solution, ionic compounds in polar solvents, and the synthesis of ammonia.
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As a nucleus becomes unstable, it will undergo radioactive decay to.?
As a nucleus becomes unstable, it will undergo radioactive decay to form the daughter nuclei because daughter nuclei is more stable and lighter than the nucleus that decayed.
What is Radioactive Decay ?Radioactive decay is the process in which the emission of energy is in the form of ionizing radiation.
It is represented as
A = - (dN/dt)
where,
A = total activity
t = time
N = number of particles
What is Daughter nucleus ?Daughter nucleus is the nucleus which remains after the decay. Daughter nucleus form when the 2 nucleus usually by mitosis results from the division of a single nucleus.
Thus from the above conclusion we can say that As a nucleus becomes unstable, it will undergo radioactive decay to form the daughter nucleus.
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If a patient receives a dose with an activity of 53.8 mCi of technetium-99m for cardiac imaging, how much radioactivity will be left in the patient’s body 72 hours after injection?
Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging, radioactivity will be left in the patient’s body 72 hours after injection is 0.00024
The equation that describes the radioactive decay is:
Ln [A] = -kt + Ln [A]₀
Where [A] could be taken as activity of the source after time t, [A]₀ is initial activity and k is decay constant.
Decay constant could be written as:
k = ln2 / Half-life
k = ln 2 / 6h
k = 0.115h⁻¹
Replacing in decay equation:
ln a = -0.115 x 72 + Ln [53.8]
ln a = - 8.28 + 3. 98
ln a = - 8.28
log a = -4/ 2.303
log a = 1.867
Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging. radioactivity will be left in the patient’s body 72 hours after injection is 1.867
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Xylem cells have thickened walls how does this thickening differ in the two xylem shown in the diagram
The secondary cell wall of the elongated, hollow xylem cells, which are dead, contains lignin.
What functions as the xylem?The specialized tissue in vascular plants called xylem distributes nutrients and water from the plant-soil contact to the stems and leaves as well as serving as a mechanical support system and a storage system. One of the key characteristics that sets vascular plants apart is the xylem's ability to transmit water.
Where can you locate the xylem?Vascular bundles, which are found in both non-woody plants and non-woody sections of woody plants, contain xylem. In woody plants, a meristem known as the vascular cambium lays down secondary xylem. as a component in a starry arrangement rather than a bundle, as in many ferns.
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The density of titanium is 4.51 g/cm^3. what is the volume (in cubic inches) of 3.0 lb of titanium?
A large balloon is initially filled to a volume of 11.2 L at 325 K and a pressure of 3450 mm Hg. What volume of gas will the balloon contain at 1.4 atm and 325 K?
Answer:
36 L
Explanation:
Since the temperature remains constant, you can use Boyle's Law to find the final volume:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. Before, you can plug the given values into the equation and solve for "V₂", you need to convert mmHg to atm to maintain consistent units.
760 mmHg = 1 atm
P₁ = 3,450 mmHg / 760 mmHg = 4.54 atm P₂ = 1.4 atm
V₁ = 11.2 L V₂ = ? L
P₁V₁ = P₂V₂ <----- Boyle's Law
(4.54 atm)(11.2 L) = (1.4 atm)V₂ <----- Insert values
50.848 = (1.4 atm)V₂ <----- Multiply 4.54 and 11.2
36 = V₂ <----- Divide both sides by 1.4
calculate the mass in grams for .65 moles of N2
The mass in grams for .65 moles of N₂ is 18.2g
What is Mole?
Mole is the mass of a substance that contains 6.023 x 10²³ particles of the substance1 mol of Carbon-12 has mass of 12 grams and contains 6.022 x 10²³ of carbon atomsAtomic mass of nitrogen is 14u . A nitrogen molecule has 2 atoms of nitrogen. Thus its molecular mass is 14 × 2 = 28u.Molar mass is the mass of 1 mole of molecules i.e. mass of 6.022 × 10²³ molecules. Its the same number as molecular mass but the unit is in gramsWe can use the simple formulan = w / M
where
n = no of moles = .65
w = Mass of the given sample = ?
M = Molar mass ( Molar mass is same as molecular mass) = 28g
substituting the values
n = w / M
w = n × M
= .65 × 28
= 18.2g
Thus we can conclude that the mass in grams for .65 moles of N₂ is 18.2g
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Which is the dependent variable
Concentration or
Time ?
What kind of force acts within a molecule?
OA. A nonpolar force
OB. A Van der Waals force
OC. An intermolecular force
OD. An intramolecular force
The forces that act within a molecule are intramolecular forces.
What is intramolecular force?The forces that will be generated within a molecule between its atoms will be called the intramolecular force, these are mainly ionic and covalent bonds. These forces are the ones that must be overcome in order to generate a chemical change within the molecule and are the ones that determine what its chemical properties are within a substance.
Ionic bond is in which the complete transfer of electrons occurs and there is a large difference in electronegativity between the atoms, while in the covalent bond the electrons are shared between the two atoms and their electronegativities are similar.
Therefore, we can confirm that the forces that act within a molecule are intramolecular forces.
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Hello,
I am stuck on this: What is the de Broglie wavelength of a neutron (mass = 1.009 amu) moving at a velocity of 7.11 × 10⁶ meters per second?
I know the formula is wavelength= h/mv, but I keep getting the answer incorrect as: 4.67E-27
The de Broglie wavelength of the neutron moving at a velocity of 7.11×10⁶ m/s is 5.56×10¯¹⁴ m
de Broglie wavelength formulaλ = h /mv
Where
λ the de Broglie wavelengthh is the Planck's constantm is the massv is the velocityHow to determine the de Broglie wavelengthThe following data were obtained from the question:
Mass (m) = 1.009 amu = 1.009 × 1.661×10⁻²⁷ = 1.676×10⁻²⁷ KgVelocity (v) = 7.11×10⁶ m/sPlanck's constant (h) = 6.626×10¯³⁴ Jsde Broglie wavelength (λ) =?The de Broglie wavelength can be obtained as follow:
λ = h /mv
λ = 6.626×10¯³⁴ / (1.676×10⁻²⁷ × 7.11×10⁶)
λ = 5.56×10¯¹⁴ m
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Level 3: 1. The type of hydrogen labeled as A, B and C are prepared as follows: Type of hydrogen Method of preparation A B C a. b. What are A, B and C? Which is most powerful reducing agent? Which hydrogen can never be isolated? Write an example of reaction which proves B is more powerful reducing agent than Write a balanced reaction which proves C is stronger reducing agent than A. Project Activity Mg + dil.HCI Passing molecular H₂ under electric arc at low pressure Sn and conc. HC1 in solution. C. d. e. World is facing problems of environmental pollution due to excessive use of fossil fuel. The c like Nepal is suffering from fuel crisis. Make a report on "use of hydrogen as fuel" and hydrogen an alternative to fossil fuel like diesel, petrol etc. Also mention limitations of the H₂ as fuel. 334 A New Comprehensive Chemistry Approved by CDC
Answer:
nnnj
Explanation:
James Author I m not sure if you have any questions or concerns please visit the plug-in settings to determine how attachments are handled the situation and see if you have yyyy I m not sure if you have any questions or concerns please visit the plug-in settings to determine how attachments are handled the situation and I m not sure if you have any questions or concerns please visit the plug-in I m not gonna lie in bed with step by step by step instructions on how we can get the answer to your account we will tell you have any questions you might want I will be able and you will send the hw the whole thing is the whole thing I have to the whole of I m too many like a good for the plug-in the plug-in I m eating a good for the whole time I was just for you the whole of the et I m eating a email to the answer to the answer to the same is the answer is er the whole time is the best ee the whole of I will send me a good time for the plug-in the whole thing was I is not to mention the plug-in I am a email I will be able to the answer is no sharing to others and you can get the
If 2.96 mL of seawater contains about 7.86×10-14 moles of gold, how many atoms of gold are in that volume of seawater? atoms
The number of atoms of gold in the 2.96 mL of the seawater is 4.73×10¹⁰ atoms
Avogadro's hypothesis1 mole of Gold = 6.02×10²³ atoms
With the above information, we can determine the number of atoms in the seawater. Details below
How to determine the atoms in 7.86×10⁻¹⁴ mole of gold1 mole of Gold = 6.02×10²³ atoms
Therefore,
7.86×10⁻¹⁴ mole of gold = (7.86×10⁻¹⁴ mole × 6.02×10²³ atoms) / 1 mole
7.86×10⁻¹⁴ mole of gold = 4.73×10¹⁰ atoms
Thus, 4.73×10¹⁰ atoms of gold are present in the seawater
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It takes a turtle 10 seconds to increase his speed from 1 m/s to 5 m/s. What is the acceleration of the turtle
The acceleration of the turtle, given the data from the question is 0.4 m/s²
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the accelerationThe acceleration of the turtle can be obtained as follow:
Time (t) = 10 sInitial velocity (u) = 1 m/sFinal velocity (v) = 5 m/sAcceleration (a) =?a = (v – u) / t
a = (5 – 1) / 10
a = 4 / 10
a = 0.4 m/s²
Thus, acceleration of the turtle is 0.4 m/s²
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If ln(x) = 3.11, what is the value of x?
Express your answer to two significant figures.
If ln(x) = 3.11, the value of x is 22.64. it has 4 significant figures.
In positional notation, significant figures are the digits in a number that is trustworthy and required to denote the amount of something. The correctness and precision of numbers are the focus of significant figures, also known as significant digits, which are crucial components of scientific and mathematical calculations.
significant figures play a crucial role when estimating the degree of uncertainty in the outcome. The number of digits that can be determined with some degree of certainty is relevant to significant figures. When compiling data from an experiment, keeping track of this number is crucial because it reduces mistakes.
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A runner exerting a running force of 325 N to the right is met with an air resistance force of 45 N to the left. What is the net
force of the runner? (1 point)
O 45 N
O 280 N
O 370 N
O 325 N
The net force of the runner, given the data from the question is 280 N
Data obtained from the questionFrom the question given above, the following data were obtained:
Exerting force = 325 NResistance force = 45 NNet force =?How to determine the net forceThe net force of the runner can be obtained as illustrated below:
Net force = Exerting force - resistance force
Net force = 325 - 45
Net force = 280 N
From the calculation made above, we can conclude that the runner's net force is 280 N
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The net force of the runner would be 280 N.
Hope this helps! Also, if you need help with the other questions regarding this assignment, feel free to check out the study set I made on Quizlet. Thanks and good luck!
Quizlet - "Unit 6: Lesson 2 Newton's First Law QC"
h t t p s : / / q u i z l e t. c o m / 7 3 7 7 5 9 5 5 5 / u n i t - 6 - l e s s o n - 2 - n e w t o n s - f i r s t - l a w - f l a s h - c a r d s / ? n e w
what were the 3 constellations that were above the horizon at
9PM on August 31, 2022?
Calculate the number of grams of xenon in 3.541 g
of the compound xenon tetrafluoride.
The mass (in grams) of xenon in 3.541 g of the compound xenon tetrafluoride is 2.243 grams
How to determine the mass of Xe in 3.541 g of XeF₄We'll begin by listing the composition of xenon tetrafluoride, XeF₄
1 mole of XeF₄ contains the following:
1 mole of XeF₄ = 131.3 + (4 × 19) = 131.3 + 76 = 207.3 g1 mole of XeF₄ contains 131.3 g of Xe1 mole of XeF₄ contains 76 g of FThe mass of Xe in 3.541 g of XeF₄ can be obtained as illustrated below:
207.3 g of XeF₄ contains 131.3 g of Xe.
Therefore,
3.541 g of XeF₄ will contain = (3.541 g × 131.3 g) / 207.3 g = 2.243 g of Xe
Thus, 2.243 g of Xe is present in 3.541 g of xenon tetrafluoride, XeF₄
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